Evaluate (754 mm)/(41 s) to three significant figures and express answer in SI units using an appropriate prefix.

Answer: conduction

Explanation:

the heat passes out of the stove and into your hand. So is holding an ice cube – the heat is conducted out of your hand, and into the ice cube (that’s why your hand feels cold).

Answer:

Conduction

Explanation:

Conduction occurs when objects touch. The heat from the warmer object is transferred to the cooler object, eventually evening out the temperatures.

Answer:

B: Invertebrates

Explanation:

Since no other food source for invertebrates is shown, the invertebrates will starve and die off first

Answer:

an insulator is a substance that does not readily allow the passage of heat or sound.

Explanation:

Answer:

54g

Explanation:

Given parameters:

Number of moles of H₂O  = 3 moles

Unknown:

mass of water  = ?

Solution:

To solve this problem, we use the expression below:

         mass  = number of moles x molar mass

Molar mass of H₂O  = 2(1)  + 16  = 18g/mol

Mass of water  = 3 x 18  = 54g

Answer:

109.34 g

Explanation:

2NaOH(aq) + H2SO4(aq) ------> Na2SO4(aq) + 2H2O(l)

Number of moles of NaOH = 105g/40g/mol = 2.6 moles

From the reaction equation;

2 moles of NaOH yields 1 mole of sodium sulphate

2.6 moles of NaOH yields = 2.6 × 1/2 = 1.3 moles of sodium sulphate

Number of moles of H2SO4= 75.5g/98 g/mol = 0.77 moles

From the reaction equation;

1 mole of H2SO4 yields 1 mole of sodium sulphate

Hence, 0.77 moles of H2SO4 yields 0.77 moles of sodium sulphate

So H2SO4 is the limiting reactant.

Theoretical yield = number of moles × molar mass

= 0.77 mol ×142 g/mol

= 109.34 g

Answer:

The answer to this question would be:  

2. The exponents need to be the same so the leading numbers can be added or subtracted.

3. The result has the same number of decimal places as the least precise number.

The exponent is the 10^x that used in scientific notation. .When adding 12.3* 10^5 with 34.56 * 10^4, you need to make the exponent same first. In this case, it would become 12.3* 10^5 + 3.456 * 10^5= 15.756* 10^5

The decimal place could be rounded up to the least precise number. I'm not sure with the significant figures but it seems to use the biggest one.

Explanation:

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0.10 mol H₃PO₄

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

6.3 × 10²² molecules H₃PO₄

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

0.104616 mol H₃PO₄ ≈ 0.10 mol H₃PO₄

Answer:

Environmental Changes

Explanation:

Over time, a species will adjust to the changes in environment in order to survive.

Answer:

The correct answer is B, random mutations

Explanation:

Alleles are shuffled in the offspring when random mating, fertilization, and recombination between homologous chromosomes during meiosis occur.

I also took the quiz, Good luck!  \ (•◡•) /

Answer:

B and C

Explanation:

The different types of motor nerves transmit information to and from muscles, and they connect to muscle fibers through the motor endplate.

Answer: 84%

Explanation:

Using the table attached, one can find out the Relative humidity.

Look at the intersection between the temperature on the dry bulb and the difference between the temperature on the dry and wet bulb.

Dry bulb temperature = 80°F

Wet bulb temperature = 76°F

Difference = 80 - 76 = 4°F

Relative humidity is therefore:

= 84%

Answer:

Forces like wind and water break down rocks through the processes of weathering and erosion. ... Forces like wind and water move the rock pieces. They mix with matter like sand to become sediment. Weathering and erosion help shape Earth's surface.

Explanation:

Answer:

Technology used to gather data enhances accuracy and allows scientists to analyze and quantify results of investigations. Scientific explanations emphasize evidence, have logically consistent arguments, and use scientific principles, models, and theories

Explanation:

Answer:

CHO₂

Explanation:

The following data were obtained from the question:

Carbon (C) = 26.68%

Hydrogen (H) = 2.24%

Oxygen (O) = 71.08%

Empirical formula =?

The empirical formula of the compound can be obtained as follow:

C = 26.68%

H = 2.24%

O = 71.08%

Divide by their molar mass.

C = 26.68 /12 = 2.223

H = 2.24 / 1 = 2.24

O = 71.08 / 16 = 4.4425

Divide by the smallest.

C = 2.223 / 2.223 = 1

H = 2.24 / 2.223 = 1

O = 4.4425 /2.223 = 2

Thus the empirical formula of the compound is CHO₂

The correct empirical formula of a compound containing 26.68% carbon, 2.24% hydrogen, and 71.08% oxygen is CHO₂

The empirical formulae shows us how elements in a compound are in their simplest ratio.

From the question, we can see  

Carbon (C) with  26.68%

Hydrogen (H)with  2.24%

Oxygen (O) with 71.08%

Now, the empirical formula of the compound can begotten following these steps:

Carbon  = 26.68 /12 = 2.223

Hydrogen= 2.24 / 1 = 2.24

Oxygen  = 71.08 / 16 = 4.4425

C arbon = 2.223 / 2.223 = 1

H ydrogen= 2.24 / 2.223 = 1

Oxygen  = 4.4425 /2.223 = 2

Giving us the empirical formula of the compound as CHO₂

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Answer:

Metals with larger grains have less grain-boundary area per unit volume, and hence will not be as able to generate as many entanglements at grain boundaries, thus the strength will be lower.

Answer:

2C2 H6 +7O2=4co2+6h2o+heat

Answer:

Due to expansion.

Explanation:

The pressure exerted by a sample of gas at constant volume doubles when the absolute temperature is doubled because with the increase of temperature, the molecules of gas start expansion which increases their volume and as a result pressure of a gas increases. Increasing temperature of a gas sample increases the kinetic energy of the particles, and as a result the gas expand.

Answer:

soil

Explanation:

some organisms aren't plants

The answer is:

A.(soil)

Some organisms need soil but not all, hope this helps!

Answer:

C4H4O

Explanation:

1.24 g x 1mol/(44)g = 0.03mol C;

Mass of C: 0.03mol x 12.g/1mol

= 0.36g of C

mol of H: 0.255g x 1mol /(18) x2= 0.028mol

Mass of H; = 0.028g × 1 of H

Mass of O: 0.519 g – (0.36g +0.028g)= 0.131g;

0.131g/16 =0.008 mol

Divide by the smallest number of moles;

0.028/0.008 mol = 3.5; 0.03/0.008 mol =3.75, 0.008 mol/0.008 mol =1

C4H4O

Explanation:

Nitrous oxide

^_^^.^^.^

The volume : V = 45.22 L

Given

Moles = n = 2

Pressure = P = 780 torr = 1,02632 atm

Temperature = T = 10 + 273 = 283 K

Required

Volume

Solution

Ideal gas law : PV = nRT

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

Input the value :

V = (nRT)/P

V = (2 x 0.082 x 283)/1,02632

V = 45.22 L

Answer:

Volcanoes can produce oxygen in the atmosphere.

Explanation:

Answer: [tex]2AgNO_3(aq)+MgSO_4(aq)\rightarrow Ag_2SO_4(s)+Mg(NO_3)_2(aq)[/tex]

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

A double displacement reaction in which on e of the product is formed as a solid is called as precipitation reaction.  

The balanced chemical equation is:

[tex]2AgNO_3(aq)+MgSO_4(aq)\rightarrow Ag_2SO_4(s)+Mg(NO_3)_2(aq)[/tex]

Answer:

each year they are adding £31.25 to the bank account as £31.25 =£375 and times by 5 is £1875 but i did not include the $100 at the beginning

Explanation:

Answer:At the molecular level, the pressure of a gas depends on the number of collisions its molecules have with the walls of the container. If the pressure on the piston is doubled, the volume of the gas decreases by one-half. The gas molecules, now confined in a smaller volume, collide with the walls of the container twice as often and their pressure once again equals that of the piston.

Explanation:

Answer:

thanks

Explanation:

1.21 g HBr

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Compounds

Atomic Structure

Step 1: Define

9.03 × 10²¹ molecules HBr

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of H - 1.01 g/mol

Molar Mass of Br - 79.90 g/mol

Molar Mass of HBr - 1.01 + 79.90 = 80.91 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.21325 g HBr ≈ 1.21 g HBr

Answer: The empirical formula for the given compound is [tex]C_3HF_2[/tex]  and molecular formula for the given compound is [tex]C_{24}H_8F_{16}[/tex]

Explanation : Given,

Mass of C = 18.24 g

Mass of H = 0.51 g

Mass of F = 16.91 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =[tex]\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{18.24g}{12g/mole}=1.52moles[/tex]

Moles of Hydrogen = [tex]\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.51g}{1g/mole}=0.51moles[/tex]

Moles of Fluorine = [tex]\frac{\text{Given mass of Fluorine}}{\text{Molar mass of Fluorine}}=\frac{16.91g}{19g/mole}=0.89moles[/tex]

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.51 moles.

