electric heater has a power of 50 watts calculate the time taken for the electric element to transfer 4750 joules of energy to the vegetable oil

Answer:

d

Explanation:

To convert the equation  [tex]∆_{W}[/tex]= [tex]V_{ab}[/tex] I[tex]∆_t[/tex] to express power P for the circuit, we need to divide both sides of the equation by [tex]∆_t[/tex]. Option B is correct.

The power P for the circuit can be expressed using the equation;

P = [tex]∆_{W}[/tex]/[tex]∆_t[/tex]

where [tex]∆_{W}[/tex] is work done on the charge and [tex]∆_t[/tex] is time interval for which the work is done.

Starting with the equation [tex]∆_{W}[/tex]= [tex]V_{ab}[/tex] I[tex]∆_t[/tex], we can rearrange it as follows:

[tex]∆_{W}[/tex]/[tex]∆_t[/tex] = [tex]V_{ab}[/tex] I

Now, substituting the expression for power P, we get;

P = [tex]V_{ab}[/tex] I

Therefore, to convert the equation [tex]∆_{W}[/tex] = [tex]V_{ab}[/tex] I[tex]∆_t[/tex] to express power P for the circuit, we need to divide both sides of the equation by [tex]∆_t[/tex], as in option B;

[tex]∆_{W}[/tex]/[tex]∆_t[/tex] = [tex]V_{ab}[/tex] I

P = [tex]∆_{W}[/tex]/[tex]∆_t[/tex]

P = [tex]V_{ab}[/tex] I/[tex]∆_t[/tex]

Dividing both sides by [tex]∆_t[/tex], we get:

P =  [tex]V_{ab}[/tex]I

Hence, B. is the correct option.

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The power being dissipated by the appliance is approximately 0.182 W.

To determine the power being dissipated by the appliance, we need to use Ohm's Law and the formula for power:

Ohm's Law: V = IR

where V is the voltage, I is the current, and R is the resistance.

Power formula: P = IV

where P is the power, I is the current, and V is the voltage.

First, let's find the current through the circuit:

V_battery = V_appliance + V_voltmeter

where V_battery is the voltage of the battery, V_appliance is the voltage across the appliance, and V_voltmeter is the voltage across the voltmeter.

Rearranging this equation to solve for V_appliance:

V_appliance = V_battery - V_voltmeter

V_appliance = 15.0 V - 11.3 V

V_appliance = 3.7 V

Now we can use Ohm's Law to find the current:

I = V_appliance / R

I = 3.7 V / 75.0 Ω

I = 0.0493 A

Finally, we can use the power formula to find the power:

P = IV

P = 0.0493 A x 3.7 V

P = 0.182 W

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--The complete question is, An idealized voltmeter is connected across the terminals of a 15.0 V battery. A 75.0 Ω appliance is also connected across the battery terminals. When the voltmeter measures 11.3 V, how much power is being dissipated by the appliance?--

With a current shunt, the current is obtained by measuring voltage across the current shunt and calculating using Ohm's Law.

A current shunt is a device that is used to measure electric current. It is a small resistor placed in parallel with the load (or the element being measured), that creates a known small voltage drop proportional to the current flowing through it.

By measuring this voltage drop and using Ohm's law, the current flowing through the shunt (and the load) can be calculated. Current shunts are commonly used in high-current applications, such as in power plants, electrical distribution systems, and electric vehicles.

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With a current shunt, the current is obtained by measuring the voltage drop across the current shunt and calculating using Ohm’s Law. A current shunt is a device that creates a low-resistance path for electric current, to allow it to pass around another point in the circuit. In current measuring, shunts allow the measurement of high current values by placing a resistor of low, known resistance in parallel with a voltmeter.

Answer:

From the power source we have to buy only energy.

Explanation:

Energy is released when an electron loses potential energy as a result of the transfer from higher state to lower state.

Electricity is the movement of electrons between atoms and it doesn't means we can isolate the electrons from the atom and sell it. It remains the part of atom and hence only energy can be purchase form the power company.

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On Mars, with an acceleration due to gravity of 3.71 m/s^2, the same falling mass of 15.0 kg would impart 55.6 J of kinetic energy to the rotating drum if it falls through the same height of 3.00 m, assuming all other factors remain the same.

The kinetic energy (K) imparted to the drum by the falling mass can be calculated using the formula:

where m is the mass of the falling object, and v is its velocity.

Since the object starts from rest, its initial velocity is zero, and we can simplify the formula to:

where u is the initial velocity of the falling object.

The potential energy (U) of the falling object is given by:

where g is the acceleration due to gravity and h is the height through which the object falls.

Since the potential energy is converted to kinetic energy, we can set U equal to K:

Simplifying the formula, we get:

Substituting the values given in the problem, we get:

Taking the square root of both sides, we get:

Using this velocity, we can calculate the kinetic energy imparted to the drum on earth:

To calculate the kinetic energy imparted to the drum on Mars, we can use the same formula, but with the acceleration due to gravity on Mars (3.71 m/s²):

Taking the square root of both sides, we get:

Using this velocity, we can calculate the kinetic energy imparted to the drum on Mars:

Therefore, the same falling mass of 15.0 kg would impart 55.6 J of kinetic energy to the rotating drum on Mars, which is less than the 350.0 J on earth due to the lower acceleration due to gravity.

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The structure of zinc telluride crystals is formed by a dense packing of anions, and cations occupy inter-nodes.

a) The structure of zinc telluride crystals is formed by a close packing of anions in a hexagonal close-packed (HCP) lattice. The stacking sequence of HCP lattice is ABABAB.

b) The cations occupy octahedral voids which are formed in between the closely packed anions.

c) In HCP lattice, there are 6 octahedral voids per unit cell. Each unit cell contains 2 zinc cations. Hence, the fraction of the available voids occupied by cations is 2/6 or 1/3.

d) Here is a depiction of two densely packed planes of anions stacked in the AB sequence with the voids filled with cations

 B           Cation in one octahedral void

  A       B       Cation in another octahedral void

        A           Anion

        A           Anion

  B       A       Cation in one octahedral void

        B           Cation in another octahedral void

The two densely packed planes of anions are labeled as A and B. Hence, The cations occupy the octahedral voids between these planes.

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When the combination of the metal, the calorimeter, and the water reaches at equilibrium, then, the final temperature of the system is 12.1°C.

First, we need to find the amount of heat lost by the metal and the amount of heat gained by the calorimeter and the water. We can use the formula;

Q = mc[tex]Δ_{T}[/tex]

where Q is amount of heat, m is the mass, c is specific heat capacity, and [tex]Δ_{T}[/tex] is the change in temperature.

The heat lost by the metal is;

Q₁ = mc[tex]Δ_{T}[/tex] = (0.2 kg)(1260 J/kg°C)(90°C - T)

where T is final temperature of the system.

The heat gained by the calorimeter and the water will be;

Q₂ = mc[tex]Δ_{T}[/tex] = [(0.5 kg + 0.1 kg)(4190 J/kg°C)](T - 20°C)

Setting Q₁ equal to Q₂ and solving for T;

(0.2 kg)(1260 J/kg°C)(90°C - T)

= [(0.5 kg + 0.1 kg)(4190 J/kg°C)](T - 20°C)

25.2 × 10⁴ J - 2520T

= 24.64 × 10⁴ J + 2095T

4615T = 0.56 × 10⁴ J

T = 12.1°C

Therefore, the final temperature of the system is 12.1°C.

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Paul Cezanne's Still Life with Apples in a Bowl (1879-83) represents a break with the tradition of using linear perspective in art.

One of the pioneers of modern art, Cezanne used a novel approach to painting at the time. In his still life paintings, Cezanne represented things utilizing a system of flattened planes and simplified forms rather than the conventional perspective techniques that provide the impression of depth and space.

Additionally, he played around with color, relying on color blocks rather than shading and modeling to convey a sense of volume and form.

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The tower's height would be around 143 m tall.

Solve for the length of the pendulum using the equation for the period of a simple pendulum.

T = 2π√(l/g)

where l = length of pendulum which is equal to height of tower because it touches the almost the floor

T = time, 24 seconds and

g = acceleration due to gravity 9.8 m/s².

Substitute the given values:

24s = 2π√(l/ 9.8 m/s²)

24/2π = √(l/ 9.8 m/s²)

l = (24/2π)² x 9.8 m/s²

l = (12/π)² x 9.8 m/s²

l = 14.59 x 9.8 m/s²

l = 142.982

Therefore, the height of the tower would be 143 m approximately.

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Answer:

We can find the position of the center of mass of the system by using the formula:

Xcm = (m1x1 + m2x2 + m3x3 + m4x4) / (m1 + m2 + m3 + m4)

where Xcm is the x-coordinate of the center of mass, m1, m2, m3, and m4 are the masses of the point masses, and x1, x2, x3, and x4 are their respective x-coordinates.

Similarly, we can find the y-coordinate of the center of mass using the formula:

Ycm = (m1y1 + m2y2 + m3y3 + m4y4) / (m1 + m2 + m3 + m4)

where Ycm is the y-coordinate of the center of mass, m1, m2, m3, and m4 are the masses of the point masses, and y1, y2, y3, and y4 are their respective y-coordinates.

Let's label the masses and coordinates as follows:

m1 = 2kg, x1 = 0cm, y1 = 0cm

m2 = 4kg, x2 = 2cm, y2 = 0cm

m3 = 6kg, x3 = 2cm, y3 = 2cm

m4 = 8kg, x4 = 0cm, y4 = 2cm

Substituting these values into the formulas, we get:

Xcm = (2kg x 0cm + 4kg x 2cm + 6kg x 2cm + 8kg x 0cm) / (2kg + 4kg + 6kg + 8kg) = 2cm

Ycm = (2kg x 0cm + 4kg x 0cm + 6kg x 2cm + 8kg x 2cm) / (2kg + 4kg + 6kg + 8kg) = 1cm

Therefore, the center of mass of the system is located 2cm from corner A in the x-direction and 1cm from corner A in the y-direction.

Explanation:

The internal resistance of the battery is approximately 24.5 Ω, and the answer is A. 24.5 Ω. Option A is correct.

We can use the equation for the total resistance of the circuit and the voltage measured by the voltmeter to find the internal resistance of the battery.

The total resistance of the circuit can be expressed as:

R_total = R_internal + R_appliance

where R_internal is the internal resistance of the battery, and R_appliance is the resistance of the 75.0 Ω appliance.

The current through the circuit can be found using Ohm's Law:

I = V_total / R_total

where V_total is the voltage of the battery, which is 15.0 V in this case.

We can also use Ohm's Law to find the voltage across the appliance:

V_appliance = IR_appliance

where I is the current through the circuit, and R_appliance is the resistance of the appliance.

We can use the voltage measured by the voltmeter to find the voltage across the internal resistance of the battery:

V_internal = V_battery - V_appliance

where V_battery is the voltage of the battery, which is 15.0 V, and V_appliance is the voltage across the 75.0 Ω appliance, which can be found using Ohm's Law.

Substituting the equations above and the given values into the expression for the current:

I = V_total / R_total

I = 15.0 V / (R_internal + 75.0 Ω)

I = (11.3 V / V_total) x 15.0 V / (R_internal + 75.0 Ω)

Simplifying and solving for R_internal, we get:

R_internal = (15.0 V - 11.3 V) / (11.3 V / 15.0 V - 1) - 75.0 Ω

R_internal = 24.5 Ω

Option A is correct.

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The  new mass of the man will be   7.0 x 10^4 kg.

Mass (symbolized m) is described as a dimensionless quantity representing the amount of matter in a particle or object.

Let us say that the density of the man's body remains constant,

we have the new mass to be  10^3 = 1000 times greater than his original mass.

New mass = 1000 x M

mass of an adult male = 70 kg (This value is an assumed value)

New mass = 1000 x 70 kg

New mass = 7.0 x 10^4 kg

New mass =7.0 x 10^4 kg

Therefore, the new mass of the man is found to be   7.0 x 10^4 kg.

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Answer:

An electromagnet is a type of magnet that is created by an electric current flowing through a coil of wire wrapped around a magnetic core. The core is usually made of a ferromagnetic or ferrimagnetic material, such as iron, that can increase the magnetic field strength by hundreds or thousands of times.

The effects on an electromagnet of removing or replacing the core depend on the properties of the core material. Here are some possible effects:

i) Removing the core: This will reduce the magnetic field strength of the electromagnet, as the core material is no longer concentrating the magnetic field lines. The electromagnet will become an air-core coil, which has a much lower magnetic permeability than a ferromagnetic or ferrimagnetic core. The electromagnet will also lose its ability to retain some magnetism when the current is switched off, as the core material is no longer magnetized.

ii) Replacing the iron core with a steel core: This will change the magnetic field strength and the magnetic behavior of the electromagnet, depending on the type and quality of steel used. Steel is an alloy of iron and other elements, such as carbon, manganese, nickel, chromium, etc. Some types of steel have higher magnetic permeability than iron, which means they can increase the magnetic field strength more than iron. However, some types of steel have lower magnetic permeability than iron, which means they can decrease the magnetic field strength. Steel also has higher coercivity and hysteresis than iron, which means it can retain more magnetism when the current is switched off, but it also requires more energy to magnetize and demagnetize. Steel can also be affected by temperature changes, corrosion, and mechanical stress, which can alter its magnetic properties over time.

(i) The work done on the point charge by the electric force when moved from A to B is 2.1 x 10⁻⁶ J.

(ii) The work done on the point charge by the electric force when moved from A to C is -5.5 x 10⁻⁶ J.

The work done by an electric force is equal to the negative of the change in potential energy, which is given by the product of the charge and the change in potential. The change in potential between two points is equal to the potential difference between those points.

For (i), the potential difference between A and B is 6 V, so the work done is (3.9 x 10⁻⁷ C) x (-6 V) = -2.1 x 10⁻⁶ J (negative because the charge moves from higher to lower potential).

For (ii), the potential difference between A and C is -15 V, so the work done is (3.9 x 10⁻⁷ C) x (-(-15 V)) = -5.5 x 10⁻⁶ J (negative because the charge moves from lower to higher potential).

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Answer:

When you add 20 ml of vegetable oil to a beaker filled with half water and 20 ml of honey, the honey will settle at the bottom of the beaker, the vegetable oil will float on top of the water, and the honey will form a layer between the vegetable oil and the water. This happens because honey is denser than water, while vegetable oil is less dense than water. The difference in density causes the honey to sink to the bottom, while the vegetable oil floats to the top. Honey and vegetable oil are not miscible because they are not chemically compatible. They are both made up of different types of molecules, which do not mix together. Honey is made up of a complex mixture of sugars, while vegetable oil is made up of triglycerides. These different molecules do not dissolve into each other, which is why they separate into distinct layers in the beaker.

Hope this helps.

The wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.

Frequency is the number of cycles of a periodic waveform that occur per unit of time. It is measured in Hertz (Hz).

We can use the equation λ=2L/n, where λ is the wavelength, L is the length of the string, and n is the harmonic number. Since the string has fixed ends, the harmonics must be odd-numbered, so we have n=1 for the fundamental frequency, n=3 for the second harmonic (315 Hz), and n=5 for the third harmonic (420 Hz).

Using n=1 and λ=2L/n, we get:

λ = 2L/1

λ = 2L

Using n=3 and λ=2L/n, we get:

λ = 2L/3

Using n=5 and λ=2L/n, we get:

λ = 2L/5

We can use the formula f=v/λ to relate the wave speed v, wavelength λ, and frequency f. For the two consecutive harmonics, we can write:

v/λ1 = f1

v/λ2 = f2

Since the two harmonics are consecutive, we can assume that they correspond to adjacent values of n, so we have:

λ1 = 2L/1 = 2L

λ2 = 2L/3

Substituting these values into the above equations and solving for v, we get:

v = f1λ1 = f2λ2 = (420 Hz)(2L) / (2L) = (315 Hz)(2L)/(2L/3) = 840 cm/s

To find the fundamental frequency, we use the formula f=v/λ1:

f = v/λ1 = 840 cm/s / 2L = (840 cm/s) / (0.75 m) = 1120 Hz

Therefore, the wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.

