explain how materials are suited for different uses based on their physical and chemical properties?

Answer:

in contrast, peru and Bolivia entered the war hindered by numerous domestic fractures and by an economic and insititutional backwardness that nearly prevented the two countries from fighting the war at all

Answer:

A compound is something like atoms coming together as a team, and a mixture is 2 or more substances mixing together.

Explanation:

Answer:

Hey mate....

Explanation:

This is ur answer....

Plants use a process called photosynthesis to make food. During photosynthesis, plants trap light energy with their leaves. Plants use the energy of the sun to change water and carbon dioxide into a sugar called glucose. Starch is stored in seeds and other plant parts as a food source.

Hope it helps!

Brainliest pls!

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Answer:

Plants use photosynthesis to convert sun light into their own food to consume. Green plants use this light energy to change water and carbon dioxide into oxygen and nutrients called sugars. The plants use some of the sugars and store the rest. The oxygen is released into the air.

The acid ionization constant is the quantitative measure of the acidic strength. For oxalic acid, Ka = [H⁺] [HC₂O₄⁻] / [H₂C₂O₄]

Acid dissociation (Ka) is the ratio of the concentration of the conjugate base and hydrogen ion to the concentration of the chemical.

Oxalic acid is a weak acid and gets dissociated as:

H₂C₂O₄ ⇌ H⁺ + HC₂O₄⁻

or

HC₂O₄⁻ ⇌ H⁺ + C₂O₄²⁻

The acid ionization constant for the reactant and the product is given as:

Ka = [H⁺] [A⁻] / [HA]

Ka = [H⁺] [HC₂O₄⁻] / [H₂C₂O₄]

Therefore, the ionization constant for oxalic acid is given as Ka = [H⁺] [HC₂O₄⁻] / [H₂C₂O₄]

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Answer:

the bond is ionic

Explanation:

[tex] = 1kg \: \: \times 9.8 {ms}^{ - 2} \\ = 9.8 \: \: N[/tex]

B. 9.8 N

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

There are four elements that are found in all living animals, that are:

Oxygen (O)

Carbon (C)

Hydrogen (H)

Nitrogen (N).

Here is the atomic model in the picture.

Answer:

1. molecule, cell, tissue, organ, organ system, organism, population, community, ecosystem, biosphere

2. A

3. D

4. C

5. C

6. C

7. C

8. B

9. Sorry I don't know :(

10. B

11. A

12. C

13. Sorry :((

14. C

15. a

16. d

Sorry I don't know the rest.. I hope this helps though!!

Answer:

273.15 Kelvins

Explanation:

Answer:

The primary producer uses some of that energy. Because we lose energy each time we move up a trophic level, we have more producers than consumers, more herbivores than carnivores, more primary consumers than secondary consumers. See this Socratic answer for more detail.

Explanation:

Answer:

Producers produce food energy for themselves and all the other levels

Explanation:

Answer:

bromine

Explanation:

The molar volume (Vm) is the volume occupied by one mole of a chemical element or chemical compound at standard temperature and pressure (STP). The molar volume of Cl₂ is 35.10 cm³/mol.

One mole of any gas has a defined volume when it is at a particular temperature and pressure. The relationship between molar mass and molar volume is direct and inverse, respectively.

Two gases have equal molecules if their volumes are the same at a given temperature and pressure. A gas's volume is directly proportional to the number of moles it contains. One mole of any gas takes up 22.4 L of space at STP.

The expression used to calculate molar volume is:

Molar volume = Molar mass / Density

The molar mass of Cl₂ = 70.906 g/mol

Molar volume = 70.906 / 2.02

Molar volume = 35.10 cm³/mol

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Answer:

0.354 molal

Explanation:

The molarity (M) or the concentration of a solution is defined as the number of moles of a compound in the solution per liter of solution (mol/L), whereas molality, is defined as the number of moles of a compound in the solution per kg of the compound (mol/kg).

Given that the density of the solution is 1.202 g/mL, which is equivalent to 1.202 kg/L. Since the prefix mili- denotes a factor of one thousandth ( [tex]10^{-3}[/tex] ) and kilo- denotes a factor of one thousand ( [tex]{10}^3[/tex] ),

[tex]1.202 \ \frac{g}{mL} \ = \ 1.202 \ \frac{g}{(10^{-3}) L} \ = \ 1.202 \ \frac{{10}^3g}{L} \ = \ 1.202 \ \frac{kg}{L}[/tex].

To calculate the corresponding molality of the solution, the formula

[tex]Molality \ (mol/kg) \ = \ \frac{Molarity \ (mol/L)}{Density \ (kg/L)}[/tex] is used.

Therefore,

[tex]Molality \ = \ \frac{0.426 \ mol/L}{1.202 \ kg/L} \ = \ 0.354 \ mol/kg \ \ (3 \ s.f.)[/tex]

Answer:

38.38 L (3 d.p.)

Explanation:

In response to questions addressing the expansion of gas via heating, Charles's Law should be considered. Charles's Law is an experimental gas law explaining the tendency of gases to expand when heated.

The law states that the volume ([tex]V[/tex])  of a gas is directly proportional to its temperature ([tex]T[/tex]) given that the pressure ([tex]P[/tex]) and the amount of gas ([tex]N_{A}[/tex]) are constant.

[tex]\displaystyle\frac{V}{T} \ = \ k \ \ \ \ \ \ \ or \ \ \ \ \ \ \ V \ = \ kT[/tex], where k is a proportionality constant.

*Note that when substituting temperature into the equation, the temperature must be in terms of the Kelvin scale and not in degrees Celsius. The relation between the Kelvin scale and the Celsius scale is  [tex]\mathrm{K} \ = \ ^{\circ}\mathrm{C} \ + \ 273[/tex].

Charles's law can be used to compare changing conditions of a particular gas. Let  [tex]V_{1}[/tex]  and  [tex]T_{1}[/tex]  be the initial volume and temperature for the gas, while  [tex]V_{2}[/tex]  and  [tex]T_{2}[/tex]  be the final volume and temperature. The mathematical relationship of Charles's law becomes:

[tex]\displaystyle\frac{V_{1}}{T_{1}} \ = \ \displaystyle\frac{V_{2}}{T_{2}}[/tex].

In accordance with the question,

[tex]V_{1} \ = \ 33.4 \ \mathrm{L}, \ T_{1} \ = \ (22 \ + \ 273) \ \mathrm{K} \ = \ 295 \mathrm{K}, \ T_{2} \ = \ (66 \ + \ 273) \ \mathrm{K} \ = \ 339 \ \mathrm{K}[/tex]

while  [tex]V_{2}[/tex]  is the final volume of the gas that we would like to find. Therefore,

[tex]V_{2} \ = \ \displaystyle\frac{V_{1} \ \times \ T_{2}}{T_{1}} \\ \\ V_{2} \ = \ \displaystyle\frac{33.4 \ \mathrm{L} \ \times \ 339 \ \mathrm{K}}{295 \ \mathrm{K}} \\ \\ V_{2} \ = \ 38.38 \ \mathrm{L}[/tex].

Answer:

A. 4,6-dimethyloct-1,4,6-yne

B. deconic acid

C. 3-ethyl-4-methyl-7-bromocyclohexene

D. 2,2,3-trimethyl-4-butyl-heptane

E. 3-methylhexane

F. ethyl hexanoate

G. butanal

H. propyne

J. 2,4-dimethyl-pent-2-ene

Explanation:

sorry i didn't have time to do I

Answer:

pure-bred green with pure-bred yellow peas. Since yellow is dominant to green, all of the offspring were yellow. The green phenotype had disappeared. ... When a pure-bred green plant is crossed with a pure-bred yellow plant, the offspring inherit one allele of the color gene from each parent.

Explanation:

Ppbag at it again

Answer:

i the answer to your question should be C

Explanation:

Hope this helps!

The atomic mass of an element related to a mole in grams, is the mass of one mole of atoms. Therefore, option C is correct.

An atom's mass is its atomic mass. Although the kilogramme is the SI measure of mass, the unified atomic mass unit, or dalton, is a common way to express atomic mass. An unbound carbon-12 atom in its ground state has a mass of 112 of a Da.

A mass that is one-twelfth the mass of an atom of carbon-12 is known as an atomic mass unit. Any isotope of any element's mass is represented in terms of the carbon-12 reference standard.

The size of an atom is indicated by its atomic mass. Technically speaking, an atom's mass is the total weight of its protons, neutrons, and electrons.

Thus, option C is correct.

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Answer:

1.1 mol

Explanation:

n=m/M, where n is moles, m is mass, and M is molar mass.

M of CO2 = 12.01+16.00+16.00 = 44.01g/mol

n=50g/44.01g/mol

n = 1.13610543 mol

n ≈ 1.1 mol

Hope that helps

The ratio of molecules in sulphur dioxide and methane will be the same as the ratio of their moles. So, first of all we should find out the number of moles of sulphur dioxide in 1 gram of sulphur dioxide in 1 gram of sulphur dioxide, and the number of moles of methane in 1 gram of methane. This can be done as follows :

(i) The molecular formula of sulphur dioxide is [tex]SO_{2}[/tex]

So, [tex]1[/tex]  mole of [tex]SO_{2}[/tex] = [tex]Mass[/tex] [tex]of[/tex] [tex]2'O'[/tex]

[tex]=32+2*16[/tex]

[tex]= 64[/tex] grams

Now, [tex]64g[/tex] of sulphur dioxide [tex]= 1[/tex] mole

So, [tex]1g[/tex] of sulphur dioxide = [tex]\frac{1}{64}[/tex] mole

Thus, we have [tex]\frac{1}{64}[/tex] mole of sulphur dioxide and it contains molecules in it. Now, since equal moles of all the substance contain equal number of molecules, therefore, [tex]\frac{1}{64}[/tex] mole of methane will also contain x molecules of methane.

(ii) Molecular formula of methan is [tex]CH_{4}[/tex]

So, 1 mole of [tex]CH_{4}[/tex]  = Mass of C + Mass of 4 H

[tex]=12+4*12[/tex]

Now, 16g of methane = 1 mole

So, 1 g of mathane = [tex]\frac{1}{16}[/tex] mole

We know that:

[tex]\frac{1}{64}[/tex] mole of methane contains = x molecules

So, [tex]\frac{1}{16}[/tex]  mole of contains will contain =[tex]\frac{x*64}{16}[/tex] molecules

=[tex]4x[/tex] molecules

It will take the Ne gas approximately 1.2 s to equilibrate between the two sides.

We know that the time taken for a gas to diffuse is dependent on the molar mass of the gas. This is one of the interpretations of Graham's law of diffusion in gases. Thus, Let;

t1 = time taken for Rn to equilibrate = 4.0 s

t2 = time taken for Ne to equilibrate = ?

M1 = molar mass of Rn = 222g/mol

M2 = molar mass of Ne = 20 g/mol

Using

t1/t2 = √M1/M2

4/t2 = √222/20

4/t2 = 3.33

t2 = 4/3.33

t2 = 1.2 seconds

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Answer:

A. CaCO(s)+SO(g)+O(g) --> CaSO(s)+CO(g)

A. CaCO(s)+SO(g)+O(g) --> CaSO(s)+CO(g)

Answer:

It depends on their melting and/or their boiling points, because the heat provides the particles with kinetic energy to break the electrosatic bonds in the substances, which can differ in strength

Explanation:

The replacement reaction will not occur because iodine is less reactive than chlorine.

A replacement reaction is a type of reaction in which one element is replaced by another in a compound.

The principle behind one element replacing the other is based on the reactivity of an element. A more reactive element will displace a less reactive one.

According to this question, the following displacement reaction is given: MgCl2 + I2 → ?

This reaction will not occur because chlorine is more reactive/electronegative than iodine, hence, iodine cannot displace it.

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Answer:

good job ;0

Explanation:

Answer:

beta to Kr-80 or Se-80

Explanation:

sorry if wrong

Answer:

A13+

Explanation:

I took a test that had this question.

This problem is asking for the equilibrium constant at two different temperatures by describing the chemical equilibrium between gaseous nitrogen, oxygen and nitrogen monoxide at 25 °C and 1496 °C as the room temperature and the typical temperature inside the cylinders of a car's engine respectively:

N₂(g) + O₂(g) ⇄ 2 NO(g)

Thus, the calculated equilibrium constants turned out to be 6.19x10⁻³¹ and 9.87x10⁻⁵ at the aforementioned temperatures, respectively, according to the following work:

There is a relationship between the Gibbs free energy, enthalpy and entropy of the reaction, which leads to the equilibrium constant as shown below:

[tex]\Delta _rG=\Delta _rH-T\Delta _rS\\\\\Delta _rG=-RT ln(K)[/tex]

Which means we can calculate the enthalpy and entropy of reaction and subsequently the Gibbs free energy and equilibrium constant. In such a way, we calculate these two as follows, according to the enthalpies of formation and standard entropies of N₂(g), O₂(g) and NO(g) since these are assumed constant along the temperature range:

[tex]\Delta _rH=2*90.25 kJ/mol - (0 kJ/mol+0 kJ/mol)=180.5kJ/mol\\\\\Delta _rS=2*(0.211 kJ/mol*K)-(0.192kJ/mol*K+0.205kJ/mol*K)=0.025kJ/mol*K[/tex]

Then, we calculate the Gibbs free energy of reaction at both 25 °C and 1496 °C:

[tex]\Delta _rG_{25\°C}=180.5-(25+298.15)*0.025=172.42kJ/mol\\\\\Delta _rG_{1496\°C}=180.5-(1496+298.15)*0.025=135.65kJ/mol[/tex]

And finally, the equilibrium constants derived from the general Gibbs equation and Gibbs free energies of reaction:

[tex]K=exp(-\frac{\Delta _rG}{RT} )\\\\K_{25\°C}=exp[-\frac{172420 J/mol}{(8.3145\frac{J}{mol*K})(298.15K)} ]=6.19x10^{-31}\\\\K_{1496\°C}=exp[-\frac{135650J/mol}{(8.3145\frac{J}{mol*K})(1769K)} ]=9.87x10^{-5}[/tex]

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