Find the area of a circle that has a circumference of 175.84 inches
with explanation.
Will give brainliest.
Answers
A = c^2/4pi
175.84^2/4pi
A≈ 2460.51
Answer:
[tex]{ \boxed{ \bold{ \text{Area \: of \: a \: circle} \: = \tt{2461.76 \: {inches}^{2}}}}} [/tex]
☯ Question :Find the area of a circle that has a circumference of 175.84 inches.☯ Step - by - step explanation :☄ Given :
Circumference of a circle = 175.84 inches☄ To find :
Area of a circle = ?☄ First, we have to find :
Radius of a circle ( r )♨ Finding the radius of a circle :
[tex] \boxed{ \sf{Circumference \: of \: a \: circle = 2\pi \: r}}[/tex]
Substitute the value of circumference of a circle
[tex] \longrightarrow{ \sf{175.84 = 2\pi \: r}}[/tex]
Swap the sides of the equation
⟶ [tex] \sf{2\pi \: r \: = 175.84}[/tex]
Use [tex] \sf{ \pi \: ≈ \: 3.14}[/tex] , we obtain
[tex] \longrightarrow{ \sf{2 \times 3.14 \times r = 175.84}}[/tex]
Multiply : 2 by 3.14
[tex] \longrightarrow{ \sf{6.28 \: r = 175.84}}[/tex]
Divide both sides by 6.28
[tex] \longrightarrow{ \sf{ \frac{6.28 \: r}{6.28} = \frac{175.84}{6.28}}} [/tex]
[tex] \longrightarrow{ \sf{r \: = \: 28 \: inches}}[/tex]
☞ Now , we have :
Radius of a circle ( r ) = 28 inchesFinding the area of a circle having the radius of 28 inches :
[tex] \boxed{ \sf{Area \: of \: a \: circle = \pi \: {r}^{2} }}[/tex]
Substituting the radius , we get :
[tex] \longrightarrow{ \sf{Area \: of \: a \: circle = \pi \: {(28)}^{2} }}[/tex]
[tex] \longrightarrow{ \sf{Area \: of \: a \: circle = 784 \: \pi}}[/tex]
Using [tex] \sf{\pi \: ≈ \: 3.14}[/tex] , we obtain :
[tex] \longrightarrow{ \sf{Area \: of \: a \: circle = 784 \times 3.14 }}[/tex]
[tex] \longrightarrow{ \boxed{ \sf{Area \: of \: a \: circle = 2461.76 \: {inches}^{2} }}}[/tex]
Therefore , area of a circle is 2461.76 inches²
And we're done !
Hope I helped!
Have a wonderful time!ツ
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Answer:
5. 3050ft³ (rounded to 3 s.f.)
6. 4190ft³(rounded to 3 s.f.)
7. 4600ft³(rounded to 3 s.f.)
Formulas (For easier reference):
Volume of a cone: pi×r²×[tex]\frac{h}{3}[/tex]
Volume of cylinder: pi×r²×h
Volume of a sphere: [tex]\frac{4}{3}[/tex]×pi×r³
Volume of a hemisphere: [tex]\frac{2}{3}[/tex]×pi×r³
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Volume of cylinder = pi×9²×10
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6. Volume of sphere = [tex]\frac{4}{3}[/tex]×pi×10³
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7. Volume of hemisphere = [tex]\frac{2}{3}[/tex]×pi×(26÷2)³
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