Evaluate the expression using a calculator. Round your answer to two decimal places when appropriate.
Square root 5^32,768 =

The electric field at this point is given by E = k * q/r^2 = (8.99e9 N * m^2/C^2) * (4.89e-9 C) / (2.79e-2 m)^2 = 7.76e6 N/C where  q is the charge (4.89e-9 C), and r is the distance from the charge (2.79e-2 m).

1. First calculate the electric field, E, using the equation E = k * q/r^2, where k is Coulomb's constant (8.99e9 N * m^2/C^2), q is the charge (4.89e-9 C), and r is the distance from the charge (2.79e-2 m).

2. Plugging in the values, we get E = (8.99e9 N * m^2/C^2) * (4.89e-9 C) / (2.79e-2 m)^2 = 7.76e6 N/C.

The electric field at this point is given by E = k * q/r^2 = (8.99e9 N * m^2/C^2) * (4.89e-9 C) / (2.79e-2 m)^2 = 7.76e6 N/C.

The complete question is :

Consider a point at a location 2.79 cm away from a 4.89-nc charge. What is the electric field at this point?

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To find the total monthly mortgage payment, we need to calculate the monthly payments for both the first (80%) and second (20%) mortgages and then add them together.

First, we'll find the monthly payment for the first mortgage:

Loan amount: $140,000 x 80% = $112,000

Interest rate: 4.75% / 12 months = 0.0395%

Loan term: 30 years x 12 months/year = 360 months

Monthly payment: $112,000 * (0.0395% / (1 - (1 + 0.0395%)^-360)) = $527.64

Next, we'll find the monthly payment for the second mortgage:

Loan amount: $140,000 x 20% = $28,000

Interest rate: 7.525% / 12 months = 0.0627%

Loan term: 30 years x 12 months/year = 360 months

Monthly payment: $28,000 * (0.0627% / (1 - (1 + 0.0627%)^-360)) = $184.07

Finally, we'll add the monthly payments for both mortgages to get the total monthly payment:

Total monthly payment: $527.64 + $184.07 = $711.71

So, the total monthly mortgage payment for Pablo's house is $711.71.

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After cost, the more money did Kevin make on Saturday than on Monday is $376.89.

The amount of Spends on monday is,

Sales = $397.35

Supply cost = $108.72

So the profit he is earning is

$397.35 - $108.72 = $288.63

The amount of Spends on Saturday is,

Sales = $914.06

Supply cost = $248.54

So the profit he is earning is

$914.06- $248.54= $665.52

Money did Kevin make on Saturday than on Monday is,

Money from saturday - money from monday

= $665.52 - $288.63

= $376.89

Profit is the term used to describe the financial gain experienced when the revenue from a commercial activity exceeds the costs, costs, and taxes associated with maintaining that activity.

Any profits generated are returned to the company's owners, who can decide whether to keep the money for themselves, pay dividends to shareholders, or reinvest it in the company.

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The of sin^2-cos^2 = [tex]Sin 2x Cos 2x = 2 Cos x (2 Sin x Cos2 x - Sin x)[/tex]

The sine of the angle is the ratio of the hypotenuse, or the angle's opposite, to the perpendicular in a right-angled triangle. Sinus is defined as Sinus = Perpendicular / Hypotenuse.

Sin 180 has a value of 0 precisely. One of the fundamental trigonometric functions is sine, which may be used to calculate the angle or sides of a right-angled triangle. Another name for it is trigonometric ratio.

If theta is an angle, then sine theta is the ratio of a right triangle's hypotenuse to its perpendicular.

trigonometric double angle formulas,

[tex]Sin 2x = 2 sin x cos x[/tex] ————(i)

And,

[tex]Cos 2x = Cos2x - Sin2x[/tex]

[tex]= 2 cos2x - 1 [Since Sin2 x + Cos2 x = 1][/tex]             ————(ii)

[tex]= 1 - 2Sin2x[/tex] ————(iii)

Now, multiply equation I by (ii) or (ii) by equation I to obtain the value of Sin 2x Cos 2x (i)

Think about equation I and (ii),

[tex]Sin 2x = 2 sin x cos x[/tex]

And,

[tex]Cos 2x = 2 cos2x - 1[/tex]

Simplifying the above equation, then we get

[tex]Sin 2x Cos 2x = 2 Sin x Cos x (2 cos2x - 1)= 4 Sin x Cos3 x - 2 Sin x Cos x= 2 Cos x (2 Sin x Cos2 x - Sin x)[/tex]

Think about equation I and (iii),

[tex]Sin 2x = 2 sin x cos xCos 2x = 1 - 2 Sin2x[/tex]

Simplifying the above equation, then we get

[tex]Sin 2x Cos 2x = 2 Sin x Cos x (1 - 2 Sin2x)= 2 Sin x Cos x - 4 Sin3 x Cos x= 2 Cos x (Sin x - 2 Sin3 x)So,Sin 2x Cos 2x = 2 Cos x (2 Sin x Cos2 x - Sin x)[/tex]

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9 i think

i’m pretty sure it’s 9 i just done it

The statement that identifies the scale used in this map would be = 1 inch equals 19 miles. That is option C.

A map is a diagram that can be used to represent the location and distance of various areas of a country or state.

In the map, there are 4 towns which are separated by 3 inches apart.

The actual distance apart = 57 miles

Therefore the actual scale that was used is calculated as follows;

3 inches = 57 miles

1 inch = X miles

make X mile the subject of formula;

X miles = 57/3 = 19 miles.

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The width of the box of books which Mr. Lin recieved which is in the shape of Rectangular Prism is (486/l*h) units.

A three-dimensional solid form having six sides, including rectangular bases, is called a rectangular prism. A rectangular prism also refers to a cuboid. A cuboid and a rectangular prism have the same cross-section.

According to the face form or the angle the faces make with the base, there are two different varieties of rectangular prisms.

Below are several characteristics of a rectangular prism that make it simple to recognize one.

The length of the rectangular Prism is l.

Width is w , height is h

Therefore,

Volume (V) = lbh

We know Volume is 486

so we casn find the width of the rectangular prism as 486/lh

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The standard parameterization for the tangent line  is x = 12t + 18 , y = 3t + 13 , z = 54t + 54

Equation of this type is known as a parametric equation; it uses an independent variable known as a parameter (commonly represented by t) and dependent variables that are defined as continuous functions of the parameter and independent of other variables.

Given that,

Given that, t = t0 = 3, I + (3t + 4) j + (2t 3) k

In order to get the tangent line to the curve at t=3, (x, y, z) = 18, 13, and 54,

r'(t) = 4t, 3, > and r'(t=3) = 12, 3, 54>. (18, 13, 54)

finally,

x = 12t + 18

y = 3t + 13

z = 54t + 54

The tangent line's usual parameterization is as follows:

x=12t+18, y=3t+13, and z=54t+54

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The process of converting repeating, non-terminating decimal to a fraction has been explained below. On conversion of 0.1515…, we get the fraction as 5/33.

What is a non-terminating decimal?

Non-terminating decimals are those decimal numbers that never reach an end since there is no endpoint in their decimal digits.

We are given a repeating, non-terminating decimal as 0.1515…

So, let x = 0.1515151515  ...(1)

Here, .15 is repeating

So, we will move one set of the repeating digits in front of the decimal.

By this, we get

100x = 15.1515151515     ...(2)

Now, on subtracting (1) from (2), we get

⇒100x - x = 15.1515151515 - 0.1515151515

⇒99x = 15

⇒x = 15/99

⇒x = 5/33

Hence, this way we can convert repeating, non-terminating decimal to a fraction.

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The independent variable in this relationship is the radius (r) and the dependent variable is the circumference (C). This is because the circumference is dependent on the radius of the circle, meaning that if the radius changes, the circumference will change accordingly.

Step-by-step explanation given below

Step 1: The rule states that the relationship between the circumference (C) and the radius (r) is C = 6.3r.

Step 2: This means that the circumference of a circle is a function of its radius.

Step 3: The independent variable in this relationship is the radius (r) because it is what is used to determine the circumference.

Step 4: The dependent variable in this relationship is the circumference (C) because it is what is being determined by the radius.

This is because the circumference is dependent on the radius of the circle, meaning that if the radius changes, the circumference will change accordingly.

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Answer:

9.5

Step-by-step explanation:

72 + 10t = 34 + 14t

72 - 34 = 14t - 10t

38/4 = 4t/4

9.5 = t

The value of the constant in the function is c  = -√3π²/6(3-π).

A differential equation is an equation that relates an unknown function and one or more of its derivatives. The equation dy/dx = f(x) is a simple example of a differential equation. Solving this equation means finding a function y with a derivative f. Therefore, the solutions of dy/dx are the antiderivatives of f. If F is one antiderivative of f, every function of the form y = f(x) + c is a solution of that differential equation.

Initial-value problems arise in many applications. Next we consider a problem in which a driver applies the brakes in a car. We are interested in how long it takes for the car to stop. Recall that the velocity function v(t) is the derivative of a position function s(t), and the acceleration a(t) is the derivative of the velocity function. In earlier examples in the text, we could calculate the velocity from the position and then compute the acceleration from the velocity. In the next example, we work the other way around. Given an acceleration function, we calculate the velocity function. We then use the velocity function to determine the position function.

The given equation is xy = y + x² sinx

⇒ xy - y =  x² sinx

⇒ y(x-1) =  x² sinx

⇒ y =  x² sinx/(x-1) +c

Also, y(π/3) = 0

Put x = π/3 in above equation:

y(π/3) =  (π/3) ² sin(π/3) /((π/3)-1)  + c = 0

After solving the above equation, we get c  = -√3π²/6(3-π)

Thus, the value of the constant in the function is c  = -√3π²/6(3-π).

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Janet hiked a distance of 2.5 miles which is equivalent to 4 km

An equation is an expression that shows the relationship between two or more numbers and variables. An equation can either be linear, quadratic, cubic and so on

Speed is the ratio of total distance to total time travelled. It is given by the equation:

Speed = distance / time

Janet hiked 2.5 miles in one hour. Hence:

Speed = distance / time = 2.5 miles / one hour = 2.5 miles per hour

1 mile = 1.609 km

2.5 miles = 2.5 miles * 1.609 km per mile = 4 km

Janet hiked 4 km

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The exact length of line segment PQ is 22.4.

The shortest distance (length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:

[tex]D = √[(x-p)² + (y-q)²] D = \sqrt{(x-p)^2 + (y-q)^2} \: \rm units.[/tex]

Given;

p(x,y)=(17,4)

m(x,y)=(-2,16)

Now,

[tex]D = √[(x-p)² + (y-q)²] D = \sqrt{(x-p)^2 + (y-q)^2} \: \rm units.[/tex]

D^2= (-2-17)^2+(16-4)^2

D^2=361+144

D^2= 505

D=22.4

Therefore, the distance will be 22.4

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Answer:

9 : 7

Step-by-step explanation:

given the ratio

4.5 : 3 [tex]\frac{1}{2}[/tex] , that is in decimal form

4.5 : 3.5 ( multiply both parts by 10 to clear the decimal )

= 45 : 35 ( divide both parts by 5 )

= 9 : 7 ← in simplest form

Answer:

9:7

Step-by-step explanation:

Convert all the numbers to either decimal or fraction. The operation becomes simple.

Simplifying after converting to decimal

Convert 3 1/2 to decimal 3 1/2 = 3 + 1/2

1/2 = 0.5

3 + 1/2 = 3 + 0.5 = 3.4

Ratio 4.5:3.5 = 4.5/3.5

Divide by 5 to give
[tex]\dfrac{4.5 /5 }{3.5/5} = 0.9/0.7\\\\[/tex]

Multiply both numerator and denominator by 10
0.9 x 10 = 9

0.7 x 10 = 7

So the ratio becomes 9/7 = 9:7

Simplifying after converting to fraction

4.5 = 4 + 0.5

0.5 = 1/2

5.5 = 4 + 1/2 = 4 1/2

Convert to mixed fraction:
4 1/2 = (4 x 2 + 1)/2 = 9/2

Convert 3 1/2 to fraction

3 1/2 = (3 x 2 + 1)/2 = 7/2

So 4.5 : 3 1/2 = 9/2 : 7/2

Multiplying by 2 we get the same answer: 9:7

Choose whichever approach you feel comfortable with

The number of 2 letter codes that can be formed is 6 with no letter repeated using Permutation.

A permutation of a set is, broadly speaking, a rearranging of its elements if the set is already sorted, or arranging its members into a sequence or linear order. The act or procedure of altering the linear order of an ordered set is referred to as a "permutation."

A permutation is a combination and an ordered arrangement of possible outcomes. For instance, there are 5 chairs, and 3 people should occupy them. There are five different methods to seat the first person, four ways to sit the person after them, and three ways to seat the third. As a result, we multiply the alternatives at our disposal to get the total number of configurations for seating 3 people in 5 seats. 5 4 3 are the methods we carry it out. It can be done in 60 different ways. You may write 5 4 3 as (5!) / (2!) (or) (5!) / (5 - 3), as you can see. .

Combinations are mathematical operations that count the number of potential configurations for a set of elements when the order of the selection is irrelevant. You can choose the components of combos in any order.

The first 3 letters of alphabet are a, b and c

The number of 2 letter codes that can be formed is 3*2 = 6 with no letter repeated.

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Answer:

118000

Step-by-step explanation:

cash out flow = beg balance - end balance

= 24 -14 =10K

128K - 10K =118K

actual pay out is 118K

Part A: The perimeter of the tree house floor is 32 m.

Part B: The area of the tree house floor is 40 m².

Part A: The perimeter of the rectangular floor can be found by adding up the lengths of all four sides.

Part B: The area of the rectangular floor can be found by multiplying the length by the width.

This is about a tree house design using a coordinate plane in which the coordinates are measured in meters (m). The task is to calculate the perimeter and the area of the rectangular floor of the tree house, given the vertices of the floor. The perimeter is found by adding up the lengths of all four sides of the rectangular floor, and the area is found by multiplying the length by the width.

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The mean in the above distribution is 1.84

From the question, we have the following parameters that can be used in our computation:

The figure

The mean value is then calculated as

Mean = SUm of the product of children and familes/Sum of families

So, we have

Mean = (0 * 23 + 1 * 19 + 2 * 29 + 3 * 9 + 4 * 20)/(23 + 19 + 29 + 9 + 20)

Evaluate

Mean = 1.84

Hence, the mean is 1.84

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The depreciation if production during the first year is 6,000 and total estimated production during the working life of the machine is 60,000 units is 15000.

Cost of machine = Rs. 1,70,000; Scrap value = Rs. 20,000;

Depreciation in production during the first year =  6,000 units;

Production units during the life of the machine = 60,000 units

Depreciation rate per unit = (Rs. 1,70,000 -  Rs. 20,000)/ 60,000 units

=  Rs. 2.5

Depreciation of first year =  6,000 * Rs. 2.5 = Rs. 15,000

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Complete question

If the original cost of a machine is Rs. 170,000, estimated scrap value Rs. 20,000, what is the depreciation if production during the first year is 6,000 and total estimated production during the working life of the machine is 60,000 units.

Suppose a deck of 52 cards is shuffled and the top two cards are dealt..

[tex]\left \P {{52} \atop {2}} \right.[/tex] =52!50! = 52 ×51 = 2652.

Now assuming each of the pairs has the same chance, calculate the probabilities for the following events

the chance that the first card is an ace;

There are 4aces in a deck, so the probability is

P (A)=

[tex]\frac{4}{52}\\ =\frac{1}{13}[/tex]

the chance that the second card is an ace

Again, there are 4aces in a deck, so the probability is

P(B)=

[tex]\\ \\ \frac{4}{52}\\ =\frac{1}{13}[/tex]

the chance that both cards are aces

There are 4aces in the deck. We already have the number ofpossible ordered pairs from P(A), each of which is equally likely. How many different ordered pairs give both aces? The answer is the number of permutations of two cards among four.

= [tex]\left \ P{4} \atop {2}} \right. \\\frac{4!}{2!}[/tex]

= 4*3

= 12

The probability that both cards are aces is therefore

[tex]\frac{\left \P {{4} \atop {2}} \right. }{\left \P{{52} \atop {2}} \right. }[/tex]

=12 /2652

=1/221

the chance of at least one ace among the two cards.

How many different permutations of the first two cards give at least one ace? The number that give two aces is P42, from above. The number that give an ace as the first card but not the second card is 4×48, since there are4aces, and after choosing one ace, there are 48 that possible non-aces for the second card. Likewise there are 48 ×4ways to choose an ace as the second card, but not the first. Thus the total number of ways that the two cards can have at least one ace is

P42+ 4 ×48 + 4 ×48 = 396.

The probability of of selecting at least one ace among the first two cards

= 396/3652

P (D)= 33 /221

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The proof of divisibility is correct in this question.

The capacity of one integer (the divisor) to divide another integer (the dividend) equally and without leaving a residual is known as divisibility in mathematics. Alternatively said, if a dividend is divisible by a divisor, the division will produce a whole number or an integer. The formula for this connection is "dividend divisor = integer." Using divisibility criteria, which are based on the characteristics of numbers and their prime factorizations, is a typical method of checking for divisibility. In subjects such as number theory, cryptography, and others, the ability to divide a number by another number can have significant ramifications.

