Dorris earns $12.25 in interest over 15 months, while Max earns $2.84 in interest over the same period. So, Dorris earns more interest than Max.
To find out who earns more interest in 15 months, we can calculate the interest earned by each person using the formula:
Interest = Principal x Rate x Time
For Dorris, we have:
Interest = $200 x 0.041 x (15/12)
Interest = $12.25
For Max, we have:
Interest = $300 x 0.019 x (15/12)
Interest = $2.84
Interest refers to the cost of borrowing money, usually expressed as a percentage of the amount borrowed over a specific period of time. When someone borrows money, they are required to pay back not only the amount borrowed but also an additional amount, which is the interest. Interest is how lenders make money and is an important component of the financial system.
There are different types of interest rates, including fixed and variable rates. A fixed interest rate remains the same throughout the loan term, while a variable interest rate may change based on market conditions. Interest rates can also be compounded, which means that interest is added to the principal amount, and future interest payments are calculated based on the new higher amount.
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A square mirror is framed with stained glass as shown. Each corner of the frame began as a square with a side length of d inches before it was cut to it the mirror. The mirror has a side length of 3 inches. The area of the stained glass frame is 91 square inches. a. Write a polynomial that represents the area of the stained glass frame.What is the side length of the frame?
Therefore, the side length of the frame is approximately 3.18 inches.
What is length?Length is a physical property that describes the distance between two points in space. It is a fundamental dimension in the study of geometry and is usually measured in units such as meters, centimeters, feet, or inches. In the context of mathematics, length can refer to the size or magnitude of a line segment, curve, or other geometric shape.
By the question.
To find the area of the stained-glass frame, we need to subtract the area of the mirror from the area of the larger square formed by the cut corners of the frame. Let's call the side length of each cut square "x".
The larger square formed by the cut corners has side length (3 + x + x) = (3 + 2x) since each cut square adds x inches to the original side length of the mirror.
The area of the larger square is then. [tex](3 + 2x)^{2}[/tex] = 9 + 12x + 4[tex]x^{2}[/tex]square inches.
The area of the mirror is[tex]3^{2}[/tex] = 9 square inches.
The area of the stained-glass frame is the difference between these two areas:
(9 + 12x + 4[tex]x^{2}[/tex]) - 9 = 12x + 4[tex]x^{2}[/tex]
We know that the area of the stained-glass frame is 91 square inches, so we can set this equal to the polynomial we just derived and solve for x:
12x + 4[tex]x^{2}[/tex] = 91
4[tex]x^{2}[/tex] + 12x - 91 = 0
We can use the quadratic formula to solve for x:
[tex]x= \frac{(-12±\sqrt{(12)^{2} -4*4(-91)}}{8}[/tex]
[tex]\frac{x= (-12±\sqrt{1480}}{8}[/tex]
We can discard the negative solution since we are looking for a positive length for the frame, so:
[tex]\frac{x= (-12±\sqrt{1480}}{8}[/tex]
x ≈ 3.18
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Help me with this it's to hard for me
Answer:
Part B: Calculate the range and interquartile range (IQR) for each group and interpret what they tell us about the data.
For Group A:
Range = 5 - 1 = 4
Q1 = 2
Q3 = 4
IQR = Q3 - Q1 = 2
For Group B:
Range = 5 - 2 = 3
Q1 = 2
Q3 = 4
IQR = Q3 - Q1 = 2
The range for Group A is larger than the range for Group B, indicating that there is more variability in the growth of the plants in Group A. However, both groups have the same IQR, indicating that the middle 50% of the data in each group is similar. This suggests that while there may be some variability in the growth of the plants, the overall distribution of growth is similar between the two fertilizers.
X = 9 y = 4 is a solution of the linear equation (a) 2x+y=17 (b) x+y=17 (c) x+2y=17 (d) 3x-2y=17
Answer:
(c) is correct.
Step-by-step explanation:
(c) 9 + 2(4) = 9 + 8 = 17
find the number equivalant to the ratio 25:6
Answer:
A ratio of 25 to 6 can be written as 25 to 6, 25:6, or 25/6. Furthermore, 25 and 6 can be the quantity or measurement of anything, such as students, fruit, weights, heights, speed and so on. A ratio of 25 to 6 simply means that for every 25 of something, there are 6 of something else, with a total of 31
Step-by-step explanation:
done hope u like it !!
1. Find the given derivative by finding the first few derivatives and observing the pattern that occurs. (d115/dx115(sin(x)). 2. For what values of x does the graph of f have a horizontal tangent? (Use n as your integer variable. Enter your answers as a comma- separated list.) f(x) = x + 2 sin(x).
The values of x such that the graph of f has a horizontal tangent are;x = 2π/3 + 2πn, 4π/3 + 2πn, where n is an integer.
1. The given derivative can be found by finding the first few derivatives and observing the pattern that occurs as shown below;Differentiating sin x with respect to x gives the derivative cos x. Continuing this process, the pattern that emerges is that sin x changes sign for every odd derivative, and stays the same for every even derivative. Therefore the 115th derivative of sin x can be expressed as follows;(d115/dx115)(sin x) = sin x, for n = 58 (where n is an even number)2. To find the values of x such that the graph of f has a horizontal tangent, we differentiate f with respect to x, and then solve for x such that the derivative equals zero. We have;f(x) = x + 2sin xDifferentiating f(x) with respect to x gives;f'(x) = 1 + 2cos xFor a horizontal tangent, f'(x) = 0, thus;1 + 2cos x = 02cos x = -1cos x = -1/2The solutions of the equation cos x = -1/2 are;x = 2π/3 + 2πn or x = 4π/3 + 2πnwhere n is an integer. Therefore the values of x such that the graph of f has a horizontal tangent are;x = 2π/3 + 2πn, 4π/3 + 2πn, where n is an integer.
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The radius of a circle is 8 meters. What is the circle's circumference?
Use 3.14 for л.
Answer:
circumference=50.24
Step-by-step explanation:
c=2x3.14xr
c=2x3.14x(8)
c=50.24
A landowner wishes to use 3 miles of fencing to enclose an isosceles triangular region of as large an area as possible. What should be the lengths of the sides of the triangle? Let x be the length of the base of the triangle. Write the area as a function of x. [First write the length of the equal-length sides in terms of the base, x, then write the height of the triangle in terms of the base.] V3 A(x) = 4 x Length of base = 1 miles Length of the other two (equal-length) sides = 2 x miles each
The area of the triangle, A(x), can be expressed as A(x) = (x * sqrt(3x^2/4))/2 and the height of the triangle, h, can be expressed as h = sqrt(3x^2/4) in terms of the base.
The landowner wishes to use 3 miles of fencing to enclose an isosceles triangular region of as large an area as possible. Let x be the length of the base of the triangle.The length of the base of the triangle is x miles, while the length of the other two equal-length sides are 2x miles each. Thus, the total length of the three sides of the triangle is 3x miles, which equals 3 miles of fencing as required.
To find the area of the triangle, we must first calculate the height of the triangle. Using the Pythagorean Theorem, we can calculate the height of the triangle in terms of the base. The formula is h^2 = (2x)^2 - (x/2)^2. Thus, the height of the triangle, h, can be expressed as h = sqrt(3x^2/4).The area of the triangle is equal to the base multiplied by the height and divided by two. Thus, the area of the triangle, A(x), can be expressed as A(x) = (x * sqrt(3x^2/4))/2.
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when a vertical beam of light passes through a transparent medium, the rate at which its intensity i decreases is proportional to i(t), where t represents the thickness of the medium (in feet). in clear seawater, the intensity 3 feet below the surface is 25% of the initial intensity i0 of the incident beam. what is the intensity of the beam 17 feet below the surface? (give your answer in terms of i0. round any constants or coefficients to five decimal places.)
