Evaluate the line integral ∫CF⋅dr, where F(x,y,z)=−xi−2yj−zk and C is given by the vector function r(t)=⟨sint,cost,t⟩, 0≤t≤3π/2.

Answers

Answer 1

Answer:

[tex]\mathbf { \int _ c Fdr= - \dfrac{9 \pi ^2}{8} - \dfrac{3}{2} }[/tex]

Step-by-step explanation:

GIven that:

[tex]r(t) = (sin \ t, cos \ t, t)[/tex]

[tex]r' (t) = (cos \ t, -sin \ \ t, 1)[/tex]

[tex]F(x, y, z) = ( -x, -2y , - z)[/tex]

[tex]F(r(t)) = ( sin \ t , - 2 cos \ t, - 1 t)[/tex]

[tex]F(r(t)) \times r'(t) = (sin \ t, - 2 \ cos \ t , -1 \ t)( cos \ t , - sin \ t , 1 )[/tex]

[tex]= sin t \ cos t + 2 \ sin t \ cos t - 1t[/tex]

[tex]= 3sint \ cost - 1 t[/tex]

[tex]\int _ c Fdr = \int ^b_a f(r(t)) \times r'(t) \ dt[/tex]

[tex]= \int^{3 \pi/2}_0 \ [3 sin \ t \ cos \ t - 1 \ t ] \ dt[/tex]

[tex]= 3 \int ^{3 \pi/2} _0 \ cos \ t ( sin \ t \ dt ) - 1 \int ^{3 \pi/2}_0 \ (t) \ dt[/tex]

Let   cos t = u   &

sint  dt = du

[tex]= 3 \int ^{3 \pi/2_} } _0 \ udu - 1 \int ^{3 \pi/2}_0 \ (t) \ dt[/tex]

[tex]= 3 [ \dfrac{u^2}{2}]^{3 \pi/2}_0 - 1 [ \dfrac{t^2}{2}]^{3 \pi/2}_0[/tex]

[tex]= \dfrac{3}{2} [ cos ^2 \ t ] ^{3 \pi/2} _0- \dfrac{1}{2} ( \dfrac{ 3 \pi }{2 })^2 - 0^2[/tex]

[tex]= \dfrac{3}{2} [ cos ^2 \ \dfrac{3 \pi}{2} - cos ^2 \ 0 ] - \dfrac{1}{2}( \dfrac{9 \pi^2}{4})[/tex]

[tex]= \dfrac{3}{2} ( 0 -1 ) - \dfrac{9 \pi^2}{8}[/tex]

[tex]= - \dfrac{3}{2} - \dfrac{9 \pi ^2}{8}[/tex]

[tex]\mathbf { \int _ c Fdr= - \dfrac{9 \pi ^2}{8} - \dfrac{3}{2} }[/tex]

Answer 2

To answer this question, we apply:

∫CF×dr = ∫ c F (r(t)) × dr

Solution is:

( 1/2)  - (9/8)×π

We know  r(t) =  sint i + cost j + t k

Then  dr = ( cost i - sint j + k ) dt

And  F ( x , y , z ) = -x i - 2y j - z k

Then  F ( r(t)) =  - sint i - 2 × cost j - t × k

And F ( r(t)) × dr  = (- sint×cost + 2 ×sint ×cost - t ) dt

F (r(t)) × dr = ∫ (- sint×cost + 2 ×sint ×cost - t ) dt  

Integration limits 0≤  t  ≤ ( 3/2 ) π

(- sint×cost + 2 ×sint ×cost - t ) dt  = ∫ ( sint ×cost - t ) dt

∫ sint ×cost × dt  - ∫ t ×  dt

F (r(t)) × dr = (1/2) sin²t  - ( 1/2) × t² | 0  y  (3/2) π

F (r(t)) × dr = (1/2)× ( -1)² - 0 - ( 9/8 ) × π - 0

F (r(t)) × dr = ( 1/2)  - (9/8)×π

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Related Questions

The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard deviation of 2.2 minutes. Find the probability that a call a. lasts between 5 and 10 minutes. b. lasts more than 7 minutes. c. lasts less than 4 minutes.

