Dissolution of KOH, ΔHsoln:

KOH(s) → KOH(aq) (10.1)
Neutralization of solid KOH, ΔHneut:

KOH(s) + HCl(aq) → H2O(l) + KCl(aq) (10.2)

1) Using Hess's law, show how to combine Reaction 10.1 and Reaction 10.2 to give
KOH(aq) + HCl(aq) → H2O(l) + KCl(aq) (10.3)

2)How should ΔHsoln and ΔHneut be combined (mathematically) to give the change in enthalpy for Reaction 10.3, ΔH?

Answers

Answer 1

Using Hess's law we found:

1) By adding reaction 10.2 with the reverse of reaction 10.1 we get reaction 10.3:

KOH(aq) + HCl(aq)  → H₂O(l) + KCl(aq)   ΔH  (10.3)

2) The ΔHsoln must be subtracted from ΔHneut to get the total change in enthalpy (ΔH).    

The reactions of dissolution (10.1) and neutralization (10.2) are:

KOH(s) → KOH(aq)   ΔHsoln    (10.1)

KOH(s) + HCl(aq) → H₂O(l) + KCl(aq)     ΔHneut     (10.2)

1) According to Hess's law, the total change in enthalpy of a reaction resulting from differents changes in various reactions can be calculated as the sum of all the enthalpies of all those reactions.      

Hence, to get reaction 10.3:

KOH(aq) + HCl(aq) → H₂O(l) + KCl(aq)    (10.3)

We need to add reaction 10.2 to the reverse of reaction 10.1

KOH(s) + HCl(aq) + KOH(aq) → H₂O(l) + KCl(aq) + KOH(s)

Canceling the KOH(s) from both sides, we get reaction 10.3:

KOH(aq) + HCl(aq)  → H₂O(l) + KCl(aq)    (10.3)

2) The change in enthalpy for reaction 10.3 can be calculated as the sum of the enthalpies ΔHsoln and ΔHneut:

[tex] \Delta H = \Delta H_{soln} + \Delta H_{neut} [/tex]

The enthalpy of reaction 10.1 (ΔHsoln) changed its sign when we reversed reaction 10.1, so:

[tex] \Delta H = \Delta H_{neut} - \Delta H_{soln} [/tex]

Therefore, the ΔHsoln must be subtracted from ΔHneut to get the total change in enthalpy ΔH.

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Related Questions

__________ are negatively charged subatomic particles found in orbital clouds around the nucleus of an atom.

Answers

the answer is electrons :)

For a process Arightwards harpoon over leftwards harpoonB, at 25 °C there is 10% of A at equilibrium while at 75 °C, there is 80% of A at equilibrium. Estimate enthalpy change of this reaction in kJ/mol

Answers

This question is describing the following chemical reaction at equilibrium:

[tex]A\rightleftharpoons B[/tex]

And provides the relative amounts of both A and B at 25 °C and 75 °C, this means the equilibrium expressions and equilibrium constants can be written as:

[tex]K_1=\frac{90\%}{10\%}=9\\\\K_2=\frac{20\%}{80\%} =0.25[/tex]

Thus, by recalling the Van't Hoff's equation, we can write:

[tex]ln(K_2/K_1)=-\frac{\Delta H}{R}(\frac{1}{T_2} -\frac{1}{T_1} )[/tex]

Hence, we solve for the enthalpy change as follows:

[tex]\Delta H=\frac{-R*ln(K_2/K_1)}{(\frac{1}{T_2} -\frac{1}{T_1} ) }[/tex]

Finally, we plug in the numbers to obtain:

[tex]\Delta H=\frac{-8.314\frac{J}{mol*K} *ln(0.25/9)}{[\frac{1}{(75+273.15)K} -\frac{1}{(25+273.15)K} ] } \\\\\\\Delta H=4,785.1\frac{J}{mol}[/tex]

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40.0 g of ice cubes at 0.0°C are combined with 150. g of liquid water at 20.0°C in a coffee cup calorimeter. Calculate the final temperature reached, assuming no heat loss or gain from the surroundings. (Data: specific heat capacity of H2O(l), c = 4.18 J/g×°C; H2O(s) => H2O(l) DH = 6.02 kJ/mol)Calculate the final temperature reached, assuming no heat loss or gain from the surroundings. (Data: specific heat capacity of H2O(l), c = 4.18 J/g×°C; H2O(s) => H2O(l) DH = 6.02 kJ/mol)

