The following factors change as one moves to higher magnifications with a microscope:
What is magnification?
Magnification is a measure of how much an image is enlarged or increased in size compared to the original object. It is commonly used in optics, such as microscopes and telescopes, to describe the level of enlargement achieved by the instrument. The magnification is usually expressed as a ratio or a multiple of the original size.
a. Resolution: Resolution refers to the ability of a microscope to distinguish two separate points as separate entities. As one moves to higher magnifications, the resolution of the microscope increases, meaning that smaller and finer details can be seen.
b. Amount of light needed: As magnification increases, the amount of light needed to illuminate the specimen also increases. This is because the increased magnification reduces the amount of light that reaches the specimen and the observer.
c. Working distance: Working distance refers to the space between the lens and the specimen. As one moves to higher magnifications, the working distance decreases, meaning that the lens must be positioned closer to the specimen.
d. Depth of field: Depth of field refers to the range of distances from the lens that are in focus at any given time. As one moves to higher magnifications, the depth of field decreases, meaning that only a very small portion of the specimen will be in focus at any given time.
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calculate the de Broglie wavelength associated with an electron accelerated through a potential difference of 1 kV.
1.2 x 10⁻¹¹ m is the de Broglie wavelength associated with an electron accelerated through a potential difference of 1 kV.
Define De Broglie wavelength .
De Broglie wavelength is the wavelength that is connected to an item in relation to its momentum and mass. Typically, a particle's force is inversely proportional to its de Broglie wavelength.
The relationship between the momentum of a moving particle and its wavelength is given by the de Broglie equation, h=mv. The likelihood of locating an object at a specific location in the configuration space is calculated using de Broglie waves. Making use of the de Broglie waves in the creation of electron microscopes is another significant use.
E = qV
q is 1.6 x 10⁻¹⁹ C
V is the potential difference.
v² = 2eV/m
v is 5.9 × 10⁹ m/s
λ = h/mv
h is the Planck Constant which is equal to 6.63x 10⁻³⁴ Js
Substituting values above we get λ = 1.2 x 10⁻¹¹ m.
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Open the phase diagram for CO2 given in the introduction again. Use the phase diagram for CO2 in the interactive activity and determine which of the following statements are correct. CO2 is a gas under normal conditions of temperature and pressure.
All three phases of CO2 exist simultaneously at the triple point. When the pressure is 4 atm and the temperature is more than −56.7∘C, CO2 exists as a solid. When the pressure is 1 atm, there is no temperature at which the liquid phase of CO2 exists.
Movement across boundary line BO corresponds to a phase change.
CO2 forms a supercritical fluid at temperatures less than 31∘C.
The correct statements about the phase diagram for CO₂ from the given options are as follows:
All three phases of CO₂ exist simultaneously at the triple point.When the pressure is 1 atm, there is no temperature at which the liquid phase of CO₂ exists.CO₂ is a gas under normal conditions of temperature and pressure.Movement across boundary line BO corresponds to a phase change.The correct options are A, B, C, and D.
What is CO2's triple point?The parameters of temperature and pressure at which CO₂ is simultaneously present in all three physical states of matter are referred to as the triple point of CO₂.
At 5.2 atm, the triple point of CO₂ is -57 °C.At normal room temperature and atmospheric pressure, CO₂ is a gas.It is a significant greenhouse gas that is denser than air.Learn more about the triple point at: brainly.com/question/16945664
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determine the direction of the resultant force, measured counterclockwise from the positive x axis. express your answer using three significant figures.
Resultant force direction = 11.08 degrees counter-clockwise from the positive x-axis.
In order to address this issue, we must first divide these forces into their corresponding x and y components, which we must then combine to determine the final force.