For Carbon = [tex]\frac{1.52}{0.51}=2.98\approx 3[/tex]

For Hydrogen  = [tex]\frac{0.51}{0.51}=1[/tex]

For Fluorine = [tex]\frac{0.89}{0.51}=1.74\approx 2[/tex]

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : F = 3 : 1 : 2

The empirical formula for the given compound is [tex]C_3H_1F_2=C_3HF_2[/tex]

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

[tex]n=\frac{\text{molecular mass}}{\text{empirical mass}}[/tex]

We are given:

Molar mass  = 562.0 g/mol

Mass of empirical formula = 3(12) + 1(1) + 2(19) = 75 g/eq

Putting values in above equation, we get:

[tex]n=\frac{562.0}{75}=7.49\approx 8[/tex]

Multiplying this valency by the subscript of every element of empirical formula, we get:

[tex]C_3HF_2=(C_3HF_2)_n=(C_3HF_2)_8=C_{24}H_8F_{16}[/tex]

Thus, the molecular formula for the given compound is [tex]C_{24}H_8F_{16}[/tex]

The proportionate of the atom found in a given compound is called the empirical formula while the molecular formula represents the actual digits of the atoms found in the given molecule of the compound.

The empirical formula for the given compound is [tex]\rm C_{3}HF_{2}[/tex]  and molecular formula for the given compound is [tex]\rm C_{24}H_{8}F_{16}[/tex].

Given,

Step 1: For determining the empirical formula, convert mass into moles:

For Carbon:

[tex]\begin{aligned}&\rm Moles \;of \;Carbon = \dfrac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}\\\\&= \dfrac{18.24 \rm g}{ 12 \rm g/mol}\\\\&=1.52\text{ moles}\end{aligned}[/tex]

For Hydrogen:

[tex]\begin{aligned}&\rm Moles \;of \;Hydrogen= \dfrac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}\\\\&= \dfrac{0.51\rm g}{ 1\rm g/mol}\\\\&=0.51\text{ moles}\end{aligned}[/tex]

For Fluorine:

[tex]\begin{aligned}&\rm Moles \;of \;Fluorine= \dfrac{\text{Given mass of Fluorine}}{\text{Molar mass of Fluorine}}\\\\&= \dfrac{16.91\rm g}{ 19\rm g/mol}\\\\&=0.89\text{ moles}\end{aligned}[/tex]

Step 2: Calculation of mole ratio for the assigned elements:

For this divide the moles of elements with the smallest number of moles calculated above.

[tex]\begin{aligned}\text{For Carbon} & = \dfrac{1.52 }{0.51}\\&= 2.98\end{aligned}[/tex]

Moles of C = 3

[tex]\begin{aligned}\text{For Hydrogen}& = \dfrac{0.51}{ 0.51}\\&= 1\end{aligned}[/tex]

Moles of Hydrogen = 1

[tex]\begin{aligned}\text{For Fluorine}& = \dfrac{0.89}{ 0.51}\\&= 1.74\end{aligned}[/tex]

Moles of Fluorine = 2

Step 3: The calculated mole ratio will be the subscript of the elements.

C : H : F = 3 : 1 : 2

Therefore, the empirical formula will be,

[tex]\rm C_{3}H_{1}F_{2} \;or\; C_{3}HF_{2}[/tex]

Determining the valency (n):

[tex]n = \dfrac {\text{molecular mass} }{\text{empirical mass}}[/tex]

Given,

= 75 g/eq

Substituting values in the above equation, we get:

[tex]\begin{aligned}n &= \dfrac{562 }{ 75}\\\\&= 7.49 \\\\&= 8\end{aligned}[/tex]

Multiply the valency calculated with the empirical formula:

[tex]\begin{aligned}\rm C_{3}HF_{2} &=\rm (C_{3}HF_{2})n\\&= \rm (C_{3}\rm HF_{2})8\\\\\\\\&= \rm (C_{24}H_{8}F_{16})\end{aligned}[/tex]

Therefore, the molecular formula is [tex]\rm C_{24}H_{8}F_{16}[/tex].

Thus, the empirical formula is  [tex]\rm C_{3}HF_{2}[/tex]  and the molecular formula is [tex]\rm C_{24}H_{8}F_{16}[/tex].

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