Does a reaction occur when aqueous solutions of copper(II) nitrate and calcium chloride are combined

Answers

Answer 1

Answer:

Does a reaction occur when aqueous solutions of copper(II) nitrate and calcium chloride are combined?

Explanation:

The given reaction is an example of a chemical double displacement reaction.

The mutual interchange of the ions takes place.

The balanced chemical equation of the reaction is:

[tex]Cu(NO_3)_2(aq)+CaCl_2(aq) -> Ca(NO_3)_2(aq)+CuCl_2(aq)[/tex]

All the products formed are also highly soluble.

So, all the ions are spectator ions.

Hence, all will cancel with each other and ions remain in the net ionic equation and hence, the reaction does not take place.


Related Questions

43 mg = [?]g
A. 0.043 g
B. 4.3 g
C. 4300 g
D. 43,000 g​

Answers

Answer:

Option A (0.043 g) is the correct answer.

Explanation:

Given:

= 43 mg

As we know,

[tex]1 \ mg = \frac{1}{1000} \ g[/tex]

then,

⇒ [tex]43 \ mg = \frac{43}{1000} \ g[/tex]

              [tex]= 0.043 \ g[/tex]

Thus, the above is the correct alternative.

Which of the following molecules can be used in catabolic reactions to generate the carbon backbones required for gluconeogenesis?

a. glutathione, a short peptide containing glutamate, serine and histidine
b. butyrate, a short chain fatty acid
c. fructose, a monosaccharide
d. starch, a polysaccharide

Answers

Answer:

The correct option is A

Explanation:

Some amino acids, called glucogenic amino acids, when catabolized convert there carbon backbones to tricarboxylic acid (TCA) cycle intermediates. These intermediates can be subsequently metabolized into carbon dioxide and water with the release of ATP or the formation of glucose (known as gluconeogenesis.

All amino acids (with the exception of leucine and lysine) are glucogenic and can thus generate the carbon backbones required for gluconeogenesis. Thus, the correct option is a.

Calculate the displacement (the total volume of the cylinder through which the piston move) of a 5.70L automobile engine in cubic inches, (1inch=2.54cm)

Answers

Answer:

348 inches³

Explanation:

From our previous knowledge of  units conversion:

We know that 1000 cm³ makes 1 Liter.

Thus, for  a 5.70 L automobile engine in cubic meters will be:

= 5.70 × 1000 cm³

= 5700 cm³

Now, the displacement of the automobile in cubic inches provided that 1 inch = 2.534 cm is:

⇒ 5700× (1/ (2.54)³) in³

= 5700×0.0610 in³

= 347.7 in³

≅ 348 inches³

What effect would a decrease in volume have on pressure, assuming that temperature (T) and moles of gas (n) are kept constant

Answers

Answer:

Pressure increases

Explanation:

Boyle's law states that; '' the volume of a given mass of ideal gas is inversely proportional to its pressure at constant temperature.

Hence, when the volume of a given mass of ideal gas is decreased, the molecules of the gas come closer together so they collide with each other and the walls of the container more frequently.

This implies that the pressure of the gas increases as volume decreases in accordance with Boyle's law.

Which of the following two periods contain the same number of element?
A. 2 & 3
B.3 & 4
c. 4 & 6
D. 2 & 4​

Answers

Answer:

4 and 6

Explanation:

Period 4 has 18 elements and so does period 6.

The number 0.0007270 is larger than the number 5.7 × 10–3.

Answers

Answer:

Yes

Explanation:

=5.7×10-3

=5.7×7=39.9

=0.0007270 greater than 5.7× 10-3

OR

=5.7×10

=57-3

=54

So it is greater number

Which of the following is true for balancing equations?
A. There must be an equal number of atoms of each element on both sides of the equation.

B. The number of products should be equal to the number of reactants

C. The properties of products should be the same as the properties of the reactants

D. There must be an equal number of compounds on both sides of the equation

Answers

Answer:

A.

Explanation:

An equation with the equal amount and proportion of atoms of each element on both sides of the reaction is commonly referred to as a balanced chemical equation.

The law of conservation of matter asserts that no observable and empirical change in the amount of matter occurs within a conventional chemical process. As a result, each element in the product would have the same equal amount or numbers of atoms as the reactants.

The following physical constants are for water, H2O.
The specific heat capacity of the solid = 2.09 J/g oC
The specific heat capacity of the liquid = 4.18 J/g oC
The specific heat capacity of the vapor = 2.09 J/g oC
∆Hfus = 6.02 kJ/mol; ∆Hvap = 40.7 kJ/mol Freezing point = 0.0oC; Boiling point = 100.0oC
How much heat(in kJ) is required to warm 10.0 grams of ice at -5.0oC to a temperature of 70.0oC?

Answers

Answer:

[tex]Q\approx6.4~kJ[/tex]

Explanation:

Quantity of heat required by 10 gram of ice initially warm it from -5°C to 0°C:

[tex]Q_1=m.C_s.\Delta T[/tex]

here;

mass, m = 10 g

specific heat capacity of ice, [tex]C_s=2.09~J.g^{-1}.^{\circ}C^{-1}[/tex]

change in temperature, [tex]\Delta T=(5-0)=5^{o}C[/tex]

[tex]Q_1=10\times2.09\times 5[/tex]

[tex]Q_1=104.5~J[/tex]

Amount of heat required to melt the ice at 0°C:

[tex]Q_2=m.\Delta H_{fus}[/tex]

where, [tex]\Delta H_{fus}=6020~J/mol[/tex]

we know that no. of moles is = (wt. in gram) [tex]\div[/tex] (molecular mass)

[tex]Q_2=\frac{10}{18} \times 6020[/tex]

[tex]Q_2=3344.44~J[/tex]

Now, the heat required to bring the water to 70°C from 0°C:

[tex]Q_3=m.C_L.\Delta T[/tex]

specific heat of water, [tex]C_L=4.18~J/g/^oC[/tex]

change in temperature, [tex]\Delta T=(70-0)=70^oC[/tex]

[tex]Q_3=10\times 4.18\times 70[/tex]

[tex]Q_3=2926~J[/tex]

Therefore the total heat required to warm 10.0 grams of ice at -5.0°C to a temperature of 70.0°C:

[tex]Q=Q_1+Q_2+Q_3[/tex]

[tex]Q=104.5+3344.44+2926[/tex]

[tex]Q=6374.94~J[/tex]

[tex]Q\approx6.4~kJ[/tex]

Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients.
P4(s) + NaOH(aq) + H2O(l) -> Ph3(g) + Na2HPO3(aq)

Answers

Answer:

I used a,b c, d in the equation as substituted coefficients to find the unknown for each element of P, Na, O, H, and I got

P4(s) + 4NaOH(aq) + 2H20(l)---->2Ph3 +2Na2HPO3(aq).

which I think should be the answer.

The metal tantalum becomes superconducting at temperatures below 4.483 K. Calculate the temperature at which tantalum becomes superconducting in degrees Celsius.

Answers

Answer:

The correct answer is "-268.667°C".

Explanation:

Given:

Temperature,

= 4.483 K (below)

Now,

The formula of temperature conversion will be:

⇒ [tex]T(^{\circ} C)=T(K)-273.15[/tex]

By putting the values, we get

⇒            [tex]=4.483-273.15[/tex]

⇒            [tex]=-268.667^{\circ} C[/tex]

Thus the above is the correct answer.

One of the purposes of this lab is to determine the order of the reaction with respect to the Allura Red dye by creating first and second-order graphs for all four trials. The correct order of the reaction is the one where the slopes of the graphs for the four trials are roughly the same. Why is this important when choosing the order of the reaction

Answers

Answer: Hello the options related to your question are attached below

The slope is related to the rate constant so all four trials should have the same slope since the reactions are all the same ( Option C )

Explanation:

It is important when choosing the order of the reaction because the concentration of the bleaches used in the four trials are in excess hence their slopes have to be roughly the same and also because the reactions are similar and they where done at the same temperature, hence the slope of the first and second-order graphs will be the same.

A piece of solid tin is submerged in silver nitrate solution a reaction occurs producing tin(IV) nitrate solution and solid silver
Write a word equation write a skeleton equation write a balanced chemical equation

Answers

Answer:

Tin + silver trioxonitrate V -------->Tin IV nitrate + silver

Explanation:

The term word equation refers to an equation in which the reactants and products are written in words rather than chemical symbols.

Note than tin is above silver in the electrochemical series hence silver will be displaced by tin as follows;

Tin + silver trioxonitrate V -------->Tin IV nitrate + silver

What kind of light would an electron experiencing n=4 to n=2 drop emit?

Answers

Hi there!

[tex]\large\boxed{\text{Visible Light.}}[/tex]

According to the diagram and the arrows, a drop from level 4 (n = 4) to level 2 (n = 2) produces orange visible light.

[tex]\red\large{{}}[/tex]

What is different between margerine and butter in term of organic chemistry

Answers

Answer:

The most important difference between the two is that butter is derived from dairy and is rich in saturated fats, whereas margarine is made from plant oils. ... If the margarine contains partially hydrogenated oils, it will contain trans fat, even if the label claims that it has 0 g.

Explanation:

(⌒_⌒;)

the ability of organism to sense changes in its body is an example of

Answers

Answer:

the ability of organism to sense changes in its body is an example of responsiveness.

Hope it is helpful to you

According to the Arrhenius equation, changing which factors will affect the
rate constant?
A. Temperature and the ideal gas constant
B. The activation energy and the constant A
C. The constant A and the temperature
D. Temperature and activation energy

Answers

Answer:

e−(Ea/RT): the fraction of the molecules present in a gas which have energies equal to or in excess of activation energy at a particular temperature

Answer:

D. Temperature and activation energy is the correct answer

Explanation:

^_^

explain why the melting point of a solid is equal to the freezing point of it's liquid.​

Answers

Explanation:

Because melting point and freezing point describe the same transition of matter, in this case from liquid to solid (freezing) or equivalently, from solid to liquid (melting). It is stuck on 0 ∘C during the entire melting or freezing process. None except melting is when you heat up and freezing when you cool down.

hope it helps.stay safe healthy and happy.

A student needed to make a 3 g/L NaCl solution. The student weighed 3 g of NaCl in a beaker and measured 1 L of water in a 1L volumetric flask that was labeled TC. The student then added the water to the beaker containing the NaCl. What errors did this student make? Describe how this can be performed properly.

Answers

Answer:

The answer is in the explanation.

Explanation:

A solution is defined as the homogeneous mixture of a solute (In this case, NaCl) and the solvent (water).

To prepare 1L of the solution, the student can weigh the 3g of NaCl in the volumetric flask but need to add slowly water to dissolve the NaCl (That is very soluble in water). When all NaCl is dissolved the student must transfer the solution to the 1L volumetric flask. Then, you must add more water to the beaker until "Clean" all the solute of the beaker to transfer it completely to the volumetric flask.

7.23 One equivalent of sodium methanethiolate is added to an electrophile that has two leaving groups. Which product will be major

Answers

The question is incomplete, the complete question is shown in the image attached to this answer

Answer:

A

Explanation:

We can see from the conditions of the reaction that the incoming nucleophile is -SCH3 and there are two possible leaving groups in the substrate.

First of all, we have to look at the conditions of the reaction. We can see that the reaction is taking place in DMF, a polar aprotoc solvent. This condition favours the SN2 synchronous mechanism over the SN1 ionic mechanism.

Hence, the nucleophile at the 1-position is preferentially substituted owing to the conditions of the reaction.

Thus, option A is the major product of the reaction.

What is the difference between conjugate acid-base pair?

a. a H atom. c. a mole water
b. a H+ ion d. a OH– ion​

Answers

Answer:

b. a H+ ion

Explanation:

The concept of conjugate acid-base pair is related to Bronsted-Lowry acid-base theory and according to this theory, acid is a proton acceptor.

In short,

conjugate base is formed when an acid donates a proton.

conjugate acid is formed when a base accepts a proton.

Please help me ASAP I’ll mark Brainly

Answers

Answer:

1. Vacuole

2. chloroplast

3. Nucleus

4. Plasma membrane - cell membrane

5. Vacuole (same as #1 ?) could be vesicle

Explanation:

Ammonia and oxygen react to form nitrogen monoxide and water. Construct your own balanced equation to determine the amount of NO and H2O that would form when 2.78 mol NH3 and 5.19 mol O2 react.

Answers

Answer:

The amount of NO formed s 2.78 moles or 83.4 grams

The amount of H2O formed is 4.17 moles or 75.1 grams

Explanation:

Step 1: Data given

Ammonia = NH3

Oxygen = O2

nitrogen monoxide = NO

water = H2O

Number of moles NH3 = 2.78 moles

Number of O2 = 5.19 moles

Step 2: The balanced reaction

4NH3 + 5O2 → 4NO + 6H2O

Step 3: Calculate moles of products

For 4 moles NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

NH3 is the limiting reactant

All the NH3 will react. There will be 0 moles of NH3 left

For 4 moles NH3 we need 5 moles O2

For 2.78 moles NH3 we need 5/4 * 2.78 = 3.475 moles

There will be left 5.19 - 3.475 = 1.715 moles O2

For 4 moles NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

For 2.78 moles NH3 we'll have 2.78 moles NO and 6/4 * 2.78 = 4.17 moles H2O

Step 4: Calculate mass of NO and H2O

Mass = moles * molar mass

Mass NO = 2.78 moles * 30.01 g/mol

Mass NO = 83.43 grams

Mass H2O = 4.17 moles * 18.02 g/mol

Mass H2O = 75.14 grams

The amount of NO formed s 2.78 moles or 83.4 grams

The amount of H2O formed is 4.17 moles or 75.1 grams

A major component of gasoline is octane when octane is burned in air it chemically reacts with oxygen to produce carbon dioxide and water what mass of carbon dioxide is produced by the reaction of oxygen

Answers

gasoline is the chemical that is coming out of the air


4. Draw conclusions: How is the periodic table organized?

Answers

Answer:

.

Elements are arranged from left to right and top to bottom in the order of their increasing atomic numbers. Thus,

Elements in the same group will have the same valence electron configuration and hence, similar chemical properties.

Whereas, elements in the same period will have an increasing order of valence electrons. Therefore, as the energy level of the atom increases, the number of energy sub-levels per energy level increases.

The first 94 elements of the periodic table are naturally occurring, while the rest from 95 to 118 have only been synthesized in laboratories or nuclear reactors.

The modern periodic table, the one we use now, is a new and improved version of certain models put forth by scientists in the 19th and 20th century. Dimitri Mendeleev put forward his periodic table based on the findings of some scientists before him like John Newlands and Antoine-Laurent de Lavoisier. However, Mendeleev is given sole credit for his development of the periodic table.

How many protons are in Oxygen-18 and how many neutrons are in Copper-65? Please include steps for solving both!

Answers

Answer: There are 8 protons in oxygen-18 and 36 neutrons in copper-65.

Explanation:

An atom contains three sub-atomic particles, that is, protons, neutrons and electrons.

The atomic number is the total number of protons present in an atom. For oxygen-18, the atomic mass is 18.

Atomic mass is the sum of total number of protons and electrons present in an atom. As the atomic number of an oxygen atom is 8 so the number of protons present in oxygen-18 is 8.

The atomic mass of copper is 65 and for a copper atom, the atomic number is 29. Hence, the number of neutrons for copper-65 is as follows.

Atomic mass = no. of protons + no. of neutrons

65 = 29 + no. of neutrons

no. of neutrons = 65 - 29 = 36

Thus, we can conclude that there are 8 protons in oxygen-18 and 36 neutrons in copper-65.

g Arrange the following compounds in order of acidity (highest to lowest): H2O, H3O , HCl A. CH3COOH > HCl > H2O B. H2O > CH3COOH > HCl C. HCl > H2O > CH3COOH D. HCl > CH3COOH > H2O

Answers

Answer:

Arrange the following compounds in order of acidity (highest to lowest): H2O, CH3COOH , HCl

A. CH3COOH > HCl > H2O

B. H2O > CH3COOH > HCl

C. HCl > H2O > CH3COOH

D. HCl > CH3COOH > H2O

Explanation:

The given substances are acetic acid, hydrochloric acid, and water.

Since HCl is a strong acid and it undergoes complete ionization.

CH3COOH acetic acid is a weak acid and it undergoes partial dissociation in water.

Pure water is a neutral substance.

Hence, the order of acidity is shown below:

HCl > CH3COOH > H2O.

Among the given options, option D is the correct answer.

a laser emits light with a frequency of 4.69 x 10 to the 14th power s - 1 calculate the wavelength of this light.

Answers

Answer:

6.40x10^-7

Explanation:

answer with work is attached.

How many atoms are in each elemental sample?
16.8 g Sr
26.5 g Fe
8.94 g Bi
40.0 g P

Answers

Explanation:

The number of atoms in 1mol of every element can be represented by Avogadro's number, which is [tex]6.022*10^{23}[/tex].

Knowing this, now we can find the atoms in each of these molecules!

[tex]16.8gSr*\frac{1molSr}{87.62gSr} *\frac{6.022*10^{23}atomsSr}{1molSr} =[/tex]

1.15*10^23 atoms of Sr

[tex]26.5gFe*\frac{1molFe}{55.85gFe} *\frac{6.022*10^{23}atomsFe}{1molFe} =[/tex]

2.86*10^23 atoms of Fe

[tex]8.94gBi*\frac{1molBi}{208.98gBi} *\frac{6.022*10^{23}atomsBi}{1molBi} =[/tex]

2.58*10^22 atoms of Bi

[tex]40.0gP*\frac{1molP}{30.97gP} *\frac{6.022*10^{23}atomsP}{1molP}=[/tex]

7.78*10^23 atoms of P

A student performs an experiment similar to Experiment 1 using hydrochloric acid (HCl) and potassium hydroxide (KOH). The mass of the hydrochloric acid solution is 250.000 g. After combining the HCl and KOH, the final combined mass is 400.000 g. Given what you have learned about the conservation of mass in this experiment, what must have been the mass of the KOH solution

Answers

Answer:

150.000 g

Explanation:

The law of conservation of mass states that the mass of reactants and products of a reaction must be equal to one another.

In other words, for this case:

Mass of KOH + Mass of HCl = Mass of Products

We are given all required data to calculate the mass of the KOH solution:

Mass of KOH + 250.000 g = 400.000 gMass of KOH = 150.000 g

Consider the following equilibrium:
2H2(g)+S2(g)⇌2H2S(g)Kc=1.08×107 at 700 ∘C.

What is Kp?

Answers

Answer:

Consider the following equilibrium:

2H2(g)+S2(g)⇌2H2S(g)Kc=1.08×107 at 700 ∘C.

What is Kp?

Explanation:

Given,

[tex]Kc=1.08 * 10^7[/tex]

The relation between Kp and Kc is:

[tex]Kp=Kc * (RT)^d^e^l^t^a^(^n^)[/tex]

Where delta n represents the change in the number of moles.

For the given equation,

The Delta n = Number of moles of products - number of moles of reactants

(2-(2+1))

=-1.

Hence,

Kp=Kc/RT.

Thus,

[tex]Kp=1.08 * 10^7 / 8.314 J.K6-1.mol^-^1 x 973 K\\Kp=1335.06[/tex]

The answer is Kp=1335.06

The value of [tex]K_p[/tex] is [tex]1.35\times 10^5[/tex].

Explanation:

The relation between [tex]K_p \& K_c[/tex] is given by:

[tex]K_p=K_c(RT)^{\Delta n_g}[/tex]

Where:

[tex]K_c[/tex] = The equilibrium constant of reaction in terms of concentration

[tex]K_p[/tex] = The equilibrium constant of reaction in terms of partial pressure

R= The universal gas constant

T = The temperature of the equilibrium

[tex]n_g[/tex]= Change in gaseus moles

Given:

An equilibrium reaction, 700°C:

[tex]2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g),K_c=1.08\times 10^7[/tex]

To find:

The equilibrium constant in terms of partial pressure, [tex]K_p[/tex].

Solution:

The equilibrium constant of reaction in terms of concentration= [tex]K_c[/tex]

[tex]K_c=1.08\times 10^7[/tex]

The equilibrium constant of reaction in terms of partial pressure =[tex]K_p=?[/tex]

The gaseous moles of reactant side = [tex]n_r= 3[/tex]

The gaseous moles of product side = [tex]n_p= 2[/tex]

The temperature at which equilibrium is given = T

[tex]T = 700^oC+273.15 K=973.15K[/tex]

The change in gaseous mole  = [tex]n_g=n_p-n_r=2-3 = -1[/tex]

[tex]K_p=1.08\times 10^7\times (0.0821 atm L/mol K\times 973.15 K)^{-1}\\K_p=1.35\times 10^5[/tex]

The value of [tex]K_p[/tex] is [tex]1.35\times 10^5[/tex].

Learn more equilibrium constants here:

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