fill in the blank. to create a dopamine deficient (dd) mouse that retains the ability to produce ne, the gene for___is selectively restored in noradrenergicc neurons

Answers

Answer 1

To create a dopamine deficient (dd) mouse that retains the ability to produce ne, the gene for dopamine beta-hydroxylase (DBH) is selectively restored in noradrenergic neurons.

DBH is an enzyme that converts dopamine to norepinephrine (ne), and its expression is critical for the production of ne. By restoring DBH expression specifically in noradrenergic neurons, researchers can create a mouse that lacks dopamine but still produces ne.

This can be a useful tool for studying the effects of dopamine deficiency on behavior, as well as the specific roles of dopamine and ne in various physiological processes. Additionally, this technique could potentially be used to develop new treatments for disorders that involve abnormalities in dopamine or ne signaling, such as Parkinson's disease or depression.

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Related Questions

identify the cellular components and the location of the component that is respnsible for producing the luciferase protein from mrna

Answers

For luciferase protein production, ribosomes would be located either in the cytoplasm or on the surface of the ER, depending on whether the mRNA molecules encoding the protein are destined for secretion or for use within the cell.

The cellular component responsible for producing the luciferase protein from mRNA is the ribosome. Ribosomes are small, complex molecular machines that are responsible for translating the genetic information in mRNA molecules into protein sequences.

In eukaryotic cells, ribosomes can be found in two locations: free in the cytoplasm and bound to the endoplasmic reticulum (ER). The free ribosomes produce proteins that are used within the cell, while the bound ribosomes produce proteins that are destined for secretion or for insertion into cell membranes.

Overall, ribosomes are the key cellular component responsible for translating mRNA molecules into proteins, including the luciferase protein.

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In mammals, which of the following vessels transports oxygenated blood from the lung back to the heart?
A. pulmonary artery
B. superior vena cava
C. coronary artery
D. pulmonary vein

Answers

(d) is the correct option. The pulmonary veins enter the left atrium and re-circulate the oxygenated blood back to the heart. Blood is pumped into the left ventricle from the left atrium.

The aorta, which carries the oxygenated blood to every area of the body, receives blood from the left ventricle. Only one type of vein carries oxygenated blood, which is the pulmonary vein. Oxygenated blood is transported from the lungs by the pulmonary veins. The heart's major artery (aorta), which supplies blood to the entire body, is directly used in coronary circulation. Deoxygenated blood travels from tissue capillaries back to the right atrium of the heart through a network of veins.

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Choose the correct order of the numbered statements to put the last four events of photosynthesis in order. 1. A photon of light strikes photosystem I and allows it to excite the electron. 2. The electron transport chain passes the electron from photosystem II to photosystem I. 3. The excited electron is passed from photosystem I to NADPH. 4. NADPH and ATP are used in the Calvin cycle to make glucose. O A. 2,1,3,4 B. 3,1,2,4 C. 1,4,3,2 D. 1,2,4,3 SUBMIT

Answers

The correct order of the numbered statements to put the last four events of photosynthesis in order is 4-2-1-3. Hence, option E is correct.

At step 4, the Calvin cycle produces glucose using NADPH and ATP. The electron is transferred from photosystem II to photosystem I in step 2 of the electron transport chain. A photon of light enters photosystem I in step 1 and causes the electron to be excited. The energized electron is transferred from photosystem I to NADPH in step 3 to finish.

Plants, algae, and some microorganisms use the process of photosynthesis to convert sunlight into energy. Water and carbon dioxide (CO₂) are chemically changed into food (sugars) and oxygen during the process. The pigment chlorophyll, which gives plants their green hue, is frequently used in the chemical reaction.

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Complete question is:

Choose the correct order of the numbered statements to put the last four events of photosynthesis in order.

1. A photon of light strikes photosystem I and allows it to excite the electron.

2. The electron transport chain passes the electron from photosystem II to photosystem I.

3. The excited electron is passed from photosystem I to NADPH.

4. NADPH and ATP are used in the Calvin cycle to make glucose. Choices:

A. 2,1,3,4

B. 3,1,2,4

C. 1,4,3,2

D. 1,2,4,3

E. 4,2,1,3

9. What number on the diagram is pointing to the deltoid muscle?

15
16
17
18

Answers

Answer:

17 number on the diagram is pointing to the deltoid muscle

explain the socio-economic challenges that exist in rural areas​

Answers

Answer:

Rural communities face challenges related to demographic changes, workforce development, capital access, infrastructure, health, land.