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Therefore, the frequency of oscillation when the spring is connected 1/5 of the way from the pivot to the end of the rod is approximately 1.34 Hz.

Since the rod is thin and uniform, its moment of inertia about the pivot point can be approximated as:

I = (1/3)ML^2

When the spring is connected 1/5 of the way from the pivot to the end of the rod, the effective length of the rod becomes:

l_eff = l/5 + (4/5)(l/2) = 9l/10

So, the frequency of oscillation is: 8.42 rad (after calculations)

The frequency of oscillation when the spring is connected 1/5 of the way from the pivot to the end of the rod is approximately 1.34 Hz.

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Answer:

The gravitational force, or gravity, is the downward force that causes objects to fall towards the surface of a planet or natural satellite. It is computed by multiplying the mass of an object with the acceleration due to gravity of the planet or natural satellite.

Answer:

The velocity of the box is related to the angular velocity of the spool, which is given by the equation:

v = r * ω

where r is the radius of the spool and ω is the angular velocity of the spool. The angular velocity of the spool, in turn, is related to the torque applied to the spool by the tension in the string, which is given by the equation:

τ = I * α

where τ is the torque, I is the moment of inertia of the spool, and α is the angular acceleration of the spool.

The tension in the string is equal to the weight of the box, which is given by:

T = m * g

Putting all of these equations together, we can solve for the time it takes for the box to reach the floor. Here's how:

First, we can find the angular acceleration of the spool using the torque equation:

τ = I * α

T = m * g = τ

m * g = I * α

α = (m * g) / I

α = (35.30 kg * 9.81 m/s^2) / 4.00 kg*m^2

α = 86.53 rad/s^2

Next, we can find the angular velocity of the spool using the kinematic equation:

ω^2 = ω_0^2 + 2 * α * θ

where ω_0 is the initial angular velocity (which is zero), θ is the angle through which the spool has turned (which is equal to the distance the box has fallen divided by the radius of the spool), and ω is the final angular velocity (which is what we want to find). Solving for ω, we get:

ω^2 = 2 * α * θ

ω = sqrt(2 * α * θ)

ω = sqrt(2 * 86.53 rad/s^2 * (3.50 m / 0.10 m))

ω = 166.6 rad/s

Finally, we can find the time it takes for the box to reach the floor using the equation:

v = r * ω

v = 0.10 m * 166.6 rad/s

v = 16.66 m/s

t = d / v

t = 3.50 m / 16.66 m/s

t = 0.21 s

As thermal energy is added to a sample of water, the potential energy of its molecules increases, and then the kinetic energy of its molecules increases.

The sections of the heating curve illustrate this process  is B followed by D

Therefore option A is correct.

Thermal energy (also called heat energy) is described as being produced when a rise in temperature causes atoms and molecules to move faster and collide with each other.

some factors of thermal energy include:

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46)

Since air resistance is ignored, both cannonballs will fall with the same acceleration due to gravity, which is approximately 9.8 m/s^2. The horizontal velocity of cannonball A does not affect its vertical motion, so it will fall at the same rate as cannonball B.

The time it takes for an object to fall to the ground from a certain height is given by the formula t = sqrt(2h/g), where t is the time, h is the initial height, and g is the acceleration due to gravity.

For cannonball B, which is dropped from a height of 20 meters, the time it takes to reach the ground is:

t = sqrt(2h/g) = sqrt(2*20/9.8) = 2.02 seconds

For cannonball A, which is fired horizontally with a velocity of 5 m/s, the time it takes to reach the ground is also 2.02 seconds, since the vertical motion is the same as cannonball B.

Therefore, both cannonballs will hit the ground at the same time.

47)

The recoil speed of the cannon can be calculated using the principle of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it.

Before firing, the total momentum of the system is zero, since the cannon and cannonball A are at rest. After firing, the cannonball A has a momentum of 5 kg * 5 m/s = 25 kg m/s to the right, so the cannon must have an equal and opposite momentum to the left in order to conserve momentum.

The mass of the cannon is 500 kg, so its momentum after firing will be:

p = -25 kg m/s

The velocity of the cannon can be found using the equation:

p = mv

where p is the momentum, m is the mass, and v is the velocity. Solving for v, we get:

v = p/m = (-25 kg m/s) / (500 kg) = -0.05 m/s

Since the momentum of the cannon is negative, the recoil velocity is also negative, indicating that the cannon will move to the left after firing. The magnitude of the recoil velocity is 0.05 m/s, or approximately 0.18 km/h.

The initial temperature of the water was 0°C and the original temperature of the ice was -78.8°C.

First, we need to determine how much heat was transferred from the water to the ice to melt the ice and raise its temperature to 0°C.

The heat is required to melt the ice will be;

Q₁ = m_ice x Lf

where m_ice is the mass of the ice and[tex]L_{f}[/tex] is the latent heat of fusion of ice.

Q₁ = 1.0 kg x 3.3 x 10⁵ J/kg

= 3.3 x 10⁵ J

The heat required to raise the temperature of the melted ice from -x°C to 0°C is;

Q₂ = m_ice x c_ice x ΔT

where c_ice is the specific heat capacity of ice and ΔT is the change in temperature.

Q₂ = 1.0 kg x 2093 J/kg.°C x (0 - (-x))°C

= 2093x J

The heat lost by the water will be equal to the heat gained by the ice;

Q₁ + Q₂ = m_water x Cw x ΔT

where m_water is the mass of the water and Cw is the specific heat capacity of water.

3.3 x 10⁵ J + 2093x J = 1.0 kg x 4186 J/kg.°C x (0 - T)°C

Solving for T, we get;

T = -[(3.3 x 10⁵ J + 2093x J)/(4186 J/kg.°C)]

= -78.8°C

Therefore, the original temperature of the ice was -78.8°C.

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The electric heater draws a current of 4.5 amps.

Using Ohm's Law, we can calculate the current drawn by the electric heater. Ohm's Law states that the current (I) flowing through a conductor is equal to the voltage (V) applied to the conductor divided by its resistance (R):

In this case, the voltage (V) is 120 V and the power (P) of the electric heater is 540 W. We can use the formula P = VI, where P is the power in watts, V is the voltage in volts, and I is the current in amperes. Solving for I, we get:

Therefore, the electric heater draws a current of 4.5 amperes (A) when operated at 120 volts (V).

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Answer:

3 N.

Explanation:

If you want to know how much two charges push or pull each other, you can use Coulomb's law. It says that the force F depends on how big the charges are (Q and q) and how far apart they are (r). The bigger the charges and the closer they are, the stronger the force. The smaller the charges and the farther they are, the weaker the force. The exact formula is:

F = k | Q q | / r 2

where k is a number that makes everything work out right. It's about 8.99 × 10 9 N ⋅ m 2 / C 2 .

Now let's say you have two charges that are a certain distance r 0 apart and they have a force F 0 between them. What happens if you move them twice as far apart? The new distance is 2 r 0 and the new force is F 1 . How do F 1 and F 0 compare? Well, you can use Coulomb's law again and divide them:

F 1 / F 0 = (k | Q q | / (2 r 0 ) 2 ) / (k | Q q | / r 0 2 )

If you simplify this, you get:

F 1 / F 0 = (1/2) 2

F 1 / F 0 = 1/4

This means that the new force is only one-fourth of the old force. So if the old force was 12 N, then the new force is:

F 1 = F 0 /4

F 1 = (12 N) /4

F 1 = 3 N

So moving the charges twice as far apart makes the force four times weaker. It goes from 12 N to 3 N.

Letter F shows the ball when it has the maximum kinetic energy.

Letter A shows the ball when it has the maximum potential energy.

Letter G shows the ball when it has the least kinetic energy.

Letter C shows the ball when it has the least potential energy.

The kinetic energy of an object is  described as the form of energy that it possesses due to its motion.

potential energy  on the hand is described as  the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.

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