Find the determinants in Exercises 5-10 by row reduction to echelon form -1 -3 1 1 4 9. -1 0 5 3 -32 3 3

The probability that the cycle time exceeds 75 minutes, given that it already exceeds 45 minutes, is 25%.

Given the information provided, we know the following:

1. The cycle time for trucks hauling concrete is uniformly distributed over the interval 40 to 85 minutes.
2. We need to find the probability that the cycle time exceeds 75 minutes, given that it already exceeds 45 minutes.

Step 1: Determine the length of the original interval.
The original interval is from 40 to 85 minutes, so the length is 85 - 40 = 45 minutes.

Step 2: Determine the length of the conditional interval.
Since we know that the cycle time already exceeds 45 minutes, our new interval starts at 45 minutes and ends at 85 minutes. The length of this interval is 85 - 45 = 40 minutes.

Step 3: Determine the length of the interval for cycle times exceeding 75 minutes.
The interval for cycle times exceeding 75 minutes starts at 75 and ends at 85, so the length of this interval is 85 - 75 = 10 minutes.

Step 4: Calculate the probability.
Since the cycle time is uniformly distributed, the probability is equal to the ratio of the lengths of the intervals:
Probability = (Length of interval for cycle times exceeding 75 minutes) / (Length of conditional interval)
Probability = 10 minutes / 40 minutes = 0.25 or 25%

So, the probability that the cycle time exceeds 75 minutes, given that it already exceeds 45 minutes, is 25%.

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The probability of a Type I error is 0.2 or 20%. This means that there is a 20% chance of rejecting the null hypothesis when it is actually true.

The power of a hypothesis test is the probability of rejecting the null hypothesis when the alternative hypothesis is true. In this case, the power of the test is given as 0.8, and the null hypothesis is that the true value of the parameter is 10, while the alternative hypothesis is that the true value is 8.

We are given the sample size, n = 25, and the standard deviation, σ = 4. To calculate the probability of a Type I error, we need to determine the significance level of the test, denoted by α.

The significance level is the probability of rejecting the null hypothesis when it is actually true. It is usually set before conducting the test, and commonly set at 0.05 or 0.01.

To calculate α, we can use the following formula:

α = 1 - power = 1 - 0.8 = 0.2

So, the probability of a Type I error is 0.2 or 20%. This means that there is a 20% chance of rejecting the null hypothesis when it is actually true.

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The car salesman must visit approximately 14 customers to meet his daily sales goal of 4 cars, based on the given probability of 0.3.

To calculate the expected number of customers a car salesman must visit to achieve his daily sales goal, we can use the concept of probability. Given that the probability of a customer purchasing a car is 0.3, and the salesman needs to make 4 sales each day, we can use the formula:

Expected number of customers = (Number of sales needed) / (Probability of a successful sale)

In this case, the number of sales needed is 4, and the probability of a successful sale is 0.3. Plugging these values into the formula, we get:

Expected number of customers = 4 / 0.3 = 13.33

Therefore, the car salesman must visit approximately 14 customers (since we cannot have a fraction of a customer) to meet his daily sales goal of 4 cars, based on the given probability of 0.3. Keep in mind that this is an average value, and the actual number of customers required may vary from day to day.

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The margin of error for a 95% confidence interval for the population mean (μ) is given by: Margin of Error = z*(σ/√n)

where z is the critical value from the standard normal distribution for a 95% confidence level (z = 1.96), σ is the population standard deviation (which is usually unknown and estimated by the sample standard deviation, s), and n is the sample size.

Assuming the conditions of the linear model hold, the margin of error for a 95% confidence interval for the population mean can be calculated using the above formula.

Note that the linear model assumptions include that the errors are normally distributed, the mean of the errors is zero, and the variance of the errors is constant.

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(a) The mean number of leaking tanks is 3.75. (b) The probability that 10 or more of the 15 tanks leak is 0.114 or 11.4%. (c) The probability that at least 540 of these tanks are leaking is 3.22%

(a) The mean number of leaking tanks in such samples of 15 can be calculated using the formula for the mean of a binomial distribution, which is mean = np, where n is the sample size and p is the probability of success. In this case, n = 15 and p = 0.25 (since 25% of tanks leak), so the mean number of leaking tanks is 15 x 0.25 = 3.75.