Explanation:

Some of the most significant examples of socio-economic issues would include things like: Income levels within a community. The kind of educational opportunities that exist. The employment situation of a community. Safety within a community.

Some socioeconomic challenges that exist in rural areas are things like education. Quality education may not be provided due to limited resources

Is it advisable to switch Microscope on while looking through the eyepiece

Answers

No, it is not advisable to switch on a microscope while looking through the eyepiece. It is important to turn on the microscope and adjust the focus and other settings before looking through the eyepiece to avoid any potential damage to the eyes or the microscope.

Describe how a meander can form an oxbow lake. Use the words "cut bank" in your answer.

Answers

Answer:A meander can form an oxbow Lake by using a cut bank to vision the forming happening.

Explanation:

bacterial infection that was likely confirmed by which of the following Lillian was diagnosed with a Gram- negative biotechnology applications? Choose one: A Restriction digest with endonuclease B. Hybridization with a labeled probe C. Polymerase chain reaction D. Making a chimera plasmid O E. None of these is possible

Answers

Lillian was diagnosed with a bacterial infection that was likely confirmed by Polymerase chain reaction (PCR).PCR is a laboratory technique used to generate millions of copies of a specific DNA sequence.

It is often used to diagnose bacterial infections because it can detect even small amounts of bacterial DNA in a sample. PCR involves three basic steps: denaturation, annealing, and extension. In the denaturation step, the sample is heated to separate the two strands of DNA. In the annealing step, primers are added to the sample to bind to the specific DNA sequence of interest. In the extension step, DNA polymerase is used to build a new strand of DNA from the primers. The result is millions of copies of the specific DNA sequence, which can be analyzed to detect the presence of the bacteria causing the infection. Restriction digests with endonuclease B is not used to diagnose bacterial infections. It is a laboratory technique used to cut DNA into smaller fragments. Hybridization with a labeled probe is another laboratory technique that can be used to detect the presence of bacterial DNA. However, PCR is more sensitive and specific and is therefore the preferred method for diagnosing bacterial infections. Making a chimera plasmid is not a laboratory technique used to diagnose bacterial infections. It involves combining DNA sequences from different sources to create a hybrid molecule. None of these is possible is not the correct answer as PCR is a possible method for diagnosing bacterial infections.

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Microsporidia have been tentatively moved from the protists to the fungi based on which of the following?
Presence of chitin in cell walls
Absence of chloroplasts
Analysis of DNA sequence data
Absence of centrioles

Answers

Microsporidia have been tentatively moved from the protists to the fungi based on the presence of chitin in their cell walls.

What is chitin?

Chitin is a tough, protective polysaccharide that is found in the cell walls of fungi but not in protists. While the absence of chloroplasts and centrioles can also be used to distinguish fungi from protists, the presence of chitin in the cell walls is a more reliable and definitive characteristic for assigning organisms to the fungal kingdom. In addition to chitin, other features such as analysis of DNA sequence data and other biochemical markers have also supported the reclassification of Microsporidia as fungi.

What is protists?

Protists are a diverse group of eukaryotic organisms that are not plants, animals, or fungi. They are unicellular or multicellular, and can be found in a variety of habitats such as fresh water, marine environments, soil, and even inside other organisms as parasites. Protists include organisms such as algae, amoebas, ciliates, and slime molds.

Protists are characterized by their eukaryotic cell structure, which includes a nucleus and other membrane-bound organelles. They may have cell walls or lack them, and can reproduce sexually or asexually. Some protists are capable of photosynthesis, while others are heterotrophic and obtain nutrients by consuming other organisms or organic matter.

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What is the connection between global warming and climate change?

Answers

Global warming is one of the main factors that contribute to climate change. The Earth's temperature has been increasing gradually due to the rise in the concentration of greenhouse gases in the atmosphere, such as carbon.

What is a gas ?

A gas is a state of matter that is characterized by a lack of definite shape and volume. In contrast to solids and liquids, gases will expand to fill any container they are placed in.

Gases are made up of individual atoms, molecules, or ions that are in constant motion and are not held together by strong bonds. They can be compressed and expanded with changes in temperature and pressure.

