Find the position of the center of mass of two bodies points of masses m1 and m2 joined by a rod of mass negligible in length d. Find the acceleration of the center of mass for the case that m1 = 1 [kg] and m2 = 3 [kg] and the applied forces of the figure with d = 2 [m]

Answer:

According to the Big Bang Theory, the density and temperature of the Universe is lower now than in the past.

Hope this answer correct :)

The density and the temperature of the universe should be lower as compared to the past.

According to this theory, it description of the way the universe should be started is provided by the astronomers. The temperature of the universe should be very much hot, the universe size should be small also the universe should be super dense. However, the universe size should be expanded and the temperature should be colder according to the time.

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Answer:

a burning piece of converts Chemical energy into Heat(Thermal) and Light energy

Answer:

It is called Reverse biased

Explanation:

It is reverse bias because the voltage potential side of the battery is connected negative to the donor side or p type material and it is connected positive to the N type material or acceptor side across the diode which increases the diode width of the PN junction.

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

a

 [tex]\epsilon = 7.57 \ V[/tex]

b

 [tex]\epsilon =0.0757 \ V[/tex]

c

  [tex]\epsilon =0.00699 \ V[/tex]

Explanation:

From the question we are told that  

  The number of turns is  N  =  40  turns  

   The  diameter is  [tex]d = 19 \ cm = 0.19 \ m[/tex]

    The initial  magnetic field is [tex]B_i = 0.40 \ T[/tex]

    The final magnetic field is [tex]B_f = 0 \ T[/tex]  

Generally the cross-sectional area of the coil is mathematically represented as

       [tex]A = \pi \frac{d^2}{4}[/tex]

=>    [tex]A = 3.142 * \frac{0.19^2}{4}[/tex]

=>    [tex]A = 0.0284 \ m^2[/tex]

At [tex]\delta t = 0.60 \ s[/tex]

The  induced emf is  

        [tex]\epsilon = - N * \frac{[B_f - B_i ] * A }{\delta t }[/tex]

=>    [tex]\epsilon = - 40 * \frac{[- 0.40 ] * 0.0284 }{0.06}[/tex]

=>   [tex]\epsilon = 7.57 \ V[/tex]

At [tex]\delta t = 6 \ s[/tex]

The  induced emf is  

        [tex]\epsilon = - N * \frac{[B_f - B_i ] * A }{\delta t }[/tex]

=>    [tex]\epsilon = - 40 * \frac{[- 0.40 ] * 0.0284 }{6}[/tex]

=>   [tex]\epsilon =0.0757 \ V[/tex]

At [tex]\delta t = 65 \ s[/tex]

The  induced emf is  

        [tex]\epsilon = - N * \frac{[B_f - B_i ] * A }{\delta t }[/tex]

=>    [tex]\epsilon = - 40 * \frac{[- 0.40 ] * 0.0284 }{65}[/tex]

=>   [tex]\epsilon =0.00699 \ V[/tex]

Answer:

because the colour black absorbs heat which will make you feel much hotter than a white shirt which blocks away heat.

Answer:

Magnitude of the average induced emf = 36.4 mv

Explanation:

Given:

inductance of the coil (L) = 7 mH

Initial current (Ci) = 0.200 A

Final current (Cf) = 1.50 A

Interval = 0.250 s

Find:

Magnitude of the average induced emf

Computation:

E = L(di/dt)

E = 7 [(1.5-0.20) / 0.250]

E = 7[5.2]

Magnitude of the average induced emf = 36.4 mv

Answer:

The correct option is a

Explanation:

Psychology can be defined as the "scientific study" of the mind and behavior of humans and other animals. It involves the use of scientific methods in determining or understanding the social, physiological and biological behaviors in different groups or individual organisms

The correct option is a

The following information should be considered:

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Explanation:

The change in velocity is the final velocity minus the initial velocity.

Δv = v − v₀

Δv = 9 m/s − 2 m/s

Δv = 7 m/s

Answer:

-107 m

Explanation:

Sum of forces in the y direction:

∑F = ma

-qE = ma

a = -qE/m

a = -(1.60×10⁻¹⁹ C) (304 N/C) / (9.11×10⁻³¹ kg)

a = -53.4×10¹² m/s²

Given in the y direction:

v₀ = 0 m/s

a = -53.4×10¹² m/s²

t = 2×10⁻⁶ s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (2×10⁻⁶ s) + ½ (-53.4×10¹² m/s²) (2×10⁻⁶ s)²

Δy = -107 m

Answer:

Sexual harassment.

Explanation:

It is illegal to harass an individual on account of the sex of that person. sexual harassment includes inappropriate sexual advances, sexual favor demands, and other physical or verbal sexual misconduct. Nevertheless, harassment should necessarily not be of a sexual nature and may make derogatory comments about a person's sex. As per the question, it is unlawful to harass Maria by making offensive remarks and comments.

Answer: The reference frame of a passenger in a seat near the center of the train

Explanation:

the speed of light is the same for the passenger and the bicyclist

then the avents are simultaneous fo the passenger not for the bicyclist

the delay between the two events for the bicyclist is

Δt=Δd/vs

where

Δd= lenght of train

vs=speed of sound

the reference frame of a passenger in a seat near the center of the train

Solution:

The space and time transformations are:

x' = γ(x - vt)

t' = γ(t - vx/c²).

In the primed frame the two events are simultaneous, so that Δt' = 0. Also here Δx' = 30. In the unprimed frame Δx' = 30 = γ(Δx - v Δt).......(*)

We also have Δt' = 0 = γ(Δt - vΔx/c²)→Δx = c²Δt/v......(**)

Substituting (**) in (*): 30 = γ(c²Δt/v - vΔt))→Δt = 30/(c²/v - v) =

30/(2c - 0.5c) = 6.7 x 10^(-8)s

Answer:

Gravitational forces and drag forces

Explanation:

All objects that are above a certain distance above the ground has gravitational force acting on them. A falling body like the iclicker has gravitational force pulling it down with a magnitude proportional to its mass and the acceleration due to gravity. As the iclicker fall, it experiences air resistance due to the drag forces on it from the air molecules around. This drag force acts upwards so as to oppose the motion of the iclicker downwards, and the magnitude is minimal when compared to the gravitational force. The resultant force is therefore downwards

Answer:

s the charge is positive, the electric field lines leave it at the point a d = 0.034 cm, the electric field lines go to the right.

Explanation:

The electric field around the cagases oisitvi, field leaving this means that the field lines move away from

If the charge is negative the lines of the field are directed towards the charge

Let's apply this to our case, as the charge is positive, the electric field lines leave it at the point a d = 0.034 cm, the electric field lines go to the right.

Answer:

11

Explanation:

1. You are going to be rounding down.

2. change the metric ton to kg.

1.000 * 10^3 kg = 1000 kg

1000 / 87 = 11.49 = 11 people

Answer:

C - higher volume

Explanation:

The pitch or frequency of sound that an object can produce depends upon its size and configuration . The shape of hand of all are same so the frequency of sound produced by hands of all will be almost same . Hence frequency of sound produced by the hands of Anand and Kumar would have been almost the same .

But the intensity of sound produced by them would have been different . Intensity represents energy a sound carries . Hard hitting clap will produce sound of higher intensity . Intensity of sound is also called high volume sound . So Kumar's clap will carry greater energy and hence greater volume of sound .

Answer:

The  frequencies are  [tex]f_n = n (0.875 )[/tex]

Explanation:

From the question we are told that

   The speed of the wave is  [tex]v = 0.700 \ m/s[/tex]

   The  length of vibrating  clothesline is  [tex]L = 40.0 \ cm = 0.4 \ m[/tex]

Generally the fundamental frequency is  mathematically represented as

        [tex]f = \frac{v}{2 L }[/tex]

=>     [tex]f = \frac{ 0.700 }{2 * 0.4 }[/tex]

=>     [tex]f = 0.875 \ Hz[/tex]

Now  this other frequencies of vibration experience by the clotheslines are know as harmonics and they are obtained by integer multiple of  the fundamental frequency

So  

   The  frequencies are mathematically represented as

       [tex]f_n = n * f[/tex]

=>     [tex]f_n = n (0.875 )[/tex]

Where  n  =  1, 2, 3 ....

Answer:

A)   Therefore laser1 has the maximum closest to the central maximum

B) Δₓ = 0.8

Explanation:

A) The expression for the constructive interference of a double slit is

           d sin θ  = m λ

let's use trigonometry to find the angle

          tan θ = y / L

in interference phenomena the angles are small

         tan θ = sin θ / cos θ = sin θ

         sin θ = y / L

we subjugate

         d y / L = m λ

         y = m λ L / d

let's apply this equation for each case

a) Lares 1 has a wavelength λ₁ = d / 20, the screen is at L = 6.00 m

they ask us for the first axiom m = 1,

let's calculate

           y₁ = 1 (d / 20) 6.00 / d

           y₁ = 0.3

Laser 2, λ₂ = d / 15

            λ₂ = 1 (d / 15) 6.00 / d

           λ₂ = 0.4

Therefore laser1 has the maximum closest to the central maximum

b) let's find the distance of each requested value

second maximum m = 2 of laser 1

            yi '= 2 (d / 20) 6 / d

            y1 '= 0.6

3rd minimum of laser 2

the expression for destructive interference is

               d sinθ = (m + 1/2) lam

               y = (m ) λ L / d

in this case m = 3

let's calculate

              y2 '= (3+0.5) (d / 15) 6 / d

              y2 '=21/15

They ask us for the dalt of these interference

            Δₓ = y3 -y2'          

           Δₓ = 21/15 - 0.6

           Δₓ = 0.8

Answer:

Explanation:

The potential energy stored in a stretch spring is given by the expression below

PE = Work = force * distance

So:

[tex]PE = (kx) * x[/tex]

This then simplifies to:

[tex]PE = kx^2[/tex]

where k is the spring constant= 140 N/m

Given that x= 25 m

Substituting our data into the expression for P.E stored we have

[tex]PE = 140*25^2\\\\PE= 140*625\\\\PE= 87500 J[/tex]

Hence the energy stored in the spring is 87.5kJ

Answer:

My answer to the question is "when its displacement is zero.

Answer:

Explanation:

Area= pier^2

=( 1.88/2)^2= 0.0000000314m^2

Intensity= 0.0265/0.000000314

= 7962W/m^2

Pressure= 2*7962)/345= 5.13*10^-5pa

Answer: 10 miles

Explanation:

5 miles +5 miles= 10 miles (despite the directions)

This is the distance traveled

-------------------------------------

EXTRA STUFF ( you can literally ignore this part)

If you are asked for displacement instead for distance, then it will be 0 miles because you went 5 miles north and 5 miles south, which at the end, you are still at where you originally were.

Hope this helps!! :)

Answer:

See explanation

Explanation:

The electric force exerted on the electron is given by Coulomb's law;

F= KqQ/r^2

F= force on the electron

K= constant of Coulomb's law

q= charge on the electron

Q=charge on the spherical object

r= distance between the charges

F= 9×10^9 × -1.602 × 10^-19 × (-7.2)/(0.03)^2

F= 103.8 × 10^-10/9×10^-4

F= 11.53 ×10^-6

F= 1.153 ×10^-5 N

The force in this case is repulsive

E= F/q

E= 1.153 ×10^-5 N/ 1.602 * 10-19 C

E= 0.719 × 10^14

E= 7.19 × 10^13 NC-1

The electro field around the electron is very strong.

c)

V= Kq/r

V= 9×10^9 × 1.602 × 10^-19/0.001

V= 14418 × 10^-10

V=1.4418 ×10^-6 V

W= qV

W= 1.602×10^-19 C × 1.4418 ×10^-6 V

W= 2.31 ×10^-25 J

Replacing the electron with a positron

F= 9×10^9 × 1.602 × 10^-19 × (-7.2)/(0.03)^2

F= 103.8 × 10^-10/9×10^-4

F= 11.53 ×10^-6

F= -1.153 ×10^-5 N

The force in this case is attractive

Explanation:

We know,

1KN = 1000N

Then, Force(F) = 5*1000N

=5000N

Here,

Power (P)=Work(W)/Time(T)

=Force * distance/ Time (W = F*s)

= 5000*15/75

=1000

So, The power of body or object is 1000Watt.

I hope this will be helpful for you.

Answer:

Explanation:

a )

one rotation per 24 hours

Time period of rotation of the earth T =  time / no of rotation

T = 24 x 60 x 60 s / 1

= 86400 s .

b )

angular velocity = angle of rotation in radian / time

in one rotation , angle made at the centre = 2π radian

= 2 x 3.14 radian

angular velocity ω = 2π / T

= 2 x 3.14 / 86400  radian / s

= 72.68 x 10⁻⁶ radian / s

c )

Relation between linear and angular velocity is as follows

v = ω  x R where R is radius of the earth and v is linear velocity .

linear velocity = 72.68 x 10⁻⁶ x 6.4 x 10⁶ m /s

= 465.152 m /s

=

Answer:

The net force on the object is zero.

Explanation:

An object is moving with constant non-zero velocity. If velocity is constant, it means that the change in velocity is equal to 0. As a result, acceleration of the object is equal to 0. Net force is the product of mass and acceleration. Hence, the correct option is (d) "The net force on the object is zero".

For a constant non-zero velocity the net force on the object is zero.

Velocity is defined as the change in displacement per change in time of motion.

[tex]v = \frac{\Delta x}{\Delta t}= \frac{x_2 - x_1}{t_2 - t_1}[/tex]

where;

Δx is the change in displacement

Δt is the change in time motion

When the change in the displacement is same for equal time interval, the resulting velocity will be constant but non-zero in magnitude.

Also, when the net force acting on an object is zero, the object will move with a constant velocity.

[tex]\Sigma F_x = 0[/tex]

Thus, for a constant non-zero velocity the net force on the object is zero.

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Answer:

916.9C

Explanation:

Using Q= It

Q= 0.54A x 1698s

= 916.9C

The charge delivered by a current with an average of 0.54 A over 28.3 minutes is 916.9C.

Electric charge is defined as the physical property of matter that causes that matter to experience a force when placed in an electromagnetic field that may be positive or negative such that charges repel each other and unlike charges attract each other. An object with the absence of net charge is said to be neutral.

The SI unit of electric charge is the coulomb which is a derived SI unit and is represented by the symbol C.

Electric Charge is represented as

Q= It

where, Q= Electric charge

I= Electric current

t= time

Q= 0.54A x 1698s

= 916.9C

Thus, the charge delivered by a current with an average of 0.54 A over 28.3 minutes is 916.9C.

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Answer:

yes

Explanation:

An object which moves in a circle is accelerating. Accelerations are caused by an unbalanced or net force. The net force is always in the same direction as the acceleration. For objects moving in circles at constant speed, the net force is directed towards the center of the circle about which the object moves.

Answer:

F = 580.25 N

Explanation:

It is given that,

A box at rest on a ramp at an incline of 22°

The normal force on the box is 538 N

We need to find the gravitational force on the box.

The force of gravity acting on an object is equal to its weight. So,

F = mg

But here the box is incline at an angle of 22 degrees

It means that mg will resolve in rectangular components such that, normal force is :

[tex]N=mg\cos\theta\\\\mg=F=\dfrac{N}{\cos\theta}\\\\F=\dfrac{538}{\cos22}\\\\F=580.25\ N[/tex]

So, the gravitational force on the box is 580.25 N.

Answer:

C) 0.5 m/s^2

Explanation:

[tex]Mass = 20kg\\Force = 10 N\\Acceleration = ?\\\\Force = Mass \times Acceleration \\\\Acceleration = \frac{Force}{Mass}\\\\ Acceleration = \frac{10}{20}\\ \\Acceleration = 1/2 = 0.5m/s^2[/tex]