Find the average rate of change of g(x)=-2x^3-5 from x=-4 to x=1

Answer:

c The expansion of (x + y)^6 will yield 7 terms

Step-by-step explanation:

(x + y)^6 =

x^6 +6x^5y + 15x^4y^2 + 20x^3y^3 + 15x^2y^4 + 6xy^5 + y^6

so its a no on A

its a no on B because its missing a 20

its a yes on c

its a no on d because the sum is 6

so c

Answer: 24

Step-by-step explanation:

Answer:

[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]

Step-by-step explanation:

The given expression to us is ,

[tex]\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}[/tex]

Now take the LCM as ( x - 1 ) and Simplify , we have ,

[tex]\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}[/tex]

Simplifying further , we get ,

[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]

Hence the second option is correct.

Answer:

[tex] \frac{ \frac{3}{x - 1} - 4}{2 - \frac{2}{x - 1} } \\ = \frac{ \frac{3 - 4(x - 1)}{x - 1} }{ \frac{2(x - 1)}{x - 1} } \\ = \frac{3 - 4x + 4}{2x - 2} \\ \frac{ - 4x + 7}{2(x - 1)} \\ option \: b \: is \: your \: answer \\ thank \: you[/tex]

Answer:

n=5

Step-by-step explanation:

by using

n=(an-a)/a+1

substituting values

n= 7.2-(-7.2)/3.6 +1

n=5

Answer:

Option A

Step-by-step explanation:

We need to solve out ,

[tex]\implies |5x + 30| = 10x [/tex]

We can write it as ,

[tex]\implies 5x + 30 = \pm 10x [/tex]

On simplyfing further,

[tex]\implies 5x + 30 = 10x \quad or \quad 5x +30=-10x [/tex]

On solving the above equation , we will get ,

[tex]\implies \boxed{ x = 6,-2}[/tex]

Now we know that the value of modulus is never negative so when we will put x is equal to 2 on the RHS we will get -20 which is not possible . Therefore , the extraneous root is -2 .

Option A is correct .

Answer:

[tex]\displaystyle x=\frac{-1}{2}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

x² + x + 1/4 = 0

↓ Compare to Standard Form

a = 1, b = 1, c = 1/4

Step 2: Solve for x

Answer:

C=32°

because sum of three angles of triangles is 180°

Answers:

Domain = {-1, 2, 1, 8, 9}

Range = {2, 51, 3, 22}

==================================

Explanation:

The domain is the set of allowed inputs of a function. So it's the set of possible x values. We simply list the x coordinates of each point to form the domain.

The range is the set of possible y values or y outputs. So we simply list the y coordinates of the points. We toss out any duplicates. Since order doesn't matter in a set, we can have the values listed any way we want.

Side notes:

Answer:

this as a equation looks like this

-1/2x+1+x=11

1/2x=10

x=20

Hope This Helps!!!

20 dollars were originally in the box

Two or more expressions with an Equal sign is called as Equation.

Given,

In an office there was a small cash box.

One day ann took half of the money plus$1 more

Then dan took half of the remaining money plus$1 more

Stan then took the remaining $11

-1/2x+1+x=11

Subtract 1/2x from both sides

1/2x=10

Multiply 2 on both sides

x=20

Hence, 20 dollars were originally in the box

To learn more on Equation:

https://brainly.com/question/10413253

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Answer:

34

Step-by-step explanation:

First we need to do 2/3*21, which equals 14 as 3 and 21 can be simplified to 1 and 7. 7 * 2/1= 14. Then we add the 20 to 14, 20+14= 34

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{y = \dfrac{2}{3}x + 20}[/tex]

[tex]\mathsf{y =\dfrac{2}{3}(21) + 20}[/tex]

[tex]\mathsf{\dfrac{2}{3}(21) + 20 = y }[/tex]

[tex]\mathsf{\dfrac{2}{3}(21)=\bf14}[/tex]

[tex]\mathsf{14 + 20 = y}[/tex]

[tex]\mathsf{14 + 20 = \bf 34}[/tex]

[tex]\huge\checkmark\boxed{\huge\textsf{y = 34}}\huge\checkmark[/tex]

[tex]\boxed{\boxed{\huge\textsf{Answer: \bf y = 34}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\huge\text{Amphitrite1040:)}[/tex]

Answer:

boom box second one one my bad just need points my g

Step-by-step explanation:

Answer:

3

decreasing

negative

Step-by-step explanation:

The graph of function g crosses the x-axis at (3,0), so there is a zero at x = 3.

As the values of x increase, the values of g(x) decrease, so function g is decreasing along all intervals, including the interval [-5, 5].

As the values of x approach positive infinity, cube root functions either approach positive infinity or negative infinity. Since this function is decreasing, the values of g(x) approach negative infinity.

Answer:

8.9m/s

Step-by-step explanation:

Time= 28s

Displacement= 250m

Velocity=?

Velocity (v) = displacement (d)/ Time (t)

V= 250/28

V=8.9m/s

OR YOU CAN APPROXIMATE IT

V=8.928

YOU CAN APPROXIMATE IT TO

V=8.93m/s

Answer:

p = 3

Step-by-step explanation:

Applying,

mid point of A and B is

P = [(x₁+x₂)/2,(y₁+y₂)/2]............... Equation 1

From the question,

Given: x₁ = 6, x₂ = -2, y₁ = -5, y₂ = 11

Substitute these values into equation 1

P = [(6-2)/2,(-5+11)/2)

P = (2,3)

comparing,

P(2,p) to (4,3)

Therefore,

p = 3

Answer:

Top one: y= 3/1+2

bottom: y= -1/1+4

Answer:

Step-by-step explanation:

Eq. 1 )   −5x−3y−9=0

Eq. 2)   4x−18y−54=0

there are two routes to solve this,   Substitution or  elimination,  I'll go for the 2nd one because I can see that the y values are a multiple of each other :)

    6 *( −5x−3y−9=0 )

Eq. 3) -30x -18y =54

subtract Eq. 2 from Eq. 3  :)

-30x -18y =54

-( 4x−18y=54)

-34x = 0

so according to the equations then x =0 but,  that's not really a full answer, so now we should go back and try the other method, substitution,

then:

-5x = 9 +3y

x = - 9/5 + (-3/5)y

now plug that into Eq. 2

4( - 9/5 + (-3/5)y ) - 18y = 54

-36/5 + (-12/5)y -18y = 54

(-12/5)y - (90/5)y = 54+36/5

-(102/5)*y =270/5+36/5

-(102/5)y = 306/5

y = (-5/102)*(306/5)

y = -306/102

y = -3

then plug in for either equation

-5x-3( -3) = 9

-5x + 9 = 9

-5x = 0

x = 0

now we have the full answer

check it by plugging in both x and y into the 2nd equation

4(0) - 18(-3) = 54

54= 54

this seems good  

Answer:

no hablo inglés wey perdón corona y gracias

Answer:

(0, 5).

Step-by-step explanation:

$5 is the base fee, so when x = 0, y = 5. 0.75 won't come into play yet.

Answer:

53:36

Step-by-step explanation:

53:36

265:180

The ratio of time Dhanu spent playing with model railway to the time riding bicycle is 53 : 35.

Ratio expresses the relationship between two or more numbers. It shows the frequency of the number of times that one value is contained within other value(s).

Time spent playing with the model railway = 4 hours 25 minutes.

Converting the time to minutes = (4 x 60) + 25 = 265 minutes

Time in minutes spent riding a bicycle = 60 x 3 = 180

Ratio of the minutes - 265 : 180

53 : 35

To learn more about ratios, please check: https://brainly.com/question/25927869

Answer:

x = 23

Step-by-step explanation:

if line j is parallel to line k then

5x + 9 + 33 + x = 180 add like terms

6x + 42 = 180 subtract 42 from both sides

6x = 138 divide both sides by 6

x = 23

Answer:

Algebra

Step-by-step explanation:

(+) it's the same thing btw6x -8 = 4x

(collect like terms) meaning the numbers with x go over the " = " sign

making it = -8 = 4x -6x

the signs change when it crosses over so it becomes that

-8 = -2x

-8 ÷ -2 = 4 (cause - ÷ by - is + )

Answer:

F(g(×)1=3(6+2)-5=18×+6-5=18×+1

Step-by-step explanation:

so correct answer is the last one pa brainliest plss

Answer:

12 in 29. uou add all the number together then and it is 12 red marbles in 29 chancesso you take one marble out and put the exact marble back in having no effect.

Answer:

Step-by-step explanation:

Answer:

15/X

Step-by-step explanation:

a number divided by 15

15/X

Answer:

The larger van has 23 seats

Step-by-step explanation:

Create a system of Equations:

1. Define variables.

> let x=small van and y=larger van

2. create 2 equations based on the information given.

> y = 6 + x

> 2x + y = 57

3. Use any method to solve

Substitution: 2x + (6 + x) = 57. x=17

                      now plug x in to the original equation to solve for y (the larger van)

                      y = 6 + 17 and y = 23

Elimination: 2y = 12 + 2x

                     y = 57 - 2x

         3y = 69  and y = 23

Answer:

[tex]x=6[/tex]

Step-by-step explanation:

We want to solve the equation:

[tex]\displaystyle \log_6(2x-6)+\log_6x=2[/tex]

Recall the property:

[tex]\displaystyle \log_bx+\log_by=\log_b(xy)[/tex]

Hence:

[tex]\log_6(x(2x-6))=2[/tex]

Next, recall that by the definition of logarithms:

[tex]\displaystyle \log_b(a)=c\text{ if and only if } b^c=a[/tex]

Therefore:

[tex]6^2=x(2x-6)[/tex]

Solve for x. Simplify and distribute:

[tex]36=2x^2-6x[/tex]

We can divide both sides by two:

[tex]x^2-3x=18[/tex]

Subtract 18 from both sides:

[tex]x^2-3x-18=0[/tex]

Factor:

[tex](x-6)(x+3)=0[/tex]

Zero Product Property:

[tex]x-6=0\text{ or } x+3=0[/tex]

Solve for each case. Hence:

[tex]x=6\text{ or } x=-3[/tex]

Next, we must check the solutions for extraneous solutions. To do so, we can simply substitute the solutions back into the original equations and examine its validity.

Checking x = 6:

[tex]\displaystyle \begin{aligned} \log_{6}(2(6)-6)+\log_{6}6&\stackrel{?}{=} 2 \\ \\ \log_6(12-6)+(1)&\stackrel{?}{=}2 \\ \\ \log_6(6)+1&\stackrel{?}{=}2 \\ \\ 1+1=2&\stackrel{\checkmark}{=}2\end{aligned}[/tex]

Hence, x = 6 is indeed a solution.

Checking x = -3:

[tex]\displaystyle\begin{aligned} \log_6(2(-3)-6) + \underbrace{\log_6-3}_{\text{und.}} &\stackrel{?}{=} 2\\ \\ \end{aligned}[/tex]

Since the second term is undefined, x = -3 is not a solution.

Therefore, our only solution is x = 6.

Answer:

x = 6

Step-by-step explanation:

The given logarithmic equation is ,

[tex]\implies log_{6}(2x - 6) + log_{6}x = 2[/tex]

We can notice that the bases of both logarithm is same . So we can use a property of log as ,

[tex]\bf \to log_a b + log_a c = log_a {( ac)} [/tex]

So we can simplify the LHS and write it as ,

[tex]\implies log_{6} \{ x ( 2x - 6 )\} = 2 [/tex]

Now simplify out x(2x - 6 ) . We get ,

[tex]\implies log_6 ( 2x^2 - 6x ) = 2 [/tex]

Again , we know that ,

[tex]\bf \to log_a b = c , a^c = b [/tex]

Using this we have ,

[tex]\implies 2x^2 - 6x = 6^2 \\\\\implies 2x^2 - 6x -36 = 0 [/tex]

Now simplify the quadratic equation ,

[tex]\implies x^2 - 3x - 18 = 0 \\\\\implies x^2 -6x + 3x -18=0\\\\\implies x( x -6) +3( x - 6 ) = 0 \\\\\implies (x-6)(x+3) = 0 \\\\\implies x = 6 , -3 [/tex]

Since logarithms are not defined for negative numbers or zero , therefore ,

[tex]\implies 2x - 6 > 0 \\\\\implies x > 3 [/tex]

Therefore the equation is not defined at x = -3 . Hence the possible value of x is 6 .

[tex]\implies \underline{\underline{ x \quad = \quad 6 }}[/tex]

Answer:

-24

Step-by-step explanation:

rest 6 minus 30 and it give you -24