Elvie can encode a document 4 hours more than EJ does.The two worked together in 3 hours when EJ left for an important appointment.Elvin continued the job and completed it in two hours.​

Answer:

c. 0.18

Explanation:

The Formula for Froude Number is given as follows:

Froude No. = Inertial Forces/Gravity Forces

Froude No. = v/√(gD)

where,

v = velocity = 1 m/s

g = 9.8 m/s²

D = Depth of channel = 3 m

Therefore,

Froude No. = (1 m/s)/√[(9.8 m/s²)(3 m)]

Froude No. = 0.18

hence, the correct option will be:

c. 0.18

Explanation:

Think of brushes as a sliding contact.

In an alternator the brushes provide power to the field coil which is physically mounted on the rotating shaft. They provide this direct current through two slip rings.

By controlling the power flow to the field, the power output of the alternator can be controlled. A regulator circuit is used to control the field so that the output voltage is maintained to about 13.5 to 14.5 VDC.

FUN FACT: Many brush holders have a small holes near the brush exit. When you assemble the alternator you physically push the brushes all the way into their holder and then thread a small wire through these hole. After the alternator is assembled you can pull the wire out and the brushes will snap into position.

Answer:

6:00 pm the next day

Explanation:

Given that

Tahir traveled twice as far as Ahmed. We say,

Ahmed traveled a distance, D

Tahir would travel a distan, 2D

Tahir traveled 1/3 as fast as Ahmed, so we say

Ahmed traveled at a speed, S

Tahir would travel at a speed, S/3

If Ahmed starts travel on tuesday at noon at point x to point z 300km, by 9:00pm,

Time taken by Ahmed to travel is

9:00 pm - 12:00 pm = 9 hours

Ahmed, traveled 300 km in 9 hours, meaning he traveled at 33.3 km in an hour.

Speed, S that Ahmed traveled with is 33.3 km/h

Remember, we stated that Tahir travels at a speed of S/3, that is, The speed of Tahir is

33.3/3 = 11.1 km/h.

300 km would then be traveled in 300 km/11.1 km/h = 27 hours.

Tahir started traveling, 3 hours after Ahmed, that is 12:00 pm + 3:00 hrs = 3:00 pm, and if he's to spend 27 hours on the journey he would reach destination z at 6:00 pm the next day

Answer:

Uair = 0.0749 KW/k = 74.9 W/k

Explanation:

The natural air change per hour is given by the formula:

Natural Air Change per Hour = ACPH = 60*Volume Flow/Volume

where,

ACPH = 0.4

Volume Flow = ? in ft³/min

Volume = 19456 ft³

Therefore,

0.4 = (60 min)(Volume Flow)/(19456 ft³)

Volume Flow = (0.4)(19456 ft³)/(60 min) = (129.7 ft³/min)(1 min/60 s)

Volume Flow =  (2.16 ft³/s)(0.3048 m/1 ft)³ = 0.061 m³/s

Now, we find heat loss coefficient:

Uair = Volumetric Flow*Density of air*Specific Heat Capacity of air

Uair = (0.061 m³/s)(1.225 kg/m³)(1 KJ/kg.k)

Uair = 0.0749 KW/k = 74.9 W/k

Answer:

The maximum water pressure at the discharge of the pump (exit) = 496 kPa

Explanation:

The equation expressing the relationship of the power input of a pump can be computed as:

[tex]E _{pump,u} = \dfrac{m(P_2-P_1)}{\rho}[/tex]

where;

m = mass flow rate = 120 kg/min

the pressure at the inlet [tex]P_1[/tex] = 96 kPa

the pressure at the exit [tex]P_2[/tex] = ???

the pressure [tex]\rho[/tex] = 1000 kg/m³

∴

[tex]0.8 \times 10^{3} \ W = \dfrac{(120 \ kg/min * 1min/60 s)(P_2-96000)}{1000}[/tex]

[tex]0.8 \times 10^{3}\times 1000 = {(120 \ kg/min * 1min/60 s)(P_2-96000)}[/tex]

