Find the area of the quadrilateral.

Answer:

21/8x

Step-by-step explanation:

10x -20 = -6x+22

+6x-20 = 22

16x-20 = 22

16x +20= +20

16x/16x = 42/16x

x = 21/8x

Answer:

you have to wait until two people answer then you click their answer to make them brainliest

Step-by-step explanation:

i dont know

blah blah blah blah blah blah blah blah blah blah blah blah

Answer:

AB

Step-by-step explanation:

From the question given above, we were told that triangle ABC is similar to triangle PTG.

Since both triangles are similar, the following assumptions hold:

PG / AC = PT / AB = TG / BC

Comparing the equation above with those given in the question, the missing part of the equation is AB

Answer:

Step-by-step explanation:

The formula for arc length is

[tex]AL=\frac{\theta}{360}*2\pi r[/tex] where theta is the measure of the central angle and r is the radius. We have both of those pieces of info; filling in:

[tex]AL=\frac{30}{360}*2(3.14) (4)[/tex] and simplifying a bit:

[tex]AL=\frac{1}{12}(8)(3.14)[/tex] and a bit more:

[tex]AL=\frac{25.12}{12}[/tex] and finally, to

AL = 2.09 m

Answer:

20 participants

Step-by-step explanation:

Given

[tex]Conditions = 2[/tex]

[tex]Scores = 20[/tex]

Type: Repeated design

Required

The number of participants (n)

The repeated measure design implies that the test was conducted repeatedly on the same sample size.

Since the score in each test is 20; then:

[tex]n = 20[/tex] --- the number of participants

Answer:

If your cost Is $66.00, how many miles were you charged for traveling?

[tex]66=46+0.25x\\66-46=0.25x\\20=0.25x\\x=\frac{20}{0.25} =80[/tex]80 miles

You have a max of $100 to spend on a car rental. what would be the maximum number of miles you could Travel?

[tex]100=46+0.25x\\100-46=0.25x\\54=0.25x\\x=\frac{54}{0.25} =216[/tex]216 miles

Answer:

In general gf(x) is not equal to fg(x)

Some pairs of functions cannot be composed. Some pairs of functions can be composed only  for certain values of x.

Only with they can be composed some values of x are the ranges of g(x) and f(x) are the same, and their domains are also the same. Or else lies inside it.

Step-by-step explanation:

g(x) = 3x + 6 - 8, f(x) = √x.

The domain of a composed function is either the same as the domain of the first function, or  else lies inside it

The range of a composed function is either the same as the range of the second function, or else lies inside it.

Or vice versa

Now only positive numbers, or zero, have real square roots. So g is defined only for numbers

greater than or equal to zero. Therefore g(f(x)) can have a value only if f(x) is greater than or

equal to zero. You can work out that

f(x) ≥ 0 only when x ≥3/2

.

Answer:

The answer is

[tex]y = 3[/tex]

[tex]y = - 4[/tex]

Step-by-step explanation:

We must find a solution where

[tex] \frac{6}{y + 1} + \frac{y}{y - 2} = \frac{6}{y + 1} \times \frac{y}{y - 2} [/tex]

Consider the Left Side:

First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get

[tex] \frac{6}{y + 1} \times \frac{y - 2}{y - 2} + \frac{y}{y - 2} \times \frac{y + 1}{y + 1} [/tex]

Which equals

[tex] \frac{6y - 12}{(y -2) (y + 1)} + \frac{ {y}^{2} + y }{(y - 2)(y + 1)} [/tex]

Add the fractions

[tex] \frac{y {}^{2} + 7y - 12 }{(y - 2)(y + 1)} = \frac{6}{y + 1} \times \frac{y}{y - 2} [/tex]

Simplify the right side by multiplying the fraction

[tex] \frac{6y}{(y + 1)(y + 2)} [/tex]

Set both fractions equal to each other

[tex] \frac{6y}{(y + 1)(y - 2)} = \frac{ {y}^{2} + 7y - 12}{(y + 1)(y - 2)} [/tex]

Since the denomiator are equal, we must set the numerator equal to each other

[tex]6y = {y}^{2} + 7y - 12[/tex]

[tex] = {y}^{2} + y - 12[/tex]

[tex](y + 4)(y - 3)[/tex]

[tex]y = - 4[/tex]

[tex]y = 3[/tex]

Answer:

Step-by-step explanation:

[tex]\frac{6}{y+1}+\frac{y}{y-2}=\frac{6}{y+1} \times \frac{y}{y-2} \\multiply ~by~(y+1)(y-2)\\6(y-2)+y(y+1)=6y\\6y-12+y^2+y=6y\\y^2+y-12=0\\y^2+4y-3y-12=0\\y(y+4)-3(y+4)=0\\(y+4)(y-3)=0\\y=-4,3[/tex]

Answer:

a) 93.75%; 6.25%

b) Keep :)

Step-by-step explanation:

[tex]\frac{45}{48}=0.9375=93.75[/tex]

93.75% made

6.25% missed

Hope this helped! Please mark brainliest :)

Answer:

1/16.

Step-by-step explanation:

2^-4 = 1/2^4

= 1/16.

Answer:

39°

Step-by-step explanation:

A radius of a circle (segment CD) drawn to the point of tangency (D) intersects the tangent (line DE) at a 90-deg angle.

That makes m<D = 90.

m<D + m<C + m<E = 180

90 + 51 + m<E = 180

m<E = 39

Answer:

b=2

Step-by-step explanation:

Step-by-step explanation:

total number of students are :4x 3 = 12

Fraction that's boys are : 3÷12

Answer:

The statement is false

Step-by-step explanation:

Given

See comment for complete statement

Required

Is the statement true or false

From central limit theorem, we understand that a distribution is approximately normal if the distribution takes a sample considered to be large enough from the population.

Also, the mean and the standard deviation are known.

However, the given statement implies that the distribution will be normal depending on an underlying distribution; this is false.

Answer:

12x2 – 75 = 3 (2x+5)(2x – 5)

Step-by-step explanation:

Answer:

y 9 5 473648

Step-by-step explanation:

Answer:

11,494.0³

Step-by-step explanation:

Volume of a sphere= (4/3) × pi × radius³

4÷3 × 3.14 ×14³

= 11,494.0³

Answer:

please mark me brainlist

Step-by-step explanation:

Answer:

x = 80

Step-by-step explanation:

3x/2=120°

3x=240°

x=80°

Answered by GAUTHMATH

Answer: [tex]7\sqrt{42}[/tex]

Step-by-step explanation:

42 students divided equally into 7 groups means 42 divided by 7, and [tex]7\sqrt{42}[/tex] is the only choice that shows that.

7√42. is the expressions would represent a class of 42 students divided equally into 7 groups

A division is a process of splitting a specific amount into equal parts.

Given,

A class of forty two Forty two students divided equally into 7 groups.

Forty two students divided equally into seven groups means forty two divided by seven, and

this can be done by using 7√42.

42 students divided equally into 7 groups means forty two divided by seven

Hence  7√42. is the expressions would represent a class of 42 students divided equally into 7 groups

To learn more on Division click:

https://brainly.com/question/21416852

#SPJ2

Answer:

In descending order, 1, 4, 3

Answer:

24

Step-by-step explanation:

18 times 5 is 90 so that means that the given numbers have to add up to 90 (including x)

so,

6+10+20+30=66

90-66=24

I hope this helps!

Answer:

[tex]x = 24[/tex]

Step-by-step explanation:

[tex]6 + 10 + x + 20 + 30 = 18[/tex]

There are 5 numbers that we must add to average out to get 18 so let set this equation up

[tex] \frac{6 + 10 + x + 20 + 30}{5} = 18[/tex]

[tex]6 + 10 + x + 20 + 30 = 90[/tex]

[tex]x = 24[/tex]

Hello!

(6a/8+3) + 7a/8 =

= 6a/11 + 7a/8 =

= 125/88 × a

Good luck! :)

Answer: x=-3/3=-1

Step-by-step explanation:

To solve for x in terms of b, simply treat b as a number, and solve for x as usual: first of all, we expand the left hand side:

-2bx+10=16

Subtract 10 from both sides:

-2bx=6

Divide both sides by -2b:

x=6/-2b=-3/b

This means that in particular, if we set b=3 , we have

x=-3/3=-1

Answer:

-105, -104, -103

Step-by-step explanation:

lets the numbers be:

x

x+1

x+2

so:

x+(x+1)+(x+2)=-312

x+x+x+1+2=-312

3x+3=-312

3x=-312-3=-315

x=-315/3=-105

Answer:

[tex]P = (\frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3})^2[/tex]

Step-by-step explanation:

Given

[tex]\frac{dP}{dt} = \sqrt{Pt[/tex]

[tex]P(1) = 2[/tex]

Required

The solution

We have:

[tex]\frac{dP}{dt} = \sqrt{Pt[/tex]

[tex]\frac{dP}{dt} = (Pt)^\frac{1}{2}[/tex]

Split

[tex]\frac{dP}{dt} = P^\frac{1}{2} * t^\frac{1}{2}[/tex]

Divide both sides by [tex]P^\frac{1}{2}[/tex]

[tex]\frac{dP}{ P^\frac{1}{2}*dt} = t^\frac{1}{2}[/tex]

Multiply both sides by dt

[tex]\frac{dP}{ P^\frac{1}{2}} = t^\frac{1}{2} \cdot dt[/tex]

Integrate

[tex]\int \frac{dP}{ P^\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]

Rewrite as:

[tex]\int dP \cdot P^\frac{-1}{2} = \int t^\frac{1}{2} \cdot dt[/tex]

Integrate the left hand side

[tex]\frac{P^{\frac{-1}{2}+1}}{\frac{-1}{2}+1} = \int t^\frac{1}{2} \cdot dt[/tex]

[tex]\frac{P^{\frac{-1}{2}+1}}{\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]

[tex]2P^{\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]

Integrate the right hand side

[tex]2P^{\frac{1}{2}} = \frac{t^{\frac{1}{2} +1 }}{\frac{1}{2} +1 } + c[/tex]

[tex]2P^{\frac{1}{2}} = \frac{t^{\frac{3}{2}}}{\frac{3}{2} } + c[/tex]

[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + c[/tex] ---- (1)

To solve for c, we first make c the subject

[tex]c = 2P^{\frac{1}{2}} - \frac{2}{3}t^\frac{3}{2}[/tex]

[tex]P(1) = 2[/tex] means

[tex]t = 1; P =2[/tex]

So:

[tex]c = 2*2^{\frac{1}{2}} - \frac{2}{3}*1^\frac{3}{2}[/tex]

[tex]c = 2*2^{\frac{1}{2}} - \frac{2}{3}*1[/tex]

[tex]c = 2\sqrt 2 - \frac{2}{3}[/tex]

So, we have:

[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + c[/tex]

[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + 2\sqrt 2 - \frac{2}{3}[/tex]

Divide through by 2

[tex]P^{\frac{1}{2}} = \frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3}[/tex]

Square both sides

[tex]P = (\frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3})^2[/tex]