Draw the two enantiomers that are obtained upon bromination of (S)-3-methylhexane.

Answer:

Amino acid alanine

Explanation:

because it is.

The volume of the closed container that will hold 3.0 moles of this ideal gas at the same temperature and pressure is 6L.

Avogadro's law is used to predict what will happen to the volume of a sample of gas as we change the number of moles. Because V/n is a constant for any given sample of gas (at constant P and T).

The volume of an ideal gas is directly proportional to the number of moles of the gas in a container. Hence, the following expression can be used:

V₁/n₁ = V₂/n₂

Where;

2/1 = V/3

V = 6L

Therefore, a 6L closed container can be used to hold the 3 moles ideal gas.

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B.) cis-1,2-dimethylcylcohexane has two equatorial alkyl substituents in its most stable conformation

In cyclohexane ring, the most stable conformation is the one that has the lowest energy. The ring can adopt different conformations, such as the chair or the boat, depending on the position of the substituents. The most stable conformation of cyclohexane ring is the one that has maximum number of Substituents in equatorial position and minimum number of substituents in axial positions. The equatorial positions are more stable than the axial positions because they are farther apart and less crowded.In option B, cis-1,2-dimethylcylcohexane, the methyl groups are in equatorial positions, which makes it the most stable conformation among the options given.

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Nitrogen fixation does result in the release of energy, but the activation of this reaction takes energy in the form of ATP hydrolysis.

Energy is released during the nitrogen fixation process, although ATP hydrolysis is required to start the reaction. Metallocenzymes, or proteins with metallic molecules as subunits, include nitrogenases.

This type of reaction is known as a reduction reaction because it causes N2 to gain electrons (see equation above). Due to technological challenges biochemists face in actually viewing this reaction in vitro, the precise mechanism of catalysis is unknown, and the precise order of the steps of this reaction is not fully understood.

Despite this, a lot is understood about the process. The equilibrium synthesis of ammonia from molecules of hydrogen and nitrogen has a negative enthalpy of reaction overall, which means it releases energy, but the energy barrier.

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Answer:

The ozone layer is a layer of the Earth's atmosphere that protects us from the sun's harmful UV radiation.

For the following aldehydes and ketones .1 , 4 , 5 are soluble and remaining are not very soluble . ether= CH3CH2OCH2CH3,diethyl ether. Ester= CH3COOCH3, ethyl hexanoate, methyl benzoate, remaining are neither ether nor ester

Aldehydes and ketones are two types of organic compounds that belong to a class of compounds known as carbonyl compounds. The defining feature of these compounds is the presence of a carbonyl group (C=O), which is a carbon atom double-bonded to an oxygen The general structural formula for an aldehyde is R-C(=O)-H, where R can be any organic group. Ketones, on the other hand, have the carbonyl group in the middle of the carbon chain and are characterized by the general structural formula R-C(=O)-R', where R and R' can be any organic group

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the complete question is:

classify the following aldehydes and ketones as soluble in water or not very soluble in water.

Drag the appropriate items to their respective bins.

Soluble Not very soluble

Answer:

Assuming the noise remains constant, the total noise for the longer path length, 65 scans should be 0.0005 x 65 = 0.0325 absorbance units. The new reading should be 0.01 absorbance units. The signal to noise ratio (SNR) of the new measurement will be 0.01/0.0325 = 3.08.

Signal averaging decreases the magnitude of the residual noise and increases the SNR. The total noise decreases by the square root of the number of scans, in this case √65 = 8, so for 65 scans, the noise level is 8 times lower than for a single scan.

The correct option is: A liquid, because its estimated boiling point is greater than 25°C

A liquid's boiling point is determined by the temperature at which its vapour pressure equals that of the gas above it. The temperature at which a liquid's vapour pressure equals one atmosphere is known as the normal boiling point of that liquid (760 torr).

When a substance's vapour pressure reaches parity with outside pressure, that point is known as its boiling point.

H₂O₂(l) ↔ H₂O₂(g)

ΔH⁰rxn = (ΔH⁰f, H₂O₂(g) - ΔH⁰f, H₂O₂(l))

or, ΔH⁰rxn = (-136.3-(-187.8))

or, ΔH⁰rxn = 51.5 KJ/mol

or, ΔH⁰rxn = (Δs⁰f, H₂O₂(g) - Δs⁰f, H₂O₂(l))

or, ΔH⁰rxn = (233 - 110)

or, ΔH⁰rxn  = 123 J/mol.k

at the boiling point (Tb), ΔG⁰ = 0 (due to equilibrium)

As we know,

ΔG⁰ = ΔH⁰- TΔs⁰

or, 0 = 51.5*10^3 - (T*123)

or, T =  boiling point of H₂O₂

or, T = 418.7 K

or, T   = 418.7 - 273.15 K

or, T = 145.55 °C

As, boiling point of H₂O₂  is higher than room temperature (25°c). it is liquid.

Thus, a liquid, because its estimated boiling point is greater than 25°C.

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The working fluid is the substance to and from which heat is transferred in a heat engine or other cyclic device.

A heat engine is a device that converts heat energy into mechanical energy, and a key component of a heat engine is the working fluid. The working fluid is the substance that is used to transfer heat in and out of the engine.

It is the fluid that is heated and cooled during the process of converting heat into mechanical energy. The working fluid is typically a liquid or gas, and it is chosen based on its ability to efficiently transfer heat, its cost, and its availability.

The working fluid is cycled through the engine, absorbing heat from a high-temperature source, then losing heat to a low-temperature sink, and the process repeats. The working fluid plays a crucial role in the efficiency and performance of the heat engine.

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If an enzyme reduces the Ea, the given statement states that the reaction rate will alter seven times.

In a chemical reaction, one or more substances—also known as reactants—are changed into one or more additional compounds are known as products. Chemical elements or chemical compounds make up substances.

K1 and K2 are the initial and end rate constants.

Given,

Ea1 - Ea2 = 5 KJ/mol

= 5000J/mol

T = 37 oC

= 310 k

Use,

ln(k2/k1) = (Ea1 - Ea2)/(R*T)

ln(k2/k1) = 5000/(8.314*310)

ln(k2/k1) = 1.94

k2/k1 = 6.96

= 7

Since the rate constant increased by seven.

As a result, the rate has increased by seven times from the beginning.

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To find the number of moles contained in 4.131 x 10^24 particles, we need to use Avogadro's number. Avogadro's number, denoted by N, is the number of atoms, molecules, or other entities in one mole of a substance. It is approximately equal to 6.022 x 10^23.

So, we can use this formula to find the number of moles:

moles = (number of particles) / N

Where N = 6.022 x 10^23

Substituting the given value of particles:

moles = (4.131 x 10^24 particles) / (6.022 x 10^23)

moles = (4.131 x 10^24) / (6.022 x 10^23)

moles = 0.6869

So, 4.131 x 10^24 particles contains approximately 0.6869 moles.

The reaction between strontium hydroxide and chloric acid produces: D) a molecular compound and a strong electrolyte. It is solved using the concept of acid-base.

The neutralization process, which produces a salt and water molecule, occurs when an acid and a base interact. Here, the reaction between the acids chloric acid and strontium hydroxide produces strontium perchlorate and two moles of water. The strong electrolyte strontium perchlorate entirely dissociates in one direction, similar to sodium chloride. Both strontium hydroxide and chloric acid are powerful acids and bases. According to Pearson's Hard Soft Acid Base Concept, ionic complexes are created when hard acid and hard base mix. Ionic complexes often completely dissociate and are thus regarded as strong electrolytes (in the present case Strontium perchlorate).

As far as we are aware, Sr is a group 2 alkaline earth metal. Because it produces basic oxides, when it reacts with acid, salt and water are produced. Since SrO is also a basic oxide in this instance, it may react with acids like HClO₄ (chloric acid) to produce salt and water.

Thus, it will form one molecular compound that is  H₂O and one strong electrolyte that is Sr(ClO₄)₂.

The reaction is as follows:

SrO  + 2HClO₄  →   Sr(ClO₄)₂  +  H₂O

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Mass, moles and the use by firefighters are not sufficient to determine the identity of a substance. To identify a substance, more information such as chemical and physical properties, chemical reactions, and spectral data are typically required.

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The given compound undergoes an E2 elimination reaction to give an alkene.

We observed the following reaction between tert-butyl bromide and cyanide at the beginning of this lesson. This is definitely not a substitution reaction.

(CH3)3C-Br + CN(–) ——> (CH3)2C=CH2 + Br(–) + HCN

We are aware that an SN2 reaction for t-butyl bromide is not anticipated. The ethanol solvent is also insufficiently polar to support an SN1 reaction. Since it is around 10 times weaker than bicarbonate, the other reactant, cyanide anion, is both an excellent nucleophile and a respectable base. The only feasible reaction for this set of reactants, then, appears to be a base-induced elimination.

Methanethiolate is 100 times more nucleophilic than methoxide in the methanol solvent employed here. While methanethiolate is around 106 times more basic than methoxide. As a result, the reaction products exhibit a distinct difference that represents nucleophilicity (bonding to an electrophilic carbon) vs basicity (bonding to a proton).n).

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2,5-dimethylpyrazine (a) is an aromatic compound that contributes to the beautiful scent of bacon.

2,5-dimethylpyrazine is a compound that is known to contribute to the smoky, meaty aroma of cooked bacon. It is created by the Maillard reaction, which occurs when the sugars and amino acids in the bacon are heated, creating a complex mixture of flavors and aromas.

2-ethyl-3,5-dimethylpyrazine (b) is not an aromatic compound that contributes to the beautiful scent of bacon. It is a different compound that can be found in other food items, such as coffee, chocolate and roasted nuts.

So the answer is (a) and not (c) or (d)

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The indicated bonds in decreasing order of wavenumber is E. IV > II > V > I > III

Atoms, molecules, or ions can enter a liquid or solid material by a process known as absorption, which can be physical or chemical in nature.

The order of absorption of the indicated bonds in decreasing order of wavenumber is IV > II > V > I > III.

This order is based on the strength of the bond and the functional group associated with it.

The order of the absorption of functional groups are typically based on the polarity and electron density of the bond.

In general, the more polar and electron-rich the bond, the higher the wavenumber of its absorption.

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Ethyne (acetylene) was first discovered in 1836 by the Irish chemist Edmund Davy as a by-product during the medication of metallic potassium by heating an intermixture of calcined potassium tartrate with charcoal.

Carbon dioxide, water, and heat are produced when ethanol burns in the atmosphere with a sooty flame. Together with hydrogen, ethyne first produces ethene and then ethane. 1,2-Tetra halo ethanes are created when ethyne interacts with halogen acids.

Ethyne has the chemical formula C2H2. This substance is an unsaturated hydrocarbon, and in its pure form, it is incredibly unstable. Due to its two carbon atoms, which are triple linked to one another, ethyne is referred to as the most basic alkyne.

All four atoms in the ethyne molecule are aligned in a straight line because it is a linear molecule. The triple bond between carbons is just 1.20 long. In the acetylene hybrid orbital, both carbons are sp- hybridised. 

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Answer:

Without fungi in the forest, dead and rotting materials would not be broken down, which would cause dead plants and animals to pile up in the forest.

Without fungi in the forest, dead and rotting materials would not be broken down. Fungi breaks down materials, and if fungi was not in the forest, the forest would have dead and rotting, plants and animals piled up everywhere.

Explanation: My frog taught me

Doing the test rn and says its right btw!

Hope I helped yall!

The supplied statement states that the pH and S²⁻ in a 0.24M H₂S solution are 3.81 & 3.92 * 10⁻¹², respectively.

A continuous variation of a continuous phase of two and more chemicals in relative proportions up the point that is known as the boundary of solubility. Although concentrations of gases other solids are possible, the term "solution" is most frequently used to refer to the liquid condition of matter. There are many different types of solutions, such as soda water, salt-and-sugar solutions, and others. In a solution, each component resembles a single phase.

Firstly, we have

[tex]$$\begin{aligned}& \mathrm{K} a_1=1.0 \times 10^{-7}=\frac{\left[\mathrm{H}^{+}\right]\left[\mathrm{HS}^{-}\right]}{\left[\mathrm{H}_2 \mathrm{~S}\right]}=\frac{\times_1^2}{0.24} \\& \text { or, } x_1^2=0.24 \times 1.0 \times 10^{-7}=2.4 \times 10^{-8} \\& \text { or, } x_1=1.54 \times 10^{-4} \mathrm{M} \\& \text { i.e, }\left[\mathrm{H}^{+}\right]=\left[\mathrm{HS}^{-}\right]=1.54 \times 10^{-4} \mathrm{~m}\end{aligned}$$[/tex]

Again,

[tex]$$\begin{aligned}& \begin{aligned}k_{a_2}=1.0 \times 10^{-19}= & \frac{\left[\mathrm{H}^{+}\right]\left[\mathrm{S}^{2-}\right]}{\left[\mathrm{HS}^{-}\right]}=\frac{x_2^2}{1.54 \times 10^{-4}} \\\text { or, } x_2^2 & =1.54 \times 10^{-4} \times 1.0 \times 10^{-19} \\& =1.54 \times 10^{-23}=15.4 \times 10^{-24} \\\text { or, } \quad x_2 & =3.92 \times 10^{-12} \\\text { i.e., }\left[\mathrm{H}^{+}\right] & =\left[\mathrm{S}^{2-}\right]=3.92 \times 10^{-12} \mathrm{M}\end{aligned}\end{aligned}$$[/tex]

[tex]$$\text { Total } \begin{aligned}{\left[H^{+}\right] } & =1.54 \times 10^{-4}+3.92 \times 10^{-12} \\& =1.54 \times 10^{-4} \mathrm{~m} \text { (approximated) }\end{aligned}$$[/tex]

Thus, [tex]$p^H=-\log \left(1.54 \times 10^{-4}\right)=3.81$[/tex]

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At long last, change over moles to grams by increase it by the molar mass (0.1017 * 2)= 0.204 grams.

To begin with, you make a proportion between the reactants (H2O & Mg) to decide the restricting reactant so 2 mol H2O/ 1 mol Mg = 2 _calculate moles of Mg (mass/molar mass) = (4.73/24)= 0.197

moles _calculate moles of H2O (mass/molar mass) = (1.83/18)= 0.1017 moles make the proportion once more between H2O & Mg= (0.1017/0.197)= 0.5

So, H2O is the restricting reactant and as you would like the mass of H2 by comparing its moles with moles of H2O, you'll get 0.1017 moles.

Finally, change over moles to grams by duplicate it by the molar mass (0.1017 * 2)= 0.204 grams

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Answer:

wait so do you need help with

Explanation:

Answer:

true

but it depends on their habitat and geographic location

Explanation:

hope this was helpful

The plot of the pH of the analyte solution vs the quantity of titrant applied over time is known as a titration curve.

Important information can be gleaned from a titration curve's shape, which is a plot of pH against the quantity of acid or base added. The titration of a strong base given to a strong acid that starts out with a low pH is shown in the diagram i. The titration of a strong acid applied to a strong base at a high pH is shown in diagram ii. The titration of a strong base added to a weak acid, which starts out with a low pH but is in the buffer region, is shown in diagram (iii).  As there are many H+ ions present, the titration of a strong base added to polyprotic acid is shown in steps in diagram (iv).

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Na+ channels enter the neuron and increase Vm because the positive Na+ ions are more abundant concentration outside the cell than inside.

The ratio of a constituent's abundance to the total volume of the mixture is its concentration. Mass concentration, molar concentration, number concentration, and volume concentration are a few of the various categories of mathematical description. Information is sent via neurons. Electrical impulses and chemical signals are used to transport information inside different brain areas as well as between the brain and the rest of the nervous system. The two primary subtypes of brain cells are neurons and glial cells. Although they play a supporting role in the brain, glial cells predominate over neurons in numerous areas of the organ.

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The "alum" used in cooking is potassium aluminum sulfate hydrate, KAl(SO4)2·x H2O and the value of x calculated is 12.

Alum is a type of chemical compound, usually hydrated double sulfate salt of aluminum having general formula X Al ₂·12 H ₂O, where X is  monovalent cation such as potassium or ammonium.

