The amount of water flowing at that time from the 2inch outlet is 16 gallons per minute
What is flow rate?Flow measurement, a quantification of bulk fluid movement, is another term for flow rate. The mass of a material that moves per unit of time is known as the mass flow rate. The amount of fluid moving per unit of time is known as the volumetric flow rate.
More ideas on how we arrived at the answer
The 1-inch outlet is flowing at 8 gallons per minute.
Now Because the 2-inch outlet is twice the size of the 1-inch outlet, it is flowing at twice the rate or 16 gallons per minute.
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A hummingbird gains a significant electric charge while flying and feeding. This has consequences: When a charged bird approaches a flower (Figure 1), the stamens of the flower bend toward the bird, even though the stamans are uncharged. Part A Explain how this happens Drag the terms on the left to the appropriate blanks on the right to complete the sentences. Reset Help toward The charge of the hummingbird ____ the stamen polarizes The charged opposite to the bird's charge particles of the stamen move ___ the bird, and like charged particles move ____the bird Therefore, the net electric force on the stamen is directed ____the hummingbird Submit Request Answer
When a hummingbird is flying and feeding, it gains a significant electric charge. When a charged bird approached a flower, the stamens of the flower (the part that produces pollen) bent toward the bird because it got polarized. This electrostatic charge is useful for a flower's reproduction process. Charged pollen can settle more effectively.
Attached below is the figure with the full question.
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An inventor is applying for a patent. He claims his new heat engine can produce 1,200 J of work for every 1,800 J of heat applied to it. In 3–5 sentences, evaluate this claim after solving for η.
will mark brainiest, need help asap
The efficiency, η, of the new engine would be 0.67.
Efficiency calculationBased on the given information, the inventor's new heat engine has an efficiency of:
η = work output / heat input = 1,200 J / 1,800 J = 0.67
This means that for every 1,800 J of heat applied to the engine, only 1,200 J of work can be produced, and the remaining 600 J of heat energy is lost as waste heat.
While an efficiency of 0.67 is relatively high for a heat engine, it is important to note that the practicality and potential applications of the engine cannot be evaluated solely based on its efficiency.
Other factors such as cost, durability, and scalability would also need to be considered in determining the viability of this invention.
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It is said that Archimedes discovered his principle during a bath while thinking about how he could determine if King Hiero's crown was actually made of pure gold. While in the bathtub, he conceived the idea that he could determine the average density of an irregularly shaped object by weighing it in air and also in water. If the crown weighed 3.55 kgf (= 34.8 N) in air and 3.25 kgf (= 31.9 N) in water, determine if the crown is made of pure gold. The density of gold is 19, 300 kg/m^3 Discuss how you can solve this problem without weighing the crown in water but by using an ordinary bucket with no calibration for volume. You may weigh anything in air.
The crown is not made of pure gold as the density of the material is found to be less than gold.
Archimedes observed that every solid, regardless of shape, will experience an upward force when submerged in a liquid that is equal to the weight of the amount of liquid that the solid has extracted.
So, if any body is weighed in air, the normal force will be equal to the gravity force (which we call weight) which can be expressed as follows:
Fg = m g = δ V g = 34.8 N
When submerged in water, the normal force is equal to the difference between the actual weight, and the upward force due to Archimedes' principle, called buoyant force, as follows:
Fn = Fg - Ep = δx. V. g - δH₂O . V. g = 31.9 N
By dividing Fg into Fn and condensing commonly used terminology, we obtain:
δx / (δx - δH₂O) = 34.8 / 31.9 = 1.09
Solving for δx, we get the following value:
δx = 10,900 Kg/m³, less dense than pure gold, so we can conclude that the crown was not made of pure gold.
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If the Earth's diameter is 12,756 km (7,922 miles) at the equator, how far is one degree of longitude at the equator (give both miles and kilometers)? First find: the Earth's circumference: (C = 2īr; r = radius, n = 3.14). How many degrees are there in a circle (360)? Divide the Earth's circumference by the number of degrees to get your answer. 2-3. How many miles and kilometers are there in one minute of longitude at the equator? 2-4. How many miles and kilometers are there in one second of longitude at the equator?
One degree of longitude at the equator is 111.32 kilometers (69.17 miles), one minute of longitude is 1.855 kilometers (1.153 miles), and one second of longitude is 0.031 kilometers (0.019 miles).
At the equator, one degree of longitude corresponds to 1/360th of the circumference of the Earth, which can be calculated as:
C = 2*π*r where C is the circumference, r is the radius of the Earth.
The radius of the Earth is half of its diameter, so:
r = 12,756 km / 2 = 6,378 km
Thus, the circumference of the Earth at the equator is:
C = 2*π*(6,378 km) ≈ 40,075 km
So, one degree of longitude at the equator is:
40,075 km / 360 ≈ 111.32 km
Or in miles:
24,901 miles / 360 ≈ 69.17 miles
To find the distance in one minute of longitude, we need to divide by 60:
111.32 km / 60 ≈ 1.855 km/min
69.17 miles / 60 ≈ 1.153 miles/min
To find the distance in one second of longitude, we need to divide by 60 again:
1.855 km/min / 60 ≈ 0.031 km/sec
1.153 miles/min / 60 ≈ 0.019 miles/sec
Therefore, one degree of longitude at the equator corresponds to approximately 111.32 kilometers (69.17 miles), one minute of longitude corresponds to approximately 1.855 kilometers (1.153 miles), and one second of longitude corresponds to approximately 0.031 kilometers (0.019 miles).
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consider a 5-m-high, 8-m-long, and 0.22-m-thick wall whose representative cross section is as given in the figure. the thermal conductivities of various material used, in w/m.k, are kA=kF=2,kC=20,kD=15 and kE = 35. The left and right surfaces of the wall are maintained at uniform temperatures 300C and 100C,respectively. Assuming heat transfer through the wall to be one-dimensional, determine
(a) the rate of heat transfer through the wall;
(b) the temperature at the point where the sections B, D, and E meet; and
(c) the temperature drops across the section F. Disregard any contact resistances at the interfaces.
The total thermal resistance of the wall can be found by summing the thermal resistances of each section:
= 4.277 m^2.K/W
To determine the rate of heat transfer through the wall, we can use Fourier's law of heat conduction which states that the rate of heat transfer through a material is proportional to the temperature gradient across the material, and can be expressed as:
q = -kA * dT/dx
where q is the rate of heat transfer, kA is the thermal conductivity of the material, dT/dx is the temperature gradient, and the negative sign indicates that heat flows from higher temperatures to lower temperatures.
(a) To find the rate of heat transfer through the wall, we need to first determine the thermal resistance of each section of the wall. The thermal resistance is given by:
R = L / k
where R is the thermal resistance, L is the length of the material, and k is the thermal conductivity.
Using this equation, we can find the thermal resistance of each section as follows:
[tex]R_A = 5 / 2 = 2.5 m^2.K/W[/tex]
[tex]R_B = 0.22 / 35 = 0.0063 m^2.K/W[/tex]
[tex]R_C = 5 / 20 = 0.25 m^2.K/W[/tex]
[tex]R_D = 0.22 / 15 = 0.0147 m^2.K/W[/tex]
[tex]R_E = 0.22 / 35 = 0.0063 m^2.K/W[/tex]
[tex]R_F = 3 / 2 = 1.5 m^2.K/W[/tex]
(b) To find the temperature at the point where sections B, D, and E meet, we can assume that there is no heat generation within the wall (i.e., steady-state conditions), so the temperature at any point within the wall is the same in the x-direction. Therefore, we can use the thermal resistance network to find the temperature drop across each section:
ΔT_A = (300 - 100) = 200°C
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As you read through the Case Study of Cold Fusion, Cite evidence in the text for or against science.
Answer:Cold fusion: A case study for scientific behavior ... Scientists take into account all the available evidence when deciding whether to accept an idea or not ...
