find the unknown angle

Answer:

0.62

Step-by-step explanation:

Probability of rain = 34% = 0.34

Probability of wind = 38% = 0.38

Probability of wind and rain = 10% = 0.1

P(wind U rain) = p(wind) + p(rain) - p(both)

= 0.34 + 0.38 -1

= 0.62

The probability that it would be rainy or sunny in any given day in April is 62%

Answer: y=x³+2 or f⁻¹(x)=x³+2

Step-by-step explanation:

To find the inverse of the radical function, we replace y with x and x with y. Then, you solve for y.

[tex]y=\sqrt[3]{x-2}[/tex]                        [replace y with x and x with y]

[tex]x=\sqrt[3]{y-2}[/tex]                        [cube both sides to cancel out the cubed root]

[tex]x^3=y-2[/tex]                          [add both sides by 2]              

[tex]x^3+2=y[/tex]

Now that we have switched the variables and solved for y, we know that the inverse function is y=x³+2 or f⁻¹(x)=x³+2.

Answer:

f^-1(x)=x^3+2

Step-by-step explanation:

Answer:

(5/3 x - k)/c  =b

Step-by-step explanation:

x = 3 / 5 (cb+k)

Multiply each side by 5/3

5/3x =5/3* 3 / 5 (cb+k)

5/3x = (cb+k)

Subtract k

5/3 x - k = cb +k-k

5/3 x - k = cb

Divide by c

(5/3 x - k)/c  = cb/c

(5/3 x - k)/c  =b

Answer:

Seven and three million ten thousand and six.

Step-by-step explanation:

703 is in the millions place.

010 is in the thousands place.

and 006 is in the hundredths place.

hope this helps you!

Answer:

15, 22, 88

Step-by-step explanation:

I assume you mean the second number is 7 more than the first.  Write the system of equations:

x + y + z = 125

y = x + 7

z = 4y

Substitute the third equation into the first.

x + y + 4y = 125

x + 5y = 125

Substitute the second equation.

x + 5(x + 7) = 125

6x + 35 = 125

6x = 90

x = 15

Solve for the other variables.

y = 22

z = 88

Answer:

Please comment on this answer what the real question is.

Step-by-step explanation:

im pretty sure that it is

i

Answer:

i

Step-by-step explanation:

[tex] \huge {i}^{37} \\ \huge= {i}^{36} \times i \\ \huge = ( {i}^{2})^{18} \times i \\\huge = ( - 1) ^{18} \times i \\ \huge = 1 \times i \\ \huge = i \\ \\\huge \therefore {i}^{37} = i[/tex]

Answer:

Teachers are the one that teach the doctors how to do their profession. They are both critical parts of society and should both be respected. Though doctors work with patients and determine what problems they have and how to help solve them. They work on treatments and can reassure patients in tough situations. They only goal is to help others and keep everyone has happy and healthy as possible.

Answer:

Actually It Does Lx-21/x-2 you have to find out what the Letter x stands for and what the letter L stands For for you to be able to find the answer

Step-by-step explanation:

Step-by-step explanation:

1.

Point M is the bisector of AB

AM = 13...(given)

Therefore, AB = 2AM = 2* 13 = 26

2.

Ray MC is the bisector of AB

AM = 8...(given)

Therefore, AB = 2AM = 2* 8 = 16

3.

Line l is the bisector of angle AB.

BM = 26...(given)

Therefore, AB = 2BM = 2* 26 = 52

Answer:

-3.5

Step-by-step explanation:

An example is -3.5.

Answer:

Step-by-step explanation:

from focus

[tex]\sqrt{(x+3)^2+(y-2)^2}[/tex]

from directrix

|y-4|

Answer:

a.   y = 6

b.  RS = 44

    ST = 37

    RT = 81

Step-by-step explanation:

RS = 7y + 2

ST = 5y + 7

RT = 14y - 3

find:

a.  y

b.  RS, ST, RT

RS + ST = RT

7y + 2 + 5y + 7 = 14y - 3

group like terms

7y + 5y + 2 + 7 = 14y - 3

12y + 9 = 14y - 3

9 + 3 = 14y - 12y

12 = 2y

y = 12/2

y = 6

-----------------------------------

b.

RS = 7(6) + 2

RS = 44

ST = 5(6) + 7

ST = 37

RT = 14(6) - 3

RT = 81

Answer:

a.   y = 6

b.  RS = 44;     ST = 37;     RT = 81

Step-by-step explanation:

RS + ST = RT

7y + 2 + 5y + 7 = 14y - 3

group like terms

7y + 5y + 2 + 7 = 14y - 3

9 + 3 = 14y - 12y

12 = 2y

y = 12/2

y = 6

plug in values to solve RS,  ST,  RT

RS = 7(6) + 2 = 44

ST = 5(6) + 7  = 37

RT = 14(6) - 3  = 81

Complete Question

The mean height of women in a country (ages 20-29) is 64.4 inches. A random sample of 75 women in this age ground is selected. what is the probability that the mean height for the sample is greater than 65 inches? assume [tex]\sigma = 2.97[/tex]

Answer:

The value is  [tex]P(X > 65) = 0.039715[/tex]

Step-by-step explanation:

From question we are told that

  The mean is [tex]\mu = 64.4 \ inches[/tex]

  The  sample size is  [tex]n = 75[/tex]

The probability that the mean height for the sample is greater than 65 inches is mathematically represented as

     [tex]P(X > 65) = P[\frac{X - \mu }{ \sigma_{\= x} } > \frac{65 - 64.4 }{ \sigma_{\= x} } ][/tex]

Where  [tex]\sigma _{\= x }[/tex] is the standard error of mean which is evaluated as

     [tex]\sigma_{\= x } = \frac{\sigma}{\sqrt{n} }[/tex]

=>   [tex]\sigma_{\= x } = \frac{2.97}{\sqrt{75} }[/tex]

=>    [tex]\sigma_{\= x } = 0.343[/tex]

Generally [tex]\frac{X - \mu }{ \sigma_{\= x } } = Z(The \ standardized \ value \ of \ X )[/tex]

       [tex]P(X > 65) = P[Z> \frac{65 - 64.4 }{0.342 } ][/tex]

So  

    [tex]P(X > 65) = P[Z >1.754 ][/tex]

From the z-table  the value of  

     [tex]P(X > 65) = P[Z >1.754 ] = 0.039715[/tex]

     [tex]P(X > 65) = 0.039715[/tex]

Answer:

Step-by-step explanation:

[tex] \sf{6x - 7(4 - 5)}[/tex]

Distribute 7 through the parentheses

[tex] \sf{6x - 28 + 35}[/tex]

Calculate

[tex] \sf{6x + 7}[/tex]

Hope I helped!

Best regards!!

Answer:

No

Step-by-step explanation:

Assuming that the x- and y- axes are respectively horizontal and vertical, a vertical line has an undefined slope and cannot be diagonal.

Note that only a diagonal line can have a slope defined.

Because both the x and y variables are associate with a value, you don’t just add 3x and 2x.

You have:

3x^5y^8 + 2x^5y^7

Apply the exponent rule a^b+c = a^ba^c

This means x^5y^8 = x^5y^7y

Now you have:

3x^5y^7y + 2x^5y^7

Since they both now have an x^5y^7 in them factor the out of both:

When you take that out it’d both numbers you are left with 3y + 2

The final answer is: X^5y^7(3y +2)

Step-by-step explanation:

the answer for 6y+21+7=4y−20+5y is

y =16

Answer:

The sample size is  [tex]n =419[/tex]

Step-by-step explanation:

From the question we are told that

    The population proportion is  [tex]p = 0.45[/tex]

     The  margin of error is  [tex]E = 0.04[/tex]

Given that the confidence level is  90%

  Then the level of significance can be mathematically represented as

          [tex]\alpha = 100 -90[/tex]

          [tex]\alpha = 10\%[/tex]

         [tex]\alpha = 0.10[/tex]

Next we obtain the level of significance from the normal distribution table the value is    

             [tex]Z_{\frac{\alpha }{2} } = 1.645[/tex]

   Generally the sample size is mathematically represented as  

        [tex]n = [ \frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * p(1- p )[/tex]

substituting values

         [tex]n = [ \frac{1.645 }{0.04} ]^2 * 0.45(1- 0.45 )[/tex]

        [tex]n =419[/tex]

Step-by-step explanation:

5y = ZW - ZC

5y = Z(W - C)

5y / W- C = Z(W -C) / W - C

Z = 5y / W - C

Answer:

Step-by-step explanation:

Divide the length of the paper strip into four equal sections of 1 inch each.

Mark the left end of the strip '0' and the right end '4.'  Label the '1,' '2,' '3' points.

Between these marks, label the strip as follows:

'1/4,' '1/2,' '3/4,' 1 (already marked), '1 1/4,' '1 1/2,' and so on.

Next time, please be sure to share ALL parts of the question with which you want help.  Thank you.

Answer:

The  probability is  [tex]P(X < 20 ) = 0.68807[/tex]

Step-by-step explanation:

From the question we are told that

     The proportion of  total part-time workforce is  [tex]\r p = 0.221[/tex]

     The  sample  size is  n  =  80  

Generally the mean is mathematically represented as

         [tex]\mu = n* p[/tex]

          [tex]\mu = 0.221 * 80[/tex]

        [tex]\mu = 17.68[/tex]

The  proportion of not part - time   workforce

      [tex]q = 1- p[/tex]

=>   [tex]q = 1- 0.221[/tex]

=>   [tex]q = 0.779[/tex]

The  standard deviation is mathematically represented as

     [tex]\sigma = \sqrt{ 80 * 0.221 * 0.779 }[/tex]

     [tex]\sigma = 3.711[/tex]

Now  applying the normal approximation,

Then the  probability that fewer than 20 people from this sample were between the ages of 25 and 34 is mathematically represented as

     [tex]P(X < 20 ) = P( \frac{X - \mu }{ \sigma } < \frac{ 20 - 17.68 }{ 3.711} )[/tex]

Applying  continuity correction

     [tex]P(X < 20 ) = P( \frac{X - \mu }{ \sigma } < \frac{ (20-0.5 ) - 17.68 }{ 3.711} )[/tex]

       [tex]P(X < 20 ) = P( \frac{X - \mu }{ \sigma } < \frac{ (20-0.5 ) - 17.68 }{ 3.711} )[/tex]

      [tex]P(X < 20 ) = P( \frac{X - \mu }{ \sigma } < 0.4904 )[/tex]

Generally

      [tex]\frac{X - \mu }{ \sigma } = Z ( The \ standardized \ value \ of \ X )[/tex]

So  

    [tex]P(X < 20 ) = P( Z< 0.4904 )[/tex]

From the z-table  

        [tex]P( Z< 0.4904 ) = 0.68807[/tex]

The probability is  

         [tex]P(X < 20 ) = 0.68807[/tex]

Answer:

[tex]Volume = 4492.125\ unit^3[/tex]

Step-by-step explanation:

Given

Uniform Distribution X

X: 15 to 18

Required

Determine the expected volume

Since, X is uniformly distributed; We have to first determine the expected value of X as follows;

[tex]Mean(X) = \frac{b + a}{2}[/tex]

Where b = 18 and a = 15

[tex]Mean(X) = \frac{18 + 15}{2}[/tex]

[tex]Mean(X) = \frac{33}{2}[/tex]

[tex]Mean(X) = 16.5[/tex]

Since the box is a square box, the volume is as follows;

[tex]Volume = 16.5 * 16.5 * 16.5[/tex]

[tex]Volume = 4492.125\ unit^3[/tex]

Hence, the expected volume is 4492.125 unit³

Hi

1 mile = 5280 feet  

at  90 mile per hour, you have  5280 *90  = 475 200 feets  

an hour is  60*60 = 3600 second  

so in 1 second the train travel  :  475 200 /3600 = 4752 /36 = 132 feets

so in 10 seconds  :  132*10 = 1320 feets.

The feet train travel in 10 seconds is  1,320 feet .

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

According to the question

Train traveling at a constant speed = 90 miles per hour

1 mile = 5280 feet  

By using unitary method:

feet does it travel in 1 seconds = [tex]\frac{90*5280}{60*60}[/tex]  

feet does it travel in 10 seconds = [tex]\frac{90*5280}{60*60} * 10[/tex]

                                                      = 1,320 feet

Hence, the feet train travel in 10 seconds is  1,320 feet .

To know more about unitary method  here:

https://brainly.com/question/22056199

#SPJ3

Answer:

Step-by-step explanation:

[tex] \mathsf{ \frac{x}{4} = 2}[/tex]

Apply cross product property

[tex] \mathsf{x \times 1 = 2 \times 4}[/tex]

Calculate

[tex] \mathsf{x = 8}[/tex]

Hope I helped!

Best regards!

Answer:

[tex] \frac{x}{4} = 2[/tex]

X=2

Step-by-step explanation:

4•x/4=2•4

X=8

Answer:

z= 3.63

z for  significance level = 0.05 is ± 1.645

Step-by-step explanation:

Here p = 42% = 0.42

n= 500

We formulate our null and alternative hypotheses as

H0: p= 0.42     against Ha : p> 0.42 One tailed test

From this we can find q which is equal to 1-p= 1-0.42 = 0.58

Taking p`= 0.5

Now using the z  test

z= p`- p/ √p(1-p)/n

Putting the values

z= 0.5- 0.42/ √0.42*0.58/500

z= 0.5- 0.42/ 0.0220

z= 3.63

For one tailed test the value of z for  significance level = 0.05 is ± 1.645

Since the calculated value does not fall in the critical region we reject our null hypothesis  and accept the alternative hypothesis that more than 42%  people owned cats.

The third column is optional/extra. It's to show which data values fit in what specific class limit interval.

===================================================

Explanation:

Imagine we had a bunch of cards. Each card will have a number that is from the data set {70, 88, 103, 64, ... etc}

The goal is to sort the cards into 7 boxes. The first box is labeled "60 through 66", the next is "67 through 73", etc.

The first box has 4 cards placed inside it because we have the values {64,65,60,60 } which fit the interval from 60 through 66. Therefore the frequency here is 4.

The next box has the cards labeled {70,69,71,72,70 } inside it. We have 5 cards here, so the frequency is 5.

This pattern is kept up until all of the cards have been sorted into the proper boxes.

What you'll end up with is what you see in the image below. It shows the table of class limits with their corresponding frequencies. I have added a third column to show which values go where, which is optional and likely something you wont put as your answer to the teacher. This third column is just something for you to help keep track of everything.

Let

[tex]A=B=\begin{bmatrix}0&1\\1&0\end{bmatrix}[/tex]

Then

[tex]AB=BA=\begin{bmatrix}0&1\\1&0\end{bmatrix}^2=\begin{bmatrix}1&0\\0&1\end{bmatrix}[/tex]

Answer:

My answer is option C.

Step-by-step explanation:

Since you cannot eliminate it immediately then you will need to multiply it by each of the number to make them equal that means you will multiply the first equation by any number in the second equation that is you can use maybe -4 or 2 or 1. and then do the same to the other equation to make them equal...if you use 2 in the second equation for the first equation and you use 7 in the first equation for the second equation the you will make them equal which makes them easier to eliminate and then when you find y which is y=1/22 then you can substitute it into any of the equation and find your x which is x=13/11.

Answer: option c

Step-by-step explanation:

Answer:

C            Mark me as brainliest!!!

Step-by-step explanation: