Falls often cause injuries, so one of the significant aspects of falls is the displacement and motion of a body. It is defined as how far a body moves vertically during the fall. Accordingly, there are three important factors that should be known to compute the kinetic energy (KE) of a falling body. These factors are:

Answers

Answer 1

Answer:

We need, mass, gravity and height.

Explanation:

When a body falls freely from a height, its initial velocity is zero, but due to the height it has some potential energy at the top and the kinetic energy is zero.

As it falls, the potential energy is gradually converted in to the kinetic energy so that the total energy of the falling body is conserved.

At the time as the body strikes the ground, the entire potential energy is converted into the kinetic energy.

Potential energy is given by

U = m g h

where, m is the mass, g is the gravity and h is the height,

So, to get the kinetic energy we require mass, gravity and height of the body.


Related Questions

You have a simple pendulum that oscillates with a period of 2 s as you stand on the surface of Earth. Your friend, an astronaut standing on the surface of the Moon, has a pendulum of the same length. What would be the period of oscillation of your friend’s pendulum?

a. Less than 2 s
b. The answer depends on whether the amplitudes are the same
c. More than 2 s
d. Exactly 2 s

Answers

Answer:

c. More than 2 s

Explanation:

First, we will find the length of the pendulum:

[tex]T = 2\pi \sqrt{\frac{l}{g}}\\\\2\ s = 2\pi \sqrt{\frac{l}{9.81\ m/s^2}}\\\\4\ s^2 = 4\pi^2 (\frac{l}{9.81\ m/s^2})\\\\l = \frac{(4\ s^2)(9.81\ m/s^2)}{4\pi^2} \\\\l = 0.99\ m[/tex]

Now, the value of g becomes 1.625 m/s² on the surface of the moon. So the time period will be:

[tex]T = 2\pi \sqrt{\frac{l}{g}}\\\\T = 2\pi \sqrt{\frac{0.99\ m}{1.625\ m/s^2}}\\\\[/tex]

T = 4.9 s

Therefore, the correct option is:

c. More than 2 s

calculate the electrical potential at a point P a distance of 1 m from either two to charge of +10 micro coulomb and -5 micro coulomb which are 10 cm apart calculate also the potential energy of a +2 micro coulomb charge placed at a point p​

Answers

Answer:

a)  V = 45 10³ V, b) U = 4.59 J

Explanation:

a) The electric potential for a series of point charges is

         V = k ∑ [tex]\frac{q_i}{r_i}[/tex]

in this case point P is at a distance of 1 m from each charge, so the point is located perpendicular to the charges at its midpoint

 

         V = k ( [tex]\frac{q_1}{r} + \frac{q_2}{r}[/tex])

         V = 9 10⁹ (10 - 5/ 1) 10⁻⁶

         V = 45 10³ V

b) the potential energy is

           U = k (  [tex]\frac{q_1q}{r} + \frac{q_2q}{r} + \frac{q_1q_2}{r_2}[/tex] )

where r = 1m and r₂ is the distance between the two charges r₂ = 0.10 m

           U = 9 10⁹ (10 2 / 1 - 5 2/1 - 10 5 /0.10) 10⁻¹²

           U = 9 10⁻³  510

           U = 4.59 J

An empty parallel plate capacitor is connected between the terminals of a 8.85-V battery and charges up. The capacitor is then disconnected from the battery, and the spacing between the capacitor plates is doubled. As a result of this change, what is the new voltage between the plates of the capacitor

Answers

Answer:

The new voltage is 17.7 V.  

Explanation:

Voltage, V = 8.85 V

The spacing is doubled.

When it is disconnected, the charge remains same,

q = C V ..... (1)

where, C is the capacitance, V is the voltage.  

The capacitance is inversely proportional to the distance between the two plates.

So, when the spacing is doubled, the capacitance is halved.

Let the new voltage is V'.

C V = C' V'

C x 8.85 = C/2 x V'

V' = 17.7 V  

A ball with a mass of 275 g is dropped from rest, hits the floor, and rebounds upward. If the ball hits the floor with a speed of 2.60 m/s, rebounds with a speed of 1.84 m/s, and is in contact with the floor for 1.40 ms,determine the following.
(a) magnitude of the change in the ball's momentum (Let up be in the positive j hat direction.)
_______________kg

Answers

Answer:

-0.209 kg.m/s

Explanation:

The mass of the ball, m = 275g or 0.275 kg

Speed or velocity, v = 2.60 m/s

Momentum, P = mv

Momentum when velocity is 2.60 = 0.275 x 2.60 = 0.715 kg.m/s

Speed or velocity, v = 1.84 m/s

Momentum, P = mv

Momentum when velocity is 1.84= 0.275 x 1.84 = 0.506 kg.m/s

Change in magnitude =  0.506 - 0.715 = -0.209 kg.m/s

Explain how the Laws of planetary motion and Newton’s laws allow the hotel to keep moving in space.

Answers

Answer:

Explanation:

i am sorry i needed points

PLEASE HELP!! Newton's second law of motion states that force equals mass times acceleration.
How would this law apply to a runner in a track and field event?

The runner needs to take a few steps to slow down after crossing the finish line.

To win the race, the runner must slow down on the turns and speed up on the straight sections.

The shoes of the runner help increase his mass so he can run faster.

Newton's second law of motion does not apply to track and field.

Answers

The answer is A the runner needs to slow down

Describes the relationship between the free energy change, the reaction quotient, and the equilibrium constant.

Answers

Explanation:

Reaction quotient is defined as the ratio of the concentration of the products and reactants of a reaction at any point of time with respect to some unit. It is represented by the symbol Q.

The ratio of the concentration of products and reactants of a reaction in equilibrium with respect to some unit is said to be equilibrium constant expression. It is represented by the symbol K.

The relationship between Gibbs free energy change and reaction quotient of the reaction is:

[tex]\Delta G=\Delta G^o+RT ln Q[/tex]           ......(1)

where,

[tex]\Delta G[/tex] = Gibbs free energy change

[tex]\Delta G^o[/tex] = Standard Gibbs free energy change

R = Gas constant

T = Temperature

At equilibrium, the free energy change of the reaction becomes 0 and standard Gibbs free energy change can be related to the equilibrium constant by the equation:

[tex]\Delta G^o=-RT ln Q[/tex]           ...(2)

When the distance between two charges I no halved, the electric force between the charges

A) quadruples
B) doubles
C) is half
D) is reduced by one quarter

Answers

Answer:

A)quadruples

Explanation:

The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled

Answer is A) quadruples

name of this musician and some of his songs​

Answers

Answer:

Bobby Benson..........taxi driver

Dr Victor Olaiya......... omo pupa

prince Nic Mbarga.........sweet mother

sir Victor Uwaifor............. mammy water

Answer:

hey ...................................... what's up

Diwn unscramble the word

Answers

Answer:

WIND Is what you're looking for

Explanation:

The word is WIND

A 1 pF capacitor is connected in parallel with a 2 pF capacitor, the parallel combination
then being connected in series with a 3 pF capacitor. The resulting combination is then
connected across a battery.
(a) Which capacitor has the greatest charge?
(b) Which capacitor has the greatest voltage?

Answers

Answer:

a)3pF  has the greatest charge

b) 3pF to have the greatest voltage.

Explanation:

From the question we are told that:

1pF is parallel to [tex]2pF =1pF//2pF[/tex]

And 3pF is in with series 1pF is parallel to[tex]2pF =3pF+(1pF//2pF)[/tex]

Generally the equation for Resultant capacitor is mathematically given by

[tex]C=3pF+(1pF//2pF)[/tex]

[tex]C=\frac{3}{2}pF[/tex]

Ohm's law

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points

a)

Since

The same charge flowing through [tex]1pF//2pF[/tex] flow through 3pF

Therefore

3pF  has the greatest charge

b)

Voltage drop in series according to ohms law

Therefore the parallel share same voltage

Given

3pF to have the greatest voltage.

Which of the following changes would double the force between two charged particles?
A. Doubling the amount of charge on each particle
B. Increasing the distance between the particles by a factor of 2
C. Decreasing the distance between the particles by a factor of 2
D. Doubling the amount of charge on one of the particles

Answers

Answer:

Doubling the amount of charge on one of the particles.

Explanation:

The force between two charges is given by :

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

Where

r is the distance between charges

or

[tex]F\propto \dfrac{1}{r^2}[/tex]

On doubling the charge on one of the particle,

F' = 2F

So, the force gets doubled. Hence, the correct option is (d).

Define reversible change​

Answers

Answer:

Reversible changes are changes that can be undone or reversed. Melting, freezing, boiling, evaporating, condensing, dissolving and also, changing the shape of a substance are examples of reversible changes. If playback doesn't begin shortly, try restarting your device.

Explanation:

Answer:

A reversible change is a change that can be undone or reversed.

Explanation:

A block is projected with speed v across a horizontal surface and slides to a stop due to friction. The same block is then projected with the same speed v up an incline where is slides to a stop due to friction. In which case did the total mechanical energy of the block decrease the least

Answers

Answer: C. The case on the inclined surface had the least decrease intotal mechanical energy.

Explanation:

First and foremost, it should be noted that the mechanical energy is the addition of the potential and the kinetic energy.

From the information given, it should be known that when the block is projected with the same speed v up an incline where is slides to a stop due to friction, the box will lose its kinetic energy but there'll be na increase in the potential energy as a result of the veritcal height. This then brings about an increase in the mechanical energy.

Therefore, the total mechanical energy of the block will decrease the least when the case on the inclined surface had the least decrease intotal mechanical energy.

Which electromagnetic waves have the greatest frequencies? ​

Answers

Answer:

Gamma rays

Explanation:

Gamma rays have the highest frequency in the electro magnetic spectrum

Charlotte throws a paper airplane into the air, and it lands on the ground. Which best explains why this is an example of projectile motion? The paper airplane’s motion is due to horizontal inertia and the vertical pull of gravity. A force other than gravity is acting on the paper airplane. The paper airplane’s motion can be described using only one dimension. A push and a pull are the primary forces acting on the paper airplane.

highschool physics, not college physics

Answers

Answer:

Answer:

A). The paper airplane’s motion is due to horizontal inertia and the vertical pull of gravity.

Explanation:

Edge.

Answer:

The motion of the paper airplane  is best explained by horizontal inertia and vertical pull of gravity.

Explanation:

What is horizontal inertia and vertical pull of gravity?

Inertia is the property by which the body wants to remain in its position unless any external for is applied. Here horizontal inertia is inertia of motion which is acting horizontally .

While vertical pull is due to the earth .

In a paper airplane , four forces act .these forces provide it flight.These forces are horizontal inertia , vertical pull downwards , lift by air and drag.

Hence horizontal inertia and vertical pull best explain the projectile motion of paper airplane.

Also read it;

https://brainly.com/question/11049671

#SPJ2

If a force of 50 N stretches a spring 0.40 m, what is the spring constant?

Answers

Answer:

The spring constant = 125 N/m

Explanation:

Given that :

Force = 50 N

distance (x) = 0.40 m

Recall that, From Hooke's law

Force = kx

where;

k = spring constant.

50 N = k × 0.40 m

k = 50 N/0.40m

k = 125 N/m

What is the main form of energy present in the initial state? (Initial state is when the rubber band is stretched , just before it is released)

O gravitational potential
O kinetic
O thermal
O elastic potential

Answers

Elastic potential. Hope this helps

A toy car rolls down a slope. If it takes 5.94 s to accelerate from 3.22 m/s to 12.4 m/s, what is the value of the acceleration?

2.01 m/s2

1.35 m/s2

1.55 m/s2

0.219 m/s2

Answers

Answer:

a = 1.55m/s²

Explanation:

a = (v_f-v_0)/t

a = (12.4m/s-3.22m/s)/5.94s

a = 1.55m/s²

What is the Y-component of a vector A, which is of magnitude
16-12 and at a 45° angle to the horizontal?

Answers

Explanation:

the answer is in the image above

The Y-component of a vector A, which is of magnitude 16√2 and at a 45° angle to the horizontal would be 16

What is a vector quantity?

The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.

Examples of vector quantities are displacement, velocity acceleration, force, etc.

As given in the problem we have to find out the  Y-component of a vector A, which is of magnitude  16√12  and at a 45° angle to the horizontal,

Y component of the vector A =  16√2 sin45°

                                                =16√2 ×1/√2

                                                =16

Thus, the Y component of vector A would be 16.

To learn more about the vector quantity here, refer to the link;

https://brainly.com/question/15516363

#SPJ2

2. A Plate 0.02 mm distance from a fixed Plate moves at a velocity Of 0.6mls and requires a force of 1.962 N Per unit area to maitain this Speed. Determine the viscosity of the fluid between the plates?​

Answers

Answer:

6.54 × 10⁻⁵ Pa-s

Explanation:

Since the shear force, F = μAu/y where μ = viscosity of fluid between plates, A = area of plates, u = velocity of fluid = 0.6 m/s and y = separation of plates = 0.02 mm = 2 × 10⁻⁵ m

Since F = μAu/y

F/A = μu/y where F/A = force per unit area

Since we are given force per unit area, F/A = 1.962 N per unit area = 1.962 N/m²

So,  μ = F/A ÷ u/y

substituting the values of the variables into the equation, we have

μ = F/A ÷ u/y

μ = 1.962 N/m² ÷ 0.6 m/s/2 × 10⁻⁵ m

μ = 1.962 N/m² ÷ 0.3 × 10⁵ /s

μ = 6.54 × 10⁻⁵ Ns/m²

μ = 6.54 × 10⁻⁵ Pa-s

in physics If we interchange rows and columns of Matrix A, what is the new matrix known as 'Matrix' A ?​

Answers

Answer:

The correct answer is (C), as explained below. The transpose of a matrix is created by interchanging corresponding rows and columns.

Switching Rows

You can switch the rows of a matrix to get a new matrix.

Explanation:

If A is an m × n matrix and AT is its transpose, then the result of matrix multiplication with these two matrices gives two square matrices: A AT is m × m and AT A is n × n. ... Indeed, the matrix product A AT has entries that are the inner product of a row of A with a column of AT.

how many atoms are in a 4.7 g copper coin?​

Answers

3.11 is the answer I think

Answer:

x = 4.45 * 10 ^22  Note. Technically, this should be rounded to 4.5 * 10^22. There are only 2 sig digits.

Explanation:

You have to assume that the coin is pure copper, which I doubt.  What a coin is actually made of  depends on when it was minted. But for the sake of this question, we'll assume coins are pure copper.

Copper has an atomic mass of 63.546 grams / mol

So 4.7 g of copper = 4.7 / 63.545 mol

We have 0.07396 mol of copper

1 mol of anything = 6.02 * 10^23 atoms (in this case).

0.07396 mol        = x

Cross Multiply

               

1 * x = 0.07396 * 6.02 * 10^23

x = 4.45 * 10 ^22  atoms of copper

The moon Phobos orbits Mars
(mass = 6.42 x 1023 kg) at a distance
of 9.38 x 106 m. What is its period of
orbit?

Answers

Answer:

The moon Phobos orbits Mars (m = 6.42 x 1023 kg) at a distance of 9.38 x 106 m.

The sound from a trumpet radiates uniformly in all directions in 20C air. At a distance of 5.00 m from the trumpet the sound intensity level is 52.0 dB. The frequency is 587 Hz. (a) What is the pressure amplitude at this distance

Answers

Answer:

The answer is below

Explanation:

The intensity level (B) of a sound wave is given by:

B = 10log(I/I₀);

where I₀ is the threshold intensity = 1 * 10⁻¹² W/m², I is the intensity at distance 5 m, B is the intensity level = 52 dB

Substituting gives:

[tex]52=10log(\frac{I}{10^{-12}} )\\\\log(\frac{I}{10^{-12}} )=5.2\\\\I=1.58*10^{-7}\ W/m^2[/tex]

The pressure is given by:

[tex]I=\frac{p_{max}^2}{2\rho v} \\\\\rho=air\ density=1.2\ kg/m^3,v=speed\ of\ sound\ in\ air=344\ m/s,p_{max}=pressure:\\\\p_{max}=\sqrt{2\rho vI}=\sqrt{2*1.58*10^{-7}*1.2*344} =1.14*10^{-2}Pa[/tex]

Two identical ambulances with loud sirens are driving directly towards you at a speed of 40 mph. One ambulance is 2 blocks away and the other is 10 blocks away. Which of the following is true? 
[Note that pitch = frequency.]a) The siren from the closer ambulance sounds higher pitched to you.b) The siren from the farther ambulance sounds higher pitched to you.c) The pitch of the two sirens sounds the same to you.d) The siren from the farther ambulance sounds higher pitched, until the
 closer ambulance passes you.

Answers

Answer:

c) The pitch of the two sirens sounds the same to you

Explanation:

The pitch does not depend on the distance of the object from the observer.

As per the given data

pitch = frequency

Frequency = [tex]f_{0}[/tex]  [tex]\frac{V +- V_{0}}{V +- V_{s}}[/tex]

[tex]f^{'}[/tex] = [tex]f_{0}[/tex]  [tex]\frac{V }{V - V_{s}}[/tex]

Hence, the pitch of the two sirens remains the same for the observer.

Answer:

c) The pitch of the two sirens sounds the same to you

Explanation:

Calculate the RMS voltage of the following waveforms with 10 V peak-to-peak:
a. Sine wave;
b. Square wave,
c. Triangle wave.
Calculate the period of a waveform with the frequency of:
a. 100 Hz,
b. 1 kHz,
c. 100 kHz.

Answers

Answer:

a) [tex]T=0.01s[/tex]

b) [tex]T=0.001s[/tex]

c) [tex]T=0.00001s[/tex]

Explanation:

From the question we are told that:

Given Frequencies

a. 100 Hz,

b. 1 kHz,

c. 100 kHz.

Generally the equation for Waveform Period is mathematically given by

[tex]T=\frac{1}{f}[/tex]

Therefore

a)

For

[tex]T=100 Hz[/tex]

[tex]T=\frac{1}{100}[/tex]

[tex]T=0.01s[/tex]

b)

For

[tex]F=1kHz[/tex]

[tex]T=\frac{1}{1000}[/tex]

[tex]T=0.001s[/tex]

c)

For

[tex]F=100kHz[/tex]

[tex]T=\frac{1}{100*100}[/tex]

[tex]T=0.00001s[/tex]

The object has a mass of 100kg. The Tension is 200N[U]. What is the acceleration of this elevator? *
A) 8m/s/s
B) 8m/s/s[D]
C) 9.8m/s/s[D]
D) 0.5m/s/s[D]

Answers

Answer:

So the answer is B. A is wrong because negative answer = deceleration

HELPPP PLSS!!!!!!
What is the chemical formula for iodine trichloride?
A. 12C|
B. ICI3
C. 3ICI
D. |1C13

Answers

B. ICL3 is the answer

Answer:

B

Explanation:

In an experiment, a shearwater (a seabird) was taken from its nest, flown a distance 5120 km away, and released. It found its way back to its nest 12.5 days after release. If we place the origin at the nest and extend the + x-axis to the release point, what was the bird’s average velocity in m/s:

a. for the return flight
b. for the whole episode, from leaving the nest to returning

Answers

Answer:

a)   v = -4.74 m / s, b)  v = 0 m / s

Explanation:

Average speed is

          v = Δx /Δt

a) the variation of the distance on the return trip is

          Δx = -5120 km = -5120 10³ km

the negative sign is because the bird is going back

          Δt = 12.5 days (24 h / 1 day) (3600 s / 1 h) = 1.08 10⁶ s

          v = -5120 10³ / 1.08 10⁶

          v = -4.74 m / s

b) the displacement for the round trip is zero, therefore the average velocity is

         v = 0 m / s

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