Answer:
This a practical that you have to do. Not to us.
Explanation:
EXPERIMEXPERIMENT: SIMPLE MACHINES When we think of a machine, car engines, cranes, lifts, power drills, and vacuum cleaners usually come to mind. These devices are complex machines. Simple machines are the wedge, inclined plane, screw (an inclined plane wrapped on an axle), pulley, and lever. The jack used to lift a car is an example of a simple machine; it is simply a lever. In this investigation you will use a lever as a simple machine, and calculate its mechanical advantage and efficiency. Here are your goals for this lesson: Make quantitative observations and measurements with precision Analyze, evaluate and predict patterns from data Communicate findings These supplies are needed: meter stick string weights Play Mute Remaining TimeÂ-1:08 Picture-in-Picture Follow these directions and complete the activities. 1. Suspend the meter stick by a string from its center. 2. Notice carefully where it balances. It probably will not balance exactly at 50 cm. All distances must be measured to this point (called the fulcrum). 3. Hang a 200 g mass on one side and a 50 g mass on the other and adjust the distances from the fulcrum until the meter stick balances.(Be sure to account for the mass of the hanger from which you are suspending the masses. This can either be part of the total mass or, alternatively, if you are using something like coffee cups to hold the masses, their masses need to be matched perfectly before starting the experiment. You can do this by first checking to see how close they com
Determine the placement d of the pin on the 3-ft-diameter circular gate so that it begins to rotate clockwise (open) when water reaches a height h = 10 ft. What is the resultant force acting on the gate?
The resultant force acting on the gate is equal to zero, the gate will not rotate and the pin can be placed at any location on the circumference of the gate.
Circular Gate RotationTo determine the placement of the pin on the circular gate, we need to consider the forces acting on the gate when the water reaches a height h = 10 ft.
When water reaches a height h = 10 ft, the gate is subjected to two types of forces: (1) buoyant force and (2) weight of the gate. The buoyant force acts upwards and is equal to the weight of the fluid displaced by the gate. The weight of the gate acts downwards and is equal to the mass of the gate multiplied by the acceleration due to gravity (g).
Let's assume that the gate has a uniform thickness and its density is equal to the density of water (ρ). Then, the volume of the gate can be calculated as follows:
V = (π/4) * d² * t
where d is the diameter of the gate and t is its thickness. The mass of the gate can be calculated as follows:
m = ρ * V
The buoyant force can be calculated as follows:
F_b = ρ * g * V
The weight of the gate can be calculated as follows:
F_w = m * g
The net force acting on the gate can be calculated as the difference between the buoyant force and the weight of the gate:
F_net = F_b - F_w = ρ * g * V - m * g = (ρ - ρ) * g * V = 0
Since the net force is equal to zero, the gate will not rotate and the pin can be placed at any location on the circumference of the gate.
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researchers measured the data speeds for a particular smartphone carrier at 50 airports. the highest speed measured was___ mbps. the complete list of 50 data speeds has a mean of ___ mbps and a standard deviation of s ___ mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds?
The difference between the carrier's highest data speed (76.2 Mbps) and the mean of all 50 data speeds (15.95 Mbps) is 60.25 Mbps.
The difference of 60.25 Mbps between the carrier's highest data speed and the mean of all 50 data speeds is quite significant. It shows that this particular carrier has a much higher data speed than the average of the other 50 airports. This could be due to the particular location of the airport, the network infrastructure, or other factors.
An elementary reaction is a type of chemical reaction in which the reactants directly form the products in a single reaction step and with a single transition state. In contrast to a non-elementary reaction, which may involve multiple steps or intermediates, an elementary reaction is a single-step process in which the reactants are converted into products in a single step.
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A circuit contains an electrical power supply, a lamp, an ammeter, and a variable resistor. The resistance of the variable resistor is increased. What happens to the ammeter reading, and what happens to the brightness of the lamp?
A) The ammeter reading decreases, and the lamp's brightness increases.
B) The ammeter reading increases, and the lamp's brightness increases.
C) The ammeter reading decreases, and the lamp's brightness decreases.
D) The ammeter reading increases, and the lamp's brightness decreases.
When connected to a 12V battery, the current in a car headlight is 4.0 A.
When the lamp is lit, what is its resistance?
A) 3.0 ohms
B) 16 ohms
C) 48 ohms
D) 0.33 ohms
Answer:
A) 3.0 ohms
Explanation:
R=V/I=12V/4.0A=3.0 ohms
In your composition for a love story, how could you use tempo to reflect the mood when the ice cream van interrupted the wedding ceremony?
A. Slow, legato
B. Fast, upbeat
C. Ritardando
A. Slow, legato. for a love story, we use slow and legato tempo to reflect the mood when the ice cream van interrupted the wedding ceremony.
How does tempo appear in a score?The beats per minute are the most precise way for a composer to specify the intended speed (BPM). This means that a specific note value is designated as the beat (for instance, a quarter note), and the marking specifies that a specific number of these beats must be performed each minute.
How do you determine a song's tempo?The music's performance speed is thus determined by the tempo. So you can rapidly establish the Beats Per Minute, or BPM, by counting how many beats there are in a music played at a particular rate. If you're pushed for time, you can also double the amount of beats in 15 seconds of music by four.
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An automobile tire has a volume of 0.0185 m³. At a temperature of 289 K the absolute pressure in the tire is 217 kPa. How many moles of air must be pumped into the tire to increase its pressure to 272 kPa, given that the temperature and volume of the tire remain constant?
0.0018 moles of air must be pumped into the tire to increase its pressure to 272 kPa.
How to find the number of moles of airWe can use the ideal gas law to find the number of moles of air in the tire.
The ideal gas law states that PV = nRT,
where
P is pressure,
V is volume,
n is the number of moles of gas,
R is the ideal gas constant, and
T is temperature.
The initial number of moles of air in the tire:
n1 = (P1 * V) / (R * T)
= (217 kPa * 0.0185 m³) / (8.31 J/mol * K * 289 K)
= 0.00625 moles
Next, we can find the final number of moles of air in the tire, assuming the temperature and volume remain constant:
n2 = (P2 * V) / (R * T)
= (272 kPa * 0.0185 m³) / (8.31 J/mol * K * 289 K)
= 0.00805 moles
Finally, we can find the difference between the final and initial number of moles, which represents the number of moles of air that must be pumped into the tire:
n2 - n1 = 0.00805 moles - 0.00625 moles = 0.0018 moles.
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Two (unnormalized) excited state wavefunctions of the H atom are (i) psi= (2-r/a)*e^(-r/2a) and (ii) psi=r*sin(theta)*cos(phi)*e^(-r/2a).(a). Normalize both functions to one and confirm that these two functions are mutually orthogonal.(b) Evaluate the expectation values of r and r^2 for the atom.
(a) Normalization factor for wavefunction 1 is, [tex]A = \sqrt{\dfrac{3^3}{{(16\pi a^5)}}[/tex], for wavefunction 2 is, [tex]B = \sqrt{\dfrac{15}{16\pi a^5}}[/tex]. The two wavefunctions are mutually orthogonal. (b) The expectation value of r for [tex]\psi_1[/tex] is 32.
(a) To normalize the wavefunctions, we need to find the normalization constants A and B such that
[tex]\int \|{\psi_1}\|^2 dV = 1[/tex] and [tex]\int \|{\psi_2}\|^2 dV = 1[/tex]
where [tex]\psi_1[/tex] and [tex]\psi_2[/tex] are the two wavefunctions given.