Answers

Answer: a. 0.6759    b. 0.3752    c. 0.1480

Step-by-step explanation:

Given : The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard deviation of 2.2 minutes

i.e. [tex]\mu = 6.3[/tex] minutes

[tex]\sigma=2.2[/tex] minutes

Let x be the long-distance call length.

a. The probability that a call lasts between 5 and 10 minutes will be :-

[tex]P(5<X<10)=P(\dfrac{5-6.3}{2.2}<\dfrac{X-\mu}{\sigma}>\dfrac{10-6.3}{2.2})\\\\=P(-0.59<Z<1.68)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=P(z<1.68)-(1-P(z<0.59))\\\\=0.9535-(1-0.7224)\ \ \ \ [\text{by z-table}]\\\\=0.6759[/tex]

b. The probability that a call lasts more than 7 minutes. :

[tex]P(X>7)=P(\dfrac{X-\mu}{\sigma}>\dfrac{7-6.3}{2.2})\\\\=P(Z>0.318)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z<0.318)\\\\=1-0.6248\ \ \ \ [\text{by z-table}]\\\\=0.3752[/tex]

c. The probability that a call lasts more than 4 minutes. :

[tex]P(X<4)=P(\dfrac{X-\mu}{\sigma}<\dfrac{4-6.3}{2.2})\\\\=P(Z<-1.045)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z<1.045)\\\\=1-0.8520 \ \ \ [\text{by z-table}]\\\\=0.1480[/tex]

Solve the system algebraically.
3x - 2y - 1 = 0 y = 5x + 4

What is the solution?

A:{(-9/7,-17/7)}
B:{(9/7.17/7)}
C:{(9/7,-17-7)}

Answers

Answer:

A:{(-9/7,-17/7)}

Step-by-step explanation:

3x - 2y - 1 = 0    ⇒  3x - 2y = 1

y = 5x + 4

then:

3x - 2(5x+4) = 1

3x - 2*5x - 2*4 = 1

3x - 10x - 8 = 1

-7x = 1 + 8

7x = 9

x = -9/7

y = 5x + 4

y = 5(-9/7) + 4

y = -45/7 + 4

y = -45/7 + 28/7

y = -17/7

Answer:

A:{(-9/7, -17/7)}

What's the answer to this question I need help I don't understand it

Answers

Greetings from Brasil...

Making the division

(X⁵ + 2X⁴ - 7X² - 19X + 15) ÷ (X² + 2X + 5)

we get

X³ - 5X + 3

Answer:

x³ − 5x + 3

Step-by-step explanation:

To solve with long division:

Start by dividing the highest terms:

x⁵ / x² = x³

This becomes the first term of the quotient.  Multiply by the divisor:

x³ (x² + 2x + 5) = x⁵ + 2x⁴ + 5x³

Subtract from the first three terms of dividend:

(x⁵ + 2x⁴ + 0x³) − (x⁵ + 2x⁴ + 5x³) = -5x³

Drop down the next two terms and repeat the process.

To use the "box" method:

Each square in the box is the product of the term at the top of the column and the term at the end of the row.  Also, squares diagonal of each other must add up to the term outside the box.

Look at the first diagonal.  There is only one square, so that must be x⁵.  Knowing this, we can say that x³ must be at the top of the column.  We can fill in the rest of the column (2x⁴ and 5x³).

Repeat this process until all squares are filled in.

Find the mode. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice. A. The​ mode(s) is(are) nothing. ​(Type an integer or a decimal. Do not round. Use a comma to separate answers as​ needed.) B. There is no mode.

Answers

Answer:

The question is not complete, but I found a possible match:

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below are the jersey numbers of 11 players randomly selected from the roster of a championship sports team. What do the results tell us?

86 4 85 83 9 51 24 34 28 43

Find the mode. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice.

A. The​ mode(s) is(are) nothing. ​(Type an integer or a decimal. Do not round. Use a comma to separate answers as​ needed.)