Given mass of KAl(SO₄)₂.XH₂O = 4.74 g

and mass of water = 2.16 g

So, mass of KAl(SO₄)₂ = 4.74 – 2.16 = 2.58 g

Molar mass of KAl(SO₄)₂ ;

= 39 + 27 + 2[32 + (4×26)]

Now, molar mass of KAl(SO₄)₂ = 258 g/mol

Molar mass of H₂O ;

= (2×1) + 16

Now, molar mass of H₂O = 18 g/mol

Hence, KAl(SO₄)₂ = 2.58 / 258 = 0.01

and H₂O = 2.16 / 18 = 0.12

KAl(SO₄)₂ = 0.01 / 0.01 = 1

H₂O = 0.12 / 0.01 = 12

The formula of the compound is obtained as KAl(SO₄)₂.12H₂O

Comparing KAl(SO₄)₂.12H₂O with KAl(SO₄)₂.XH₂O,  value of X is 12.

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From the Ksp for Na3PO4, the solubility of the ions is determined to be 27S4. Solubility is a term used in chemistry to describe a substance's capacity to mix with another substance, the solvent.

Na+ and PO4-3 are the ions found in Na3PO4. Since sodium is listed on the periodic table as an alkali metal, it will create a positive charge in solution. A polyatomic ion is one that requires its charge to be remembered, such as the phosphate ion. Therefore, each unit of sodium phosphate that dissolves produces 4 ions. As a result, each molecule of Na3PO4 has a total of four ions in the solution.

Na3PO4 -> 3Na+ + [PO4 3-]

Let the solubility of each ion be S such that

Ksp = [Na+]^3 [(PO4)3-]

Ksp = (3S)^3 (S) = 27S^4 as there are 3 sodium ions and 1 phosphate ion.

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The product derived from the acyl portion of propanamide is attached below.

The study of the various spatial arrangements of atoms in molecules is the focus of the branch of chemistry known as stereochemistry. Stereochemistry is the systematic presentation of a particular area of science and technology that customarily necessitates a brief prelude into history.

Because propanamide contains a primary amine group, the carbon centre will become less electrophilic as a result. As a result, resonance structure will form, which will reduce the reactivity of the electrophilic carbon and eliminate the possibility of a high-yield product formation.

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A

following orbital diagrams reflects an atom not in the ground state

The ground state of an atom is the lowest energy level it is capable of occupying. This is the atomic energy level that would be regarded as typical.

The electrons in an atom are shown in pictures called orbital diagrams. Orbital diagrams may be created using three rules. Each electron resides in the lowest-energy orbital, in accordance with the Auf Bau Principle. Only two electrons can fit into a single orbital, according to the Pauli Exclusion Principle.

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Two peaks can be seen in the proton NMR spectra of the molecule below.

In order to ascertain the structure of a substance's molecules, proton nuclear magnetic resonance uses nuclear magnetic resonance with regard to hydrogen-1 nuclei inside its molecules. The preferred method for determining or validating the structure of organic molecules or those containing protons is H NMR. When compared to other nuclei, a solution-state proton spectrum may be obtained relatively quickly, and it contains a wealth of knowledge regarding a compound's structure. Because proton spectra are considerably easier to acquire than carbon spectra, H NMR spectroscopy is employed more frequently than 13C NMR. Since just 1% of carbon atoms have the 13C isotope, it is challenging to find.

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Part - A 164000 molecules of substrate can a molecule of enzyme process in each minute.

Part - B The kcat/KM for the enzyme reaction is  85.416×10⁶ (M.s)⁻¹

An enzyme will attach itself to one or more reactant molecules and start the reaction by catalyzing it. These molecules are the substrates for the enzyme. One substrate may undergo several product breakdowns in some reactions. Others involve the fusion of two substrates into a single larger molecule or the exchange of individual molecules.

The place on an enzyme's surface where substrates bind and the chemical reaction it catalyzes take place is called the active site of the enzyme.

(A)kcat = turnover number

kcat = Vmax/[Etotal] = ( 164×10⁻⁶ (mol/L)min⁻¹ )/(1×10⁻⁹ mol/L)

kcat = 164000 min⁻¹

(B) kcat/kM = ( 164000 min⁻¹ / 32×10⁻⁶M )

kcat/kM = 5125×10⁶ (M.min)⁻¹

kcat/kM  = 85.416×10⁶ (M.s)⁻¹.

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