(i) [tex]\psi_1 = (2 - \dfrac{r}{a}) \times e^{\dfrac{-r}{2a}}[/tex]
The normalization condition for psi1 is:
[tex]\int \|\psi_1\|^2 dV = \int \{2 - \dfrac{r}{a} \times e^{\dfrac{-r}{a}}\}^2 r^2 sin\theta dr d\theta d\phi\\\\ = 1[/tex]
Evaluating the integral using spherical coordinates, we get:
[tex]\int_0^\infty \int_0^\pi \int_0^{2\pi} [(2 - r/a)^2 e^{-r/a} r^2 sin\theta]\ dr\ d\theta\ d\phi = 1\\\\\dfrac{(16\pi a^5)}{(3^3)} \times \|A\|^2 = 1\\A = \dfrac{3^3}{{(16\pi a^5)}^{0.5}}[/tex]
(ii) [tex]\psi_2 = r sin\theta\ cos\phi\ e^{\dfrac{-r}{2a}}[/tex]
Evaluating the integral using spherical coordinates, we get:
[tex]\int_0^\infty \int_0^\pi \int_0^{2\pi} r^4 sin^3\theta cos^2\phi e^{-r/a} dr\ d\theta\ d\phi = 1\\\\\dfrac{16\pi a^5}{15} \times \|B\|^2 = 1\\B = \sqrt{\dfrac{15}{16\pi a^5}}[/tex]
To confirm that the two wavefunctions are mutually orthogonal, we need to evaluate the integral [tex]\int \psi_1\times \psi_2 dV[/tex] and show that it is equal to zero. Using spherical coordinates, we get:
[tex]\int_0^\infty \int_0^\pi \int_0^{2\pi} [(2 - r/a) \times e^{-r/a} \times r sin\theta cos\phi \times e^{-r/2a}]\ r^2\ sin\theta\ dr\ d\theta\ d\phi\\\\= 8\pi a^5 \times [\int_0^\infty e^{-r/a} r^2 (2 - r/a) e^{-r/2a}\ dr] \times [\int_0^\pi sin\theta\ cos\theta\ d\theta] \times [\int_0^{2\pi} cos\phi\ d\phi]\\= 0[/tex]
Therefore, the two wavefunctions are mutually orthogonal.
(b) To evaluate the expectation values of r and r^2, we need to calculate the integrals [tex]\int psi_1 \times r\ \psi_1 dV[/tex] and [tex]\int \psi_1 \times r^2\ \psi_1 dV[/tex]. Using spherical coordinates, we get:
For psi1:
[tex]\int psi_1 \times r\ \psi_1 dV = 4\pi \int_0^\infty (2 - r/a)^2 e^{-r/a} r^4 dr\\\\ = \dfrac{32\pi a^5}{15}[/tex]
[tex]\int \psi_1 \times r^2\ \psi_1 dV = 4\pi \int (2 - r/a)^2 e^{-r/a} r^5 dr\\\\ = \dfrac{128\pi a^6}{45}[/tex]
Therefore, the expectation value of r for [tex]\psi_1[/tex] is 32.
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You place a book on top of a spring and push down, compressing the spring by 10 cm. When you let go of the book, it is pushed up by the spring. Which statement describes what happens to the energy of the spring-book system? A) The gravitational potential energy of the system decreases. B) The total energy of the sytem remains constant. C) The kinetic energy of the system decreases. D) The elastic potential energy of the system increases.
The total energy of the system remains constant.
Option B.
What is law of conservation of energy?
The law of conservation of energy states that energy can neither be created nor destroyed but can be transferred from one form to another.
When you let go of the book, and it is pushed up by the spring, the elastic potential energy of the spring will be converted into potential energy and kinetic energy of the block.
elastic potential energy = potential energy + kinetic energy
Thus, we can conclude that the total energy of the system is constant.
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The 20-g centrifuge at NASA's Ames Research Center in Mountain View, California, is a horizontal, cylindrical tube of length 58.0 ft. Another 20-g centrifuge of length L = 59.0 ft is represented in the figure below. Assume an astronaut in training sits in a seat at one end, facing the axis of rotation 29.5 ft away. Determine the rotation rate, in revolutions per second, required to give the astronaut a centripetal acceleration of 20.0g. L/2. Part 1 of 4 - Conceptualize: Look carefully at the figure and imagine you are the astronaut sitting in the seat at the far right. As the centrifuge rotates, you are experiencing an acceleration toward the center of the device. The faster the centrifuge spins, the larger is that acceleration. The problem is asking for a rotation rate, measured in revolutions per second. Because the period of circular motion is the number of seconds per revolution, we see that the rotation rate will be the inverse of the period. rotation rate. 3) Based on the correct choice in question (2), substitute numerical values, including a unit conversion factor, to find the rotation rate for the centrifuge that will provide a centripetal acceleration of 20.0g for the astronaut. 1 ac 20.0( 9.8 m/s²), 1 1 X9 ft 2n 29.5 ft 1 m 0.74 rev/s %
For part 4 after solving the equation the the rotation rate is 0.74 rev/s.
What is rotation rate?
Rotation rate is the angular velocity of a body or object in a circular motion. It is typically measured in rotations per minute (RPM) and is the number of times a full rotation is completed in one minute.