[tex]800000 = {(120 \ kg/min * 1min/60 s)(P_2-96000)}[/tex]

[tex]\dfrac{800000}{2} = P_2-96000[/tex]

400000 = P₂ - 96000

400000 +  96000 = P₂

P₂ = 496000 Pa

P₂ = 496 kPa

Thus, the maximum water pressure at the discharge of the pump (exit) = 496 kPa

Answer:

Following are the solution to this question:

Explanation:

Whenever a chemical reaction occurs between water and cement the heat is released, and a [tex]CaOSiO_2H_2O[/tex] (C-S-H gel) gel constructs gel is also recognized as "tobermorite gel."

This one gel acts like a pack of gum and also has a cement quality, that holds its particles intact and therefore contributes to the overall compression mix. An increase in supply explicitly causes the movement in the outcome of power. C3S and C2S are both the compounds of Bouge that produce hydration C-S-H gel.

It mixture must be balanced as [tex]Ca(OH)_2[/tex] with C-S-H gel also is given as a byproduct. It [tex]Ca(OH)_2[/tex] , that cause sudden with sulphate and form [tex]CaSO_4[/tex] , is an unacceptable substance. Sulfate attack or later deterioration of its cement is caused by this [tex]CaSO_4[/tex] .

All C3S and C2S generate various amounts of C-S-H gel so, the required strength can be maintained without compromising on real term durability.

Answer:

Stages of Interpretation and Mapping

Selection of photographs. Whenever possible, all photographs of a site or small area should be assessed for fitness of purpose. ...

Control points. A good spread of control points on a photograph is vital to establish the exact location or size of features. ...

Transformation.

Explanation:

Answer:

The major financial flop that led to the end of the Sega Dreamcast and ultimately caused Sega to stop making game consoles altogether is:

3: A game called Shenmue, that cost more than $70 million to make, meant that everyone who owned a Dreamcast needed to buy two copies of the game just for Sega to make back the money they had spent to develop it-which didn't happen.

Explanation:

Shenmue, released on December 29, 1999, was created for Dreamcast by Suzuki.  It was widely described as the most expensive video game ever produced.  It had an estimated production and marketing cost of between US$47 and $70 million, according to the latest available data.

Answer:

A. Juna's answer is correct because both the number of feet and the number of inches are correct

Explanation:

Answer:

Environmental science and protection technicians both use laboratory equipment, such as microscopes, to analyze samples collected in the field. Environmental science and protection technicians also monitor the environment and investigate sources of pollution and contamination, including those affecting public health.

Hope this was helpful ;)

answer is a and b                                        jjjjxjxjxjxjx        xxxjxjxj

Answer:

A civil engineering degree program applies mathematics and physical science to solve specific, real-world problems in commerce and industry. A strong civil engineering program typically emphasizes the practical use of geometry, trigonometry, and calculus in conjunction with physics, material science, and chemistry.

Explanation:

Hope this helps!! Please consider marking brainliest! Have a good one!!

Answer:

Explanation:

This is not a question so to say. This is more like a complaint about how the platform works. Are you needing help with solving a personal problem or having troubles with the platform in itself

Answer:c

Explanation:

Answer:

Explanation:

The simple change that would be made to a basic PID controller to prevent it from been noisy  is tuning the value of  Ki term   while

The simple change that would be made to a PID controller if you want to  change the target by large steps is increasing/changing the Kp term associated with the PID  controller

Answer:

c thereeeeeeeeeeeeeeeeee

Answer:

Hello your question is incomplete attached below is the complete question

answer :

A) At 8 meters below center

Total stress = 228.827 KN/m^2

pore water pressure = 0 KN/m^2

effective stress = 228.827 - 0 = 228.827 KN/m^2

B) At 8 meters below tank edge

Total stress = 186.289 KN/m^2

pore water stress = 0 Kn/m^2

effective stress = 186.289 - 0 = 186.289 KN/m^2

Explanation:

Given data :

