Estimate the constant rate of withdrawal (in m3 /s) from a 1375 ha reservoir in a month of 30 days during which the reservoir level dropped by 0.75 m in spite of an average inflow into the reservoir of 0.5 Mm3 /day. During the month, the average seepage loss from the reservoir was 2.5 cm, total precipitation on the reservoir was 18.5 cm and the total evaporation was 9.5 cm

Answer: When the car speed triples, momentum also triples but Kinetic energy increases 9 times or by 9 fold.

Explanation:

The momentum of a car (an object) is

p= mv

where

m is =the mass of the object( in this case car)

v is its= velocity

While the kinetic energy is is given by the formulae

K=1/2mv²

To determine how momentum and kinetic energy of the  car changes when the speed of the object triples, We have that the new velocity,

v¹= 3v

So that  the momentum  change becomes

p¹=mv¹=m (3v)= 3mv

mv=p

therefore p¹= 3p

we can see that the momentum also triples.

And the kinetic energy change  becomes

K¹=1/2m(v¹)²= 1/2m (3v)²

= 1/2m9v²= 1/2 x m x 9 x v²=9 x1/2mv²

1/2mv²=K

K¹= Kinetic energy = 9k

but Kinetic energy increases 9 times

Answer:

the answer is D

Explanation:

Mass extinctions were first identified by the obvious traces they left in the fossil record. ... Such dramatic changes in adjacent rock layers make it clear that mass extinctions were geologically rapid and suggest that they were caused by catastrophic events (e.g., a period of intense volcanic activity).

Mass extinction events wiped out many species at the same time resulting in older rock layers having more fossil variety than younger rock layers.

Mass extinction events are events which resulted in the mass death of many species of organisms.

Mass extinction events are presumed to have occurred in the past as seen from gaps in the fossils records.

Mass extinction events are thought to have occurred through intense volcanic activity in a particular area.

A mass extinction event in the fossil record will show an older layer of rock containing a much greater variety of fossils than a slightly younger layer of rock does.

Therefore, mass extinction events wiped out many species at the same time.

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Answer:

All of then are true

I need brainliest so I can rank up

Explanation:

Answer:

I think all options are true is the right answer

Explanation:

Mark me the brainliest plzzz

Answer:

nope

Explanation:

sige bigyan kitang Happy pills

Answer:

Option A

Explanation:

Answer:

a. volume of gas:  (decreases)

b. temperature of gas:  (same)

c. internal energy of gas: (same)

d. pressure of gas: (increases)

Explanation:

We have a gas (let's suppose that is ideal) in a piston with a fixed volume V.

Then we put in a reservoir at 0°C (the mixture of water and ice)

remember that the state equation for an ideal gas is:

P*V = n*R*T

and:

U = c*n*R*T

where:

P = pressure

V = volume

n = number of mols

R = constant

c = constant

T = temperature.

Now, we have equilibrium at T = 0°C, then we can assume that T is also a constant.

Then in the equation:

P*V = n*R*T

all the terms in the left side are constants.

P*V = constant

And knowing that:

U = c*n*R*T

then:

n*R*T = U/c

We can replace it in the other equation to get:

P*V = U/c = constant.

Now, the piston is (slowly) moving inwards, then:

a) Volume of the gas: as the piston moves inwards, the volume where the gas can be is smaller, then the volume of the gas decreases.

b) temperature of the gas: we know that the gas is a thermal equilibrium with the mixture (this happens because we are in a slow process) then the temperature of the gas does not change.

c) Internal energy of the gas:

we have:

P*V = n*R*T = constant

and:

P*V = U/c = constant.

Then:

U = c*Constant

This means that the internal energy does not change.

d) Pressure of the gas:

Here we can use the relation:

P*V = constant

then:

P = (constant)/V

Now, if V decreases, the denominator in that equation will be smaller. We know that if we decrease the value of the denominator, the value of the quotient increases.

And the quotient is equal to P.

Then if the volume decreases, we will see that the pressure increases.

Answer:

14

Explanation:

EWAN KO LANG DIN BASTA YAN ALAM KO

Answer:

Workdone = -2730 J

Explanation:

Formula for workdone is;

W = Force × Displacement

Now, according to Newton's 3rd law of motion, to every action, there is an equal and opposite reaction.

In the question given, we are told that a force gauge placed halfway down the rope reads out a constant 2100 Newtons while Magnus pulls the bus. This means that the force exerted by the rope on Magnus acts in an opposite direction to that which Magnus does to the rope.

Therefore, the force will be in the negative direction.

So;

Workdone = -2100 N × 1.3 m

Workdone = -2730 J

Answer:

difference between the field  = 1.56 N/C

as; 1.56 N/C is greater than 0.77 N/C;

Hence, Honeybees can detected the difference

Explanation:

Given the data in the question;

distance r = 24 cm = 0.24 m

charge 1 Q1 = +30 pC = 30×10⁻¹² C

charge 2 Q2 = +40 pC = 40×10⁻¹² C

Now, electric field due to +30 pC charge

E1 = kQ1/r²

where coulomb constant k is 9 × 10⁹ N.m²/C²

so we substitute

E1 = [( 9 × 10⁹ ) × (30×10⁻¹²)] / (0.24)²

E1 = 0.27 / 0.0576

E1 = 4.69 N/C

electric field due to +40 pC charge

E2 = kQ1/r²

E2 = [( 9 × 10⁹ ) × (40×10⁻¹²)] / (0.24)²

E2 = [( 9 × 10⁹ ) × (40×10⁻¹²)] / (0.24)²

E2 = 0.36 / 0.0576

E2 = 6.25 N/C

Now,

E2 = E1 =  6.25 N/C - 4.69 N/C = 1.56 N/C

difference between the field  = 1.56 N/C

as; 1.56 N/C is greater than 0.77 N/C;

Hence, Honeybees can detected the difference

Answer:

a. Vc = 5.06 m/s

b. Vp =  22.18 m/s

Explanation:

The acceleration of the pulley-mass system is as follows:

a = [tex]\frac{mg}{m + M}[/tex]

Solving for acceleration, we get:  

a = [tex]\frac{6.17 *9.8}{6.17 + 55.6}[/tex]

a = 0.97

So, for the part a:

Calculate the velocity of the crewman by using the following equation:

Vc = [tex]\sqrt{Vi^{2} + 2ay}[/tex]

Substituting the values into the equation, we get:

Vc = [tex]\sqrt{1.50^{2} + 2*0.97*13.2}[/tex]

Vc = 5.06 m/s

Now, for part b:

Calculate the final velocity of the pulley by using the following expression:

Vp = [tex]\sqrt{Vi^{2} +2gy }[/tex]

Just plugging in the values.

Vp = [tex]\sqrt{5.06^{2} +2*9.8*23.8 }[/tex]

Vp =  22.18 m/s

To calculate potential energy, use the formula

[tex]ep \: = mgh[/tex]

Where m is mass in kg, g is gravitational field strength in m s^-2 and h is height in metres.

So in this case, calculate

2kg × 9.8m/s × 40m

and you should find your answer.

Answer:

The sugars produced by photosynthesis can be stored, transported throughout the tree, and converted into energy which is used to power all cellular processes. Respiration occurs when glucose (sugar produced during photosynthesis) combines with oxygen to produce useable cellular energy.

Explanation:

I think this is correct lol.

Answer:

Explanation:

FBEDAC

Answer: I think false

Explanation:The velocity at which an object is sent moving and the mass of the object both play a hand in the level of kinetic energy that object produces. Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.

The gravitational force is determined as 7.37 x 10⁻⁷ N.

The gravitational force is determined by applying Newton's law of universal gravitation.

Mathematically, the formula for the Newton's law of universal gravitation is given as;

Fg = ( Gm₁m₂ ) / ( r² )

where;

Fg = ( 6.67 x 10⁻¹¹ x 63.7 x 9750.6 ) / ( 7.5² )

Fg = 7.37 x 10⁻⁷ N

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Answer:

h over 2 dg

Explanation:

brainliest!!!!!!!

Answer:

Charges are transferred from one object to another.

Explanation:

The charges from one object to another are sharing there energy.

Answer:

d velocity will be the one according to me

Answer:

so easy add the subtract then multiplay the add

Explanation:

Answer:

Explanation:

for vertical movement , time to reach the top = time to reach the hand = 2.5 s

v = u - gt

At the top , v = 0 , time t = 2.5 s

0 = u - g x 2.5

u = 2.5 x 9.8 = 24.5 m /s

velocity of throw = 24.5 m /s

So , when it passes the hand on its way down , it will have velocity equal to 24.5 m /s and it will accelerate downwards . Let its velocity down by 22 m be v

v² = u² + 2 g s

= 24.5² + 2 x 9.8 x 22

= 600.25 + 431.2

= 1031.45

v = 32.11 m /s .

Answer:

They have the same acceleration of 0.5m/s2 (please note m/s2 is the unit for acceleration and 2 is the power of s)

Explanation:

acceleration= velocity ÷ time

and the time is said to be 10seconds

velocity of car will be the new velocity- the initial velocity = 27-22= 5

acceleration= 5÷10

acceleration= 0.5

hope this helped

now hit that crown button :)

Air resitances also know as drag is a force that is caused by air the force acts in oppsite directions to an object moving through the air ..

HOPE THIS HELP YOU ..

Answer:

34.4Joules

Explanation:

Complete question

a man is trying to pull a box a distance of 3 m with a force of 20 N that makes a 35º with the horizontal. Find the workdone

Work done = Fdsin theta

Force F = 20N

distance d = 3m

theta = 35 degrees

Substitute

Workdone = 20(3)sin 35

Workdone = 60sin35

Workdone = 34.4Joules

Hence the workdone by the man is 34.4Joules

Answer:

1) The total charge of the top plate is 0.008 C

b) The total charge of the bottom plate is -0.008 C

2) The electric field at the point exactly midway between the plates is 0

3) The electric field between plates is approximately 1.1294 × 10¹² N/C

4) The force on an electron in the middle of the two plates is approximately 1.807 × 10⁻⁷ N

Explanation:

The given parameters of the parallel plate capacitor are;

The dimensions of the plates = 4 × 2 cm

The distance between the plates = 10 cm

The surface charge density of the top plate, σ₁ = 10 C/m²

The surface charge density of the bottom plate, σ₂ = -10 C/m²

The surface area, A = 0.04 m × 0.02 m = 0.0008 m²

1) The total charge of the top plate, Q = σ₁ × A = 0.0008 m² × 10 C/m² = 0.008 C

b) The total charge of the bottom plate, Q = σ₂ × A = 0.0008 m² × -10 C/m² = -0.008 C

2) The electrical field at the point exactly midway between the plates is given as follows;

[tex]V_{tot} = V_{q1} + V_{q2}[/tex]

[tex]V_q = \dfrac{k \cdot q}{r}[/tex]

Therefore, we have;

The distance to the midpoint between the two plates = 10 cm/2 = 5 cm = 0.05 m

[tex]V_{tot} = \dfrac{k \cdot q}{0.05} + \dfrac{k \cdot (-q)}{0.05} = \dfrac{k \cdot q}{0.05} - \dfrac{k \cdot q}{0.05} = 0[/tex]

The electric field at the point exactly midway between the plates, [tex]V_{tot}[/tex] = 0

3) The electric field, 'E', between plates is given as follows;

[tex]E =\dfrac{\sigma }{\epsilon_0 } = \dfrac{10 \ C/m^2}{8.854 \times 10^{-12} \ C^2/(N\cdot m^2)} \approx 1.1294 \times 10^{12}\ N/C[/tex]

E ≈ 1.1294 × 10¹² N/C

The electric field between plates, E ≈ 1.1294 × 10¹² N/C

4) The force on an electron in the middle of the two plates

The charge on an electron, e = -1.6 × 10⁻¹⁹ C

The force on an electron in the middle of the two plates, [tex]F_e[/tex] = E × e

∴ [tex]F_e[/tex] = 1.1294 × 10¹² N/C ×  -1.6 × 10⁻¹⁹ C ≈ 1.807 × 10⁻⁷ N

The force on an electron in the middle of the two plates, [tex]F_e[/tex] ≈ 1.807 × 10⁻⁷ N

Answer:

A)

The impulse that reaches the cell phone first is the Longitudinal wave

B)  0.0206  seconds

Explanation:

length of Iron rail = 7.5 m

speed of sound in Iron = 5950 m/s

speed of sound in Air = 343 m/s

A) Determine which pulse reaches the cell phone first

The impulse that reaches the cell phone first is the Longitudinal wave

 Time for longitudinal pulse to be detected =  7.5 / 5950 = 0.00126 s

  Time for pulse through air to be detected = 7.5 / 343 = 0.02186  s

B) separation in time between the arrivals of the two pulses

   ΔT = 0.02186 - 0.00126  = 0.0206  seconds

Answer:

RThe answer is Reflection....

Answer:

ACD

Explanation:

according to it's description above

The wave is a mechanical wave and can also be sound wave also the wave is a longitudinal wave. The correct option is A, C, and D.

A mechanical wave is one whose energy cannot be transmitted via a vacuum. To transfer their energy from one place to another, mechanical waves need a medium.

A mechanical wave is something like a sound wave. A vacuum can not be traversed by sound waves.

Waves like mechanical waves require a medium to travel through. Non-mechanical waves are those that can travel through any medium.

Mechanical waves include, but are not limited to, sound waves, water waves, and seismic waves.

The three claims are accurate as follows: The wave is a longitudinal wave and can also be a mechanical wave or a sound wave.

Thus, the correct option is A, C, and D.

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Your question seems incomplete, the missing image is:

Answer:

The number of electrons that surround the nucleus will determine whether or not it is electrically charged or electrically neutral

Explanation: