Expand and combine like terms.

(4b^2+3)(4b^2-3)

Answer:

16b^4-9

Step-by-step explanation:

Factoring gives us 16b^4+12b^2-12^2-9. Simplifying gives us the answer which is 16b^4-9

Answer:

[tex]16b^4-9[/tex]

Step-by-step explanation:

When multiplying binomials, we can use a method called FOIL (First-Outside-Inside-Last).

For [tex](t_1+t_2)(t_3+t_4)[/tex], let:

[tex]t_1\implies \text{First Term},\\t_2\implies \text{Second Term},\\t_3\implies \text{Third Term},\\t_4\implies \text{Fourth Term}[/tex]

In the FOIL method, the steps go:

[tex]\text{\textbf{F}irst: Multiply the first and third terms (first term of each binomial)},\\\text{\textbf{O}utside: Multiply the first and fourth terms},\\\text{\textbf{I}nside: Multiply the second and third terms},\\\text{\textbf{L}ast: Multiply the second and fourth terms (last term of each binomial) }[/tex]

Given [tex](4b^2+3)(4b^2-3)[/tex], we have:

[tex]\text{First: }4b^2\cdot 4b^2,\\\text{Outside: }4b^2\cdot -3,\\\text{Inside: }3\cdot 4b^2,\\\text{Last: }3\cdot -3,\\\rightarrow 16b^4-12b^2+12b^2-9[/tex]

Combine like terms:

[tex]\boxed{16b^4-9}[/tex]

can someone help me with this question? i’ll mark as brainliest if correct! thanks

Can someone help me with this question? I’ll mark as brainliest if correct!

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