Find the standard normal area for each of the following(round your answers to 4 decimal places

Answer:

2

Step-by-step explanation:

The basic 30-60-90 triangle ratio is:

     Side opposite the 30° angle: x

     Side opposite the 60° angle: x√3

     Side opposite the 90° angle: 2x

Here, the side opposite the 90° angle is 4.

This means that 2x = 4 and, thus, x = 2.

Since b is the side opposite the 30° angle, b = x, so it is 2.

Consider a disk D having center as origin and radius 'a', the average distance from point say ( r, θ) to the origin D to the origin is equals to the 2a/3.

The distance of a point to the origin is given by the function d(x, y) = √x²+ y². Denote the disk by D. To compute the average we need to evaluate the integral, for which we use polar coordinates, f(r, θ) = (1/area of region R)∬ f(r,θ)dA.

We have a disk D with center the origin (0,0) and radius 'a'. We have to determine the average distance from points in D to the origin. Since r is defined as the distance from the origin, the distance of any point (r,θ) from the origin is f(r,θ) = r

Integrating f over the region D, with limits r = 0 to a, and 0≤ θ≤2π , dA = r×dr×dθ

[tex]∬f(r,θ)dA = \int_{0}^{a} \int_{0}^{2π} r (rdr)dθ [/tex]

[tex]= \int_{0}^{2\pi} \int_{0}^{a} r^{2} drdθ = \int_{0}^{2\pi}[\frac{{r}^{3}}{3}]_{0}^{a}dθ[/tex]

[tex]= \int_{0}^{2π}[ \frac{a³}{3} ] dθ = \frac{{a}^{3}}{3} \int_{0}^{2π}dθ[/tex]

[tex]= \frac{a³}{3} [θ]_{0}^{2π} = 2\pi(\frac{a³}{3})[/tex]

Area of disk D with radius 'a' = πa²

So, the average distance from point ( r,θ) in D to the origin is = (1/area of region D)∬f(r,θ)dA

= (1/πa²)( 2πa³/3)

= 2a/3

Hence, required distance is 2a/3.

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Answer:

(1, 2) and (-1, -2). or. (±1, ±2)

Step-by-step explanation:

[tex]{ \sf{f(x) = \frac{4x}{ {x}^{2} + 1 } }} \\ [/tex]

- Simply, a critical number or critical point is gotten by differentiating the function.

From Quotient rule;

[tex]{ \sf{ {f}^{l}(x) = \frac{4( {x}^{2} + 1) - (2x)(4x)}{ {( {x}^{2} + 1)}^{2} } }} \\ \\ { \sf{f {}^{l}(x) = \frac{ {4x}^{2} + 4 - {8x}^{2} }{ {( {x}^{2} + 1) }^{2} } }} \\ \\ { \sf{f {}^{l}(x) = \frac{4(1 - {x}^{2}) }{ {( {x}^{2 } + 1) }^{2} } }}[/tex]

Then equate this derivative to zero;

[tex]{ \sf{0 = \frac{4(1 - {x}^{2} )}{ {( {x}^{2} + 1) }^{2} } }} \\ \\ { \sf{4(1 - {x}^{2} ) = 0}} \\ \\ { \sf{4 - {4x}^{2} = 0}} \\ \\ { \sf{4 {x}^{2} = 4}} \\ \\ { \sf{x = \sqrt{1} }} \\ \\ { \sf{ \underline{ \: x = \pm 1 \: }}}[/tex]

Substitute for x in f(x)

For x = 1

[tex]{ \sf{f(1) = \frac{4(1)}{ {(1)}^{2} + 1} = \frac{4}{2} = 2 }} \\ [/tex]

For x = -1

[tex]{ \sf{f( - 1) = \frac{4( - 1)}{ {( - 1)}^{2} + 1 } = \frac{ - 4}{2} = - 2 }} \\ [/tex]

Therefore points are;

(1, 2) and (-1, -2)

The nullspace of matrix A found by solving the equation Ax=0. It is the nullspace of A is spanned by the vector [-2, 1, 0] and [0, -1, 1]. Any 3x2 matrix B that satisfies AB=0 belongs to the nullspace of A.

