Evaluate the expression 10^x-3 for x = 2.

Answer for first question: x-intercept(s): (92,0)(92,0) y-intercept(s): (0,−95) for second question : x-intercept(s): (23,0)(23,0) y-intercept(s): (0,−12)

Step-by-step explanation:

Answer:

False.

Step-by-step explanation:

Because 12 and 9 are both multiples of 3.

The volume of this right prism that has a triangular base is equal to 108 cubic meters.

Mathematically, the volume of a right prism is given by this formula:

V = L x W x H

Where:

Given the following data:

Length of base = 6 meters.

Width of base = 4 meters. cm.

Height of prism = 4.5 meters.

Substituting the given parameters into the formula, we have;

V = 6 x 4 x 5

V = 108 cubic meters.

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Answer: 54 m³

Step-by-step explanation: proof with more answers

Answer:

x⁴ - 8x² + 9

Step-by-step explanation:

The Area of the smallest square is A1 = x . x = x²

The Area of the second square is A2 = ( x² - 3 )(x² - 3)

A2 = x⁴ - 3x² - 3x² + 9

A2 = x⁴ - 6x² + 9

The Area of the Shaded shape is A2 - A1

x⁴ - 6x² + 9 - x²

x⁴ - 8x² + 9

Answer:

The answer should be C. 250 in^3

Answer:

C. 250 in^3

Step-by-step explanation:

Answer:

$168.75

Step-by-step explanation:

In the morning you'll have a time of about 4 hours.

In the afternoon you'll have 8.5 hours.

You take these and add them together 4 + 8.5 = 12.5

Then you take your sum and multiply it by the wage you make per hour 13.50 x 12.5 = $168.75

Answer:

9*9+40*40=41*41

Step-by-step explanation:

The largest length is always the hypotenuse. If we were to multiply any triple by a constant, this new triple would still represent the sides of a right triangle. Therefore, 6, 8, 10 and 15, 20, 25, among countless others, would represent the sides of a right triangle.

Answer:

b no.is the correct answer.

Answer:

x=11

Step-by-step explanation:

It seems that the two angles are supplementary.  Soo they add up to 180

Thus,

15+15x=180

Solve for x...

15x=165

x=11

Hope this helps!!!

Answer:

20% off

Step-by-step explanation:

Divide:

72.8/364

Answer:

.20

Convert:

.20=20%

The shopkeeper giving 80% discount on the Christmas tree during the sale.

A discount is an amount that is subtracted from the regular price of an item.

[tex]discount \ percent = \frac{original \ price - final \ price }{original \ price } \times 100[/tex]

According to the given question.

The marked price of the Christmas tree i.e. original price = $364.

The price of the Christmas tree on sale i.e. final price  = $72.80

So,

The discount given on the Christmas tree

= Original price - final price

= $364 - $72.80

= 291.2

Therefore,

Discount percent  = [tex]\frac{291.2}{364} (100)= 80 \ percent[/tex]

Hence, the shopkeeper giving 80% discount on the Christmas tree during the sale.

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Answer:

6

Step-by-step explanation:

because 5 is greater than 4

[tex]\dfrac{3a^2-6a+3}{a^2-1}\\\\=\dfrac{3(a^2 -2a+1)}{(a+1)(a-1)}\\\\=\dfrac{3(a-1)^2}{(a+1)(a-1)}\\\\=\dfrac{3(a-1)}{a+1}\\\\=\dfrac{3a-3}{a+1} ~~~\text{for}~ a\neq 1[/tex]

The equations that has a leading coefficient of 3, and a constant of -2 are:

0 = 3x² + 2x – 2

0 = –3x + 3x² – 2

0 = –1x – 2 + 3x²

A leading coefficient is the term that has the highest degree in a polynomial expression.

A constant is a term that has only numbers and contains no variable.

We are given the following equations:

The first, third, and last equations each has a leading coefficient of 3 and a constant of -2.

Therefore, the equations that has a leading coefficient of 3, and a constant of -2 are:

0 = 3x² + 2x – 2

0 = –3x + 3x² – 2

0 = –1x – 2 + 3x²

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Answer:

x-y=3

Step-by-step explanation:

Answer:

[tex]x - y = 3[/tex]

is

[tex]y - 3 = (x - 6)[/tex]

in standard form

Answer:

$40

Step-by-step explanation:

Old Sale Price = $100

It was given 60% discount

 60% of 100 = 0.6 x 100 = 60

we remove the discount from  the original price( 100 -60 ) =  40.

So the new sale price for the pants are now $40

Answer:

[tex]\begin{aligned}{&\cos \theta=\frac{10}{26} \\\bf{&\tan \theta=\frac{24}{10}}\end{aligned}[/tex]

Step-by-step explanation:

Since the angle is in the first quadrant, the values of all trigonometric functions are positive. Also. the formulas for the trigonometric functions we need to find from the problem are shown below:
[tex]\begin{aligned}\cos \theta &=\frac{x}{r} \\\tan \theta &=\frac{y}{x}\end{aligned}[/tex]

Based on the formulas listed, the value of y and r are y = 24 and r = 26 respectively. This means that in order to determine the value of the other functions, we need In compute for the value of x using the Pythagorean Theorem:

[tex]\begin{aligned}r^{2} &=x^{2}+y^{2} \\r^{2}-y^{2} &=x^{2}+y^{2}-y^{2} \quad\left[\text { \text{Subtracting \ both \ sides \ of \ the \ equation\ by} } y^{2}\right] \\r^{2}-y^{2} &=x^{2} \\\sqrt{r^{2}-y^{2}} &=\sqrt{x^{2}} \\\sqrt{r^{2}-y^{2}} &=x \\\sqrt{26^{2}-24^{2}} &=x \\10 &=x\end{aligned}[/tex]Then, substituting this to the formula to determine the answers yields:

[tex]\begin{aligned}\cos \theta &=\frac{x}{r} \\&=\frac{10}{26} \\\tan \theta &=\frac{y}{x} \\&=\frac{24}{10}\end{aligned}[/tex]

Therefore, the answers are:

[tex]\begin{aligned}&\cos \theta=\frac{10}{26} \\&\tan \theta=\frac{24}{10}\end{aligned}[/tex]

Answer:

See below

Step-by-step explanation:

We are here given that ,

[tex]\longrightarrow \sin\theta =\dfrac{24}{26}[/tex]

And we would like to find out other trigonometric ratios ( since it is not mentioned about which two I will find out all 6 ) . As we know that ,

[tex]\longrightarrow \sin\theta =\dfrac{perpendicular}{hypotenuse} =\dfrac{p}{h}[/tex]

So that ,

[tex]\longrightarrow \dfrac{p}{h} =\dfrac{24}{26}[/tex]

Let us assume the given ratio to be 24x : 26x .

So we can say that ,

Now let's find out the value of base , so that we can find out the other ratios .

By Pythagoras Theorem ,

[tex]\longrightarrow (perpendicular) ^2+(base)^2=(hypotenuse) ^2[/tex]

Substitute the respective values ,

[tex]\longrightarrow (26x)^2=(24x)^2+b^2\\[/tex]

[tex]\longrightarrow 676x^2 = 576x^2+b^2\\ [/tex]

[tex]\longrightarrow b^2=100x^2\\[/tex]

[tex]\longrightarrow b =\sqrt{100x^2}\\[/tex]

[tex]\longrightarrow \boldsymbol{ b = 10x } [/tex]

Now we may find the other ratios as ,

[tex]\longrightarrow \cos\theta = \dfrac{base}{hypotenuse}=\dfrac{10x}{26x}=\boxed{\boldsymbol{\dfrac{5}{13}}}\\[/tex]

[tex]\longrightarrow \tan\theta =\dfrac{perpendicular}{base}=\dfrac{24x}{10x}=\boxed{\boldsymbol{\dfrac{12}{5}}}\\[/tex]

[tex]\longrightarrow \cosec\theta =\dfrac{hypotenuse}{perpendicular}=\dfrac{26x}{24x}=\boxed{\boldsymbol{\dfrac{13}{12}}}\\ [/tex]

[tex]\longrightarrow \sec\theta =\dfrac{hypotenuse}{base}=\dfrac{26x}{10x}=\boxed{\boldsymbol{\dfrac{13}{5}}} \\[/tex]

[tex]\longrightarrow \cot\theta =\dfrac{base}{perpendicular}=\dfrac{10x}{24x}=\boxed{\boldsymbol{\dfrac{5}{12}}} [/tex]

And we are done !

Answer:

2x/x+2

Step-by-step explanation:

Factor out 2x in the numerator

Then you get: 2x(x+4)

Factor the denominator

Two numbers that multiply to 8 and add to 6(2 and 4)

So you get: (x+2)(x+4)

Now you have: (2x(x+4))/(x+2)(x+4)

Simplify by cancelling the x+4

2x/x+2

Hey there!

Answer: [tex] \Rightarrow \boxed {\sf{\frac{2x}{(x+2)}}}[/tex]

Solving steps:-

[tex] \rightarrow\sf{\frac{ {2x}^{2} + 8x}{ {x}^{2} + 6x + 8} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x(x + 4)}{ {x}^{2} + 4x +2x + 8} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x(x + 4)}{ x (x + 4) +2(x + 4)} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x\sout{(x + 4)}}{ \sout{(x + 4)} (x + 2)} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x}{ (x + 2)} }[/tex]

~Done~

Answer:

5(x+2)

Step-by-step explanation:

Use the slope formula and pick any two points  to find the slope.

m= Y2- Y1/x2-x1

I picked the points (1,8) (3,14).

14-8/3-1= 6/2= 3

Hope this helps .

This being a piecewise function, trying to solve f(2), we must find which two equations we can use.

We can use the function '3x + 1' because its domain is 'x is greater than or equal to 2

   --> f(2) = 3(2) + 1 = 7

Hope that helps!

Answer:

Yes. They are proportional.

Step-by-step explanation:

[tex]\frac{56}{72} =\frac{7}{9}[/tex]

[tex]0.777=0.777[/tex]

The left side 0.777 is equal to the right side 0.777, which means that the given statement is always true.

True

since the diameter is 66 cm, then its radius is half that or 33 cm.

[tex]\textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ r=33\\ \underset{complete~turn}{\theta =2\pi ~\hfill } \end{cases}\implies s=(33)(2\pi )\implies s=66\pi \implies s\approx 207.34~cm[/tex]

Answer:

N = -1

explanation:

x = N

solving steps:

[tex]\sf f(x)=x^2+2x-15[/tex]

To find symmetry of a quadratic function.

                                                                   vertex formula    :   [tex]\sf x=\dfrac{-b}{2a}[/tex]

[tex]a=1,\:b=2[/tex]

[tex]\sf x=\dfrac{-2}{2\cdot \:1}[/tex]

[tex]\sf x = -1[/tex]

Then,

N = -1

Answer: Answer:

A. is your answer

When using the Slope Method, your answer is y - 5 = 4(x - 2).

Feel free to give brainliest.

Have a great day everyone!

4) -0.3 = -1/3 < -1/7 since the bigger a negative number is the less positive it is. 1/8 is positive so it is clear that it should be placed last. & thus do all options this way.

5) B

Area of a triangle = ½ bh.

where b = base &

h = height.

Area of outer shape = (½ x 16 x 12) in^2.

= 96 in^2.

Area of unshaded inner shape = (½ x 3 x 4) in^2.

= 6 in^2.

Area of shaded region = (96 – 6) in^2.

= 90 in^2.

Answer:

$10/hour

Step-by-step explanation:

Solving

Take two points and find slope

Slope

Pay rate 10$/h

Answer:

9 and 18

Step-by-step explanation:

let the numbers be x and 2x

so that x+2x=27

3x=27

x=9

so the numbers are 9 and 18.

I hope this will help

Answer:

[tex] \\ [/tex]

Step-by-step explanation:

It is given that, the sum of two numbers is 27 and one of the number is 2 times as large as the other.

[tex] \\ [/tex]

Let us assume the one number as x and as state in the question, one of the number is 2 times as large as the other (x) . So, the other number will be 2x .

[tex] \\ [/tex]

Now,

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x + 2x = 27 \:}}} \\ \\[/tex]

Adding like terms we get :

[tex]\\ {\longrightarrow \pmb{\sf {\qquad 3x = 27 \:}}} \\ \\[/tex]

Dividing both sides by 3 we get :

[tex]\\ {\longrightarrow \pmb{\sf {\qquad \frac{3x}{3} = \frac{27}{3} \:}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\frak {\qquad {x} = {9} \:}}} \\ \\[/tex]

So,

[tex] \\ [/tex]

Now,

[tex] \\ {\longrightarrow \pmb{\frak {\qquad Other \: number = 2x \:}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\frak {\qquad Other \: number = 2(9) \:}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\frak {\qquad Other \: number = 18 \:}}} \\ \\[/tex]

Therefore,