Find the missing side length. Round to the nearest tenth if needed.

Answer:

I think glide reflection

Step-by-step explanation:

a certain video on yt had explained the examples of similar look alike this picture

If a semicircle is rotated about the x axis of the graph then the resulting three dimensional shape will be a sphere.

Given a semicircle on a graph.

A semicircle is a half circle .A sphere is a geometrical object that is a three dimensional  shape , It is the set of points that are all at the same distance r from given point in three dimensional shape.

Rotation is basically an action of rotating around an object or an axis.

If a semicircle is rotated about x axis then the resulting figure will be a sphere. This is because of the fact that when the semi circle is rotated about the x axis then all the points will be at equal distance in all directions from the center.

Hence if a semicircle is rotated about x axis then the resulting figure will be a sphere.

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The percentage of dogs who didn't try to bite the groomer is; 65%.

If follows from the task content that the number of dogs is 300 of which, 0.35 faction of the whole tried to bite the groomer.

Hence, the faction that did not try to bite the groomer is; 0.65 which corresponds to 65% when expressed as a percentage.

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Answer:

[tex]2x^2+1-\dfrac{x}{2x^2-3}[/tex]

Step-by-step explanation:

Use the long division method to divide polynomials:

[tex]\large \begin{array}{r}2x^2\phantom{)))))}+1\phantom{)}\\2x^2-3{\overline{\smash{\big)}\,4x^4-4x^2-x-3\phantom{)}}}\\\underline{-~\phantom{(}(4x^4-6x^2)\phantom{-b))))))}}\\0+2x^2-x-3\phantom{)}\\\underline{-~\phantom{()}(2x^2\phantom{))))}-3)}\\-x\phantom{))))))}\end{array}[/tex]

Therefore:

[tex]\dfrac{4x^4-4x^2-x-3}{2x^2-3}=2x^2+1-\dfrac{x}{2x^2-3}[/tex]

The equation of the function is −3<x<1. See the explanation below.

Given the graph of function f is a parabola,

Thus, equation of parabola  is y=(x+3)(x+1)

⇒y=x² +4x+3

⇒y−3+2²

= x²+2× x ×2+2²

⇒y+1=(x+2)²

We can rewrite this as

 (x+2)² =4× (1/4) ×(y+1)

Comparing the above equation to the equation of a parabola, (x−h)² =4a(y−k), where (h,k) is the coordinates of vertex of parabola, we have,

(h,k)≡(−2,−1)

Hence, the x coordinate of the vertex is −2 which lies in the interval −3<x<1

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The new price after the price increase of Nu 40 will be Nu 840.

The price of a pant after n Nu 40 price increases will be:

= 800 + 40

= 840

The expected weekly sales as a function of the number of price increases will be:

= n - 1) × 800

= (30 - 1) × 800

= 29 × 800

= 23200

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quick answer (A)

ALL real numbers less than or equal to 8

Answer: [tex]\frac{12}{x}[/tex] is an asymptote

Step-by-step explanation:

Apply a table, and plug in values of x into the equation.  For example f(2)=[tex]\frac{12}{2} =6[/tex]. That's one of the points on the graph that we just found (2,6)

Answer: [tex]\frac{\sqrt{6}}{2}[/tex]

Step-by-step explanation:

By the Pythagorean theorem,

[tex]2^2 + (MN)^2 = (\sqrt{10})^2\\\\4+(MN)^2 = 10\\\\(MN)^2 = 6\\\\MN=\sqrt{6}\\\\\implies \tan L=\frac{\sqrt{6}}{2}[/tex]

Answer:

Below.

Step-by-step explanation:

x^2 + 4x  = 18

x^2 + 4x + (2)^2 = 15 + 2^2

x^2 + 4x + 4 = 18 + 4

(x + 2)^2 = 22

x  + 2 = +/- √22

x = -2 + √22 and x =  -2 + √22

x = 2.7  and -6.7  to nearest tenth.

The individuals in this data set that can be gotten is B) Compression bandage styles and this data set contains A) 3 variables, 1 of which is categorical.

A categorical variables serve as the variable type that posses two or more categories.

This categories could be nominal variable, however considering the data , we can see that the first two are quantitative data and the data are:

THE COMPLETE QUESTION IS:

Alek is taking an inventory of styles of compression bandages for work. Here is the data he has collected.

The individuals in this data set are:Choose 1 answer:

A) Blood Centers

B) Compression bandage styles

C) Nurses

This data set contains:Choose 1 Answer:

A) 3 variables, 1 of which is categorical

B) 3 variables, 3 of which are categorical

C) 6 variables, 1 of which categorical

D) 6 variables, 3 of which are categorical

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The simplified form of the expression is x-4 + 2/x-2

Given the following fraction below

f(x) = x^2 + 2x - 6/x-2

Using the long division as shown below;

        x + 4

x-2 |  x^2 + 2x - 6

        x^2 - 2x

_________________

                4x   - 6

                 4x   - 8

___________________

                         2

Hence the simplified form of the expression is x-4 + 2/x-2

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To make x² + 6x = 7 a perfect square, we add 16 to the equation.

In the question, we are asked for the term that must be added to the equation x² + 6x = 7, to make it into a perfect square.

The given equation can be shown as:

x² + 6x = 7,

or, x² + 6x - 7 = 0.

To make it a perfect square, we need to find the b² term as per the 2ab term for the formula, (a + b)² = a² + 2ab + b², where a is x.

This can be shown as:

x² + 6x - 7 = 0,

or, x² + 2(x)(3) - 7 = 0, where we get b = 3.

Thus, b² = 3² = 9, can be obtained by adding 16 to the equation, as -7 + 16 = 9.

Thus, we add 16 to both sides of the equation, to get:

x² + 2(x)(3) - 7 + 16 = 16,

or, x² + 2(x)(3) + 9 = 16,

or, (x + 3)² = 16, which gives us the required perfect square.

Thus, to make x² + 6x = 7 a perfect square, we add 16 to the equation.

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Answer:

See below

Step-by-step explanation:

The larger is  

7-6 = 1 unit bigger than the smaller....and this unit = 24 gallons

   each unit is 24 gallons

larger barrel holds   24 * 7 = 168 gal

smaller barrel holds  24 * 6 = 144 gal

Answer:

Small barrel=144 large barrel=168

Step-by-step explanation:

The ratio is 6 to 7 so lets assign x as a factor.

6x=Small barrel (S)

7x=Large barrel (L)

7x-6x=x

x is the difference so x is 24

x=24

6*24=144=S

7*24=168=L

Answer:

[tex]x = 1 + \sqrt5, x = 1 - \sqrt5[/tex]

Step-by-step explanation:

Hello!

We can solve the quadratic by using the quadratic formula.

Standard form of a quadratic: [tex]ax^2 + bx + c = 0[/tex]

Quadratic Formula: [tex]x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}[/tex]

Given our Equation: [tex]g(x) = x^2 - 2x - 4[/tex]

Plug the values into the equation and solve.

Answer:

Step-by-step explanation:

$1,248.92

Answer:

Step-by-step explanation:

The area of the shaded region = area of larger circle - area of smaller circle = 423.9 yd².

Area = πr²

Area of the shaded region = area of larger circle - area of smaller circle

Area of larger circle = πr² = (3.14)(16²) = 803.84 yd²

Area of smaller circle = πr² = (3.14)(11²) = 379.94 yd²

Area of the shaded region = 803.84 - 379.94 = 423.9 yd².

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Answer:

x = 2/5

y = 3/5

Step-by-step explanation:

**Disclaimer** Hi there! I assumed the question to be a system of equations. The following answer is a method for solving a system of equations. Thus, if it is not, please let me know and I will modify my answer.

Given information:

[tex]\frac{x}{2}+y=\frac{4}{5}[/tex]

[tex]x+\frac{y}{2} =\frac{7}{10}[/tex]

Eliminate fractions by multiplying 10 on both sides of the first equation:

[tex]10*\frac{x}{2}+10*y=10*\frac{4}{5}[/tex]

[tex]5x+10y=8[/tex]

Eliminate fractions by multiplying 10 on both sides of the second equation:

[tex]10*x+10*\frac{y}{2} =10*\frac{7}{10}[/tex]

[tex]10x+5y=7[/tex]

Current system:

[tex]5x+10y=8[/tex]

[tex]10x+5y=7[/tex]

Multiply the second equation by 2:

[tex]5x+10y=8[/tex]

[tex]20x+10y=14[/tex]

Subtract the first equation from the second equation:

[tex](20x+10y)-(5x+10y)=14-8[/tex]

[tex]20x+10y-5x-10y=6[/tex]

[tex](10y-10y)+20x-5x=6[/tex]

[tex]0+15x=6[/tex]

[tex]\boxed{x=\frac{2}{5} }[/tex]

Substitute the x value back to one of the equations to get the y value:

[tex]x+\frac{y}{2} =\frac{7}{10}[/tex]

[tex](\frac{2}{5}) +\frac{y}{2} =\frac{7}{10}[/tex]

[tex](\frac{2}{5}) +\frac{y}{2}-\frac{2}{5} =\frac{7}{10}-\frac{2}{5}[/tex]

[tex]\frac{y}{2} =\frac{3}{10}[/tex]

[tex]\frac{y}{2}*2 =\frac{3}{10}*2[/tex]

[tex]\boxed{y=\frac{3}{5} }[/tex]

Hope this helps!! :)

Please let me know if you have any questions

The answer is x = 2/5, y = 3/5 or (2/5, 3/5)

First, in order to avoid fractional values during calculation, multiply both equations by 10 to simplify.

Multiply the 1st equation by 10 and 2nd equation by 5.

    3. 10 (5x +  10y) = 10 (8) ⇒ 50x + 100y = 80

    4. 5 (10x + 5y) = 5 (7) ⇒ 50x + 25y = 35

Subtract : 3rd equation - 4th equation

Now, substitute for x in the 1st equation to find y.

Step-by-step explanation:

[tex] \frac{y2 - y1 }{x2 - x1} = \frac{3 - - 2}{5 - 0} = \frac{5}{5} = 1[/tex]

(a) The scale used in the analysis is qualitative as the data is not assigned any numeric value.

The daily performance is an ordinal variable, as the values assigned are ranked according to an order of the delivery time.

(b) The frequency table of the given data is:

Variable Frequency

Early  23

On-time  65

Late            9

Lost            3

Total 100.

(c) The relative frequency table for the given data is:

Variable Frequency Relative frequency

Early  23           23/100 = 0.23 = 23%

On-time  65           65/100 = 0.65 = 65%

Late            9             9/100 = 0.09 = 9%

Lost            3             3/100 = 0.03 = 3%

(a) The scale used in the analysis is qualitative as the data is not assigned any numeric value.

The daily performance is an ordinal variable, as the values assigned are ranked according to an order of the delivery time.

(b) The frequency table is a table showing frequency of each variable for the number of times they appear in the data.

The frequency table of the given data is:

Variable Frequency

Early  23

On-time  65

Late            9

Lost            3

Total 100.

(c) The relative frequency for a variable is the ratio of its frequency to the total frequency.

The relative frequency table for the given data is:

Variable Frequency Relative frequency

Early  23           23/100 = 0.23 = 23%

On-time  65           65/100 = 0.65 = 65%

Late            9             9/100 = 0.09 = 9%

Lost            3             3/100 = 0.03 = 3%

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Answer:

C.

Step-by-step explanation:

Using the given property, we conclude that:

f(4) = 8

We know that our function has the property:

5*f(x) = f(5*x)

Now, we also know that:

f(20) = 40

Notice that we can rewrite:

f(20) = f(5*4)

Using the above property, we know that:

f(20) = f(5*4) = 5*f(4) = 40

Using the last part:

5*f(4) = 40

f(4) = 40/5 = 8

f(4) = 8

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Finding the roots of an equation is done using the equation systems  [tex]y=2x^{3}+4x^{2} -x+5[/tex] & [tex]y= -3x^{2} +4x+9[/tex] .

This equation seems to have the following form:[tex]2x^{3}+4x^{2} -x+5= -3x^{2} +4x+9[/tex]

We must assess the appropriate set of equations that may be utilized to identify the equation's roots.

By drawing the equations' graph, we may determine the equation's root. We can suppose that the left and right sides of the following equations are two independent equations for the sake of graphing.

Therefore,

[tex]y=2x^{3}+4x^{2} -x+5[/tex]

[tex]y= -3x^{2} +4x+9[/tex]

The graphs of these two equations are now shown in the identical coordinate plane. The roots of the equation given will be the crossing point(s).

The equation system that we may utilize to get the root of the formula given is thus,

[tex]y=2x^{3}+4x^{2} -x+5[/tex]

[tex]y= -3x^{2} +4x+9[/tex]

So, the correct answer is option C.

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The center of the circle lies on the x-axis

The radius of the circle is 3 units.

The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

The standard equation of a circle is expressed as:

[tex]x^2 + y^2 + 2gx + 2fy + C = 0[/tex]

Where

Given a circle whose equation is

Let's get the center of the circle

2gx = -2x

2g = -2

We have that;

g = -1

Similarly, 2fy = 0

given that

f = 0

Centre = (-(-1), 0) = (1, 0)

This explains that the center of the circle lies on the x-axis

We move further to the radius

r = radius = √g²+f²-C

radius = √1²+0²-(-8)

radius =√9

= 3 units

The radius of the circle is 3 units.

For the circle x² + y² = 9, the radius is expressed as:

r² = 9

r = 3 units

Hence the radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

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The correct statements are –6x + 15 < 10 – 5x and a number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

Inequality are expressions not separated by an equal sign. Given the inequality expression:

–3(2x – 5) < 5(2 – x)

Expand

-6x +15 < 10 - 5x

Collect the like terms

-6x+5x < 10 - 15

-x <-5

x > 5

Hence the correct statements are –6x + 15 < 10 – 5x and a number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

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Answer:

C.) [tex]x^{\frac{3}{2} } y^{\frac{19}{2} }[/tex]

Step-by-step explanation:

To simplify the expression, you need to:

1.) Rewrite [tex]\sqrt{xy^{3} }[/tex]

    -----> [tex]\sqrt{x} = x^{\frac{1}{2} }[/tex]

2.) Distribute the exponents

    -----> When an exponent is raised to another exponent, they should be multiplied

3.) Create common denominators

4.) Combine the variables

    -----> When two variables with exponents are being multiplied, the exponents should be added

The equivalent expression of [tex]\frac{3x^{-6}y^{-3}}{15x^2y^{10}}[/tex] is [tex]\frac{1}{5x^{8}y^{13}}[/tex]

The expression is given as:

[tex]\frac{3x^{-6}y^{-3}}{15x^2y^{10}}[/tex]

Divide 3 and 15 by 3

[tex]\frac{x^{-6}y^{-3}}{5x^2y^{10}}[/tex]

Apply the law of indices

[tex]\frac{1}{5x^{2+6}y^{10+3}}[/tex]

Evaluate the sum

[tex]\frac{1}{5x^{8}y^{13}}[/tex]

Hence, the equivalent expression of [tex]\frac{3x^{-6}y^{-3}}{15x^2y^{10}}[/tex] is [tex]\frac{1}{5x^{8}y^{13}}[/tex]

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