B. There is no mode.

Answer:

The correct answer is:

There is no mode (B.)

Step-by-step explanation:

b. The mode of data is the number that repeats the most number of times. The number that occurs most frequently. on the list of the distribution, 86 4 8 5 83 9 51 24 34 28 43, every number occurs just once, hence, there is no mode for the distribution.

a. To calculate the Mean

[tex]Mean: \frac{Sum\ of\ terms}{number\ of\ players}\\ Mean = \frac{86\ +\ 4\ +\ 8\ +\ 5\ +\ 83\ +\ 9\ +\ 51\ +\ 24\ +\ 34\ +\ 28\ +\ 43}{11}\\Mean= 34.09[/tex]

c. To calculate the median:

Median is  the mid-way term of the distribution, but first, we have to arrange the terms in ascending order (descending order can also be used)

4, 5, 8, 9, 24, 28, 34, 43, 51, 63, 86

To find the median, count the numbers equally from the left- and right-hand sides to the middle, the remaining number becomes the median. In this case, the median = 28

d. Midrange:

The midrange is the number mid-way between the greatest and smallest number in a data set. To find the midrange, we will add the smallest (4) and largest number (86), and divide by 2:

Midrange = (4 + 86) ÷ 2

Midrange = 90 ÷ 2 = 45

e. what do the results tell us:

Since only 11 of the jersey numbers were in the sample, the statistics cannot give any meaningful results

Eddie treated his sister to lunch while visiting her in Manchester, Their lunch cost $20, and the
sales tax in Manchester is 15%, If Eddie left a 15% tip on the $20, how much in total did he pay?
Sul

Answers

Answer:

Eddie spent $26 total

Step-by-step explanation:

15% of 20 is 3

He paid 15% tax which is $3

He also tipped 15% of the $20 which he paid for lunch so another $3

3+3+20= $26

Solve the equation V2 + 4 + 12 = 3-
a.
330
-733
d. 753
b. -776
Please select the best answer from the choices provided

Answers

Answer:

d

Step-by-step explanation:

trust

Answer:

x = -733

Step-by-step explanation:

[tex]\sqrt[3]{x+4}[/tex] + 12 = 3

[tex]\sqrt[3]{x+4}[/tex]  = -9 (cube both sides)

x + 4 = -729

x = -733

1. Brandon has $12. He will eam $8 for every
hour he works. He would like to have $52 at
the end of the day. Let h represent the
number of hours Brandon works.
Equation:
Solve it to find how many hours he needs

Answers

Answer:52-12=$40

1/8*40 = 5 hours.

Step-by-step explanation:

A newsletter publisher believes that above 41A% of their readers own a personal computer. Is there sufficient evidence at the 0.100.10 level to substantiate the publisher's claim?

Answers

Complete Question

A newsletter publisher believes that above 41% of their readers own a personal computer. Is there sufficient evidence at the 0.10 level to substantiate the publisher's claim?

State the null and alternative hypotheses for the above scenario.

Answer:

The null hypothesis is  [tex]H_o : p \le 0.41[/tex]

The  alternative hypothesis  [tex]H_1 : p> 0.41[/tex]

Step-by-step explanation:

From the question we are told that

      The population proportion is [tex]p = 0.41[/tex]

        The level of significance is  [tex]\alpha = 0.10[/tex]

The null hypothesis is  [tex]H_o : p \le 0.41[/tex]

The  alternative hypothesis  [tex]H_1 : p> 0.41[/tex]

         

When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation
PV^1.4=C
where C is a constant. Suppose that at a certain instant the volume is 610 cubic centimeters and the pressure is 89 kPa and is decreasing at a rate of 10 kPa/minute. At what rate in cubic centimeters per minute is the volume increasing at this instant?

Answers

Answer:

48.96 cm³/min

Step-by-step explanation:

We are given;

Relationship between pressure P and volume V; PV^(1.4) = C

Volume;V = 610 m³

Pressure; P = 89 KPa

Rate of decreasing pressure; dP/dt = -10 kPa/minute.

We want to find the rate at which the volume is increasing at that instance, thus, its means we need to find dV/dt

So, we will differentiate the relationship equation of P and V given.

Thus, we have;

[V^(1.4)(dP/dt)] + d(V^(1.4))/dt = dC/dt

Differentiating this gives us;

[(dP/dt) × (V^(1.4))] + [1.4 × P × V^(0.4) × (dV/dt)] = 0

Plugging in the relevant values, we have;

(-10 × 610^(1.4)) + (1.4 × 89 × 610^(0.4) × (dV/dt)) = 0

This gives;

-79334.44155 + 1620.5035(dV/dt) = 0

Rearranging, we have;

1620.5035(dV/dt) = 79334.44155

Divide both sides by 1620.5035 to give;

dV/dt = 79334.44155/1620.5035

dV/dt = 48.96 cm³/min

Given A = {a, b, c, d} and B = {1, 2, 3, 4} , sets A and B can be defined as? Question 2 options: equal sets equivalent sets equal and equivalent sets neither equal or equivalent sets

Answers

Answer:

equal and equivalent sets

Step-by-step explanation:

Where does the graph of the line 3x – 4y = 12 intersect the y-axis?
A. (4,0)
B. (-4, 0)
C. (0, 3)
D. (0, -3)

Answers

The answer is D-(0,-3)

Answer

[0,-3] should be the right answer

The line should intersect at y axis i.e x=0

Then put the value of x as zero in the equation to find the value of y.

3*0-4y=12

-4y=12

y=12/-4=-3

y=-3 ..

HOPE THIS HELPS YOU

4.72x10^10 Please I need help fast

Answers

Answer:

The answer is 47200000000

Use technology and a​ t-test to test the claim about the population mean at the given level of significance using the given sample statistics. Assume the population is normally distributed. ​Claim: ​;     Sample​ statistics: ​, s​, n What are the null and alternative​ hypotheses? Choose the correct answer below. A. H0​: HA​: B. H0​: HA​: C. H0​: HA​: D. H0​: HA​:

Answers

Complete question is;

Use technology and a t-test to test the claim about the population mean μ at the given level of significance α using the given sample statistics. Assume the population is normally distributed.

Claim: μ > 71; α = 0.05

Sample statistics:

¯x = 73.9, s = 3.7, n = 25

A) What are the null and alternative hypotheses?

Choose the correct answer below.

A. H0:μ = 71 ; HA:μ ≠ 71

B. H0:μ ≤ 71; HA:μ > 71

C. H0: μ ≥ 71; HA: μ < 71

D. H0: μ ≠ 71; HA: μ = 71

B) What is the value of the standardized test statistic? The standardized test statistic is (Round to two decimal places as needed.)

C) What is the P-value of the test statistic? P-value = Round to three decimal places as needed.)

D) Decide whether to reject or fail to reject the null hypothesis.

Answer:

A) Option B - Alternative hypothesis: HA: μ > 71

Null hypothesis: H0: μ ≤ 71

B) t = -7.54

C) p-value = 0.000

D) we reject the null hypothesis

Step-by-step explanation:

A) We are told that the claim is: μ > 71. Thus, due to the sign, the alternative hypothesis would be the claim. So;

Alternative hypothesis: HA: μ > 71

Null hypothesis: H0: μ ≤ 71

B)Formula for standardized test statistic with a t-test is;

t = (¯x - μ)/√(s/n)

Plugging in the relevant values, we have;

t = (71 - 73.9)/√(3.7/25)

t = -7.54

C) From online p-value from t-score calculator attached using t = -7.54, n = 25, significance level = 0.05, DF = 25 - 1 = 24 and a one - tailed test, we have;

p-value = 0.00001 ≈ 0.000

D) The p-value of 0.000 is less than the significance value of 0.05,thus we will reject the null hypothesis

Find the average rate of change of the area of a circle with respect to its radius r as r changes from 3 to each

Answers

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question.

Find the average rate of change of the area of a circle with respect to its radius r as r changes from 3 to each of the following.

(i)    3 to 4

(ii)    3 to 3.5

(iii)    3 to 3.1

(b) Find the instantaneous rate of change when r = 3.  A'(3)

Area of a circle A(r)= πr²

The average rate of change of the area of a circle with respect to its radius

ΔA(r)/Δr = πr₂²-πr₁²/r₂-r₁

ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁

i) If the radius changes from 3 to 4

ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁

ΔA(r)/Δr = π(4²-3²)/4-3

ΔA(r)/Δr = π(16-9)/1

ΔA(r)/Δr = 7π

Hence, average rate of the area of a circle when the radius changes from 3 to 4 is 7π

ii) If the radius changes from 3 to 3.1

ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁

ΔA(r)/Δr = π(3.5²-3²)/3.5-3

ΔA(r)/Δr = π(12.25-9)/0.5

ΔA(r)/Δr = 3.25π/0.5

ΔA(r)/Δr = 6.5π

Hence, average rate of the area of a circle when the radius changes from 3 to 3.5 is 6.5π

iii) If the radius changes from 3 to 3.1

ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁

ΔA(r)/Δr = π(3.1²-3²)/3.1-3

ΔA(r)/Δr = π(9.61-9)/0.1

ΔA(r)/Δr = 0.61π/0.1

ΔA(r)/Δr = 6.1π

Hence, average rate of the area of a circle when the radius changes from 3 to 3.1 is 6.1π

iv) Instantaneous rate of change A'(r) = 2πr

When r = 3;

A'(3) = 2π(3)

A'(3) = 6π

Hence, the instantaneous rate of change when r = 3 is 6π

Answer:A number decreased by 4 is the same as 12.5

Step-by-step explanation:

The derivative of the trigonometric function. Please help me.

Answers

[tex]y=\dfrac{sin(x^2)}{x^3}[/tex]

Apply the quotient rule:

[tex]\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{x^3\frac{\mathrm d\sin(x^2)}{\mathrm dx}-\sin(x^2)\frac{\mathrm dx^3}{\mathrm dx}}{(x^3)^2}[/tex]

Chain and power rules:

[tex]\dfrac{\mathrm d\sin(x^2)}{\mathrm dx}=\cos(x^2)\dfrac{\mathrm dx^2}{\mathrm dx}=2x\cos(x^2)[/tex]

Power rule:

[tex]\dfrac{\mathrm dx^3}{\mathrm dx}=3x^2[/tex]

Putting everything together, we have

[tex]\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{x^3(2x\cos(x^2))-\sin(x^2)(2x\cos(x^2))}{(x^3)^2}[/tex]

[tex]\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x^3\cos(x^2)-2x\sin(x^2)\cos(x^2)}{x^6}[/tex]

[tex]\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x^2\cos(x^2)-\sin(2x^2)}{x^5}[/tex]

When [tex]x=\sqrt{\frac\pi2}[/tex], we have

[tex]\cos\left(\left(\sqrt{\dfrac\pi2}\right)^2\right)=\cos\left(\dfrac\pi2\right)=0[/tex]

[tex]\sin\left(2\left(\sqrt{\dfrac\pi2}\right)^2\right)=\sin(\pi)=0[/tex]

so the derivative is 0.

what percent of 6.2 is 14

Answers

Answer:

0.87

Step-by-step explanation:

If a 1000-count bottle of omeprazole 40 mg capsules costs the pharmacy $42.88, what is the estimated cost per capsule, rounded
to the nearest penny?

Answers

Answer:

Estimated cost per capsule = 4.288 (penny)

Step-by-step explanation:

Given:

Cost of 1000 capsule = $42.88

Number of capsules = 1000

Find:

Estimated cost per capsule

Computation:

1 dollar = 100 penny

So,

$42.88 = 4288 penny

Estimated cost per capsule = 4288 / 1000

Estimated cost per capsule = 4.288 (penny)

How to translate the number of people increased by 13 into an algebraic expression

Answers

Answer:

x +13.

where

x is number of people

Step-by-step explanation:

Let the number of people be x

given that number of people increased by 13

increased by 13 means that we whatever is the initial number of people, new number of people is 13 more than that.

thus, new number of people = x +13

to  translate the number of people increased by 13 into an algebraic expression

we add 13 to number of people which can be represented by  x +13.

