Find the mean absolute deviation (MAD) of the data in the bar chart below.
Please answer

Find The Mean Absolute Deviation (MAD) Of The Data In The Bar Chart Below.Please Answer

Answers

Answer 1

Mean absolute deviation of the data is 1.

What is mean absolute deviation?

The mean absolute deviation of a dataset is the average distance between each data point and the mean. It gives us an idea about the variability in a dataset.

Given, In bar chart

Number of artists n = 4

Number of albums for Lil Shane x₁ = 7

Number of albums for Ben Raises x₂ = 9

Number of albums for Nicky x₃ = 6

Number of albums for Underdog x₄ = 6

Mean of the number of albums

μ = (7 + 9 + 6 + 6)/4 = 28/4 = 7

|μ - x₁| = |7 - 7| = 0

|μ - x₂| = |7 - 9| = |-2| = 2

|μ - x₃| = |7 - 6| = 1

|μ - x₄| = |7 - 6| = 1

Mean absolute deviation = ∑|x - μ|/n

= (0 + 2 + 1 + 1)/4

= 1

Hence, 1 is the mean absolute deviation (MAD) of the data in the bar chart.

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Related Questions

The sixth-grade class was asked the question, “Where would you prefer to go on a field trip?” The results are shown in the table. What percent of the sixth-grade class preferred each location? Write your answers in the table and round to the nearest whole percent, if necessary.

Field Trip Location Number of Students Percent​
Dairy farm 27 ​
%
Robotics center 65
%​
Lion tamer at the circus 70
%​
Wildlife recovery center 58
%​

Answers

Field Trip Location Number of Students Percent

Dairy farm 27 17%

Robotics center 65 41%

Lion tamer at the circus 70 44%

Wildlife recovery center 58 37%

To calculate the percentage, we divide the number of students who preferred each location by the total number of students and then multiply by 100. We round to the nearest whole percent.

For the dairy farm: (27/160) x 100 ≈ 16.875 ≈ 17%

For the robotics center: (65/160) x 100 ≈ 40.625 ≈ 41%

For the lion tamer at the circus: (70/160) x 100 ≈ 43.75 ≈ 44%

For the wildlife recovery center: (58/160) x 100 ≈ 36.25 ≈ 37%

Evaluate z- (y-z) if z= 4 and y =6

Answers

Answer: 2

4 – (6-4) = 2

Answer: 2- (y= 6 , z=2)

Step-by-step explanation:

If z = 4 and y = 6, then we can substitute these values into the expression:

z - (y - z) = 4 - (6 - 4)

Expanding the subtraction in the parentheses, we get:

z - (y - z) = 4 - (6 - 4) = 4 - (2) = 4 - 2

Finally, solving for the subtraction:

z - (y - z) = 4 - 2 = 2

So, the value of the expression z - (y - z) when z = 4 and y = 6 is 2.

What is the area of this figure?
23 km
8 km
6 km
11 km
6 km
15 km
11 km
34 km

Answers

The area of the figure is calculated as: 536 km².

How to Find the Area of a Figure?

The area of the figure given can be found by decomposing the figure into three rectangles.

Area of rectangle 1:

Length = 15 km

Width = 11 km

Area = length * width = 15 * 11 = 165 km²

Area of rectangle 2:

Length = 6 + 11 = 17 km

Width = 11 km

Area = 17 * 11 = 187 km²

Area of rectangle 3:

Length = 23 km

Width = 8 km

Area = 23 * 8 = 184 km²

The area of the figure = 165 + 187 + 184 = 536 km²

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Find the binary representation of each of the following positive integers by working through the algorithm by hand. You can check your answer using the sage cell above. (a) 64 (b) 67 (c) 28 (d) 256
Previous question

Answers

The algorithm to write the binary representation of the positive integer "64" is explained below and the binary representation of 64 is 1000000 .

The steps  to find the binary representation of 64 :

Step(i) : 64 divided by 2 gives a quotient of 32 with a remainder of 0.

Step(ii) : 32 divided by 2 gives a quotient of 16 with a remainder of 0.

Step(iii) : 16 divided by 2 gives a quotient of 8 with a remainder of 0.

Step(iv) : 8 divided by 2 gives a quotient of 4 with a remainder of 0.

Step(v) : 4 divided by 2 gives a quotient of 2 with a remainder of 0.

Step(vi) : 2 divided by 2 gives a quotient of 1 with a remainder of 0.

Step (vii) : 1 divided by 2 gives a quotient of 0 with a remainder of 1.

So , we observe that  the remainders, read from bottom to top, are 1000000.

Therefore, the binary representation of "64" is 1000000 in binary.

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The given question is incomplete , the complete question is

Find the binary representation of the positive integer "64" by working through an algorithm by hand .

Let n be the outer unit normal of the elliptical shell. S: 4x²+9y²+36z²= 36

Answers

The outer unit normal vector at any point (x, y, z) on the surface of the ellipsoid is given by:

n = <8x, 18y, 72z> / sqrt((8x)² + (18y)² + (72z)²)

What is expression ?

In mathematics, an expression is a combination of one or more values, variables, operators, and/or functions that are evaluated to produce a single result.

For example, 3 + 4 is an expression that evaluates to 7, and (x + 2) / (y - 1) is an expression that can be evaluated for different values of x and y.

Expressions can be simple or complex, and can involve arithmetic operations (addition, subtraction, multiplication, division), algebraic operations (such as factoring or expanding), trigonometric functions, logarithmic functions, and many other mathematical operations.

Expressions are often used in mathematical modeling and problem solving, and can be written in a variety of formats, including symbolic notation, numerical values, or verbal descriptions.

According to given condition :

The equation you provided, 4x² + 9y² + 36z² = 36, represents an ellipsoid centered at the origin (0,0,0) with semi-axes of length 3, 2, and 1 in the x, y, and z directions, respectively.

The outer unit normal vector, n, at a given point on the surface of the ellipsoid is perpendicular to the tangent plane at that point. To find the normal vector at a given point (x, y, z) on the surface, we can take the gradient of the function 4x² + 9y² + 36z², which gives us:

∇(4x² + 9y² + 36z²) = <8x, 18y, 72z>

At any point on the surface of the ellipsoid, this gradient vector is proportional to the normal vector, and the constant of proportionality is the reciprocal of the length of the gradient vector:

n = k<8x, 18y, 72z>

To find the value of k, we need to normalize n so that its length is 1. That is,

|n| = sqrt((8x)² + (18y)² + (72z)²) = 1

Solving for k, we get:

k = 1 / sqrt((8x)² + (18y)² + (72z)²)

Thus, the outer unit normal vector at any point (x, y, z) on the surface of the ellipsoid is given by:

n = <8x, 18y, 72z> / sqrt((8x)² + (18y)² + (72z)²)

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288

toy cars can be kept in either 16

cuboidal boxes or 18

cubical boxes. Find out the number of toy cars that can be kept in: 9

cuboidal boxes and 8

cubical boxes.

Answers

Nine cuboidal boxes and eight cuboidal boxes can each hold 153 and 136 toy cars, respectively.

How is the average calculated?

The ratio of the sum of all provided observations to the total number of observations is the arithmetic mean, which is another name for the average formula. So, any sample of data may have its arithmetic mean determined using the average formula.

What does arithmetic mean?

The mean or arithmetic average are terms that are frequently used to refer to the arithmetic mean. It is determined by adding up all the numbers in a given data collection, then dividing that total by the number of items in the data set. For uniformly distributed integers, the middle number is the arithmetic mean (AM).

Given: There are two storage options for 288 toy cars: 16 and 18 cuboidal boxes.

supposing there were 288 toy cars stored in 16 toy cars.

There are 18 toy cars in a box of 288 (288 / 16) toy cars.

if 288 toy cars were housed in 18 toy cars.

There are 16 toy cars in a box that holds 288 toy cars.

Average: 18 + 16 / 2 = 34 / 2 = 17 toy cars.

Nine boxes of toy cars include 153 toy cars (9 * 17).

eight boxes of toy cars include 136 toy cars (8 * 17)

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If cos(θ)>0 and tan(θ)<0, in which quadrant does θ lie?

Answers

Answer:

Quadrant IV

Step-by-step explanation:

cos(∅) > 0 means cos (∅) is positive

tan (∅) < 0 means tan (∅) is negative

thus,

∅ lies in Quadrant IV

(6.82x-2.53y - 5.72)-(-5.72 +9.45y-8.11x)

Answers

A mathematical statement known as an equation is created by joining two expressions with an equal sign. For instance, 3x - 5 = 16 is an equation. This equation may be solved, and the result shows that the value of the variable x is 7.

What is meant by mathematical equation?The definition of an equation in algebra is a mathematical statement that proves two mathematical expressions are equal. Consider the equation 3x + 5 = 14, in which the terms 3x + 5 and 14 are separated by the word "equal." Equations are collections of variables, constants, and mathematical operations such as addition, subtraction, multiplication, or division. Each equation is balanced by an equal sign.The left-hand side (LHS) of the equation is on the left, while the right-hand side is on the right (RHS).A mathematical equation is a claim that the values of two expressions are equal. A mathematical equation essentially states that two things are equal.

Given,

(6.82x - 2.53y - 5.72) - (-5.72 + 9.45y - 8.11 x)

Simplifying the above equation,

= 6.82x - 2.53y - 5.72 - (-5.72 + 9.45y - 8.11 x)

= 6.82x - 2.53y - 5.72 + 5.72 - 9.45y + 8.11 x

Simplify

6.82x - 2.53y - 5.72 + 5.72 - 9.45y + 8.11 x : 14.93x - 11.98y

Then we get,

= 14.93x - 11.98y

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A firm manufactures a commodity at two different factories, Factory X and Factory Y. The total cost in dollars of manufacturing depends on the quantities, x and y produced at each factor, respectively, and is expressed by the joint cost function: C(x,y)=2x^2+xy+4y^2+1600
If the companies objective is to produce 500 units per month while minimizing the total monthly cost of production, how many units should be produced at each factory. (Round your answer to the nearest whole number.)
Units to be produced to minimize costs:
x =
y=
Now determine the minimum cost. Minimal cost =$

Answers

From the given data, the company can produce 500 units per month at a minimum cost of $140,000.

To minimize the total monthly cost of production while producing 500 units per month, we can use the method of Lagrange multipliers. Let L(x, y, λ) be the Lagrangian function:

L(x, y, λ) = 2x² + xy + 4y² + 1600 + λ(500 - x - y)

We need to find the values of x and y that minimize L(x, y, λ), subject to the constraint that 500 units are produced per month. Taking partial derivatives of L with respect to x, y, and λ and setting them to zero, we get:

∂L/∂x = 4x + y - λ = 0

∂L/∂y = x + 8y - λ = 0

∂L/∂λ = 500 - x - y = 0

Solving these equations simultaneously, we get:

x = 200

y = 150

λ = 26/3

Therefore, to minimize the total monthly cost of production while producing 500 units per month, the company should produce 200 units at Factory X and 150 units at Factory Y.

To find the minimum cost, we substitute the values of x and y into the joint cost function:

C(x, y) = 2x² + xy + 4y² + 1600

C(200, 150) = 2(200)² + (200)(150) + 4(150)² + 1600

C(200, 150) = 140,000

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Question 4 Part C (3 points): Landon has $16 and wants to buy a combination of sandwiches and chips to feed his 4 teammates. Each sandwich costs $4 and each bag of chips costs $2. This system of inequalities models the scenario.


4x + 2y ≤ 16


x + y ≥ 4


Is the point (2,5) included in the solution area for the system? Justify your answer mathematically.

Answers

The point (2,5) satisfies only one of the two inequalities in the system, it is not included in the solution area for the system.

To see if the point (2,5) is in the system's solution area, we need to see if it satisfies both inequalities in the system:

4x + 2y ≤ 16

4(2) + 2(5) ≤ 16

8 + 10 ≤ 16

18 ≤ 16

Because this inequality is false, point (2,5) fails to satisfy the first inequality.

x + y ≥ 4

2 + 5 ≥ 4

7 ≥ 4

Because this inequality holds, the point (2,5) satisfies the second inequality.

Because point (2,5) satisfies only one of the system's two inequalities, it is not included in the system's solution area. Landon cannot, therefore, spend $16 on two sandwiches and five bags of chips to feed his four teammates.

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The vertices of a feasible region are (1,2) (7,3) (5,1). What is the minimum value of the function P=x-2y

Answers

The minimum value of the function P over the feasible region is -3, which occurs at the point (1,2).

What is a function?

The expression that established the relationship between the dependent variable and independent variable is referred to as a function. In the function as the value of the independent variable varies the value of the dependent variable also varies.

To find the minimum value of the function P = x - 2y over the feasible region determined by the vertices (1,2), (7,3), and (5,1), we need to evaluate the function at each of these points and find the lowest value.

P(1,2) = 1 - 2(2) = -3

P(7,3) = 7 - 2(3) = 1

P(5,1) = 5 - 2(1) = 3

Therefore, the minimum value of the function P over the feasible region is -3, which occurs at the point (1,2).

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determine the number of solution for the equation shown below? 4x+6=4-6

Answers

Answer: X= -8

Step-by-step explanation: 4 minus 6 equals to -2. So for 4x + 6 to equal -2 you have to do 4x times -8 to get -8 then add it by 6 to get -2.

4 times 8 = -8 + 6 = -2

consider the setup of double-slit experiment in the schematic drawing below. one of the double-slit interference maxima is located at the first single-slit diffraction minimum.

Answers

At y there is a minimum for single-slit diffraction and a maximum for double-slit interference, as noted in the question.

For single-slit diffraction, the first minimum occurs when

sin θ = λ/a.

and double-slit interference maxima occur when

(m) λ / d = sin θ --------- (2)

The first diffraction minimum for single-slit diffraction and the fourth double-slit interference maximum (m = 4) occur at the same position y, as seen in the figure below.

On the left of the screen, the dashed curve is due to single-slit interference. On the right of the screen, the dashed curve is due to double-slit interference. The positive direction is reflected on each of the two sides of the screen and the screen position is zero amplitude.

Since the single-slit diffraction minimum masks the fourth double-slit interference maxima, one must estimate where the fourth double-slit maxima occur using the spacing between the double-slit interference pattern appearing on the right-hand side of the display screen, as seen in the figure above.

Using Eq. 1 and 2, we have

sin θ / λ = 1/ a = (m) 1/ d

d/ a = (4)

= 4.

Therefore, At y there is a minimum for single-slit diffraction and a maximum for double-slit interference, as noted in the question.

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The correct question is:

Consider the setup of double-slit experiment in the schematic drawing below. One of the double-slit interference minima is located at the first single-slit diffraction minimum. Determine the ratio d/a ; i.e., the slit separation d compared to the slit width a. Use a small angle approximation; e.g., sin θ ≈ tan θ ≈ θ and cos θ ≈ 1.

1. d/a = 13/2

2. d/a = 6

3. d/a = 15/2

4. d/a = 5

5. d/a = 7

6. d/a = 9/2

7. d/a = 11/2

8. d/a = 17/2

9. d/a = 4

10. d/a = 8

2. In the Accounting Equation, the three things you need to include are
Worth 4.000 points.
O A. net income, liabilities and profit
OB. assets, profit and revenue
O C. calendar year profit, expenses and net income
OD. assets, liabilities and owner's equity

Answers

Answer:

e

Step-by-step explanation:

e

A decorative gift box is in the shape of a triangular prism as shown. What is the lateral surface area of the box? Draw a net if necessary.

Answers

The lateral surface area of the box is given as follows:

112.5 in².

How to obtain the area of a rectangle?

The area of a rectangle is given by the multiplication of the width and the length of the triangle, as follows:

A = lw.

The lateral of the triangular box for this problem is composed by two rectangles, with dimensions given as follows:

5 inches and 10 inches.5 inches and 12.5 inches.

Hence the lateral surface area of the box is obtained as follows:

5 x 10 + 5 x 12.5 = 112.5 in².

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The question is: Find a recurrence relation for number of ternary strings of length n that contain two consecutive zeros.
I know for ternary strings with length one, there are 0. For a length of 2, there is just 1 (00), and for a length of 3, there are 5 (000,001,002,100,200).
I did a similar problem, finding a relation for the number of bit strings of length n with two consecutive zeros:
an=an−1+an−2+2n−2
Since you can add "1" to the end of all the an−1
strings, "10" to all the an−2
strings, and "00" any string of size n−2
.
For the ternary string problem, I'm pretty sure you would replace the 2n−2
with 3n−2
, but confused about the other terms of the relation. My guess is that it would have the coefficient 2
in front of the other terms, since you can add either 1
or 2
to the end of an−1
and either 01
or 02
at the end of an−1
.
So I believe the answer for the relation is:
an=2an−1+2an−2+3n−2

Answers

The recurrence relation for the number of ternary strings of length n that contain two consecutive zeros looks correct.

You can see that the first few terms match with your calculations:

a_1 = 0 (no possible strings)

a_2 = 1 (only one possible string: "00")

a_3 = 5 (possible strings: "000", "001", "002", "100", "200")

To explain your reasoning:

You can add "1" or "2" to the end of all the a_{n-1} strings, so there are 2a_{n-1} possible strings with n-1 length that end with "1" or "2".

You can add "01" or "02" to the end of all the a_{n-2} strings, so there are 2a_{n-2} possible strings with n-2 length that end with "01" or "02".

To count the number of strings of length n that contain two consecutive zeros, you need to add the strings that end with "00". There are 3^{n-2} possible strings of length n-2 that you can append "00" to.

Therefore, the recurrence relation is:

a_n = 2a_{n-1} + 2a_{n-2} + 3^{n-2}

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can someone help me with this please

Answers

The equation for the polynomial is P(x) = -1/64(x + 4)(x + 1)(x - 2)(x - 4)^2

How to determine the equation for the polynomial

From the graph, we have the following parameters that can be used in our computation:

A zero at x = -4 A zero at x = -1 A zero at x = 2 A zero at x = 4 with a multiplicity of two (because the graph touches and not pass through the graph at this point)

A polynomial is represented as

P(x) = (x - zero)^multiplicity

Using the above as a guide, we have the following:

P(x) = a(x + 4)(x + 1)(x - 2)(x - 4)^2

The y-intercept of the graph is (0, 2)

So, we have

a(0 + 4)(0 + 1)^3(0 - 2)(0 - 4)^2 = 2

Evaluate

-128a = 2

So, we have

a = -1/64

The equation becomes

P(x) = -1/64(x + 4)(x + 1)(x - 2)(x - 4)^2

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neralize
Nathan has two 8-foot boards. He cuts one board into
-foot pieces. He cuts the other board into-foot pieces.

Answers

According to the information, he gets 6 pieces in total after cutting his boards.

How to find the number of pieces that Nathan gets?

To find the number of pieces Nathan gets, we must divide the total length of the boards by the length of the pieces. Below is the procedure:

8 feet / 2 feet = 4 pieces.8 feet / 4 feet = 2 pieces.2 pieces + 4 pieces = 6 pieces.

According to the above, from one table he gets 4 2-feet pieces, from the other he gets 2 4-feet pieces. Additionally, in total he would have 6 pieces.

Note: This question is incomplete because there is some information missing. Here is the complete information:

Nathan has two 8-foot boards. He cuts one board into 2-foot pieces, and he cuts the other board into 4-foot pieces.

How many pieces does he get?

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Try it
Evaluate the step function for the given input values.
-4, -3 ≤ x < -1
-1,
-1 ≤ x < 2
2 ≤ x < 4
X24
g(x) =
g(2) =
g(-2) =
g(5) =
lating a Step Function Us
3,
5,
4

Answers

The value of g(x) = [x] At, 2 ≤ x < 3, g(x) = 2, It is also known as the greatest integer function.

What is a step function?

A function on real numbers is called a step function if it can be written as a finite linear combination of indicator functions of intervals.

Informally speaking, a step function is a piecewise constant function having only finitely many pieces.

A step function f(x) = [x] is called a step function where the output is the greatest integer less than or equal to the input.

The function is g(x) = [x].

At, - 1 ≤ x < 0, g(x) = 0.

At, 1 ≤ x < 2, g(x) = 1.

At, 2 ≤ x < 3, g(x) = 2.

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I need help with the volume of the following rectangular prism of 16 1/4 and 1/2

Answers

Answer:

To find the volume of a rectangular prism, you need to multiply its length, width, and height.

Assuming that the dimensions are in inches, we have:

Length = 16 inches + 1/4 inch = 16.25 inches

Width = 1/2 inch

Height = some unknown value (not given in the question)

So, if we know the height, we can calculate the volume of the rectangular prism. If the height is, for example, 10 inches, then:

Volume = Length x Width x Height

Volume = 16.25 inches x 0.5 inches x 10 inches

Volume = 81.25 cubic inches

Therefore, the volume of the rectangular prism depends on its height, which is not given in the question.

Please solve quickly! Within 30 minutes would be great!

Please solve for the variable indicated.

A=1/2h(b+B), solve for h

If you could break it down step by step that would be super helpful! I’m very confused. Thank you!

Answers

1) Multiply both sides of the equation by 2:

2(A)=2[1/2h(b+B)

2A=2/2h(b+B)

2A=1h(b+B)

2A=h(b+B)

2) Divide both sides of the equation by (b+B):

(2A)/(b+B)=[h(b+B)]/(b+B)

2A/(b+B)=h

h=2A/(b+B)

Answer: [tex]h=2\frac{A}{(b+B)}[/tex]

hope this helped!!

NEED HELP FAST I WILL GIVE THE BRAINLIEST AND 15 pts

Answers

The area of the triangle ΔABC is given by A = √275 units²

What is a Triangle?

A triangle is a plane figure or polygon with three sides and three angles.

A Triangle has three vertices and the sum of the interior angles add up to 180°

Let the Triangle be ΔABC , such that

∠A + ∠B + ∠C = 180°

The area of the triangle = ( 1/2 ) x Length x Base

For a right angle triangle

From the Pythagoras Theorem , The hypotenuse² = base² + height²

if a² + b² = c² , it is a right triangle

if a² + b² < c² , it is an obtuse triangle

if a² + b² > c² , it is an acute triangle

Given data ,

Let the area of the triangle ΔABC be A

Now , the measure of side BD = 5

The measure of side ED = 11

So , the measure of side EB = 11 - 5 = 6

The measure of side AD = 10

And , the measure of side CE = 4

For a right angle triangle

From the Pythagoras Theorem , The hypotenuse² = base² + height²

From the triangle ΔABD ,

The measure of side AB = √ ( AD )² - ( BD )²

The measure of side AB = √ ( 100 - 25 )

The measure of side AB = √75 units

And , from the triangle ΔBCE

The measure of side CB = √ ( EB )² - ( CE )²

The measure of side CB = √ ( 36 - 16 )

The measure of side CB = √20 units

And , from the triangle ΔABC

The measure of side AC = √ ( AB )² - ( CB )²

The measure of side AC = √ ( 75 - 20 )

The measure of side AC = √55 units

And , the area of triangle ΔABC = ( 1/2 ) x AC x BC

The area of triangle ΔABC = ( 1/2 ) x √55 x √20

The area of triangle ΔABC = ( 1/2 ) x √1100

The area of triangle ΔABC , A = ( 1/2 ) x 2√275

The area of triangle ΔABC , A = √275 units²

Hence , the area of triangle ΔABC is √275 units²

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Two buses leave Charlotte at the same time traveling in opposite directions. One bus travels at 63mph and the other at 62mph. How soon will they be 187.5 miles apart?

Answers

1 1/2 hours
I’m one hour they are 125 miles apart
63 + 62 = 125
Cut them I half (adds half an hour)
31 +31.5 = 62.5
125+62.5= 187.5
So it takes 1 hour and 30 minutes for them to be 187.5 miles apart

Given the expression -12x² + 3-4x-10, answer the questions below.
BTP THIEMESLA
MATERIANGELOOS!
CREARES Y RECREINAGE
En Menasgitteell
paleta balia
CARE SEGN 400
MASHIL MOTEL EGTE
MODEJMLE 25000
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HUNG TRUE
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TRARON SE Shiptare
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A. In the expression -12x² + 3-4x -10, what are the terms?
Type the constant terms in the box below.
Tans Slide
B. In the expression -12x² + 3-4x -10, what are variable terms?
Type the variable terms in the box below.

Answers

Answer:

Step-by-step explanation:

12x2  +3-4-10

You are buying a pair of jeans and several shirts at the store. If the jeans cost $40, and the shirts are $11 each, how many shirts can you buy if the total is $106?

Answers

Answer:

6 Shirts

Step-by-step explanation:

if you buy 1 pair of jeans you can buy 6 pairs of shirts since 6 x 11 = 66

66 + 40 = 106

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The distance between the cities of Palo Alto and Beijing is approximately equal to 8990.334 kilometers.

How to determine the distance between two cities on Earth

In this problem we must determine the distance between the cities of Palo Alto and Beijing, whose astronomical coordinates are given in spherical coordinates. The distance is the sum of distance along the terrestrial arc, whose formula can be derived from circular arc formula:

s = (Δθ / 180°) · 2π · R + (Δλ / 180°) · 2π · R

Where:

Δθ - Change in the latitude, in degrees. Δλ - Change in the longitude, in degrees. R - Radius, in kilometers.

Now we proceed to determined the distance between the two cities:

s = [(39.914° - 37.429°) / 180°] · 2π · (6367.5 km) + [[116.392° - (- 122.138°)] / 180°] · (6367.5 km)

s ≈ 8990.334 km

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1. Which expression can be used to name the angle below?

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ANSWER: The third option: C, or Angle A.

In exercise 5.12, we were given the following joint probabiltiy density function for the random variables Y1 and Y2, which were the proportions of two components in a sample from a mixture of insecticide:f(y1,y2)={2, 0<=y1<=1, 0<=y2<=1, 0<=y1+y2<=1. 0, elsewhere}For the two chemicals under consideration, an important quantity is the total proportion Y1+Y2 found in any sample. Find E(Y1+Y2) and V(Y1+Y2).

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The probability density function is of E(Y1) and E(Y2) is 1/6 and variance is 1/18.

To find the expected value E(Y1+Y2), we can use the linearity of expectation and the fact that the expected value of a constant is that constant:

E(Y1+Y2) = E(Y1) + E(Y2)

To find E(Y1) and E(Y2), we need to integrate y1 and y2 respectively over their joint probability density function:

E(Y1) = ∫∫ y1 f(y1,y2) dy1 dy2

= ∫0^1 ∫0^(1-y1) 2y1 dy2 dy1

= ∫0^1 2y1(1-y1)/2 dy1

= ∫0^1 y1-y1^2 dy1

= [y1^2/2 - y1^3/3] from 0 to 1

= 1/6

Similarly,

E(Y2) = ∫∫ y2 f(y1,y2) dy1 dy2

= ∫0^1 ∫0^(1-y2) 2y2 dy1 dy2

= ∫0^1 2y2(1-y2)/2 dy2

= ∫0^1 y2-y2^2 dy2

= [y2^2/2 - y2^3/3] from 0 to 1

= 1/6

Therefore, E(Y1+Y2) = E(Y1) + E(Y2) = 1/6 + 1/6 = 1/3.

To find the variance V(Y1+Y2), we can use the formula:

V(Y1+Y2) = E((Y1+Y2)^2) - [E(Y1+Y2)]^2

To find E((Y1+Y2)^2), we need to integrate (y1+y2)^2 over their joint probability density function:

E((Y1+Y2)^2) = ∫∫ (y1+y2)^2 f(y1,y2) dy1 dy2

= ∫0^1 ∫0^(1-y1) (y1+y2)^2 2 dy2 dy1

= ∫0^1 [(2/3)y1^3 + y1^2 + (1/3)y1] dy1

= 5/18

Therefore, V(Y1+Y2) = E((Y1+Y2)^2) - [E(Y1+Y2)]^2 = 5/18 - (1/3)^2 = 5/18 - 1/9 = 1/18

The variance is 1/18.

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a) determine the point where the two lines intersect. b) use your results from part (a) to obtain the equation of the plane that passes through the two lines.

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a. The two lines intersect at the point (-1/2, 8, 3/2).

b. The equation of the plane that passes through the two lines is -2y - 4z + 20 = 0.

a) To find the point where the two lines intersect, we need to solve the system of equations:

x = -2 + t

y = 3 + 2t

z = 4 - t

x = 3 - t

y = 4 - 2t

z = t

Equating x from the two equations, we get:

-2 + t = 3 - t

2t = 5

t = 5/2

Substituting t in either equation, we get:

x = -2 + 5/2 = -1/2

y = 3 + 2(5/2) = 8

z = 4 - 5/2 = 3/2

Therefore, the two lines intersect at the point (-1/2, 8, 3/2).

b) To obtain the equation of the plane that passes through the two lines, we first find the direction vectors of the lines. These are given by the coefficients of t in the equations:

Line 1: (-2, 3, 4) + t(1, 2, -1)

Line 2: (3, 4, 0) + t(-1, -2, 1)

The direction vectors are (1, 2, -1) and (-1, -2, 1), respectively.

The normal vector of the plane can be found by taking the cross-product of these two direction vectors:

(1, 2, -1) × (-1, -2, 1) = (0, -2, -4)

Now we use the point (-1/2, 8, 3/2) that we found in part (a) and the normal vector (0, -2, -4) to write the equation of the plane in the point-normal form:

0(x + 1/2) - 2(y - 8) - 4(z - 3/2) = 0

Simplifying, we get:

-2y - 4z + 20 = 0

Therefore, the equation of the plane that passes through the two lines is -2y - 4z + 20 = 0.

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The question is -

a) determine the point where the two lines

x=−2+t, y=3+2t, z=4−t and x=3−t, y=4−2t, z=t intersect.

b) use your results from part (a) to obtain the equation of the plane that passes through the two lines.

A ship anchor was sitting on the ocean floor 8 meters below the sea level while a dolphin was swimming at sea level

if any object below sea level is considered to be at a negative location which number line could be used to represent the positions of the anchor on the ocean floor and the dolphin at sea level ​

Answers

The correct representation on the number line is given as follows:

Option C.

How to represent the information on the number line?

A dolphin was swimming at sea level, hence the position of the dolphin is given as follows:

Position zero.

A ship anchor was sitting on the ocean floor 8 meters below the sea level, hence the position of the ship anchor is given as follows:

Position -8.

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