Diameter = 21 m

radius = 21 / 2 = 10.5 m

soil moist = 18.4 KN/cubic meter

Average bearing pressure = 105 kPa

i) Before Loading Tank

 Total stress = 8 * 18.4 = 147.2 KN/m^2

 Pore pressure = 0 KN/m^2

 Effective stress = 147.2 - 0 = 147.2 KN/m^2

ii) After loading Tank

  No change occurs

A) At 8 meters below center

Total stress = 228.827 KN/m^2

pore water pressure = 0 KN/m^2

effective stress = 228.827 - 0 = 228.827 KN/m^2

B) At 8 meters below tank edge

Total stress = 186.289 KN/m^2

pore water stress = 0 Kn/m^2

effective stress = 186.289 - 0 = 186.289 KN/m^2

attached below is the detailed solution

Answer:

AI 7075

Explanation:

Material                Density g/cc         Yield strength      

AI 7075                   2.81                         503

AISI 4340/SAE       7.85                         1160

Mg-ZK61                 1.83                          195

Ti8A|1Mo1V             4.37                         570

Determine the alloy with the lightest weight using this relationship

weight ∝  ( S / E )

E = yield strength

S = density

from the above calculation the alloy with the lightest weight is ;

AI 7075

Answer:

option  C

Explanation:

The correct statement is As specific ions form a film on the metal surface, hence those ions which form films may be adequate to cause SCC

other options are wrong as ; specific ions are not necessary for metals and alloys and also an environment causing SCC for an alloy might not cause SCC of another alloy found in the environment

Answer:

a) 1

b) 1813.96 MJ/kmol

c) 32.43 MJ/kg ,  1980.39 MJ/Kmol

Explanation:

molar mass of  ethanol (C2H5OH) = 46 g/mol

molar mass of   octane (C8H18) = 114 g/mol

therefore the moles of ethanol and octane

ethanol =  0.85 / 46

octane = 0.15 / 114

a) determine the molar air-fuel ratio and air-fuel ratio by mass

attached below

mass of air / mass of fuel = 12.17 / 1 = 12.17

b ) Determine the lower heating value

LHV  of  ( C2H5OH) = 26.8 * 46 = 1232.8 MJ/kmol

LHV  of (C8H18). = 44.8 mj/kg * 114 kg/kmol = 5107.2 MJ/Kmol

LHV ( MJ/kmol)  for fuel mixture = 0.85 * 1232.8 + 0.15 * 5107.2 = 1813.96 MJ/kmol

c) Determine higher heating value  ( HHV )

HHV of (C2H5OH) = 29.7 * 46 = 1366.2 MJ/kmol

HHV of C8H18 = 47.9 MJ/kg * 114 = 5460.6 MJ/kmol

HHV  in MJ/kg  = 0.85 * 29.7 + 0.15 * 47.9  = 32.43 MJ/kg

HHV in  MJ /kmol  =  0.85 * 1366.2 + 0.15 * 5460.8 = 1980.39 MJ/Kmol

/~\ The correct answer is:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

B. A demand for unique features.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

I hope this helps! /~\

Answer:

A. A reliance on mass production of necessary parts.

Explanation:

Took the test

Answer:

a) 764.45K

b) 210.48 kJ/kg

c) 30.14%

Explanation:

pressure ratio = 10

minimum temperature = 295 k

maximum temperature = 1240 k

isentropic efficiency for compressor = 83%

Isentropic efficiency for turbine = 87%

a) Air temperature at turbine exit

we can achieve this by interpolating for enthalpy

h4 = 783.05 kJ/kg ( calculated in the background ) at state 4 using Table A-17  for  Ideal gas properties of air

T4 ( temperature at Turbine exit ) = 760 + ( 780 - 760 ) [tex](\frac{783.05-778.18}{800.13-778.18} )[/tex] = 764.45K

b) The net work output

first we determine the actual work input to compressor

Wc = h2 - h1  ( calculated values )

     = 626.57 - 295.17 =  331.4 kJ/kg

next determine the actual work done by Turbine

Wt = h3 - h4  ( calculated values )

     = 1324.93 - 783.05 = 541.88 kJ/kg

finally determine the network output of the cycle

Wnet = Wt - Wc

         = 541.88 - 331.4  = 210.48 kJ/kg

c) determine thermal efficiency

лth = Wnet / qin  ------ ( 1 )

where ; qin = h3 - h2

equation 1 becomes

лth = Wnet / ( h3 - h2 )

      = 210.48 / ( 1324.93 - 626.57 )

      = 0.3014  =  30.14%

Answer:

3 m/s²

Explanation:

Acceleration is calculated as :

a= Δv/ t

where ;

Δv = change in velocity

Δv = 45 - 0 = 45  m/s

t= 15 s

a= 45 /15

a= 3 m/s²

Answer:

Explanation:

Step one:

given data

from the table  for R-134a

For the given pressure state the following data were extracted.

s=0.94202kJ/kg.K

h1=241.14kJ/kg

∝1=0.12355m^3/kg

By interpolation, the final enthalpy and pressure with data from the table of  R-134a

h2=277.12kJ/kg

The minimum power output is then determined from the energy balance

W=m(h2-h1)

W=V1/∝1(h2-h1)

W=2.4/60/0.12355(277.12-241.14)

W=0.04/0.12355(35.98)

W=0.3237(35.98)

W=11.65kW Approx.

The minimum power output of the compressor is 11.65kW

Answer:

The difference lies in the coverage of the construction.  While local level construction focuses on the local area, national level construction has a nation-wide coverage.

Explanation:

Residential construction concentrates on the construction of residential buildings that have sleeping accommodations.  Such constructions are opposed to the construction of other buildings that are meant for commercial uses as they lack sleeping accommodations.  The federal, state, and local governments can embark on the construction of residential quarters for their residents.  The constructions are also funded at the given level.  When it is locally funded, the construction is meant to satisfy specific local needs.  The constructions by the federal government consider the needs of many localities, and may not meet specific local needs.

Answer: A Residential construction is local in its effects even though those effects have a national impact.

Explanation:

Answer:

Impeller diameter should be 0.02 meter

Explanation:

The Impeller diameter is a parameter with a circular design of a high speed pump. The performance of the pump depends on this parameter.

As per the given data

Speed of pump = 3,560 rpm

Rate of water flow = 500 gpm = 0.0005 m^3/minutes

Size of head = 250 ft = 250 ft x 0.3048 m/ft = 76.2 m

The impeller diameter can be calculated using following formula

Impeller diameter =0.1 x  [tex]\sqrt{Water flow rate X 60}[/tex]

Impeller diameter =0.1 x  [tex]\sqrt{0.0005 X 60}[/tex]

Impeller diameter =0.1 x  [tex]\sqrt{0.03}[/tex]

Impeller diameter = 0.1 x 0.1732

Impeller diameter = 0.01732

Impeller diameter = 0.02 m

Answer:

0.124

Explanation:

We calculate the hydraulic gradient by the formulas below.

I = (change in h)/(change in l)-----eqn 1

I = (hk-hl)/change in L ----- equation 2

At k the headloss = hk,

At L the headloss = hL

The distance of water travel is change in I

Total head at k

hk = 543+23

= 566 ft

Total head at L

hL = 461+74

= 535 ft

Change in L = 250

When we substitute these values in equation 2

566-535/250

= 0.124

The hydraulic gradient is 0.124

Answer:

C

Explanation:

Answer:

For a deeper material truss, increase in distance between the top chord and bottom chord will cause the truss to bear more load with increase in Span

For Cantilever Truss ; increase in span will result in decrease in load bearing capacity of the truss

When a truss fails the areas that are affected are the supports of the truss and its corresponding spam. i.e. 4 crossbars at quarter of the span

Explanation:

The load-carrying capacity of a truss on the span  is basically based on the type of truss ,

For a deeper material truss, increase in distance between the top chord and bottom chord will cause the truss to bear more load with increase in Span

For Cantilever Truss ; increase in span will result in decrease in load bearing capacity of the truss

When a truss fails the areas that are affected are the supports of the truss and its corresponding spam. i.e. 4 crossbars at quarter of the span