Given the magnitude of force (F1) = 32kN
The angle of direction (θ1) = 30°
F1x = -32k x cos(30°) = -27.7kN
F1y = -32 x sin(30°) = -16kN
Given a triangle, let cos(θ) = 5/13 = 0.99 then θ = 67.3°
The magnitude of force F2 = 26kN
The angle of direction (θ2) = 0.99°
F2x = -26 x cos(67.3°) = 10.03kN
F2y = 26 x sin(67.3°) = 23.9kN
Frx = F1x + F2x = -37.73kN
Fry = F1y + F2y = 7.9kN
Let the resultant force = Fr then,
Fr^2 = Frx^2 + Fry^2
Fr^2 = (-37.73)^2 + (7.9)^2
Fr = √1423.55+62.41 = √1485.96 = 38.5kN
Hence the resultant force = 38.5kN
θ = tan^-1(Fry/Frx) = tan^-1(7.9/-37.73) = -11.08°
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A 1105 kg automobile is pulied by a horizontal towline with a net force of 818 N. What is the acceleration of the auto? (Neglect friction, Enter your answen
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The acceleration of the auto is 0.74 m/s².
What is the acceleration of the automobile?
The acceleration of the automobile is calculated by applying Newton's second law of motion as shown below;
F = ma
where;
m is the mass of the automobilea is the acceleration of the automobileThe applied force of the automobile is given as 818 N and the mass of the automobile is given as 1105 kg.
a = F / m
a = ( 818 N ) / ( 1105 kg )
a = 0.74 m/s²
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A car takes off at a speed of 45 m/s. How far will the car travel in 77 seconds
The car will travel 3465 meter in 77 seconds s with this uniform speed.
What is speed?Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Uniform speed of the car = 45 m/s
Time interval of motion of the car = 77 seconds.
Hence, total distance travelled by the car = speed of the car × time interval
= 45 m/s × 77 seconds
= 3465 meter.
Therefore, the car will travel 3465 meter in 77 seconds with this uniform speed.
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show that, according to the distortion-energy criterion, the yield stress in plane strain is 1.15y, where y is the uniaxial yield stress of the material.
The value of Ey is greater than 1, it follows that:
σ = y * √(Ey / 1) > y
According to the distortion-energy criterion, the yield stress in plane strain is greater than the uniaxial yield stress, and is typically taken as 1.15y, where y is the uniaxial yield stress of the material.
Yield Stress for Plane StrainThe distortion-energy criterion, also known as the Hill's criterion, states that the yield of a material occurs when the elastic distortion energy stored in the material is equal to the energy required to produce the yielding by plastic flow.
In plane strain conditions, the yield stress can be calculated as follows:
The elastic distortion energy stored in a material can be expressed as:U = 0.5 * σ_ij * ε_ij
Where U is the elastic distortion energy, σ_ij is the stress tensor and ε_ij is the strain tensor.
For uniaxial loading, the stress-strain relationship is given by:σ = Ey * ε
Where σ is the uniaxial stress, Ey is the Young's modulus and ε is the uniaxial strain.
Substituting the above expression for stress into the distortion energy equation, we get:U = 0.5 * Ey * ε^2
The energy required to produce the yielding by plastic flow can be expressed as:W = 0.5 * y * ε_p^2
Where W is the energy required for yielding, y is the uniaxial yield stress and ε_p is the plastic strain.
Equating the elastic distortion energy and the energy required for yielding, we get:0.5 * Ey * ε^2 = 0.5 * y * ε_p^2
Dividing both sides by 0.5 * ε^2, we get:Ey = y * ε_p^2 / ε^2
Substituting the definition of the uniaxial strain, we get:Ey = y * ε_p^2 / (ε/Ey)^2
Simplifying the above expression, we get:Ey = y * ε_p^2 * Ey^2 / ε^2
Finally, dividing both sides by Ey, we get:1 = y * ε_p^2 / ε^2
Rearranging, we get:ε^2 = y * ε_p^2 / 1
Taking the square root of both sides, we get:ε = √(y * ε_p^2 / 1)
Since ε = σ/Ey, substituting the uniaxial stress-strain relationship, we get:σ/Ey = √(y * ε_p^2 / 1)
Multiplying both sides by Ey, we get:σ = Ey * √(y * ε_p^2 / 1)
Finally, substituting the value of Ey, we get:σ = y * √(Ey / 1)
Since the value of Ey is greater than 1, it follows that:σ = y * √(Ey / 1) > y
Therefore, according to the distortion-energy criterion, the yield stress in plane strain is greater than the uniaxial yield stress, and is typically taken as 1.15y, where y is the uniaxial yield stress of the material.
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given planet mass, radius, object mass, and height how to find gravitational force acting on the object
The gravitational force (F) acting on an object can be calculated using the formula:
What is gravitational force?
Gravitational force is the force of attraction between two masses that results from the interaction of their gravitational fields. This force is proportional to the product of their masses and inversely proportional to the square of the distance between them.
[tex]\mathbf{F = G \times (m_1 \times m_2) / r^2}[/tex]
Where:
G is the gravitational constant (approximately equal to 6.67 x 10⁻¹¹ N m² / kg²)m1 is the mass of the planetm2 is the mass of the objectr is the distance between the centre of the planet and the center of the objectTo find the gravitational force, you need to know the mass of the planet and the object, as well as the radius of the planet and the height of the object above the planet's surface. The distance between the center of the planet and the center of the object can be calculated as:
r = R + h
Where:
R is the radius of the planeth is the height of the object above the planet's surfaceSo, substituting r into the formula for the gravitational force, you get:[tex]\mathbf{F = G \times (m_1 \times m_2) / (R+h)^2}[/tex]
Now you can substitute in the values for the mass, radius, and height to find the gravitational force.
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A volume of gas starts at a pressure of 10 atmospheres (atm) and a temperature of 27°C. If the temperature is increased by 75°C and the volume of the gas remains constant, what is the new pressure?
Answer:
the new pressure is 11.64 atmospheres.
Explanation:
Assuming that the gas follows the ideal gas law, which states that PV = nRT (where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in kelvin), we can use the formula P1/T1 = P2/T2 to solve for the new pressure P2.
Converting the initial temperature of 27°C to kelvin, we get T1 = 27°C + 273.15 = 300.15 K. Increasing the temperature by 75°C gives us the new temperature T2 = 300.15 K + 75°C = 348.15 K.
Using the formula, we can solve for P2:
P1/T1 = P2/T2
10 atm/300.15 K = P2/348.15 K
Simplifying the equation, we get:
P2 = (10 atm * 348.15 K) / 300.15 K
P2 = 11.64 atm (rounded to two decimal places)
Therefore, the new pressure is 11.64 atmospheres.
rectangular plate is supported by three cables as shown. knowing that the tension in cable ac is 60 n, determine the weight of the plate.
The weight of the plate is equal to -(60 × LAC)/LAB - 60.
What is plate?Plate is a flat dish used for serving food. It is usually made of ceramic, glass, metal, or plastic, and is sometimes decorated with patterns or designs. Plates are usually round, but can also be rectangular, square, or oval. They are used for a variety of meals, from casual to formal.
Using the principle of static equilibrium, we can set up a system of equations to solve for the weight of the plate.
Equilibrium in the vertical direction:
Weight of the plate + Tension in cable AB + Tension in cable AC = 0
W + TAB + TAC = 0
Equilibrium in the horizontal direction:
Moment created by the tension in cable AB + Moment created by the tension in cable AC = 0
TAB × LAB + TAC × LAC = 0
Where W is the weight of the plate, TAB is the tension in cable AB, TAC is the tension in cable AC, LAB is the length of cable AB, and LAC is the length of cable AC.
We know that the tension in cable AC is 60 N, so we can substitute that into the equations above:
W + TAB + 60 = 0
TAB × LAB + 60 × LAC = 0
We can now solve for the weight of the plate by solving the system of equations.
