Find the area of the figure

Please help :)

Find The Area Of The Figure Please Help :)

Answers

Answer 1

9514 1404 393

Answer:

  372 m²

Step-by-step explanation:

A vertical line down the center of the figure will divide it into two congruent trapezoids, each with bases 13 and 18, and height 12.

The area of one of them is ...

  A = 1/2(b1 +b2)h

So, the area of the two of them together is ...

  A = (2)(1/2)(b1 +b2)h = (b1 +b2)h

  A = (13 m + 18 m)(12 m) = 372 m²


Related Questions

What type of line is PQ⎯⎯⎯⎯⎯⎯⎯⎯?

Answers

Answer:

median

Step-by-step explanation:

Q is at the midpoint of RS and so PQ is a median

A median is a segment from a vertex to the midpoint of the opposite side.

We want to define what type of line is PQ (the line that passes through points P and Q) by looking at the given image, one can easily see that the line PQ is a median, now let's explain why.

First, let's analyze the image:

In the image, we can see that P is one vertex of the triangle, and Q is the midpoint of the segment RS (you can see that RQ = 4 and QS = 4) , where R and S are the other two vertexes of the triangle.

Particularly, we can define a median of a triangle as the line that passes through the midpoint of one side of the triangle and by the vertex that does not belong to that side.

With that definition, we can see that PQ is a median because Q is the midpoint of one side of the triangle and P is the vertex that does not belong to that side.

If you want to learn more, you can read:

https://brainly.com/question/2272632

Question 4
Which term in the sequence given by n th term formula 7n - 50 has a value of 41?
th term

Answers

Answer:

13th term

Step-by-step explanation:

41 = 7n - 50

41 + 50 = 7n

91 = 7n

7n = 91

n = 91/7

n = 13

13th term has value 41

Answer:

n = 13

Step-by-step explanation:

7n - 50 = 41

Add 50 to both sides

7n = 41 + 50

7n = 91

Divide both sides by 7

n = 91/7

n = 13

The half life of carbon 14 is 5,730 year suppose a fossil found with 20 percent as much of its carbon 14 as compared to a living sample how old is the fossil

3,235 years
32,346 years
1331 years
13,307 years

Answers

13,307 I know because I do this type of math and I fell your pain but I asked someone else this question that’s why I don’t know step bye step but yeah hope this help

13,305 years

Step-by-step explanation:

[tex]A = A_02^{-\frac{t}{5730}}[/tex]

Since only 20% of the original C-14 is left, then [tex]A=0.2A_0[/tex]. We can then write

[tex]0.2A_0=A_02^{-\frac{t}{5730}}[/tex]

Taking the log of both sides,

[tex]\log 0.2 = \left(-\dfrac{t}{5730}\right)\log 2[/tex]

Solving for t,

[tex]t = \dfrac{-(5730\:\text{years})\log 0.2}{\log 2}[/tex]

[tex]\:\:\:\:\:\:\:= 13,305\:\text{years}[/tex]

What does point b represent on the graph ?

Answers

You need to add the photo

Answer:

Step-by-step B represents the $14 John earned in the 2 hours he worked.

explanation:

Will give brainliest.

Answers

The answer is the second one

Answer: Assuming there isnt a fourth answer, the answer is the second choice.

Step-by-step explanation: Point A is located in the first quadrant, Point B is located at 3, -1/2 and Point C is reflected off the y axis, in the second choice.

Multiply 25 x 47 x 3

Answers

3525 is your answer please consider brainliest<3

Find m∠GHIm∠GHI if m∠GHI=14x+6m∠GHI=14x+6, m∠QHI=130∘m∠QHI=130∘, and m∠GHQ=3x−3m∠GHQ=3x−3.

Answers

Answer:

m∠GHI = 160

Step-by-step explanation:

From the question given above, the following data were obtained:

m∠GHI = 14x + 6

m∠QHI = 130°

m∠GHQ = 3x – 3

m∠GHI =?

Next, we shall determine the value of x. This can be obtained as follow:

m∠GHI = m∠QHI + m∠GHQ

14x + 6 = 130 + (3x – 3)

14x + 6 = 130 + 3x – 3

Collect like terms

14x – 3x = 130 – 3 – 6

11x = 121

Divide both side by 11

x = 121 / 11

x = 11

Finally, we shall determine the value m∠GHI. This can be obtained as follow:

m∠GHI = 14x + 6

x = 11

m∠GHI = 14(11) + 6

m∠GHI = 154 + 6

m∠GHI = 160

Need the answers from a - e

Answers

Answer:

10

Step-by-step explanation:

Sorry. I needed to answer this question to get access.

the old building at the back of the school is badly in need of repair. the company Hsa and the executive are planning to renovate the building to accommodate a new music room. There are 15 rooms in the building and the dimension of the rooms to be redone with tiles are 6m long and 4 m wide. ted the tile man has 500 one meter square tiles.
Explain how you would estimate whether Ted has enough tiles to cover all the kitchen floors in the entire apartment building?
How many tiles, each measuring 1 square meter, are needed to cover one room floor?
How many tiles are needed to cover all the floors in the entire building? Show your work? ​

Answers

Answer:

a. If the area of the tiles is greater than or equal to the area of all the rooms.

b. 24

c. 360

Step-by-step explanation:

a. Explain how you would estimate whether Ted has enough tiles to cover all the kitchen floors in the entire apartment building?

Ted would have enough tiles if the  area of the tiles is greater than or equal to the area of all the rooms. Since we have 500 one meter square tiles, we have 500 m² of tiles.

Since the rooms are 6 m long and 4 m wide, the area of each room is 6 m × 4 m = 24 m². Since there are 15 rooms, the area of all the rooms is 15 × 24 m² = 360 m².

Since the area of the tiles = 500 m² is greater than the area of the rooms = 360 m², Ted would have enough tiles to cover all kitchen floors in the entire apartment building.

b. How many tiles, each measuring 1 square meter, are needed to cover one room floor?

Since the area of each room floor is 24 m² and the area of each tile is 1 m², so the number of  1 square meter tiles needed to cover each floor is n = area of floor/area of tile = 24 m²/1 m² = 24.

c. How many tiles are needed to cover all the floors in the entire building?

Since 24 tiles are needed to cover each floor and there are 15 rooms in the building, we would require 24 tiles/room × 15 rooms/building = 360 tiles.

So we require 360 tiles.

It has a time to failure distribution which is normal with a mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles. Find its designed life if a .97 reliability is desired.

Answers

Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that [tex]\mu = 35000, \sigma = 7000[/tex]

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.88 = \frac{X - 35000}{7000}[/tex]

[tex]X - 35000 = -1.88*7000[/tex]

[tex]X = 21840[/tex]

The designed life should be of 21,840 vehicle miles.

25 x 2
help me
plz understand me by opening​

Answers

Answer:

[tex]25 \times 2 = 50 \\ you \: are \: idiot \: [/tex]

really?! :|

The answer is fifty/50

. A small home business is set up with an investment of Birr 1,000,000 for equipment. The business manufactures a product at a cost of Birr 60 per unit. If the product sells for Birr 140, how many units must be sold before the business breaks even?

Answers

Answer:

12,500

Step-by-step explanation:

P = R-E

b.e.p : P=0

R=E

140x = 1000000 + 60 x

80x = 1000000

x=12,500

According to the graph above, College R showed
the greatest change in enrollment between which
two decades?

Answers

Given:

The graph that shows the ennoblement for college R between 1950 and 2000.

To find:

The two decades that has the greatest change in enrollment.

Solution:

From the given graph, it is clear that the change in the enrollment is:

From 1950 to 1960 is [tex]4-3.5=0.5[/tex] thousand.

From 1960 to 1970 is [tex]5-4.5=1.5[/tex] thousand.

From 1970 to 1980 is [tex]5.5-5=0.5[/tex] thousand.

From 1980 to 1990 is [tex]6.5-5.5=1[/tex] thousand.

From 1990 to 2000 is [tex]7-6.5=0.5[/tex] thousand.

The two decades 1960-1970 and 1980-1990 have the greatest change in enrollment.

Answer:1980 to 1990

Step-by-step explanation:

I WILL GIVE BRAINLIEST FAST
TRUE OR FALSE?
The triangles shown below must be congruent

Answers

B is the answer.

The triangles doesnt creates a SSS,SAS,SAA, scenario.

This triangle isn't ASA because the triangles share the same side but it have different angles that include the side.

You are charged $9.33 total for a meal, assume the 7% sales tax, how much was the menu price of this item?

I have already tried
$8.68
$8.71
$8.67
all were wrong ​

Answers

Answer:

$8.71.

Step-by-step explanation:

Given that you are charged $ 9.33 total for a meal, assuming the 7% sales tax, to determine how much was the menu price of this item, the following calculation must be performed:

100 + 7 = 107

107 = 9.33

100 = X

100 x 9.33 / 107 = X

933/107 = X

8.71 = X

Therefore, the menu price of this item was $ 8.71.

rank the three fractions from smallest to largest? and why
2/7, 4/14, 8/11

Answers

Answer:

2/7 = 4/14 so from smallest to largest the fractions are:

2/7 4/14 and 8/11

Step-by-step explanation:

if a=(1 2 3 4) find A×A and the relation determined by (I) y=2x (II) x+y​

Answers

Answer:

HOPE IT HELPS PLZ MARK ME BRAINLIEST

Step-by-step explanation:

A={1,2,3,4,5,6}

R={(x,y):y is divisible by x}

We know that any number (x) is divisible by itself.

(x,x)∈R

∴R is reflexive.

Now,(2,4)∈R [as 4 is divisible by 2]

But,(4,2)∈ /

R. [as 2 is not divisible by 4]

∴R is not symmetric.

Let (x,y),(y,z)∈R. Then, y is divisible by x and z is divisible by y.

∴z is divisible by x.

⇒(x,z)∈R

∴R is transitive.

Hence, R is reflexive and transitive but not symmetric.

Will give brainliest if correct

Which congruence theorem can be used to prove △BDA ≅ △BDC?


Triangles B D A and B D C share side B D. Sides B C and B A are congruent. Sides A D and D C are congruent.


HL

SSA

AAS

SSS

Answers

Answer:

SSS or D on edge

Step-by-step explanation:

.

The three sides of triangle ΔBDA are equal to the three sides of triangle ΔBDC.

The congruency theorem that can be used to prove ΔBDA ≅ ΔBDC is; SSS

Reasons:

The given parameters are;

The common side to ΔBDA and ΔBD = BD

BC ≅ BA

AD ≅ DC

The two column proof is presented as follows;

Statement [tex]{}[/tex]                     Reasons

BC ≅ BA [tex]{}[/tex]                        Given

AD ≅ DC [tex]{}[/tex]                       Given

BD ≅ BD [tex]{}[/tex]                         By reflexive property

Therefore, we have;

ΔBDA ≅ ΔBDC  [tex]{}[/tex]             By Side-Side-Side SSS, congruency rule

The congruency theorem that can be used to prove ΔBDA ≅ ΔBDC is therefore;

SSS

The Side-Side-Side congruency rule states that if three sides of on triangle are congruent to three sides of another triangle, then the two triangles are congruent.

Learn more about Side-Side-Side, SSS congruency rule here:

https://brainly.com/question/10684250

Anthony had to travel 24 miles north and then 7 miles west. Find the shortest distance between the starting and the end points.
30 miles
36 miles
25 miles
39 miles

Answers

Answer:
25 miles

Explanation:
To make it easy dray two lines one to the north the other to the west then draw the shortest way you will have a t triangle with side length 24,7 to find the hypotenuse(shortest way) use the Pythagorean theorem a^2+b^2=c^2

What is the HCF of 1280 and 630

Answers

Given:

The two numbers are 1280 and 630.

To find:

The HCF of the given numbers.

Solution:

First write the given numbers in prime factorization form.

[tex]1280=2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 5[/tex]

[tex]630=2\cdot 3\cdot 3\cdot 5\cdot 7[/tex]

Now the product of all the common prime factors is known as the HCF of 1280 and 630.

[tex]HCF=2\cdot 5[/tex]

[tex]HCF=10[/tex]

Therefore, the HCF of 1280 and 630 is 10.

Suppose the figure KLMN is dilated using a scale factor of 1/3 with the center of dilation at the origin. Which are the ordered pairs for the image?

1. K’(-1,3), L’(-3,0), M’(⅔, -8/3), N’(2, 4/3)

2. K’(-9,27), L’(-27,0), M’(6, -24), N’(18, 12)

3. K’(0,6), L’(-6,-3), M’(-1, -5), N’(3, 1)

4. K’(3,-1), L’(0,-3), M’(-8/3, ⅔), N’(4/3,2)

Answers

Answer:

K’(-1,3), L’(-3,0), M’(⅔, -8/3), N’(2, 4/3)

Step-by-step explanation:

the mean of 5 numbers is 198. the numbers are in ratio 1:2:3:4:5 find the smallest number​

Answers

Answer:  13.2

In fraction form, this is 66/5

=============================================================

Explanation:

The five values are in the ratio 1:2:3:4:5 which scales up to 1x:2x:3x:4x:5x for some positive number x.

Add up the pieces of the second ratio and set that sum equal to 198. Then solve for x.

1x+2x+3x+4x+5x = 198

15x = 198

x = 198/15

x = 66/5

x = 13.2 is the smallest number since 1x = 1*13.2 = 13.2 was the smallest value of the ratio 1x:2x:3x:4x:5x.

in the diagram below, BD is parallel to XY. what is the value of y?
a. 70
b. 130
c. 110
d. 20

Answers

I can't see the diagram sorry.

Step-by-step explanation:

Is there supposed to be a picture attached?

Anyone know this question?

Answers

Answer:

[tex](f + g)(4) = 191[/tex]

Step-by-step explanation:

Given

[tex]f(x) = 5x^2 - 5x + 15[/tex]

[tex]g(x) = 6x^2 + 7x - 8[/tex]

Required

[tex](f + g)(4)[/tex]

First, calculate [tex](f + g)(x)[/tex]

This is calculated as:

[tex](f + g)(x) = f(x) + g(x)[/tex]

So, we have:

[tex](f + g)(x) = 5x^2 - 5x + 15+6x^2 + 7x - 8[/tex]

Collect like terms

[tex](f + g)(x) = 5x^2 +6x^2 - 5x+ 7x + 15 - 8[/tex]

[tex](f + g)(x) = 11x^2 + 2x + 7[/tex]

Substitute 4 for x

[tex](f + g)(4) = 11*4^2 + 2*4 + 7[/tex]

[tex](f + g)(4) = 191[/tex]

If there is a 90% chance of rain tomorrow and a 70% chance of wind and rain,
what is the probability that it is windy, given that it is rainy? Round your
answer to the nearest percent.

Answers

Answer:

78%

Step-by-step explanation:

the chance of rain

P(R) = 0.9

the chance of wind and rain

P(R∩ W) = 0.7

The probabilities of windy weather is

P(W) = [tex]\frac{P(RW)}{P(R)} =\frac{0.7}{0.9} =0.78[/tex]

The correct answer is B) 78%

What is the circumference of the given circle in terms of [tex]\pi[/tex]?

a. 14[tex]\pi[/tex] in.
b. 28[tex]\pi[/tex] in.
c. 42[tex]\pi[/tex] in.
d. 196[tex]\pi[/tex] in.

Answers

Answer:

b. 28[tex]\pi[/tex] in.

Step-by-step explanation:

circumference of a circle = 2 [tex]\pi[/tex] r

whrere r is the radius of rhe circle

= 2 × [tex]\pi[/tex] × 14 in.

= 28 [tex]\pi[/tex] in.

that is option b

We have to find,

The circumference of the given circle in terms of the π.

The formula we use,

→ C = 2πr

Then we can find the circumference,

→ 2 × π × r

→ 2 × π × 14

→ 28π in.

Hence, option (b) is correct answer.

Hannah would like to make an investment that will turn 8000 dollars into 33000 dollars in 7 years. What quarterly rate of interest, compounded four times per year, must she receive to reach her goal?

Answers

Answer:

20.76%

Step-by-step explanation:

[tex]33000=8000(1+\frac{i}{4})^{4*7}\\4.125=(1+\frac{i}{4})^{28}\\\sqrt[28]{4.125}=1+\frac{i}{4} \\i= .207648169[/tex]

which rounds to 20.76%

Answer:

About 0.2076 or 20.76%.

Step-by-step explanation:

Recall that compound interest is given by the formula:

[tex]\displaystyle A=P\left(1+\frac{r}{n}\right)^{nt}[/tex]

Where A is the final amount, P is the principal, r is the interest rate, n is the number of times the interest is applied per year, and t is the number of years.

Since Hannah wants to turn an $8,000 investment into $33,000 in seven years compounded quarterly, we want to solve for r given that P = 8000, A = 33000, n = 4, and t = 7. Substitute:

[tex]\displaystyle \left(33000\right)=\left(8000\right)\left(1+\frac{r}{4}\right)^{(4)(7)}[/tex]

Simplify and divide both sides by 8000:

[tex]\displaystyle \frac{33}{8}=\left(1+\frac{r}{4}\right)^{28}[/tex]

Raise both sides to the 1/28th power:

[tex]\displaystyle \left(\frac{33}{8}\right)^{{}^{1}\! / \! {}_{28}}= 1+\frac{r}{4}[/tex]

Solve for r. Hence:

[tex]\displaystyle r= 4\left(\left(\frac{33}{8}\right)^{{}^{1}\! / \! {}_{28}}-1\right)[/tex]

Use a calculator. Hence:

[tex]r=0.2076...\approx 0.2076[/tex]

So, the quarterly rate of interest must be 0.2076, or about 20.76%.

Lost-time accidents occur in a company at a mean rate of 0.4 per day. What is the probability that the number of lost-time accidents occurring over a period of 9 days will be no more than 5

Answers

Answer:

0.8441

Step-by-step explanation:

This question can be solved by using the microsoft excel command.

we start off by solvingfor the mean rate for 9 days

mean rate = 0.4

for 9 days = 0.4*9 = 3.6

using the excel command,

POISSON (5, 3.6, TRUE)

p(x≤ 5) = 0.8441

so in conclusion 0.8441 is the probability that lost time accidents over 9 days would not be greater than 5.

the attachment is an excel sheet showing the input and the result.

Solve for x. Round your answer to the nearest tenth if necessary. Please look at the picture above

Answers

Answer:

veoba

Step-by-step explanation:

A researcher designs an experiment by manipulating the following variables: temperature (low or high), illumination level (low or high), and time of testing (day or night). For a repeated measures design, how many participants would the researcher require in order to have 10 participants per condition?

Answers

Answer:

10

Step-by-step explanation:

As it could be inferred from the name, repeated measure design may be explained as experimental measures involving multiple (more than one) measures of a variable on the same observation, subject or participants which are taken at either various times or periodic intervals, different levels, different conditions. Hence, a repeated measurement taken with the same sample but under different treatment conditions. Therefore, since the measurement will be performed on a the same subjects(paired) , then the number of subjects needed will be 10. As it is this same samples that will be used for the other levels or conditions.

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