Explanation:
A car starts from rest on a curve with a radius of 100 m and tangential acceleration of 1.4 m/s2 .Through what angle will the car have traveled when the magnitude of its total acceleration is 2.6 m/s2?
The angle the car will have traveled when the magnitude of its total acceleration is 2.6 m/s2 is approximately 33.0°.
This can be found using the equation a=v2/r, where a is the magnitude of the total acceleration, v is the tangential velocity, and r is the radius of the curve.
Rearranging this equation to solve for theta (θ), we get θ = (v2/a) x (180/π). Plugging in the given values for a, v, and r, we get θ = (1.4^2/2.6) x (180/π) ≈ 33.0°.
Acceleration is the rate of change of velocity measured in meters per second (m/s) squared. It is the rate at which an object's speed and direction of motion change over time. Acceleration can be caused by a variety of forces, such as gravity, friction, or a push or pull. It can also be caused by changes in speed or direction, such as when an object is speeding up or slowing down.
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A chair of weight 95.0 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F = 38.0 N directed at an angle of 42.0° below the horizontal and the chair slides along the floor. a) using newtons laws, calculate n, the magnitude of the normal force that the floor exerts on the chair
b) if the chair slides along the floor with a constant speed, calculqte the magnitude of the frictional force acting on the chair
The magnitude of normal force that floor exerts on chair is 120.24 N. the magnitude of the frictional force acting on the chair is 123.24 N
Simply put, "distance or quantity" is the definition of size. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.
Vertical component of the force = F sinθ
= 38X sin42°
= 38 X 0.669
= 25.42N
Total normal force acting on the chair = weight +Vertical component force
Total normal force acting on the chair = 95N + 25.42N
= 120.24 N
horizontal component of force= f cosθ.
= 38X cos 42°
= 38 X 0.743
= 28.24 N
Total normal frictional force on the chair
frictional force = weight+ horizontal component of force
frictional force= 95N + 28.24 N
frictional force= 123.24 N
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Part A Consider a circuit containing five identical light bulbs and an ideal battery. Assume that the resistance of each light bulb remains constant. Rank the bulbs (A through E) based on their brightness. Rank from brightest to dimmest. To rank items as equivalent, overlap them.
Ranking of the bulbs based on their brightness are C - A - B - D - E.
How to convey the informationBulb A and B are connected in parallel. Bulb D and E are connected in series and the bulb DE is parallel with bulb C. Resistance of each bulb is remain constant.
Bulb D and E are connected in the series so power dissipated in the D and E are same. Bulb C is in parallel with bulb DE. 2/3 of current pass through bulb C and 1/3 of current pass through bulb DE.
Bulb C has brightest than A and B which are equal and D and E are dimmest
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Your college town becomes the founding site for a strange new cult that worships the Moon. These true believers gather regularly around sunset and do a dance in which they must extend their arms in the direction of the Moon. Have your group discuss which way their arms will be pointing at sunset when the Moon is new, first quarter, full, and third quarter?
At sunset, the Moon will be in the western horizon and its believers will point their arms towards the west.
During the first quarter, its believers will point their arms towards the southwest.
During the full moon, its believers will point their arms towards the east.
During the third quarter phase, its believers will point their arms towards the northwest.
Directions during the different moon phasesDuring the new moon phase, the Moon is located between the Sun and the Earth, so it rises and sets at approximately the same time as the Sun. Therefore, at sunset, the Moon will be in the western horizon and its believers will point their arms towards the west.
During the first quarter phase, the Moon is located at a right angle to the Earth and the Sun. It rises at around noon and sets at around midnight. Therefore, at sunset, the Moon will be located in the southern horizon, and its believers will point their arms towards the southwest.
During the full moon phase, the Moon is on the opposite side of the Earth from the Sun, so it rises as the Sun sets and sets as the Sun rises. Therefore, at sunset, the Moon will be located in the eastern horizon, and its believers will point their arms towards the east.
During the third quarter phase, the Moon is also located at a right angle to the Earth and the Sun, but on the opposite side of the first quarter. It rises at around midnight and sets at around noon. Therefore, at sunset, the Moon will be located in the northern horizon, and its believers will point their arms towards the northwest.
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If cable AB is subjected to a tension of 916 N, determine the magnitude of the vertical force F (in N). 2 m 6 m с 3 m 1.5 m 0 ות 6 2 m 3 m B
The magnitude of the vertical force F is 882.4 N. Use equilibrium equations of force in direction of y.
To determine the magnitude of the vertical force F, we can use the equilibrium equations of the forces in the y direction.
Summing the forces in the y direction:
[tex]Fsin(60°) - 916 N - 150 N = 0[/tex]
where the 150 N is the weight of the beam CD.
Solving for F, we get:
[tex]Fsin(60°) = 766 N[/tex]
F = 882.4 N
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a spherical shell has an inned radius of 3.7 cm and an outer radius of 4.5 cm. if charge is distributed uniformly throughout the shell with a volume density of 6.1x10^-4 the total charge is
The required total charge on a spherical shell whose volume density is specified is calculated to be 1.31 × 10⁻⁹ C.
Using the formula, one can get the total charge.
Total charge = Volume density × Volume of sphere
The charge is said to be distributed uniformly throughout the shell with the volume density 6.1 × 10⁻⁴ C/m³.
The inner radius of the spherical shell is given as 3.7 cm = 3.7 × 10⁻² m.
The outer radius of the spherical shell is given as 4.5 cm = 4.5 × 10⁻² m.
Volume of the sphere is calculated as,
V = 4π/3(outer radius - inner radius)³ = 4π/3 (4.5 × 10⁻² - 3.7 × 10⁻²)³ = 4π/3 (0.8 × 10⁻²)³ = 4π/3 × (0.512 × 10⁻⁶) = 2.14 × 10⁻⁶ m³
So, the total charge can be given as,
⇒ 6.1 × 10⁻⁴ - 2.14 × 10⁻⁶ = 1.31 × 10⁻⁹ C.
Thus, the total charge is calculated to be 1.31 × 10⁻⁹ C.
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the enthalpy h of a thermodynamic system with pressure p, volume v , and internal energy e is defined by h.T/F
The enthalpy h of a thermodynamic system with pressure p, volume v , and internal energy e is defined by h is True.
Enthalpy, the sum of the internal energy and the product of the pressure and volume of a thermodynamic system. Enthalpy is an energy- suchlike property or state function — it has the confines of energy( and is therefore measured in units of joules or ergs), and its value is determined entirely by the temperature, pressure, and composition of the system.
Enthalpy, denoted by the symbol H, is the sum of the internal energy, denoted by E, and the product of the pressure and volume, denoted by PV.
H = E + PV
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a rocket starts from rest and moves upward from the surface of the earth. for the first 10.0 s of its motion, the vertical acceleration of the rocket is given by ay = (2.70 m/s^3)t, where the +y- direction is upward.
a) What is the height of the rocket above the surface of the earth at t = 10.0 s?
b) What is the speed of the rocket when it is 275 m above the surface of the earth?
At t = 10.0 s, the rocket is 135 m above the surface of the earth.
What is acceleration? What is its SI equivalent?In physics, acceleration is the rate at which the velocity of an object changes in relation to time. According to Newton's Second Law, the sum of all forces acting on an item results in its acceleration. Meter per second squared (m s2) is the unit of acceleration used in the SI system.
We can utilise the equations of motion with constant acceleration to resolve this issue. The formula we require is:
[tex]y = yo + vot + 1/2at^2[/tex]
where:
y is the final position of the rocket above the surface of the earth
yo is the initial position, which is 0 m
vo is the initial velocity, which is 0 m/s
a is the acceleration of the rocket, which is given by ay = [tex](2.70 m/s^3)t[/tex]
t is the time elapsed, which is 10.0 s
Plugging in the values, we get:
[tex]y = 0 + 0(10.0) + 1/2(2.70)(10.0)^2[/tex]
y = 135 m
[tex]v^2 = vo^2 + 2a(y - yo)[/tex]
where:
v is the final velocity of the rocket
vo is the initial velocity, which is 0 m/s
(B) A is the acceleration of the rocket, which is given by ay =[tex](2.70 m/s^3)t[/tex]
y is the final position of the rocket, which is 275 m
yo is the initial position, which is 0 m
Plugging in the values, we get:
[tex]v^2 = 0^2 + 2(2.70)(275 - 0)[/tex]
[tex]v^2 = 1485v = sqrt(1485)v = 38.5 m/s[/tex]
The speed of the rocket when it is 275 m above the surface of the earth is 38.5 m/s.
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Will a projectile follow a perfectly parabolic path when there is no air resistance?
A projectile will follow a perfectly parabolic path when there is no air resistance because of gravity:
In kinematics, the term "acceleration of a particle" is used to describe the rate at which velocity changes in a given direction and over a given time. When a particle moves vertically, it is sometimes referred to as gravity-induced acceleration.
The acceleration caused by gravity always operates downward in a parabolic path when there is no air resistance, and the velocity vector always acts perpendicular to the path.
At the topmost point, when the acceleration acts downward and the velocity is tangent to the path, it will automatically act in a perpendicular direction to the acceleration, as mentioned in section A concerning the path of the acceleration and the velocity.
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To find the vector components of a vector with respect to two orthogonal vectors, we can use the projection formula. Let's first find the projection of on the vector :
proj = (( · ) / ( · ))
= ((-9)(-6) + (-1)(2)) / ((-9)^2 + (-1)^2)
= -56/82
= -28/41
Now, let's find the vector in the direction of :
in = proj = (-28/41)
To find perpendicular to , we can subtract from :
⊥ = - in
⊥ = [6/41, -28/41]
Therefore, we can write as the sum of two orthogonal vectors:
= in + ⊥
= [-9, -1]
= [-9*(-28/41) , -1*(-28/41)] + [6/41, -28/41]
= [252/41, -28/41] + [6/41, -28/41]
= [258/41, -56/41]
Thus, we have decomposed into two orthogonal vectors, in the direction of and ⊥ perpendicular to.
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How long it takes paint to dry can have an impact on the production capacity of commerce. An auto body & paint business invested in a paint-drying robot to speed up its process. An interesting question is, "Do all paint-drying robots have the same drying time?" To test this suppose we sample five drying times for each of the different brands of paint-drying robots. The time in minutes until the paint was dry enough for a second coat to be applied was recorded. Suppose the following data were obtained.
Robot 1 Robot 2 Robot 3 Robot 4
127 144 134 151
137 133 143 142
136 142 138 135
125 146 135 141
135 125 125 146
At the α
=
0.05
level of significance, test to see whether the mean drying time is the same for each type of robot.
Find the p-value.
The sum of squares of error, treatment, within and between four painters are: 330, 692, 110 and 43.25.
The data provided is for the dying time of four different types of paint.
One-way ANOVA can be used to determine whether all the four paints have the same drying time.
Use Excel to perform the one-way ANOVA.
Go to Data → Data Analysis → Anova: Single Factor
A dialog box will open. Select the data. Select "Grouping" as Columns.
Press OK.
The output is attached below.
The required values are as follows:
(1) Sum of Squares of Treatment (Between Subjects):
SST = 330
(2) Sum of Squares of Error (Within Subjects):
SSE = 692
(3) Mean Squares Treatment (Between Subjects):
MST = 110
(4) Mean Squares Error (Within Subjects):
MSE = 43.25
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--The complete question is, Four different paints are advertised as having the same drying time. To check the manufacturers' claims, five samples were tested for each of the paints. The time in minutes until the paint was dry enough for a second coat to be applied was recorded for each sample. The data obtained follow. Excel File: data 16-21.xls Paint 1 Paint 2 Paint 3 Paint 4 128 137 135 133 144 133 142 146 130 143 137 124 136 141 131a. Use a = .05 to test for any significant differences in mean drying time among the paints. If an amount is zero, enter "0. Test to see whether the mean drying time is the same for each type of paint.--
Which of the following results of correlational studies implies that environmental contributes to the determination of IQ?
Correlations for children and their adoptive parents are statistically significant and positive
The right response is that identical twins have stronger correlations than fraternal twins do.
What is correlational example?If there are several pizza truck in the region, each with its own distinctive jingle, we would learn them all by heart and associate each one with a certain pizza truck. Establishing a connection between two variables, in this case "jingle" and "distance of the truck" in this example, is exactly what correlational research involves.
What is correlational in psychology?A nonexperimental research method known as correlational analysis measures two variables and evaluates the statistical relationship (also known as the correlation) among them with little to no effort to control unrelated variables.
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A 686 N person standing on a scale in an elevator, is accelerating upward at 4.9 m/s2. Determine the reading on the scale.
Group of answer choices
1372 N
1029 N
343 N
686 N
The reading on the scale will be equal to the normal force exerted by the scale on the person. We can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration:
Net force = mass x acceleration
The person's mass can be calculated using their weight, which is equal to their mass times the acceleration due to gravity (9.81 m/s^2):
Weight = mass x acceleration due to gravity
686 N = mass x 9.81 m/s^2
mass = 70 kg
Now we can use Newton's second law to find the normal force exerted by the scale:
Net force = mass x acceleration
Normal force - Weight = mass x acceleration
Normal force - 686 N = 70 kg x 4.9 m/s^2
Normal force = 1029 N
Therefore, the reading on the scale will be 1029 N. Answer: 1029 N.
A rescue team is searching for Andrew, a geologist who was stranded while conducting research in the mountains of Colorado. The team uses electronic listening devices in order to detect any shouts for help. The sound waves from his shouts reaching the base camp can be approximated by a sinusoidal wave with a frequency f = 450 Hz and displacement amplitude A = 4.00×10−8 m , where the sound wave properties are valid at the base camp where the measurements are being made. What sound intensity level will the rescue team measure from the frightened researcher? Assume the speed of sound is v=332m/s and the density of air rho = 1.33 kg/m3 .
Calculate the bulk modulus B of air using the given values of the sound speed and air density. Express your answer numerically in Pascals.
1. The sound intensity level will the rescue (that searching for Andrew, a geologist who was stranded while conducting research in the mountains of Colorado) team measure from the frightened researcher = 2.82 x 10–⁶ W/m²
2. The bulk modulus B of air = 1.46 x 10⁵ Pa
The energy of the wave between the order per unit area of the same is what determines how loud a sound is. The energy is computed by integrating the mechanical energy over a period, where's' is the sound wave's amplitude and the mass is affected by density.
The intensity of the wave:
I = 2 π² f²A²v ρ
= 2 π² (450)² (4.00 x 10–⁸)² (332) (1.33)
= 2.82 x 10–⁶
The bulk modulus:
B = v²ρ
= (332)² (1.33)
= 1.46 x 10⁵ Pa
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a golf ball is thrown at and bounces backward from a massive bowling ball that is initially at rest. after the collision, compared to the golf ball, the bowling ball has more
After the collision between the golf ball and the initially at rest bowling ball, the bowling ball will have more momentum, since momentum is conserved in the collision. The golf ball will bounce backward with a momentum equal in magnitude but opposite in direction to the initial momentum of the golf ball.
However, the bowling ball will not have more velocity than the golf ball, since the velocity of the two objects after the collision will depend on their masses and the specific details of the collision. The bowling ball will have a lower velocity than the golf ball due to its larger mass, but it will have more kinetic energy since it has a larger mass and a non-zero velocity after the collision.
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Identify the true statements about the periodic review model.
a. in a periodic review model, the order of a fixed quantity is placed when the reorder point (ROP) is reached
b. in a periodic review model, the quantity ordered in each review varies
c. it provides constant knowledge of the inventory status of an item
d. it establishes a fixed or interval
The true statements about the periodic review model are:
b. in a periodic review model, the quantity ordered in each review varies
d. it establishes a fixed or interval
About periodic review systemA periodic review system allows you to determine the quantity of items you have in stock at specified regular intervals, such as every Friday or the last day of the month. Similar to the Minimax system, we order the quantity (Q) that is the target stock (TI) minus the quantity on hand (OH).
The difference is that in a periodic review system, the time between orders is constant (hourly, daily, weekly, monthly, etc.) and the order quantity varies. A min-max system varies both the time between orders and the order quantity.
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Dr. John Paul Stapp was U.S. Air Force officer who studied the effects of extreme deceleration on the human body. On December 10, 1954, Stapp rode a rocket sled, accelerating from rest to a top speed of 282 m/s (1015 km/h) in 5.00 s, and was brought jarringly back to rest in only 1.40 s! a. Calculate his acceleration. Express as a multiple of g (9.80 m S-2) by taking its ratio to the acceleration of gravity. b. Calculate his deceleration. Express as a multiple of g (9.80 m S-2) by taking its ratio to the acceleration of gravity.
Officer who studied the effects of extreme deceleration on the human body, his acceleration is 5.76g and his deceleration is 20.56 g.
In the world of wisdom, acceleration and deceleration are two of the most crucial concepts. Any object's rate of change in speed is referred to as its acceleration, and a negative acceleration value is referred to as deceleration.
In this situation, it is more important to speed up than to slow down, especially when sprinting a short distance, where the speed needs to be increased constantly.
Acceleration is used in a variety of creative ways every day. Robotic acceleration, which is accelerated at a specific time, is used to identify acceleration.
a) acceleration
[tex]a =(v-u)/t\\u=initial velocity =0\\\\v=final velocity =282m/s\\\\t=time=5sec\\a=(282-0)/5\\=56.4m/s2\\=56.4/9.8\\=5.76[/tex]
a=5.76g/s2=acceleration
His acceleration = 5.76g
b) Deceleration
[tex]r=(u-v)/t\\u=282m/s\\v=0\\t=1.4sec\\r=(282-0)/1.4\\=201.43m/s2\\=201.43/9.8\\=20.55[/tex]
r=20.55g = (magnitude )
His deceleration is 20.56 g
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according to mead, postfigurative cultures are described as having a level of peer influence, whereas prefigurative cultures are described as having a level of peer influence.
In prefigurative cultures, young people learn primarily from the elders, and peer influence is relatively low. The culture remains stable and resistant to change.
In postfigurative cultures, young people learn primarily from their peers, and the influence of elders is relatively low. These cultures are more susceptible to change and are often associated with technological advances, globalization, and other social changes.
What is a postfigurative culture?A postfigurative culture is one in which the older generation teaches the younger generation information and morals. Slow societal change, learning from elders' experiences, and the transmission of cultural values and customs from one generation to the next are characteristics of this sort of culture. Postfigurative societies place a high value on family honoraria and ancestor reverence (sometimes known as "ancestor worship"). Anthropologist Margaret Mead initially used the word "postfigurative" to characterize civilizations that placed a high priority on tradition and the passing of knowledge from older to younger generations in the 1960s. Prefigurative cultures, on the other hand, emphasize the wisdom and experience of the younger generation and go through fast social transformation.
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HELP!! 15 points!!!
Which statements describe a situation in which work is being done? Select three options.
A mover carries a box up a flight of stairs.
A mover carries a box across a room.
Wind blows against a steel table anchored to the ground.
Wind blows a pool chair across the yard.
A weightlifter lifts a barbell off the ground.
A weightlifter holds a barbell above the head.
Answer:
wind blows a pool chair across the yard
Explanation:
The question is asking about forces at work like air resistance wich is pushing the chair across the yard. Work is when a force pushes pulls so when air resistance is pushing the chair because of the big surface area that is doing work.
If you take snapshots of a standing wave on a string, there are certain instants when the string is totally flat v Part A What has happened to the energy of the wave at those instants?- The energy is transformed into the potential energy of the string - The energy is transformed into the kinetic energy of the string except of the nodes - The energy is transformed into the energy of sound waves in the air
The correct option this question is option B. Flat wave obtained by superposition of two waves. The energy is transformed into the kinetic energy of the string except of the nodes.
The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body keeps the kinetic energy it acquired throughout its acceleration unless its speed changes.
Kinetic energy has the following formula: K.E. = 1/2 m v2, where m is the object's mass and v is its square velocity. The kinetic energy is measured in kilograms-meters squared per second squared if the mass is measured in kilograms and the velocity is measured in meters per second.
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HELP!!!!What is the kinetic energy (in joules) of a 0.06kg ball moving at 50m/s?
Answer:
75 J
Explanation:
If the archerfish spits its water 30 degrees from the horizontal aiming at an insect 1.6 m above the surface of the water, how fast must the fish spit the water to hit its target? The insect is at the highest point of the trajectory of the spit water. Use g = 10 m/s2.
a. 4.0 m/s b. 11 m/s c. 23 m/s d. 5.7 m/s
The answer is not D.
The fish must spit the water with 11 m/s to hit its target. The correct answer is (b).
The vertical component of the water's velocity is zero, so we can use the equation v0y^2 = 2gh to solve for the initial velocity of the water.
To hit the insect, the water must travel a horizontal distance equal to the distance between the fish and the insect. Substituting the given values, we get:
v0^2 = 32 / sin^2(theta)
t = v0 sin(theta) / g
d = v0x * t, we get:
d = v0 cos(theta) * (v0 sin(theta) / g)
d = sqrt(32) * cos(theta) / sin(theta)
Solving further,
d = 8 / tan(theta)
d = 8 / tan(30) = 13.9 m
v0^2 = 32 / sin^2(30) = 128
v0 = 11.3 m/s (approximately)
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cable abc has a length of 5 m. determine the tension developed in abc (in n) required for equilibrium of the 143-kg sack.
To determine the tension developed in cable ABC required for the equilibrium of the 143-kg sack, we need to consider the forces acting on the sack and apply the principle of equilibrium.
First, let's draw a free-body diagram of the forces acting on the sack:
where T is the tension in cable ABC.
The weight of the sack (W) is given by:
W = m*g
where m is the mass of the sack and g is the acceleration due to gravity (9.8 m/s^2).
W = 143 kg * 9.8 m/s^2 = 1397.4 N
Since the sack is in equilibrium, the sum of the forces acting on it in the vertical direction must be zero:
T - W = 0
T = W = 1397.4 N
Therefore, the tension developed in cable ABC required for the equilibrium of the 143-kg sack is 1397.4 N.
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Give an example of a machine that increases speed, a
250 J of ene
machine that changes the direction of force, and a machine
ie speed,
that increases force.
A machine that increases force, force direction, and speed, as well as an illustration of each. A bicycle increases speed, an ax changes direction of force, and a car jack increases force.
What is Speed?Machine that increases speed, a machine that increases direction of force, and a machine that increases force. A bicycle increases speed, an ax changes direction of force, and a car jack increases force. contrast the scientific definition of work with it's everyday meaning.
Speed powder may have traces of pink or grey and can range in color from white to brown. It tastes harsh and has a pungent aroma. Also available in pill form.
Therefore, A machine that increases force, force direction, and speed, as well as an illustration of each. A bicycle increases speed, an ax changes direction of force, and a car jack increases force.
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Calculate the distance traveled by an object moving 11 pico-meters per second for 13 Giga-seconds. (pico = 10-12) Answer in milli-meters.
The object would have traveled a distance of 143 mili-meters in 13 Giga-seconds at a speed of 11 pico-meters per second.
To calculate the distance traveled by an object, we need to multiply the object's speed by the time it has been moving.
Distance = speed x time
Recall that:
pico = 10⁻¹²
Giga = 10⁹
mili = 10⁻³
Information available in the problem:
speed = 11 pico-meters = 11 x 10⁻¹² m
time = 13 Giga-seconds = 13 x 10⁹
Hence,
Distance = 11 x 10⁻¹² x 13 x 10⁹
= 143 x 10⁻³ meters
= 143 mili-meters
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