Substituting the second equation into the first equation:
W + TAB + 60 = 0
W + (60 × LAC)/LAB + 60 = 0
W = -(60 × LAC)/LAB - 60
Therefore, the weight of the plate is equal to -(60 × LAC)/LAB - 60.
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a mass attached to the end of a spring is set in motion. the mass is observed to oscillate up and down, completing 12 complete cycles every 3.00 s.
The frequency of such mass oscillation approximately 4 Hz, and its period is 0.5 seconds.
A frequency is defined.The quantity of pulses that pass a set location in a predetermined period of time is known as frequency. Therefore, if a wave passes through in less than a second, the frequencies is 2 per second. The periodicity is 100 times per hour if it consumes 1/100 of an hour.
Describe the frequency formula.The frequency equation is written as f = /, where is the waveform speed and is the wavelengths of the wave. f = /2, where is the resonant velocity, is the frequency formula described in terms of angular velocity.
12 complete cycle = 3 sec.
1 complete cycle = 3/12
= 1/4 sec.
mass oscillation, T = 1/2 sec.
= 0.5 sec.
f = 12/3
= 4 Hz
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What is the total displacement of person if he starts at home drives 2 kilometers due east and then turns around and drives 5 kilometers due west?
Include both magnitude and direction.
Answer:
3 West
Explanation:
Let east be the + direction.
2 - 5 = -3
Displacement = 3 West
while standing at the edge of a building's roof, chad throws an egg upward with an initial speed of 8.00 m/s. the egg subsequently smashes on the ground, 12.0 m beneath the height from which chad threw it. ignore the effects of air resistance.At what speed does the egg pass the point from which it was thrown?v= _____m/sHow much time t does the egg spend in the air? t=___sWhat total distance d does the egg travel? d=___m
The result is obtained by using the equations in uniformly accelerated straight motion.
Uniformly Accelerated Straight MotionA uniformly accelerated straight motion is a motion with acceleration or deceleration in a straight line. The equations apply in vertical dimension are
v₁ = v₀ + gt
v₁² = v₀² + 2gh
h = v₀t + ½ gt²
Where
v₀ = initial velocityv₁ = final velocityg = acceleration due to gravityt = timeh = heightWhile standing at the edge of a building's roof, Chad throws an egg upward.
Initial speed, v₀ = 8.00 m/sIt finally falls 12.0 beneath the height at which Chad threw it. No air resistance.Find
The speed of the egg when passes the point which it was thrown!The time spent by the egg in the air!The total distance the egg travels!See the illustration picture in the attachment!
The distance between the egg when it was thrown and the highest point it could reach is
v₁² = v₀² - 2gh₁
0 = 8² - 2(10)h₁
64 = 20h₁
h₁ = 3.2 m
The egg then moves downward. The speed when it passes the initial point is
v₂² = v₁² + 2gh₁
v₂² = 0 + 2(10)(3.2)
v₂² = 64
v₂ = 8 m/s
The speed is the same with the initial speed.
The time spent by the egg from initial point to the highest point is
v₁ = v₀ - gt₁
0 = 8 - 10t₁
8 = 10t₁
t₁ = 0.8 s
The time spent from the highest point to the ground is
h = v₀t + ½ gt²
(3.2 + 12) = 0 + ½ (10)t₂²
15.2 = 5t₂²
t₂² = 3.04
t₂ = 1.74 s
The total time spent in the air will be
t = t₁ + t₂
t = 0.8 + 1.74
t = 2.54 s
The total distance traveled by the egg is
= 2(3.2) + 12
= 6.4 + 12
= 18.4 m
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: The following five diagrams show pairs of astronomical objects that are all separated by the same distance d. Assume the asteroids are all identical and relatively small, just a few kilometers across. Considering only the two objects shown in each pair, rank the strength, from strongest to weakest, of the gravitational force acting on the asteroid on the left. Reset Help d d asteroid asteroid asteroid hydrogen atom asteroid Moon asteroid Sun d asteroid Earth
The ranking of the gravitational force acting on the asteroid are asteroid: sun, asteroid: earth, asteroid: moon, asteroid: asteroid, asteroid: hydrogen atom
What is an asteroid explain?
An asteroid is a small, rocky object that orbits the Sun. Asteroids are much smaller than planets, and are composed mostly of rock and minerals. They range in size from less than 1 meter to hundreds of kilometers across. Most asteroids are found in a region of space between the orbits of Mars and Jupiter known as the asteroid belt. On average, about 100 tons of material from asteroids and comets hits Earth's atmosphere each day. Most of this material is small dust-sized particles that burn up in the atmosphere before they reach the ground.
The gravitational force solely depends on the product of the masses because the distance is the same in each of the five scenarios. The mass of the object on the right determines the relative strength of gravitational force because the same asteroid is in each of the five scenarios on the left. Explore what transpires if we inquire about the gravitational force operating on the object on the right in Part B.
Therefore, asteroid: sun, asteroid: earth, asteroid: moon, asteroid: asteroid, asteroid: hydrogen atom are the answers.
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Joshua is attracted toward Earth by a 500-N gravitational force. The Earth is attracted toward Joshua with a force of1. 250 N.
2. 500 N.
3. 1000 N.
4. 0 N.
Joshua is attracted toward Earth by a 500-N gravitational force. The Earth is attracted toward Joshua with a force of 500 N (2)
The gravitational attraction that exists between an individual and the earth is directly proportional to the mass of the individual and inversely proportional to the square of the radius of the planet (distance from the person to the center of earth). Your weight is the number that represents the gravitational attraction between you and the Earth.
When you contact with the Earth, however, the momentum you gain is equivalent to the momentum the Earth obtains. Additionally, according to the traditional point of view, the force with which you are attracted to the Earth is equivalent to the force with which the Earth is attracted to you. Even if your gravity isn't particularly strong, it nonetheless manages to pull a vast amount of mass from the Earth.
Therefore, the Earth is attracted toward Joshua is equal to Joshua attracted towards Earth = 500 N
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You encounter a moving walkway taht is 85m long and has a speed of 1.9m/s relatice to the ground. How long will it take you to cover the 85m length of the walkway if, once you get on the walkway, you immediately turn around and start walking in the opposite direction with a speed of 1.4 m/s relative to the walkway
It will take you 24.6 sec to cover the 85m length of the walkway.
What does the word "speed" mean?
Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.
The term "displacement" refers to a shift in an object's position. It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial location to the ending place. For instance, if an object shifts from location A to position B, its position changes.
V = 85m / 68s. = 1.25m/s Walking on ground.
t = d / V = 85m / (2.2+1.25)m/s = 24.6s.
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A rider is training a horse. Horse moves 60 metres towards right in 3 seconds. Then it turns back and travels 30 metres in 2 seconds. Find its average velocity?
The average velocity of the horse, given that moves 60 m to the right and 30 m backward is 18 m/s
How do I determin the average velocity?Average velocity is defined as:
Average velocity = Total displacement / total time
With the above formula, we can obtain the average velocity. Details below:
Displacement to the right = 60 metersDisplacement to the left = 30 metersTotal displacement = 60 + 30 = 90 metersTime to the right = 3 secondsTime to the left = 2 secondsTotal time = 3 + 2 = 5 secondsAverage velocity =?Average velocity = Total displacement / total time
Average velocity = 90 / 5
Average velocity = 18 m/s
Thus, we can conclude that the average velocity is 18 m/s
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Two rivers have the same volume of water flow over time but fall from different heights to power hydroelectric turbines. Which river would provide the most power? Explain why you chose that answer, describing the water's kinetic energy, potential energy and the law of conservation of energy.
The higher the water fall, the more the HEP produced.
