Draw the Lewis Structure for C2F4. b. Total RED's c. Nonbonding RED's d. Electron-Pair Geometry e. Molecular Shape f. Is it Polar, Nonpolar or Ionic

Answer:

Without the hydrosphere, the atmosphere will no longer be able to carry up the evaporated water, as well as pour down the water, leaving the biosphere to rot away. The hydrosphere works with the Biosphere to provide the requirement of water to the organisms needs, as well as the hydrosphere assisting in photosnythesis.

Explanation:

Answer:

The hydrosphere refers to the water on the earth crust. If there were no hydrosphere, we would not have lakes, oceans, rivers, or even a hose full of water. There would also be no life. Nothing can live without water, so nothing would have evolved.  

Explanation:

boron, carbon, nitrogen, oxygen and flourine families in addition to the noble gases.

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also to answer the 'hello guys what is good!':nothin u?

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Answer:

nm, dm, km, m

Explanation:

1 nanometer = 1e-12 (0.000000000001) kilometers

1 decimeter = 1e-4 (0.0001) kilometers

1 kilometer = 1 kilometer

Regardless of whether 'm' stands for mile or meter, it's still larger than all of these being approx. 1.61 and 1e-3 (0.001) kilometers respectively.

in the future, please provide the exact units.

Such as:

nanometers, decimeters, kilometers, meters

Answer:

oxygen carbon hydrogen nitrogen

Explanation:

identified by the number of protons in its atoms

Answer:

your question is not very clear but I think the answer is either

Primary (non-rechargeable)

Secondary (rechargeable) or

Lithium-ion battery.

Rechargeable li-ion button cell.

Answer:

0.1045 L (4 s.f.)

Explanation:

The molecular weight, [tex]M_{r}[/tex], of calcium chloride is

[tex]M_{r}(\mathrm{CaCl_{2}}) \ = \ A_{r}(\mathrm{Ca}) \ + \ 2 \times A_{r}(\mathrm{Cl}) \ = \ (40 \ + \ 2 \times 35.5) \ \mathrm{g \ mol^{-1}} \ = \ 111 \ \mathrm{g \ mol^{-1}}[/tex], where [tex]A_{r}[/tex] is the atomic weight of the respective elements.

To calculate the number of moles (n) of calcium chloride present in 58g,

[tex]n_{\mathrm{CaCl_{2}}} \ = \ mass \ \div \ molecular \ weight \ (M_{r}) \\ \\ \-\hspace{1.13cm} = \ 58g \ \div \ 111 \ \mathrm{g \ mol^{-1}} \\ \\ \-\hspace{1.13cm} = \ 0.5225 \ \mathrm{mol \ of \ CaCl_{2}}[/tex]

Since molarity, M, is defined as the number of moles (n) of the solute per liters of a solution (L), hence to get the volume (V) required to make up a 5 molar solution is

[tex]n \ = \ M \times V \\ \\ V \-\hspace{0.05cm} = \ \displaystyle\frac{n}{M} \\ \\ V \-\hspace{0.05cm} = \displaystyle \frac{0.5225 \ \mathrm{mol}}{5 \ \mathrm{mol \ L^{-1}}} \\ \\ V \-\hspace{0.05cm} = \ 0.1045 \ \mathrm{L}[/tex]

The electronic configuration of magnesium is:

1s² 2s² 2p⁶ 3s² = [Ne] 3s²

This means that for a magnesium atom, in order to have its outermost orbital full, the easiest way would be to lose the two outermost electrons. This is seen in its relatively low first two ionization energies. The third ionization energy is several times higher because the ion would move from a stable form to an highly unstable form. (Mg⁺² → Mg⁺³ + e⁻).

Sodium only has one electron in its outermost orbital, so its first ionization energy would be several times lower than the second.

Answer:

Yes

Explanation:

Because first of all you used yellow food coloring second you added it third the mixute turned the color of yellow

Answer:

Explanation:

Consider the general chemical reaction

                                                       [tex]\mathrm{A} \ \overset{k}{\longrightarrow} \ \mathrm{product}[/tex]  .

If [A] is the concentration of A (reactant) at any time t and n is the reaction order for the whole equation, the rate is then related to the concentration of reactant A with the following differential form of equation

                                               [tex]Rate \ = \ -\displaystyle\frac{d[\mathrm{A}]}{dt} \ = \ k[\mathrm{A}]^{n}[/tex]  .

where k is the rate constant.

*Note that the differential term [tex]\displaystyle\frac{d[\mathrm{A}]}{dt}[/tex] has a negative sign to denote that the concentration of A is decreasing over time t.

Since the chemical reaction between tert-butyl bromide and water is given to be a first-order reaction, hence n = 1, and the resulting differential equation becomes

                                        [tex]Rate \ = \ -\displaystyle\frac{d[\mathrm{A}]}{dt} \ = \ k[\mathrm{A}]^{1} \ = \ k[\mathrm{A}][/tex]

To solve this first-order linear homogenous differential equation, the method of separation of variables can be used.

[tex]\-\hspace{1cm} \displaystyle\frac{d[\mathrm{A}]}{dt} \ = -\ k[\mathrm{A}] \\ \\ \-\hspace{0.5cm} \displaystyle\frac{1}{[\mathrm{A}]} \, d[\mathrm{A}] \ = -\ k \, dt \\ \\ \int\ {\displaystyle\frac{1}{[\mathrm{A}]} \, d[\mathrm{A}] \ = \ -\int {k} \, {dt}[/tex]

         [tex]\ln{[\mathrm{A}]} \ = \ -kt \ + \ C \\ \\ \-\hspace{0.45cm} $[A]$ \ = \ e^{-kt \ + \ C} \\ \\ \-\hspace{0.45cm} $[A]$ \ = \ e^{-kt}e^{C} \ \ \ \ \ \ \ \ \ (e^{a \ + \ b} \ = \ e^{a}e^{b} \ \ \ \mathrm{by \ the \ law \ of \ indices})[/tex]

Since the term [tex]e^{C}[/tex] is a constant, let [tex]\alpha \ = \ e^{C}[/tex], hence [tex][\mathrm{A}] \ = \ \alpha e^{-kt}[/tex] or [tex]C \ = \ \alpha e^{-kt}[/tex] according to the question. Given that the initial concentration (t = 0) of tert-butyl bromide is 0.2 mol/L and k = 0.0537[tex]\mathrm{h^{-1}}[/tex], so

[tex]0.2 \ = \ \alpha e^{-0.0537 \ \times \ 0} \\ \\ 0.2 \ = \ \alpha \ \ \ \ \ (e^{0} \ = \ 1)[/tex]

Therefore, the rate equation is [tex]C \ = \ 0.2e^{-0.0537t}[/tex].

The concentration of tert-butyl alcohol after 1 hour is

[tex]C \ = \ 0.2e^{-0.0537 \ \times \ 1} \\ \\ C \ = \ 0.2e^{-0.0537} \\ \\ C \ = \ 0.190 \ \mathrm{mol/L} \ \ \ (3 \ \ \mathrm{s.f.})[/tex]

bcz the defination of matter is that

anything which occupy space

Hence , option a is correct

There are 2 electrons in the overlapping region.

Chlorine is the second member of the halogen group which are form of family of elements that resemble one another very closely.

The electronic configuration of chlorine shows the arrangement of chlorine electrons within it's atom.

At the outer most shell of the atom is seven electrons, therefore requires only one electron each to attain the octet arrangement.

The overlapping of the orbitals indicates the chemical bond formed by sharing of electrons between atoms called covalent bonding.

To complete it's outer most shell, it will need to share electron with another chlorine atom.

Therefore, there are 2 electrons in the overlapping region.

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Answer:

Water will generally require more energy for a phase change compared to a similar substance without hydrogen bonds.

Explanation:

Answer:

About 58%.

Explanation:

We first need to write the balanced chemical equation:

[tex]\displaystyle \text{CH$_4$(g)} + 2\text{O$_2$(g)} \longrightarrow \text{CO$_2$(g)} + 2\text{H$_2$O(g)}[/tex]

We are given that 0.809 g of carbon dioxide was produced from the reaction of 0.80 g of methane and 2.1 g of oxygen gas. We want to calculate the percent yield of carbon dioxide.

First, determine the limiting reagent. We can convert each initial mass to the mass of carbon dioxide using stoichiometry. The molar mass of methane is 16.05 g/mol and the molar mass of carbon dioxie is 44.01 g/mol. From the equation, every one mole of carbon dioxide is produced from every one mole of methane and every two moles of oxygen gas.

0.80 g of methane will (theoretically) produce:

[tex]\displaystyle \begin{aligned} 0.80 \text{ g CH$_4$} &\cdot \frac{1 \text{ mol CH$_4$}}{16.05 \text{ g CH$_4$}} \cdot \frac{1 \text{ mol CO$_2$}}{1 \text{ mol CH$_4$}} \cdot \frac{44.01 \text{ g CO$_2$}}{1 \text{ mol CO$_2$}} \\ \\ & = 2.2 \text{ g CO$_2$}\end{aligned}[/tex]

2.1 g of oxygen gas will (theoretically) produce:

[tex]\displaystyle \begin{aligned} 2.1 \text{ g O$_2$} & \cdot \frac{ 1 \text{ mol O$_2$}}{32.00 \text{ g O$_2$}} \cdot \frac{1 \text{ mol CO$_2$}}{2 \text{ mol O$_2$}}\cdot \frac{44.01 \text{ g CO$_2$}}{1 \text{ mol CO$_2$}} \\ \\ & = 1.4 \text{ g CO$_2$} \end{aligned}[/tex]

Hence, oxygen gas is the limiting reagent. A maximum of 1.4 g of carbon dioxide can be produced.

To calculate the percent yield, we divide the actual yield by the theoretical yield. The actual yield was 0.809 g and the theoretical yield is 1.4 g. Hence:

[tex]\displaystyle \begin{aligned} \%\text{Yield} & = \frac{\text{Actual}}{\text{Theoretical}} \times 100\% \\ \\ & = \frac{(0.809\text{ g CO$_2$})}{(1.4\text{ g CO$_2$})} \times 100\% \\ \\ & = 58\%\end{aligned}[/tex]

In conclusion, the percent yield of carbon dioxide is about 58%.

Answer:

A

Explanation:

reason:

H-F is most polar

because bond is polarized negative towards F which is the more electronegative atom.

Answer:

yes here is the answer key

for the last question it is a challenge question, here is the answer:

(A) The mass of the cart is 1.214 kg

(B) The mass of one fan is 1.262 kg

(C) The mass of one of the draggable mass units is 3.131 kg

Explanation:

Explanation:

The oxidation number of Ni is +4

Answer:

plastic,palstic bottle,balloon,cap of water bottle,plastic slippers and plastic comb.

Explanation:

hope it helps :D

The concentration of NaOH in the reaction can be determined using the Titration method.

The concentration of NaOH in the reaction can be determined by titration.

A burette if filled with the known concentration of H₂SO₄ and then titrated against the known volume of NaOH in a conical flask. An indicator is used in order to determine the end-point of the titration process. At the end-point of the titration, the volume of acid used is recorded.

Next, we will write the balanced chemical equation of the reaction.

The balanced chemical equation for the reaction is

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

This means 2 moles of NaOH is required to neutralize 1 mole of H₂SO₄

Now, we can determine the concentration of NaOH by using the titration formula.

[tex]\frac{C_{A}V_{A} }{C_{B}V_{B}} = \frac{n_{A}}{n_{B}}[/tex]

Where [tex]C_{A}[/tex] is the concentration of acid

[tex]V_{A}[/tex] is the volume of acid

[tex]C_{B}[/tex] is the concentration of base

[tex]V_{B}[/tex] is the volume of base

[tex]n_{A}[/tex] is the mole ratio of acid

[tex]n_{B}[/tex] is the mole ratio of base

Then, we put the respective parameters, including the volume of acid determined from the titration process, into the formula to determine the concentration of the NaOH.

Hence, the concentration of NaOH in the reaction can be determined using the Titration method.

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The average atomic mass of her sample is 114.54 amu

Let the 1st isotope be A

Let the 2nd isotope be B

From the question given above, the following data were obtained:

The average atomic mass of the sample can be obtained as follow:

[tex]Average \: atomic \: mass \: = \frac{mass \: of \: A \times A\%}{100} + \frac{mass \: of \: B \times B\%}{100} \\ \\ Average \: atomic \: mass \: = \frac{113.6459\times 59.34}{100} + \frac{115.8488\times 40.66}{100} \\ \\ Average \: atomic \: mass \: = 114.54 \: amu \\ \\ [/tex]

Thus, the average atomic mass of the sample is 114.54 amu

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Answer:

1050-452 = 598, the liquid is more than the ammonium chloride so it is the majority

Answer:

1.533 moles Au

Explanation:

To find the moles from atoms, you just use Avogadro's number (6.02214076×10^23 mol^-1) and divide by it. Hope this helped!

Answer:

[tex]\boxed {\boxed {\sf 1.53 \ mol \ Au}}[/tex]

Explanation:

We are asked to find how many moles of gold are in 9.23 *10²³ atoms of gold.

Avogadro's Number or 6.022 *10²³ is used to convert atoms to moles. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of gold.

We convert using dimensional analysis. Set up a conversion factor using Avogadro's Number.

[tex]\frac {6.022 \times 10^{23} \ atoms \ Au}{ 1 \ mol \ Au}[/tex]

We are converting 9.23 * 10²³ atoms of gold to moles, so we multiply by this value.

[tex]9.23 \times 10^{23} \ atoms \ Au *\frac {6.022 \times 10^{23} \ atoms \ Au}{ 1 \ mol \ Au}[/tex]

Flip the conversion factor so the units of atoms of gold cancel.

[tex]9.23 \times 10^{23} \ atoms \ Au *\frac { 1 \ mol \ Au}{6.022 \times 10^{23} \ atoms \ Au}[/tex]

[tex]9.23 \times 10^{23} *\frac { 1 \ mol \ Au}{6.022 \times 10^{23}}[/tex]

[tex]\frac {9.23 \times 10^{23} }{6.022 \times 10^{23} } \ mol \ Au[/tex]

[tex]1.53271338426 \ mol \ Au[/tex]

The original measurement of atoms has 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 2 in the thousandth place tells us to leave the 3.

[tex]1.53 \ mol \ Au[/tex]

9.23 *10²³ atoms of gold is equal to approximately 1.53 moles of gold.

The most generally accepted form of conclusive evidence for the theory of Evolution is the fossil record.

Therefore, we can confirm that the most generally accepted form of conclusive evidence for evolution is the presence of fossils that show the genetic correlation between two organisms and the progression of evolution between them.

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Answer:

objects thaty release 0H+ and H- ions when dissociated

Explanation:

in chemistry

please mark brainliest

Answer:

Determining what data to collect.

Explanation:

Answer:

6.023×10^23

Explanation:

Molecular mass= 2 (H)+1 (O) =2*1+1*16=2+16= 18 gm per 1gm molecule of water

Answer:

The three specific cone cells in our eyes work together, allowing us to translate these three colors of light into millions of different colors. ... When green and blue light are combined, they make cyan. Red and green light make yellow. And when all three primary colors of light are combined, we see white light.

Explanation:

Answer:

d took the test

Explanation: