earth's gravity attracts a person with a force of 120 lbs. the force with which the earth is attracted towards the person is

The right response is B. v, where v stands for the wave's frequency.

Frequency, also referred to as pitch, is the rate at which a sound pressure wave repeats itself. A bullfrog cry is significantly lower in frequency than a whistle, while a cricket is much lower in frequency than a drumbeat. With decreasing frequency, the oscillations become less prominent.

The ability to identify one sound from another and one colour of light depends on frequency. Red light, for instance, differs from blue light because of its lower frequency. Dogs are able to sense sounds, thus they can hear a whistle that you cannot.

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The optical generation rate of a silicon sample illuminated with light is the rate at which photogenerated carriers are created in the sample.

Optical generation rate is typically expressed in units of A/cm2. The optical generation rate is a function of the light intensity, the wavelength of the light, and the material properties of the silicon sample. The rate of generation of electron-hole pairs through photon absorption is known as "optical generation rate". Optical generation rate is usually denoted by G(x) and in unit of electrons/cm³s.

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The ratio of the charge on each particle to its mass must be equal when the magnitude of the gravitational force between two of these particles is equal to the magnitude of the electric force between them.

The term “magnitude” refers to the size or quantity of a physical quantity, without taking into account its direction. It is a scalar quantity, meaning it has only a numerical value and no associated direction.

For example, the magnitude of a vector quantity like velocity, which has both a magnitude and direction, refers only to its numerical value, without regard to its direction.

Similarly, the magnitude of a force, electric field, magnetic field, or any other vector quantity refers to the strength or intensity of that quantity, regardless of its direction.

When the gravitational and electric forces between two particles are equal in strength, the following equation describes these forces:

Gravitational force:

[tex]F_g = G\times \frac{(m1 m2)}{(r_2)}[/tex]

Electric force:

[tex]F_e = K\times \frac{(q1 q2)}{(r_2)}[/tex]

Where G is the gravitational constant, k is the Coulomb constant, m1 and m2 are the masses of the particles, q1 and q2 are their charges, and r is the distance between them.

Since, the charge-to-mass ratio for the particles is needed, let's rearrange the equations as follows:

(1) [tex]q_1\times q_2 = F_e\times \frac{r_2}{k}[/tex]

(2) [tex]m_1\times m_2 = F_g\times \frac{r_2}{k}[/tex]

Divide the first equation by the second equation

[tex](q1 \times q2) / (m1 \times m2) = (Fe / Fg) \times (G / k)[/tex]

This expression has to be equal to 1, so can set

[tex](Fe / Fg) \times (G / k) = 1[/tex]

Substituting the expressions for Fg and Fe,

Rearrange the equation

Therefore, This means that the charge-to-mass ratio for the two particles must be the same. In other words, the ratio of the charge on each particle to its mass must be equal.

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The work that must be done on charges brought from infinity to charge a spherical shell of radius R = 0.100 m to a total charge Q = 125 μC = 1.12 x 10⁶ J

The potential difference of the charge is the amount of work required to bring a unit positive charge from infinity.

V = E x d

= k (q/r)

where;

V = The potential difference (J)

E = The field potential (N/C)

d = The distance that the charge (m)

k = Coulomb constant (8.99 x 10⁹ Nm²/C²)

q = The unit charge

r = radius

Hence,

The work done:

= (8.99 x 10⁹ Nm²/C²) (125 x 10–⁶) / 0.1

= 1.12 x 10⁶ J

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C - Pieces of information recorded in an experiment.

The sample space S of a random experiment is defined as the set of all possible outcomes of an experiment. In a random experiment, the outcomes, also known as sample points, are mutually exclusive.

Data refers to any pieces of information that are collected or recorded during an experiment or study.

This information can be qualitative or quantitative and may include measurements, observations, survey responses, or any other type of information that can be analyzed to answer research questions or test hypotheses.

Data can be analyzed and interpreted to draw conclusions or make predictions about the phenomenon being studied.

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Explanation:

Convert °F to °C. and Convert °C to °F

The nebula is the closest big star-forming zone to Earth but is still 1,500 light-years away, giving it a moderately bright apparent brightness of 4.

The Orion Nebula, sometimes referred to as Mass 42, M42, also NGC 1976, is a diffused nebula below Orion's Belt with a greenish hue. Several of the sharpest nebulae, it may be seen in the sky at night with the unaided eye.

One of the clearest and most familiar constellation inside the sky is the one that bears the name of the hunt from Greek mythology. According to the astronomy website Astronomy Trek, Orion contains Betelgeuse (Alpha Orionis) and Rigel (Beta Orionis), 2 of the 10 bright stars in the sky.

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Answer:

Below

Explanation:

The 156  and  20 m/s speeds form the LEGS of a right triangle....you want to find the resultant hypotenuse....so use pythagorean theorem

Resultant ^2 = 156 ^2 + 20^2

resultant ^2 = 24736

Resultant = 157.3 m/s    magnitude

The forces are unequal in size, act in opposite directions, and produce a net force in the direction of motion. Option d is correct answer.

When multiple forces act on an object in same direction, net force can be found by adding up individual forces.

If the forces are equal in size but opposite in direction, they produce a zero net force, resulting in no acceleration. However, if forces are unequal in size and opposite in direction, they produce a net force in the direction of the larger force, resulting in an acceleration. Therefore, the correct answer is (d) the forces are unequal in size, act in opposite directions, and produce a net force in the direction of motion.

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--The complete question is, In the video, forces acting on the car that are parallel to the direction of motion are analyzed. How are these forces related?

a. The forces are equal in size, act in the same direction, and produce a net force in the direction of motion.

b. The forces are equal in size, act in opposite directions, and produce a zero net force.

c. The forces are unequal in size, act in the same direction, and produce a net force in the direction of motion.

d. The forces are unequal in size, act in opposite directions, and produce a net force in the direction of motion.

e. The forces are equal in size, act in opposite directions, and produce a net force in the direction of motion.--

The force acted through a distance of 5 meters.

Force and surface area are related through pressure, defined as the force per unit area. Force is inversely proportional to the surface area over which the force is distributed. If the surface area is increased, the pressure exerted by a given force will decrease; if the surface area is decreased, the pressure will increase.

Pressure is defined as the force per unit area and is typically measured in units of pascals (Pa) or pounds per square inch (psi). The formula for calculating pressure is Pressure (P) = Force (F) / Area (A).

As we know:

F * d = ΔK

Solving for d, we get:

d = ΔK / F

Substituting the given values, we get:

d = (5 x 10² J) / (1 x 10² N)

d = 5 meters

Therefore, the force acted through a distance of 5 meters.

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Develop expressions for variations in pressure in fluids ⇒  p = K[tex]\frac{h^2}{2}[/tex] + γ₀h

Since we are given a function of specific weight value, which varies with height, we have to define a differential change in pressure over an infinitesimally small change in height:

dp = γdh

Substitute the function:

dp = (Kh+γ₀) dh

This relationship allows us to integrate pressure changes, over small height changes, and obtain the total pressure change:

p = ∫(Kh+γ₀)dh

p = [tex]\int\limits^h_0[/tex]Khdh + [tex]\int\limits^h_0[/tex]γ₀dh

p = Kh²/2[tex]]_0^h[/tex] + γ₀h[tex]]_0^h[/tex]

p = K[tex]\frac{h^2}{2}[/tex] + γ₀h

Your question is incomplete but most probably your full question was:

Develop an expression for the pressure variation in a liquid in which the specific weight increases with depth, h, as γ = Kh+γ₀ where K is a constant and yo is the specific weight at the free surface.

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the answer to the (a) F=m(a−g) and (b) ║F║= 440. 19 N. to solve this we need to use newton's law of motion as follows:

a) Our task is to write an equation giving the vertical force that must apply to the pole.

From the Newton's second law of the motions, the net force [tex](F_{net})[/tex] is

[tex](F_{net})[/tex] = ∑[tex]F= F_{1}[/tex] + [tex]F_{2}[/tex] + [tex]F_{3}[/tex] ..... = m.a

When we accord into equation (1), we get.

F-W = m.a

F−m⋅g = m.a

​

The vertical force from the equation (3) will be.

Fj=  m.aj - m⋅gj

When we take the common factor, final equation will be.

F=m(a−g)

b) Our task is to determine the magnitude of the force.

║F║= m(a - g)

​

 calculations

║F║ = 90kg [tex]( 5.0 \frac{m}{s_{2}} - 9.6 \frac{m}{s_{2}} )[/tex]

= 90 kg ( -4.81 [tex]m/s_{2}[/tex])

║F║= 440. 19 N

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​

The fulcrum should be positioned 1.125 m from the left side of the board to balance the masses horizontally. The closest answer choice is (C) 1.1 m.

To balance the masses horizontally, the torque on the left of the fulcrum must be equal to the torque on the right of the fulcrum. The torque on each side is given by the product of the force and the distance from the fulcrum.

On the left side, the force is the weight of the box, which is mg = (25 kg)(9.8 m/s²) = 245 N. Let x be the distance from the left side of the board to the fulcrum.

On the right side, the force is the weight of the box, which is m2g = (15 kg)(9.8 m/s²) = 147 N. The distance from the fulcrum to the right side of the board is 3.0 m - x.

Setting the torques equal, we have:

245 N x = 147 N (3.0 m - x)

Simplifying and solving for x, we get:

245x = 441 - 147x

392x = 441

x = 1.125 m

Therefore, the fulcrum should be positioned 1.125 m from the left side of the board to balance the masses horizontally. The closest answer choice is (C) 1.1 m.

In this problem, the board is acting as a lever with the fulcrum in the middle. For the board to be in rotational equilibrium, the clockwise and counterclockwise torques acting on the board must be equal. The torque due to the weight of the first box (τ1) is given by τ1 = m1 * g * d, where m1 is the mass of the first box, g is the acceleration due to gravity, and d is the distance from the fulcrum to the first box. Similarly, the torque due to the weight of the second box (τ2) is given by τ2 = m2 * g * (L - d), where m2 is the mass of the second box and L is the length of the board.

At equilibrium, τ1 = τ2, which can be solved to find the value of d that balances the masses horizontally.

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From point A to point B, the electric flow through a sphere with a radius of 2.044 mm is dependent on the total electrical current encompassed by this surface. Due to B(VB)=kqb=910925.8, there is an electric field.

The electric field from outside sphere is comparable to the area from either a charged particle with the a net charge of Q, according to Gauss' law, whereas the electromagnetic current on the inside of the sphere is zero. For a hollow or hollow sphere, this conclusion holds valid. Therefore, we can state that inside a conducting sphere, the electromagnetic current is zero.

According to the Gauss Theorem, the total electric flow through with a closed surface exceeds the net electrical flux the Gauss theorem's mathematical formula is =qenclosed0 if there is an electric field in a vacuum.

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At any point on a line charge distribution, the linear charge density is the amount of charge per unit length, expressed in coulombs per meter (Cm1). Electric charge can be positive or negative, hence charge density can also be positive or negative.

Linear charge density is a measure of the amount of electric charge per unit length along a line or wire. It is denoted by the symbol λ (lambda) and has units of coulombs per meter (C/m).

To calculate the linear charge density, you divide the total charge by the length of the line or wire. For example, if a wire has a total charge of 5 coulombs and a length of 2 meters, then the linear charge density would be:

λ = 5 C / 2 m = 2.5 C/m

P.S: Your information is incomplete and an overview was given.

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Answer:

heat

Explanation:

Heat will cause expansion of food and air and water ( steam) inside of the pot causing the lid to pop off  

Nuclear fusion is the process that occurs when two or more atomic nuclei unite. In below given way words can be matched.

Nuclear fusion is the process that occurs when two or more atomic nuclei unite to generate one or more distinct atomic nuclei containing subatomic particles (neutrons or protons). The mass difference between both the products and the reactants manifests itself as either energy release or absorption.

1. Nuclear fusion of hydrogen into helium occurs in the CORE.

2. Energy moves through the sun's  CONVECTION ZONE by means of the rising of hot gas and falling of cooler gas.

3. Nearly all the visible light we see from the sun is emitted from the PHOTOSPHERE.

4. Most of the sun's ultraviolet light is emitted from the narrow layer called the CHROMOSPHERE where temperature increases with altitude.

5. We can see the sun's CORONA  most easily during total solar eclipses.

6. The  RADIATION ZONE is the layer of the sun between its core and convection zone.

Therefore, in above given way words can be matched.

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The  temperature outside is 1.6 degrees Celsius

Charles's law, also known as the law of volumes, is a fundamental gas law that describes the relationship between the volume and temperature of a gas at a constant pressure.

It states that, for a fixed mass of gas at a constant pressure, the volume of the gas is directly proportional to its absolute temperature.

By the use of the Charlee's law;

V1/T1 = V2/T2

V1T2 = V2T1

T2 = V2T1/V1

T2 = 4.9 * 297/5.3

T2 = 1.6 degrees Celsius

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Finally, let's consider the accelerations of the truck and the log. Since the cable connecting them is not slack or stretched, the truck and the log have the same acceleration. Therefore, at the instant when the truck has an acceleration of 0.5 ft/s2 to the right, the log also has an acceleration of 0.5 ft/s2 to the right.