Answers

The final temperature of the mixture in the coffee cup calorimeter is; 19.467 °C

According to the law of energy conservation:

As such; the heat transfer in the liquid water is equal to heat gained by the ice

Heat transfer by liquid water is therefore;

DH = m × c × DT

DH = 6.02 kJ/mol) = 150 × 4.18 × (T1 - T2)

6020 J/mol = 627 × (20 - T2)

However, since 18g of water makes one mole

6020 J/mol = 6020/18 = 334.44 J/g.

334.44 = 627 × (20 - T2)

0.533 = (20 - T2)

T2 = 20 - 0.533

T2 = 19.467°C

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Construct a conclusion using the claim, evidence and reasoning format to explain the typical properties observed by ionic and covalent compounds.

Answers

Answer:

The key to understanding why ionic and covalent compounds have different properties from each other is understanding what's going on with the electrons in a compound. Ionic bonds form when atoms have different electronegativity values from each other. When the electronegativity values are comparable, covalent bonds form.

But, what does this mean? Electronegativity is a measure of how easily an atom attracts bonding electrons. If two atoms attract electrons more or less equally, they share the electrons. Sharing electrons results in less polarity or inequality of charge distribution. In contrast, if one atom attracts bonding electrons more strongly than the other, the bond is polar.

Ionic compounds dissolve in polar solvents (like water), stack neatly on each other to form crystals, and require a lot of energy for their chemical bonds to break. Covalent compounds can be either polar or nonpolar, but they contain weaker bonds than ionic compounds because they are sharing electrons. So, their melting and boiling points are lower and they are softer.

I hope this helps have a great day :)

Determine the molarity for each of the following Solution: 98.0 of phosphoric acids H3PO4 in 1.00L of Solution.​

Answers

The molarity of the solution is 0.01.

Brainliest?

How much does a cloud weigh in pounds?

Answers

Answer:

1.1 million pounds

Explanation:

Answer:

1.1 million pounds

Explanation:

that's a lot of water above us!!

Explain how the following properties change across the periodic Table from group 1 to group 2, and give reasons for the increase or decrease thereof:
a) Ionic radius
b) Ionization enthalpy
c) Density
d) Melting point
e) Electropositive character​

Answers

The following properties change across the periodic Table from group 1 to group 2

a) Ionic radius - decreaseb) Ionization enthalpy - increasec) Density - increased) Melting point - increasee) Electropositive character​ - decrease

Group 1 are alkali metals that have one valence electron in the outermost orbit whereas alkaline earth metals are in group 2 have two valence electrons in the outermost orbit.

a) Ionic radius:

The atomic and ionic radii of alkaline earth metals are fairly large though smaller than those of the corresponding alkali metals.  

b) Ionisation enthalpy:

Alkali metals have low Ionisation energy.in the case of alkaline earth metals Ionisation energy is higher compared to alkali metals  

c) Density:

The alkaline earth metals are denser than the alkali metals due to the smaller size and better packing of the atoms in the crystal lattice  

d) Melting point:

Melting points of alkaline earth metals are low but higher than those of alkali metals.  

e) Electropositive character:

all alkali metals are strongly Electropositive due to their low Ionisation enthalpies.alkaline earth metals are less Electropositive than alkali metals.

Thus, changes in properties are:

a) Ionic radius - decreaseb) Ionization enthalpy - increasec) Density - increased) Melting point - increasee) Electropositive character​ - decrease

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Oxidation unit test
Please help ASAP.

Which phrase best defines a redox reaction? (1 point)
O a reaction in which oxygen combines with different atoms
O a reaction in which electrons are transferred between different atoms
O a reaction in which electrons are released from the system
O a reaction in which the number of oxygen atoms is reduced

Answers

Answer:

a reaction in which electrons are transferred between different atoms

Explanation:

I took the test and got it right :)

c. a reaction in which electrons are released from the system

Oxidation:

Oxidation is a process which involves the addition of oxygen or any electronegative element or the removal of hydrogen or any electropositive element.  In terms of electrons, oxidation is defined as the process in which an atom or ion loses one or more electrons.Oxidation occurs when the oxidation state of a molecule, atom or ion is increased. The opposite process is called reduction, which occurs when there is a gain of electrons or the oxidation state of an atom, molecule, or ion decreases.

