Find an ordered pair (x,y) that is a solution to the equation.
x-2y=6

Answer:

It was 3

Step-by-step explanation:

This is because its the one clóset to 0

I hope this help you out

Answer:

19

Step-by-step explanation:

See attachment for math work and answer.

Answer:

2

Step-by-step explanation:

15 + 5 × 3

________

  3² + 6

For this question, we need to use PEMDAS to solve the question correctly. PEMDAS stands for "parentheses, exponents, multiplication, division, addition, subtraction". In this question, for the numerator, we see 5 x 3 so that's multiplication. So we multiply those together to get 15. In the denominator, there's an exponent which is 3². We have to find the square of 3 so that we can simplify the denominator as well. That simplifies to 9:

(15+15)/(9+6)

Next, we just have to add the 15+15 in the numerator together and 9+6 in the denominator together:

30/15

Finally, we divide 30/15 to get 2 as our answer

2

Answer:

21.00

Step-by-step explanation:

21.00 I think (sorry if it wrong!!)

The cost of the backpack before tax was $20.94 if Greg paid $22.05 for a backpack. This amount includes a sales tax of 5%.

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

It is given that:

Greg paid $22.05 for a backpack. This amount includes a sales tax of 5%

Let x be the cost of the backpack before tax.

22.05(1 - 5%) = x

x = 22.05(1 - 0.05)

x = $20.94

Thus, the cost of the backpack before tax was $20.94 if Greg paid $22.05 for a backpack. This amount includes a sales tax of 5%.

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Answer:

3(-10.5)

Step-by-step explanation:

Answer:

3(-10.5)

Step-by-step explanation:

80 times farther from the Sun is Neptune than Mercury.

Given that, the distance between Mercury and Sun = 35,000,000 miles and the distance between Neptune and Sun = [tex]2.8\times10^9[/tex].

An average distance is the average of the greatest and least distances of a celestial body from its primary.

Now, number of times farther from the Sun is Neptune than Mercury

= [tex]\frac{2.8\times10^9}{3.5\times10^7}[/tex]

=0.8×10²

=80

Time taken for light to reach Neptune = 3×80=240 minutes

=4 hours

Therefore, 80 times farther from the Sun is Neptune than Mercury.

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Answer:

9 dollars

Step-by-step explanation:

It would be 9 dollars because that is the only common factor that could go into 27, 28, or 45.

Answer:

1.5 pounds

Step-by-step explanation:

1 pound costs $8, $1 buys 1/8 pound

$12 buys 12/8=3/2=1.5 pounds

Answer:

12-8= 4

Step-by-step explanation:

one pound of it cost 8 dollars and he only has 12 so subtract 8 from 12 he only has enough to buy 1 pack.

Answer:

Step-by-step explanation:

-(-2)^2 - (8(-2)-2(-3)) + 4(-3)

-4 -(-16 + 6) - 12

-4 - (-10) - 12

-4 + 10 - 12

6 - 12 = -6

Answer:

10^3

Step-by-step explanation:

Answer:

10^3

Step-by-step explanation:

count how many 10s are there and that is the answer

(there are 3 tens so put the power as 3)

To check 10 X 10 X 10 is 1000

10^3 is 1000

While on vacation in Washington DC, the cab ride for the Dulles airport to the hotel is 15 miles. The total cost of the cab ride was $25.50. The cabbie charges $1.50 per mile for the entire trip A.

Answer:

the answers are the first one and the third one.

A's slope is y = 5.75x + 3

B's slope is y = 5.5x + 4

Answer:

the answer is A, x=2

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\sqrt{18}=\sqrt{2*3*3}=3\sqrt{2}[/tex]

[tex]\sqrt{12}=\sqrt{2*2*3}=2\sqrt{3}[/tex]

[tex]A=\sqrt{2}+\sqrt{18}\\\\=\sqrt{2}+3\sqrt{2}\\\\=(1+3)\sqrt{2}\\\\=4\sqrt{2}[/tex]

[tex]B=\sqrt{3}+\sqrt{12}=\sqrt{3}+2\sqrt{3}\\\\ = (1+2)\sqrt{3}\\\\ = 3\sqrt{3}[/tex]

[tex]\sqrt{B^{2}+A^{2}-2*B*A}=\sqrt{(B-A)^{2}}\\\\=B-A\\\\=3\sqrt{3}-4\sqrt{2}[/tex]

= 3* 1.732 - 4 *1.4142

= 5.196 - 5.6568

= -0.4608

Exact Answer:   [tex]4\sqrt{2} - 3\sqrt{3}[/tex]

Approximate Answer:  0.46070182678574

Round the approximate value however you need to.

=================================================

Work Shown:

[tex]C = \sqrt{ B^2 + A^2 - 2BA}\\\\C = \sqrt{ B^2 - 2BA + A^2}\\\\C = \sqrt{ (B-A)^2 }\\\\C = -(B-A) \ \ \text{ see note below}\\\\C = -B+A\\\\C = A-B\\\\C = (A) - (B)\\\\[/tex]

[tex]C = (\sqrt{2}+\sqrt{18}) - (\sqrt{3}+\sqrt{12})\\\\C = \sqrt{2}+\sqrt{18} - \sqrt{3}-\sqrt{12}\\\\C = \sqrt{2}+\sqrt{9*2} - \sqrt{3}-\sqrt{4*3}\\\\C = \sqrt{2}+\sqrt{9}*\sqrt{2} - \sqrt{3}-\sqrt{4}*\sqrt{3}\\\\C = \sqrt{2}+3\sqrt{2} - \sqrt{3}-2\sqrt{3}\\\\C = 4\sqrt{2} - 3\sqrt{3} \ \ \text{ ..... exact value}\\\\C \approx 0.46070182678574 \ \ \text{ ..... approximate value}[/tex]

-------------------

Note: The rule used here is

If x is positive then [tex]\sqrt{x^2} = x[/tex]

Or if x is negative, then [tex]\sqrt{x^2} = -x[/tex]

Since B-A = -0.4607 approximately, we will use the second version of the rule above.

Answer:

1/6

Step-by-step explanation:

Total quantity of water = 2/3

Total quantity drank = 1/4

The portion of the water that you drank = 1/4 of 2/3

= 1/4 × 2/3

= 1*2 / 4*3

= 2 / 12

= 1 / 6

The portion of the water that you drank = 1/6

This means you drank one - sixth of the water in the bottle

Answer:

1.yes

2. yes, and yes [tex]\frac{4}{1}[/tex]

3. yes, its a whole number.

4.yes

5. whole, intenger, rational, real

Step-by-step explanation:

Answer:

59

Step-by-step explanation:   x=number of hours

150+7.50x=595

7.50x=595-150

7.50x/7.50=445/7.50

x=59

a. 6x2

b. 2x3

c. 5x2

d. 4x2

e. 5x1

Answer:

23

Step-by-step explanation:

7 - 5p + 3a

7 - 5(1) + 3(7)

7 - 5 + 21

2 + 21

23

Answer:

[tex]12[/tex]

Step-by-step explanation:

[tex] {4}^{2} - ( { - 2}^{2} ) \\ 16 - 4 \\ 12[/tex]

Answer:

The minimum cost for the transportation for the field trip is $1700

Step-by-step explanation:

Let x be the no. of large buses and y be the no. of small buses

Number of students in large bus = 60

Number of students in x large buses = 60x

Cost of 1 large bus =$300

Cost of x large buses = 300x

Number of students in small bus = 45

Number of students in y small buses = 45y

Cost of 1 small bus =$200

Cost of y small buses = 200y

Cost = 300x+200y

We are given that A school district needs to arrange transportation for at least 360 students

[tex]60x+45y \geq 360[/tex]

The district only has chaperones for, at most, seven buses.

[tex]x+y \leq 7[/tex]

Plot the lines on graph

[tex]60x+45y \geq 360[/tex] --- Black region

[tex]x+y \leq 7[/tex] --- Red region

Feasible points :

At(3,4)

Cost  = 300x+200y=300(3)+200(4)=1700

At(7,0)

Cost  = 300x+200y=300(7)+200(0)=2100

At(6,0)

Cost  = 300x+200y=300(6)+200(0)=1800

So, The minimum cost for the transportation for the field trip is $1700

Answer:

1700

Step-by-step explanation:

2020 edge

Answer:

Multiply the numerator by the reciprocal of the denominator to get 650 x 2 divided by 3. Then, multiple 650 and 2 which is 1300, then it is 1300 over 3, or 433.3, and it is repeating.

