Answer:
10.46m/s
Explanation:
Given
Distance = 5.58m
Required
magnitude of the velocity'
Using the equation of motion expressed as
v² = u² + 2gS
v² = 0 +2(9.8)(5.58)
v² = 109.368
v= √109.368
v = 10.46m/s
Hence the magnitude of the velocity of the of the chain is 10.46m/s
distance formula and unit
Answer:
distance = speed × time
Explanation:
the unit of distance is meter(m)
but the formula differs according to the given
A person is standing on and facing the front of a stationary skateboard while holding a construction brick. The mass of the person is 67.0 kg, the mass of the skateboard is 4.10 kg, and the mass of the brick is 2.50 kg. If the person throws the brick forward (in the direction they are facing) with a speed of 23.0 m/s relative to the skateboard and we ignore friction, determine the recoil speed of the person and the skateboard, relative to the ground.
Answer:
v₁ = -0.8087 m / s
Explanation:
To solve this problem we can use the conservation of momentum, for this we define a system formed by the man, the skateboard and the brick, therefore the force during the separation is internal and the momentum is conserved
Initial instant. When they are united
p₀ = 0
Final moment. After throwing the brick
[tex]p_{f}[/tex] = (m_man + m_skate) v1 + m_brick v2
the moment is preserved
p₀ = p_{f}
0 = (m_man + m_skate) v₁ + m_brick v₂
v₁ = - [tex]\frac{ m_{brick} }{m_{man} + m_{skate} } v_{2}[/tex]
the negative sign indicates that the two speeds are in the opposite direction
let's calculate
v₁ = - [tex]\frac{2.5}{67 + 4.10} 23.0[/tex]
v₁ = -0.8087 m / s
If a 15kg mass weighs 372 N on Jupiter, what is Jupiter's gravitational acceleration?
Answer:
The mass of Jupiter is 1.9 x 1027 kg. It is hard to fully understand a number that large, so here are a few comparisons to help. It would take 318 times Earth's mass to equal Jupiter's.
Explanation:
A 146N force is needed to pull a 350 N block across a horizontal surface at a constant speed by a rope making an angle of 50 degrees with the floor. Find the coefficient of friction.
Answer:
F = force
f = friction
u = coefficient of friction
R = normal reaction force
a = Acceleration
m = mass of block
g = gravity
f = uR
F = Ma
Say the block is moving to the right.
The 146N force thus acts to the right, and the friction force to the left, since it resists movement.
The 146N force acts to the right, but the horizontal component of it is 146 cos 50 = 93.84: So this is the force to the right.
Since F = uR and we're trying to find u, we need both F and R. R is easy to get since it is just m x g. This is in fact already given as the weight 350N. So R = 350.
The block is moving at a constant speed, so the force to the right must = the force to the left.
F = ma, so 93.84 - f = (350/g) x 0
This means f must be 93.84 also.
so we have f = uR,
93.84 = u x 350
so u = 0.268 or
0.27 to 2dp.
Hope you understand this.
Explanation:
The coefficient of friction is 0.26 if the 46N force is needed to pull a 350 N block across a horizontal surface at a constant speed by a rope making an angle of 50 degrees with the floor.
What is the friction force?It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N). Mathematically it is defined as the product of the coefficient of friction and normal reaction.
We know:
f = uR
Where f is the friction force and u is the coefficient of friction, R is the normal reaction force.
The horizontal component of 146N is:
F' = 146cos50°
F' = 93.84 N
Since F = mass×acceleration
Because the block is traveling at a constant speed, the right-hand force must equal the left-hand force.
F' = f = 93.84 N
93.84 = u x 350 (R = 350N)
u = 0.26
Thus, the coefficient of friction is 0.26 if the 46N force is needed to pull a 350 N block across a horizontal surface at a constant speed by a rope making an angle of 50 degrees with the floor.
Learn more about the friction force here:
https://brainly.com/question/1714663
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Help please!!
During transcription, the DNA strand being transcribed has the following nucleotides: CTT CAG.
What would be the matching nucleotides on the mRNA?
Select one
1. GAA GUC
2.GUU GTC
3. AUU ATC
4. ACC AUC
Answer:
l think the correct answer is 1.GAA GUC
A concave mirror creates a real, inverted image 16.0 cm from its surface. If the image is 3.5 times larger, how far away is the object? Use the GUESS method to solve the problem and show all your work. Record you final answer using the correct number of significant digits
Answer:
3.6, make sure you study
help mmmemememeeee I'M BEING TIMED
Answer:
it's c. or A. not b.
Explanation:
.................
if a tomato is considered a fruit... then is ketchup considered a smoothie?
Answer:
depends... do you add suger to your ketchup?
Explanation:
Describe reflection using the terms incident ray and reflected ray.
Answer:
Explanation:
The ray of light that hits the polished surface is called the incident ray. The ray that gets reflected away is called the reflected ray. The point at which the light hits the surface is called the point of incidence. If a line is drawn perpendicular to that point, it is called the normal.
honey solidifies from the bottom whereas water from the top. Why?
Answer:
it is due to anamolous expansion of water as water cools from 4dg.c to 0dg.c. it expand making ice lighter than water to float
At what efficiency is a photovoltaic array running if insolation on the collector is 650 W/m2, the total collector area is 10 m2, the voltage across the array is 50 V, and the current being delivered is 15 A
Answer: 11.53 %
Explanation:
Given
area [tex]A=10\ m^2[/tex]
Voltage V=50 V
current I=15 A
Array running at [tex]650\ W/m^2[/tex]
Power [tex]P=VI=50\times 15=750\ W[/tex]
Efficiency [tex]\eta=\frac{750}{650\times 10}\times 100=11.53\%[/tex]
Determine the magnitude of the resultant force FR=F1+F2FR=F1+F2. Assume that F1F1F_1 = 235 lblb and F2F2F_2 = 350 l
Answer:
585lb
Explanation:
Given the following
F1 = 235lb
F2 = 350lb
The resultant is expressed as;
FR = F1+F2
Substitute the given values
FR = 235+350
FR = 585lb
Hence the magnitude of the resultant is 585lb
1. Define "compressibility." Give an example from your daily life
A block weighing 9.3 N requires a force of 3.7 N to push it along at constant velocity. What is the coefficient of friction for the surface
Answer:
0.398
Explanation:
According to friction, the frictional force is directly proportional to the normal reaction
Ff = nR
Ff is the frictional force
n is the coefficient of friction
R is the reaction
Reaction is equal to the weight
R= W = 9.3N
Fm = Ff = 3.7N
Fm is the moving force
Get the coefficient of friction
n = Ff/R
n = 3.7/9.3
n = 0.398
Hence the coefficient of friction for the surface is 0.398
One wave of 1 m amplitude meets another wave of 2 m amplitude. If they are exactly out of phase, what is the magnitude of the new amplitude
Answer:
1 m
Explanation:
Assuming both waves have the same frequency, and speed, this means that they have the same wavelength.If they are exacty out of phase, one will be at its maximum positive amplitude (crest), while the other will be at its maximum negative amplitude (trough), which means that the magnitude of the new amplitude will be the difference between both amplitudes, i.e., 1 m.If both waves had the same amplitude, the new amplitude would be just zero.The two charges are then brought closer together so that the force between them increases by a factor of 25. By what factor was their separation decreased
Answer:
Explanation:
The forces between two charges is inversely proportional to the square of distance.
[tex]F = k q_1 q_2 / r^{2}[/tex]
So if the distance is half then the force increases by a factor of 4 . if force between the charges increases by a factor of 25 then separation between them is decreased by a factor of 5 i.e distance between them is 1/5.
You walk into the living room and find your family watching a nature documentary on PBS. Which lens does this network fall under
Answer:
Natural Sciences
Explanation:
This network would fall under the lens of Natural Sciences. This is based on what the family is currently watching. Nature documentaries focus on our Planet as well as all the wildlife in it. In these documentaries, they talk about how and why certain things in nature occur. All of this would be considered educational information on the subjects of Earth Science and Biology which are main subcategories under the lens of Natural Sciences.
where V is the voltage in volts, I is the current in amperes, and R is the resistance in ohms. Assume that, as the battery wears out, the voltage decreases at 0.03 volts per second and, as the resistor heats up, the resistance is increasing at 0.02 ohms per second. When the resistance is 100 ohms and the current is 0.02 amperes, at what rate is the current changing
Answer:
[tex]\frac{dI}{dt} =-3.04*10^-^4amps/sec[/tex]
Explanation:
From the question we are told that
Voltage change [tex]\frac{dv}{dt}=-0.03volts/sec[/tex]
Resistance change [tex]\frac{dR}{dt}=0.02ohms/sec[/tex]
Resistance [tex]R=100[/tex]
Current [tex]I=0.02[/tex]
Generally the equation for ohms law is mathematically represented as
[tex]V=IR[/tex]
Therefore
[tex]\frac{dv}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]
[tex]\frac{dv}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]
Resolving the Rate of current changing [tex]\frac{dI}{dt}[/tex] as subject of formula
[tex]\frac{dv}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]
[tex]R\frac{dI}{dt} =\frac{dv}{dt} -I\frac{dR}{dt}[/tex]
[tex]\frac{dI}{dt} =\frac{1}{R} (\frac{dv}{dt} -I\frac{dR}{dt})[/tex]
Therefore
[tex]\frac{dI}{dt} =\frac{(-0.03) -(0.02)(0.02)}{100}[/tex]
[tex]\frac{dI}{dt} =-3.04*10^-^4amps/sec[/tex]
Therefore the current decreases at a rate
[tex]\frac{dI}{dt} =3.04*10^-^4amps/sec[/tex]
A 200 kg motorcycle speeds at 90 mph (40 m/s) off of a highway overpass and lands on top of a 18,000 kg semi truck, which is traveling in the same direction at 65 mph (30 m/s). Assume both vehicles stick together are coasting without friction after the collision. What will be the final speed of the semi truck after the collision
Answer:
The final speed of the semi truck is 30.11 m/s.
Explanation:
Given;
mass of the motorcycle, m₁ = 200 kg
initial speed of the motorcycle, u₁ = 40 m/s
mass of the semi truck , m₂ = 18,000 kg
initial speed of the semi truck, u₂ = 30 m/s (same direction as u₁)
If the two vehicles stick together after collision, the final speed of the motorcycle will be equal to final speed of the semi truck = v
Apply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(200 x 40) + (18,000 x 30) = v(200 + 18,000)
8000 + 540,000 = v(18,200)
548,000 = v(18,200)
[tex]v = \frac{548,000}{18,200} \\\\v = 30.11 \ m/s[/tex]
Therefore, the final speed of the semi truck is 30.11 m/s.
Which statement describes the vector plotted below?
A. The vector goes from (1, -2) to (-3,1).
B. The vector goes from (-3,-1) to (-3,-1).
c. The vector goes from (1, 2) to (-3,1).
D. The vector goes from (-3,-1) to (1,2).
Answer: the vector goes from (1,2) to (-3,1)
Explanation:
When you graph displacement vs. time, velocity is represented by
A. the x-intercept of the graph
B. the y-intercept of the graph
C. the slope of the graph
D. the curve of the graph
A 9.0 kg test rocket is fired vertically from Cape Canaveral. Its fuel gives it a kinetic energy of 1905 J by the time the rocket engine burns all of the fuel. What additional height will the rocket rise
Answer:
21.6m
Explanation:
Since the rocket engine burns all the fuel hence the kinetic energy will be converted to potential energy
Potential Energy = mass × acceleration due to gravity × height
Given
PE = 1905J
Mass = 9.0kg
Acceleration due to gravity =9.8m/s²
Required
Height h
Substitute into the formula
1905 = 9(9.8)h
1905 = 88.2h
h =1905/88.3
h = 21.6m
Hence the required height is 21.6m
A rope 6m long is fixed at one end; the other end is attached to a light string so that it is free to move. The speed of waves on the rope is 18 m/s. The frequency of the second harmonic is
Given :
A rope 6m long is fixed at one end, the other end is attached to a light string so that it is free to move.
The speed of waves on the rope is 18 m/s.
To Find :
The frequency of the second harmonic.
Solution :
We know, for second harmonic wave :
Wavelength = Length of rope
[tex]\lambda = L\\\\\lambda = 6 \ m[/tex]
Now, we know frequency is given by :
[tex]Frequency = \dfrac{Speed}{Wavelenght}\\\\f = \dfrac{18 \ m/s}{6\ m}\\\\f = 3 \ s^{-1}[/tex]
Therefore, the frequency of the second harmonic is 3 s⁻¹.
A 60.0 kg woman runs up a staircase 15 m high (vertically) in 20. s. (a) How much power does she expend
Given that,
Mass of a woman, m = 60 kg
She runs up a staircase 15 m high in 20 s.
To find,
Power expanded.
Solution,
Power = rate of doing work
[tex]P=\dfrac{W}{t}\\\\P=\dfrac{mgh}{t}\\\\P=\dfrac{60\times 9.8\times 15}{20}\\\\=441\ W[/tex]
So, the required power is 441 W.
What is the difference between the number of electrons in an atom of Iodine (I) and the number of electrons in an atom of Aluminum (Al)?
Answer:
Iodine is element number 53. Iodine has 53 protons and 53 electrons (because it has no charge the number of protons equals the number of electrons). Iodine-131 has 131 protons and neutrons.
Explanation:
Question 7 of 10
What is the period of a wave with a frequency of 3 Hz and an amplitude of
0.01 m?
A. 0.0033 s
B. 300 s
C. 0.33 s
D. 0.030 S
Answer:
0.33s
Explanation:
hope this is the correct ans
A 7.03 nC charge is located 1.75 m from a 4.26 nC point charge. (a) Find the magnitude of the electrostatic force that one charge exerts on the other.
Given that,
Charge, q₁ = 7.03 nC
Charge, q₂ = 4.26 nC
Distance, r = 1.75 m
To find,
The magnitude of the electrostatic force that one charge exerts on the other.
Solution,
The force between two charges at a distance is given by the formula as formula :
[tex]F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 7.03\times 10^{-9}\times 4.26\times 10^{-9}}{(1.75)^2}\\\\=8.8\times 10^{-8}\ N[/tex]
So, the required force is [tex]8.8\times 10^{-8}\ N[/tex].
4.
What is the BEST example you can offer to explain a folkway?
A. It is against your religious beliefs to commit adultery.
B. Your workplace decreases your pay if you arrive late.
C. When you answer your phone, you say hello.
D. All people are kind to one another.
If the entire population of Earth were transferred to the Moon, how far would the center of mass of the Earth-Moon-population system move
The question is incomplete. The complete question is :
If the entire population of Earth were transferred to the Moon, how far would the center of mass of the Earth-Moon population system move? Assume the population is 7 billion, the average human has a mass of 65 kg, and that the population is evenly distributed over both the Earth and the Moon. The mass of the Earth is 5.97×1024 kg and that of the Moon is 7.34×1022 kg. The radius of the Moon’s orbit is about 3.84×105 m.
Solution :
Given :
Mass of earth, [tex]$M_e = 5.97 \times 10^{24} \ kg$[/tex]
Mass of moon, [tex]$M_m = 7.34 \times 10^{22} \ kg$[/tex]
Mass of each human, [tex]$m_p =65 \ kg$[/tex]
Therefore mass of total population, [tex]$M_p = 65 \times 7 \times 10^{9} \ kg$[/tex]
[tex]$M_p = 4.55 \times 10^{11} \ kg$[/tex]
Let the earth is at the origin of the coordinate system. Then,
Since [tex]$M_e>> M_p$[/tex]
[tex]$M_m>> M_p$[/tex]
Hence if we shift all the population on the moon there will be negligible change in the mass of the moon and earth. Hence there will not be any significant shift on the centre of mass. i.e.
[tex]$X_{cm} = \frac{5.97 \times 10^{24}+ 7.34 \times 10^{22} \times 3.84 \times 10^5}{5.97 \times 10^{24}+ 7.34 \times 10^{22}}$[/tex]
[tex]$= 4.68 \times 10^6 \ m$[/tex]
[tex]$ 4.68 \times 10^3 \ km$[/tex] from the earth.
Consider the standing wave on a guitar string and the sound wave generated by the string as a result of this vibration. What do these two waves have in common
Answer:
As the string vibrates, it "moves" the particles in the air, generating what we know as a soundwave.
Because this soundwave is generated by the wave-like motion of the string, makes sense that the soundwave will have some characteristics in common with the standing wave on the guitar string. This means that both waves will have the same normal modes. (So if the principal mode of the vibrating string has a frequency of 440hz, to soundwave also will have that main frequency, and we will hear an A). You can hear almost all the normal modes when you pluck a guitar string, particularly in music, these are called "overtones" or "harmonics"