Answer:
no
Explanation:
ans should be correct
Define Newton's law of motion?
Connected to a battery that offers a d.d.p. of 3.0Volts, we have the four lamps, all identical with resistances equal to 2.0 Ohms. The association appears in the figure. Note that the switch is open, so it doesn't pass current in the circuit (it's like an off switch). When the key closes, the lamps come on. Determining the Req of the association and the total current flowing through the circuit, we will find:
Answer:
Option D. 5Ω e 0.6 A
Explanation:
1. Determination of the equivalent resistance.
We'll begin by calculating the equivalent resistance of resistor B and resistor C. This can be obtained as follow:
Resistor B (R₆) = 2 Ω
Resistor C (R꜀) = 2 Ω
Equivalent Resistance (R₆꜀) =?
R₆꜀ = R₆ × R꜀ / R₆ + R꜀ (parallel connection)
R₆꜀ = 2 × 2 / 2 + 2
R₆꜀ = 4 / 4
R₆꜀ = 1 Ω
Finally, we shall determine the equivalent resistance of the circuit. This can be obtained as follow:
Resistor A (Rₐ) = 2 Ω
Equivalent resistance of resistor B and C (R₆꜀) = 1 Ω
Resistor D (Rₔ) = 2 Ω
Equivalent Resistance (R) =?
R = Rₐ + R₆꜀ + Rₔ (series connection)
R = 2 + 1 + 2
R = 5 Ω
Thus, the equivalent resistance of the circuit is 5 Ω
2. Determination of the total current in the circuit.
Potential difference (V) = 3 V
Equivalent resistance (R) = 5 Ω
Total current (I) =?
V = IR
3 = I × 5
Divide both side by 5
I = 3 / 5
I = 0.6 A
Thus, the total current in the circuit is 0.6 A
Summary:
Equivalent resistance = 5 Ω
Current = 0.6 A
Option D gives the current answer to the question.
Which of the following is not an example of bias
A. Pro hi FRUCTOSE corn syrup ADVERTISEMENTS paid for by corn farmers
B. anti-smoking articles written by the national health ASSOCIATION
C. anti-by four articles written by a journalist working for it Oil company
D Pro ADHD medicine article written by PHARMACEUTICAL
Answer:
B
Explanation:
The writers are from a trusted source that is considered impartial. The message is backed up by scientific investigation, and the writers have no monetary gain from their message.
A 90 kg astronaut Travis is stranded in space at a point 12 m from his spaceship. In order to get back to his ship, Travis throws a 0.50 kg piece of equipment so that it moves at a speed of 4 m/ s directly away from the spaceship towards the left . How long will it take him to reach the ship? *hint find his speed after the collision and consider it a constant speed all the way back to his spaceship*
Answer:
Explanation:
This is a recoil problem, which is just another application of the Law of Momentum Conservation. The equation for us is:
[tex][m_av_a+m_ev_e]_b=[m_av_a+m_ev_e]_a[/tex] which, in words, is
The momentum of the astronaut plus the momentum of the piece of equipment before the equipment is thrown has to be equal to the momentum of all that same stuff after the equipment is thrown. Filling in:
[tex][(90.0)(0)+(.50)(0)]_b=[(90.0)(v)+(.50)(-4.0)]_a[/tex]
Obviously, on the left side of the equation, nothing is moving so the whole left side equals 0. Doing the math on the right and paying specific attention to the sig fig's here (notice, I added a 0 after the 4 in the velocity value so our sig fig's are 2 instead of just 1. 1 is useless in most applications).
0 = 90.0v - 2.0 and
2.0 = 90.0v so
v = .022 m/s This is the rate at which he is moving TOWARDS the ship (negative was moving away from the ship, as indicated by the - in the problem). Now we can use the d = rt equation to find out how long this process will take him if he wants to reach his ship before he dies.