(b) To calculate the probability that 10 or more of the 15 tanks leak, we can use the binomial distribution again. The formula for this probability is P(X ≥ 10) = 1 - P(X ≤ 9), where X is the number of leaking tanks. Using a binomial calculator or a probability distribution table, we can find that P(X ≤ 9) = 0.886 and therefore P(X ≥ 10) = 1 - 0.886 = 0.114 or 11.4%.

(c) To calculate the probability that at least 540 of the 2000 tanks are leaking, we can use the normal approximation to the binomial distribution, since the sample size is large and the probability of success is not too small or too large (0.25 in this case). We first calculate the mean and standard deviation of the number of leaking tanks: mean = np = 2000 x 0.25 = 500 and standard deviation = sqrt(np(1-p)) = sqrt(2000 x 0.25 x 0.75) = 21.65 (rounded to two decimal places). Then, we standardize the value 540 using the formula z = (x - mean) / standard deviation, where x is the number of leaking tanks we want to find the probability for. Thus, z = (540 - 500) / 21.65 = 1.85 (rounded to two decimal places). Using a normal distribution table or calculator, we can find that the probability of getting a z-score of 1.85 or higher is 0.0322 or 3.22%. Therefore, the probability that at least 540 of the 2000 tanks are leaking is 3.22%.

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The intercept is an essential component of the regression model, as it helps to establish a baseline prediction for the number of shaped ski rentals before accounting for the effects of the independent variables.

Based on the previous multivariate regression model that used weekend, school break, and weather as predictors of shaped ski rentals, the value of the intercept refers to the estimated number of shaped ski rentals when all independent variables are equal to zero.

In this case, the intercept would represent the expected number of shaped ski rentals on a weekday during a non-school break period when the weather is average. Unfortunately, without the exact equation for the regression model, it's impossible to determine the specific value of the intercept.

However, it is important to note that the intercept is an essential component of the regression model, as it helps to establish a baseline prediction for the number of shaped ski rentals before accounting for the effects of the independent variables.

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The chance of drawing two Jacks one after another, when drawing without replacement from an incomplete deck of 48 cards that contains 4 Jacks, is [tex]\frac{1}{188}[/tex]

The chance of drawing two Jacks one after another, when drawing without replacement from an incomplete deck of 48 cards that contains 4 Jacks, can be calculated using the following steps:

Step 1: Find the probability of drawing the first Jack.
There are 4 Jacks in the 48-card deck, so the probability of drawing the first Jack is [tex]\frac{4}{48}[/tex].

Step 2: Find the probability of drawing the second Jack.
After drawing the first Jack, there are now 3 Jacks left in the deck and only 47 cards remaining. The probability of drawing the second Jack is now [tex]\frac{3}{47}[/tex].

Step 3: Multiply the probabilities from steps 1 and 2 to find the overall probability of drawing two Jacks one after another.
[tex](\frac{4}{48}) (\frac{3}{47} ) = \frac{12}{2256}[/tex]

Step 4: Simplify the probability.
The simplified probability of drawing two Jacks one after another is [tex]\frac{1}{188}[/tex] .

Therefore, the chance of drawing two Jacks one after another, when drawing without replacement from an incomplete deck of 48 cards that contains 4 Jacks, is 1/188.

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The four consecutive odd integers are -11, -9, -7, and -5.

Let's define the consecutive odd integers and set up an equation using the given conditions:
Let the four consecutive odd integers be:
x, x+2, x+4, x+6

The problem states that 5 times the sum of the first two is 5 less than 19 times the fourth:
5(x + (x+2)) = 19(x+6) - 5
Now, let's solve for x step-by-step:
Distribute the 5 and 19:
5(2x + 2) = 19x + 114 - 5
Simplify further:
10x + 10 = 19x + 109
Move all terms with x to one side by subtracting 10x from both sides:
10 = 9x + 109

Subtract 109 from both sides:
-99 = 9x
Divide by 9:
x = -11
Now that we have x, we can find the consecutive odd integers:
-11, -9, -7, -5.

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Answer:

c

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

2x+10=x+30

so, the answer is 30.

To minimize the use of framing, the rectangular frame should have dimensions of around 9.3 inches by 2.9 inches.

Let's assume the length and width of the rectangular frame be L and W, respectively. The total area of the frame can be expressed as:

Total Area = (L + 3W) * (W + 3L) [adding 1.5 inch of framing to each side]

The opening of the frame is given as 27 square inches:

L * W = 27

We can substitute the value of L from the second equation into the first equation and simplify:

Expanding the brackets and simplifying:

Total Area = 3W² + 27*3 + 81/W + 27/W²

We can now take the derivative of this expression with respect to W and set it to zero to find the value of W that minimizes the total area:

Substituting the value of W back into the equation L * W = 27:

Therefore, the dimensions of the frame should be approximately 9.3 inches by 2.9 inches to minimize the amount of framing used.

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The  value of the line integral / (+ +4vY) ds, where C is the path going counterclockwise around the square with vertices (0,0), (2,0), (2,2) and (0,2), is 32v.

To evaluate the line integral, we need to parameterize the square and then compute the line integral along each of the four sides.

Let's parameterize the square as follows:
- For the bottom side from (0,0) to (2,0), we can use the parameterization r(t) = <t, 0>, where 0 ≤ t ≤ 2.
- For the right side from (2,0) to (2,2), we can use the parameterization r(t) = <2, t>, where 0 ≤ t ≤ 2.
- For the top side from (2,2) to (0,2), we can use the parameterization r(t) = <t, 2>, where 0 ≤ t ≤ 2.
- For the left side from (0,2) to (0,0), we can use the parameterization r(t) = <0, t>, where 0 ≤ t ≤ 2.

Now we can compute the line integral along each of these sides and add them up to get the total line integral.

Line integral along the bottom side:
- r(t) = <t, 0>, where 0 ≤ t ≤ 2.
- dr/dt = <1, 0>.
- ds/dt = ||dr/dt|| = 1.
- (+4vY) ds = 4v(0) ds = 0.
- Integral from t=0 to t=2: 0 dt = 0.

Line integral along the right side:
- r(t) = <2, t>, where 0 ≤ t ≤ 2.
- dr/dt = <0, 1>.
- ds/dt = ||dr/dt|| = 1.
- (+4vY) ds = 4v(t) ds = 4v(t) dt.
- Integral from t=0 to t=2: 4v(t) dt = 8v.

Line integral along the top side:
- r(t) = <t, 2>, where 0 ≤ t ≤ 2.
- dr/dt = <1, 0>.
- ds/dt = ||dr/dt|| = 1.
- (+4vY) ds = 4v(2) ds = 8v ds = 8v.
- Integral from t=0 to t=2: 8v dt = 16v.

Line integral along the left side:
- r(t) = <0, t>, where 0 ≤ t ≤ 2.
- dr/dt = <0, 1>.
- ds/dt = ||dr/dt|| = 1.
- (+4vY) ds = 4v(t) ds = 4v(t) dt.
- Integral from t=0 to t=2: 4v(t) dt = 8v.

Adding up the line integrals along each side, we get:
- Total line integral = 0 + 8v + 16v + 8v = 32v.

Therefore, the value of the line integral / (+ +4vY) ds, where C is the path going counterclockwise around the square with vertices (0,0), (2,0), (2,2) and (0,2), is 32v.

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Thus,  the 95% confidence interval for the population variance is (54.95, 1274.12) ounces^2. This means that we are 95% confident that the true variance of the population lies within this interval.

To construct the confidence interval for the population variance of the given sample, we can use the Chi-square distribution.

Since we are given a 95% level of confidence, the critical values for the Chi-square distribution with degrees of freedom (df) equal to n-1 (n=17) and a significance level of 0.05/2 (two-tailed test) are 7.261 and 28.412, respectively.

Using the formula (n-1)s^2/χ^2(df,α/2) and (n-1)s^2/χ^2(df,1-α/2), where s^2 is the sample variance and α is the significance level, we can calculate the lower and upper bounds of the confidence interval. Substituting the given values, we get:

Lower bound: (17-1)×(98.5294)/28.412 = 54.9471
Upper bound: (17-1)×(98.5294)/7.261 = 1274.1194

Therefore, the 95% confidence interval for the population variance is (54.95, 1274.12) ounces^2. This means that we are 95% confident that the true variance of the population lies within this interval.

It is important to note that this interval does not contain any negative values, which is expected for a variance measure. Also, since the sample is assumed to be from a normally distributed population, this assumption should be checked using appropriate tests or techniques.

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When an inequality is multiplied or divided by a negative number, the inequality sign will flip, meaning it will change its direction. For example, if you have a > b and you multiply or divide both sides by a negative number, the inequality will become a < b. This is because the relationship between the values reverses when multiplied or divided by a negative number.

Explanation:

When an inequality is multiplied or divided by a negative number, the direction of the inequality sign is flipped. This is because multiplication or division by a negative number, results in a reversal of the order of the numbers on the number line.

To see why this happens, consider the following example:

Suppose we have the inequality x < 5. If we multiply both sides of this inequality by -1, we get -x > -5. Notice that we have flipped the inequality sign from "<" to ">". This is because multiplying by -1 changes the sign of x to its opposite, and also changes the sign of 5 to its opposite, resulting in a reversal of the order of the numbers on the number line.

Similarly, if we divide both sides of the inequality x > 3 by -2, we get (-1/2)x < (-3/2). Here, we have again flipped the inequality sign from ">" to "<". This is because dividing by a negative number also changes the order of the numbers on the number line.

In general, if we have an inequality of the form a < b or a > b, where a and b are real numbers, and we multiply or divide both sides by a negative number, we obtain:

If we multiply by a negative number, the inequality sign is flipped. For example, if a < b and c < 0, then ac > bc.

If we divide by a negative number, the inequality sign is also flipped. For example, if a > b and c < 0, then a/c < b/c.

Therefore, it is important to be mindful of the signs of the numbers involved when performing operations on inequalities. If we multiply or divide by a negative number, we must flip the direction of the inequality sign accordingly.

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It would cost approximately $1.10 to use the clothes washer.

To calculate the cost of using the clothes washer, you'll need to multiply the energy usage (in kilowatts) by the duration (in hours) and the cost per kilowatt-hour. In this case, the clothes washer used 2.6 kilowatts for 0.9 hours and the electricity cost is $0.47 per kilowatt-hour.

To find the total cost, use the following formula:

Total cost = Energy usage (kilowatts) × Duration (hours) × Cost per kilowatt-hour

Plug in the given values:

Total cost = 2.6 kilowatts × 0.9 hours × $0.47 per kilowatt-hour

Total cost = $1.1046

To find the cost to the nearest penny, round the result to two decimal places:

Total cost = $1.10

So, it cost approximately $1.10 to use the clothes washer.

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The sum S of the series is approximately 0.86832, and the error is less than or equal to 0.01295.

Using the sum of the first 10 terms, we can approximate the sum S of the series as follows:

S ≈ sum of first 10 terms
  ≈ 0.86832

To estimate the error, we can use the remainder formula for an infinite series:

Rn = Sn - S
  = sum from n+1 to infinity of 1/sqrt(n^8 + 3)

Since we are trying to estimate the error using the sum of the first 10 terms, we can use n = 10 in the remainder formula:

R10 = sum from 11 to infinity of 1/sqrt(n^8 + 3)

To find an upper bound for R10, we can use the integral test:

1/sqrt(x^8 + 3) is a decreasing function for x ≥ 1, so we can use the integral from 10 to infinity to find an upper bound for R10:

integral from 10 to infinity of 1/sqrt(x^8 + 3) dx
≈ 0.01295

Therefore, we can estimate the error as:

error ≤ R10
     ≤ 0.01295

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Three of the system of equations has no solution and one have Infinite solutions.

Given are system of equations, we need to solve them,

A) 5(11x + 4) - x = 61x + 20

55x+20-x = 61x+20

55x = 62x [no solution]

B) 7(5x + 10) - x = 34x + 74

35x + 70 - x = 34x+74

34x + 70 = 34x + 74

70 = 74 [no solution]

C) 6x + 8 + x = 7x + 6

7x + 8 = 7x +6 [no solution]

D) 5(x − 12) + 3x = 8x - 60

5x-60+3x = 8x-60

8x-60 = 8x-60 [Infinite solutions]

Hence, three of the system of equations has no solution and one have Infinite solutions.

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Therefore, the fraction of the pizza left when the rats are done is 1/20.

we need to first find out how much of the pizza is left after the ogre eats 4/5 of it. We can do this by subtracting 4/5 from 1 (the whole pizza) to get 1/5.
Then, we need to find out how much of that 1/5 is left after the rats eat 3/4 of it. To do this, we can multiply 1/5 by 1/4 (since the rats ate 3/4, that means they left 1/4 of what was left) to get 1/20.
The ogre under the bridge eats 4/5 of the pizza, leaving 1/5 of the pizza left. Then, the rats eat 3/4 of what is left, which is 1/5. We can find out how much of that 1/5 is left by multiplying it by 1/4 (since the rats ate 3/4), which gives us 1/20. Therefore, the fraction of the pizza left when the rats are done is 1/20.

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The probability that one girl and two boys are chosen for the team is 0.355 or 35.5%.

The total number of ways to select a team of 3 students from 26 students is:

C(26, 3) = 26! / (3! (26-3)!) = 26! / (6! 20!) = 2600

To select a team of one girl and two boys, we can choose one girl from

the 14 girls and two boys from the 12 boys. So the number of ways to

select a team of one girl and two boys is:

C(14, 1) × C(12, 2) = 14! / (1! 13!) × 12! / (2! 10!) = 14 × 66 = 924

Therefore, the probability of selecting a team of one girl and two boys is:

P(one girl and two boys) = 924 / 2600 = 0.355 or 35.5% (approximate to

one decimal place).

So the probability that one girl and two boys are chosen for the team is

0.355 or 35.5%.

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When determining the cell density of a sample by the standard plate count method, the final density of cells is reported as colony forming units "(CFUs) per milliliter of sample."

This method involves diluting the sample and spreading it onto a solid agar medium, allowing the bacteria to grow and form visible colonies.

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Answer:

Let a be the cost of an adult ticket and c be the cost of a child's ticket.

40a + 25c = 56,050--->40a + 25c = 56,050

a + c = 1600-------------->40a + 40c = 64,000

----------------------------

15c = 7,950

c = 530, a = 1,070

530 child tickets, 1,070 adult tickets

The points at which the graph of  y = (x + 2)(x² + 4x + 3) crosses the x-axis are: (-1, 0), (-2, 0) and (-3, 0)

Consider an equation of the graph y = (x + 2)(x² + 4x + 3)

We need to find the points at wchi the graph of function y = (x + 2)(x² + 4x + 3)  crosses the x-axis.

We know that the x-intercept if nothing ut the point at whhich the graph of the function crosses the x-axis.

To find the x-intercept of the graph we need to solve an equation y = 0

Consider  y = 0

(x + 2)(x² + 4x + 3) = 0

x + 2 = 0    OR   x² + 4x + 3 = 0

x = -2      OR      (x + 1)(x + 3) = 0

x = -2      OR       x = -1         OR       x = -3

Thus the required points are x = -1, -2 and -3

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An example of a linear equation that represents a horizontal line is expressed as: y = 1.

The linear equation that represents a horizontal line is expressed as y = b, where the value of b is the point on the x-axis where the line intercepts the y-axis horizontal line. The point is on the line is (0, b).

An example of a graph that shows a horizontal line is attached below where the line cuts the y-axis at (0, 1).  Thus, the linear equation is expressed as y = 1.

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Multiple regression analysis assumes certain underlying statistical assumptions are met, such as linearity, independence of errors, homoscedasticity, and normally distributed errors.

A statistical method that would be best to use in this situation is Multiple Regression Analysis.

Multiple Regression Analysis is a statistical method used to identify the relationships between a dependent variable and multiple independent variables.

The dependent variable is the grade point average (GPA) of students, and the independent variables are the factors that may be affecting how well the students are doing.

Multiple regression can be used to model the relationships between these variables and to identify which factors are most strongly associated with differences in GPA.

Multiple regression analysis is a useful tool for exploring the complex relationships between multiple variables and can help identify which factors are most important in predicting GPA.

By analyzing the relationships between the various independent variables and GPA, school districts can identify areas where they may need to focus their efforts to improve academic performance.

It's also important to use caution when interpreting the results of regression analysis, as correlation does not necessarily imply causation, and other factors not included in the model may also be influencing GPA.

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The proof for each theorem is matched as;

<EFC is a right angle: Definition of a right angle

m<EFC = 90; Definition of a tangent line

m<EFC + m<FEC + m<ECF = 180 degrees; triangle sum theorem

90 + m<FEC + m<ECF = 180; substitution property of equality

m<FEC + m<ECF = 90; substitution property of equality

m<FEC + m<ECF = definition of complementary angles

To determine the values, we need to know the following;

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It would take approximately 0.458 seconds for the ball to travel from the hitter to the pitcher, assuming no other factors affecting the ball's trajectory.