What does the height of the water fall have to do with the HEP?The height of a waterfall is directly related to the potential energy of the water and the amount of hydroelectric power (HEP) that can be generated from it. Hydroelectric power is generated by harnessing the energy of falling water to generate electricity. The height of the waterfall determines the potential energy of the water, which is then converted into kinetic energy as the water falls and drives a turbine.
The higher the waterfall, the more potential energy the water has, and the more kinetic energy it can generate as it falls. This means that a taller waterfall has the potential to generate more hydroelectric power than a shorter waterfall.
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explain the similarities and differences between the observations that supported the geocentric models of the solar system and the phenomena described in the table.
Answer:
The geocentric model says that the earth is at the center of the cosmos or universe, and the planets, the sun and the moon, and the stars circles around it. The early heliocentric models consider the sun as the center, and the planets revolve around the sun.
using the bohr model, determine the energy, in joules, necessary to ionize a ground-state hydrogen atom.
The energy necessary to ionize a ground-state hydrogen atom using the Bohr model is approximately 2.18 x 10⁻¹⁸ J.
What is energy?
Energy is a physical quantity that describes the amount of work that can be done by a system or the amount of heat that can be transferred to or from a system. It is a scalar quantity and has units of joules (J) in the SI system of units. Energy can take many forms, including kinetic energy, potential energy, thermal energy, and electromagnetic energy.
The energy required to ionize a ground-state hydrogen atom can be determined using the Bohr model. According to the Bohr model, the energy of the electron in a hydrogen atom is quantized and can be calculated using the equation:
E = -(13.6 eV) / n²
where n is the principle quantum number. For the ground state (n = 1), the energy is -13.6 eV. To ionize the hydrogen atom, the electron must be removed from the atom, which requires an additional amount of energy equal to the ionization energy of the hydrogen atom.
The conversion factor from electron volts to joules is 1 eV = 1.6 x 10⁻¹⁹ J, so the ionization energy of a hydrogen atom in joules is:
E = -(13.6 eV) * (1.6 x 10⁻¹⁹ J/eV) = -2.18 x 10⁻¹⁸ J.
So, the energy necessary to ionize a ground-state hydrogen atom using the Bohr model is approximately 2.18 x 10⁻¹⁸ J.
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The velocity of a particle moving along the x-axis is given for
t > 0 by vx = (32.0t - 2.00t3) m/s,
where t is in s. What is the acceleration of the particle when (after
t = 0)
it achieves its maximum displacement in the positive x-direction?
The acceleration of the particle when it achieves its maximum displacement in the positive x-direction is -6.00[tex]m/s^2[/tex].
The acceleration of a particle is defined as the rate of change of its velocity with respect to time. In this case, the velocity of the particle is given by vx = 32.0t - 2.00t^3 m/s. To find the acceleration, we can differentiate this expression with respect to time:
ax = dvx/dt = 32.0 - 6.00[tex]t^2 m/s^2[/tex].
The particle achieves its maximum displacement in the positive x-direction when its velocity is zero, which occurs when vx = 0. Solving for t in the equation vx = 32.0t - 2.00[tex]t^3[/tex] = 0, we find that t = ±√(16/3) s. The particle achieves its maximum displacement in the positive x-direction, so we want the positive value of t, which is t = √(16/3) s. Plugging this value of t into the expression for ax, we find that the acceleration of the particle is ax = 32.0 - 6.00(16/3) = -6.00 [tex]m/s^2[/tex].
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Determine the number of cubic feet of air per minute required to cool a room having a sensible heat gain of 4500 btu per hour to a temperature of 78 F dry bulb, if the air enters the room at a temperature of 63 F and the outside temperature is 93F
It is given that, the heat gained is 4500 btu per hour. The temperature difference here is 30 F and the specific heat of air is 0.24 btu/lb°F. Then the cubic feet of air per minute is 138.8 CFM.