To find a 3×2 nonzero matrix B such that AB = 0, we need to find the nullspace of matrix A. The nullspace of a matrix A is the set of all vectors x such that Ax = 0.

Let's first write matrix A in row-echelon form:

1 2 1

0 -1 0

From this, we can see that the pivot variables are x1 and x2, and the free variable is x3. Thus, the general solution to Ax = 0 is given by:

x1 = -2x2 - x3

x2 = x2

x3 = x3

We can now write the columns of matrix B as:

[1, 0]

[-2, 1]

[0, -1]

To show that any such matrix B must have rank 1, we need to show that the columns of B are linearly dependent. Let's assume that B has rank 2. Then, the columns of B are linearly independent, and we can write:

c1[1, -2, 0] + c2[0, 1, -1] = [0, 0, 0]

where c1 and c2 are constants. This gives us the system of equations:

c1 = 0

-2c1 + c2 = 0

c2 = 0

which has only the trivial solution c1 = c2 = 0. This means that the columns of B are linearly dependent, and hence, any such matrix B must have rank 1.

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_____The given question is incomplete, the complete question is given below:

For the given matrix A.= [1 2 1  1 1 1] find a 3 × 2 nonzero matrix B such that AB = 0 that any such matrix B must have rank 1. (Hint: The columns of B belong to the nullspace of A.] 0, Prove A= 13.421

The probability that a randomly selected bottle is correctly placed AND is a Plastic #4 bottle is 0.25 or 25%

What is Conditional probability?

Conditional probability is the probability of an event occurring given that another event has occurred or is known to have occurred. It is denoted by P(A|B), which reads as "the probability of A given B."

The formula for conditional probability is:

P(A|B) = P(A and B) / P(B)

where P(A and B) is the probability of both events A and B occurring, and P(B) is the probability of event B occurring.

The total number of Plastic #2 bottles is 8 (correctly placed) + 5 (incorrectly placed) = 13.

The total number of Plastic #4 bottles is 5 (correctly placed) + 2 (incorrectly placed) = 7.

The probability that a randomly selected bottle is correctly placed AND is a Plastic #4 bottle is given by:

(number of Plastic #4 bottles correctly placed) / (total number of bottles)

So the probability is:

5/20 = 1/4 = 0.25

Therefore, the probability that a randomly selected bottle is correctly placed AND is a Plastic #4 bottle is 0.25 or 25%.

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For the function f(x) = 7/8x² - 14, the x-intercepts are x = -4 and x = 4.

What is a function?

In mathematics, a function is a unique arrangement of the inputs (also referred to as the domain) and their outputs (sometimes referred to as the codomain), where each input has exactly one output and the output can be linked to its input.

To find the x-intercepts of the function f(x), we need to solve the equation f(x) = 0.

f(x) = 7/8x² - 14

Substitute f(x) with 0 -

0 = 7/8x² - 14

Add 14 to both sides -

7/8x² = 14

Multiply both sides by 8/7 -

x² = 16

Take the square root of both sides -

x = ±4

Therefore, the x-intercepts of the function f(x) are x = -4 and x = 4.

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The equation of the circle with center at (-11, 15) and radius 9 is found to be x² + y² + 22x -30y + 337 = 0.

The center of the circle is located at the point (-11, 15). The radius of the circle is given to be 9.

Now, using the standard equation of the circle that has point (a, b) as center and r as the radius, we can write,

(x-a)² + (y-b)² = r²

Now, putting all the values,

(x-(-11))² + (y-15)² = (3)²

Solving further,

x² + 121 + 22x + y² + 225 - 30y = 9

x² + y² + 22x -30y + 337 = 0

So, the equation of the circle is found to be x² + y² + 22x -30y + 337 = 0.

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Answer: 1/12

Step-by-step explanation:

Answer:4/5 are adults. There are 72 adult dogs.

Step-by-step explanation:

Using calculus, we can find the rate of change of area of circle and square that is 83.44 m/sec.

One of the most crucial areas of mathematics that addresses ongoing change is calculus. Calculus is primarily built on the two ideas of derivatives and integrals. The area under the curve of a function is measured by its integral rather than its derivative, which measures the rate of change of the function.

Whereas the integral adds together a function's discrete values over a range of values, the derivative explains the function at a particular point.

Let x be the side of the square and r be the radius of the circle,

If so, the area inside the square but outside the circle is given by:

V = Square area minus Circle area.

hence, area of a square = side² and area of a circle = π(radius)²,

Thus,

V = x² - πr²

Differentiating with respect to time (t)

dV/dt = 2x × dx/dt - 2πr dr/dt

Given,

x = 16

r = 3

dx/dt = 2 m/sec

dr/dt = 1 m/sec

⇒ dV/dt = 2 × 16 × 3 - 2π × 2 × 1

= 96 - 4π

= 96-12.56

≈ 83.44 m/sec

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Answer:

1 1/2 or 3/2

Step-by-step explanation:

Cutting the recipe in half means multiplying each measurement by 1/2.

3 x 1/2 = 3/2 or 1 1/2

The given distribution has mean value of 0.6. The values of m and n can have multiple solutions. sum of the probabilities P(X<=1) is 0.5, variance of X is 2.11, expected value of Y=3X+1 is 4.9, and variance of Y is 19.0.

The given distribution can be represented as follows:

X         -1 0.2 2 0.1 3

P(X)  0.2 0.2 0 0.1 0.5

To find the mean value of X, we use the formula:

E(X) = Σ [ xi * P(X = xi)

E(X) = (-1 * 0.2) + (0.2 * 0.2) + (2 * 0) + (0.1 * 0.1) + (3 * 0.5)

E(X) = 1.3

Since E(X) = 0.6, we can set up the following equation:

E(X) = Σ [ xi * P(X = xi) ] = 0.6

(-1 * 0.2) + (0.2 * 0.2) + (2 * 0) + (0.1 * 0.1) + (3 * 0.5) = 0.6

Simplifying this equation gives us:

0.1 + 1.5 = m * n

m * n = 1.6

We can choose any values of m and n that satisfy this equation. For example, we can choose m = 1 and n = 1.6, or m = 2 and n = 0.8.

P(X <= 1) is the sum of the probabilities of all values of X less than or equal to 1:

P(X <= 1) = P(X = -1) + P(X = 0.2) + P(X = 0.1)

P(X <= 1) = 0.2 + 0.2 + 0.1

P(X <= 1) = 0.5

The variance of X can be found using the formula:

Var(X) = E(X^2) - [E(X)]^2

To find E(X^2), we use the formula:

E(X^2) = Σ [ xi^2 * P(X = xi) ]

E(X^2) = (-1)^2 * 0.2 + 0.2^2 * 0.2 + 2^2 * 0 + 0.1^2 * 0.1 + 3^2 * 0.5

E(X^2) = 4.3

Then, we can calculate the variance:

Var(X) = E(X^2) - [E(X)]^2

Var(X) = 4.3 - 1.3^2

Var(X) = 2.11

The expected value of Y = 3X + 1 can be found using the formula:

E(Y) = E(3X + 1) = 3E(X) + 1

E(Y) = 3(1.3) + 1

E(Y) = 4.9

To find the variance of Y, we use the formula:

Var(Y) = Var(3X + 1) = 9Var(X)

Var(Y) = 9(2.11)

Var(Y) = 19.0

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Step-by-step explanation:

4 i guess... sry i m not good at maths

The ratio of frequencies between G# and D# is: G# / D# = 415.3 / 293.7 ≈ 1.414

To find the missing frequencies for G# and D# using the ratio 1.0595, we need to multiply the frequency of the previous note by 1.0595. Starting from A440, we can use this ratio to calculate the frequencies of G# and D#:

G#: 440 x 1.0595^8 ≈ 830.6 Hz

D#: 440 x 1.0595^6 ≈ 622.3 Hz

The ratio of frequencies between G# and D# is:

830.6 / 622.3 ≈ 1.334

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to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture below.

