Find the arithmetic mean of the sales per day in a fair price shop in a week.
Rs 10000, Rs 10250, Rs 10790, Rs 9865, Rs 15350, Rs 10110.​

Answer:

Step-by-step explanation:

[tex]\text{We have a rectangle of 100 by 50 and half a circle with a radius of 25.}\\ \\ A=100(50)+3.14(25^2)\\ \\ A\approx 6962.5\ m^2[/tex]

Answer:

2km

Step-by-step explanation:

400*5=2000m

2000/1000=2km

Answer:

Part A

There is sufficient statistical evidence to suggest that the difference between the proportion of White students exposed to poverty is likely due to something beside chance

Part B

There is sufficient statistical evidence to suggest that the difference between the proportion of Black students exposed to poverty is likely due to something beside chance

Step-by-step explanation:

Part A

The given data are;

The percent of White students exposed to school poverty in 2,000, [tex]\hat p_1[/tex] = 30%

The number of White students in the district in 2,000, n₁ = 5184

The percent of White students exposed to school poverty in 2,015, [tex]\hat p_2[/tex] = 47.8%

The number of White students in the district in 2,015, n₂ = 7,306

The significant level, α = 0.05

The confidence level = 1 - α/2 = 1 - 0.05/2 = 0.975

The critical z at 0.975 confidence level, [tex]Z_c[/tex] = 1.96

The null hypothesis, H₀; [tex]\hat p_1[/tex] = [tex]\hat p_2[/tex]

The null hypothesis, H₀; [tex]\hat p_1[/tex] ≠ [tex]\hat p_2[/tex]

The Z test is given as follows;

[tex]Z=\dfrac{\hat{p}_1-\hat{p}_2}{\sqrt{\hat{p}(1-\hat{p})\left (\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}} \right )}}[/tex]

Therefore, we have;

[tex]Z=\dfrac{0.3 - 0.478}{\sqrt{0.3 \cdot (1-0.3)\left (\dfrac{1}{5184}+\dfrac{1}{7306} \right )}} = -21.3894[/tex]

Given that the actual Z is much larger than the critical Z, we reject the null hypothesis that the difference between the proportion of White students is likely due to something other than chance

Part B, we have;

The percent of black students exposed to school poverty in 2,000, [tex]\hat p_1[/tex] = 34.5%

The number of black students in the district in 2,000, n₁ = 1035

The percent of black students in the district in 2,015, [tex]\hat p_2[/tex] = 76.1%

The number of black students in the district in 2,000, n₁ = 2037

[tex]Z=\dfrac{0.345 - 0.761}{\sqrt{0.345 \cdot (1-0.35)\left (\dfrac{1}{1,035}+\dfrac{1}{2,037} \right )}} =-22,925[/tex]

Similarly, due to the large value of Z compared to [tex]Z_c[/tex], there must be other variables responsible for the difference in proportion

Answer:

x=17

Step-by-step explanation:

The equation is 44+60+(4×+8)=180

Answer:

14 minutes

Step-by-step explanation:

The barrel held 21 quarts of oil, which is equal to 84 cups. Trina drains the barrel at 6 cups per minute, so to find out how much time it takes her to drain it, divide 84 by 6:

84 / 6 = 14

So, it took Trina 14 minutes to drain the whole barrel.

Answer:

y= 150,000(1+0.08)^t

The exponential growth equation is f ( x ) = 150,000 ( 1 + 0.08 )ˣ , where x is the number of years = t

The exponential growth or decay formula is given by

x ( t ) = x₀ × ( 1 + r )ⁿ

x ( t ) is the value at time t

x₀ is the initial value at time t = 0.

r is the growth rate when r>0 or decay rate when r<0, in percent

t is the time in discrete intervals and selected time units

Given data ,

Let the initial value of the function be x₀ = 150,000

Now , the initial attendance = x₀

And , the percentage of increase every year r = 8 %

So , the equation will be

f ( x ) = x₀ × ( 1 + r )ˣ , where x is the number of years = t

Substituting the values in the equation , we get

f ( x ) = 150,000 ( 1 + 0.08 )ˣ

Hence , the exponential growth equation is f ( x ) = 150,000 ( 1 + 0.08 )ˣ

To learn more about exponential growth factor click :

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Answer:

a) The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams

b) 49 measurements are needed.

Step-by-step explanation:

Question a:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.98}{2} = 0.01[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.01 = 0.99[/tex], so Z = 2.327.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 2.327\frac{0.0003}{\sqrt{5}} = 0.00031[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 10.0044 - 0.00031 = 10.00409 grams

The upper end of the interval is the sample mean added to M. So it is 10 + 0.00031 = 10.00471 grams

The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams.

(b) How many measurements must be averaged to get a margin of error of +/- 0.0001 with 98% confidence?

We have to find n for which M = 0.0001. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]0.0001 = 2.327\frac{0.0003}{\sqrt{n}}[/tex]

[tex]0.0001\sqrt{n} = 2.327*0.0003[/tex]

[tex]\sqrt{n} = \frac{2.327*0.0003}{0.0001}[/tex]

[tex](\sqrt{n})^2 = (\frac{2.327*0.0003}{0.0001})^2[/tex]

[tex]n = 48.73[/tex]

Rounding up

49 measurements are needed.

Answer:

10

Step-by-step explanation:

6^2+8^2=x^2

36+64=x^2

x=sqrt100

x=10

Answer:

Step-by-step explanation:

according to the question

3x-20+4x+11=180

=>7x-9=180

=>7x=180+9

=>7x=189

=>7x/7=189/7

therefore

Answer:

z=13

Step-by-step explanation:

Answer:

.25 is the answer

Step-by-step explanation:

.5/2=.25

Answer:

Exponents, Multiplication, Division (from left to right), Addition, Subtraction (from left to right), value

Step-by-step explanation:

Answer:

Step-by-step explanation:

because in square all sides are equal

Answer:

bc=28

Step-by-step explanation:

give them brainliest

Answer:D

Step-by-step explanation:

it has 2 number between 8-10 and the graph doesn't

PLZ GIVE BRAINLY

Answer:

The researcher did not state that the p-value is conditional on the null hypothesis being true.

Step-by-step explanation:

The p-value or the assumed value represent the probability in which the test results that are received would be atleast extreme in that the null hypothesis would be correct

Here the wrong thing would be that researcher would not stated the p value is in conditional form based on the null hypothesis being true

Therefore the correct option is A.

Answer:

8-x is the expression for the question

Answer:

The correct answer is 3x

Step-by-step explanation:

Add 2x and x

~Hoped this helped~

~Brainiliest, please?~

Answer:

$52.80

Step-by-step explanation:

First off we need to find out how much she didn't save (to make it easier)

$120 - 44% = $67.20

Well how much did she save? Lets subtract $67.20 from $120 to find our answer.

$120 - $67.20 = $52.80

Emma saved $52.80 (44%).

Hopefully this helps :3 Sorry if wrong :( plz mark brainiest if correct :D Your bootiful/handsome! Have a great day luv <3

-Bee~

Answer:

The integral of the volume is:

[tex]V = 32\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy[/tex]

The result is: [tex]V = 78.97731[/tex]

Step-by-step explanation:

Given

Curve: [tex]x^2 + 4y^2 = 4[/tex]

About line [tex]x = 2[/tex] --- Missing information

Required

Set up an integral for the volume

[tex]x^2 + 4y^2 = 4[/tex]

Make x^2 the subject

[tex]x^2 = 4 - 4y^2[/tex]

Square both sides

[tex]x = \sqrt{(4 - 4y^2)[/tex]

Factor out 4

[tex]x = \sqrt{4(1 - y^2)[/tex]

Split

[tex]x = \sqrt{4} * \sqrt{(1 - y^2)[/tex]

[tex]x = \±2 * \sqrt{(1 - y^2)[/tex]

[tex]x = \±2 \sqrt{(1 - y^2)[/tex]

Split

[tex]x_1 = -2 \sqrt{(1 - y^2)}\ and\ x_2 = 2 \sqrt{(1 - y^2)}[/tex]

Rotate about x = 2 implies that:

[tex]r = 2 - x[/tex]

So:

[tex]r_1 = 2 - (-2 \sqrt{(1 - y^2)})[/tex]

[tex]r_1 = 2 +2 \sqrt{(1 - y^2)}[/tex]

[tex]r_2 = 2 - 2 \sqrt{(1 - y^2)}[/tex]

Using washer method along the y-axis i.e. integral from 0 to 1.

We have:

[tex]V = 2\pi\int\limits^1_0 {(r_1^2 - r_2^2)} \, dy[/tex]

Substitute values for r1 and r2

[tex]V = 2\pi\int\limits^1_0 {(( 2 +2 \sqrt{(1 - y^2)})^2 - ( 2 -2 \sqrt{(1 - y^2)})^2)} \, dy[/tex]

Evaluate the squares

[tex]V = 2\pi\int\limits^1_0 {(4 +8 \sqrt{(1 - y^2)} + 4(1 - y^2)) - (4 -8 \sqrt{(1 - y^2)} + 4(1 - y^2))} \, dy[/tex]

Remove brackets and collect like terms

[tex]V = 2\pi\int\limits^1_0 {4 - 4 + 8\sqrt{(1 - y^2)} +8 \sqrt{(1 - y^2)}+ 4(1 - y^2) - 4(1 - y^2)} \, dy[/tex]

[tex]V = 2\pi\int\limits^1_0 { 16\sqrt{(1 - y^2)} \, dy[/tex]

Rewrite as:

[tex]V = 16* 2\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy[/tex]

[tex]V = 32\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy[/tex]

Using the calculator:

[tex]\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy = \frac{\pi}{4}[/tex]

So:

[tex]V = 32\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy[/tex]

[tex]V = 32\pi * \frac{\pi}{4}[/tex]

[tex]V =\frac{32\pi^2}{4}[/tex]

[tex]V =8\pi^2[/tex]

Take:

[tex]\pi = 3.142[/tex]

[tex]V = 8* 3.142^2[/tex]

[tex]V = 78.97731[/tex] --- approximated

Answer:   The last one is the one with the Median

Step-by-step explanation: Hope this helps ^^

Answer:

18,15,11,14,19,15,6 the last one

Solution

x=5

x= -3/2

Hopefully its good

Answer:

domain:{10,28,42,52}

range:{-10,6,10}

Step-by-step explanation:

Hello There!

If you didn´t know the domain is the set of x values

the x values in the given relation are

10,28,42,10 and 52

so the domain is {10,28,42,52}

The range is the set of y values

the y values in the given relations are

6,-10,6,10,10

so the range is {-10,6,10}

Answer:

[tex]f(x)=2(x-2)(x^2+64)[/tex]

Step-by-step explanation:

A standard polynomial in factored form is given by:

[tex]f(x)=a(x-p)(x-q)...[/tex]

Where p and q are the zeros.

We want to find a third-degree polynomial with zeros x = 2 and x = -8i and equals 320 when x = 4.

First, by the Complex Root Theorem, if x = -8i is a root, then x = 8i must also be a root.

Therefore, we acquire:

[tex]f(x)=a(x-(2))(x-(-8i))(x-(8i))[/tex]

Simplify:

[tex]f(x)=a(x-2)(x+8i)(x-8i)[/tex]

Expand the second and third factors:

[tex]=(x+8i)x+(x+8i)(-8i)\\\\=(x^2+8ix)+(-8ix-64i^2)\\\\=(x^2)+(8ix-8ix)+(-64i^2)\\\\=x^2-64(-1)\\\\ =x^2+64[/tex]

Hence, our function is now:

[tex]f(x)=a(x-2)(x^2+64)[/tex]

It equals 320 when x = 4. Therefore:

[tex]320=a(4-2)(4^2+64)[/tex]

Solve for a. Evaluate:

[tex]320=(2)(80)a[/tex]

So:

[tex]320=160a\Rightarrow a=2[/tex]

Our third-degree polynomial equation is:

[tex]f(x)=2(x-2)(x^2+64)[/tex]

Answer:

f(x)=2(x-2)(x^2+64)

Step-by-step explanation:

Answer:

B. As t approaches positive infinity, A(t) approaches zero and B(t) approaches positive infinity.

Step-by-step explanation:

I got it right on my test

Answer:

420 points

Step-by-step explanation:

5 levels of video games = 175 points

1 level = 175 ÷ 5

= 35 points

Therefore,

12 levels of video games = 35 × 12

= 420 points

Answer:

180

Step-by-step explanation: