Answer:
Step-by-step explanation:
a1=5
d=2-5=-3
[tex]a_{n}=5+(n-1)(3)\\a_{n}=5+3n-3\\a_{n}=3n+2[/tex]
The quotient of 365.085 and 79.8
Answer:
4.575
Step-by-step explanation:
365.085/79.8=4.575
The U.S. Federal Seed Act establishes germination rates for various fruit and vegetable seeds. Watermelon seeds are to meet a 70% germination standard. A skeptical gardener who has not had very good luck planting watermelons believes that the seed company he purchases seeds from is not adhering to the 70% federal mandate. Once a week for 12 weeks, he purchases a pack of 10 watermelon seeds to act as his sample. He plants the seeds in a greenhouse with good soil to maintain a consistent temperature and watering routine. He finds that the germination rate for the company's watermelon seeds is 55%. Compute a 98% confidence interval to estimate the proportion of watermelon seeds that germinate. Be sure to interpret your interval in the context of the problem.
Answer:
The 98% confidence interval to estimate the proportion of watermelon seeds that germinate is (0.4443, 0.6557). This means that we are 98% sure that the true proportion of all watermalong seeds of the company that germinate is between these two values, which means that there is good evidence that the proportion is below the 70% standard.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
Once a week for 12 weeks, he purchases a pack of 10 watermelon seeds to act as his sample. He plants the seeds in a greenhouse with good soil to maintain a consistent temperature and watering routine. He finds that the germination rate for the company's watermelon seeds is 55%.
This means that [tex]n = 12*10 = 120, \pi = 0.55[/tex]
98% confidence level
So [tex]\alpha = 0.02[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.02}{2} = 0.99[/tex], so [tex]Z = 2.327[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.55 - 2.327\sqrt{\frac{0.55*0.45}{120}} = 0.4443[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.55 + 2.327\sqrt{\frac{0.55*0.45}{120}} = 0.6557[/tex]
The 98% confidence interval to estimate the proportion of watermelon seeds that germinate is (0.4443, 0.6557). This means that we are 98% sure that the true proportion of all watermalong seeds of the company that germinate is between these two values, which means that there is good evidence that the proportion is below the 70% standard.
andrea is planning a birthday party and wants to include a cheese board with the desserts.
she reads online that she should have 110g of cheese per person ,but the cheese is sold in blocks of 500g
How many blocks of cheese should she buy to ensure that each guest can have 110g of cheese?
Step-by-step explanation:
how many people in the party please ?
given that abc=def what is the measure of d
Answer:
C. 47 deg
Step-by-step explanation:
m<A = 180 - 94 - 39 = 47
m<D = m<A = 47
QUICK PLEASE HELPPPPPPPPPPPP
=====================================================
Explanation:
Set the expression equal to 100 and get everything to one side
[tex]d^2 - 12d + 45 = 100\\\\d^2 - 12d + 45 - 100 = 0\\\\d^2 - 12d - 55 = 0\\\\[/tex]
Now use the quadratic formula. We'll plug in a = 1, b = -12, c = -55.
[tex]\ d = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\ d = \frac{-(-12)\pm\sqrt{(-12)^2-4(1)(-55)}}{2(1)}\\\\\ d = \frac{12\pm\sqrt{364}}{2}\\\\\ d \approx \frac{12\pm19.07878403}{2}\\\\\ d \approx \frac{12+19.07878403}{2}\ \text{ or } \ d \approx \frac{12-19.07878403}{2}\\\\\ d \approx \frac{31.07878403}{2}\ \text{ or } \ d \approx \frac{-7.07878401}{2}\\\\\ d \approx 15.53939201\ \text{ or } \ d \approx -3.53939201\\\\d \approx 15.54 \ \text{ or } \ d \approx -3.54[/tex]
We'll ignore the negative d value as we can't have a negative number of days.
This means d = 15.54 is the only approximate solution we'll consider.
If we plugged in d = 15, then,
d^2 - 12d + 45
(15)^2 - 12(15) + 45
90
This tells us that 90 masks were sold on day d = 15.
Now try d = 16
d^2 - 12d + 45
(16)^2 - 12(16) + 45
109
We see that 109 masks were sold on day d = 16. Somewhere between those days, 100 masks were sold. At the end of the 15th day, we got to 90. So in the middle of day 16 is when we reach the exact 100 mark we're after.
In short, we would round d = 15.54 up to d = 16 so that we clear the hurdle.
In other words, if you rounded d = 15.54 to d = 15, then you'd be 10 masks short of the goal. Besides, 15.54 rounds to 16 when rounding to the nearest whole number.