Part 1 of 4 - Conceptualize: Look carefully at the figure and imagine you are the astronaut sitting in the seat at the far right. As the centrifuge rotates, you are experiencing an acceleration toward the center of the device.
The faster the centrifuge spins, the larger is that acceleration. The problem is asking for a rotation rate, measured in revolutions per second. Because the period of circular motion is the number of seconds per revolution, we see that the rotation rate will be the inverse of the period.
Part 2 of 4 - Calculate: To calculate the rotation rate, we need to find the period of the motion. The period of circular motion is given by:
T = 2π√(L/2a)
Where L is the length of the centrifuge and a is the centripetal acceleration.
Part 3 of 4 - Calculate: In this problem, L = 59.0 ft, and a = 20.0g. Since gravitational acceleration is equal to 9.8 m/s2, we need to convert the acceleration from g to m/s2. We can do this by multiplying the acceleration by 9.8. Thus, a = 20.0g × 9.8 m/s2 = 196.0 m/s2. Substituting the numerical values into the equation, we get:
T = 2π√(59.0 ft/2 × 196.0 m/s2) = 2π√(29.5 ft × 9.8 m/s2) = 2π√(291.1 m2/s2) = 2π√(291.1) s = 5.15 s
Part 4 of 4 - Calculate: Since the period of circular motion is the number of seconds per revolution, the rotation rate is equal to the inverse of the period. Thus, the rotation rate is:
Rotation rate = 1/T = 1/5.15 s = 0.74 rev/s
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A skier starts down a 10 degree incline at 2 m/s, reaching a speed of 15m/s at the bottom. What is the length of the incline?
How long does it take the skier to reach the bottom.
Answer:
-11.29 m
Explanation:
The length of the incline can be calculated using the following formula:
L = (Vf^2 - Vi^2) / (2 * a)
where:
L = length of incline
Vf = final speed (15 m/s)
Vi = initial speed (2 m/s)
a = acceleration due to gravity (9.8 m/s^2 on the surface of the Earth)
Since the skier is going downhill, the acceleration is negative.
Substituting the given values into the formula:
L = (15^2 - 2^2) / (2 * -9.8)
L = (225 - 4) / -19.6
L = 221 / -19.6
L = -11.29 m
So the length of the incline is approximately -11.29 meters. This negative value indicates that the skier's final position is lower than the starting position.
a tow rope pulls a skier directly behind a boat with a force of 25 N for a total of 20 meters. How much work has the rope done on the skier?
The amount of work done by the applied force on the skier is 500 J.
What is the amount of work done by the applied force?
The amount of work done by the applied force on the skier is calculated by applying the following equation as shown below.
W = Fd
where;
F is the applied forced is the displacement of the skierThe amount of work done by the applied force on the skier is calculated as;
W = (25 N ) x ( 20 m )
W = 500 J
Thus, the work done by a force is defined to be the product of component of the force in the direction of the displacement and the magnitude of this displacement.
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The motions described in each of the questions take place at an intersection on a two-lane road with a stop sign in each direction. For each motion, select the correct position versus time graph. For all of the motions, the stop sign is at the position x=0, and east is the positive x direction.
A) Motion 1: The car starts at rest at the stop sign, at x=0, and then accelerates in the east (positive x) direction.
What is accelerates?Acceleration is the rate of change of an object's velocity over time. It is a vector quantity, meaning that it has both magnitude and direction. Acceleration is usually measured in meters per second squared (m/s2). It is a fundamental concept in physics, and is used to describe the motion of objects in a variety of contexts, from astronomy to everyday life. Acceleration can result from a force, from a change in direction, or from a change in speed.
The correct position vs time graph for this motion is a line with a positive slope, starting at the origin and going up to the right. This shows that the car is accelerating in the positive x direction and is increasing its position over time.
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Which is NOT a function of the skeletal system?
Answer:produces red and white blood cells
Explanation: the bone marrow helps with the blood but cannot produce red and white blood cells
Answer:
"prevents movement of limbs and digits" is NOT a function of the skeletal system.
The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25 degree C. the pressure gage reads 210 kPa. If the volume of the tire it 0.025 m3 determine the pressure rise in 0k tire when the air temperature in the tire rises to 50 degree C. Also, determine the amount of air that must be bled off to restore pressure to its original value at this temperature. Assume the atmospheric pressure is 100 kPa
0.00455 moles of air must be released from the tire to restore the pressure to 210 kPa at 50 degrees C.
The pressure rise in a 0k tire when the air temperature rises from 25 degrees C to 50 degrees C can be calculated using the ideal gas law. The formula is
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature. In this case, the temperature is rising from 25 degrees C to 50 degrees C, so the pressure will increase with the temperature.
By plugging these values into the equation, we can calculate that the pressure increase is 45.5 kPa.
To restore the pressure to its original value of 210 kPa at 50 degrees C, we need to bleed off the amount of air equal to the pressure increase. This is equal to 45.5 kPa, or 0.00455 moles. This means that 0.00455 moles of air must be released from the tire to restore the pressure to 210 kPa at 50 degrees C.
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how to find resultant force and magnitude of charges in right angled triangle
To find the resultant force and magnitude of charges in a right-angled triangle, you need to use Pythagorean theorem and principles of electrostatics respectively.
What is resultant force in right angled triangle?
The magnitude of the charges can be determined using Coulomb's law, which states that the force between two charges is proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
To find the resultant force, you need to resolve each individual force into its x and y components and then add them up vectorially.
The magnitude of the resultant force can then be found using the Pythagorean theorem, which states that the magnitude of the resultant force is equal to the square root of the sum of the squares of its x and y components.
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0.50-kg cord is stretched between two supports, 7.3m apart. When one support is struck by a hammer, a transverse wave travels down the cord and reaches the other support in 0.72s . What is the tension in the cord?
The tension in the cord will be 6.99 N. To solve this problem we will refer to the laws of Mersenne. Mersenne's laws are regulations relating to the frequency of oscillation of a stretched string or monochord, helpful in musical tuning and musical instrument building.
This law suggests that the velocity in a string is directly proportional to the root of the applied tension and inversely proportional to the root of the linear density, that is,
v = √T/μ
Here,
v = Velocity
μ = Linear density ( mass per unit length)
T = Tension
Rearranging to find the Period we have that
T = v²μ
T = v²(m/L)
As we know that speed is equal to displacement in a unit of time, we will have to
T = (L/t)² (m/L)
T = (7.3/0.72)² (0.50/7.3)
T = 6.99 N
Therefore, the tension in the cord will be 6.99 N.
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four stars are listed below with their apparent magnitudes next to them: star a: 0.4 star b: 5.6 star c: 0.0 star d: 4.2 which of the following choices is the correct order from dimmest to brightest as these stars would appear in the sky?
The correct order from dimmest to brightest as these stars would appear in the sky is Star C (0.0), Star A (0.4), Star D (4.2), Star B (5.6).
Apparent magnitude is a measure of the star brightness as seen from the Earth. Lower magnitudes indicate brighter stars and higher magnitudes indicate dimmer stars.
In the case of the four stars listed, Star C has the lowest magnitude of 0.0, making it the brightest of the four. Star A is slightly dimmer with a magnitude of 0.4. Star D is dimmer still with a magnitude of 4.2, and Star B is the dimmest of the four with a magnitude of 5.6. It's important to note that this is just a relative comparison and does not necessarily indicate the true brightness of the stars, only how bright they appear from our perspective on Earth.
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Horsepower is defined as ______.
A. power applied over the distance of an English horserace track
B. the mechanical advantage gained by using a typical horse
C. the mass of a horse divided by the time it takes the horse to run 100 meters
D. a specific amount of power (550 ft-lb/s)
The definition of horsepower is . A. the amount of force used to cover the length of an English associated activities track B. the practical benefit of utilizing a standard horse
Who developed the horsepower?
James Watt, an engineer, is credited with creating the term horsepower. According to legend, Watt wanted to find a method to describe the power that one of those animals could produce while he was dealing with ponies in a coal mine. An engine is connected to a dynamometer in order to determine its horsepower.
What is the power of a horse?
The most prevalent unit of power is horsepower , which measures how quickly work is completed. According to the British Imperial Units, a horsepower is equivalent to 33,000 walking of work per minute, or the force required to elevate a mass of 3 million pounds one foot in a minute.
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A ball falls down from a cliff 0.86 meters in height, and lands 1.4 meters away from the bottom of the cliff. Find the velocity of which the ball left the cliff and the direction of the ball's velocity before it hit the ground.
Answer:
The velocity of the ball before it hit the ground was (3.59 m/s, -3.32 m/s) in the horizontal and vertical direction
Explanation:
The velocity of the ball can be calculated using the equation of motion:
v^2 = u^2 + 2as,
where
u = initial velocity,
v = final velocity,
a = acceleration due to gravity (9.8 m/s^2),
s = vertical height fallen (0.86 m).
Solving for u:
u = sqrt(v^2 - 2as)
We know the final velocity, v = 0 (the ball lands on the ground and stops), so
u = sqrt(2as) = sqrt(2 * 9.8 * 0.86) = 3.32 m/s.
The direction of the velocity before it hit the ground can be determined using horizontal distance traveled and time of flight.
The time of flight, t, can be found using:
t = sqrt(2s/a) = sqrt(2 * 0.86 / 9.8) = 0.39 s.
The horizontal velocity, vx, can be found using:
vx = d / t = 1.4 / 0.39 = 3.59 m/s.
A star of mass 5 × 10^30 kg is located at ‹ 8 × 10^12, 5 × 10^12, 0 › m. A planet of mass 6 × 10^24 kg is located at ‹ 5 × 10^12, 8 × 10^12, 0 › m and is moving with a velocity of ‹ 0.5 × 10^4, 1.5 × 10^4, 0 › m/s. During a time interval of 1×10^6 seconds, what is the change in the planet's velocity (Vf - Vi)?
The change in the velocity of the planet is 18.55 m/s.
What is the change in the planets velocity?
The gravitational force between the star and the planet, is calculated by applying Newton's third law of motion.
F = Gm₁m₂ /r²
where;
r is the distance between the star and the planet\m₁ is the mass of the starm₂ is the mass of the planetThe distance between the start and the planet is calculated as;
r = √ ( 8 x 10¹² - 5 x 10¹² )² + ( 5 x 10¹² - 8 x 10¹² )²
r = 4.24 x 10¹² m
F = ( 6.67 x 10⁻¹¹ x 5 x 10³⁰ x 6 x 10²⁴ ) / ( 4.24 x 10¹² )²
F = 1.11 x 10²⁰ N
The acceleration of the planet is calculated as;
a = F / m₂
a = ( 1.11 x 10²⁰ N ) / ( 6 x 10²⁴ kg )
a = 1.85 x 10⁻⁵ m/s²
The change in the velocity of the planet;
Δv = at
Δv = ( 1.85 x 10⁻⁵ x 1 x 10⁶ s )
Δv = 18.55 m/s
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Transverse waves on a string have wave speed 12m/s, amplitude 0.05m and wavelength 0.4m. The waves travel in the positive x direction, and at t=0 the x = 0 end of the string has zero displacement and is moving upward.
(a) Find the frequency, period and wave number of these waves
(b)Write a wave function describing the wave
(c) Find the transverse displacement of a wave at x=0.25 at time t -0.15sec
(d) How much time must elapse from the instant in part "(c)" until the point at x = 0.25m has zero displacement
Two ice skaters stand together as illustrated in Figure (a) below. They "push off" and travel directly away from each other, the boy with a velocity of v = 0.540 m/s to the left. If the boy weighs 747 N and the girl weighs 497 N, what is the girl's velocity (in m/s) after they push off? (Consider the ice to be frictionless.)
the girl's velocity after they push off is 0.816 m/s.
What is velocity?Velocity is described as the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.
The momentum of the boy after he pushes off is given by m_boy * v_boy = -747 N * 0.540 m/s = -405.08 N * m/s.
The momentum of the girl after she pushes off is denoted as m_girl * v_girl, where m_girl is the mass of the girl and v_girl is her velocity.
The principle of conservation of momentum requires that the total momentum of the two-person system before and after the push off must be the same, hence we have:
m_boy * v_boy + m_girl * v_girl = 0
Substituting in the values for m_boy and v_boy, we find:
-405.08 N * m/s + m_girl * v_girl = 0
Solving for v_girl, we find:
v_girl = 405.08 N * m/s / m_girl = 405.08 N * m/s / 497 N = 0.816 m/s.
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A 2.2 × 103 kg car accelerates from rest under the action of two forces. One is a forward force of 1143 N provided by traction between the wheels and the road. The other is a 909 N. Calculate the kinetic energy K of the mass as it reaches 7 m. Answer in units of J.
When the car reaches 7 m it has a kinetic energy of 14364 J and a terminal velocity of 4.67 m/s.
What is speed?Speed defines the direction in which a body or object is moving. Speed is primarily a scalar quantity. Velocity is basically a vector quantity. Rate of change of distance. Rate of change of displacement.
What is velocity and its SI units?(a) The rate of change of displacement is known as velocity. It can be calculated by finding the ratio of displacement and total required time. The SI unit for velocity is "m/s", just like velocity.
The work done by the forward force is:
W1 = F1d = 1143 N × 7 m = 8001 J The work done by the second force is:
W2 = F2d = 909 N x 7 m = 6363 J The net work done on the car is the sum of the following he two works.
[tex]\mathrm{W_{net}}[/tex] = W1 + W2 = 8001 J + 6363 J = 14364 J According to the work energy principle, the net work done in a car is equal to the change in its kinetic energy.
[tex]\mathrm{W_{net}}[/tex] = ΔK where ΔK is the change in kinetic energy. Since the car starts from a standing start, the initial kinetic energy is 0, so ΔK equals the final kinetic energy. So it looks like this:
[tex]\mathrm{W_{net}}[/tex] = 14364 J Finally, we can convert this energy to Joules using the following formula:
1 J = 1 kg m²/s²
So it looks like this:
K = 14364 J = (2.2 × 10³ kg) × v² where v is the final velocity of the car. Solving for v gives:
v = √(K / (2.2 × 10³ kg))
= √(14364 J / (2.2 × 10³ kg))
= 4.67 m/s
So when the car reaches 7 m it has a kinetic energy of 14364 J and a terminal velocity of 4.67 m/s.
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Using Thomson's ___________ and Millikan's _____, the _____ of an ________ was determined.
Using Thomson's cathode ray tube and Millikan's oil drop experiment, the charge of an electron was determined.
Thomson's cathode ray tube and Millikan's oil drop experiment were two important experiments in the history of physics. Thomson used his cathode ray tube to observe the behavior of electrons, while Millikan used his oil drop experiment to measure the charge of an electron. By combining the results of these two experiments, scientists were able to determine the charge of an electron, which is a fundamental unit of electrical charge in the study of electricity and electromagnetism.
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If the net force on a baseball with a mass of 0.145 kg is 18.9 N, then was is the resulting acceleration?
Answer:
130.34 m/s²
Explanation:
see attachment
hope this helps!
A mass on a string of unknown length oscillates as a pendulum with a period of 3.3 s. What is the period if a. The mass is doubled?b. The string length is doubled?c. The string length is halved?d. The amplitude is doubled?
a. The mass is doubled = 4 s
b. The string length is doubled= 5.66 s
c. The string length is halved=2.83 s
d.The amplitude is doubled= 4 s
How to calculate period of pendulum(a) The period of the pendulum is independent of the mass, therefore, the period when the mass is doubled is
T= To =4.00s
(b) Let I be the new length of the pendulum and Lo be the original length of the pendulum. The period of the pendulum if the string length is doubled is found by substituting 2Lo for L in Equation (*):
2π=√2Lo/g
√2=(2π(√Lo/g)
where the term in parenthesis is the original period of the pendulum To:
T=√√2To
T=√2.(4seconds)
T=5.66 s
c) The period of the pendulum if the string length is halved is found by substituting Lo/2 for L in Equation (*):
T=2π(√Lo/2 :g)
T= 1/√2 (2π√(Lo/g)
where the term in parenthesis is the original period of the pendulum To:
T =To /√2
T=4.00s/√2
T=2.83 s
d.) The period of the pendulum is independent of the amplitude, therefore, the period when the amplitude is halved is
T= To 4.00s
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A sphere and a cylinder of equal mass and radius are simultaneously released from rest on the same inclined plane and roll without sliding down the incline. Then: A. the sphere reaches the bottom first because it has the greater inertia B. the cylinder reaches the bottom first because it picks up more rotational energy C. the sphere reaches the bottom first because it picks up more rotational energy D. they reach the bottom together E. none of the above are true
The correct option for the problem is option D. they reach the bottom together. Their gravitational potential energy is converted to kinetic energy, total energy will be conserved for the system and we can safely say they will reach the bottom together without considering their shape.
Here sphere and cylinder both have equal mass and equal radius and it is given that both are simultaneously released also.
When two objects with equal mass and equal radius like these two, the time taken for them to roll down and reach the bottom will be their gravitational potential energy.
Here what happens is that their gravitational potential energy is converted to kinetic-energy and both of them rolling down the incline.
Total energy will be conserved for the system and we can safely say they will reach the bottom together without considering their shape.
Inertia and rotational energy are also there in this context for their motion but they do not take part any role for the time taken to slide down.
Instead, they affect the stability and trajectory of the objects as they roll down the incline.
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Calculate the frequency in hertz of electromagnetic radiation that has a wavelength of 536.0 nm. (c = 3.00 X 10⁸ m/s)
The frequency of electromagnetic radiation with a wavelength of 536.0 nm is 5.6 x 10¹¹ Hz.
What is electromagnetic radiation?Electromagnetic radiation is a form of energy that consists of waves of electric and magnetic fields, travelling through the air or other substances at the speed of light. These waves are created when an electric charge is accelerated and can be generated from a variety of sources, such as a light bulb, the sun, a microwave oven, or a radio transmitter.
The frequency (f) of electromagnetic radiation is calculated using the equation:
f = c/λ
where c is the speed of light (3.00 x 10⁸ m/s) and λ is the wavelength of the radiation (536.0 nm).
Therefore, we can calculate the frequency (f) as follows:
f = (3.00 x 10⁸ m/s) / (536.0 nm)
First, we need to convert the wavelength from nanometers (nm) to meters (m). We can do this by dividing 536.0 nm by 1,000,000 to get 0.000536 m.
Therefore, we can calculate the frequency (f) as follows:
f = (3.00 x 10⁸ m/s) / (0.000536 m)
f = 5.6 x 10¹¹ Hz
The frequency of electromagnetic radiation with a wavelength of 536.0 nm is 5.6 x 10¹¹ Hz.
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A 5.00g bullet is fired horizontally into a 1.20kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between the block and surface is .20. The bullet remains embedded in the block, which is observed to slide .31m along the surface before stopping. What was the initial speed of the bullet?
the initial speed of the bullet as it was fired horizontally into the wooden block resting on a horizontal surface is 265m/s.
What is the law of conservation of momentum?A conservation law states that the total linear momentum of a closed system remains constant through time, regardless of other possible changes within the system.
Given, A 5.00g bullet is fired horizontally into a 1.20kg wooden block resting on a horizontal surface.
In our case,
Mass of bullet = 5 gram = 0.005 kg
Mass of wooden block = 1.2 kg
the initial velocity of block = 0
Kinetic friction = 0.20
First, we get the velocity of the Wood.
From Conservation of Energy:
1/2m v² = μ mgs
v = √(2 μgs)
Where v is the velocity of the block,
μ is the coefficient of kinetic friction,
s is the displacement of the bullet
g is the acceleration due to gravity (9.81)
v = √(2 *0.2*9.81 * 0.31)
v = 1.1 m/s
so, the velocity of the wooden block after the collision will be 1.10 m/s
Now, we determine the velocity of the bullet. Using Conservation of Momentum.
m₁v₁ + m₂v₂ = MV
0.005 *v + 0 = (1.20 + 0.005) * 1.1
v = 1.325/0.005
v = 265 m/s
Therefore, the initial speed of the bullet as it was fired horizontally into the wooden block resting on a horizontal surface is 265m/s.
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Felipe is riding his skateboard toward Lilah at 15 km/h. He throws a football to Lilah. The football is thrown at 8 km/h.
The velocity of the football that is thrown by Felipe to Lilah will be 23 km per hour.
What is the relative velocity?The movement of an object in relation to another observer is known as its relative velocity. It is the pace at which one object's relative location changes in relation to another object over time.
Felipe is riding his skateboard toward Lilah at 15 km/h. He throws a football to Lilah. The football is thrown at 8 km/h.
Then the velocity of the ball is given as,
v = 15 + 8
v = 23 km/h
The velocity of the ball will be 23 km / h.
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