Examine the figure. What is the measure of angle a?

Answer:

9/4

Step-by-step explanation:

Answer:

9/2.25 = 4

Step-by-step explanation:

9/x = 4

x = 9/4 or 2.25

The equation has the same solution as w / 3.9 = 3 is w+0.6=1.9

Given:

w / 3.9 = 3

cross multiply

w × 3 = 3.9

3w = 3.9

divide both sides by 3

w = 3.9 / 3

w = 1.3

Check all that applies

A. w+0.6=1.9

w = 1.9 - 0.6

w = 1.3

B. w-0.6 = 11.1

w = 11.1 + 0.6

w = 11.7

C. w+1.03=2.93

w = 2.93 - 1.03

w = 1.9

D. w-1.03=8.24

w = 8.24 + 1.03

w = 9.27

Therefore, the equation has the same solution as w / 3.9 = 3 is w+0.6=1.9

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Answer:

so where does that line intersect the y axis? just plug in x=0 and you see y= -1. so (0, -1)

y = -x -1 is parallel because it has the same slope and goes through the right point

Answer:

rthrthrt

Step-by-step explanation:

Answer:

6.78

Step-by-step explanation:

Answer:

6.78 pounds

Step-by-step explanation:

Add: 3.18+1.35+2.25=6.78

(If you wanted the cost for the whole thing then you need to include the price for each of the pounds)

Answer:

28ft tall

Step-by-step explanation:

Since they are proportional, you can set up a ratio of length to width.

L/W=L/W

42/54=L/36

L=(42*36)/54

L=28

Answer:it's a for sure I think

The measure of the exterior angle at vertex D is: D. 54°

Recall:

Thus:

In ΔDEF, (8x−2)º is an exterior angle at vertex D.

m∠E = (3x−8)° (interior angle)

m∠F = (4x+13)° (interior angle)

Therefore:

(8x−2)º = (3x−8)° + (4x+13)°

8x - 2 = 3x - 8 + 4x + 13

8x - 2 = 7x + 5

8x - 7x = 2 + 5

x = 7

Exterior angle at vertex D = (8x−2)º

= 8(7) - 2

= 54º (option D)

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The point-slope equation of the line as described by the points is; y + 5 = -4(x - 2).

The equation of the line given in the task content in the point-slope form can be determined as follows;

Slope = (-5-3)/(2-0) = -8/2 = -4.

Hence, it follows that point-slope form of the equation of the line is; Choice A; A. y + 5 = -4(x - 2).

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Answer:

Width=6 5/6cm and Length=13 2/3cm

Step-by-step explanation:

Lets have width=x

Therefore, 4x+2x=41cm

6x=41cm

x=41/6=6 5/6

the width is 6 5/6 cm and length 41/3=13 2/3

Answer:

$85.50

Step-by-step explanation:

57 x 1.5 = 85.5

Answer:

  SAS similarity

Step-by-step explanation:

You have two side ratios and the angle between the sides with those ratios. The appropriate similarity theorem is SAS.

Answer:

Step-by-step explanation:

The total they want to raise is $2,400 if that is what you're asking?

Answer:

Step-by-step explanation:

The angles 1 and 2 are marked as congruent

If a ≅ b, then b ≅ a, this is called the symmetric property of congruence:

Correct choice is B

Answer:

Symmetric property of similarity

Step-by-step explanation:

Answer:

Step-by-step explanation:

$92.43 / 0.74 = $124.91

The total bill is equal to $124.9

A percentage is a number or ratio that can be expressed as a fraction of 100. If we have to calculate the percent of a number, divide the number by the whole and multiply by 100. Hence, the percentage means, a part per hundred. The word percent means per 100. It is represented by the symbol “%”

Given here, the given bill as 74% of the total bill as $92.43

Thus the total bill must be = 92.43×100/74

                                            = $124.9

Hence, The total bill is equal to $124.9

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Answer:

Yes Jeff is the correct answer

Step-by-step explanation:

Answer:

5/9

Step-by-step explanation:

Answer: bro I don’t if this is correct but try 11+3i

Answer:

first let's solve for x

x + (x + 30) + 2x = 180

4x + 30 = 180

-30          -30

4x = 150

/4      /4

x = 37.5

Now solve for the angle measures:

(x + 30)    =    (37.5 + 30) = 67.5

2x       =        2(37.5) = 75

x = 37.5

Answer:

X= 37.5

Step-by-step explanation:

Answer:

559

Step-by-step explanation:

Answer:

[tex]Fourth \: option: y^2=9^2+19^2-2(9)(19) cos(41°)[/tex]

[tex]The \: law \: of \: cosines \: to \: solve \: for \: one \: side  \: is:[/tex]

[tex]c^2=a^2+b^2-2ab \: cos \: C[/tex]

We must know the other two sides (a and b) and the angle between these sides (angle C, the opposite to the side that we want to determine)