Line c has an equation of y=-1/6x+5. Perpendicular to line c is line d, which passes through the point (-3,-8). What is the equation of line d
Answer:
The equation of line d is [tex]y + 8 = 6(x + 3)[/tex]
Step-by-step explanation:
Equation of a line:
The equation of a line, in point-slope form, is given by:
[tex]y - y_0 = m(x - x_0)[/tex]
In which the slope is m and the point is [tex](x_0,y_0)[/tex]
Perpendicular lines:
If two lines are perpendicular, the multiplication of their slopes is -1.
Perpendicular to y=-1/6x+5
Slope of - 1/6, so:
[tex]-\frac{1}{6}m = -1[/tex]
[tex]m = 6[/tex]
So
[tex]y - y_0 = 6(x - x_0)[/tex]
Passes through the point (-3,-8).
This means that [tex]x_0 = -3, y_0 = -8[/tex]. So
[tex]y - y_0 = 6(x - x_0)[/tex]
[tex]y - (-8) = 6(x - (-3))[/tex]
[tex]y + 8 = 6(x + 3)[/tex]
PLS HELP LAST THING I NEED FOR MATH THIS SCHOOL YEAR
ANSWER WITH STEP BY STEP SOLOUTION/PROCESS = BRAINLIEST ANSWER AND 5* VOTE
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PART 2, PART 1 ALREADY POSTED CHECK PROFILE
Answer:
B = 25 because 180-25-130 = 25 and all angles within triangle add to 180 degrees
a = 6 because the triangle is isosceles and we can see symmetry and draw this to prove on two opposite lines, therefore we can now find height easier.
c = 10. 876 because 130/2 = 65 degree and with new central height we can find Right Angle and using 6 x sin (65) = 5. 438 then we multiply by 2 to find c
Then all you have to do is re-write and round to the nearest 10th and check the units and write degree sign where required.
Step-by-step explanation:
Can someone please answer quickly <3
Please help me on this!!!!
F(1) is saying the value of x is 1
Look at the graph where x is 1 and find the y value of where the line is.
At x = 1, the line is at y = 1 ( there is actually a dot showing you the location.
The answer is 1
a racer called the whirlwind. Its poster says that in 1/20 hour it covers 7/10 mile. What is the Whirlwind’s speed in miles per hour?
Answer:
Its speed is 14 mph.
Step-by-step explanation:
Given that regarding racer called The Whirlwind, its poster says that in 1/20 hour it covers 7/10 mile, to determine what is the Whirlwind’s speed in miles per hour the following calculation must be performed:
1/20 x 60 = 0.05 x 60 = 3 minutes
7/10 = 0.7
Therefore, every 3 minutes the Whirlwind travels 0.7 miles.
60/3 = 20
0.7 x 20 = 14
Thus, in an hour it travels 14 miles, with which its speed is 14 mph.
2 units
5
2 units
2 units
8 units
2 units
2 units
2 units
6 units
The area of the figure is
square units.
pls help asap!!
For the following geometric sequence, find the recursive formula.
(-80,20,-5...)
Answer:
asap!!
For the following geometric sequence, find the recursive formula.
(-80,20,-5...)
Step-by-step explanation:
asap!!
For the following geometric sequence, find the recursive formula.
(-80,20,-5...)
Force: F = MA; Solve for m.
mass = force / area
this is second law of motion ( Newton's 2nd law)
[tex]\longrightarrow{\blue{ m = \frac{F}{a} }}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Explanation}}{\red{:}}}}}[/tex]
F = ma
➺ m = [tex]\frac{F}{a} [/tex]
where,
F = Force
m = mass
a = acceleration
"F = ma" is Newton's second law of motion, which states that force is equal to mass times acceleration.
The SI unit of force is newton, symbol N.
[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]
What is 1/3 of 30% of 5/6 of 0.6 of 12?
Step-by-step explanation:
[tex] \frac{1}{3 } \times \frac{30}{1} = 10 \\ \\ \frac{10}{1} \times \frac{5}{6} = 8.33 \\ \\ \frac{833}{100} \times \frac{6}{10} = 4.998 \\ \\ \frac{4998}{1000} \times \frac{12}{1} = 59.976[/tex]
Help help help help help
Answer:
m(∠y) = 64°
Step-by-step explanation:
From the figure attached,
m(∠e) = 90°
m(∠b) + 67° = 180° [Linear pair of angles]
m(∠b) = 180 - 67
= 113°
m(∠c) + 75° = 180° [Linear pair of angles]
m(∠c) = 105°
m(∠a) = m(∠d)
By the property of a polygon,
Sum of the interior angles of a polygon is given by,
Sum of interior angles = (n - 2) × 180°
Here, n = number of sides of the polygon
For n = 5,
Sum of interior angles = (5 - 2)×180°
= 540°
m(∠a) + m(∠b) + m(∠c) + m(∠d) + m(e) = 540°
2m(∠d) + 113° + 105° + 90° = 540°
2m(∠d) + 308 = 540°
2m(∠d) = 540 - 308
m(∠d) = 116°
m(∠d) + m(∠y) = 180°
m(∠y) + 116° = 180° [Linear pair of angles]
m(∠y) = 64°
Solve for x in the equation x2 - 4x-9 = 29.
Answer:
[tex]x=2+\sqrt{21}\\\\x=2-\sqrt{21}[/tex]
Step-by-step explanation:
One is given the following equation;
[tex]x^2-4x-9=29[/tex]
The problem asks one to find the roots of the equation. The roots of a quadratic equation are the (x-coordinate) of the points where the graph of the equation intersects the x-axis. In essence, the zeros of the equation, these values can be found using the quadratic formula. In order to do this, one has to ensure that one side of the equation is solved for (0) and in standard form. This can be done with inverse operations;
[tex]x^2-4x-9=29[/tex]
[tex]x^2-4x-38=0[/tex]
This equation is now in standard form. The standard form of a quadratic equation complies with the following format;
[tex]ax^2+bx+c[/tex]
The quadratic formula uses the coefficients of the quadratic equation to find the zeros this equation is as follows,
[tex]\frac{-b(+-)\sqrt{b^2-4ac}}{2a}[/tex]
Substitute the coefficients of the given equation in and solve for the roots;
[tex]\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}[/tex]
Simplify,
[tex]\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}\\\\=\frac{4(+-)\sqrt{16+152}}{2}\\\\=\frac{4(+-)\sqrt{168}}{2}\\\\=\frac{4(+-)2\sqrt{21}}{2}\\\\=2(+-)\sqrt{21}[/tex]
Therefore, the following statement can be made;
[tex]x=2+\sqrt{21}\\\\x=2-\sqrt{21}[/tex]
Debbie did a survey of how many states the members of her class had visited. The results were: 10, 15, 23, 2, 21, 31, 14, 10,
8.17, 11, 19.8.42.15. 22. 6, 34, 19.3, 24,
What is the five-number summary for this set of data?
Answer:
Step-by-step explanation:
11 22 6 34 19
what would my grade be if i got 68% on my exam?
Answer:
I am not to sure how the actual grade was calculated, maybe there are some other factors to it, but from the three grades you got, the weighted total is 70.2%, if we add the weighted average of 68 on the exam (with the weight being 20%), we get 83.3%.
find all possible values for each expression
9514 1404 393
Answer:
D
Step-by-step explanation:
The sine function is negative only for angles greater than 180°. This eliminates choice B.
The sine function is periodic with a period of 360°, eliminating choices A and C.
The only viable choice is D, which is the correct one.
Which of the following expressions have a difference of 5? Check all that apply.
VX
0-3-(-8)
-2-3
1-(-4)
07-(-2)
9514 1404 393
Answer:
A, C
Step-by-step explanation:
A: -3 -(-8) = -3 +8 = 5
B: -2 -3 = -5
C: 1 -(-4) = 1 +4 = 5
D: 7 -(-2) = 7 +2 = 9
__
Differences A and C are 5.
Answer: A: -3- (-8)
B:1 -(-4)
Step-by-step explanation:
in A your subtracting them in B your adding them
How many ounces are equivalent to 9 pounds?(1pound=16 ounces)
Answer: 144
Step-by-step explanation:
If 1 pound is 16 ounces then you have to do 9 X 16
9x16 = 144
Therefore the answer is 144 ounces
Hope this helped!
Write the word or phrase that best completes each statement or answers the question. Solve the problem.
Two kinds of cargo, A and B, are to be shipped by truck. Each crate of cargo A is 50 cubic feet in volume and weighs 200 pounds, whereas each crate of cargo B is 10 cubic feet in volume and weighs 360 pounds. The shipping company charges $75 per crate for cargo A and $100 per crate for cargo B. The truck has a maximum load limit of 7200 pounds and 1000 cubic feet. How many crates of each cargo should be shipped on each truck in order to satisfy the load limits and yield the greatest charges? What is the greatest charge?
Answer:
z(max) = 2350
x₁ = 18 x₂ = 10
Step-by-step explanation:
Vol (ft³) W (p) Income ($)
Cargo A (x₁) 50 200 75
Cargo B (x₂) 10 360 100
Max load limit 1000 7200
Objective Function
z = 75*x₁ + 100*x₂
Constraints:
Volume constraint:
50*x₁ + 10*x₂ ≤ 1000
Weight constraint:
200*x₁ + 360*x₂ ≤ 7200
Model:
z = 75*x₁ + 100*x₂ to maximize
Subject to:
50*x₁ + 10*x₂ ≤ 1000
200*x₁ + 360*x₂ ≤ 7200
x₁ ≥ 0 x₂ ≥ 0 x₁ and x₂ integers
After 6 iterations with an on-line solver optimal solution is:
z(max) = 2350
x₁ = 18 x₂ = 10
1.4 meters is the same as
Answer:
Step-by-step explanation:
1.4 m = 1.4 * 100 = 140.0 = 140 cm
Which graph shows a dilation
Answer:
show the graphs?
Step-by-step explanation:
Find each event probability
Answer:
Event 4 (0%), Event 2 (45%), Event 3 (80%), Event 1 (100%)
Step-by-step explanation:
How long does it take to get more skips
Answer: Just create an account and you have unlimited skips.
Determine whether each of the binary relation R defined on the given sets A is reflexive, symmetric, antisymmetric, or transitive. If a relation has a certain property, prove this is so; otherwise provide a counterexample to show that it does not. (a) A = Z: (a, b) E R if and only if ab > 0. (b) A = R: (a, b) R if and only if a^2=b^2 (c) A = N: (a, be R if and only if a/b is an integer.
Answer:
In explanation
Please let me know if something doesn't make sense.
Step-by-step explanation:
a)
*This relation is not reflexive.
0 is an integer and (0,0) is not in the relation because 0(0)>0 is not true.
*This relation is symmetric because if a(b)>0 then b(a)>0 since multiplication is commutative.
*This relation is transitive.
Assume a(b)>0 and b(c)>0.
Note: This means not a,b, or c can be zero.
Therefore we have abbc>0.
Since b^2 is positive then ac is positive.
Since a(c)>0, then (a,c) is in R provided (a,b) and (b,c) is in R.
*The relation is not antisymmretric.
(3,2) and (2,3) are in R but 3 doesn't equal 2.
b)
*This relation is reflective.
Since a^2=a^2 for any a, then (a,a) is in R.
*The relation is symmetric.
If a^2=b^2, then b^2=a^2.
*The relation is transitive.
If a^2=b^2 and b^2=c^2, then a^2=c^2.
*The relation is not antisymmretric.
(1,-1) and (-1,1) is in the relation but-1 doesn't equal 1.
c)
*The relation is reflexive.
a/a=1 for any a in the naturals.
*The relation is not symmetric.
Wile 4/2 is an integer, 2/4 is not.
*The relation is transitive.
If a/b=z and b/c=y where z and y are integers, then a=bz and b=cy.
This means a=cyz. This implies a/c=yz.
Since the product of integers is an integer, then (a,c) is in the relation provided (a,b) and (b,c) are in the relation.
*The relation is antisymmretric.
Assume (a,b) is an R. (Note: a,b are natural numbers.) This means a/b is an integer. This also means a is either greater than or equal to b. If b is less than a, then (b,a) is not in R. If a=b, then (b,a) is in R. (Note: b/a=1 since b=a)
Find the missing term given below.
14,916,2536,?
find the equation of the line passing through points A(3,4) and B(1,10)
Answer:
y = -3x + 13
Step-by-step explanation:
First, find the slope:
[tex]m=\frac{y_1-y_2}{x_1-x_2}\\\\m=\frac{4-10}{3-1}\\\\m=\frac{-6}{2}\\\\m=-3[/tex]
Finally, find the equation:
[tex]y-y_1=m(x-x_1)\\\\y-4=-3(x-3)\\\\y-4=-3x+9\\\\y=-3x+13[/tex]
reduce 1/2 × 16/9 is to lowest form
Answer:
The correct answer will be "[tex]\frac{8}{9}[/tex]".
Step-by-step explanation:
The given expression is:
= [tex]\frac{1}{2}\times \frac{16}{9}[/tex]
By applying multiplication, we get
= [tex]\frac{16}{18}[/tex]
= [tex]\frac{8}{9}[/tex]
Thus, the above is the lowest form.