To calculate the time elapsed between the hit and the ball reaching the pitcher, we need to know the distance between the hitter and the pitcher, as well as the speed of the ball.

Let's assume that the distance between the hitter and the pitcher is 60.5 feet, which is the distance between the pitcher's mound and home plate in baseball.

Assuming that there is no air resistance or other factors affecting the ball's trajectory, we can use the following equation to calculate the time elapsed:

time = distance / speed

In this case, the speed of the ball is 90 mph, which is equivalent to 132 feet per second. So:

time = 60.5 feet / 132 feet per second

time = 0.458 seconds

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Dion's study suffers from selection bias as his sample of individuals on the beach in Miami may not be representative of the entire population's affinity for warm weather.

This is because he is only sampling residents of Miami, Florida, who are on the beach.

This group may not accurately represent the entire population's affinity for warm weather, as it excludes those who may not enjoy the beach or may not have the opportunity to visit the beach.

A more representative sample would include individuals from various locations and backgrounds to better assess the affinity for warm weather across the population.

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The 98th percentile of the number of hours spent studying the week before final exams is approximately 39.35 hours.

The 98th percentile of the number of hours spent studying the week before final exams, assuming a normal distribution with mean 25 and standard deviation 7, can be calculated using the standard normal distribution table.

To find the z-score corresponding to the 98th percentile, we use the formula:

z = (x - μ) / σ

where x is the value at the 98th percentile, μ is the population mean, and σ is the population standard deviation.

Using a calculator, we find that the z-score corresponding to the 98th percentile is approximately 2.05.

To find the value of x at the 98th percentile, we rearrange the formula as:

x = μ + zσ

Substituting the given values, we get:

x = 25 + 2.05 × 7 ≈ 39.35

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The probability that Kareem will attend either State or Northern is 0.88, which is 88% as a percentage. Rounded to two decimal places, the answer is 0.88.

The probability that Kareem will attend either State or Northern is the sum of the individual probabilities of attending each college.

Probability is a measure of the likelihood or chance of an event occurring. It is usually expressed as a number between 0 and 1, where 0 indicates that an event is impossible and 1 indicates that an event is certain.

The probability of an event A is calculated as the number of outcomes that result in A divided by the total number of possible outcomes. This is known as the classical definition of probability.

P(State or Northern) = P(State) + P(Northern) = 0.55 + 0.33 = 0.88

So the probability that Kareem will attend either State or Northern is 0.88, which is 88% as a percentage. Rounded to two decimal places, the answer is 0.88.

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The correct value of [tex]$t^*$[/tex] to be used to create a 90% confidence interval for the true mean number of calls is 1.676

In this scenario, the director of a customer service center wants to estimate the mean number of customer calls the center handles each day. To create a 90% confidence interval for the true mean number of calls, the director needs to use a confidence interval formula that takes into account the sample size, sample mean, and the standard error of the mean.

The standard error of the mean, denoted as [tex]$SE_{\bar{x}}$[/tex], represents the standard deviation of the sampling distribution of the mean. It can be calculated using the formula:

[tex]$SE_{\bar{x}} = \frac{s}{\sqrt{n}}$[/tex]

where[tex]$s$[/tex] is the sample standard deviation and [tex]$n$[/tex] is the sample size.

The director can use the t-distribution to create the confidence interval, as the sample size is relatively small (less than 30). The formula for the 90% confidence interval is:

[tex]$\bar{x} \pm t^* \frac{s}{\sqrt{n}}$[/tex]

where[tex]$\bar{x}$[/tex] is the sample mean, [tex]$s$[/tex] is the sample standard deviation,[tex]$n$[/tex] is the sample size, and [tex]$t^*$[/tex] is the critical value from the t-distribution with (n-1) degrees of freedom and a 90% confidence level.

To determine the value of [tex]$t^*$[/tex], the director needs to consult a t-distribution table or use a statistical software. For a 90% confidence interval and 47 degrees of freedom (48 - 1), the value of [tex]$t^*$[/tex] is approximately 1.676.

Therefore, the correct value of [tex]$t^*$[/tex] to be used to create a 90% confidence interval for the true mean number of calls is 1.676. Using this value, the director can calculate the confidence interval by plugging in the sample mean, sample standard deviation, and sample size into the formula. This will give an estimate of the range of values where the true population mean lies with 90% confidence.

To learn more about confidence interval refer here:

https://brainly.com/question/29680703

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