12 = .022t and
t = 550 seconds, which is the same thing as 9.2 minutes
A 4 LBfweight is attached to a spring suspended from the ceiling. When the weight comes to rest at equilibrium, the spring has been stretched 3 inches. The damping constant for the system is 2 LBf−sec ft . If the weight is raised 9 inches above equilibrium and given an initial upward velocity of 2 ft/sec, determine the equation of motion of the weight and give its damping factor, quasiperiod and quasifrequency.
Answer:
attached below
Explanation:
The initial conditions :
x(0) = - 9 inches = -3/4 ft
x'(0) = - 2 ft/sec
spring stretched 3 inches = 1/4 ft
mass = w / g = 4 Ib / 32 ft/sec^2 = 1/8 slug
the spring constant ( k ) = w / l = 4 / ( 1/4 ) = 16 Ib/ft
applying the second law of motion
m d^2x/dt^2 + b dx/dt + kx
= 1/8 d^2x/dt^2 + 2 dx/dt + 16 x
= d^2x/dt^2 + 16 dx/dt + 128 x ------- ( 1 )
we will resolve the above equation to obtain the required equation of motion x( t )
Attached below is the remaining part of the solution
which type of image is formed by convex lens on a screen?
Answer:
The type of image formed on a screen by a convex lens is real, enlarged and inverted.
Explanation:
A lens can be defined as a transparent optical instrument that refracts rays of light to produce a real image.
Basically, there are two (2) main types of lens and these includes;
I. Diverging (concave) lens.
II. Converging (convex) lens.
A converging lens refers to a type of lens that typically causes parallel rays of light with respect to its principal axis to come to a focus (converge) and form a real image.
Basically, the type of image formed on a screen by a converging (convex) lens is real, enlarged and inverted because it is usually thick across the middle (causing rays of light to converge) but thin at the lower and upper edges.
3. Thekinetic energy of an object of
mass, m moving with a velocity
of 5 ms-t is 25 J. What will be its
Toinetic energy when its velocity
is doubled? What will be its
Icinetic energy ruhen its velocity
is increased three times?
Answer:
1. 100 J
2. 225 J
Explanation:
We'll begin by calculating the mass of the object. This can be obtained as follow:
Velocity (v) = 5 ms¯¹
Kinetic energy (KE) = 25 J
Mass (m) =?
KE = ½mv²
25 = ½ × m × 5²
25 = ½ × m × 25
25 = 25m / 2
Cross multiply
25m = 25 × 2
25m = 50
Divide both side by 25
m = 50 / 25
m = 2 Kg
1. Determination of the kinetic energy when the velocity is doubled.
Mass (m) = 2 Kg
Velocity (v) = double the initial velocity
= 2 × 5 ms¯¹
= 10 ms¯¹
Kinetic energy (KE) =?
KE = ½mv²
KE = ½ × 2 × 10²
KE = ½ × 2 × 100
KE = 100 J
2. Determination of the kinetic energy when the velocity increased three times.
Mass (m) = 2 Kg
Velocity (v) = three times the initial velocity
= 3 × 5 ms¯¹
= 15 ms¯¹
Kinetic energy (KE) =?
KE = ½mv²
KE = ½ × 2 × 15²
KE = ½ × 2 × 225
KE = 225 J
Light strikes a smooth wooden tabletop.
What happens to the light after it is reflected?
The light rays bounce off the table and all move in the same direction.
The light rays bounce off the table and move in different directions.
The light rays pass through the table and all move in the same direction.
The light rays pass through the table and move in different directions.
Answer:
For smooth surface:The light rays bounce off the table and all move in the same direction.
Show that the path followed by a projected horizontally frop top of the tower with uniform speed is a parabola .
Answer:
Explained below.
Explanation:
Let the initial velocity from the top of the tower of height(h) be u'
Now, since it is projected horizontally, the horizontal distance covered will be due to having a uniform horizontal velocity (u) while it will possess a vertical distance in the downward direction due to constant acceleration due to gravity (g).
If the time it takes the ball to reach the ground is "t", then we can say the horizontal distance travelled by the ball is denoted as; x(t) = x, while the vertical distance is denoted by; y(t) = y
Now, since it's a projectile the intial velocity (u) will have vertical and horizontal components which are;
u_y and u_x respectively.
Applying kinematic equations, we have;
x = u_x•t + ½at²
Acceleration is zero in the horizontal x direction. Thus;
x = u_x•t
For the vertical y-direction;
y = u_y•t + ½at²
Here since direction is in that of gravity, then a = g.
Also, since the initial velocity has no downward component, then u_y = 0 m/s
Thus;
y = ½gt²
From x = u_x•t, we have;
t = x/u_x
Thus;
y = ½g(x/u_x)²
y = ½gx²/(u_x)²
Let g/(u_x)² be treated as a constant with the letter k.
Thus;
y = kx²
This is the form of a parabolic equation.
Thus, it has been proved that the projectile follows the path of a parabola.
an object that has lost its electrons become?
A cylindrical container closed of both end has a radius of 7cm and height of 6cm A.)find the total surface area of the container B.) find the volume of the container
Amy throws a softball through the air. What are the different forces acting on the ball while it’s in the air?
The softball experiences
force as a result of Amy’s throw. As the ball moves, it experiences
from the air it passes through. It also experiences a downward pull because of
.
Answer:
1.the friction of air, gravity2.gravity
Answer:
The softball experiences an applied force as a result of Amy’s throw. As the ball moves, it experiences drag from the air it passes through. It also experiences a downward pull because of gravity.
Explanation:
Plato
A cycle travels along a circular track of diameter 42 m. Calculate the distance travelled and the displacement of the cycle in (a) Half round (b)One round.
please explain it to me clearly,its so confusing
i will give brainlist to the one who explains it clearly
Answer:
(a) i) The distance travelled by the cycle in half round is approximately 65.97 m
ii) The displacement is 42 m
(b) (i) The distance travelled in one round is approximately 131.95 m
(ii) The displacement of the cycle in one round is 0
Explanation:
The diameter of the track through which the cycle travels, D = 42 m
(a) i) Half round is the motion of half the length of the circular path
The distance travelled by the cycle in half round = The length of half the circular track = (1/2) × π × D
∴ The distance travelled by the cycle in half round = (1/2) × π × 42 m = 21·π m ≈ 65.97 m
ii) The displacement half round = The change in the location of the cycle = The difference between the start and stop locations of the cycle on a straight line after half round
The angle at the center of the circular path the cycle turns in half round = 180°
Therefore, the path between the start and stop location of the cycle in half round = The diameter of the circular track
The displacement of the cycle in half round = The diameter of the circular track = 42 m
(b) (i) The distance travelled in one round = The perimeter of the circular track = π·D
∴ The distance travelled in one round = π × 42 m ≈ 131.95 m
(ii) The displacement of the cycle in one round = The change in the location of the cycle
The start and stop location of the cycle after moving one round is the same, therefore, there is no change in the location of the cycle.
Therefore we have;
The displacement of the cycle in one round = 0 (no change in location of the cycle)
The decrease in the intensity of light over distance, such as with increasing depth in water, is known as ______.
Answer:
Attenuation
Step By step Explanation:
The decrease in the intensity of light over distance, such as with increasing depth in water, is known as ______.
It is called attenuation.
The decraese in the amplitude of the signals is called attenuation.
Describe the resistance through a
diode
Explanation:
A diode is an electrical element which offers the flow of current freely in one direction with very less resistance.
The given figure depicts a diode in forward bias, where the p-side and the n-side of the diode are connected to positive and negative terminals respectively. In such a case the current flows from the p-side to n-side of the p-n junction very easily and the value of the current increases rapidly after a certain voltage, this voltage is called threshold voltage.
We can deduce from the graph that the resistance of the diode reduces with increase in voltage. As resistance is given by the formula:
[tex]R=\frac{V}{i}[/tex]
what do you mean by time?
que es la energia electrica
Answer:
:) :) :) :) :) :) :) :) :)
Explanation:
:) :) :) .......
