Find the size of each of the unknown angles. Help me plz.

The answer is a=b=60 degree and c=120 degree. Give me solution plz​

Answer:

(2x²+4x-24) in.

Step-by-step explanation:

.

Answer:

Answer: for polynomials in two or more variables, the degree of a term is the sum of the exponents of the variables in the term; the degree (sometimes called the total degree) of the polynomial is again the maximum of the degrees of all terms in the polynomial

Answer:

The probability that the average score of a group of n = 4 people is between 70 and 75=0.13591

Step-by-step explanation:

We are given that

[tex]\mu=65[/tex]

[tex]\sigma=10[/tex]

n=4

We have to find the probability that the average score of a group of n = 4 people is between 70 and 75.

[tex]P(70<\bar{x}<75)=P(\frac{70-65}{\frac{10}{\sqrt{4}}}<\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}<\frac{75-65}{\frac{10}{\sqrt{4}}})[/tex]

[tex]=P(\frac{5}{5}<Z<\frac{10}{5})[/tex]

[tex]=P(1<Z<2)[/tex]

[tex]=P(Z<2)-P(Z<1)[/tex]

[tex]=0.97725-0.84134[/tex]

[tex]=0.13591[/tex]

Hence,  the probability that the average score of a group of n = 4 people is between 70 and 75=0.13591

Answer:

5x+8x+17-9+2y

13x+8+2y

Answer:

13x+8+2y

Step-by-step explanation:

5x+8x=13x

17–9=8

2y=2y

Hi there!  

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I believe your answer is:  

(0.286, 5.587)

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Here’s why:  

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Hope this helps you. I apologize if it’s incorrect.  

Answer:

C= 15

Step-by-step explanation:

[tex] \frac{9}{5} C + 32 = 59 [/tex]

subtracting 32 from both sides

[tex] \frac{9}{5}C = 59 -32 [/tex]

[tex] \frac{9}{5} C = 27[/tex]

Dividing both sides by 9/ 5

[tex]C = 27 \times \frac{5}{9} [/tex]

[tex]C = 3 \times 5[/tex]

[tex]C = 15[/tex]

Answer:

equivalent

Step-by-step explanation:

Answer:

Falso.

Step-by-step explanation:

Sea [tex]d = \frac{a}{b}[/tex] un número racional, donde [tex]a, b \in \mathbb{R}[/tex] y [tex]b \neq 0[/tex], su opuesto es un número real [tex]c = -\left(\frac{a}{b} \right)[/tex]. En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) El exponente es cero.

(b) El exponente es un negativo impar.

(c) El exponente es un negativo par.

(d) El exponente es un positivo impar.

(e) El exponente es un positivo par.

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, [tex]c = d = 1[/tex]. La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

[tex]d' = d^{-n}[/tex] y [tex]c' = c^{-n}[/tex]

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

[tex]d' = \left(\frac{a}{b} \right)^{-n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}[/tex]

[tex]d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]y [tex]c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{b}{a} \right)\right]^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = - \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' \neq c'[/tex], la proposición es falsa.

(c) El exponente es un negativo par.

Si [tex]n[/tex] es par, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' = c'[/tex], la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

[tex]d' = d^{n}[/tex] y [tex]c' = c^{n}[/tex]

[tex]d' = \left(\frac{a}{b}\right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = - \left(\frac{a}{b} \right)^{n}[/tex]

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es par, entonces [tex]d' = c'[/tex] y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.

Answer:

68.5

Step-by-step explanation:

Arc ABE = 360 - 2x

Arc AE = 2x

half the difference between the two arcs is 43

43 = [tex]\frac{1}{2}[/tex] [360 -2x - (2x)]    

Answer:

x=0..............................

Answer:

use average seep hours

top = 77/12 = 6.4 (most)

middle = 6 (middle)

bottom = 50/9 = 5.5 (least)

Step-by-step explanation:

Answer:

-3/4

Step-by-step explanation:

The line passes through the two points which are A(1,1) and B(5,-2) . We know that the slope of the line passing through two points is ,

[tex]\implies Slope =\dfrac{y_2-y_1}{x_2-x_1}\\\\\implies Slope =\dfrac{ -2-1}{5-1}\\\\\implies Slope =\dfrac{-3}{4} \\\\\implies \underline{\underline{ Slope (m) =\dfrac{-3}{4}}}[/tex]

Hence the slope of the line is -3/4 .

Answer:

7

Step-by-step explanation:

evaluate the function means substitute x=-1 and calculate

f(x) = 3x²-4x

f(-1) =f(x=-1) = 3(-1)²-4(-1) =3+4 =7, because (-1)²=1 and -4(-1) =4

Answer:

9. The area of rectangle S is four times bigger than rectangle R

10. (1, 3)

Step-by-step explanation:

To find the solution of the two linear equations:

y=x+2

y=-2x+5

x+2=y=-2x+5

3x=3

x=1

y=1+2

y=3

(1,3)

Answer:

0 and 2

Step-by-step explanation:

Answer:

-8x - 1

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

-10x - 10 + 2x + 9

Step 2: Simplify

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\large\textsf{-10x - 10 + 2x + 9}[/tex]

[tex]\huge\textsf{COMBINE the LIKE TERMS}[/tex]

[tex]\large\textsf{-10x + 2x - 10 + 9}[/tex]

[tex]\large\textsf{-10x + 2x}\\\\\large\textsf{ = \bf -8x}[/tex]

[tex]\large\textsf{-10 + 9}\\\\\large\textsf{ = \bf -1}[/tex]

[tex]\boxed{= \large\textsf{\bf -8x - 1}}\large\checkmark[/tex]

[tex]\boxed{\boxed{\huge\textsf{Answer: \bf -8x - 1 }}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

do you have a pic of the problem

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

the answer is the sqare rute of 25 which is 5

Answer:

Step-by-step explanation:

The change of base formula is

[tex]log_a(b)=\frac{log_{10}b}{log_{10}a}[/tex] so filling in our given:

[tex]log_{13}}(297)=\frac{log_{10}297}{log_{10}13}[/tex] (Note: you do not have to put the base of 10 in the change of base formula because the "normal" base for a log is 10 and that is how your calculator figures it.)

Do this on your calculator to get

[tex]\frac{log297}{log13}=2.2198[/tex] Not sure how many decimal places you needed!

1.4

2.8

3.7 by 10

*Others do by your self*

Step-by-step explanation:

1. 3×4/3= 4

2.⅖×20=8

3.6/5×7/18=7/15

4.10/7×9/5=18/7= 2 4/7. Mixed Fraction

5.4/15×25/8=5/6

6.6×¾= 9/2= 4 1/2. Mixed Fraction

Slope intercept form of a line is, y = mx + c where m is the slope and c is constant.

Judging the given equation y = 2x + 5

Slope (m) of the line is 2,

y-intercept of the line,

y = 2x + 5

y = 2×0 + 5

y = 5

Answered by GAUTHMATH

Answer:

m = 2

y intercept = 5

Step-by-step explanation:

The given equation of the line is ,

[tex]\implies y = 2x +5[/tex]

We know that the Standard equation of Slope Intercept Form of the line is,

[tex]\implies y = mx + c[/tex]

Where ,

On comparing to the Standard form of the line we get ,

[tex]\implies Slope = 2 [/tex]

[tex]\implies y - intercept= 5[/tex]

Answer:

m = 4

Step-by-step explanation:

The slope for the linear points is given by :

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have,

y₂ = 4, y₁ = 0, x₂ = 2, x₁ = 1

Putting all the values,

[tex]m=\dfrac{4-0}{2-1}\\\\\implies m=\dfrac{4}{1}\\\\m=4[/tex]

So, the slope of the line is equal to 4.

[tex]\displaystyle\bf \underbrace{19}_910{\underbrace{1}_9} \Longrightarrow This\: is \:an \:\:arithmetic\:\: progression[/tex]

Answer:

1000

Step-by-step explanation:

Given data

we have the sequence

25, 10, -5, ...

we want to find the 66th term, let us apply the formula

an = a + (n – 1)d

a= 25

n= 66

d= 15

substitute

a66= 25+(66-1)15

a66= 25+(65)*15

a66= 25+975

a66= 1000

Hence the 66th term is 1000

Answer:

Option b, 112°

Step-by-step explanation:

<A+<B=180

or, 68+<B=180

or, <B=112

Answered by GAUTHMATH

Scale is 1 inch to 6 mile.

So, ½ inch = 6 mile/2 = 3 mile

Answer:

275,128

Step-by-step explanation:

"___ more than 3455" is the same as saying "___ added to 3455"

So it will look something like this:

___ + 3,455 = 278,583

Then rearrange the equation to use subtraction to solve it:

278,583 - 3,455 = ____

Plug it in the calculator or solve it by hand, and you have your answer!

(To double check, add 3,455 and 275,128, and you get 278,583)

Hope it helps (●'◡'●)

Proportional Linear Relationships can be expressed in the following ways:

From a graphical point of view, a relationship is proportional and linear if the line representing the equation goes via the origin. It is to be noted that a relationship must be linear for it to be proportional and vice versa.

Thus, it is correct to state that Proportional Linear Relationships can be expressed in the following ways:

An example of an equation that is proportional and linear is:
y = 6x + 8. Note that this linear equation is proportional because it has a constant component.

Learn more about the proportional linear relationships at;
https://brainly.com/question/2143065
#SPJ6

Answer:

(x - [tex]\sqrt{5}[/tex] )(x + [tex]\sqrt{5}[/tex] )

Step-by-step explanation:

x² - 5 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

x² - 5

= x² - ([tex]\sqrt{5}[/tex] )²

= (x - [tex]\sqrt{5}[/tex] )(x + [tex]\sqrt{5}[/tex] )

Answer:

both choices with 2x+y = -3

Step-by-step explanation:

to have the solution (-4, 5), that point must be on both equations/functions, meaning it must be on either one.

in other words, if the point is not on at least one of the functions, it cannot be a solution for that system.

the given function

2x + y = -3

looks like for the point (-4, 5)

2×-4 + 5 = -3

-8 + 5 = -3

-3 = -3

correct.

but

-2x + y = -3

looks like for (-4, 5)

-2×-4 + 5 = -3

8 + 5 = -3

13 = -3

wrong. the point is not on this function.

as we can therefore rule out 2 of the answer options, the other 2 most be correct.

The two equations which when written as a system has a solution of (-4, 5) is; 2x + y = -3 and 2x + y = -3

The correct equations must have same output with the given one when we place -4 and 5 for x and y respectively.

Now, for 2x + y = -3

At x = -4, and y = 5 we have;

2(-4) + 5 = -3

Same with the right hand side.

For -2x + y = -3;

At x = -4, and y = 5 we have;

-2(-4) + 5 = 13

Not the same with the right hand side.

Thus, the two equations with 2x + y = -3 are correct

Read more about Inequalities at; https://brainly.com/question/24372553