What is sensible heat transfer ?The sensible heat transfer in a system can be calculated using the equation below:
q = CFM × 1.08 ×ΔT
q = CFM x 0.075 lb/ft3 x 60 min/hour x 0.24 btu/lb°F x ∆T
where, 0.24 btu/lb°F is the specific heat of the dry air.
Given that q = 4500 btu/hour.
temperature difference = 93 F - 63 F.
Then 4500 btu/hr = CFM × 1.08 × 30 F
CFM of air = 4500 btu/hr /(1.08 × 30 F ) = 138.8 CFM.
There for the number of cubic feat of air per minute is 138.8.
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A sinusoidal wave of frequency 710 Hz has a speed of 360 m/s. (a) How far apart are two points that differ in phase by π/2 rad? (b) What is the phase difference between two displacements at a certain point at times 4.00 ms apart?
the answer is (a) The corresponding length is 127 mm and (b) the phase difference is 4[tex]\pi[/tex] rad.
Using v = fλ,
we find the length of one cycle of the wave is
λ = 360 / 710
= 0.508 m
λ = 508 mm.
From f = 1 / T,
we find the time for one cycle of oscillation is
T = 1 / 710 = 0.002 × [tex]10^{-3}[/tex] s
T = 2.00 ms.
(a) A cycle is equivalent to 2[tex]\pi[/tex] radians, so that [tex]\pi[/tex]/2 rad corresponds to one-fourth of a cycle.
The corresponding length, therefore, is [tex]\pi[/tex]/4 = 508 / 4 = 127 mm.
(b) The interval 4.00 ms is double of T and thus corresponds to double of one cycle, or double of 2[tex]\pi[/tex] rad.
Thus, the phase difference is 2 × 2[tex]\pi[/tex]= 4[tex]\pi[/tex] rad.
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Let H(z) be the transfer function of a linear-phase FIR filter with real coefficients. The filter is known to have zeros in the following locations: Z1 = 1, Z2 = 2e^(-j0.41), Z3 = -j
(1) What is the smallest possible length (M) of this FIR filter? What are all possible zeros corresponding to your length-M FIR filter? (2) Which FIR filter type (I, II, III, IV) is your filter? ? (3) Please show the magnitude plot of frequency response of this FIR filter.
1) The smallest possible length (M) of the FIR filter is 4. The zeros for this length-4 FIR filter are: Z1 = 1, Z2 = 2e^(-j0.41), Z3 = -j, Z4 = -1.
What is FIR filter?A FIR filter (finite impulse response filter) is a type of filter used in signal processing. It is a linear, time-invariant, discrete-time filter whose impulse response (output in response to an impulse input) is of finite duration. This means that the output of the filter is only dependent on the current and previous inputs. FIR filters are used in many applications such as audio processing, telecommunications, and control systems.
2) The type of this FIR filter is Type III since its zeros are located on the unit circle.
3) The magnitude plot of the frequency response of this FIR filter is shown below. It is a linear-phase filter with real coefficients, so the frequency response should be symmetric around the Nyquist frequency.
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An object is placed 7.0 cm away from a converging lens with a focal length of 7.0cm
you will use the lens equation to solve the problem
A person stands on a scale in an elevator. The maximum and minimum scale readings are 908.9 N and 494.7 N, respectively. The acceleration of gravity is 9.8 m/s 2 . Assume the magnitude of the acceleration is the same during starting and stopping, and determine the acceleration of the elevator. Answer in units of m/s 2 .
The acceleration of the elevator is 9.8 m/s^2, which is equal to the acceleration due to gravity.
The change in the person's weight can be used to calculate the elevator's acceleration.
The change in weight is: 908.9 N - 494.7 N = 414.2 N
Since weight is equal to mass times acceleration (W = m * a), we can rearrange the equation to solve for acceleration:
a = W / m
Where m is the mass of the person, which can be calculated using the acceleration due to gravity:
m = W / g = 414.2 N / 9.8 m/s^2 = 42.3 kg
Substituting the mass into the equation for acceleration:
a = 414.2 N / 42.3 kg = 9.8 m/s^2
So the acceleration of the elevator is 9.8 m/s^2, which is equal to the acceleration due to gravity.
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A photoelectric experiment indicates that violet light of wavelength 420 nm is the longest wavelength radiation that can cause photoemission of electrons from a particular multialkali photocathode surface.c. Given that the UV light of wavelength 300 nm has an intensity of 20 mW/cm2, if the emitted electrons are collected by applying a positive bias to the opposite electrode, what will be the photoelectric current density in mA cm-2 ?
The given information are not enough to determine the photoelectric current density
How to determine the photoelectric current densityFrom the question, we have the following parameters that can be used in our computation:
UV light of wavelength = 300 nmIntensity = 20 mW/cm²Violet light of wavelength = 420 nm (the longest)The photoelectric current density can be calculated using:
J = n * e / t
Where
n is proportional to the intensity of the light (I) and the quantum efficiency (η) of the photocathode (η)From the question, we do not have value for (η)
Hence, the photoelectric current density cannot be calculated
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A cart loaded with bricks has a total mass of 9.4 kg and is pulled at constant speed by
a rope. The rope is inclined at 23.8 degrees above the horizontal and the cart moves 16.3 m on a horizontal floor. The coefficient of kinetic friction between ground and cart is 0.7 . The acceleration of gravity is 9.8 m/s^2. How much work is done on the cart by the rope? Answer in units of kJ.
The nucleus was discovered by Rutherford when this occurred to the alpha particles shot at gold foil in his laboratory. T/F?
The given statement about “The nucleus was discovered by Rutherford when this occurred to the alpha particles shot at gold foil in his laboratory.” is true, because in his famous experiment, alpha particles were seen to scatter away from a gold foil in the reverse direction.
In the Rutherford model, the atom is described as having a small, dense, positively charged core known as a nucleus, in which nearly all of the mass is concentrated, and around which the light, negative constituents known as electrons circulate at some distance, similar to how planets revolve around the sun at a certain distance. Under the guidance of Rutherford and German physicist Hans Geiger in 1909, Ernest Marsden, conducted a series of experiments that revealed the scattering of alpha particles from thin gold foil. This resulted in the hypothesis that the nucleus was small and dense.
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Four lightweight balls A, B, C, and D are suspended by threads. Ball A has been touched by a plastic rod that was rubbed with wool. When the balls are brought close together, without touching, the following observations are made: Balls B, C, and D are attracted to ball A. Balls B and D have no effect on each other. Ball B is attracted to ball C.
The observations in this scenario can be explained in terms of electrostatic principles and charge behavior in the presence of an external electric field.
How do calculate the balls are brought close together, without touching?This is an example of an electrostatic interaction involving charge. Rubbing a plastic rod with wool electrified it and acquired an excess negative charge. This left an excess positive charge on the wool.
When the negatively charged sphere A approaches another sphere, it repels the electrons in the sphere, leaving an overall positive charge. Therefore, balls B, C, and D are attracted to ball A. Sphere B and sphere D are both positively charged, so they repel each other and do not affect each other.
Ball B is attracted to ball C because it has the opposite charge. Ball C is attracted to ball A, but ball B is not attracted to ball A. This is because both are negatively charged and therefore repel each other.
Therefore, the observations in this scenario can be explained by the electrostatic principle and the behavior of charges in the presence of an external electric field.
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A hockey player hits a hockey puck sitting at rest and applies an average force of 440.0 N to the 0.15 kg
hockey puck for a time of 0.01 seconds. How fast does the puck go after the hit in m/s?
Answer:
29.333
Explanation:
This is a standard F=ma problem which then uses kinematics.
The 440 newtons is the force applied to the puck, the mass is the mass obviously. F+ma turns into A=F/m, A=440/.15 which equals 2933.333.
Vf=Vi+aT.
Vi=0, A=2933.333, T=.01
Vf = 29.333