It is a true statement that the idea that all matter consists of elements was first introduced a few hundred years ago.
What is the matter?Anything which has mass and occupies space is known as matter, mainly there are four states of matter solid liquid gas, and plasma.
These different states of matter have different characteristics according to which they vary their volume and shape.
Individuals have believed that earth, air, water, and fire are the only four elements that make up matter for roughly two thousand years.
For more than two thousand years, Aristotle's theory that all matter is composed of just four elements was accepted, but only around 500 years ago did scientists begin to find all of the elements that are currently recognized.
Beginning around five hundred years ago, scientists started learning about all of the elements that are currently recognized.
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The air pressure inside a car tire is
3.00 atm, and it creates 41,500 N
of force pushing out on the tire.
What is the surface area of the
inside of the tire?
(Unit = m^2)
Answer:
[tex]A=0.136\ m^2[/tex]
Explanation:
The air pressure inside a car tire is 3 atm = 303975 Pa
The force of 41,500 N of force pushing out on the tire.
We need to find the surface area of the inside of the tire. The pressure acting on an object is given by :
[tex]P=\dfrac{F}{A}\\\\A=\dfrac{F}{P}\\\\A=\dfrac{41500}{303975}\\\\A=0.136\ m^2[/tex]
So, the surface area of the inside of the tire is [tex]0.136\ m^2[/tex].
An element has a charge of -3, has 8 protons, 11 neutrons, and electrons
Word Bank:
12 5 11 8 13
pls help
A hockey puck that has a mass of 0.170 kg travels with a speed of 42.0 m/s.
What is the momentum of the puck?
Answer:
Momentum = 7.14 Kgm/s
Explanation:
Given the following data;
Mass = 0.170 kg
Velocity = 42m/s
To find the momentum;
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
Momentum = mass * velocity
Substituting into the equation, we have;
Momentum = 0.170 * 42
Momentum = 7.14kgm/s
Therefore, the momentum of the honey puck is 7.14 Kgm/s.
Comparing the Motion of Two Cars
Position vs Time
for Two Cars
D
Which statements describe the motion of car A and car
B? Check all that apply.
Car A and car B are both moving toward the origin.
Car A and car B are moving in opposite directions,
Car Ais moving faster than car B.
Car A and car B started at the same location.
Car A and car B are moving toward each other until
they cross over.
B
Position (m)
Time (s)
B, C, E
Hope this helps
A 9 V battery produces a current of 18 amps. What is the resistance?
[tex] \sf• \: Battery \: Voltage \: (V) = 9 \: v[/tex]
[tex] \sf• \: Current \: (I) = 18 \: Amps.[/tex]
[tex] \\ [/tex]
[tex]\bf{ \underline{To \: Find :- }}[/tex][tex] \sf• \: The \: Resistance. [/tex]
[tex] \\ [/tex]
[tex] \huge\bf{ \underline{Solution :- }}[/tex]
[tex] \bf \red{ \bigstar{ \: Formula \: of \: Resistance \: (R) = \frac{V}{I}}}[/tex]
[tex] \rightarrow \sf R = \frac{9}{18} [/tex]
[tex] \rightarrow \sf R = \frac{1}{2}[/tex]
[tex] \rightarrow \sf R = 0.5[/tex]
[tex] \\ [/tex]
[tex] \bf \purple{Therefore, \: the \: \: resistance \: \: is \: \: 0.5 \: Ω \: .}[/tex]scientific notation
1. 0,000034
2. 0,0054
3. 346574
4. 0,00125
5. 348954
Answer:
1. 3.4 x10^-5
2. 5.4 x10^-3
3. 346574
4. 12.5x10^-4
5. 348954
Hope this helps, please mark me brainliest if it does! :)
An ice skater accelerates backward for 5.0 second to final speed of 12m/s. If the acceleration backward was at a a rate of 1.5m/s2 what was the skater's initial speed
Answer:
Initial velocity, U = 4.5m/s
Explanation:
Given the following data;
Final velocity, v = 12m/s
Time, t = 5 seconds
Acceleration, a = 1.5m/s²
To find the initial velocity, we would use the first equation of motion.
[tex] V = U + at[/tex]
Where;
V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
Substituting into the equation, we have;
12 = U + 1.5*5
12 = U + 7.5
U = 12 - 7.5
Initial velocity, U = 4.5m/s
PLS ANSWER FAST WILL GIVE BRAINLYEST TIMED TEST!!!!
use the equation solving a= F divided by M
Also use metres per second squared [m/s2]
A Spring balance is used to launch a 0.05 kg foam ball with a force of 5N. What acceleration is produced?
walks 5 meters in 5 seconds what is the average speed
Answer:
10 is the speed
Explanation:
this is y
How quickly will a 4 kg ball be accelerated if it is struck by a 12 N force?
Explanation:
Hey there!
Given that 4kg ball struck by 12 N force.
So, we need acceleration.
Force = Mass × Acceleration
And, so
Acceleration = Force / Mass.
Acceleration = 12/4
Acceleration is equal to 3m/s² in SI units.
Hope it helps :)
Which of the following represents a chemical change?
A. Melting
of ice to water.
B. Combustion of a firecracker
C. Salt dissolves in water
D. The iron stretched into wires-ductile and iron pounded into sheets-malleable.
You toss a walnut at a speed of 15.0 m/s at an angle of 50.0∘ above the horizontal. The launch point is on the roof of a building that is 20.0 m above the ground.
a)How long after it is launched does the walnut reach the ground?
b)How far does the walnut travel horizontally from launch point to landing point?
c) What are the horizontal and vertical components of the walnut’s velocity just before it reaches the ground? Suppose that the +y-axis is directed upward and the +x-axis is directed horizontally from the launch point toward the landing point.
Answer:
a.3.51s
b.33.8m
c. 9.64,-22.9
Explanation:
(a) The time taken be "3.5083 sec".
(b) The distance will be "33.82 m".
(c) The horizontal and vertical components be "9.64 m/s and -22.89 m/s".
Velocity and DirectionAccording to the question,
Speed, V₀x = 15 Cos (50.0°)
= 9.64 m/s
V₀y = 15 Sin (50.0°)
= 11.49 m/s
Vertical displacement = -20.0 m
(a) We know the relation between displacement, time and acceleration
→ y = vt + [tex]\frac{1}{2}[/tex]at²
By substituting the values,
→ -20.0 = 11.49 t - 4.9 t²
4.9 t² - 11.49 t - 20.0 = 0
t = [tex]\frac{11.49 + \sqrt{132.02+392} }{9.8}[/tex]
= [tex]\frac{11.49 + 22.89}{9.8}[/tex]
= 3.5083 sec
(b) We know the formula,
Distance = Speed × Time
or,
→ X = 9.64 t
= 9.64 × 3.5083
= 33.82 m
(c) Again by using the above relation, we get
Vx = V₀x
= 9.64 m/s
Vy = V₀y - gt
By substituting the values,
= 11.49 - 9.8 × 3.5083
= 11.49 - 34.38
= -22.89 m/s
Thus the response above is correct.
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its in the pic plz help
Answer:
Hand soap: basic
chocolate milk: neutral
apple juice: acidic
shampoo: acidic
mouthwash: acidic
tap water: basic
Explanation:
Check your PH scale
1-6 = acidic
7 = neutral
8-14 = basic
A bird is flying with a speed of 18.0 m/s over water when it accidentally drops a 2.00 kg fish. If the altitude of the bird is 5.40 m and friction is ignored, what is the kinetic energy of the fish when it hits the water?
If a 5.5 kg object experiences 15 N of force for .15 seconds what is the speed change
The speed change : Δv = 0.41 m/s
Further explanationGiven
mass = 5.5 kg
Force = 15 N
time = 0.15 s
Required
the speed change
Solution
Newton 2nd's law
Impulse and momentum
F = m.a
F = m . Δv/t
F.t = m.Δv
Input the value :
15 N x 0.15 s = 5.5 kg x Δv
Δv = 0.41 m/s
need help someone please
Answer:
C would be the correct answer.
If you have observed something about the world and want to
investigate it further, what are you seeking to do?
a Do background research
b Construct a hypothesis
C Ask a question
d Report the results
Answer: a
Explanation: :)
Which process causes the transfer of energy by air currents within the Earth's atmosphere?