[tex](\stackrel{x_1}{2}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{21}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{21}-\stackrel{y1}{7}}}{\underset{\textit{\large run}} {\underset{x_2}{4}-\underset{x_1}{2}}} \implies \cfrac{ 14 }{ 2 } \implies 7[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7}=\stackrel{m}{ 7}(x-\stackrel{x_1}{2}) \\\\\\ y-7=7x-14\implies {\Large \begin{array}{llll} y=7x-7 \end{array}}[/tex]

Answer:

f(x) = 7x - 7

or

y = 7x - 7

Step-by-step explanation:

The y intercept is the point (0, -7), so the y intercept is -7.  The slope is the change in y over the change in x.   y is increasing by 7 as x is increasing by 1, so the slope is 7/1 or just 7

y = mx + b  put the slope in for m and the y-intercept for b

y = 7x - 7

Helping in the name of Jesus.

The stone fell from a height of 1.75 m above the top of the window.

We can use the kinematic equation for the vertical motion of an object in free fall to solve this problem:

y = vi*t + (1/2)at^2

where y is the initial height above the top of the window, vi is the initial velocity (which is zero since the stone is dropped), t is the time it takes for the stone to fall past the window (0.31 s), a is the acceleration due to gravity (-9.8 m/s^2).

Since the stone falls past a window that is 2.2 m tall, the final height of the stone is 2.2 m. Substituting these values into the equation, we get:

2.2 m = 0 + (1/2)(-9.8 m/s^2)(0.31 s)^2 + y

Simplifying and solving for y, we get:

y = 2.2 m - (1/2)(-9.8 m/s^2)(0.31 s)^2

y = 2.2 m - 0.45 m

y = 1.75 m

Therefore, the height from stone fell is 1.75 m.

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The probability that Bernard will take 1 green counter and 1 white counter is 0.82.

Let's first find the total number of white and green counters in the bag:

Total counters = 20

Red counters = 7

Green/White counters = 20 - 7 = 13

Now, let's calculate the probability that Bernard will take 2 white counters:

Probability of getting the first white counter = 13/20

Probability of getting the second white counter (after taking one out) = 12/19

Probability of getting 2 white counters = (13/20) * (12/19) = 0.41 (rounded to two decimal places)

Now, let's calculate the probability that Bernard will take 1 green counter and 1 white counter:

Probability of getting 1 green counter = 13/20

Probability of getting 1 white counter (after taking 1 green out) = 12/19

Probability of getting 1 green and 1 white counter = (13/20) * (12/19) = 0.41

However, we have to consider that there are two ways in which Bernard can get 1 green and 1 white counter - he can either get the green counter first and the white counter second, or vice versa. Therefore, we need to multiply the above probability by 2:

Probability of getting 1 green and 1 white counter = 0.41 * 2 = 0.82

Therefore, the probability that Bernard will take 1 green counter and 1 white counter is 0.82.

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Answer:

Step-by-step explanation:

1 ft = 12 in

We can convert 3/4 ft to inches as follows:

3/4 ft = (3/4) x 12 in/ft = 9 in

Therefore, 3/4 ft is equal to 9 inches.

Answer:  Participant A

Step-by-step explanation:

if you divide 120 by 10 you would get 12 jumping jacks per minute and if you divide 140 by 14 you would get 10 jumping jacks per minute

The equation of the line with slope 2 that goes through the point (6,1) in slope-intercept form is y = 2x - 11. This means that the y-intercept of the line is -11, and the slope of the line is 2, which means that for every increase of 1 in x, the line will increase by 2 in y.

To find the equation of a line with a given slope and a point on the line, we can use the point-slope form of a linear equation:

y - y1 = m(x - x1)

where m is the slope and (x1, y1) is the given point on the line.

In this case, the slope is given as 2 and the point (6,1) is on the line. Plugging these values into the equation, we get:

y - 1 = 2(x - 6)

Expanding the right side, we get:

y - 1 = 2x - 12

Adding 1 to both sides, we get:

y = 2x - 11

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Rhiannon arrived home approximately 17 minutes earlier than Alexander.

This is the arithmetic mean and is calculated by adding a group of numbers and then dividing by the count of those numbers. For example, the average of 2, 3, 3, 5, 7, and 10 is 30 divided by 6, which is 5.

To solve this problem, we can use the formula:

time = distance / speed

a) The time it took Alexander to get home is:

time_Alexander = 14 km / 20 km/h = 0.7 hours

The time it took Rhiannon to get home is:

time_Rhiannon = 10 km / 24 km/h = 0.41667 hours

Since Rhiannon's time is smaller than Alexander's, Rhiannon arrived home earlier.

b) The time difference between their arrivals is:

time_difference = time_Alexander - time_Rhiannon = 0.7 hours - 0.41667 hours = 0.28333 hours

To convert this to minutes, we can multiply by 60:

time_difference_in_minutes = 0.28333 hours x 60 minutes/hour ≈ 17 minutes

Therefore, Rhiannon arrived home approximately 17 minutes earlier than Alexander.

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Answer:

To form a rectangle, the piece of wire will have two sides of length x and two sides of length (18 - 2x)/2 = 9 - x. Therefore, the perimeter of the rectangle is given by:

2x + 2(9 - x) = 18 - 2x

The area of the rectangle is given by:

A = x(9 - x)

Expanding this expression, we get:

A = 9x - x^2

To find the dimensions of the rectangle with maximum area, we can differentiate the area expression with respect to x:

dA/dx = 9 - 2x

Setting this equal to zero to find the maximum:

9 - 2x = 0

x = 4.5

So, one side of the rectangle is x = 4.5 cm and the other side is (18 - 2x)/2 = 4.5 cm. Therefore, the dimensions of the rectangle with maximum area are 4.5 cm by 4.5 cm.

To calculate the maximum area, we can substitute x = 4.5 into the area expression:

A = 9(4.5) - (4.5)^2 = 20.25 cm^2

Step-by-step explanation:

Answer:

Step-by-step explanation:

To calculate how much Flounder paid for the bonds, we need to use the present value formula for a bond:

PV = C/(1+r)^1 + C/(1+r)^2 + ... + C/(1+r)^n + F/(1+r)^n

where PV is the present value, C is the annual coupon payment, r is the yield, n is the number of years, and F is the face value.

In this case, Flounder purchased 325 bonds with a face value of $1000 each, so the total face value of the bonds is:

325 * $1000 = $325,000

The coupon rate is 11%, which means that the annual coupon payment is:

0.11 * $1000 = $110

The bonds mature in 10 years, so n = 10. The yield is also 11%, so r = 0.11.

Using these values, we can calculate the present value of the bond:

PV = $110/(1+0.11)^1 + $110/(1+0.11)^2 + ... + $110/(1+0.11)^10 + $1000/(1+0.11)^10

PV = $110/(1.11)^1 + $110/(1.11)^2 + ... + $110/(1.11)^10 + $1000/(1.11)^10

PV = $110/1.11 + $110/(1.11)^2 + ... + $110/(1.11)^10 + $1000/(1.11)^10

PV = $110*(1-(1.11)^-10)/0.11 + $1000/(1.11)^10

PV = $750.98 + $314.23

PV = $1,065.21

Therefore, Flounder paid $1,065.21 for the 325 bonds of Walters Inc.

Answer:

Step-by-step explanation:

Sure! Here's a number line showing the distance of 0.75 kilometers:

0 -------------|-------------|------------- 0.75 km

The "0" on the left represents the starting point (such as home), and the "|---|" in the middle represents the distance of 0.75 kilometers to the destination (such as school).

The confidence interval for the difference between two means with dependent samples when the mean of the differences is d is given by

Confidence Interval = d ± t(0.005, n-1) × (SD / √n)

To calculate the 99% confidence interval for the difference between two means with dependent samples when the mean of the differences is d, you will need to know the standard deviation of the differences, the sample size, and the t-value for the 99% confidence level with (n-1) degrees of freedom.

Assuming that you have all these values, the formula for calculating the confidence interval is

Confidence Interval = d ± t(0.005, n-1) × (SD / √n)

Where

d is the mean of the differences between the two samples.

t(0.005, n-1) is the t-value for the 99% confidence level with (n-1) degrees of freedom. The 0.005 corresponds to the two-tailed alpha level of 0.01, since we are using a 99% confidence level.

SD is the standard deviation of the differences between the two samples.

n is the sample size.

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The answer of the standard normal area for each of the following questions are given below respectively.

Standard normal area refers to the area under the standard normal distribution curve, which is a normal distribution with a mean of 0 and a standard deviation of 1.

a. P(1.24<Z<2.14) = 0.0912

b. P(2.03 <Z<3.03) = 0.0484

c. P(-2.03 <Z<2.03) = 0.9542

d. P(Z > 0.53) = 0.2977

Note: The standard normal distribution is a continuous probability distribution with mean 0 and standard deviation 1. The area under the curve represents probabilities and can be calculated using a standard normal distribution table or a calculator with a normal distribution function.

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The perimeter of the given figures is: Triangle = 4x - 2. Rectangle = 8x - 8, and square = 12x - 8y.

The whole distance encircling a form is referred to as its perimeter. It is the length of any two-dimensional geometric shape's border or outline. Depending on the size, the perimeter of several figures can be the same. Consider a triangle built of an L-length wire, for instance. If all the sides are the same length, the same wire can be used to create a square.

The perimeter of a figure is the sum of all the segments of the figure.

The perimeter of triangle is:

P = 2x - 5 + x + x + 3 = 4x - 2

The perimeter of rectangle is:

P = 2(l + b)

P = 2(3x + 1 + x - 5)

P = 2(4x - 4)

P = 8x - 8

The perimeter of square is:

P = 4(s)

P = 4(3x - 2y)

P= 12x - 8y

Hence, the perimeter of the given figures is: Triangle = 4x - 2. Rectangle = 8x - 8, and square = 12x - 8y.

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Answer:

7 miles

Step-by-step explanation:

Note there are 63,360 inches in a mile.

So, rewrite scale as 1 inch: 1 mile, where inch replaces the unit.

Therefore 7 inches: 7 miles.

Therefore, the only statement that is true is: "The new area is 6 times the original area."

Area is a measure of the size or extent of a two-dimensional surface or region, such as the surface of a square, rectangle, circle, triangle, or any other shape. It is expressed in square units, such as square meters, square feet, or square centimeters.

Here,

If the side lengths of a square are tripled, the new side length will be 2 mm x 3 = 6 mm.

The original area of the square is:

Area = side length x side length = 2 mm x 2 mm = 4 mm²

The new area of the square with tripled side lengths will be:

New area = new side length x new side length = 6 mm x 6 mm = 36 mm²

Therefore, the new area of the square will be 36 mm².

To determine which of the following statements about its area will be true, we need to see which statements are true for the new area of 36 mm²:

A. The new area is 6 times the original area. This statement is true because 36 mm² is 6 times larger than 4 mm².

B. The new area is 3 times the original area. This statement is false because 36 mm² is 9 times larger than 4 mm², not 3 times larger.

C. The new area is equal to the original area. This statement is false because the new area of 36 mm² is much larger than the original area of 4 mm².

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Complete question:

look at this square: 2 mm 2 mm if the side lengths are tripled, then which of the following statements about its area will be true?

The ratio of the new area to the old area will be 2:1

The ratio of the new area to the old area will be 6:1.

The ratio of the new area to the old area will be 1:2.

The ratio of the new area to the old area will be 4:1.