Find the distance between the points (-5, -4) and (3, 1).

On a coordinate plane, points are at (3, 1), (negative 5, negative 4).

Answer:

c) tan

Step-by-step explanation:

For the 63-deg angle, YZ is the opposite leg. The unknown side, AY, is the adjacent leg. The trigonometric ratio that relates the opposite and adjacent legs is the tangent.

Answer: c) tan

Answer:

b

Step-by-step explanation:

im doing it on edge right now

Answer

all y values change sign that is reflection over x axis SKETCH IT !!!!

More

Step-by-step explanation:

guess

Dependent variable: y and Independent variable: x

gauthammath dot com 

Answer:

Hence,

a) The probability that the sample average would be less than 90 pounds is 0.0210.

b) The probability that the sample average would be between 98 and 105 pounds is 0.5045.

c) The probability that the sample average would be less than 112 pounds is 0.9935.

d) The probability that the sample average would be between 93 and 96 pounds is 0.1341.

Step-by-step explanation:

a) [tex]P(X < 90) = P(Z < (90 - 99.9) / (30\sqrt(38)))[/tex]

                     = P(Z < -2.03) = 0.0210

b )[tex]P(98 < x <105) = P((98 -99.9) / (30 \sqrt(38)) < Z < (105 -99.9) / (30 \sqrt(38)))[/tex]

                              = P(-0.39 < Z < 1.05) = 0.5045

c ) [tex]P(X < 112) = P(Z < (112 - 99.9) / (30\sqrt(38)))[/tex]

                        = P(Z < 2.49) = 0.9935

d )[tex]P(93 < x < 96) = P((93 -99.9) / (30 \sqrt(38)) < Z < (96 -99.9) / (30 \sqrt(38)))[/tex]

                            = P( -1.42 < Z < -0.8 )

                            = 0.2119 - 0.0778 = 0.1341

Given:

The graph that represents the enrollment for college R between 1950 and 2000.

To find:

The average rate of increase in enrollment per decade between 1950 and 2000?

Solution:

The average rate of change of function f(x) over the interval [a,b] is:

[tex]m=\dfrac{f(b)-f(a)}{b-a}[/tex]

So, the average rate of increase in enrollment per year between 1950 and 2000 is:

[tex]m=\dfrac{f(2000)-f(1950)}{2000-1950}[/tex]

[tex]m=\dfrac{7-4}{50}[/tex]

[tex]m=\dfrac{3}{50}[/tex]

[tex]m=0.06[/tex]

It is given average rate of increase in enrollment per year between 1950 and 2000 is 0.06.

We need to find the average rate of increase in enrollment per decade between 1950 and 2000, So, multiply the average rate of increase in enrollment per year by 10.

[tex]0.06\times 10=0.6[/tex]

Therefore, the average rate of increase in enrollment per decade between 1950 and 2000 is 0.6.

Answer:

This Question Is From The Novel Of The Fantastic Mr.Fox

Q. Boggis , Bunce and Bean are Offering a reward for Mr.Fox , They are tired of Losing Chickens Geese and Cider , Create a Description And Drawing of Mr.Fox to allow him to be captured , use the word bank....

________________________________

Swift | Slay | Ginger | Rough | Fast

Thief. | Clever | Fur | Tail | Wife | Night

Cunning | Bushy | wiry | bush | Den | trick

________________________________

Answer:

angle C= 65 degree

Step-by-step explanation:

60+55+x= 180

115+x= 180

x= 180-115

x= 65

angle C= 65 degree

Please mark me as brainliest.

Answer:

The farmer should plant 14 additional trees, for maximum yield.

Step-by-step explanation:

Given

[tex]Trees = 24[/tex]

[tex]Yield = 104[/tex]

[tex]x \to additional\ trees[/tex]

So, we have:

[tex]Trees = 24 + x[/tex]

[tex]Yield = 104 - 2x[/tex]

Required

The additional trees to be planted for maximum yield

The function is:

[tex]f(x) = Trees * Yield[/tex]

[tex]f(x) = (24 + x) * (104 - 2x)[/tex]

Open bracket

[tex]f(x) = 24 * 104 + 104x - 24 * 2x - x * 2x[/tex]

[tex]f(x) = 2796 + 104x - 48x - 2x^2[/tex]

[tex]f(x) = 2796 + 56x - 2x^2[/tex]

Rewrite as:

[tex]f(x) = - 2x^2 + 56x + 2796[/tex]

Differentiate

[tex]f'(x) = -4x + 56[/tex]

Equate [tex]f'(x) = -4x + 56[/tex] to 0 and solve for x to get the maximum of x

[tex]-4x + 56 = 0[/tex]

[tex]-4x =- 56[/tex]

Divide by -4

[tex]x =14[/tex]

The farmer should plant 14 additional trees, for maximum yield.

Answer:

which standard questions is it

Answer:

(a) 1 - (15 C 6) / (30 C 6)

(b)  (5 C 2) x (10 C 2) x (15 C 2) / (30 C 2)

Step-by-step explanation:

Number of  nickels = 5

Number of dimes = 10

Number of quarters = 15

(a) The probability of getting 6 quarters  

= (15 C 6) / (30 C 6)

So, the probability of not getting 6 quarters = 1 - (15 C 6) / (30 C 6)

(b) Probability of getting 2 nickels , 2 dimes and 2 quarters

= (5 C 2) x (10 C 2) x (15 C 2) / (30 C 2)

Answer:

Step-by-step explanation:

commission = 0.7% of $12,500

= 0.007×$12,500

= $87.5

Answer:

22 mi

Step-by-step explanation:

From the question given above, the distance from E to F is 6 in.

Thus, we can obtain the distance from E to F (i.e mi) by using the scale provided in the question. This is illustrated below:

3 in = 11 mi

Therefore,

6 in = 6 in × 11 mi / 3 in

6 in = 22 mi

Therefore, the distance from E to F is 22 mi

Answer:

"D" is the correct answer

Step-by-step explanation:

Answer:

The equation of [tex]f(x) = e^{-3\cdot x}[/tex] by Maclaurin series is [tex]f(x) = \Sigma\limits_{i=0}^{\infty} \frac{(-3\cdot x)^{i}}{i!}[/tex].

Step-by-step explanation:

The Maclaurin series for [tex]f(x)[/tex] is defined by the following formula:

[tex]f(x) = \Sigma\limits_{i = 0}^{\infty} \frac{f^{(i)}(0)}{i!} \cdot x^{i}[/tex] (1)

Where [tex]f^{(i)}[/tex] is the i-th derivative of the function.

If [tex]f(x) = e^{-3\cdot x}[/tex], then the formula of the i-th derivative of the function is:

[tex]f^{(i)} = (-3)^{i}\cdot e^{-3\cdot x}[/tex] (2)

Then,

[tex]f^{(i)}(0) = (-3)^{i}[/tex] (2b)

Lastly, the equation of the trascendental function by Maclaurin series is:

[tex]f(x) = \Sigma\limits_{i=0}^{\infty} \frac{(-3)^{i}\cdot x^{i}}{i!}[/tex]

[tex]f(x) = \Sigma\limits_{i=0}^{\infty} \frac{(-3\cdot x)^{i}}{i!}[/tex] (3)

Answer:

(1,7), (2,2), (3,5) (4,8)

(2,6), (6,5), (3,2) (5,3)

(4,3), (3,3), (2,3) (1,3)

Step-by-step explanation:

those represent functions b/c the domain of the relation is not written twice

Hope that'll help!

Answer:

the total number of participants required is 90

Step-by-step explanation:

Given the data in the question;

Factor A has three levels

Factor B has three levels

sample size n; ten participants

we have two Way ANOVA involving Factor A and Factor B.

Now,

{ Total # Participants Required } = { #Levels factor A } × { #Levels factor B } × { Sample size of each level }

we substitute

{ Total # Participants Required } = 3 × 3 × 10

{ Total # Participants Required } = 9 × 10

{ Total # Participants Required } = 90

Therefore, the total number of participants required is 90

Answer:

You're correct

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

We are given that y varies inversely with x. Recall that inverse variation has the form:

[tex]\displaystyle y=\frac{k}{x}[/tex]

Where k is the constant of variation.

We are given that y = 36 when x = 1/12. Thus:

[tex]\displaystyle (36)=\frac{k}{\left({}^{1}\!/\!{}_{12}\right)}[/tex]

Solve for k. Multiply both sides by 1/12:

[tex]\displaystyle k=\frac{1}{12}(36)=3[/tex]

Hence, our equation is:

[tex]\displaystyle y=\frac{3}{x}[/tex]

Our answer is B.

Answer:

Domain: -4 ≤ x ≤ -1

Range: -1 ≤ y ≤ 3

Step-by-step explanation:

Hi there!

The domain is the possible x-values of a function.

The lowest x-value the function contains is -4, and the greatest is -1.

Therefore, the domain is -4 ≤ x ≤ -1.

The range is the possible y-values of a function.

The lowest y-value the function contains is -1, and the greatest is 3.

Therefore the range is -1 ≤ y ≤ 3.

I hope this helps!

Answer:

To find the surface area of a cuboid we can also label the length, width and the height of the prism and use the formula SA=2LW+2LH+2HW to find the area of a cuboid

Answer:

202 cm²

Step-by-step explanation:

The opposite faces of a cuboid are congruent , then

SA = top/bottom + front/ back + sides , that is

SA = 2(9 × 4) + 2(9 × 5) + 2(4 × 5)

     = 2(36) + 2(45) + 2(20)

     = 72 + 90 + 40

    = 202 cm²

Step-by-step explanation:

We have to expand,

[tex]\longrightarrow [/tex] (2x — 4)²

[tex]\longrightarrow [/tex] (2x)² + (4)² ― 2(2x × 4)

[tex]\longrightarrow [/tex] 4x² + 16 ― 2(8x)

[tex]\longrightarrow [/tex] 4x² + 16 ― 16x

[tex]\longrightarrow [/tex] 4x² ― 16x + 16

Hence, solved!

Answer:

D is the correct answer (2x)2 – 2(2x)(4) + 42

Step-by-step explanation:

Divide total miles by speed:

360 / 50 = 7.2 hours

Answer:

10/1 is the largest because 10÷1 = 10

Answer:

10/1 =  10 and is by far the biggest value in the list

Step-by-step explanation:

Complete Question

ymposium is part of a larger work referred to as Plato's Dialogues. Wishart and Leach† found that about 21.4% of five-syllable sequences in Symposium are of the type in which four are short and one is long. Suppose an antiquities store in Athens has a very old manuscript that the owner claims is part of Plato's Dialogues. A random sample of 498 five-syllable sequences from this manuscript showed that 129 were of the type four short and one long. Do the data indicate that the population proportion of this type of five-syllable sequence is higher than that found in Plato's Symposium? Use = 0.01.  

a. What is the value of the sample test statistic? (Round your answer to two decimal places.)  

b. Find the P-value of the test statistic. (Round your answer to four decimal places.)

Answer:

a) [tex]Z=2.45[/tex]

b) [tex]P Value=0.0073[/tex]

Step-by-step explanation:

From the question we are told that:

Probability of Wishart and Leach [tex]P=21.4=>0.214[/tex]

Population Size [tex]N=498[/tex]

Sample size [tex]n=12[/tex]

Therefore

[tex]P'=\frac{129}{498}[/tex]

[tex]P'=0.2590[/tex]

Generally the Null and Alternative Hypothesis is mathematically given by

[tex]H_0:P=0.214[/tex]

[tex]H_a:=P>0.214[/tex]

Test Statistics

[tex]Z=\frac{P'-P}{\sqrt{\frac{P(1-P)}{n}}}[/tex]

[tex]Z=\frac{0.2590-0.214}{\sqrt{\frac{0.214(1-0.214)}{498}}}[/tex]

[tex]Z=2.45[/tex]

Therefore P Value is given as

[tex]P Value =P(Z\geq 2.45)[/tex]

[tex]P Value =1-P(Z\leq 2.45)[/tex]

[tex]P Value =1-0.99268525[/tex]

[tex]P Value=0.0073[/tex]

Option C

SOLUTION:

We need to find the value of B - CF

First find the value CF:

[tex]CF=\left[\begin{array}{ccc}12&0&1.5\\1&-6&7\\\end{array}\right] \left[\begin{array}{ccc}-2&0\\0&8\\2&1\end{array}\right][/tex]

[tex]CF=\left[\begin{array}{ccc}12(-2)+0 *0+1.5*2&12*0+0.8+1.5*1\\1*(-2)+(-6)*0+7.2&1*0+(-6)*8+7.1\\\end{array}\right][/tex]

[tex]CF=\left[\begin{array}{ccc}-21&1.5\\12&-41\\\end{array}\right][/tex]

Now find value of B - CF:

[tex]B-CF=\left[\begin{array}{ccc}2&8\\6&3\\\end{array}\right] -\left[\begin{array}{ccc}-21&1.5\\12&-41\\\end{array}\right][/tex]

[tex]B-CF=\left[\begin{array}{ccc}23&6.5\\-6&44\\\end{array}\right][/tex]

∴ the value of B - CF is [tex]\left[\begin{array}{ccc}23&6.5\\-6&44\\\end{array}\right][/tex]

I hope this helps....

Answer:

C) x = ± 4

Step-by-step explanation:

12x² - 288 = 0

12x ² = 288

[tex] \small \sf \: x {}^{2} = \frac{288}{12} \\ [/tex]

[tex]\small \sf x {}^{2} = \frac{ \cancel{288 }}{ \cancel{12}} \\ [/tex]

x² = 24

[tex] \small \sf \: \sqrt{x {}^{2} } = ± \sqrt{ 24} [/tex]

[tex] \small \sf \: x_1, _2 = ± \sqrt{ 24} [/tex]

[tex] \small \sf \: x_1, _2 = ± 4.899 [/tex]

Answer:

2TRN

Let me know if this is wrong!

233115555532224444432

Answer:

Anything to the power of zero (with the exception of zero itself) is equal to one.

So 3⁰ = 1