Answer:
Conduction, radiation and convection all play a role in moving heat between Earth's surface and the atmosphere. Since air is a poor conductor, most energy transfer by conduction occurs right near Earth's surface
3. A ferryboat accelerates from rest at a rate of 0.500 m/s2.
a. What is the velocity of the boat after it has traveled 4.75 m?| I
Answer:
2.18 m/s.
Explanation:
7. A ball is dropped from a height of 4.0 m. Just before it hits the ground it's momentum is
8.85 kg-m/s. What is the mass of the ball?
Answer:
Approximately [tex]1\; \rm kg[/tex]. (Assumption: [tex]g = 9.8\; \rm m \cdot s^{-2}[/tex].)
Explanation:
Let the mass of this ball be [tex]x\; \rm kg[/tex].
Initial gravitational potential energy of this ball: [tex]m \cdot g \cdot h \approx (39.2\, x) \; \rm J[/tex].
Just before the ball hits the ground, all [tex](39.2\, x)\; \rm J[/tex] of gravitational potential energy would have been converted to kinetic energy. Calculate the velocity of the ball at that moment:
[tex]\begin{aligned} \text{kinetic energy} = \frac{1}{2}\, m \cdot v^{2} \end{aligned}[/tex].
Therefore, right before hitting the ground, the velocity of the ball would be:
[tex]\begin{aligned} v&= \sqrt{\frac{2\, (\text{kinetic energy})}{m}} \\ &= \sqrt{\frac{2 \times (39.2\, x)}{x}}\\ & \approx \sqrt{2 \times 39.2} \approx 8.85\; \rm m \cdot s^{-1}\end{aligned}[/tex].
The momentum [tex]p[/tex] of an object of mass [tex]m[/tex] and velocity [tex]v[/tex] would be [tex]p = m \cdot v[/tex]. Rewrite this equation to find an expression for mass [tex]m\![/tex] given velocity [tex]v\![/tex] and momentum [tex]p\![/tex]:
[tex]\displaystyle m = \frac{p}{v}[/tex].
Right before collision, the momentum of this ball is [tex]p = 8.85\; \rm kg \cdot m \cdot s^{-1}[/tex] while its velocity is [tex]v \approx 8.85\; \rm m \cdot s^{-1}[/tex]. Therefore, the mass of this ball would be:
[tex]\begin{aligned}m &= \frac{p(\text{right before landing})}{v(\text{right before landing})} \\ &\approx \frac{8.85\; \rm kg \cdot m \cdot s^{-1}}{8.85\; \rm m \cdot s^{-1}} \approx 1\; \rm kg\end{aligned}[/tex].
2. What is the y-component of a 95.3 N force that is exerted at 57.1
degree to the horizontal, *
Answer: 80N
Explanation:
The y-component would be the magnitude of the force multiplied by the sine of the angle.
[tex]95.3*\sin(57.1)=80N[/tex]
The y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.
What is Force?Force is defined as an external agent which is capable of changing the state of rest or motion of a body with magnitude and direction. The direction towards which the force is applied is known as the direction of the force, and the point of application of the force is where the force is applied.
It can be expressed as:
F = m a
Where, F= Force
m= mass of the object
a= acceleration
In the given example, the force acts as vector which is broken down into the components. Given the angle θ along the horizontal axis,
so, For x component [tex]F_x[/tex] = Fcosθ
For y component [tex]F_y[/tex] = F sinθ
Given, F= 95.3 N ; θ= 57.1 °
[tex]F_y = (95.3) * (sin 57.1)\\ F_y= 80.0N[/tex]
Thus, the y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.
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An excited 92 kg football player celebrates a touchdown by carelessly running straight into the goalpost at 9.4 m/s. He bounces straight backward at 6.2 m/s. What was the change in velocity? What was the impulse of the player?
Answer:
i. 15.6 m/s
ii. I = 1.44 KNs
Explanation:
The impulse, I, on a body is the product of force applied on it and the time it acts.
i.e I = F x t
Impulse is sometimes expressed as the change in momentum of a body. It is measured in Ns.
i. mass, m, of the player = 92 kg
initial velocity of the player, u = 9.4 m/s
final velocity of the player, v = 6.2 m/s
Since he bounces back on hitting the pole, then the sign of initial and final velocities are of opposite sign.
So that,
change in velocity of the player = final velocity - initial velocity
= 6.2 - (-9.4)
= 6.2 + 9.4
= 15.6 m/s
change in velocity of the player is 15.6 m/s
ii. Impulse, I = m(v - u)
= 92 x 15.6
= 1435.2
Impulse on the player is 1.44 KNs.
How do limiting factors impact Pacific Coast organisms?
Answer:
Limiting factors include a low food supply and lack of space. Limiting factors can lower birth rates, increase death rates, or lead to emigration. When organisms face limiting factors, they show logistic growth (S-shaped curve, curve B: Figure below). ... Limiting factors determine the carrying capacity of a population.
Explanation:
A cart at rest accelerates to a speed of 30 meters per second over a 3.0 second time interval. What is the average velocity of the cart during these 3.0 seconds? P.4B
Answer:
15 m/s
Explanation:
Given data
Initial velocity= 0m/s----------since the cart was at rest
Final velocity = 30m/s
time= 30 seconds
Required
the average speed
We know that the sum of the initial and final velocity is divided by 2 to find the average velocity
average velocity= 0+30/2
average velocity= 30/2
average velocity= 15 m/s
Hence the average velocity is 15 m/s
Formula for angular acceleration
Answer:
[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}[/tex]
Explanation:
The angular acceleration is given by the relation as follows :
[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}[/tex]
Where
[tex]\omega_i\ and\ \omega_f[/tex] are the initial and final angular velocities
t is time
The SI unit of angular acceleration is rad/s². Hence, this is the required solution.
no one can answer
why electrons are negetive?
Answer:
they're negative bc a proton is positive. a proton attracts an electron by the fact that opposite charges attract each other, while two electrons repel each other. Thus it shows that polarity of the charge on an electron and a proton is opposite.
Explanation:
When you push an object, it pushes back with an equal and opposite force
Answer:
I would say false
Explanation:
Because friction slows it down which means when the object bounces back it will not have the same energy or force that was applied before.
What is the net force of a scooter acting on the road with an impulse of 550 Ns for 10s.
Answer:
55N
Explanation:
Impulse is the product of Force and Time
Impulse = Force * Time
Given
Impulse = 550Ns
Time = 10s
Force = Impulse/Time
Force = 550/10
Force = 55N
Hence the net force on the scooter is 55N
A trash compactor pushes down with a force of 500 N on a 3 cm2 input piston, causing a force of 30,000 N to crush the trash. What is the area of the output piston that crushes the trash
Answer:
[tex]180 cm^2[/tex]
Explanation:
We are given that
Force [tex]F_1=500 N[/tex]
[tex]A_1=3cm^2[/tex]
[tex]F_2=30000 N[/tex]
We have to find the area of the output piston that crushes the trash
Input piston=Output piston
We know that
[tex]Pressure=\frac{force}{Area}[/tex]
Using the formula
[tex]\frac{F_1}{A_1}=\frac{F_2}{A_2}[/tex]
Substitute the values
[tex]\frac{500}{3}=\frac{30000}{A_2}[/tex]
[tex]A_2=\frac{30000\times 3}{500}[/tex]
[tex]A_2=180 cm^2[/tex]
Hence, the area of the output piston that crushes the trash 180 square cm
A trash compactor pushes down with a force of 500 N on a 3 cm² input piston, causing a force of 30,000 N on a 180 cm² output piston.
In physics, the pressure (P) is the force (F) applied perpendicular to the surface of an object per unit area (A) over which that force is distributed.
[tex]P = \frac{F}{A}[/tex]
A trash compactor pushes down with a force of 500 N (F₁) on a 3 cm² (A₁) input piston, causing a force of 30,000 N (F₂) to crush the trash.
Since the pressure in both pistons is equal, we can use the previous expression to calculate the area of the output piston (A₂).
[tex]\frac{F_1}{A_1} = \frac{F_2}{A_2} \\\\A_2 = \frac{A_1 \times F_2}{F_1} = \frac{3cm^{2} \times 30,000N}{500N} = 180cm^{2}[/tex]
A trash compactor pushes down with a force of 500 N on a 3 cm² input piston, causing a force of 30,000 N on a 180 cm² output piston.
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An object’s distance from a converging lens is 16.1 times the focal length.
How far is the image from the lens?
Answer in units of f .
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Have a blessed day;))
Explanation: