find the circumference of a circular swimming pool with a diameter of 18 feet use 3.4 as an approximation round your answer to the nearest foot

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

Number of days Adya took to complete the work = 20

Work done by Adya in 1 day = [tex]\frac{1}{20}[/tex]

Number of days Ashley took to complete the work = 25

Work done by Ashley in 1 day = [tex]\frac{1}{25}[/tex]

So,

Total work by Adya & Ashley in 1 day =

[tex] \frac{1}{20} + \frac{1}{20} \\ = \frac{5 + 4}{100} \\ = \frac{9}{100} [/tex]

•°• Their total work in 10 days =

[tex] \frac{9 \times 10}{100} \\ = \frac{90}{100} \\ = \frac{9}{10} [/tex]

Now,

The work left to be completed =

[tex]1 - \frac{9}{10} \\ = \frac{10}{10} - \frac{9}{10} \\ = \frac{1}{10} [/tex]

From this we know that,

Amber completes [tex]\frac{1}{10}[/tex] of the work in 3 days.

So,

Time taken by Amber to complete the whole work =

[tex]3 \times 10 \\ = 30 \: \: days[/tex]

↦ If Amber alone would do the whole work, he would take [tex]\boxed{30 \ \ days}[/tex] to complete it.

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ ツ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Answer:

x = -4

Step-by-step explanation:

Plug in -4 into the function and solve for x:

f(x) = 6x + 20

-4 = 6x + 20

-24 = 6x

-4 = x

So, the answer is x = -4

Answer:

Check your question one time

Answer:

-√(1 - 2x) + C

Step-by-step explanation:

1/√(1-2x)

We want to integrate it. Thus;

∫1/√(1 - 2x) dx

Let u = 1 - 2x

Thus;

du/dx = -2

Thus, dx = -½du

Thus,we now have;

-½∫1/√(u) du

By application of power rule, we will now have;

-½∫1/√(u) du = -√(u) + C

Plugging in the value of u, we will have;

-√(1 - 2x) + C

Answer:

15 9 3

Step-by-step explanation:

15 9 3

sorry i guessed on this one

but it does work

when they said 3 in the first sentence i helped me guess

Answer:

first term = 15

second term = 9

Third term = 3

Step-by-step explanation:

Let the first term be 3x

Let the second term be = 3x - 6       [ 6 less than first term]

Let the third term be = 1/5 of 3x

                                 [tex]=\frac{1}{5} \times 3x\\\\=\frac{3}{5}x[/tex]

Difference between first and third term = 12

That is ,

           [tex]3x - \frac{3}{5}x = 12\\\\\frac{(3x \times 5) - 3x }{5} = 12\\\\15x - 3x = 12 \times 5\\\\12x = 60\\\\x = \frac{60}{12} = 5\\\\Therefore , \ first \ term = 3x = 3 \times 5 = 15\\\\second \term = 3x - 6 = 3( 5) - 6 = 15 - 6 = 9\\\\Third \ term = \frac{1}{5} \times 3x = \frac{1}{5} \times (3 \times 5) = 3[/tex]

Hello,

Answer (1/2,-1/4)

[tex]8x^2-2x-1=0\\\\8x^2-4x+2x-1=0\\\\4x(2x-1)+2x-1=0\\\\(2x-1)(4x+1)=0\\\\sol=\{\dfrac{1}{2} ,-\dfrac{1}{4} \}\\[/tex]

The equation is:

3n - 3 = 2n + 19

=> 3n - 2n = 19 + 3

=> n = 22

So, the answer is 22.

Answer:

Solution given:

f(x) = [tex]\frac{1}{9}[/tex] x-2

let f(x)=y

y = [tex]\frac{1}{9}[/tex] x-2

interchanging role of x and y

x= [tex]\frac{1}{9}[/tex] y-2

x+2= [tex]\frac{1}{9}[/tex] y

y=9(x+2)

y=9x+18

So

F-¹(x)=9x+18

and

F-¹(-1)=9*-1+18=-9+18=9

Answer:

2/3.

Step-by-step explanation:

.

Answer:

Solution given:

the relationship between perpendicular and base is given by tan angle

Tan 60=opposite/Adjacent

[tex]\sqrt{3}[/tex]=x/3

x=[tex]3\sqrt{3}[/tex]

The value of x is [tex]3\sqrt{3}[/tex]

Answer:

y=1x-5

Step-by-step explanation:

it goes over to the right 1 time and down 5

(1+1,6-5)=(2,1)

Answer:

Step-by-step explanation:

x²+y² =(Radius)²

x²+y² =10². So the radius is 10

Answer:

radius = 10

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ( where r is the radius )

x² + y² = 100 ← is in this form

with r² = 100 ( take the square root of both sides )

r = [tex]\sqrt{100}[/tex] = 10

Answer:

subtraction property of equality

Step-by-step explanation:

From the Standard form for quadratic equation, it is possible to see that step 1 represents the subtraction property of equality.

The quadratic function can be represented by a quadratic equation in the Standard form: ax²+bx+c=0 where: a, b and c are your respective coefficients. In the quadratic function the coefficient "a" must be different than zero (a≠0), the coefficient c is a constant and the degree of the function must be equal to 2.

From the Standard form: ax²+bx+c=0, it is possible to see that step 1:

–c = ax² + b represents the subtraction property of equality.

Read more about a quadratic function here:

brainly.com/question/1497716

Answer:x intercept is where the line is crossing the x axis or where y=0

y intercept is where the line crosses the y axis or where x=0

to find them, set other ting to zero

3/5x+1/3y=1/15

xintercept, set y=0

3/5x+1/3(0)=1/15

3/5x+0=1/15

3/5x=1/15

times 5/3 both sides

x=1/9

xintercept is x=1/9

yintercet

set x=0

3/5(0)+1/3y=1/15

0+1/3y=1/15

1/3y=1/15

times 3/1 both sides

y=1/5

yintercept is y=1/5

xint is x=1/9

yint is y=1/5

Step-by-step explanation:

The equation of line is ( 3/5 )x+ ( 1/3)y = ( 1/15 ) , where x-intercept of the line is ( 1/9 , 0 ) and the y-intercept of the line is ( 0 , 1/5 )

The equation of a line is expressed as y = mx + b where m is the slope and b is the y-intercept

And y - y₁ = m ( x - x₁ )

y = y-coordinate of second point

y₁ = y-coordinate of point one

m = slope

x = x-coordinate of second point

x₁ = x-coordinate of point one

The slope m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Given data ,

Let the equation of line be represented as A

( 3/5 )x+ ( 1/3)y = ( 1/15 )

To find the x-intercept of the line, we set y = 0 and solve for x:

3/5x + 1/3(0) = 1/15

3/5x = 1/15

x = (1/15) ÷ (3/5) = 1/9

So the x-intercept of the line is (1/9, 0)

To find the y-intercept of the line, we set x = 0 and solve for y:

3/5(0) + 1/3y = 1/15

1/3y = 1/15

y = (1/15) ÷ (1/3) = 1/5

So the y-intercept of the line is (0, 1/5)

Hence , the equation of line is solved

To learn more about equation of line click :

https://brainly.com/question/14200719

#SPJ2

Answer:

Step-by-step explanation:

u799

Answer:

5 is 14cm . 14 is 2pie r. 6 is 120

Answer:

Question 5 = 14

Question 6 = 120

I hope this helped!

Answer:

270 & 30

Step-by-step explanation:

let the number is n,

the equation :

n× 1/9 n= 27(n +1/9 n)

1/9 n² = 27n + 3n

1/9 n² = 30n

1/9n²- 30n = 0

n(1/9n -30)= 0

n = 0 or

1/9n = 30 => n = 30×9 = 270

270 is a number,

the other : 270/9 = 30

Answer:

In this case, we can do substitution.

Step-by-step explanation:

For the first one, (s - t)(x) = ((x - 5) - 4x^2)(x) = x^2 - 21x

For the second one, (s*t)(x) = ((x - 5) *4x^2)(x) = 4x^4 - 20x^3

And for the last one,  (s+t)(-2) = ((x - 5) + 4x^2)(-2) = -8x^2 - 2x + 10

Hope your happy with the answer :)

Answer:

6x2+3y2=12,x+y=2,2x-y=-1x+y=4,x-y=2

Step-by-step explanation:

I just know.

Answer:

Step-by-step explanation:

5x – 4y = -10

y = 2 x – 5

Rearrage the equation:

5x – 4y = -10 (1)

-2 x +y =  5.  (2)

pluging variable y equation2 in 1

5x - 4•(2x-5) = -10

 -3x = -30

Solve equation [1] for the variable  x  

3x = 30

x = 10

x = 10

y = 2x-5

Use the  x  value to solve for  y  

y = 2(10)-5 = 15

x= 10

y= 15

Answer:

B) =−7j−k−1

Step-by-step explanation:

10k+17-7j-18-11k what we have

=(−7j)+(10k+−11k)+(17+−18) combine like terms

=−7j−k−1

Answer:

-7j-k-1

Step-by-step explanation:

for this problem you have to subtract the like terms while following the order of the equation (start with the terms on the left and move terms)

Step 1:

-7j has no like terms

= -7j

Step 2:

10k and -11k are like terms

10k-11k

= -1k

Step 3:

17 and -18 are like terms

17-18

= -1

Step 4:

put all simplified terms together

=-7j-k-1

Answer:

is there is no value of April

Step-by-step explanation:

so the value of the month April is zero

Given:

The focus of the parabola is at (6,-4).

Directrix at y=-7.

To find:

The equation of the parabola.

Solution:

The general equation of a parabola is:

[tex]y=\dfrac{1}{4p}(x-h)^2+k[/tex]                  ...(i)

Where, (h,k) is vertex, (h,k+p) is the focus and y=k-p is the directrix.

The focus of the parabola is at (6,-4).

[tex](h,k+p)=(6,-4)[/tex]

On comparing both sides, we get

[tex]h=6[/tex]

[tex]k+p=-4[/tex]                            ...(ii)

Directrix at y=-7. So,

[tex]k-p=-7[/tex]                            ...(iii)

Adding (ii) and (iii), we get

[tex]2k=-11[/tex]

[tex]k=\dfrac{-11}{2}[/tex]

[tex]k=-5.5[/tex]

Putting [tex]k=-5.5[/tex] in (ii), we get

[tex]-5.5+p=-4[/tex]

[tex]p=-4+5.5[/tex]

[tex]p=1.5[/tex]

Putting [tex]h=6, k=-5.5,p=1.5[/tex] in (i), we get

[tex]y=\dfrac{1}{4(1.5)}(x-6)^2+(-5.5)[/tex]

[tex]y=\dfrac{1}{6}(x-6)^2-5.5[/tex]

Therefore, the equation of the parabola is [tex]y=\dfrac{1}{6}(x-6)^2-5.5[/tex].

Answer:

A - True

B - False

C - True

D - False

E - True

Step-by-step explanation:

うsじょうぉじょあそlざ

ありおdごうおの

Answer:

First drop box: 40x + 18(x - 3) = 468

Second drop box: $6

Step-by-step explanation:

Explanation in progress! Enjoy your answer first then come back for the explanation once you've done it (●'◡'●)

Answer:

Answer:

The x and y coordinates swap position

Step-by-step explanation:

Given

Reflection across: [tex]y = x[/tex]

Required

What happens to the coordinate

When a point is reflected about [tex]y = x[/tex], the x and y coordinates swap position

i.e.

[tex](x,y) \to (y,x)[/tex]

Answer:

When the shape reflects about the line y = x, the x-coordinate and the y-coordinate of each point are swapped.

Step-by-step explanation:

Answer:

36?

Step-by-step explanation:

Answer:

42 Triangles

Step-by-step explanation:

Count all the triangles one by one and determine the # of triangles.

Answer:

a. 18

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Distributive Property

Algebra I

Calculus

Integrals

Integration Rule [Reverse Power Rule]:                                                                      [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                        [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:                                                             [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:                                                           [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int\limits^2_0 {x(4x^2 + 1)} \, dx[/tex]

Step 2: Integrate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

Answer:

27/10 is the value of (3/10)^3.

Step-by-step explanation:

It is also written as 0.027

Hello,

Let 's  n the number of sides,

R the radius of the circonscrit circle,

c the side of the polygon (c like côté)

Angle in the center is 360/n and its half is 180/n

(c/2)/R=sin(180/n)

Inside angles are (180-360/n)/2 = 90-180/n (°)