The solution becomes cloudy with a white solid, is the observation that indicates the chemical reaction.
A chemical reaction is a process in which one or more substances, also called reactants, are converted to one or more different substances, known as products. Substances are either chemical elements or compounds.
A chemical reaction is usually accompanied by easily observed physical effects, such as the emission of heat and light, the formation of a precipitate, the evolution of gas, or a color change. Absolute confirmation of a chemical change can only be validated by chemical analysis of the products.
Therefore, the solution becomes cloudy with a white solid is the correct choice.
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--The complete question is, During an experiment, Jon exhales through a straw and blows bubbles into a solution. Which observation would most likely indicate that a chemical reaction is occurring?
a. The bubbles disappear into the solution before reaching the surface.
b. The gas forms a layer above the surface of the solution.
c. The solution becomes very stirred up by the bubbles.
d. The solution becomes cloudy with a white solid.--
if the initial concentrations of both a and b are 0.42 m, at what initial rate is c formed? answer in units of m/min. answer in units of m/min
The initial rate of formation of product c is 0.1008 M/s.
The rate of formation of product c in a chemical reaction can be determined by using the rate law. The rate law is an equation that describes the relationship between the rate of the reaction and the concentrations of the reactants involved in the reaction. In this case, the rate law is given as rate = k[a][b], where,
k is the rate constant [a] and [b] are the concentrations of reactants "a" and "b".Given the initial concentrations of reactants "a" and "b" are both 0.42 M, and the value of the rate constant, k, is 1.2 x 10^-3 s^-1, we can calculate the initial rate of formation of product "c" as follows:
rate = k[a][b] = (1.2 x 10^-3 s^-1)(0.42 M)(0.42 M)
= 0.1008 M/s.
So the initial rate of formation of product "c" is 0.1008 M/s.
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The complete question is:
What is the initial rate of formation of product "c" in a reaction where the initial concentrations of reactants "a" and "b" are both 0.42 M, given the rate law: rate = k[a][b], and the value of the rate constant, k, is 1.2 x 10^-3 s^-1?
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a sample of gas occupies 250 ml at 1 atm. if the pressure increases to 2 atm while the temperature stays the same, what is the new volume?
At 1 atm, a sample of gas takes up 250 ml. if the pressure increases to 2 atm while the temperature stays the same, 125ml is the new volume.
The ideal gas law states that PV = nRT, where n is the number of moles of gas, P is the pressure, V is the volume, R is the gas constant, and T is the temperature in Kelvin.
P1V1 = P2V2
where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.
Substituting the given values, we have:
1 atm x 250 ml = 2 atm x V2
Solving for V2, we get:
V2 = (1 atm x 250 ml) / (2 atm)
V2 = 125 ml
Therefore, the new volume of the gas is 125 ml when the pressure increases from 1 atm to 2 atm while the temperature remains constant.
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the half-life for the second-order decomposition of hi is 15.4 s when the initial concentration of hi is 0.34 m. what is the rate constant for this reaction?
The rate constant is 0.09691 m-1 s-1.
Half-life is defined as the time it takes for a quantity to decrease to half its original value. A second order reaction can be defined as a chemical reaction for which the sum of the exponents of the corresponding rate laws of the chemical reaction is equal to two. A rate constant or specific rate constant is the constant of proportionality in the equation that describes the relationship between the rate of a chemical reaction and the concentration of reacting substances.
secondary half-life
t=1/Kao
Substituting the given values of initial concentration and half-life into equation (1), we get
k = 0.09691 m-1 s-1
The rate constant is 0.09691 m-1 s-1
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Calculate the number of moles of helium that contains 3.29 × 1021 atoms.
The number of moles of helium that contains 3.29 × 1021 atoms is 5.49 × 10-3 moles.
What is helium?
Helium is a colorless, odorless, and tasteless chemical element, and is the second-lightest element in the periodic table. It is a noble gas, meaning it has a very low level of reactivity, and it is found in abundance in the universe. In the atmosphere, helium is the second most abundant element, making up about 24% of the total elemental mass.
The number of moles of helium that contains 3.29 × 1021 atoms can be calculated using Avogadro's number. Avogadro's number is the number of atoms in one mole of a substance, which is equal to 6.02 × 1023 atoms.
Therefore, the calculation is as follows:
Number of moles of helium = 3.29 × 1021 atoms ÷ 6.02 × 1023 atoms/mole = 5.49 × 10-3 moles.
Hence, the number of moles of helium that contains 3.29 × 1021 atoms is 5.49 × 10-3 moles.
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Jim Blonde and the evil professor Malhomme are in a car chase. Blonde has a 24-km lead and travels km/h. Malhomme is going 156 km/h. Fill the table to determine when and where Malhomme will catch up to Blonde.
Malhomme will catch Blonde in a car chase at time 3 hours and distance 468 km.
What is velocity?The distance travelled divided by the time passed represents an object's average speed. Average velocity can be calculated by dividing the displacement by the time. Velocity is a vector quantity. The average velocity has the following form for the unique case of straight line motion in the x direction:
From the definition, it can be inferred that the units for velocity are metres per second or, more generally, any distance unit over any time unit.
By taking the limit as the time interval gets smaller and smaller, you can get close to an expression for the instantaneous velocity at any point along the path.
At first Blonde has a 24-km lead, so at t = 0 he is at 24 km
and in the rest of the hours we can simply add the velocity.
At
t(hours) D(Blonde) D(Malhomme )
0 24 0
1 172 156
2 320 312
3 468 468
4 616 624
Thus, Malhomme will catch Blonde in a car chase at time 3 hours and distance 468.
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how do these results disprove the plum pudding model? keep in mind that there are 1,000,000 alpha particles passing through the gold foil per second.
The model could not explain the reason because of which how alpha particles could be deflected at large angles.
Rutherford demonstrate that J.J Thompson's Plum Pudding model was not accurate and did not provide accurate results.
Rutherford made a theory that atoms have their charge concentrated in a very small nucleus.
This was famous Rutherford's Gold Foil Experiment. He actually bombarded thin foil of gold with positive alpha particles which are helium atom particles and it totally consist of two protons and two neutrons.
Rutherford observed the deflection of alpha particles on the photographic film. It notices that most of alpha particles passed straight through foil.
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When 0.10 mol NO2 is added to a 1.0-L flask at 25 °C, the concentration changes so that at equilibrium, [NO2] = 0.016 M and [N2O4] = 0.042 M. (a) What is the value of the reaction quotient before any reaction occurs? (b) What is the value of the equilibrium constant for the reaction?
(a) The value of the reaction quotient before any reaction occurs is 0.10 M.
(b) The value of the equilibrium constant for the reaction is 0.38.
The reaction quotient (Q) before any reaction occurs is the ratio of the concentrations of the products raised to their stoichiometric coefficients, to the concentrations of the reactants raised to their stoichiometric coefficients, prior to any reaction taking place.
The reaction between NO2 and N2O4 can be written as:
2NO2(g) ⇌ N2O4(g)
At the start of the reaction, before any reaction occurs, the concentration of NO2 is 0.10 M, and there is no N2O4.
Therefore, the value of Q at this point would be:
Q = (N2O4^2)/(NO2^2)
= 0.10^2 / 0
= 0
The equilibrium constant (Kc) is the value of the reaction quotient at equilibrium, which can be determined from the equilibrium concentrations of reactants and products.
Given that [NO2] = 0.016 M and [N2O4] = 0.042 M, we can calculate the value of Q at equilibrium as:
Q = (0.042^2)/(0.016^2)
= 0.38
So the value of the equilibrium constant, Kc, is equal to the value of the reaction quotient at equilibrium, which is Kc = 0.38.
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in this experiment you reflux your solvent using a water condenser. why is that necessary rather then just heating an open flask?
Refluxing a solvent using a water condenser provides a safer and more controlled environment for a chemical reaction to occur, increasing the chances of a successful outcome.
Refluxing a solvent using a water condenser is necessary because it provides a controlled environment for the reaction to occur. When a reaction mixture is heated in an open flask, the solvent can easily evaporate, causing the reaction to proceed at a different rate than desired or even stop altogether. Additionally, volatile or hazardous compounds can escape into the atmosphere, posing a safety risk.
In a reflux setup, the water condenser acts as a barrier, preventing the solvent from evaporating and also trapping any volatile compounds that may be produced during the reaction. The water flowing through the condenser helps to cool the reaction mixture, preventing it from overheating and potentially causing a dangerous runaway reaction. By controlling the temperature and limiting evaporation, refluxing helps to ensure that the reaction proceeds at a predictable and controlled rate, leading to a higher yield of product.
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a solution is prepared by adding 26.4 g of copper(ii) sulfate , cuso4, to 250. g of water. determine whether the solution is saturated, unsaturated, or if a precipitate will form given that the solubility of cuso4 is 1.38 m.
This mixture is not saturated. Considering that CuSO4 has a solubility of 1.38 mol/L, adding 26.4 g of CuSO4 to 250 g of water would provide a concentration of 0.33 mol/L, which is less than CuSO4's solubility.
What is concentration?Concentration is the ability to focus on a single task or activity and block out distractions. It requires the individual to pay attention and commit to a task, ignoring outside influences and irrelevant stimuli.
By developing the ability to concentrate, individuals can enhance their productivity and improve their performance in both academic and professional settings.
Concentration also allows individuals to better engage with material, understand its complexity, and remember the information for longer periods of time. It is a skill that can be developed and improved with practice, as well as by creating a healthy environment to focus in.
This could include limiting distractions, setting aside dedicated times for studying or working, and breaking down complex tasks into smaller, more manageable chunks.
Therefore, With the right strategies and habits, individuals can significantly improve their concentration, and in turn, increase their success.
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Give the number of grams in:
a. 8 x 10 33 particles of Sodium Chloride
b. 2 x 10 14 particles of Calcium Oxide
please show work
7.71×10¹¹g of Sodium Chloride are present in 8 x 10³³ particles. Sodium chloride (NaCl) is indeed an ionic compound.
What is sodium chloride?Sodium chloride (NaCl) is indeed an ionic compound with the chemical name (NaCl), signifying a 1:1 ratio of sodium and chlorine ions. Sodium chloride is the salt chiefly responsible for seawater saltiness and the interstitial matrix of numerous multicellular organisms.
In its edible form, table salt, it is extensively employed as a condiment as well as food preservative. Massive volumes of NaCl are employed in a variety of industrial processes and serve as a primary source of salt and chlorine compounds used as feedstocks in subsequent chemical synthesis.
mole = number of atoms/ 6.022×10²³
=8 x 10³³/ 6.022×10²³
=1.32×10¹⁰mole
mass =1.32×10¹⁰×58.44
=7.71×10¹¹g
Therefore, 7.71×10¹¹g of Sodium Chloride are present in 8 x 10³³ particles.
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Decane is a minor component in some gasolines. The standard molar enthalpy of formation of n-decane C₁0H22(0) is-249.4 kJ/mol. For the balanced reaction equation of
decane use:
C10H22(I)+ 12.5O2 --> 10CO₂ + 11H₂O.
Decane is a liquid, but all the other chemicals in this reaction are gases. What is the enthalpy change of this reaction in kJ/mol of decane?
The standard molar enthalpies of formation of:
O₂(s) - 0 kJ/mol;
CO₂(g)--393.5 kJ/mol; and
H₂O(g)--241.8 kJ/mol.
The enthalpy change of the reaction of decane would be -6582.3 kJ/mol of decane.
Enthalpy change calculationThe enthalpy change of a reaction can be calculated using the following equation:
ΔH = ∑nΔH_f(products) - ∑mΔH_f(reactants)
We are given the standard molar enthalpy of formation of n-decane, C10H22, which is -249.4 kJ/mol.
Using the balanced chemical equation, we can identify the stoichiometric coefficients of the reactants and products:
C10H22(I) + 12.5O2(g) --> 10CO2(g) + 11H2O(g)
Reactants:
n(C10H22) = 1
n(O2) = 12.5
Products:
n(CO2) = 10
n(H2O) = 11
Now we can calculate the enthalpy change of the reaction:
ΔH = ∑nΔH_f(products) - ∑mΔH_f(reactants)
ΔH = [10(-393.5 kJ/mol) + 11(-241.8 kJ/mol)] - [1(-249.4 kJ/mol) + 12.5(0 kJ/mol)]
ΔH = -6582.3 kJ/mol
The enthalpy change of the reaction is -6582.3 kJ/mol of decane.
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Can someone help me with these please?
Answer:
Hex-3-ene of Question no 5
Calculate the density of an irregularly shaped object that weighs 15.324 g. The volume of the object was measured through displacement. The initial volume in the graduated cylinder was 20.8 mL and the final volume was 34.8 mL.
The correct option is C. The density of an irregularly shaped object weighs 1.09 g/mL.
Mass = 15.324 g
The volume of the object = final volume - initial volume
= 34.8 mL - 20.8 mL
= 14 mL
Now use:
density = mass/volume
= 15.324 g / 14 mL
= 1.09 g/mL
Density (volumetric mass density or specific mass) is the substance's mass in line with a unit of volume. The symbol most usually used for density is ρ (the decreased case Greek letter rho), although the Latin letter D also can be used. Mathematically, density is defined as mass divided by using extent:
The density of cloth varies with temperature and stress. this alteration is commonly small for solids and liquids but a great deal more for gases. increasing the stress on an object decreases the volume of the object and for that reason increases its density. increasing the temperature of a substance (with a few exceptions) decreases its density by growing its volume. In maximum substances, heating the bottom of fluid results in convection of the heat from the bottom to the top, because of the lower density of the heated fluid, which reasons it to rise relative to the denser unheated fabric.
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Complete Question:
Calculate the density of an irregularly shaped object that weighs 15.324 g. The volume of the object was measured through displacement. The initial volume in the graduated cylinder was 20.8 mL and the final volume was 34.8 mL.
A).0.914g/ml
B).0.737g/ml
C).1.09g/ml
D).0.440g/ml
chemists commonly use a rule of thumb that an increase of 10 k in temperature doubles the rate of a reaction. what must the activation energy be for this statement to be true for a temperature increase from 25 to 358c?
According to Arrhenius equation, the activation energy for a temperature increase from 25°C to 358°C will be 52.4 kJ/mol.
The general rule states that the rate of reaction doubles for a 10° C increase in temperature and this applies only at a certain temperature for a given activation energy .
To establish a connection between the temperature and activation energy for the rule to be valid, we have to ignore any concentration-related temperature variations.
According to the general rule of thumb in organic chemistry, a reaction's pace doubles for every 10° increase in temperature from room temperature. For a given reaction, the ratio of its rate constant at a higher temperature to its rate constant at a lower temperature is known as its temperature coefficient, it is denoted by (Q).
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Please help!
How many grams of Potassium can be extracted from 340 grams of K2Cr2O7?
340 grams of K₂Cr₂O₇ is used, the theoretical yield of potassium would be 78.2 grams.
Potassium can be extracted from potassium dichromate ( K₂Cr₂O₇ ) by reducing it with a metal, such as aluminum or zinc.
K₂Cr₂O₇ + 6Al + 14H⁺ → 2 Cr³⁺ + 3K⁺ + 7 H₂O + 6 Al³⁺
or
K₂Cr₂O₇ + 14H⁺ + 6Zn → 2 Cr³⁺ + 3K⁺ + 7 H₂O + 6 Zn²⁺
The number of grams of potassium that can be extracted from 340 grams of K₂Cr₂O₇ depends on the stoichiometry of the reaction and the amount of reducing agent used. However, assuming a complete reaction, it is possible to calculate the theoretical yield of potassium.
In this case, one mole of K₂Cr₂O₇ yields 2 moles of potassium ions, so the number of grams of potassium produced can be calculated using the formula:
grams of K = 2 moles K × 39.1 g/mol = 78.2 g
Therefore, if 340 grams of K₂Cr₂O₇ is used, the theoretical yield of potassium would be 78.2 grams.
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--The given question is incorrect, the correct question is
"How many grams of theoretical yield of Potassium can be extracted from 340 grams of K2Cr2O7?"--
20.00 ml of a h2so4 solution with an unknown concentration was titrated to a phenolphthalein endpoint with 33.09 ml of a 0.1147 m naoh solution. what is the concentration of the h2so4 solution?
The concentration of a solution is expressed in terms of molarity. The quantity of moles of solute (the substance dissolved) per liter of solution is known as molarity, often referred to as molar concentration. The concentration of H₂SO₄ is 0.095 M.
M, sometimes known as a molar, stands for molarity. When one gram of solute dissolves in one liter of solution, the solution has a molarity of one. Since the solvent and solute combine to form a solution in a solution, the total volume of the solution is measured.
The balanced chemical equation is:
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
Number of moles of NaOH used = Molarity × volume
n = 0.1147 M × 33.09 mL
n = 3.7954 mol
one mole of H₂SO₄ reacts with two moles of NaOH. Therefore,
Number of moles of H₂SO₄ = 3.7954 ÷ 2 = 1.8977 mol
Volume of H₂SO₄ = 20.00 mL
Concentration of H₂SO₄ = Number of moles ÷ volume
C = 1.8977 mol / 20.00 = 0.09488 M
0.09488 M ≈ 0.095 M
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hy does pumping air into a tire at a constant temperature increase the pressure? responses the atmospheric pressure decreases. the atmospheric pressure decreases. the number of molecules increases. the number of molecules increases. the temperature increases. the temperature increases. the volume increases.
pumping air into a tire at a constant temperature increases the pressure volume of the tire increases slightly as air is pumped in, but this is not the main factor causing the increase in pressure.
Pumping air into a tire at a constant temperature increases the pressure because the number of air molecules in the tire increases, leading to an increase in pressure. The pressure inside a tire is directly proportional to the number of air molecules in the tire, and an increase in the number of air molecules leads to an increase in pressure. The atmospheric pressure does not change significantly in this scenario, and the temperature remains constant. The volume of the tire increases slightly as air is pumped in, but this is not the main factor causing the increase in pressure.
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Answer:
The volume increases.
Explanation:
a chemical equation is a statement using chemical that expresses both the identities and the relative of the reactants and products involved in a chemical or physical change. multiple choice question. numbers; masses formulas; quantities formulas; masses names; quantities
A chemical equation is a statement using chemical formulas expresses both the identities and the relative quantities of the reactants and products involved in a chemical or physical change. The correct answer is B.
An expression of the identities and relative quantities of the reactants and products involved in a chemical or physical transformation is called a chemical equation. Chemical equations are statements made using chemical formulas.
What exactly is a chemical equation?In chemical equations, variables like the direction of a reaction and the physical states of the reacting parties are represented by symbols. In 1615, the French chemist Jean Beguin created the first chemical equation.
Chemical equations, such as the one below, can be used to depict chemical reactions on paper (for the reaction between hydrogen gas and oxygen gas to form water).
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A student accurately measured the volume of a solution, but spilled some before measuring solution mass. What is the effect on calculated solution density?
Answer:
The solution density will decrease because the volume is the same but the mass is less
Explanation:
Density=mass÷voulme
Hydrogen peroxide decomposes into water and oxygen. The uncatalyzed reaction has activation energy of 86 kJ/mol. The Ea value in the presence of acetanilide is 112 kJ/mol and in the presence of MnO2 it is 49 kJ. What conclusion can you draw from the above observations?
The given reaction proceeds faster in the presence of manganese oxide.
catalyst:
A catalyst is a substance that speeds up a reaction without causing a permanent chemical or quantitative change. This is done by lowering the activation energy or going through another reaction pathway.
Activation energy:
The minimum energy above the normal energy that molecules must acquire when they collide to react with each other is known as the activation energy.
This reaction is carried out in the presence of acetanilide. Here, a low activation energy means a fast reaction.
Diploma:
A given reaction will proceed faster in the presence of manganese oxide because the activation energy for the reaction is lower in the presence of manganese oxide than in the presence of acetanilide.
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What is the mass of 0.10 mole of methane (CH4)?
A. 0.10 gram
B. 1.00 gram
C. 1.60 grams
D. 16.00 grams
Calculating for mass given moles:
Generally: [tex]n=\frac{n}{M} }[/tex]
n= molesm= massM or MM = molar massRearranging the equation we get:
[tex]m=nM[/tex]
1. Finding the molar mass of a compound
is the sum of the molar masses of each element respective to the coefficients and subscriptsMM of CH4:[tex]1(12.0g/mol) +4(1.01g/mol) = 16.05g/mol[/tex]
2. Insert the known values and solve
[tex]m=(0.10mol)(16.05g/mol)[/tex]
[tex]m=1.60 g[/tex]
how many milliliters of 0.1681 m ba(oh) 2 are needed to titrate 26.91 ml of 0.4714 m hcl to the equivalence point?
75.46 milliliters of 0.1681 m BaOH₂ are needed to titrate 26.91 ml of 0.4714 m HCl to the equivalence point.
Equivalence point is a point in titration at which the amount of titrant added is just enough to completely neutralize the analyte solution. At the equivalence point in an acid-base titration,
moles of base = moles of acid and
the solution only contains salt and water.
1 mole of barium hydroxide will neutralize 2 moles of HCl.
Let V ml of 0.1681 M barium hydroxide is required to neutralize 26.91 mL of 0.4714 M HCl.
Then,
0.1681M × V = 0.4714M×26.91mL
V = 75.46 mL
The volume required is 75.46 mL.
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What is empirical formula of a compound which consists of 89.14% Au and 10,80% of 0?
Au[tex]_2[/tex]O[tex]_3[/tex] is empirical formula of a compound which consists of 89.14% Au and 10,80% of oxygen.
What is empirical formula?A compound's empirical equation is defined as both the formula that displays the ratio of substances contained in the compound rather than the actual number of atoms contained in the molecule. Subscripts adjacent towards the element symbols indicate the ratios.
So because subscripts are really the fewest whole integers that reflect the ratio of components, the empirical formula also was called as the simplest formula.
moles of Au = 0.8914 g/ (196.97 g/mol) = 4.5255 x 10⁻³ mols
moles of oxygen= (0.1080 g)/ (16 g/mol) = 6.75 x 10⁻³mols
Simplest whole number ratio
Au = 4.5255 x 10⁻³ / 4.5255 x 10⁻³ moles = 1
O = 6.75 x 10⁻³ mols/ 4.5255 x 10⁻³ moles = 1.5
empirical formula= Au[tex]_2[/tex]O[tex]_3[/tex]
Therefore, empirical formula is Au[tex]_2[/tex]O[tex]_3[/tex].
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In a certain molecule, atom X is bonded to H. The force of attraction for X’s nucleus on the shared valence electron is 2.2 x 10-8 N. If the radius of atom X is 1.02 x 10-10 m, predict the number of protons in X’s nucleus. Predict the identity of atom X. Show your set-up.
Determine the atomic number, atomic mass, and number of protons, neutrons and electrons for phosphorus using the periodic table.
Help please
Atomic number is the number of protons in an atom with the symbol Z.
The periodic table is a tabular chart of the chemical elements according to their atomic numbers so that elements with similar properties are in the same group (column).
In a neutral atom, the number of protons is equal to the number of electrons in the atom. However, the number of neutrons can be derived by subtracting the neutron number from the atomic mass.
Hence, the number of protons, electrons and neutrons of phosphorus are as illustrated above.
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Please i need help asap!!!
The goodyear blimp is filled with 5.74 X 10^6 liters of Helium at STP. 256 × 10⁶ moles of helium.
What do you mean by the term mole ?The term mole is defined as the amount of a substance that includes the same number of elementary particles that are ions, molecules, or atoms as the number of atoms present in carbon.
One mole of any substance is equal to the 6.023 x 10²³ particles.
6.023 x 10²³ particles (1 mole) of any gas contains 22.4 Liters at STP. No matter what gas it is. The quantity 22.4 Liters is called the molar volume of a gas.
Therefore,
= 5.74 × 10⁶ liters of Helium 1mole / 22.4 litres
= 0.256 × 10⁶
Thus, The goodyear blimp is filled with 5.74 X 10^6 liters of Helium at STP 256 × 10⁶ moles of helium.
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a 514.0 g block of aluminum cools from 365 k to 298 k. what is the energy change associated with this temperature change from the standpoint of the block of aluminum? the specific heat of aluminum is 0.900
The energy change is 30994.2 J that is associated with the temperature change is calculated below.
The quantity of heat required to raise the temperature of one gram of a substance by one Celsius degree. The given parameters are-
T1= 365 K
T2= 298 K
m= 514.0 g
c(Aluminum)=0.900
The formula for calculating the energy change associated with this temperature change from the standpoint of the block of aluminum can be expressed as follows-
Q= m*C*del T
=514.0*0.900*(365-298)
=514*0.900*67
=30994.2 J
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Suppose 3 different experimental runs with varying concentrations of initial reactants were conducted. The time for each run to reach the concentration of I2 determined in problem number 3 was measured and recorded as follows: Run #1 8 minutes 45 seconds, Run #2 5 minutes 14 seconds, and Run #3 3 minutes 27 seconds. Determine the average rate of each experimental run in [I2]/s
The average rate of all 3 experimental run is [tex]2.38 \times 10^{-6} \text { M/s}[/tex] , [tex]3.98 \times 10^{-6} \text { M/s}[/tex] and [tex]6.04 \times 10^{-6} \text { M/s}[/tex].
Run 1st Exp.
The average rate
[tex]\frac{ \text { 0.00125 M} }{ \left ( \text { 8 minutes } \times \text { 60 seconds/minute } \right ) + \text { 45 seconds } } = 2.38 \times 10^{-6} \text { M/s}[/tex]
Run 2nd Exp.
The average rate
[tex]\frac{ \text { 0.00125 M} }{ \left ( \text { 5 minutes } \times \text { 14 seconds/minute } \right ) + \text { 45 seconds } } = 3.98 \times 10^{-6} \text { M/s}[/tex]
Run 3rd Exp.
The average rate
[tex]\frac{ \text { 0.00125 M} }{ \left ( \text { 3 minutes } \times \text { 27 seconds/minute } \right ) + \text { 45 seconds } } = 6.04 \times 10^{-6} \text { M/s}[/tex]
The average rate in chemistry refers to the speed at which a chemical reaction takes place. It is defined as the change in the concentration of a reactant or product over time. The average rate is calculated by dividing the change in concentration by the time elapsed during the reaction.
The average rate can also be used to compare the reaction rates of different chemical reactions. For example, if two reactions have the same change in concentration of a reactant, but one reaction takes twice as long as the other, then the reaction that takes less time will have a higher average rate. It is important to note that the average rate of a reaction can change over time, especially if the reaction involves multiple steps.
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calculate the amount of heat needed to melt of ice () and bring it to a temperature of . be sure your answer has a unit symbol and the correct number of significant digits.
The amount of heat needed to melt 165 g of ice (H₂O) and bring it to a temperature of 87.1 °C is 115 kJ.
The mass = 165 h
The final temperature, T = 87.1 °C
The heat of fusion , ΔH = 333 J/g
The heat is as follows :
q melt = 165 × 333
= 5.50 × 10⁴ J
The equation is :
q₂ = m c ΔT
q₂ = 165 ×4.184 × ( 87.1 - 0)
= 6.01 × 10⁴ J
The total heat required for the process is as :
q = q melt + q₂
q = 5.50 × 10⁴ J + 6.01 × 10⁴ J
q = 1.15 × 10⁵ J = 115 kJ
This question is incomplete the complete question is :
calculate the amount of heat needed to melt 165 g of ice (H₂O) and bring it to a temperature of 87.1 °C . be sure your answer has a unit symbol and the correct number of significant digits.
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propose or recommend the concentration of [cv ] that should be used in this part of the experiment when varying the hydroxide ion concentration. explain.
When varying the hydroxide ion concentration, it is recommended to use a concentration of 0.1 M for the CV.
This is because a low concentration of CV helps to reduce the effect of the hydroxide ions and maintain a more consistent pH throughout the experiment. Additionally, a low concentration of CV also reduces the amount of time required for the experiment. With the help of spectroscopy and graphical analysis, the rate law for the color-fading reaction between crystal violet and sodium hydroxide will be ascertained in this advanced inquiry lab exercise. The lab starts off with a tutorial on how to build a calibration curve for the absorbance vs concentration of the dye crystal violet. A stock solution of crystal violet is used to create a series of known or standard solutions, and the absorbance of each is measured at the ideal wavelength. In a rate law experiment, the concentration of any "unknown" dye solution can be calculated using a Beer's law plot of absorbance as a function of concentration.
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