Examples of gases include oxygen, nitrogen, helium, carbon dioxide, and methane. Gases play an important role in many natural processes, such as respiration, photosynthesis, and the greenhouse effect, as well as in a wide range of human activities, including energy production, transportation, and industrial processes.

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what types of energy are in a gas powered car?
what types of energy are in an electrical car?
what types of energy are in a curling iron?

Answers

Answer:

Explanation:

In a gas powered car, the types of energy include:

Chemical energy stored in the gasoline

Thermal energy produced by the combustion of gasoline

Mechanical energy used to power the car's movement

Kinetic energy of the car in motion

In an electric car, the types of energy include:

Electrical energy stored in the battery

Potential energy stored in the battery's chemical bonds

Kinetic energy of the car in motion

Thermal energy produced by the battery and the electric motor

In a curling iron, the types of energy include:

Electrical energy from the power source

Thermal energy produced by the heating element

Radiant energy in the form of infrared radiation emitted by the heating element

Mechanical energy used to apply pressure and manipulate the hair.

structurally, myoglobin and hemoglobin are very smilar proteins. in which of the following levels of structure do they differ most?

Answers

Myoglobin and hemoglobin differ most significantly in their quaternary structure level of protein organization, with myoglobin consisting of a single polypeptide chain and hemoglobin consisting of four polypeptide chains that come together to form a complex quaternary structure.

Myoglobin and hemoglobin are both oxygen-binding proteins found in red blood cells, and they share a high degree of structural similarity. However, they differ most significantly in the quaternary structure level of protein organization.

The quaternary structure refers to the arrangement of subunits in a multi-subunit protein. Myoglobin consists of a single polypeptide chain and therefore has a simple tertiary structure. In contrast, hemoglobin is made up of four polypeptide chains: two alpha chains and two beta chains, each with its own heme group that binds to oxygen. The four chains come together to form a complex quaternary structure.

The quaternary structure of hemoglobin is important for its function as an oxygen carrier in the blood. The structure allows hemoglobin to undergo a conformational change when oxygen binds to one of the heme groups, which promotes the binding of additional oxygen molecules. In contrast, myoglobin does not have this ability to undergo a conformational change, as it only binds a single oxygen molecule.

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When all available water has been used up in a soil, what is left ?

1. Is unavailable to plants.
2. Can only be obtained by large plants.
3. Is too small to make any effect.
4. Will only be used by certain plants.

Answers

Answer:

When all available water has been used up in a soil, the remaining water is typically unavailable to plants. Therefore, option 1 is the correct answer.

Plants can only absorb water that is in the soil's pore spaces and is not too tightly bound to soil particles. Once all the available water has been used up, the remaining water is held too tightly to soil particles for plants to access it. This can lead to water stress and drought conditions for plants, and can also negatively affect soil fertility and other aspects of ecosystem health.

which of the following is least likely to help a virus avoid triggering an adaptive immune response?

Answers

Answer:

Synthesizing protein similar to other viruses would not help the virus avoid activating the adaptive immune response. The MHC molecules of the cells recognize the other protein molecules. It triggers the adaptive immune system.

Which of the following best explains how gene pools change to bring about evolution?

A.certain alleles help animals to survive and those alleles are more abundant in the next generation

B. mutations help organisms whenever they appear in organisms

C. individuals alter their alleles to become better suited to the selective pressures of the environment

D. survival of the fittest members of a population increases variation in the gene pool

Answers

Certain alleles allow animals to survive and those alleles are more abundant in the next generation this is how the gene pools evolve to bring about evolution.

Describe the gene pool?

The gene pool refers to all the alleles (various forms of genes) present in a population of organisms.

It includes variances in the genes that determine physical attributes, behavior, and other traits as well as the entire genetic variety present in the community.

Natural selection, genetic drift, gene flow, and mutation are a few examples of the processes that can cause the gene pool to alter through time.

How does evolution alter the genetic diversity?

By evolution, the gene pool of a population can evolve over time. There are a number of processes by which this might happen, including mutations, natural selection.

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select all of the following that cause the difference between the theoretical and actual yields of atp in aerobic respiration.