Celine's book club read 42 books over 14 months. How many total months will it take them to read 57 books? Solve using unit rates.

Answers

Answer:

Step-by-step explanation:

42/14 = 57/x

42x = 57*14

42x = 798

x = 19 months

Answer: Actually its 18 months they calculated wrong

851-473 is the same as (_)-378...
What is working to get the answer in the parentheses?

Answers

Answer:

851- 473 = 373

(751)-378 = 373

Find the value of x.

Answers

Step-by-step explanation:

3x-12 + 6 = 14

3x-12 = 14 - 6

3x = 8 + 12

x= 20 ÷ 3

x = 6.7

Internal Angle Bisector Theoram:

Interior Angle Bisector Theorem : The angle bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.

[tex] \Large{ \boxed{ \bf{ \color{limegreen}{Solution:}}}}[/tex]

Here, We can see that angle bisector of an angle is dividing the opposite side.

And,

From here, we can say that the ratio of side being divided is same as the ratio of sides containing this angle.

So, we can write it as,

➝ 14 : 21 = 6 : 3x - 12

Prdouct of means = Product of extremes

➝ 21 × 6 = 14(3x -12)

➝ 126 = 14(3x - 12)

➝ 9 = 3x - 12

Flipping it,

➝ 3x - 12 = 9

➝ 3x = 21

➝ x = 7

☘️ So, Value of x is [tex]\boxed{\sf{x = 7}}[/tex]

━━━━━━━━━━━━━━━━━━━━

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating rectangle.

2x + y2 = 48, x = y

Find the area of the region.

Answers

Answer: A = 58

Step-by-step explanation: The sketched region enclosed by the curves and the approximating rectangle are shown in the attachment.

From the sketches, the area will be integrated with respect to y.

To calculate the integral, first determine the limits, which will be the points where both curves meet.

In respect to y:

[tex]2x+y^{2} = 48[/tex]

[tex]2x= 48- y^{2}[/tex]

[tex]x= 24 - \frac{y^{2}}{2}[/tex]

Finding limits:

[tex]y= 24 - \frac{y^{2}}{2}[/tex]

[tex]24 - \frac{y^{2}}{2}-y=0[/tex]

Multiply by 2 to facilitate calculations:

[tex]48 - y^{2}-2y=0[/tex]

Resolving quadratic equation:

[tex]y=\frac{-2+\sqrt{2^{2}+192} }{2}[/tex]

y = 6 and y = -8

Then, integral to calculate area will be with limits -8<y<6:

[tex]A = \int {24-\frac{y^{2}}{2}-y } \, dy[/tex]

[tex]A = 24y - \frac{y^{3}}{6}-\frac{y^{2}}{2}[/tex]

[tex]A = 24.6 - \frac{6^{3}}{6}-\frac{6^{2}}{2}-[24.(-8) - \frac{(-8)^{3}}{6}-\frac{(-8)^{2}}{2}][/tex]

A = 58

The area of the enclosed region is 58 square units.

answer the following Question

Answers

Answer:

a)$15.95

b) 8kg

Step-by-step explanation:

a)Approach this question by finding how much does it cost for 1g

So,

$2.1/50=$0.042per gram

then, multiple 380 to get the cost of sweets for 380 g

$0.042/gram*380gram=$15.96(Note: the gram cancel out each other)

Which is $15.95 as the question requested

b)This question stated that 3/4 of the metal has 15 kg

So, in order to find the total mass of metal we invert the 3/4 fraction

e.g 4/3*15=20kg

now we have the total mass we can find the mass for 2/5 of the metal

2/5*20kg=8kg

a jogger runs at an average speed of six miles per hour. At that rate, how far will the jogger travel in one and one half hours?​

Answers

Answer:

9 miles

Step-by-step explanation:

Hour = 6 miles

Half an hour = 3

6 + 3 = 9

The following data shows the number of laps run by each participant in a marathon. 46 65 55 43 51 48 57 30 43 49 32 56Which of these choices display the correct stemplot?A. 3 0 2 4 3 6 8 9 4 1 3 5 6 7 6 5B. 3 0 2 4 3 3 6 8 9 5 1 5 6 7 6 5

Answers

Answer:

The Stem plot is displayed below.

