Find the distance between the two points in simplest radical form.
n.
(6, -9) and (1,3)
Help?
Answers
[tex]\large\underline{\underline{\red{\sf \blue{\longmapsto} Step-by-step\: Explanation:-}}}[/tex]
Given to points to us are :-
( 6 , -9)( 1 , 3 )Now , we can use Distance Formula , which is :-
[tex]\boxed{\purple{\tt Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}}[/tex]
Here ,
x1 = 6 .x2 = 1.y1 = (-9)y2 = 3.→ Substituting the respective values ,
⇒ Distance = √ [ ( 6 - 1)² + ( 3 +9)² ] .
⇒ Distance = √ 5² + 12²
⇒ Distance = √ 25 + 144
⇒ Distance = √ 169 .
⇒ Distance = 13 units .
Hence the distance between two points is 13u.
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Step-by-step explanation:
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Step-by-step explanation:
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***remember the 180 rule, and supplementary/complementary angles!
180 rule: all triangle's internal angles add up to 180, this means if you know any two angles you can always find the last one
supplementary angles:
angles that add up to 180, 180 is a straight line so they can be found on almost all triangle problems.
if there is a straight line and you know one of the angles that is on the line, you can find the other one by subtracting it from 180
complementary angles:
same thing ^ but with 90
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♨Rage♨
Step-by-step explanation:
Hey there!
Given;
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We know that (1/2) can be written as 2^-1. So, it will be;
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