due in 1 hour ok help

Answer:

the answer is b

Step-by-step explanation:

35 occurs the most on the graph meaning that it's the mode

Answer:

116 days because 32 percent of 365 is 116

Answer:

[tex]19.4 ms^{-2}[/tex]

Step-by-step explanation:

Newton second law: [tex]\vec F= m\vec a[/tex] We know the force, we know the mass, we can substitute and find the acceleration, which is [tex]61/3.2 = 19.4 ms^{-2}[/tex]

Answer:

3

Step-by-step explanation:

Evaluate:

Sqrt of k = 32 + m = -14

Sqrt of 32-14 = 9

Sqrt of 9 = 3

Therefore, our answer is 3!

Btw sqrt means: square root

Hope this helps! Have a good day!

Answer:

B :) (im sure btw)

Step-by-step explanation:

Answer:

-100d⁴ + 125d²s - 6s²

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

(-20d² + s)(5d² - 6s)

Step 2: Expand

The coefficients of the polynomial are rational, which means that any non-real roots occur alongside their complex conjugates. In this case, 6+i is a root, so 6-i is also a root.

So the simplest polynomial you can build with these roots is

(x - (-5)) (x - (6 + i )) (x - (6 - i )) = x ^3 - 7x ^2 - 23x + 185

(first choice)

Answer:

3072 that what I known as a 10th grader

Answer:

4th term = 29

to generate the terms, substitute n = 2, 3, 4 into the rule

noting that b(1) = - 7

b(2) = b(2 - 1) + 12 = b(1) + 12 = -7 + 12 = 5

b(3) = b(3 - 1) + 12 = b(2) + 12 = 5 + 12 = 17

b(4) = b(4 - 1) + 12 = b(3) + 12 = 17 + 12 = 29

Answer:

The answer for this question is 3

Answer:

i believe its 2 but i could be wrong

Step-by-step explanation:

im sorry if i am

Answer:

[tex]V_w =1100[/tex] ---- velocity of wind

[tex]V_a = 150[/tex] --- velocity of airplane

Step-by-step explanation:

Given

[tex]V_a \to[/tex] velocity of airplane

[tex]V_w \to[/tex] velocity of wind

Flying with the wind, the distance (d) is:

[tex]d = (V_w + V_a) * t[/tex]

Where d and t are distance travel and time spent with the wind

So:

[tex]3750 = (V_w + V_a) * 3[/tex]

Divide by 3

[tex]1250 = (V_w + V_a)[/tex]

Flying against the wind, the distance (d) is:

[tex]d = (V_w - V_a) * t[/tex]

Where d and t are distance travel and time against with the wind

So:

[tex]3800 = (V_w - V_a) * 4[/tex]

Divide by 4

[tex]950 = (V_w - V_a)[/tex]

Make [tex]V_w[/tex] the subject

[tex]V_w= 950 + V_a[/tex]

Substitute: [tex]V_w= 950 + V_a[/tex] in [tex]1250 = (V_w + V_a)[/tex]

[tex]1250 = 950 + V_a + V_a[/tex]

[tex]1250 = 950 + 2V_a[/tex]

Collect like terms

[tex]2V_a = 1250 -950[/tex]

[tex]2V_a = 300[/tex]

Divide by 2

[tex]V_a = 150[/tex]

Substitute [tex]V_a = 150[/tex] in [tex]V_w= 950 + V_a[/tex]

[tex]V_w =950 +150[/tex]

[tex]V_w =1100[/tex]

Answer:

$56.32

Step-by-step explanation:

Find the selling price by multiplying the original cost by 1.76:

32(1.76)

= 56.32

So, the selling price is $56.32

Answer:

nessa resposta da 10 beijos

Answer:

x = 18

Step-by-step explanation:

The given angles are same- side exterior angles and sum to 180°, that is

6x + 5 + 3x + 13 = 180

9x + 18 = 180 ( subtract 18 from both sides )

9x = 162 ( divide both sides by 9 )

x = 18

Answer:

where are the answer choices?

Step-by-step explanation:

Perimeter = Sum of the sides measures

Perimeter = | AB | + | AT | + | BT |

Perimeter = ( x + 3 ) + ( 4x ) + ( 2x + 2 )

40 = x + 4x + 2x + 3 + 2

Colect like terms

40 = ( 1 + 4 + 2 )x + ( 3 + 2 )

40 = 7x + 5

Subtract both sides - 5

40 - 5 = 7x + 5 - 5

35 = 7x

Switch sides

7x = 35

Divide both sides by 7

7x ÷ 7 = 35 ÷ 7

x = 5

_____________________________

AB = x + 3 = 5 + 3 ======》 AB = 8

AT = 4x = 4 × 5 =========》 AT = 20

BT = 2x + 2 = 2(5) + 2 ===》 BT = 12

According to the law of inequality in a triangle, the sum of any two random sides must be greater than the size of the other side which means :

AB + AT > BT

&

AB + BT > AT

&

AT + BT > AB

If the sides is true in the above inequalities, then those sides are able to form a triangle ;

But if even one of the above inequalities is violated, those sides will not be able to form a triangle.

8 + 20 > 12 ( Check )

8 + 12 > 20 ( Nope this inequlity violated )

Thus the measures of the sides can not represent the measures of the sides of a triangle .

And we're done ...

Answer:

perpendicular

Answer:

8. x = 16

9. x = 10

14.

m ∠RSU = 130°

m ∠UST = 50°

15.

m ∠RSU = 124°

m ∠UST = 56°

Step-by-step explanation:

8.

Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF

That is , (x + 15)° = 31°

                x = 31 - 15 =  16

9.

Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF

That is ,

           (6x - 4)° = 56°

            6x = 56 + 4

               6x = 60

                 x = 10

14.

13x + 5x = 180°                       [straight line angles ]

18x = 180

x = 10

m ∠RSU = 130°

m ∠UST = 50°

15.

4x + 12 + 2x = 180°                       [ straight line angles]

6x = 180 - 12

6x = 168

x = 28

m ∠RSU = 4(28) + 12 = 112 + 12 = 124°

m ∠UST = 2(28) = 56°

Answer:

14. 13x+5x

=18x

180(angles on a st. line)= 18x

180/18

=10

RSU=13*10=130

UST=5*10=50

Answer:

Doing the test rn got 3 1/3 i dont know if u should trust me but just try

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

The green is the starting place, when you move from a point on the green triangle to the blue one, you go 5 to the left and 3 down.

Step-by-step explanation:

the equation is:

y= -10/3 x +5

the graph as attached

34.3 cm3

if you use formula    

30mm 2970cm3

x-x un^3

Answer:[tex]3^1^1\\[/tex]

Step-by-step explanation:

[tex]\frac{81^4}{3^5}[/tex]

[tex]\frac{3^1^6}{3^5}[/tex]

The base is same power can be add or subtract

[tex]3^1^6^-^5[/tex]

[tex]3^1^1[/tex]

Answer:

answer in the link below if you have any questions let me know

Answer:

≈ 0.14

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

[tex]\frac{f(b)-f(a)}{b-a}[/tex]

Here [a, b ] = [ - 1, 3 ] , then

f(b) = f(3) = [tex]\sqrt[3]{3+3}[/tex] = [tex]\sqrt[3]{6}[/tex] ≈ 1.817

f(a) = f(- 1) = [tex]\sqrt[3]{-1+3}[/tex] = [tex]\sqrt[3]{2}[/tex] ≈ 1.260 , then

average rate of change = [tex]\frac{1.817-1.260}{3-(-1)}[/tex] = [tex]\frac{0.557}{4}[/tex] ≈ 0.14 ( to the nearest hundredth )

Answer:

[tex]\displaystyle d = 13[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Algebra II

Step-by-step explanation:

Step 1: Define

Identify

Point (-6, -8)

Point (6, -3)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Answer:

40 %

Step-by-step explanation:

no of members in youth club = 150

no of girls = 60

girls percentage = ?

girls percentage = no of girls / total members * 100%

= 60 / 150 *100%

=6000 / 150

=40 %

I don't have a value... jk jk :)

Answer: 40°

Explanation... since U is on a straight line and since GS is 140

180 - 140 = 40

Hope it helps...

Answer:

2%

60/3000g= ?/100

60×100/3000=2

Answer:

Step-by-step explanation:

Generally, we have the equation of a straight line as;

y = mx + b

where m is the slope and g is y intercept

a) The gradient is the slope and we have the value as 2

b) The y-intercept here is 5

c) for slope -3 and intercept 1, the equation becomes

y = -3x + 1

Answer:

$372.33

Step-by-step explanation:

For 1 mile= $0.45

For 827.4 miles = $0.45 x 827.4

= $372.33

The values are :

let's plug the values :

Therfore, correct answer is :

[tex]\mathfrak{good \: \: luck \: \: for \: \: your \: \: assignment}[/tex]

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

[tex] \huge\underline{\sf{\red{Problem:}}}[/tex]

[tex] \huge\underline{\sf{\red{Given:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{a = 2}[/tex]

[tex]\quad\quad\quad\quad\sf{b = - 1}[/tex]

[tex]\quad\quad\quad\quad\sf{c = - 3}[/tex]

[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶{c}^{2} + 5ab}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶{( - 3)}^{2} + 5( 2)( - 1)}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶9+ 5( 2)( - 1)}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶9+ 10( - 1)}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶9 - 10 }[/tex]

[tex]\quad \quad \quad \quad ⟶ \boxed{ \sf{ -1}}[/tex]

[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]

[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{-1}}}}[/tex]

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

#CarryOnLearning

[tex]\sf{\red{✍︎ C.Rose❀}}[/tex]