To solve this problem, we need to apply the principles of kinematics and pulley systems. Let's assume that the pulley is ideal (i.e., frictionless and massless) and that the cable connecting the truck and the log does not stretch or slip.

First, let's consider the distances moved by the truck and the log. Since the cable does not stretch, the distance moved by the truck is equal to the distance moved by the log. Therefore, after the truck has moved 4 ft to the right, the log has also moved 4 ft to the right.

Next, let's consider the velocities of the truck and the log. Since the cable connecting them is not slack or stretched, the truck and the log have the same velocity. Therefore, at the instant when the truck has a velocity of 2 ft/s to the right, the log also has a velocity of 2 ft/s to the right.

Therefore, at the instant when the truck has an acceleration of 0.5 ft/s2 to the right, the log also has an acceleration of 0.5 ft/s2 to the right.

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8.20 meters away from the speaker, there is roughly 0.092 W/m2 of sound intensity.

Since sound is perceived on a logarithmic scale, a rise of 10 dB corresponds to an intensity that is 10 times stronger. For instance, the intensity of the sound of the waves at the coast is 1,000 times greater than that of a whisper, or an increase of 30 dB.

The following equation can be used to calculate sound intensity: I=Δp22ρvw. P stands for pressure change or amplitude, D stands for material density, and VW stands for measured sound speed. The more volume you use The greater the wave oscillation, the louder your sound will be.

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Answer: .083

Explanation:

acellus

Answer:

Explanation:

Work done = force * displacement = 33Cos60 * 3 = 49.5J

The rock was dropped from a height of approximately 0.862 meters above the top of the glass door.

We can use the kinematic equations of motion to solve this problem. In particular, we can use the equation:

y = vi*t + [tex](1/2)at^2[/tex]

where:

y is the distance the rock falls

vi is the initial velocity of the rock (which is 0, since the rock is dropped from rest)

a is the acceleration due to gravity (which is approximately [tex]-9.81 m/s^2[/tex], since the rock is falling downwards)

t is the time it takes for the rock to fall the distance y.

We know that the rock falls a total distance of 2.1 meters (the height of the glass door), and it takes 0.28 seconds to fall this distance. Therefore, we can plug in these values and solve for the initial height:

2.1 m = 0 + [tex](1/2)( -9.81 m/s^2)(0.28 s)^2[/tex]+ vi*(0.28 s)

Simplifying and solving for vi, we get:

vi = (2.1 m - (1/2)[tex](-9.81 m/s^2)(0.28 s)^2)[/tex] / 0.28 s

vi = 6.14 m/s

So the initial velocity of the rock when it was dropped was 6.14 m/s. Now we can use the kinematic equation:

y = vi*t + [tex](1/2)at^2[/tex]

To solve for the initial height. We know the initial velocity and the time it took for the rock to fall past the glass door (0.28 seconds), so we can plug in these values and solve for y:

y = vit + [tex](1/2)at^2[/tex]

y = (6.14 m/s)(0.28 s) + [tex](1/2)(-9.81 m/s^2)(0.28 s)^2[/tex]

y = 0.862 m

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To square-root the angular frequency to double the total energy of a mass oscillating at the end of a spring with amplitude A. 2. Amplify the signal by the square root of 2.

Simple harmonic motion is a periodic motion in which the acceleration of each individual particle is proportionate to its displacement and is aimed at the mean position.

This is due to the fact that the total energy of a straightforward harmonic oscillator is inversely proportional to its amplitude. The total energy is quadrupled (i.e., doubled squared) if the amplitude is doubled, which is the factor required to double the total energy.

The amplitude must therefore rise by the square root of 2 to twice the total energy.

Therefore, The amplitude of a mass-spring system oscillating in simple harmonic motion must rise by a factor of $sqrt2$, or around 1.414, to double the total energy of the system.

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The correct units for kinetic energy is, kg*m^2/s^2.

Units can be derived by looking at the units of the equation for kinetic energy: K E = 1/2 m v^2. The mass (m) is typically measured in kilograms (kg), while the velocity (v) is measured in meters per second (m/s). Squaring velocity gives units of m^2/s^2. Multiplying by mass and the 1/2 coefficient gives units of kg*m^2/s^2, which is equivalent to joules (J).

Joules are a derived unit of energy, defined as the amount of work done when a force of one newton (N) is applied over a distance of one meter (m). They are widely used in physics and engineering to quantify energy, as well as other quantities like work, power, and heat.

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--The complete question is, The kinetic energy for a moving object is given by K E = 1/2 m v^2. Which of the following gives the correct units for energy?
a. m/s
b. kg. m/s^2
c. kg. m s^2

d. kg. m^2/s^2--

The correct order of the six possible combinations of electric charges is as follows: -10C, -Inc +inc, -10C, +1, -Inc +10C, 1+11C, and the most favorable:  +10C, +100

A subatomic particle experiences a force when it is in contact with an electric and magnetic field due to its electric charge. The majority of charge carriers for the positive and negative forms of electric charges, respectively, are protons and electrons.

Coulomb's law reveals the electric force between two charges,

                              F = kq₁q₂/r²

we can rank the combinations of charges from most negative force to most positive force:

-10C, -Inc

+inc, -10

-10C, +1

+1, -Inc

+10C, 1+11C

+10C, +100

Therefore, the correct ranking of the six combinations of electric charges from most negative to most positive is:

most negative:

-10C, -Inc

+inc, -10

-10C, +1

+1, -Inc

+10C, 1+11C

most positive: +10C, +100

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The depth pressure of the vat obtained is 44.076 m.

Extinguisher Type hue of the band acceptable for (class of fire) Comments All Red Water Unsafe around other types of fire. BA Foam Blue Unsafe around other types of fire. Class A fires can also be put out with Powder White B, (E), or "AB(E)" type powder. Dioxide of carbon (E) Black, B Watch out for discharge pressure.

Time from the crane to the bottom of the vat (t) = 3.20 s

H = ½gt²

H = ½ × 9.8 × 3.2²

H = 4.9 × 10.24

H = 50.176 m

Height (H) = 50.176 m from crane to vat's bottom

Crane's height above the vat (h) is 6.10 metres

Depth of vat = H – h

Depth of vat = 50.176 – 6.10

Depth of vat = 44.076 m

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The temperature gradient in the flow of direction is 294525 W.

A temperature gradient is the gradual variance in temperature with distance. The slope of the gradient is consistent within a material. A gradient is established anytime two materials at different temperatures are in physical contact with each other.

Q= T/( L/ KA)

Q= ( 1500 − 450) / 0.15 / 9.35v * 4.35)

   = 294525 W

Units of measure of temperature gradients are degrees per unit distance, such as °F per inch or °C per meter.

Many temperature gradients exist naturally, while others are created. The largest temperature gradient on Earth is the Earth itself. Q= T/Ka.

Therefore, The temperature gradient in the flow of direction is 294525 W.

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The displacement of the log if the truck at c pulls the cable 10 ft to the right will be 3.33ft in the opposite direction.

2Sb+(Sb-Sc)=l

3Sb-Sc=l

3deltaSb-deltaSc=0

3deltaSb=deltaSc

3deltaSb=-10

Sb=-3.3333

negative sign here indicates the opposite direction of the displacement.

Displacement is known as the change in position of an object. It is a vector quantity which means it has both direction and magnitude. The representation of displacement is by  an arrow that points from the starting position to the final position. For example- If an object moves from A position to B, then the object's position changes.

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The work done on the bowling ball is 576 J to accelerate an 8.0-kg bowling ball from rest to a speed of 12 m/s and a distance of 2.5 m to reach a speed of 12 m/s if the average force on the bowling ball is 230 N.

Work = 1/2 × m × [tex]v^2[/tex]

( m =8 kg=is the mass, v= 12 m/s= is final velocity)

Work = 1/2 × 8.0 kg × [tex](12 m/s)^2[/tex] = 576 J

As per work-energy principle,  the work done on an object = the change in its kinetic energy

Work = ΔKE

(ΔKE = change in kinetic energy, initial kinetic energy=0)

final kinetic energy is,

KE = 1/2 × m × [tex]v^2[/tex] = 1/2 × 8.0 kg × [tex](12 m/s)^2[/tex] = 576 J

the change in kinetic energy,

ΔKE = KE - 0 = 576 J (work is equal to force here)

So, Work = Force × Distance

Distance = Work / Force = 576 J / 230 N = 2.5 m

As a result, the work done on the bowling ball is 576 J to accelerate and travel 2.5 m with an 8.0-kg bowling ball.

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The words that fill in the blanks are;

Completely filled

High

Noble gases are a group of chemical elements in the periodic table that are typically inert or unreactive due to their stable electronic configurations. They include helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn).

We know that the Noble gases do have a complete outer shell and that they are able to not combine with the other elements in a chemical bond. This is the hallmark of the noble gases as we know in the periodic table.

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