Step-by-step explanation:

By the concept of division by a fraction, 650 divided by 3/2 will result in [tex]433 \frac{1}{3}[/tex].

We have to solve 650 divided by 3/2.

Mathematically, it can be expressed as:

650 ÷ [tex]\frac{3}{2}[/tex]   -----(1)

To solve the above expression, at first we can apply the concept of dividing by a fraction. Which say that:

dividing by a fraction =  multiplying by the reciprocal of the fraction

And the reciprocal of any fraction is simply the ratio of denominator and numerator.

So, the reciprocal of  [tex]\frac{3}{2}[/tex]  is [tex]\frac{2}{3}[/tex] .

Then, expression (1) will be equivalent to

[tex]650 \div \frac{3}{2} = 650 \times \frac{2}{3}[/tex]  ------(2)

That means we have to multiply 650 and fraction 2/3.

To get the multiplication of two fractions, we multiply the numerators together and the denominators together.

[tex]650 \times \frac{2}{3} = \frac{650\times 2}{3}[/tex]

[tex]650 \times \frac{2}{3} = \frac{1300}{3}[/tex]

[tex]650 \times \frac{2}{3} = \frac{1300}{3}[/tex]

[tex]650 \times \frac{2}{3} = 433 \frac{1}{3}[/tex]

Thus, from equation (2)  

[tex]650 \div \frac{3}{2} = 433 \frac{1}{3}[/tex]

Hence, 650 divided by 3/2 is:

[tex]650 \div \frac{3}{2} = 433 \frac{1}{3}[/tex]

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Answer:

a₅ = 37

Step-by-step explanation:

The term to term rule ' subtract 3 ' is the common difference d of an arithmetic sequence with n th term

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₁₂ = 16, then

a₁ + 11d = 16 ← substitute d = - 3

a₁ + 11(- 3) = 16

a₁ - 33 = 16 ( add 33 to both sides )

a₁ = 49 , then

a₅ = 49 + (4 × - 3) = 49 - 12 = 37

Answer:

24

Step-by-step explanation:

(4-3) + (23) = 24

Answer:

(E) if im wrong don't sew meh

Step-by-step explanation:

Answer:

The correct option is;

Alternate interior angles

Step-by-step explanation:

The m∠5 + m∠2 + m∠6 = 180° proof is given as follows;

Statement                [tex]{}[/tex]                        Reason

1. ABC is a triangle              [tex]{}[/tex]             Given

2. y ║ z                                [tex]{}[/tex]              Given

3. ∠1 ≅ ∠5; ∠3 ≅ ∠6                         Alternate interior angles

4. m∠1 = m∠5; m∠3 = m∠6        [tex]{}[/tex]       Definition of (congruency) ≅

5. m∠1 + m∠2 + ∠3 = m∠LAM        [tex]{}[/tex]  ∠Addition postulate

6. m∠1 + m∠2 + ∠3 = 180°        [tex]{}[/tex]        Definition of straight angles

7. m∠5 + m∠2 + ∠6 = 180°        [tex]{}[/tex]        Substitution property

Step 3;

Given that line y is parallel to line z, we have that the transversal AB will make equal corresponding angles with the lines y and z, therefore, ∠6 will be equivalent to segment AB extended

Which gives, ∠6 is supplementary to ∠a where ∠a = ∠1 + ∠2

Therefore, given that ∠3 is also supplementary to ∠a where as we have above, ∠a = ∠1 + ∠2, we have that ∠3 = ∠6 and ∠3 ≅ ∠6 where ∠3 and ∠6 are alternate interior angles;

Similarly, ∠1 ≅ ∠5 by alternate interior angles of two parallel lines property.

Answer:

The answer is A. alternate interior angles are congruent

Step-by-step explanation:

I tried all my options and that one was correct.

Answer: 10%

Step-by-step explanation:

The following information can be gotten from the question regarding the number of people that went to the swimming pool are:

First week of July = 1020

Second week = 1020 - 100 = 920

Third week = 920 + 130 = 1050

Fourth week = 1050 - 132 = 918

The percentage decrease over the four weeks will be:

= (1020 - 918)/1020 × 100

= 102/1020 × 100

= 10%