According to the question

It is necessary to demonstrate that the phrase 45*45*15*15 may be divided by 75*30. We must first comprehend the characteristics of the numbers' prime factorization in order to do this.

The number 75 may be represented as 31 * 52, and when it is raised to the 30th power, it becomes 75^30 = 31 * 52^30 = 3^30 * 5^60. Similar to how 45 may be expressed as 3^2 * 5^1, 3^90 * 5^45 is equal to 45^45 = (3^2 * 5^1)^45. Additionally, 15 may be written as 3 * 5 1, which means that 15 = 3 * 5 * 15.

75 = 3^1 * 5^2,

∴ 75^30 = (3^1 * 5^2)^30 = 3^30 * 5^60.

It follows that 75^30, or 3^30 * 5^60, divides 45^45 * 15^15, or 3^90 * 5^45 * 3^15 * 5^15, as 3^30 divides 3^90 and 5^60 divides 5^45.

45 = 3^2 * 5^1,

∴ 45^45 = (3^2 * 5^1)^45 = 3^90 * 5^45.

15 = 3^1 * 5^1,

∴ 15^15 = (3^1 * 5^1)^15 = 3^15 * 5^15.

In other words, the equation 45*45*15*15 may be evenly divided by 75*30 without any residual, proving that it is divisible by 75*30. The division may be used to confirm this, but it can also be demonstrated by the fact that all of the dividend's prime factors—45*45*15*15—are included in the divisor's prime factorization, 75*30, in the multiples necessary to divide it evenly.

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The proof of divisibility is correct in this question.

Divisibility

The capacity of one integer (the divisor) to divide another integer (the dividend) equally and without leaving a residual is known as divisibility in mathematics. Alternatively said, if a dividend is divisible by a divisor, the division will produce a whole number or an integer. The formula for this connection is "dividend divisor = integer." Using divisibility criteria, which are based on the characteristics of numbers and their prime factorizations, is a typical method of checking for divisibility. In subjects such as number theory, cryptography, and others, the ability to divide a number by another number can have significant ramifications.

According to the question,

It is necessary to demonstrate that the phrase 45*45*15*15 may be divided by 75*30. We must first comprehend the characteristics of the numbers' prime factorization in order to do this.

The number 75 may be represented as 31 * 52, and when it is raised to the 30th power, it becomes [tex]75^{30}=(31*52^{30})=(3^{30}*5^{60})[/tex]. Similar to how 45 may be expressed as [tex](3^2*5^1)[/tex]. [tex](3^{90}*5^{45})[/tex] is equal to [tex]45^{45}=(3^2*5^1)^{45}[/tex]. Additionally, 15 may be written as 3 * 5 1, which means that 15 = 3 * 5 * 15.

[tex]75=3^1*5^2[/tex],

∴ [tex]75^{30}=(3^1*5^2)^{30}=3^{30}*5^{60}[/tex].

It follows that [tex]75^{30}[/tex], or [tex](3^{30}*5^{60})[/tex], divides [tex](45^{45}*15^{15})[/tex] or [tex](3^{90}*5^{45}*3^{15}*5^{15})[/tex], as [tex]3^{30}[/tex] divides [tex]3^{90}[/tex] and [tex]5^{60}[/tex] divides [tex]5^{45}[/tex].

[tex]45=3^2*5^1[/tex]

∴ [tex]45^{45}=(3^*5^1)^{45}=3^{90}*5^{45}[/tex]

[tex]15=3^1*5^1[/tex]

∴ [tex]15^{15}=(3^1*5^1)^{15}=3^{15}*5^{15}[/tex]

In other words, the equation 45*45*15*15 may be evenly divided by 75*30 without any residual, proving that it is divisible by 75*30. The division may be used to confirm this, but it can also be demonstrated by the fact that all of the dividend's prime factors—45*45*15*15—are included in the divisor's prime factorization, 75*30, in the multiples necessary to divide it evenly.

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Answer:

x = -39

-39 + 27 = -12

Step-by-step explanation:

Hope it helps! =D

Answer:

Here you have

Step-by-step explanation:

x + 27 = -12

x= -12 - 27

x= - 39

Scarlett typically rides her bike for around 1 and a half hours per day, thus she covered a distance of 7/12.

The overall uninspired velocity of an object will be its distance. Distance is the amount of space an object has traveled, regardless of where it began or ended. Distance would be the measurement of said size or extent of the separation between two places. It is important to keep in mind that the distance between two spots and the traveled between them aren't the same thing. Distance traveled is the sum of a line's length joining various places. Distance refers to the actual travel path of a body. Path length is another term for it. For instance, if an object is traveling from board to point P, the path's length will be similar to OP = 360 m.

given

We are aware of: t = 1 1/5   d = 7/8

Write down and replace 7/8 = v * (1* 1/5)

Remove the connecting element: 7/4 * 1/3

As a single fraction, write:

7 / 4*3

Determine the quotient or product: 7/12

Response: 7/12

Scarlett typically rides her bike for around 1 and a half hours per day, thus she covered a distance of 7/12.

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Yes, the three lines have a common point of intersection. This point is located where all three equations equal the same value, which in this case is (4,-4).

Yes, the three lines 3x1−12x2=4, 6x1 39x2=−76, and −3x1−51x2=80 have a common point of intersection. This point is located where all three equations equal the same value. To find this point, one must solve the three equations simultaneously. First, one can subtract the first equation from the third equation, which will result in a new equation equal to −3x1 + 48x2 = 76. From there, one can subtract the second equation from the new equation, resulting in a new equation equal to −45x2 = 132. From this equation, one can solve for x2 and the result is x2 = -4. Then, one can substitute the value of x2 into any of the original equations to solve for x1 and the result is x1 = 4. Therefore, the common point of intersection for these three equations is (4, -4).

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Answer:

25 minutes

Step-by-step explanation:

5/12×60 minutes

5×60=300

300/12

Answer =25

Answer:

39°

Step-by-step explanation:

Information we need to know

As we know, one of the angles in this triangle is 39° this means that the angle opposite it would also be 39°! This is because as the triangle is SAS v and the given 39 has to be equal

Have a lovely day :)

Answer:

39°

Step-by-step explanation:

Triangle HJI is an isosceles triangle.

In isosceles triangles the base angles are congruent which means their measures are equal.

So the measure of m∠HIJ = 39°

n−4  out of the n−3 neighbors of [tex]v_0[/tex] are leaves, except for [tex]v_k[/tex], which has degree 3 and is adjacent to [tex]v_0[/tex],  [tex]v_n_-_1[/tex]. and [tex]v_n[/tex] . [tex]v_n[/tex] and [tex]v_n_-_1[/tex] are both leaves.

Now, According to the question:

It is easy to show that a tree with  n ≥ 9 can have at most one vertex of degree n - 3. It is [tex]v_0[/tex].

Now, there are n - 1 - (n - 3) = 2 vertices that are not adjacent to [tex]v_0[/tex], it is also

[tex]v_n_-_1[/tex] and [tex]v_n[/tex]

Then a desired tree can be of 3 possible forms:

1. n - 4 out of n - 3  neighbors of [tex]v_0[/tex] are leaves, except for [tex]v_k[/tex], which has degree 2 and is adjacent to both [tex]v_0[/tex] and [tex]v_n_-_1[/tex]. [tex]v_n_-_1[/tex] has degree 2 and is adjacent to [tex]v_k[/tex] and [tex]v_n.v_n[/tex] is a leaf.

2. n − 5  out of the n − 3 neighbors of [tex]v_0[/tex] are leaves, except for [tex]v_j[/tex] and [tex]v_k[/tex]. [tex]v_j[/tex]has degree 2 and is adjacent to [tex]v_0[/tex] and  [tex]v_n_-_1[/tex]. [tex]v_k[/tex] also has degree 2 and is adjacent to[tex]v_0[/tex] and [tex]v_n[/tex]. [tex]v_n[/tex] and  [tex]v_n_-_1[/tex] are both leaves.

3. n−4  out of the n−3 neighbors of [tex]v_0[/tex] are leaves, except for [tex]v_k[/tex], which has degree 3 and is adjacent to [tex]v_0[/tex],  [tex]v_n_-_1[/tex]. and [tex]v_n[/tex] . [tex]v_n[/tex] and [tex]v_n_-_1[/tex] are both leaves.

It is then easy to computer the number of trees in each form and sum them up.

Learn more about Vertex at:

https://brainly.com/question/29258065

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