In this case c=y, a=9, b=19, and C=41°, then:

[tex]y^2=9^2+19^2-2(9)(19) \: cos \: (41°)[/tex]

Answer:

  a.  39 ft²

  c. 2x² +11x +12

  e. 35 yd²

Step-by-step explanation:

The missing vertical dimension is 5-3 = 2'. The missing horizontal dimension is 11-8 = 3'. Then the figure can be decomposed into a rectangle 11'×3' and one that is 3'×2'. The sum of those areas is ...

  total area = (11 ft)(3 ft) +(3 ft)(2 f) = (3 ft)(11 +2 ft) = (3 ft)(13 ft) = 39 ft²

__

We don't know what to make of the rectangles in each corner, so we'll assume they are distorted right-angle indicators. The area is the product of the dimensions shown:

  A = LW

  A = (2x +3)(x +4) = 2x² +11x +12 . . . area of figure

__

The shaded area is half the area of the rectangle. That is the same area you get if you use the triangle formula for the area of the shaded triangle.

  A = 1/2(14 yd)(5 yd) = 35 yd²

Answer:

y=25x+1150

Step-by-step explanation:

1425-1275=150

150/6=25 so 25 dollars per month

1275-5(25)

1275-125=1150

y=25x+1150

[tex](\stackrel{x_1}{6}~,~\stackrel{y_1}{3})~\hspace{10em} \stackrel{slope}{m}\implies 7 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{7}(x-\stackrel{x_1}{6}) \\\\\\ y-3=7x-42\implies y = 7x-39[/tex]

Answer:

[tex]y-3=7(x-6)[/tex]

Step-by-step explanation:

We are given that a line has a slope (m) of 7 and passes through the point (6,3).

We want to write the equation of this line.

There are three ways to do it:

As the question doesn't specify, either form should work, but let's write the equation in point-slope form as that's the easiest to do.

As we are already given both the point and the slope, we can plug them both into the equation.

Starting with the slope, substitute 7 for m.

[tex]y-y_1=7(x-x_1)[/tex]

Now, substitute 6 as [tex]x_1[/tex] and 3 as [tex]y_1[/tex].

[tex]y-3=7(x-6)[/tex]

Check the picture below.

there are a few angles shaded, I'll call that angle at O ∡O, and that angle at "x" ∡x and the green angle at A, ∡A, and the angle at B, ∡B, just so you know which angle we're referring to.

well, first off let's notice that B and C are points of tangency, meaning we get right-angles as you see in the picture, if we run an angle bisector from ∡x, towards point O, we get two congruent triangles, lemme shorten that up some, 90 + 90 + ∡O +∡x = 360, which means that ∡O + ∡x = 180,  meaning that ∡O = 180 - ∡x, if that's so, the angle at point O across the shade, is 360 - ∡O or 360 - (180 - ∡x).

alrighty, by the inscribed angle theorem, ∡A is half of ∡O.

let's now focus on the triangle AOB, we'll be using half of ∡A and half of ∡O and ∡B on that triangle, let's proceed.

[tex]\measuredangle x + \measuredangle O=180\implies \measuredangle O=180-\measuredangle x \\\\\\ \measuredangle A = \cfrac{\measuredangle O}{2}\implies \measuredangle A = \cfrac{180-\measuredangle x}{2} \\\\\\ \stackrel{\textit{the angle across from }\measuredangle O~is}{360-\measuredangle O}\implies 360-(180 - \measuredangle x)\implies 180+\measuredangle x \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{\large the sum of all three angles at }\triangle AOB}{\stackrel{\textit{half of }\measuredangle A}{\cfrac{1}{2}\cdot \cfrac{180-\measuredangle x}{2}}~~ + ~~\stackrel{\textit{half the angle across from }\measuredangle O}{\cfrac{180+\measuredangle x}{2}}~~ +~~\measuredangle B~~ =~~180} \\\\\\ \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B = 180[/tex]

now, let's multiply both sides by the LCD of all denominators, hmmmm in this case that'll be 4, so multiplying both sides by the LCD will do away with the denominators, so let's do so.

[tex]4\left( \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B \right) = 4(180) \\\\\\ (180-\measuredangle x)+2(180+\measuredangle x)+4\measuredangle B = 720 \\\\\\ (180-\measuredangle x)+(360+2\measuredangle x)+4\measuredangle B = 720\implies 540+\measuredangle x+4\measuredangle B = 720[/tex]

[tex]\measuredangle x+4\measuredangle B = 180\implies 4\measuredangle B = 180-\measuredangle x\implies \measuredangle B = \cfrac{180-\measuredangle x}{4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \measuredangle B = 45 - \cfrac{\measuredangle x}{4}~\hfill[/tex]

Answer:

[tex]\sqrt{242}[/tex]

Answer: He has 91, to figure this out count everything in top row which is 13 and then count everything in left row only which is 7 and 13 x 7 is 91

Step-by-step explanation: