Doland is currently driving his car at 10 m/s. He sees Gooby and accelerates at 20 m/s2 for 2 seconds until he passes him to scare
him. How far did Doland drive during that time.
Answers
Answer:
[tex]60\; \rm m[/tex].
Explanation:
Refer to the velocity-time diagram attached. The displacement of an object over a period of time is equal to the area of the region between the velocity-time plot and the horizontal time axis. That is the case even if the velocity of the object is changing over time.
For the car in this question, the distance travelled in that two seconds should be equal to the trapezoid highlighted in green. That's the region bounded with:
on the top: the velocity-time function of this car, on the two sides: the start and end of the acceleration ([tex]\text{Time} = 0\; \rm s[/tex] and [tex]\text{Time} = 2\; \rm s[/tex],) as well as on the bottom: the horizontal time axis.The formula for the area of a trapezoid is:
[tex]\displaystyle \text{Trapezoid Area} = \frac{1}{2}\times \text{Height} \times (\text{Upper Base} + \text{Lower base})[/tex].
For the imaginary trapezoid on this velocity-time graph:
Height: [tex]\text{Time taken} = 2\; \rm s[/tex].Upper base and lower base: [tex]\text{Initial velocity} = 20\; \rm m \cdot s^{-1}[/tex] and [tex]\text{Final velocity} = 20\; \rm m \cdot s^{-1} + 2\; \rm s \times 20\; \rm m \cdot s^{-1} = 50\; \rm m \cdot s^{-1}[/tex].Therefore:
[tex]\begin{aligned}&\text{Displacement} \\ &= \text{Area of the imaginary trapezoid}\\ &= \frac{1}{2} \times 2\; \rm s \times \left(10\; \rm m \cdot s^{-1} + 50\; \rm m \cdot s^{-1}\right)\\ &= 60\; \rm m\end{aligned}[/tex].
Related Questions
An automobile travels a displacement of 75km 45 degrees north of east. How many kilometers north does it travel?
Answers
Answer:
It travelled 53.03 Km North.
The distance traveled by the automobile is 53.03 km north.
The given parameter:
the displacement of the automobile, = 75 km 45 degrees north of east.
To find:
the distance traveled by the automobileThe vertical component of the displacement is equal to the distance traveled by the automobile in north.
[tex]distance \ towards \ north = 75 \ km \ \times \ sin(45)\\\\distance \ towards \ north = 75 \ km \times 0.7071\\\\distance \ towards \ north = 53.03 \ km \ north[/tex]
Thus, the distance traveled by the automobile is 53.03 km north.
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An internal combustion engine has an efficiency of 22.3%. This engine is used to deliver 6.25 x 104 J of work to drive the motion of the train. What is the total energy that needs to be put into the engine.
Answers
Answer:
Only about 12%–30% of the energy from the fuel you put in a conventional vehicle is used to move it down the road, depending on the drive cycle. The rest of the energy is lost to engine and driveline inefficiencies or used to power accessories. Therefore, the potential to improve fuel efficiency with advanced technologies is enormous.
Dust particles fall down when a carpet or a piece of cloth is beaten by a stick,why?
Answers
Dust particles fall down when we hit the carpet or a piece of cloth with a stick because it loses it inertia of rest and move forward, but dust particles fall down in absence of the carpet.
Two balls are released from the same height on the moon. They both reach the ground at the same time. Which statement is correct about the two balls
Answers
Answer:
same acceleration
Explanation:
An electric iron of resistance 20Ω takes a current of 5A. Calculate the heat developed in 30seconds?
Answers
The amount of heat (H) produced is given by the joule’s law of heating as H= Vlt
Where,
Current, I = 5 A
Time, t = 30 s
Voltage, V = Current x Resistance = 5 x 20 = 100V
H= 100 x 5 x 30 = 1.5 x 10⁴ J.
Therefore, the amount of heat developed in the electric iron is 1.5 x 10⁴J.
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Which motor and body should Devon use to build the car with the greatest acceleration? motor 1, with body 1 motor 1, with body 2 motor 2, with body 1 motor 2, with body 2
Answers
Answer:
hello your question is incomplete below is the complete question
Devon has several toy car bodies and motors. The motors have the same mass, but they provide different amounts of force, as shown in the table.
Which motor and body should Devon use to build the car with the greatest acceleration?
motor 1, with body 1
motor 1, with body 2
motor 2, with body 1
motor 2, with body 2
answer: Motor 2 body 1
Explanation:
F = ma
hence a ( acceleration ) = F / m
force of motor 2 = 15 N since the mass of the motor is the same and that of the bodies aren't given
The motor and body that would produce the greatest acceleration would be : Motor 2 Body 1 if the mass of Body 1 is less than the mass of Body 2
Answer:
c
Explanation:
A box 5cm long, 4cm wide and 6cm high would have what volume? Show your work
Answers
Explanation:
volume= length×width×height
5cm×4cm×6cm = 20×6= 120cm³The table displays the scores of students on a recent exam. Find the mean of the
scores to the nearest 10th.
Score Number of Students
65
4.
70
2
75
2
80
1
85
7
90
5
Answers
Answer:
Solution
x f fx
65 4 260
70 2 140
75 2 150
80 1 80
85 7 595
90 5 450
total N=21 Summation fx=1675
We know
Mean= Summation fx/N
=1675/21
=79.8
Hence, the required mean is 79.8 ans.
The scores of students on a recent exam. The mean of the scores is 51.42857.
What is mean?The mean is the ratio of addition of all the observation values and the number of observations.
The mean of the score is equal to
Mean = {(65×4)+(70×2)+(75×2)+(80×1)+(85×7)+(90×5)} / (4+2+2+1+7+5)
Mean = 51.42857
Therefore, the mean of the scores is 51.42857.
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A car traveling at 30 mis runs out of gas while traveling up a 10o slope. How far up the hill will the car coast before starting to roll back down
Answers
Answer:
5.21 milesExplanation:
The set up will be a right angle triangle (an inclined plane). The height of the inclined plane is the opposite side of the triangle while the distance traveled by the car along the slope will be the hypotenuse with angle of inclination of 10°.
Using the SOH trigonometry identity i.e sinθ = opposite/hypotenuse
sin 10° = opposite/30
opposite = 30sin10°
opposite = 5.21 miles
Hence the car must have traveled 5.21 miles up the hill before starting to roll back down.
where would information on the chemical and physical properties of a specific chemical be located in a laboratory or in the workplace?
Answers
Answer:
on the body of the container of the chemical and it also on the shelf where the chemical is kept in the laboratory.
Explanation:
The information on the chemical and physical properties of a specific chemical should be located on the body of the container of the chemical. when storing chemicals in a laboratory the properties, both chemical and physical properties of the chemical should be written out and pasted on the body of the container that contains the chemicals.and also o the shelf where the chemical is kept in the laboratory or workplace .
4) A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.
a) What is their speed during that run?
b) What is their velocity?
I
c) If they kept running at that velocity for another 1.3 seconds, what would their
final position be?
Answers
Answer:
(a). Their speed during that run is 10 m/s.
(b). Their velocity is 6.86 m/s
(c). The final position is at 8.91 m.
Explanation:
Given that,
A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.
Suppose, the distance between 40 yard line and 25 yard line is 20 yard.
(a). We need to calculate their speed during that run
Using formula of speed
[tex]v=\dfrac{d}{t}[/tex]
Where. d = distance
t = time
Put the value into the formula
[tex]v=\dfrac{18.288}{2}[/tex]
[tex]v=10\ m/s[/tex]during that run
(b). We need to calculate their velocity
Using formula of speed
[tex]v=\dfrac{\Delta d}{\Delta t}[/tex]
Put the value into the formula
[tex]v=\dfrac{22.86-36.58}{2}[/tex]
[tex]v=-6.86\ m/s[/tex]
Negative sign shows the direction of motion.
(c). If they kept running at that velocity for another 1.3 seconds,
We need to calculate the final position
Using formula of position
[tex]d=vt[/tex]
Put the value into the formula
[tex]d=6.86\times1.3[/tex]
[tex]d=8.91\ m[/tex]
Hence, (a). Their speed during that run is 10 m/s.
(b). Their velocity is 6.86 m/s
(c). The final position is at 8.91 m.
What is the current in a circuit that has a power of 200 W and a resistance of 150 Ω
Answers
Answer:
Current = 1.15 AExplanation:
Since we are finding the current
Power in a circuit can be found by using the formula
[tex]P = I ^{2} R[/tex]Where
I is the current
R is the resistance
P is the power
From the question
Power = 200 W
Resistance = 150 Ω
Substitute the values into the above formula and solve for the current
That's
[tex]200 = 150{I}^{2} [/tex]Divide both sides by 150
We have
[tex] {I}^{2} = \frac{200}{150} \\ = \frac{4}{3} [/tex]Find the square root of both sides
We have
[tex]I = \sqrt{ \frac{4}{3} } [/tex]= 1.154700
We have the final answer as
Current = 1.15 A
Hope this helps you
Which sport requires participants to wear safety equipment during competition?
Answers
Answer:
Football
Explanation:
Answer:
Hockey
Explanation:
The answer is hockey because in order to play hockey you have to have a lot of safety equipment because people play hockey by being very close to one another. Also, getting hurt during playing hockey without proper equipment can cause many damages to your body.
Hope this helps! :D
A woman dropped a dime in a wishing well , she heard it 30 sec later ..Find velocity on impact while moving at 9.8 m/s 2
Answers
Answer:
The velocity at impact is 222.2 m/s
Explanation:
The given information are;
The time at which the woman heard the sound of the coin after dropping it into the wishing well = 30 seconds
The average speed of sound in air = 344 m/s
The time in which the dime travel = t₁
The time in which the sound travel = t₂
1/2 × 9.8 × t₁² = 344 × t₂
t₁ + t₂ = 30
4.9·t₁² = 344 × (30 - t₁)
4.9·t₁² + 344·t₁ - 10320 = 0
Which gives -344±
[tex]t_1 = \dfrac{-344\pm \sqrt{344^{2}-4\times 4.9 \times 10320}}{2\times 4.9}[/tex]
t₁ = 22.676 seconds or -92.9 seconds
Therefore the correct natural time is t₁ = 22.676 seconds
The velocity at impact, v = g×t₁ = 9.8 × 22.676 = 222.2 m/s
The velocity at impact= 222.2 m/s.
If a man travels from 0m to 5m then back to -3m, all in four seconds, what is the mans displacement?
Answers
Answer:
-3 m
Explanation:
Displacement is the final position minus the initial position.
Δx = x − x₀
Δx = -3 m − 0 m
Δx = -3 m
A light beam travels through a diamond (n=2.42) to pure water (n=1.33). The refracted ray will:
a) bend toward the normal
b) bend away from the normal
c) remain unchanged
d) bend toward the normal then away
Answers
Answer:
b) bend away from the normal
Explanation:
According to snell's law , if i be the angle of incidence and r be the angle of refraction
sin i / sin r = 1.33 / 2.42
sin i / sin r = .55
Hence sin r > sin i
r > i
In other words angle of refraction will be more than angle of incidence . So, the ray will bend away from the normal .
HELP PLEASE !!!!!!! If a ball is accelerating down through the air with no horizontal motion, what must be true about the net forces acting on the ball? The gravitational force is greater than the drag. The net force on the ball is zero. The drag is greater than the gravitational force. The net force on the ball is directed upward.
physics
Answers
Answer:
A. The gravitational force is greater than the drag.
Explanation:
Remember that the second Newton's law says that:
F = m*A
Force equals mass times acceleration.
With this we will see that the correct option is:
"The gravitational force is greater than the drag."
We know that the ball is accelerating downwards, and there is no horizontal motion. Because the acceleration is downwards, we know that the net force must be downwards (for the second law).
Now, what must be true about the net forces acting on the ball? let's analyze each statement:
1) "The gravitational force is greater than the drag."
The gravitational force is what causes the objects to fall down to the ground, so if the ball is falling, this will always be true.
2) " The net force on the ball is zero."
We know that the ball is accelerating, thus the net force can not be zero, this is false.
3) "The drag is greater than the gravitational force. "
This is the opposite to the first option, this is false.
4) "The net force on the ball is directed upward."
The acceleration and the net force have the same direction, if the ball is accelerating downwards, then the net force is directed downwards. This is false.
Then the only true statement is the first one:
"The gravitational force is greater than the drag."
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What is the angular separation of two spectral lines of wavelengths 497 nm and 251 nm formed in the third order with a diffracting grating having 587 lines per millimeter
Answers
Answer:
34.8°
Explanation:
Given the following :
Number of lines (N) = 587mm
529mm to m = 587*1000 = 587000 per meter
d = 1 / N ; 1/587000 = 0.00000170357
Wavelength of light waves :
λ1 = 497nm = 497 × 10^-9 m
λ2 = 251nm = 251 × 10^-9 m
Angular position in 3rd order; m=3
For
λ1 ; dsinθ3 = 3λ1 ;
λ2 = dsinθ3 = 3λ2
Substituting values
dsinθ3 = 3λ1 =
0.00000189 * sinθ3 = 3 * 497 × 10^-9
θ3(1) = sin^-1(1491 * 10^-9 / 0.00000170357)
θ3(1) = sin^-1(0.8752208)
θ3(1) = 61.07°
λ2 = dsinθ3 = 3λ2
0.00000189 * sinθ3 = 3 * 251 × 10^-9
θ3(2) = sin^-1(753 * 10^-9 / 0.00000170357)
θ3(1) = sin^-1(0.4420129)
θ3(1) = 26.23°
Angular separation :
61.07° - 26.23° = 34.84°
34.8°
Jaune moves North 15 meters, South 5 meters, then North 8 meters. How far is Jaune DISPLACED?
Answers
Answer:
Displacement = 7 meters
Explanation:
Given that,
Jaune moves North 15 meters, South 5 meters, then North 8 meters. We need to find the displacement of Jaune.
The attached figure shows the motion of Jaune.
We know that, Displacement = final position - initial position
Initially, Jaune traveled 15 meters due North and finally, he travel 8 meters North.
Displcement = 15 m - 8 m
Displacement = 7 m
So, the displacement of Jaune is 7 meters.
Two students make a model of a tree house they want to
The scale is 1:44. In the scale model, the tree house
has 2 windows.
How many windows should the real tree house have?
O A. 2
O B. 22
C. 4
D. 88
Answers
Answer:
A 2
Explanation:
Scaling deals with measurements.
for example, the question says, 1 : 44. Assuming we're using cm : m, this is inferring that, 1 centimeter on the model will represent 44 meters in real life. This means, the number of windows in the real tree will be carried down to the model, only the sizes would be reduced.
if a window in the real tree measures 44 meters, then it would be scaled down to be 1 centimeter on the model.
irrespective, models doesn't change the number of features, only the dimensions.
800 J of heat is needed to raise the temperature of 2 kg of iron by 1°C. What is the heat capacity of 3.6 kg of iron?
Answers
Answer: 1440 J/kg/degree Celsius
Explanation:
Heat capacity = thermal energy required / change in heat
Tech A says that when a fuse has blown, it just has to be replaced, because it performed its job. Tech B says that when a fuse has blown, the circuit has to be diagnosed because the fuse was probably not the problem. Who is correct
Answers
Answer:
tech B
Explanation:
im assuming its ASE or CDX i got my ase certification
you should also always replace that fuse its there to stop a harmful amount of voltage to said thing like a starter or a a fan
As a 1850 kg car is traveling down a road, it experiences a force of friction of 121 N and a force of air resistance if 186N. If the engine is not applying any force, what is the acceleration of the car
Answers
Answer:
-0.166 m/s²
Explanation:
F = Ma
a = F/M = (121 N +186 N)/(1850 kg) = 0.166 m/s²
The acceleration of 0.166 m/s² is in the direction opposite to the direction of travel, so might be considered to be negative.
Answer:
-0.166 m/s²
As a 1850 kg car is traveling down a road, it experiences a force of friction of 121 N and a force of air resistance if 186N. If the engine is not applying any force, what is the acceleration of the car
What is your average velocity or speed if you travel 500 km in 3 hours
Answers
Answer:
166.6 km/h
Explanation:
500/3
=166.6
An atom of sodium-23 (Na-23) has a net charge of +1. Identify the number of protons, neutrons, and electrons in the atom. Then, explain how you determined the number of each type of particle
Answers
Answer:
11 protons, 12 neutrons, 10 electrons
Explanation:
Sodium has an atomic number of 11, so it has 11 protons.
The atomic mass is 23, so there are 23 − 11 = 12 neutrons.
The charge is +1, so there is 1 more proton than electrons, so there are 10 electrons.
where would information on the chemical and physical properties of a specific chemical be located in a laboratory or in the workplace?
Answers
Answer:
Both
Explanation:
A cell membrane has a thickness of about 7 nm. How many cell membranes would it take to make a stack 3.4 in high?
Answers
Answer:
486 of cell membranes
Explanation:
one cell membrane has 7*10^-9m as the height
So, by dividing 3.4 with 7*10^-9 you will get the number of cell require to form the height.
3.4/(7*10^-9)=485.71
because we can't have decimal number of cell we would round it into three significant figures, 486.
How much time does it take for a car with a speed of 85 m/s to drive a distance of 200 m? (1 point)
Answers
The car will take 2.35 seconds to drive a distance of 200 m.
What is speed?
Speed is a physical quantity that is a measure of the rate of change in the position of an object. It is the rate of change of distance with respect to time. Speed is a scalar quantity and is expressed as the magnitude of velocity, which is the rate and direction of motion of an object. Speed is measured in meters per second (m/s).
To find the time it takes for the car to drive a distance of 200 m with a speed of 85 m/s, we can use the formula:
time = distance / speed
Plugging in the values given, we get:
time = 200 m / 85 m/s
Simplifying this expression, we get:
time = 2.35 s
Therefore, it takes 2.35 seconds for the car to drive a distance of 200 m with a speed of 85 m/s.
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if an object is moving with constant speed then its distance-time graph will be a straight line. (a)along time axis. (b)along distance axis (c)parallel to time axis (d)inclined to time axis
Answers
Answer: (d)inclined to time axis
Explanation:
For a moving object, the distance equation can be written as:
D = S*t
if S = 0, we will have a line parallel to the time axis.
if S = infinity we will have a line parallel to the distance axis.
Both options are discarded here, as S = ∞ is not possible, and S = 0 would mean that the object is not moving.
where D is the distance moved at the time t, t is the variable, and S is the speed of the object.
As S is constant, this equation defines a linear relationship.
The graph of this line will be a line that is not parallel either to the time axis nor the distance axis, this will be an inclined line that goes between them.
So the correct option is: (d)inclined to time axis
HELP ME PLS!
Determine the presssure at the bottom of a container filled
with gasoline, if the height of the container is 200 cm long.
The gasoline's density is 680 kg/m3.
Answers
Explanation:
Pressure = Height * Density * acc. due to gravity
P = 2 * 680 * 9.8 = 13, 328 Pa
Answer:
13328pa
Explanation:
p = hgd
h = height = 200cm = 2m
g = 9.8m/s²
d = density = 680kg/m³
p = pressure
p = 2 x 9.8 x 680 = 13328pa