Step-by-step explanation:

A Stem Plot is a chart for demonstrating the distribution of numeric variables .

It is used to analyze the shape of the distribution.

The data provided is as follows:

S = {46, 65, 55, 43, 51, 48, 57, 30, 43, 49, 32, 56}

The Stem plot is displayed as follows:

3 | 0  2

4 | 3  3  6  8  9

5 | 1  5  6  7

6 | 5

s=πrl+πr2 solve for l.

Answers

Answer:

[tex]l = \frac{s - π {r}^{2} }{πr} [/tex]

Step-by-step explanation:

s = πrl + πr²

First move πr² to the left side of the equation

We have

πrl = s - πr²

Divide both sides by πr to make l stand alone

That's

[tex] \frac{\pi \:rl}{\pi \: r} = \frac{s - \pi \: {r}^{2} }{\pi \: r} [/tex]

We have the final answer as

[tex]l = \frac{s - π {r}^{2} }{πr} [/tex]

Hope this helps you

Derivative Function.. Could you solve this, please?

Answers

Hello, please consider the following.

f is differentiable so g is differentiable and we we can compute the derivative of g.

[tex]\text{derivative of } u^2\text{ is } 2uu'\\\\\text{derivative of } f(f(x^3)+x)\text{ is } (3x^2f'(x^3)+1)f'(f(x^3)+x)\\\\\text{So, }\\\\g'(x)=2f(f(x^3)+x)(3x^2f'(x^3)+1)f'(f(x^3)+x)\\\\\text{ We replace x par 1}\\\\g'(1)=2f(f(1)+1)(3f'(1)+1)f'(f(1)+1)\\\\g'(1)=2f(2)(3f'(1)+1)f'(2)\\\\\text{ We can put f'(2) in one part of the equation}\\\\f'(2)=\dfrac{2f(2)(3f'(1)+1)}{g'(1)}=\dfrac{2*5*(3*(-3)+1)}{2}\\\\=5*(-9+1)\\\\=5*(-8)\\\\=\boxed{-40}[/tex]

Thank you.

all the factors of 6

Answers

Answer:

1, 2, 3 and 6.

Step-by-step explanation:

Factors of 6 are 1, 2, 3 and 6.

Choose two statements that are true for this expression.
4x^3 – 7x^2 – 30/y + 15
A. There are four terms.
B. There are three terms. 30
C. The term is a ratio.
D. The entire expression is a difference.​

Answers

Answer:

A. There are four terms.

C. The term [tex]\frac{30}{y}[/tex] is a ratio.

Step-by-step explanation:

The expression given is the sum of four components: a third order monomial ([tex]4\cdot x^{3}[/tex]), a second order monomial ([tex]-7\cdot x^{2}[/tex]), a zero order monomial ([tex]15[/tex]) and a ratio ([tex]\frac{30}{y}[/tex]). There are a sum and two differences. Hence, the correct answers are:

A. There are four terms.

C. The term [tex]\frac{30}{y}[/tex] is a ratio.

Answer:

there are 4 terms

the term 30/y is a ratio

Step-by-step explanation:

got it right on my quiz

33505 divide 160 in fraction

Answers

Answer: The answer is 209.40625

The fractional equivalent of 33505 divided by 160 is 6701/32 .

Given,

33505/160

Now,

To get the fractional equivalent of 33505/160,

Divide numerator and denominator by the common factor .

So divide numerator and denominator by 5.

33505/5 = 6701

160/5 = 32

Now the simplified fraction is 6701/32.

Know more about fractions,

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