Two blocks, one of mass 5 kg and the other of mass 2 kg, are attached to opposite ends of a light string and hung vertically from a massless, frictionless pulley. Initially the heavier block is held in place a distance 2.5 m above the floor, the lighter block is just touching the floor, and the cord is taut. Then the heavier block is released and comes crashing to the floor while the cord slackens and the lighter block continues to rise. What is the maximum height reached by the lighter block
Answer:
[tex]H_{max}=3.4m[/tex]
Explanation:
From the question we are told that:
Mass 1 [tex]m_1=5kg[/tex]
Mass [tex]m_2=2kg[/tex]
Distance above floor [tex]d=2.5m[/tex]
Generally the equation for Conservation of energy is mathematically given by
[tex]0.5m_1v^2+0.5m_2v^2=2mg[/tex]
[tex]0.5m_1v^2+0.5m_2v^2=2g(m_1-m_2)[/tex]
[tex]v^2(0.5*m_1+0.5*m_2)=2*g(m_1-m_2)[/tex]
[tex]v^2(0.5*5+0.5*2) = 2 * 9.8 * (5 - 2)[/tex]
[tex]v^2=\frac{58.8}{3.5}[/tex]
[tex]v=4.1m/s[/tex]
Generally the equation for The maximum height of lighter block is mathematically given by
[tex]H_{max}=d+\frac{v^2}{2g}[/tex]
[tex]H_{max}=2.5+\frac{16.2}{2*9.81}[/tex]
[tex]H_{max}=3.4m[/tex]
Which two factors affect the size of the gravitational field?
Answer:
Explanation:
mass and distance
three condensers are connected in series across a 150 volt supply. The voltages across them are 40,50 and 60 volts respectively, and the charge on each condenser is 6×10^-8(a) calculate the capacitance of each condenser (b)calculate the effective capacitance of the combination
Explanation:
Given that,
The voltages across them are 40,50 and 60 volts respectively, and the charge on each condenser is 6×10⁻⁸ C.
(a) Capacitance of capacitor 1,
[tex]C_1=\dfrac{Q}{V_1}\\\\C_1=\dfrac{6\times 10^{-8}}{40}\\\\C_1=1.5\times 10^{-9}\ F\\\\C_1=1.5\ nF[/tex]
Capacitance of capacitor 2,
[tex]C_2=\dfrac{Q}{V_2}\\\\C_2=\dfrac{6\times 10^{-8}}{50}\\\\C_2=1.2\times 10^{-9}\ F\\\\C_2=1.2\ nF[/tex]
Capacitance of capacitor 3,
[tex]C_3=\dfrac{Q}{V_3}\\\\C_3=\dfrac{6\times 10^{-8}}{60}\\\\C_3=1\times 10^{-9}\ F\\\\C_3=1\ nF[/tex]
(b) The equivalent capacitance in series combination is :
[tex]\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}\\\\\dfrac{1}{C}=\dfrac{1}{1.5}+\dfrac{1}{1.2}+\dfrac{1}{1}\\\\C=0.4\ nF[/tex]
Hence, this is the required solution.
A 67.3-kg climber is scaling the vertical wall of a mountain. His safety rope is made of a material that, when stretched, behaves like a spring with a spring constant of 1.23 x 103 N/m. He accidentally slips and falls freely for 0.921 m before the rope runs out of slack. How much is the rope stretched when it breaks his fall and momentarily brings him to rest
Answer:
[tex]d=0.59m[/tex]
Explanation:
From the question we are told that:
Mass [tex]m=67.3 kg[/tex]
Spring constant [tex]\mu=1.23 * 10^3 N/m[/tex]
Fall Height [tex]h=0.921m[/tex]
Generally the Energy theorem equation for momentum is mathematically given by
Change in KE=Work done by gravity + work done by spring
[tex]0=mg*(h + d) - \frac{\mu d^2}{2}[/tex]
[tex]0=(67.3 * 9.81 (0.921 + d)) -\frac{(1.23 * 10^3 * d^2}{ 2}[/tex]
[tex]0=608.1-660.213d-615d^2[/tex]
Solving Quadratic equation
[tex]d=0.59m[/tex]
orange light has a wavelength of 600nm. calculate the frequency if the speed of light in vacuum
the correct answer is ---- 122
what is measurement?
Jake launches a water balloon at an angle of 35° above the horizontal. If he sends it flying with an initial velocity of 3 m/s, how far away does Fred (who is the same height as Jake) need to be for it to hit him (assuming Jake has a good aim)?
Answer:
R = 0.86 m
Explanation:
The formula for the range of the projectile motion can be used here:
[tex]R = \frac{v^2 Sin2\theta}{g}[/tex]
where,
R = Range of projectile = distance between Jake and Fred = ?
v = launch speed = 3 m/s
θ = Launch Angle = 35°
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]R = \frac{(3\ m/s)^2Sin[(2)(35^o)]}{9.81\ m/s^2}\\\\[/tex]
R = 0.86 m
can anyone help me with this?
the question : find the value of the resistors
Answer:
Value of the resistors R = 2 ohm
Explanation:
Given:
Resistor R1 = 4 ohm
Resistor R2 = 4 ohm
Find:
Value of the resistors R
Computation:
We know that Resistor R1 and Resistor R2 connected in parallel series.
So,
Using common resistance in parallel series
⇒ 1/R = 1/R1 + 1/R2
⇒ 1/R = 1/4 + 1/4
⇒ 1/R = (1 + 1) / 4
⇒ 1/R = 2/4
⇒ R = 4/2
⇒ R = 2
Value of the resistors R = 2 ohm
What are the fundamental units involved in a unit of the given derived quantities
Density
Acceleration
Force
Pressure
Work
Answer:
Density → Mass and Length.
Acceleration → Length and Time.
Force → Mass, Length and Time.
Pressure → Mass, Length and Time.
Work → Mass, Length and Time.
a motorcyclist drives from A to B with a uniform speed of 30 km/h and returns back with a speed of 20km/h-¹ find the average speed ?
PLEASE DO IT AS FAST YOU CAN AND NO SCAM ANSWERS OR ELSE I WILL REPORT
Answer:
Average speed = 24 km/h
Explanation:
Let the distance be x.Given the following data;
Uniform speed A = 30 km/h
Uniform speed B = 20 km/h
To find the average speed;
Mathematically, the average speed of an object is given by the formula;
[tex] Average \; speed = \frac {total \; distance}{total \; time} [/tex] ..... equation 1
Total time = TA + TB
[tex] T_{A} = \frac {x}{30} [/tex]
[tex] T_{B} = \frac {x}{20} [/tex]
[tex] Total \; time = \frac {x}{30} + \frac {x}{20} [/tex]
[tex] Total \; time = \frac {5x}{60} [/tex]
Total distance = x + x
Total distance = 2x
Substituting the values into equation 1;
[tex] Average \; speed = \frac {2x}{\frac {5x}{60}} [/tex]
[tex] Average \; speed = \frac {2x*60}{5x} [/tex]
[tex] Average \; speed = \frac {120}{5} [/tex]
Average speed = 24 km/h
Mains electricity is an ac supply. Explain the difference between direct and alternating potential difference.
Direct current (DC) is the flow of electric charge in only one direction. It is the steady state of a constant-voltage circuit. Most well-known applications, however, use a time-varying voltage source. Alternating current (AC) is the flow of electric charge that periodically reverses direction.
#LETS STUDYA woman wearing high heels will find difficult to walk on the sandy beach than if she wears flat sole sandals. Why?
Explanation:
the high heels has a more pressure than flat soles bcoz small area has more pressure than large area.
Sonny took 16 seconds to finish a 100-m race. What was
Sonny's average speed in the race
Speed = Distance/Time
=> Speed = 100m/16s
=> Speed = 6.25m/s
=> Speed = 6.25 ms^-1