el valor númerico del término n=15 de la sucesión 5 20 80... es?​

Answers

Answer 1

Answer:

É 5x3=15

Step-by-step explanation:


Related Questions

line passes through the points (4,-2) and the slope is 5/4 write an equation in slope intercept form

Answers

Answer:

y=5/4x -7

Step-by-step explanation:

Hope this helps!

Which equation has the same solution as w / 3.9 = 3? A. w+0.6=1.9 B. w-0.6 = 11.1 C. w+1.03=2.93 D. w-1.03=8.24

Answers

The equation has the same solution as w / 3.9 = 3 is w+0.6=1.9

Given:

w / 3.9 = 3

cross multiply

w × 3 = 3.9

3w = 3.9

divide both sides by 3

w = 3.9 / 3

w = 1.3

Check all that applies

A. w+0.6=1.9

w = 1.9 - 0.6

w = 1.3

B. w-0.6 = 11.1

w = 11.1 + 0.6

w = 11.7

C. w+1.03=2.93

w = 2.93 - 1.03

w = 1.9

D. w-1.03=8.24

w = 8.24 + 1.03

w = 9.27

Therefore, the equation has the same solution as w / 3.9 = 3 is w+0.6=1.9

Learn more about equation:

https://brainly.com/question/2972832

Heheh... uhm, yeah, I don't do best with algebraic questions-

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Answer:it's a for sure I think

.I want a way to solve this question​

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Check the picture below.

so then γ ≈ 180 - 69 - 43, γ ≈ 68.

Plz help me well mark brainliest only if correct!…

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B. Is the answer. As it is the best simplest form

I need help with this question

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Answer: bro I don’t if this is correct but try 11+3i

What is the slope of the line?

Answers

3/1 is the answer follow the line

slope:change in x\change in y


[tex]2 log_{3}(8) - 3 log_{3}(2) [/tex]
what is the answer to the question​

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We have:   2log₃(8) - 3log₃(2) = 2log₃(8) - log₃(2³)

= 2log₃(8) - log₃(8) =  log₃(8)

= 1,892789261 ≈ 1,9

ok done. Thank to me :>

Answer:

~1.8928 or 3log_3 (2)

Step-by-step explanation:

change 8 to 2^3 and move to front

=2*3log_3 (2) -3log_3 (2)

=6log_3 (2) -3log_3 (2)

with subtraction

=3log_3 (2)

approx with calculator

~1.8928

What is the answer to the following question?

Answers

Answer:

  SAS similarity

Step-by-step explanation:

You have two side ratios and the angle between the sides with those ratios. The appropriate similarity theorem is SAS.



Which term has the definition "A relationship in which two variables change at the same rate

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positive correlation

(i believe thats what it is)

Which type of correlation does this scatterplot show?

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Positive correlation. Y varies directly with x. Meaning as x increases or decreases, Y will behave the same as x.

guys help plzz i need your help

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Answer:

it correct because i took this before

Please help me with this please

Answers

The answer is 30

1. Find the equilateral triangle angles in this case all of them are 60
2. 90-60 to right the opposite angle that is divided in the right angle
3. The answer should be the same as angle 2

1+3+5+...+X=441
X=? ​

Answers

Answer:

559

Step-by-step explanation:

Can someone check my answer?? PLEASE-

The length of a rectangle is six more than the width. If the perimeter of the rectangle is 40 ft, find the length of the rectangle.

A. 13 ft (what I think) ****

B. 7 ft

C. 23 ft

D. 17 ft

Answers

Answer:

the length of the rectangle is 13 ft.

Step-by-step explanation:

width of a rectangle x ft

length of a rectangle x+6 ft

the perimeter of the rectangle is 40 ft,

2(x+x+6) = 40

2x+6 = 20

2x = 14

x = 7

So the length of the rectangle is x+6 = 7+6 = 13 ft

congrats you're right (≧▽≦)!!

Answer:

The correct answer ia A)13 ft

Step-by-step explanation:

hope this helps

Find the equation of a line that intersects with y=2x-1 on the y-axis and is parallel to y=-x. Please explain.

Answers

Answer:

so where does that line intersect the y axis? just plug in x=0 and you see y= -1. so (0, -1)

y = -x -1 is parallel because it has the same slope and goes through the right point

Find an equation of the line having the given slope and containing the given point. Slope 7 through (6,3)​

Answers

[tex](\stackrel{x_1}{6}~,~\stackrel{y_1}{3})~\hspace{10em} \stackrel{slope}{m}\implies 7 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{7}(x-\stackrel{x_1}{6}) \\\\\\ y-3=7x-42\implies y = 7x-39[/tex]

Answer:

[tex]y-3=7(x-6)[/tex]

Step-by-step explanation:

Pre-Solving

We are given that a line has a slope (m) of 7 and passes through the point (6,3).

We want to write the equation of this line.

There are three ways to do it:

Slope-intercept form, which is y=mx+b where m is the slope and b is the value of y at the y-intercept.Point-slope form, which is [tex]y-y_1=m(x-x_1)[/tex] where m is the slope and [tex](x_1,y_1)[/tex] is a point. Standard form, which is ax+by=c where a, b, and c are free integer coefficients.

As the question doesn't specify, either form should work, but let's write the equation in point-slope form as that's the easiest to do.

Solving

As we are already given both the point and the slope, we can plug them both into the equation.

Starting with the slope, substitute 7 for m.

[tex]y-y_1=7(x-x_1)[/tex]

Now, substitute 6 as [tex]x_1[/tex] and 3 as [tex]y_1[/tex].

[tex]y-3=7(x-6)[/tex]

An office clerk earns $120 for two 4-hour work shifts. How much will she earn
for 15 hours of work?

Answers

Answer:

$225

Step-by-step explanation:

$120 for 2 4-hour shifts, $120 in 8 hours

$15 every 1 hour

Money for 15 hours: 15 x 15 = $225

The office clerk earns $225 for 15 hour of work .

What is unitary method?

The formula of the unitary method is to find the value of a single unit and then multiply the value of a single unit to the number of units to get the necessary value.

According to the question

An office clerk earns $120 for two 4-hour work shifts.

i.e

In 2 * 4-hour work shifts office clerk  earns = $120

or

In 8 hour work shifts office clerk earns = $120

Now ,

By using unitary method

In 1 hour  work shifts office clerk earns = $[tex]\frac{120}{8}[/tex]

                                                                = $15

Therefore, for 15 hours of work shifts office clerk earns =  $15 * 15

                                                                                          = $225

Hence, The office clerk earns $225 for 15 hour of work .

To know more about unitary method here:

https://brainly.com/question/23423168

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The formula for finding the perimeter of a rectangle is P = 2L + 2W. If a rectangle has a perimeter of 68 inches and the length is 14 inches longer than its width, find the width.

Answers

Answer:

width(w)= 20inches

Step-by-step explanation:

solution,

given,

perimeter of a rectangle (P)=68inches

length of rectangle= 14 inches

we know,

perimeter of a rectangle=2L + 2W

or,68=2×14+2×w

or,68-28=2w

or,40=2w

or,w=40÷2

or,w=20inches.

I will give u a crown The rectangles below are similar in shape and their sides are proportional. The large rectangle is 42 feet tall and 54 feet wide. The smaller rectangle is 36 feet wide. How tall is the smaller rectangle? *

Answers

Answer:

28ft tall

Step-by-step explanation:

Since they are proportional, you can set up a ratio of length to width.

L/W=L/W

42/54=L/36

L=(42*36)/54

L=28

I need this soon pls

Answers

3 -4 is the answer

Its (x, y) so the x is first and the y is last

Which equation correctly uses the law of cosines to solve for y? 92 = y2 + 192 – 2(y)(19)cos(41°) y2 = 92 + 192 – 2(y)(19)cos(41°) 92 = y2 + 192 – 2(9)(19)cos(41°) y2 = 92 + 192 – 2(9)(19)cos(41°) PLS HELP!!

Answers

Answer:

[tex]Fourth \: option: y^2=9^2+19^2-2(9)(19) cos(41°)[/tex]

[tex]The \: law \: of \: cosines \: to \: solve \: for \: one \: side  \: is:[/tex]

[tex]c^2=a^2+b^2-2ab \: cos \: C[/tex]

We must know the other two sides (a and b) and the angle between these sides (angle C, the opposite to the side that we want to determine)

In this case c=y, a=9, b=19, and C=41°, then:

[tex]y^2=9^2+19^2-2(9)(19) \: cos \: (41°)[/tex]

Find the area for each of the given shapes below. If a shape has shading, find the area of the shaded region only.

Answers

Answer:

  a.  39 ft²

  c. 2x² +11x +12

  e. 35 yd²

Step-by-step explanation:

a.

The missing vertical dimension is 5-3 = 2'. The missing horizontal dimension is 11-8 = 3'. Then the figure can be decomposed into a rectangle 11'×3' and one that is 3'×2'. The sum of those areas is ...

  total area = (11 ft)(3 ft) +(3 ft)(2 f) = (3 ft)(11 +2 ft) = (3 ft)(13 ft) = 39 ft²

__

c.

We don't know what to make of the rectangles in each corner, so we'll assume they are distorted right-angle indicators. The area is the product of the dimensions shown:

  A = LW

  A = (2x +3)(x +4) = 2x² +11x +12 . . . area of figure

__

e.

The shaded area is half the area of the rectangle. That is the same area you get if you use the triangle formula for the area of the shaded triangle.

  A = 1/2(14 yd)(5 yd) = 35 yd²

I REALLY NEED HELP WITH QUESTION!! URGENTLY!! ANYONE WHO'S GOOD AT MATHS ​

Answers

Check the picture below.

there are a few angles shaded, I'll call that angle at O ∡O, and that angle at "x" ∡x and the green angle at A, ∡A, and the angle at B, ∡B, just so you know which angle we're referring to.

well, first off let's notice that B and C are points of tangency, meaning we get right-angles as you see in the picture, if we run an angle bisector from ∡x, towards point O, we get two congruent triangles, lemme shorten that up some, 90 + 90 + ∡O +∡x = 360, which means that ∡O + ∡x = 180,  meaning that ∡O = 180 - ∡x, if that's so, the angle at point O across the shade, is 360 - ∡O or 360 - (180 - ∡x).

alrighty, by the inscribed angle theorem, ∡A is half of ∡O.

let's now focus on the triangle AOB, we'll be using half of ∡A and half of ∡O and ∡B on that triangle, let's proceed.

[tex]\measuredangle x + \measuredangle O=180\implies \measuredangle O=180-\measuredangle x \\\\\\ \measuredangle A = \cfrac{\measuredangle O}{2}\implies \measuredangle A = \cfrac{180-\measuredangle x}{2} \\\\\\ \stackrel{\textit{the angle across from }\measuredangle O~is}{360-\measuredangle O}\implies 360-(180 - \measuredangle x)\implies 180+\measuredangle x \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{\large the sum of all three angles at }\triangle AOB}{\stackrel{\textit{half of }\measuredangle A}{\cfrac{1}{2}\cdot \cfrac{180-\measuredangle x}{2}}~~ + ~~\stackrel{\textit{half the angle across from }\measuredangle O}{\cfrac{180+\measuredangle x}{2}}~~ +~~\measuredangle B~~ =~~180} \\\\\\ \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B = 180[/tex]

now, let's multiply both sides by the LCD of all denominators, hmmmm in this case that'll be 4, so multiplying both sides by the LCD will do away with the denominators, so let's do so.

[tex]4\left( \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B \right) = 4(180) \\\\\\ (180-\measuredangle x)+2(180+\measuredangle x)+4\measuredangle B = 720 \\\\\\ (180-\measuredangle x)+(360+2\measuredangle x)+4\measuredangle B = 720\implies 540+\measuredangle x+4\measuredangle B = 720[/tex]

[tex]\measuredangle x+4\measuredangle B = 180\implies 4\measuredangle B = 180-\measuredangle x\implies \measuredangle B = \cfrac{180-\measuredangle x}{4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \measuredangle B = 45 - \cfrac{\measuredangle x}{4}~\hfill[/tex]

One positive integer is 5 times another positive integer and their product is 320. What are the positive integers?​

Answers

Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
x = 5y
xy = 320

Substitute the first equation into the second equation
(5y)(y) = 320
5y^2 = 320
y^2 = 64
y = 8 (y must be positive)

The integers are (x, y) = (40, 8).

How many pennies dose Michael please help please I need your help please please please please help

Answers

Answer: He has 91, to figure this out count everything in top row which is 13 and then count everything in left row only which is 7 and 13 x 7 is 91

Step-by-step explanation:

Which of the following is not considered a buying incentive?
a coupon
b. display
C. prize
d. rebate
Please select the best answer from the choices provided
A
B
C
D

Answers

Answer: B) Display

=============================================

Explanation:

A buying incentive is anything that encourages any potential customers to become actual customers. Ideally, those people are repeat customers down the road as well (even if such buying incentives are no longer in place).

If someone sees a coupon or a rebate, then they'll be more likely to buy the item since the price is lower. A coupon is an immediate discount right on the spot, whereas a rebate is when you get a discount later on. A rebate means you have to mail in proof of purchase, and the company will send money back. These are two ways to apply a discount.

A third way to entice customers is to offer prizes. An example of this is a "buy one get one" sale (often abbreviated as BOGO). The company may lose money doing this, but they do so in the hopes of gaining new customers. Plus word of mouth tends to spread more often when such sales occur.

With everything discussed so far, this allows us to rule out choices A, C and D. They are all some kind of way to encourage potential buyers. Choice B is the answer because a display simply shows the price and any other relevant info to the product. Displays are neutral in the sense that they don't encourage a purchase and rather just convey information. When I mention this, I'm not talking about displays that advertise discounts or coupons.

Is (-2,-6) a solution of y < 7+ + 8?

Answers

Answer:

rthrthrt

Step-by-step explanation:

i need help with this

Answers

Answer:

Yes Jeff is the correct answer

Step-by-step explanation:

please help me with this math problem please I need help

Answers

is 1.25 because you just add them together

Other Questions
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Next came Peter, who wished to be an Engineer when he grew up; and the youngest was Phyllis, who meant extremely well.Mother did not spend all her time in paying dull calls to dull ladies, and sitting dully at home waiting for dull ladies to pay calls to her. She was almost always there, ready to play with the children, and read to them, and help them to do their home-lessons. Besides this she used to write stories for them while they were at school, and read them aloud after tea, and she always made up funny pieces of poetry for their birthdays and for other great occasions, such as the christening of the new kittens, or the refurnishing of the doll's house, or the time when they were getting over the mumps.These three lucky children always had everything they needed: pretty clothes, good fires, a lovely nursery with heaps of toys, and a Mother Goose wall-paper. They had a kind and merry nursemaid, and a dog who was called James, and who was their very own. 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