Answers

Transporting pyruvate and ADP into the mitochondrial matrix requires ATP. Each ATP that is transported out of the mitochondria to collect other organelles costs one ATP. Respiration enzyme activity is slowed down by lipid molecules in cells.

What is the ATP production rate predicted by theory for aerobic respiration?

A total of 38 molecules of ATP can theoretically be produced throughout the whole aerobic respiration of glucose, with four produced by substrate-level phosphorylation and 34 by oxidative phosphorylation.

Anaerobic or aerobic respiration: which is more effective and why Class 10?

By fully oxidising a single glucose molecule, aerobic respiration produces roughly 38 molecules of ATP. Yet, only 2 ATP are produced by anaerobic respiration for every glucose molecule.

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Help me please answer all te questions

Answers

Answer:

1. A

2. B

3. D

4. A

Explanation:

peas (pisum sativum) were well suited for mendel's breeding experiments for all of the following reasons except:

Answers

Peas (Pisum sativum) were well-suited for Mendel's breeding experiments for several reasons, including their short life cycle, their ability to self-fertilize, and the ease with which they could be manipulated. However, there is no reason to suggest that they were not well-suited for Mendel's experiments based on the following reasons:

They are too difficult to cultivate: In fact, peas were relatively easy to grow and maintain, making them an ideal choice for experimentation.

They do not exhibit clear phenotypic traits: On the contrary, peas exhibit a variety of clear and distinct phenotypic traits, such as flower color, seed shape, and pod texture, that can be easily observed and analyzed.

They have a high mutation rate: There is no evidence to suggest that peas have an unusually high mutation rate, and in fact, their relatively stable genetics were a key factor in Mendel's ability to identify patterns of inheritance.

Therefore, all of the given reasons are not valid in suggesting why peas were not well-suited for Mendel's breeding experiments.

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explain the socio-economic challenges that exist in urban areas​

Answers

Answer:

the unemployment rate will increase.

Answer:

dually fishtail good too risks tittiesss

select the options that indicate when you know that you have increased the microscope's magnification enough.

Answers

The field of view shrinks, the depth of the field gets shallower, the resolution gets better, and the image gets bigger when you have sufficiently magnified the microscope.

What happens when a microscope's magnification is increased?

The object appears bigger when a magnified more. The Resolution: improves the object's or image's clarity.

Your field of view also expands as the magnification increases.

Field of vision and magnification are inversely related. This implies that while one increases, the other declines (decreases). As a result, the field of vision would be reduced with an increase in magnification, such as when utilising more powerful objective lenses.

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Question:

What are the indicators that you have increased the microscope's magnification enough?

A. The field of view becomes smaller

B. The image becomes dimmer

C. The depth of field becomes shallower

D. The resolution improves

E. The image becomes larger

Please select all that apply.

Which organelle is denoted by B?
RER
SER
cytoplasm
golgi

Answers

The organelle denoted by B is the Golgi apparatus.

Golgi apparatus.Eukaryotic cells have an organelle called the Golgi apparatus, which is crucial for the processing, alteration, and classification of proteins and lipids. It is constructed of a number of stacked cisternae, which are flattened, membrane-bound sacs. Endoplasmic reticulum (ER) proteins and lipids are transferred to the Golgi apparatus, where they are altered by the addition or removal of sugars, phosphates, or other chemical groups. Then, it organizes these molecules into vesicles, which can carry them to a variety of locations inside and outside the cell. The Golgi apparatus is essential for ensuring the appropriate operation of the cell in this way.

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Assignment sports leadership news paper article

Scenario You are working in a small, but developing, coaching company. You have contacted a local newspaper to discuss how to develop interest in volunteering in sports leadership. The editor has asked you to write an article that explores the requirements of becoming a successful sports leader, using examples of successful sports leaders to demonstrate attributes and responsibilities required.
Task 1
Carry out research into successful sports leaders using textbooks, the internet and journals. You may also consider sports leaders who have led sporting events that you have taken part in and/or sports leaders who coach professional or national sports teams.

Prepare a two-page article for the newspaper about the attributes and responsibilities of sports leaders. (2A.P1, 2A.P2, 2A.M1, 2A.M2)

Within the feature you should compare and contrast the attributes of two successful sports leaders. (2A.D1)

Checklist of evidence required
Article for a newspaper or web article.
Criteria covered by this task:
Unit/Criteria reference
To achieve the criteria you must show that you are able to:
6/2A.P1
Describe, using relevant examples, the attributes required for, and responsibilities of, sports leadership.
6/2A.P2
Describe the attributes of two selected successful sports leaders.
6/2A.M1
Explain the attributes required for, and responsibilities of, sports leadership.
6/2A.M2
Evaluate the attributes of two successful sports leaders.
6/2A.D1
Compare and contrast the attributes of two successful sports leaders.

Answers


Answer:

Title: The Role of Attributes and Responsibilities in Sports Leadership

As the world becomes more competitive, it is important to have skilled sports leaders who can inspire and motivate athletes to reach their full potential. Successful sports leaders possess a unique combination of attributes that enable them to excel in their role. In this article, we will explore the attributes and responsibilities of sports leadership through the lens of two successful sports leaders.

The first sports leader we will examine is Sir Alex Ferguson, who is widely regarded as one of the most successful football managers of all time. Sir Alex Ferguson led Manchester United for 26 years, during which time he won 38 trophies, including 13 Premier League titles and two Champions League titles. One of his key attributes was his ability to motivate and inspire his players to perform at their best. He was also known for his strategic thinking and ability to identify and develop talent.

The second sports leader we will examine is Serena Williams, who is one of the greatest tennis players of all time. Serena has won 23 Grand Slam singles titles and 14 Grand Slam doubles titles. Her attributes include her exceptional physical ability, her mental toughness, and her ability to adapt her game to different opponents and situations. She is also known for her leadership skills, both on and off the court, as she has used her platform to advocate for social justice and equality.

The role of a sports leader is not just about winning, but also about developing athletes and creating a positive environment for them to thrive. A successful sports leader must possess a range of attributes, including communication skills, strategic thinking, adaptability, and the ability to inspire and motivate others. They must also be responsible for creating a positive team culture, managing conflicts, and ensuring that the team is well-prepared for competitions.

Sir Alex Ferguson and Serena Williams both demonstrate these attributes and responsibilities in their leadership roles. While they come from different sports and have different approaches, they both prioritize the development of their athletes and the creation of a positive team culture. They also demonstrate exceptional leadership skills, including their ability to inspire and motivate others, their strategic thinking, and their adaptability.

In conclusion, successful sports leaders possess a unique combination of attributes and responsibilities that enable them to excel in their role. They must possess strong communication skills, be able to think strategically, and have the ability to inspire and motivate others. Additionally, they are responsible for creating a positive team culture, managing conflicts, and ensuring that their team is well-prepared for competitions. By studying successful sports leaders like Sir Alex Ferguson and Serena Williams, we can learn valuable lessons about what it takes to be an effective sports leader.

It is harder to read the wording on very old tombstones than it is to read the wording on newer ones. The difference is most likely a result of: Group of answer choices

slow crystallization of the stone

dirt filling the letters

weathering of the stone

modern tombstones being made of artificial material

Answers

Answer:

Weathering of the stone.

true/false. an increase in temperature will cause an equilibrium to: select the correct answer below: shift right shift left no change depends on the equilibrium

Answers

When the temperature rises, an equilibrium will: Decide which of the following is true: No change relies on the equilibrium; go right; move left. True.

Le Chatelier's Principle states that a reversible reaction system that is endothermic in the forward direction will shift in the forward direction when its temperature rises (heats up). We may thus conclude that this response will indeed go to the right.

The equilibrium is shifted in favor of the endothermic process as the temperature rises. Because energy is transferred from the environment during an endothermic reaction, this lessens the effects of the change. The equilibrium is shifted toward the exothermic process as the temperature is lowered.

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A bacterial culture is growing exponentially. At 7:00 AM, the number of cells was estimated to be 5.5 X 104 cells. At 11:00 AM, the number of cells increased to 8.7 X 107 cells. What is the generation time in minutes of the bacteria? Please assume we are in the log phase of growth for this bacterial population. Please show your work.

Answers

To find the generation time, we need to use the formula:

N = N0 x 2^(t/g)

where:
N0 = initial number of cells
N = final number of cells
t = time elapsed
g = generation time

We can use the information given to solve for g.

At 7:00 AM, N0 = 5.5 x 10^4 cells
At 11:00 AM, N = 8.7 x 10^7 cells
The time elapsed is 4 hours, or 240 minutes.

Substituting these values into the formula, we get:

8.7 x 10^7 = 5.5 x 10^4 x 2^(240/g)

Dividing both sides by 5.5 x 10^4, we get:

1582.7 = 2^(240/g)

Taking the logarithm of both sides (base 2), we get:

log2(1582.7) = 240/g

Solving for g, we get:

g = 240 / log2(1582.7)

Using a calculator, we find that g is approximately 29.3 minutes. Therefore, the generation time of the bacteria is approximately 29.3 minutes.

fill in the blank. the type of viral infection in which a virus enters a host cell, immediately replicates, and causes the host cell to burst is a___infection.

Answers

The type of viral infection in which a virus enters a host cell immediately replicates and causes the host cell to burst is a lytic infection.

During lytic infection, the virus injects its genetic material into the host cell and uses the host cell's machinery to replicate its own genetic material and produce new viral particles. Once the new viral particles are produced, they cause the host cell to burst or lyse, releasing the viral particles into the surrounding environment where they can infect new host cells.

Lytic infections can occur in a variety of organisms, including bacteria, plants, and animals. They are often associated with acute infections that result in the rapid onset of symptoms and can lead to severe disease or even death if left untreated.

In contrast, latent infection is a type of viral infection in which the virus enters a host cell and integrates its genetic material into the host cell's DNA, remaining dormant until it is reactivated at a later time.

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Identify whether each feature listed belongs to primates or to other mammals.
- have relatively short growth and development periods
- feature relatively short periods between births
-tend to give birth to only one offspring at a time
- have relatively longer periods of maternal investment

Answers

Primates, unlike other mammals, have relatively short growth and development periods. The rest of the characteristics mentioned belong to primates.

Primates, especially humans, have a prolonged developmental phase with a short growth period, which is one of the traits that set them apart from other mammals. In comparison to most other mammals, primates, especially humans, have a long developmental phase characterized by prolonged infancy and an extended learning period. Here are the other three characteristics that are exclusively found in primates:Feature relatively short periods between births: The majority of primates, including humans, have a longer pregnancy period than other mammals. Because of this, primates generally have more extended periods between births.

Tend to give birth to only one offspring at a time: Compared to other mammals, primates, especially humans, generally give birth to a single offspring at a time, which may be attributed to their prolonged developmental period and maternal investment.Have relatively longer periods of maternal investment: Because primates have a more extended developmental phase than other mammals, they require more maternal attention and care. As a result, primates, especially humans, have a longer period of maternal investment.

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3. Use the diagram and information to answer questions below the figure.

You may use the amino acid table at beginning of exam to look up the 3 letter amino acid abbreciation and structure.
You have discovered a new enzyme that you name Pac-Manase that breaks down Pac-dot substrates (see figure below). You determine that the following potential interactions may occur between amino acids (3 letter abbreviation in red) in the enzyme's active site and its substrate (in yellow in figure below). At each site between the chemical group (in green) on the substrate and the closest side chain of an amino acid (in red) on the enzyme (in the gray circles), Pac-Manase, determine if a favorable interaction is likely to take place.
For each amino acid and substrate functional group pair, decide if a favorable interaction is likely take place and if so state the name for the strongest interaction/bond that may occur. For all cases where a potential interaction seems unfavorable, explain why.

A. GLN

B. ASP

C. ILE

D. LYS

E. ARG

Answers

The interactions that take place between each amino acid and substrate functional group pair play important roles in determining the structure and function of the enzyme Pac-Manase.

What interaction takes place between each amino acid and substrate functional group pair?

Several interactions take place between each amino acid and substrate functional group pair of the enzyme Pac-Manase.

These interactions are described below:

GLN and -OH: GLN contains a side chain with a carboxamide group (-CONH2), which can form hydrogen bonds with a hydroxyl group (-OH). This interaction is called a hydrogen bond.ASP and -NH2: ASP contains a negatively charged side chain, while -NH2 represents a positively charged amino group. The oppositely charged groups can attract each other, forming an ionic bond.ILE and -CH3: ILE contains a side chain with a methyl group (-CH3), which can interact with other methyl groups through van der Waals forces. This interaction is called hydrophobic interaction.LYS and -NH2: LYS contains a positively charged side chain, while -NH2 represents a positively charged amino group. The two positively charged groups can repel each other, but they can also form a salt bridge, which is a strong ionic interaction between oppositely charged groups.ARG and -COOH: ARG contains a positively charged side chain, while -COOH represents a negatively charged carboxyl group. The oppositely charged groups can attract each other, forming a salt bridge.

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Would the mosquito still be able to fin the nesting site

Answers

Answer:

Give the full question please

Can you please provide more context or information about what you are asking?

please help me i begging you

topic : Nonodontogenic
inflammatory processes of maxillofacial area (furuncle, carbuncle, erysipelas).


1) Furuncle (boil) is acute infection of:
A. a hair follicle and adjacent soft tissue.
B. a hair folicle.
C. a group of adjacent hair follicles become deeply infected.
D. oil and sweat-gland.
E. oilgland.

2) Cavernous sinus thrombosis can complicate boils or carbuncles on the:
A. lower lip and submentum.
B. parotid region.
C. nose, upper lip and cheek.
D. temporal region.
E. submandibular regionandneck.

3) The boils may coalesce into violaceous plaques at patient with:
A. HIV.
B. diabetes mellitus.
C. congenital anomalies.
D. atopic dermatitis.
E. cellulitis.

4)Select the type of microorganism causing of erysipelas:
A. staphylococcus.
B. pneumococcus.
C. actynomycetes.
D. herpes zoster.
E. streptococcus.

5) Depression of which of the following cells delay wound healing:
A. neutrophils.
B. lymphocytes.
C. monocytes.
D. erythrocytes.
E. none of above listed.

6) Organisms gain entry to form abscess:
A. direct infection.
B. local extension.
C. lymphatic and hematogenous spread.
D. none of above listed.
E. all of above.

7) Re-sutured wounds:
A. heals foster.
B. gets infected.
C. heals slower.
D. do not heal easily.
E. none of above listed.

8) If boils are recurred which of the following should be excluded:
A. epilepsy.
B. diabetes.
C. hypertension.
D. arrhythmias.
E. allergy.

9) Boils usually infect regional lymph nodes:
A. secondary.
B. primarily.
C. all of above.
D. none of above.
E. chronically.

10) The major factor in the production of inflammatory edema is:
A. arterial dilatation.
B. venous obstruction.
C. leukocytosis.
D. all of above listed.
E. increased capillary permeability.

11) Multiple pustules appear on the affected surface of skin by:
A. воil.
B. carbuncles.
C. eresipelas.
D. hidradenitis suppurativa.
E. cubcutaneous granuloma.

12) The causative agent of boils and carbuncles are:
A. streptococcus.
B. e. coli;
C. proteus;
D. association s.aureus and proteus.
E. staphylococcus.

13) The unlimited spread of on exudate through the tissues in acute inflammation is a characteristic feature of:
A. granulomatous infection.
B. cellulitis.
C. abscess.
D. leukocytosis
E. leukopedia

14) Predisposing factor for origin of erysipelas in adult is:
A. furunculosis.
B. a cut in the skin, skin ulcers, and problems with the drainage through the veins or lymph system.
C. congenital anomalies of skin.
D. exudative diathesis.
E. cardivascular decompensation.

15) To choice diseases for differential diagnosis of boil:
A. cavernous sinus thrombosis, mediastinitis.
B. siphylis, tuberculosis, actinomycosis.
C. hidradenitis suppurativa, acne vulgaris, anthrax.
D. lymphadenitis.
E. lupus erythematosus.

Answers

Answer:

1) A. a hair follicle and adjacent soft tissue.

2) C. nose, upper lip, and cheek.

3) B. diabetes mellitus.

4) E. streptococcus.

5) B. lymphocytes.

6) E. all of the above.

7) C. heals slower.

8) B. diabetes.

9) A. secondary.

10) E. increased capillary permeability.

11) A. boil.

12) E. staphylococcus.

13) B. cellulitis.

14) B. a cut in the skin, skin ulcers, and problems with the drainage through the veins or lymph system.

15) C. hidradenitis suppurativa, acne vulgaris, anthrax.

Answer:

1.  A

2.  C

3.  A

4.  E

5.  C

6.  E

7.   C

8.  B

9.  A

10. E

11.  D

12. E

13. B

14. B

15. C

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