find missing side of triangle

Given:

The graph of triangle PQR and triangle P'Q'R'.

To find:

The transformation that will map the triangle PQR onto P'Q'R'.

Solution:

From the given graph it is clear that the triangle PQR is formed in II quadrant and its base lies on the negative direction of x-axis.

The triangle P'Q'R' is formed in IV quadrant and its base lies on the positive direction of x-axis.

This is possible it the figure is rotated 180 degrees about the origin.

Therefore, the correct option is A.

Answer:

OMG I LOVE LOUIS SO MUCH HE IS SO PERFECT

Step-by-step explanation:

Answer:

6.5

Step-by-step explanation:

We need to solve out for x , the given Equation is ,

[tex]: \implies[/tex] x - 3x + 2 = -11

[tex]: \implies[/tex] -2x = -11 -2

[tex]: \implies[/tex] -2x = -13

[tex]: \implies[/tex] x = -13/-2

[tex]: \implies[/tex] x = 6.5

Answer:

x = 6.5

Step-by-step explanation:

[tex]x - 3x + 2 = - 11 \\ - 2x + 2 = - 11 \\ - 2x = - 11 - 2 \\ \frac{ - 2x}{ - 2} = \frac{ - 13}{ - 2} \\ x = + 6.5 [/tex]

Answer:

Step-by-step explanation:

Step-by-step explanation:

C

im not sure of my answer. hope to help

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\large\textsf{Variables by itself with no number with it is understood as an invisible}\\\large\textsf{1}[/tex]

[tex]\huge\textsf{c + c - 7c}[/tex]

[tex]\huge\textsf{= 1c + 1c - 7c}[/tex]

[tex]\huge\text{COMBINE the LIKE TERMS}[/tex]

[tex]\large\textsf{= (1c + 1c - 7c)}[/tex]

[tex]\large\textsf{1c + 1c = \bf 2c}[/tex]

[tex]\large\textsf{= 2c - 7c}[/tex]

[tex]\large\textsf{= \bf -5c}[/tex]

[tex]\boxed{\boxed{\huge\textsf{Answer: \underline{Option C. \bf -5c}}}}\huge\checkmarl[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]

Answer:

A = 39.48 cm²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = [tex]\frac{1}{2}[/tex] h (b₁ + b₂ )

where h is the perpendicular height and b₁, b₂ the parallel bases

Here h = 4.2, b₁ = 13.5, b₂ = 5.3 , then

A = [tex]\frac{1}{2}[/tex] × 4.2 × (13.5 + 5.3) = 2.1 × 18.8 = 39.48 cm²

Answer:

Any value of x makes the equation true. All real numbers Interval Notation: ( − ∞ , ∞ )

Hope This Helps!!!

[tex]\displaystyle\bf (3-5\sqrt{5} )-(5\sqrt{3} -3)=3+3-5\sqrt{5} -5\sqrt{3} =\boxed{6-5\sqrt{5} -5\sqrt{3} } \\\\\\\\\sqrt{5} (\sqrt{5} -2x)=\boxed{-2x\sqrt{5} +5}[/tex]

Answer:

y = 5

Step-by-step explanation:

The given equation to us is

⇒ -4y = -20

⇒ y = -20/-4

⇒ y = 5

Therefore this line will pass 5 units away from y axis. For graph refer to the attachment .

More Information :-

Answer:

A=2

B=8

C=-38

X=2.8/X=-6.8

Step-by-step explanation:

Answer:

The value of x is 8 .

Step-by-step explanation:

It is known that EF = x cm , GH = (x + 6) cm , RS = 16 cm and NP = 28 cm . Knowing that EF ,GH , RS , and NP are, in that order, proportional segments, determine the value of x .

As EF, GH, RS and NP are in proportion

So,

EF : GH = RS : NP

[tex]\frac{x}{x+6}=\frac{16}{28}\\\\7 x = 4 (x + 6)\\\\7 x = 4 x + 24 \\\\3 x = 24 \\\\x = 8[/tex]

Answer:

[tex]8)79 + .3y |1| 5131x - 2884 \frac{ {8 - { { - 44 - {516}^{ |?| } }^{?} }^{?} }^{2} }{?} 5 - {1 {y {1 {40091 - \times \frac{?}{?} }^{?} }^{2} }^{2} }^{2} 444 = .3 = 547 - 274[/tex]

Answer:

Option i

Step-by-step explanation:

The given expression is , 5x² - 3xy .

We can clearly see that there are two terms in the expression , 5x² and 3xy .

Therefore option (i) is correct .

Answer:

g(f(2)) = 9

Step-by-step explanation:

Evaluate f(2) and substitute the value obtained into g(x)

f(2) = 2 + 1 = 3 , then

g(3) = 3² = 9

Answer:

9

Step-by-step explanation:

f(x)=x+1........(i)

g(x)= x^2......( ii ).

gf(2)........(III)

substitute f( 2) to ......(I)

f(2)=2+1

f(2)=3

gx=gf(2)

gf(2)= 3^2

=9

Answer:

£1837.5

Step-by-step explanation:

Given data

Cost of car P=  £2100.

Rate r= 2.2%

Time t= 6 years

Now we want to find the  worth after 6 years, let us apply the compound interest expression but this time for depreciation

A= P(1-r)^t

Substitute

A= 2100(1-0.022)^6

A= 2100*(0.978)^6

A= 2100*0.875

A= £1837.5

Hence the amount of the car after 6 years is £1837.5

Answer:

2.56 kgs

Step-by-step explanation:

76.8kg ÷ 30 days = 2.56 kgs

Amount of sugar used - 76.8 kg

No. Of Days in Month of April - 30 days

∴ Sugar used each day is = 76.8 ÷ 30

[tex]76.8 \div 30 \\ \\ = \frac{76.8}{30} \\ \\ = \frac{768}{30 \times 10} \\ \\ = \frac{ \cancel{768}}{ \cancel{30} \times 10} \fbox{cancelling by 3} \\ \\ = \frac{256}{10 \times 10} \\ \\ = \frac{256}{100} \\ \\ = 2.56 \: kg[/tex]

Answer:

40.5 square inches

Step-by-step explanation:

Rectangle consists of two identical squares.

So, if the sides of square = x,

Then,  Width of rectangle = x     &

Length of rectangle = x +x = 2x

Perimeter of rectangle = 27 inches

2*(length + width) = 27

2*( 2x + x) = 27    {Combine like terms]

2* 3x = 27

    6x= 27           {Divide both sides by 6}

       x = 27/6

x = 4.5

Width = x = 4.5 inches

Length = 2x = 2*4.5 = 9 inches

Area of rectangle = length *width

                             = 4.5 *9

                             = 40.5  square inches

Answer:

40.5

Step-by-step explanation:

Answer:

1. The third quartile

2. The quartile

3. Four

4. 25

5. The second quartile, Q₂

6. 20th percentile

7. Decile

8. Percentile

9. D₈

10. The third quartile, Q₃

Step-by-step explanation:

1. The other term(s) for Q₃ is third quartile (or upper quartile). It is the mid point between the distribution's largest number and the median

2. The measure of position divided into four equal parts is the quartile

3. The quartile is the division of the data at three points (Q₁, Q₂, and Q₃) into four equal parts equal parts

4. Q₁, which is the first quartile is equivalent to the 25th percentile

5. The other term for the median is the second quartile, Q₂

6. D₂ which is the second decile (a decile divides the data into 10 equal parts) is equivalent to 20th percentile

7. The decile, D, divides a given data into 10 equal parts

8. The percentile divides a given data into 100 equal parts

9. The decile equivalent to P80, which is the 80th percentile, is D₈

10. The quartile equivalent to P75, which is the 75th percentile or the three quarter mark point of the data is equivalent to the the third quartile, Q₃

1) 520

2)60

3)2600

4)3760

Answer:

1. 520

2. 60

3. 2600

4. 3760

Step-by-step explanation:

[tex]{hope it helps}}[/tex]

Answer:

[tex]{ \tt{f(x) = 2}} \\ when \: y = 2 \\ { \bf{x = - 0.5}}[/tex]

Answer:

see explanation

Step-by-step explanation:

cosM = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{MN}{LM}[/tex] = [tex]\frac{8}{17}[/tex]

sinM = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{LN}{LM}[/tex] = [tex]\frac{15}{17}[/tex]

tanM = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{LN}{MN}[/tex] = [tex]\frac{15}{8}[/tex]

Answer:

Y = -6X - 15

Step-by-step explanation:

-3 = -6(-2) + B

-3 = 12 + B

B= -15

Answer:

You didn't attach the options, but y = - 6x - 15

Step-by-step explanation:

Using the equation y = mx + b, you can plug in values that you have to solve for b, the y intercept. Since m is the slope and the slope is - 6, and you have a y and x value, you can write the equation as follows:

-3 = - 6 * -2 + b

Then solve for b

-3 = 12 + b

-15 = b

Then you rewrite the original formula with the values of m and b:

y = - 6x - 15

Answer:

x = -7

Step-by-step explanation:

We have

PQ = (x+14)

QR = (x+12)

PR = 12

We can see that, PQ+QR = PR

So,

x+14+x+12 = 12

Solving for x.

2x = -14

x = -7

So, the value of x is equal to -7.

Answer:

a

Step-by-step explanation:

in integer there will negative ,positive or rational number

Answers:

3 chocolate cones

1 strawberry cones

===========================================================

Explanation:

Let's isolate the variable c in the first equation

c+s = 4

c = 4-s

we subtract s from both sides to get c all by itself. This will then be plugged into the second equation. I'm using the substitution property.

1.75c + 1.3s = 6.55

1.75(4-s) + 1.3s = 6.55 ..... replace c with 4-s

1.75*4 + 1.75*(-s) + 1.3s = 6.55

7 - 1.75s + 1.3s = 6.55

-0.45s + 7 = 6.55

-0.45s = 6.55 - 7

-0.45s = -0.45

s = -0.45/(-0.45)

s = 1

So he bought 1 strawberry cone. Use this value of s to find c

c = 4-s

c = 4-1

c = 3

This says he also bought 3 chocolate cones.

-------------------

As a check, we see that c+s = 3+1 = 4, showing that he bought 4 cones total.

Also,

1.75c + 1.3s = 1.75*3 + 1.3*1 = 6.55

indicating he spent $6.55 total for the four cones. This matches with what the instructions tell us, so the answer is confirmed.

Answer:

Step-by-step explanation:

[tex]\left \{ {{c+s=4} \atop {1.75c+1.3s=6.55}} \right.[/tex]

1.75c + 1.75s = 1.75 × 4 ........ (1)

1.75c + 1.3s = 6.55 ........ (2)

(1) - (2)

0.45s = 0.45 ⇒ s = 1

c + 1 = 4 ⇒ c = 3

[ 3 ] chocolate  [ 1 ] strawberry

Answer:

Area of a circle is denoted by: πr^2 where r is the radius of the circle. = 16/2 = 8 feet.

Step-by-step explanation:

Answer:

113,04 square root is 10.632027088 divided by Pi

3.38427933228

so the radius of her tire is 3.38

Hope This Helps!!!

Answer:

64

Step-by-step explanation:

2x2x2x2x2x2 = 64