The intensity of the beam 17 feet below the surface is 0.440265 times the initial intensity i0 of the incident beam is I(17) ≈ 0.002678.
It can be calculated as:
Let I(t) be the intensity of the beam at a depth of t feet below the surface, and
let k be a constant of proportionality.
Then we have:
[tex]dI/dt = -kI[/tex]
This equation says that the rate of change of intensity with respect to depth is proportional to the intensity itself, and the negative sign indicates that intensity decreases as depth increases.
We can solve this differential equation using separation of variables:
[tex]dI/I = -k dt[/tex]
[tex]\int\ dI/I = \int\ -k dt[/tex]
[tex]ln(I) = -kt + C[/tex]
[tex]I = e^{(C - kt)}[/tex]
where C is the constant of integration.
Now we can use the given information to find the value of k and the constant of integration C.
We know that at a depth of 3 feet below the surface, the intensity is 25% of the initial intensity i0:
[tex]I(3) = 0.25 i0[/tex]
[tex]e^{(C - 3k)} = 0.25 i0[/tex]
We also know that the depth at which we want to find the intensity is 17 feet below the surface:
t = 17
Now we can use the equation we derived earlier to find the intensity at a depth of 17 feet:
[tex]I(17) = e^{(C - 17k)}[/tex]
To find the constant of integration C and the constant of proportionality k, we can use the fact that we have two equations with two unknowns. First, we can solve the equation for C:
[tex]e^{(C - 3k)} = 0.25 i0[/tex]
[tex]C - 3k = ln{(0.25 i0)}[/tex]
[tex]C = ln{(0.25 i0)} + 3k[/tex]
Now we can substitute this expression for C into the equation for I(17):
[tex]I(17) = e^{(C - 17k)}[/tex]
[tex]I(17) = e^{(ln(0.25 i0) + 3k - 17k)}[/tex]
[tex]I(17) = e^{(ln(0.25 i0) - 14k)}[/tex]
Finally, we can solve for k using the fact that we know the intensity decreases by a factor of 0.25 when the depth increases from 0 to 3 feet:
[tex]dI/dt = -kI[/tex]
[tex]ln(I) = -kt + C[/tex]
[tex]I(3) = 0.25 i0[/tex]
[tex]e^{(C - 3k)} = 0.25 i0[/tex]
Taking the natural logarithm of both sides, we have:
[tex]C - 3k = ln{(0.25 i0)}[/tex]
Substituting the expression for C we derived earlier, we have:
[tex]ln{(0.25 i0)} + 3k - 3k = ln{(0.25 i0)}[/tex]
[tex]ln{(0.25 i0)} = ln{(0.25 i0)}[/tex]
This equation is true for all values of k, so we can choose any value for k that satisfies the differential equation.
For simplicity, we can choose[tex]k = ln(4)/3[/tex], which makes the constant of proportionality equal to[tex]-ln(4)/3.[/tex]
Now we can substitute this value of k into our expression for I(17) and simplify:
[tex]I(17) = e^{(ln(0.25 i0) - 14k)}[/tex]
[tex]I(17) = e^{(ln(0.25 i0) - 14ln(4)/3)}[/tex]
[tex]I(17) = 0.25 i0 e^{(-14ln(4)/3)}[/tex]
[tex]I(17) \approx 0.002678[/tex]
The intensity of the beam 17 feet below the surface is approximately 0.002678.
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suppose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.56 and a standard deviation of 0.38 . using the empirical rule, what percentage of the students have grade point averages that are between 1.42 and 3.7 ?
Using the empirical rule, the percentage of the students have grade point averages that are between 1.42 and 3.7 is 99.7%
How do we use the empirical rule?The empirical rule states that for a bell-shaped distribution, the percentage of data that lie within a specified number of standard deviations from the mean is as follows: 68% of the data lie within 1 standard deviation of the mean. 95% of the data lie within 2 standard deviations of the mean
99.7% of the data lie within 3 standard deviations of the mean. Mean = 2.56Standard Deviation = 0.38We want to know what percentage of students have a grade point average between 1.42 and 3.7. To do this, we need to convert 1.42 and 3.7 into standard deviations away from the mean.
Using the z-score formula:(1.42-2.56)/0.38 = -2.99 and(3.7-2.56)/0.38 = 3.00This tells us that a grade point average of 1.42 is about 2.99 standard deviations below the mean, and a grade point average of 3.7 is about 3 standard deviations above the mean.
Using the empirical rule, we know that 99.7% of the data lies within 3 standard deviations of the mean. So the percentage of students that have a grade point average between 1.42 and 3.7 is approximately 99.7%.Thus, the correct answer is 99.7%.
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Explain what is wrong with the statement. If 0 = f (x) = g(x) and g(x) dx diverges then by the comparison test so f(x)dx diverges. x O If 0
The statement is incorrect due to the invalid assumption of f(x) = g(x) = 0, and the incorrect application of the comparison test.
The comparison test states that if 0 ≤ f(x) ≤ g(x) and the integral of g(x) dx diverges, then the integral of f(x) dx also diverges. However, the statement assumes that f(x) and g(x) are equal to zero, which means that 0 ≤ f(x) ≤ g(x) is not satisfied.
Additionally, the assumption that g(x) dx diverges does not necessarily imply that f(x) dx also diverges. For example, let g(x) = 1/x^2 and f(x) = 0 for all x. Then g(x) dx diverges, but f(x) dx converges to zero.
In conclusion, the statement is incorrect due to the invalid assumption of f(x) = g(x) = 0, and the incorrect application of the comparison test.
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Solve for x,
using the tangent lines.
13 cm
X
x = [?] cm Remember: a. b = c. d
The value οf x accοrding tο the circle and the tangent figure is 13 cm.
What is tangent?A tangent οn any curve is an extended straight line that tοuches οnly a single pοint οf the curve and nοwhere else
Tangent οn a circle is always perpendicular tο the radius οf the circle
Here, we have 2 tangents A (x) and B (13) subtended frοm twο pοints οf the same circle.
The Tangent οn a circle is perpendicular tο the radius thrοugh the pοint οf cοntact and thus the triangle fοrmed in the figure is right-angled.
Sο, frοm a pοint οutside the circle, if 2 tangents are drawn, bοth will have the same length tο the pοint οf cοntact οn the circle.
Here, the twο tangents have the same exteriοr pοint where the tangent initiates. Thus, frοm the abοve theοry, x = 13 cm.
Hence, the length οf the οther tangent tο the circle pοint οf cοntact i.e. x is 13 cm.
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Answer: 13
Step-by-step explanation:
x is congruent to 13
the pictograph below shows the approximate gross revenues in the united states from four walt disney animated movies. find the ratio of the gross revenue of the hunchback of notre dame to the gross revenue of beauty and the beast. a. 1
b. 2/3
c. 3
d. 2
e. 3/2
14x+312=2(12x+34)
What is the value of x?
A. 2 over 3
B. 5 over 4
C. 3 over 2
D. 8 over 3
Answer:
None of the given options matches the value we got for x, but the closest option is A. 2 over 3. However, we need to note that x is not a whole number, it's a decimal.
Step-by-step explanation:
Let's solve the given equation
14x+312=2(12x+34)
Distribute the 2 on the right-hand side
14x+312=24x+68
Subtract 14x from both sides
312=10x+68
Subtract 68 from both sides
244=10x
Divide both sides by 10
x=24.4
Answer:
2 over 3
Step-by-step explanation:
none of the options match the value of x
ABC ~ PQR. If AB : PQ = 4:5,
find A(ABC): A(PQR).
Area (ABC) is measured as Area (PQR), which equals 16:25.
To locate,
Area (ABC) is measured as: (PQR).
Solution,
This mathematical issue can easily resolved by utilising the procedure outlined below:
According to the "Area of Similar Triangles Theorem" in mathematics,
When two triangles are similar, their area ratios are proportional to the square of the ratio of the respective sides.
{Statement-1}
In light of the query and assertion 1, we can state,
Area (ABC) is measured as: (PQR)
= (AB: PQ), (BC: QR), and (AC: PR)
= (4:5)2 = (4/5)2
= 16/25 = 16:25
As a result, Area (ABC): Area (PQR) is measured at 16:25.
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Given the following data, find the weight that represents the 28th percentile.
Weights of Newborn
Babies
6.1 9.1 9.5 6.0 8.6
6.2 9.1 6.1 8.0 5.7
6.5 6.4 5.8 9.3 6.2
Therefore, 6.1 pounds are the weight that corresponds to the 28th percentile.
what is percentile ?In statistics, a percentile is a metric that shows the value below which a specific percentage of observations in a group fell. It is frequently used to evaluate an individual's or a group's performance in relation to a specific metric against a broader population. A dataset's 75th percentile, for instance, is the number below which 75% of the observations fall and above which the remaining 25% of observations fall.
given
These procedures must be taken in order to determine the weight that corresponds to the 28th percentile:
5.7, 5.8, 6.0, 6.1, 6.2, 6.4, 8.0, 8.6, 9.1, 9.1, 9.3, 9.5 are the weights to order in ascending sequence.
Determine the 28th percentile's rank:
28th percentage = 28/100 x 13 = 3.64 (rounded up to 4)
Identify the 6.1-pound weight at the fourth level.
Therefore, 6.1 pounds are the weight that corresponds to the 28th percentile.
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On Friday night, 165 people saw the dinosaur exhibit at the natural history museum. This amount represents 22% of the people who visited the museum that night.
A total of ______ people visited the natural history museum Friday night.
36
133
750
1500
A total of 750 people visited the natural history museum on Friday night.
The total number of people who visited the natural history museum on Friday night can be calculated by dividing the number of people who saw the dinosaur exhibit (165) by the percentage of visitors who saw the exhibit (22%).
To do this, we can use the following formula:
Total number of visitors = Number of visitors who saw the exhibit ÷ Percentage of visitors who saw the exhibit
Substituting the given values, we get:
Total number of visitors = 165 ÷ 0.22 = 750
Therefore, a total of 750 people visited the natural history museum on Friday night.
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I need help somebody please
Answer: 54 square in
Step-by-step explanation:
I don't know if this is the same person but I answered this same question just now please check my profile or comment if you want the explanation
suppose that 78% of all dialysis patients will survive for at least 5 years. in a simple random sample of 100 new dialysis patients, what is the probability that the proportion surviving for at least five years will exceed 80%, rounded to 5 decimal places?
The probability that the 78% of all the dialysis patients survive for at least five years will exceed 80%, rounded to 5 decimal places is 0.3192.
What is the probability?The proportion of dialysis patients surviving for at least 5 years = 78% = 0.78
Assuming that a simple random sample of 100 dialysis patients is selected, the sample size is n = 100.
Let p be the proportion of dialysis patients in the sample surviving for at least 5 years.
Then, the sample mean is given by:
μp = E(p) = p = 0.78
So, the mean proportion of dialysis patients surviving for at least 5 years is equal to 0.78.
The standard error of the sample proportion is given by:
σp=√p(1−p)/n
σp=√0.78(1−0.78)/100
σp=0.04278
The required probability is to find P(p > 0.80):
P(p > 0.80) = P(Z > (0.80 - 0.78)/0.04278)
P(p > 0.80) = P(Z > 0.467) = 1 - P(Z < 0.467) = 1 - 0.6808 = 0.3192 (rounded to 5 decimal places)
Therefore, the probability that the proportion surviving for at least five years will exceed 80% in a simple random sample of 100 new dialysis patients is 0.3192.
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67% of all americans are home owners. round your answers to four decimal places. if 37 americans are randomly selected, find the probability that
Answer: Exactly 26 of them are are home owners
Step-by-step explanation:
A researcher wished to compare the average amount of time spent in extracurricular activities by high school students in a suburban school district with that of high schoolers in a school district of a large city. The researcher obtained an SRS of 60 high school students in a large suburban school district and found the mean time spent in extracurricular activities per week to be x1 = 6 hours, with a standard deviation s1 = 3 hours. The researcher also obtained an independent SRS of 40 high school students in a large city school district and found the mean time spent in extracurricular activities per week to be x2 = 4 hours, with a standard deviation s2 = 2 hours. Let u1 and u2 represent the mean amount of time spent in extracurricular activities per week by the populations of all high school students in the suburban and city school districts, respectively.
Assume the two-sample t-procedures are safe to use. With a level of 5%, test the hypothesis that the amount of time spent on extracurricular activities is no different in the two groups.
Since the calculated t-value (3.14) is greater than the critical value (1.98), we reject the null hypothesis.
What is null hypothesis?In statistical hypothesis testing, the null hypothesis is a statement about a population parameter that is assumed to be true until there is sufficient evidence to suggest otherwise. The null hypothesis is typically denoted by H0 and represents the status quo or default assumption.
The null hypothesis often takes the form of an equality or a statement of "no difference" or "no effect" between two or more groups, variables, or populations. For example, the null hypothesis could be that the mean score of a group of students on a test is equal to a certain value, or that there is no difference in the average height of males and females in a population.
We want to test the hypothesis that the mean amount of time spent in extracurricular activities per week is the same in the suburban and city school districts. Set up the null and alternative hypotheses is as given by:
Null hypothesis: u1 - u2 = 0
Alternative hypothesis: u1 - u2 ≠ 0
To test this hypothesis, we can use a two-sample t-test. We first calculate the test statistic:
t = ((x1 - x2) - (u1 - u2)) / √(s1²/n1 + s2²/n2)
where x1, s1, and n1 are the sample mean, standard deviation, and sample size for the suburban school district, and x2, s2, and n2 are the sample mean, standard deviation, and sample size for the city school district.
Plugging in the values, we get:
t = ((6 - 4) - 0) / √((3²/60) + (2²/40)) ≈ 3.14
This test's degrees of freedom are given by:
df = (s1²/n1 + s2²/n2)² / ( (s1²/n1)² / (n1 - 1) + (s2²/n2)² / (n2 - 1) )
Plugging in the values, we get:
df = ((3²/60) + (2²/40))² / ( (3²/60)² / 59 + (2²/40)² / 39 ) ≈ 93.24
Using a t-distribution table with 93 degrees of freedom and a level of significance of 0.05, we find the critical values to be approximately -1.98 and 1.98.
Since the calculated t-value (3.14) is greater than the critical value (1.98), we reject the null hypothesis and conclude that there is sufficient evidence to suggest that the mean amount of time spent in extracurricular activities per week is different between the suburban and city school districts.
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Snyder’s Moving company has two segments of customer: Small Business (SB) and Residential. 10% of Snyder’s 2,200 clients fall into both categories, using Snyder’s as their mover of choice for both their business and personal needs. The remaining clients are split evenly between segments. A client who falls into one category will use Snyder’s once every 3 years. Clients who fall into both categories use Snyder’s twice every 3 years. SB moves cost 15% more to the clients than Residential moves due to additional insurance costs for Snyder’s. The average profit Snyder’s makes per move, regardless of which type, is $260. Snyder recently launched a marketing campaign to all SB-only clients to encourage them to use Snyder’s for residential moves. 10% of recipients decided to do so. Assuming the campaign cost $500 to execute, how profitable was it?
The marketing campaign by Snyder's Moving company was profitable, generating an additional profit of $31,288 after subtracting the cost of the campaign. The total revenue generated after the campaign was $403,588.
To determine the profitability of the marketing campaign, we need to calculate the additional profit generated by the clients who were convinced to use Snyder's for residential moves.
Let's start by calculating the number of clients in each segment
Clients who fall into both categories, 0.1 x 2,200 = 220
Clients in each segment, (2,200 - 220) / 2 = 990
Now let's calculate the revenue generated by each segment
Revenue from clients in each segment: 990 clients x $260 profit per move = $257,400
Revenue from clients who fall into both categories: 220 clients x 2 moves x $260 profit per move = $114,400
Total revenue generated: $371,800
Now let's calculate the revenue generated after the marketing campaign
10% of 990 SB-only clients decided to use Snyder's for residential moves
0.1 x 990 = 99 clients
Additional revenue generated from these clients: 99 clients x $260 profit per move x 1.15 (15% higher price for SB moves) = $31,788
Total revenue generated after the marketing campaign, $403,588
Finally, let's subtract the cost of the marketing campaign
Profit generated after the marketing campaign: $403,588 - $500 = $403,088
Therefore, the marketing campaign was profitable, generating an additional profit of $31,288.
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in how many ways can a class of 40 students select a committee from the class that consists of a president, a vice president, a treasurer and a secretary g
The total number of ways of selecting the committee is, therefore,40 x 39 x 38 x 37= 7,903,040
A class of 40 students select a committee from the class that consists of a president, a vice president, a treasurer, and a secretary in the following way:Step-by-step explanation:The number of ways that a class of 40 students can choose a committee consisting of a president, vice president, treasurer, and a secretary can be found by using the permutation formula.If we assume that the positions of the committee members are different, the number of ways can be calculated as follows:The number of ways of selecting the president from 40 students is 40.The number of ways of selecting the vice president from the remaining 39 students is 39.The number of ways of selecting the treasurer from the remaining 38 students is 38.The number of ways of selecting the secretary from the remaining 37 students is 37.The total number of ways of selecting the committee is, therefore,40 x 39 x 38 x 37= 7,903,040Thus, secretary.
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Is the relation a function, and what is the range.
last one is the answer
Step-by-step explanation:
not a function because every input has more than 1 output
Y is directly proportional to x if x=20,when y=160,then what is the value of x when y=3. 2
Answer: 0.4
Step-by-step explanation:
I genuinly cant be asked to explain.
Compute the directional derivative of the following function at the given point Pin the direction of the given vector. Be sure to use a unit vector for the direction vector.f(x,y)=ln(5+3x2+2y2); P(2,−1); ⟨1,1⟩
The directional derivative of the function at the given point P in the direction of the given vector is:
(8/21)√(2).
Directional derivativeThe directional derivative of a function in the direction of a unit vector is the rate at which the function changes in that direction.
To compute the directional derivative of f(x, y) = ln(5 + 3x^2 + 2y^2) at the point P(2, -1) in the direction of the vector ⟨1, 1⟩, we need to:
Compute the gradient of f(x, y) at P(2, -1).Normalize the direction vector ⟨1, 1⟩ to obtain a unit vector.Compute the dot product of the gradient of f at P with the unit direction vector.The gradient of f(x, y) is given by:1) ∇f(x, y) = (6x / (5 + 3x^2 + 2y^2), 4y / (5 + 3x^2 + 2y^2))
Therefore, the gradient of f at P(2, -1) is:
∇f(2, -1) = (24/21, -4/21)
2) To obtain a unit vector in the direction of ⟨1, 1⟩, we need to divide it by its length:
||⟨1, 1⟩|| = √(1^2 + 1^2) = sqrt(2)
Therefore, a unit vector in the direction of ⟨1, 1⟩ is given by:
u = ⟨1, 1⟩ / √2) = ⟨√(2)/2, √(2)/2⟩
3) The directional derivative of f at P in the direction of u is given by:
D_uf(2, -1) = ∇f(2, -1) · u
where "·" denotes the dot product. Substituting the values for ∇f(2, -1) and u, we get:
D_uf(2, -1) = (24/21, -4/21) · (√(2)/2, √(2)/2)
= (24/21)(√(2)/2) + (-4/21)(√(2)/2)
= (8/21)√(2)
Therefore, the directional derivative of f(x, y) at P(2, -1) in the direction of ⟨1, 1⟩ is (8/21)√(2).
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A rectangle has a perimeter of 48 feet. Which dimensions could the rectangle have? Choose two. A) 6 feet x 8 feet B) 12 feet x 12 feet C) 16 feet x 8 feet D) 12 feet x 4 feet
Note: I am bad at math
Answer:
Let the length of the rectangle be l and the width be w. Then, according to the problem statement, we have:
Perimeter of rectangle = 2(l + w) = 48 feet
Dividing both sides by 2, we get:
l + w = 24 feet
Now we can check the options:
A) 6 feet x 8 feet: l + w = 6 + 8 = 14 feet, which is not equal to 24 feet. Therefore, this option is not correct.
B) 12 feet x 12 feet: l + w = 12 + 12 = 24 feet, which is equal to the given perimeter. Therefore, this option is correct.
C) 16 feet x 8 feet: l + w = 16 + 8 = 24 feet, which is equal to the given perimeter. Therefore, this option is correct.
D) 12 feet x 4 feet: l + w = 12 + 4 = 16 feet, which is not equal to 24 feet. Therefore, this option is not correct.
So, the correct options are B) 12 feet x 12 feet and C) 16 feet x 8 feet.
A+9 as a verbal expression
Answer:
"9 more than A" is a verbal expression.
A certain medicine is given in an amount proportional to a patient's body weight. Suppose a patient weighing 162 pounds requires 216 milligrams of medicine. What is the weight of a patient who requires 220 milligrams of medicine?
A patient weighing 220 pounds needs 293 milligrams of medicine.
We have given that,
patient weighing 162
pounds requires 216 milligrams of medicine
We have to calculate the amount of medicine required by a patient weighing 220 pounds
Consider the value of amount of medicine is x.
Set up a proportion.
pounds / milligrams of medicine
What is the proportion we get?
[tex]162/216=220/x[/tex]
So,
[tex]162/216=220/x[/tex]
[tex]162x=216\times220[/tex]
[tex]162x=47,520[/tex]
[tex]x=47,520/162[/tex]
[tex]x=293[/tex]
A patient weighing 220 pounds needs 293 milligrams of medicine.
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parabola a and parabola b both have the x-axis as the directrix. parabola a has its focus at (3,2) and parabola b has its focus at (5,4). select all true statements.
a. parabola A is wider than parabola B
b. parabola B is wider than parabola A
c. the parabolas have the same line of symmetry
d. the line of symmetry of parabola A is to the right of that of parabola B
e. the line of symmetry of parabola B is to the right of that of parabola A
In the following question, among the given options, Option (b) "Parabola B is wider than Parabola A" and option (d) "The line of symmetry of Parabola A is to the left of that of Parabola B" are the true statements.
The following statements are true about the parabolas: c. the parabolas have the same line of symmetry, and d. the line of symmetry of parabola A is to the right of that of parabola B.
Parabola A and Parabola B have the x-axis as the directrix, with the focus of Parabola A at (3,2) and the focus of Parabola B at (5,4). As the focus of Parabola A is to the left of the focus of Parabola B, the line of symmetry for Parabola A is to the right of the line of symmetry of Parabola B.
Parabola A and Parabola B may have different widths, depending on their equation, but this cannot be determined from the information given.
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HELPPP
12 divided by five +32 x 2.2
Answer:
To evaluate this expression, you need to follow the order of operations, which is:
Do any calculations inside parentheses first. (There are no parentheses in this expression.)
Exponents or radicals (There are no exponents or radicals in this expression.)
Multiplication or division, from left to right. (Perform 32 x 2.2, which equals 70.4.)
Addition or subtraction, from left to right. (Perform 12 divided by five, which equals 2.4, then add that to 70.4.)
Therefore, the answer is:
12 ÷ 5 + 32 x 2.2 = 2.4 + 70.4 = 72.8