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Mixtures of hydrogen and oxygen in varying concentrations can be sparked to produce water. Define mixture and compound, and then explain the differences between a mixture of hydrogen and oxygen and the compound dihydrogen monoxide (also known as water).

Answers

Explanation:

Mixture is the physical Combination Of two or Substance

Example

a mixture of sugar and water.

Compound is the chemical combination of two or more metals.

Example.

a mixture of hydrogen and water.

A mixture of hydrogen and oxygen forms water or H2O

whereas The dihydrogen monoxide parody involves calling water by an unfamiliar chemical name, most often "dihydrogen monoxide" (DHMO), and listing some of water's properties in a particularly alarming manner, such as accelerating corrosion (rust) and causing suffocation (drowning). The parody often calls for dihydrogen monoxide to be banned, regulated, or labeled as dangerous. It plays into chemophobia and demonstrates how a lack of scientific literacy and an exaggerated analysis can lead to misplaced fears. The parody has been used with other chemical names such as hydrogen hydroxide, dihydrogen oxide, hydroxic acid, hydric acid and oxidane.

A Mixture of hydrogen and oxygen in varying concentrations can be sparked to produce water. This is formed due to the property of chemical combination.

A Mixture is the physical Combination Of two or Substance whereas a Compound is the chemical combination of two or more metals.

Example of a mixture is a mixture of sugar and water. And, Example of an compound is A mixture of hydrogen and oxygen forms water or H₂O

Water is also called as dihydrogen monoxide. The prefix mono and di are used to indicate a single atom and combination of two atoms respectively.   Some of its properties includes such as accelerating corrosion (rust) and causing suffocation (drowning).

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Which statement best describes the driving force behind the electrophilic addition of strong acid to an alkene

Answers

The chemical transformation of a carbon-carbon double bond is by addition reaction. The statement best describes the driving force is that the reaction is favorable because the total bond strength in the products is greater than in the reactants.

A great number of reagents often found in inorganic and organic, have been known to add to the functional group of alkenes.

The bond energies of a molecule is simply known as the energies needed to break all the covalent bonds in the molecule.

When the bond energies of the product molecules is known to be greater than the bond energies of the reactants, the reaction is regarded as exothermic.

The full question is below

Which statement best describes the driving force behind the electrophilic addition of strong acid to an alkene?

The reaction is favorable because the pi bond is stronger than a sigma bond and it takes more energy to break it.

The reaction is favorable because a less stable, high-energy intermediate is formed.

The reaction is favorable because the first step is the rate-determining step.

The reaction is favorable because the total bond strength in the products is greater than in the reactants.

The reaction is favorable because the overall reaction is endothermic.

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Write a balanced chemical equation for this reaction by completing the reaction below. Add the missing products and coefficients. Do not include phases.

Answers

To balance a chemical equation you must pay attention that the algebraic equation has the same number of element atoms in reactant and the product.

A chemical equation is a term to refer to the symbolic description of a chemical reaction, that is, the written representation of symbols. For example:

2H₂ + O₂ ---> 2H₂O

The balance of an equation can be related to the law of conservation of matter, that is, the number of atoms of each element in the reactants is in the result.

Note: This question is incomplete, because the information some information is missing.

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Why we use two different methods for detection of cogulase enzyme ? Or what other reason or what basic different between them?

Answers

I’m so sorry I hope you have a wonderful day good luck

analyze why is the result of the stage of meiosis shown below an advantage for organisms that reproduce sexually.

Answers

Answer:

Meiosis produces haploid cells (gametes), which contain single chromosomes, or on-half the number of chromosomes in diploid cells. When a sperm and an egg join, the single chromosomes pair up, which results in genetic diversity in the offspring

Given the balanced chemical equation:
4 Fe + 3 O2 ----> 2 Fe2O3


How many moles of iron(III) oxide, Fe2O3 , will be produced if 12 moles of iron, Fe, are consumed.

Answers

Answer:

6 moles

Explanation:

Looking at the coefficient of the reactants/ products, the ratio of Fe consumed to Fe₂O₃ produced is 4: 2.

Fe: Fe₂O₃

= 4: 2

= 2: 1

This means that the amount of Fe₂O₃ produced is half the amount of Fe consumed, in terms of moles.

Given that 12 moles of Fe are consumed,

amount of Fe₂O₃ produced

= 12 ÷2

= 6 moles

Answer:

see explanation

Explanation:

4Fe +3O2----------2Fe2O3

if we have 12 moles of Fe, we have 3X4 mole of Fe

but since 4 moles of Fe produce 2 moles of Fe2O3,6 then 3X 4 moles of Fe produce 3X2 moles of Fe2O3 or

6 moles.

One mole of Fe2O3 has a molar mass of (56X2) +(3X16) = 112+48 = 160

One mole Fe2O3 has a molar mass of 160 gm

6 moles of Fe2O3 have a mass of 160 X6 =960 gm

What element is being oxidized in the following redox reaction?

Cr(OH)4-(aq) + ClO-(aq) → CrO42-(aq) + Cl-(aq)

Answers

Answer:

Cr

Explanation:

Cr goes from +3 to +6 and when it increases it means is being oxidized.

The element being oxidized in the redox reaction is Cr. Oxidation state helps to determine the amount of oxidation which an atom undergoes. An increase in oxidation state or number signifies oxidation has taken place.

A decrease in oxidation state depicts reduction has taken place. In this

scenario, the element Cr has a change in oxidation state from +3 to +6 which

signifies oxidation took place in the atoms of the element. This is why Cr will

be the right option.

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The pH of an acidic solution is 4.83. What is [H"]?

Answers

[tex]pH = -\log[H^{+}] \\\\\implies \log[H^{+}] = -pH\\\\\implies [H^{+}] = 10^{-pH}\\\\\implies [H^{+}] = 10^{-4.83} = 0.000015[/tex]

A mixture is made of 40 ml of salt water to 200 ml of solution. What percent of the solution is salt water?

Answers

Answer:

16.7%

Explanation:

40 ml of salt water + 200 ml of solution = 240 ml

40/240 = 4/24 = 1/6=16.7%

Cómo se forma un enlace polipeptido?

Answers

Qué es la pregunta que estás preguntando?

Which substance is the limiting reactant when 24.0 g of sodium hydroxide reacts with 18.0 g of oxygen and 12.0 g of sulfur according to the following chemical equation:
2 S(s) + 3 O2(g) + 4 NaOH(aq) → 2 Na2SO4(aq) + 2 H2O(l)

Answers

Answer:

Sodium hydroxide.

Explanation:

Don't be confused by the fact that you have three reactants, you can find the limiting reagent by using the same technique you use for reactions that have two reactants.

for more info... use the link

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ThAnK YoU

Hello, is there anyone here a pharmacy technician?

Answers

Explanation:

It can take up to two years to become a pharmacy technician, depending on the education program you choose. In fact, most pharmacy certification programs can be in a year, or less than eight months.

6. How will you obtain ? (a) Magnesium oxide from magnesium. (b) Silver chloride from silver nitrate. (c) Nitrogen dioxide from lead nitrate. (d) Zinc chloride from zinc. (e) Ammonia from nitrogen. Also give balanced equations for the reactions.​
plx answer this question

Answers

Answer:

a) reaction with oxygen

2mg +o2---------2mgo

b) Agno3+NaCl ----------AgCl+NaNo3

How many atoms are in mercury (I) phospate?
The chemical formula is (Hg2)3(PO4)2

A)11
B)14
C)15
D)16

Answers

Mercury (I) phosphate with the chemical formula  (Hg2)3(PO4)2 has 16 atoms.

Number of Hg atoms = 2x3 = 6Number of P atoms = 2 x 1 = 2Number of O atoms = 4x2 = 8

Sum of all the atoms = 6+2+8

                                   = 16 atoms

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Pleeeeasee someone who’s good at chemistry?! 10 grade

ASAP
I’ll give points, just help please

Answers

I’m good in chemistry but where’s the question?

what is the best way to make a supersaturated solution?
A: Heat the solution
B: Stir the Solution
C: Evaporate the solution
D: Cool the solution

Answers

Answer:

heat the solution

Explanation:

i think

Answer:

The way to make a supersaturated solution is to add heat, but just a little heat won't do the job. You have to heat the water close to the boiling point. When the water gets this hot, the water molecules have more freedom to move around, and there is more space for solute molecules between them.

the amount of solute dissolved in a solvent
A. Concentration.
B.alloy
C.mixture
D.solution

Answers

Answer:

solution

Explanation:

solvent +solute =solution

The octahedral complex ion [MnCl6] 3- has more unpaired spins than the octahedral complex ion [Mn(CN)6] 3- . How many unpaired electrons are present in each species

Answers

[MnCl6] 3- is high spin and has five unpaired electrons while [Mn(CN)6] 3- has only two unpaired electrons.

A complex may be low spin or high spin depending on the kind of ligand attached to the central metal atom/ion. If the ligand is a weak field ligand, the complex may be high spin (maximum number of unpaired electrons). If the complex is low spin, there are few unpaired electrons (minimum number of unpaired electrons). In that case, the ligand is a strong field ligand.

In the octahedral geometry,  [MnCl6] 3- is high spin and has five unpaired electrons since the chloride ion is a weak field ligand. On the other hand  [Mn(CN)6] 3- has only two unpaired electrons because the cyanide ion is a strong field ligand.

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PLS HELP CHEM

What is the temperature, in Celsius, of 20.8 g of carbon dioxide (CO2) in a 575 mL container under 1.5 atm of pressure?

Answers

Answer:

Use the formula PV=nRT to get the temperature

what is the free energy change G for the equilibrium between hydrogen iodine a hydrogen and iodine at 4:53

Answers

Answer:

Many chemical reactions are reversible; that is, the products of the reaction can combine to re-form the reactants. An example of a reversible reaction is that of hydrogen with iodine to form hydrogen iodide:

H2(g) + I2(g) 2 HI(g)

We can study this reversible reaction by placing hydrogen and iodine in a reaction vessel and then measuring the concentrations of H2, I2, and HI at various times after the reactants are mixed. Figure 13.8 is a plot of the concentrations of reactants and products of this reaction versus time. The concentration of hydrogen iodide increases very rapidly at first, then more slowly, and finally, after the time indicated by the vertical line marked "Equilibrium," remains constant. Similarly, the concentrations of hydrogen and iodine are large at the start of the reaction but decrease, rapidly at first, and then more slowly. Finally, they, too, become constant.

If this reaction were not reversible, the concentrations of hydrogen and iodine would have continued to decrease and the concentration of hydrogen iodide to increase. This process does not happen. Instead, as soon as any molecules of hydrogen iodide are formed, some decompose into hydrogen and iodine. Two reactions are taking place simultaneously: the formation of hydrogen iodide and its decomposition. When the concentrations of all these components become constant (at the equilibrium point in Figure 13.8), the rate of the forward reaction (H2 + I2 2 HI) must be equal to the rate of the reverse reaction (2 HI H2 + I2). A state of dynamic chemical equilibrium has then been reached, one in which two opposing reactions are proceeding at equal rates, with no net changes in concentration.

PICTURE 13.8

FIGURE 13.8 Concentration changes during the reversible reaction

H2(g) + I2(g) 2 HI as it proceeds toward equilibrium.

We have encountered this criterion for equilibrium before. In the equilibrium between a liquid and its vapor, the rate of vaporization is equal to the rate of condensation. In the equilibrium of a saturated solution with undissolved solute, the rate of dissolution is equal to the rate of precipitation. In the equilibrium of a weak acid with its ions, the rate of dissociation is equal to the rate of recombination. Note that none of these reactions is static: Two opposing changes are occurring at equal rates.

B. The Characteristics of Chemical Equilibrium

1. Equal rates

At equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction.

2. Constant concentrations

At equilibrium, the concentrations of the substances participating in the equilibrium are constant. Although individual reactant molecules may be reacting to form product molecules and individual product molecules may be reacting to re-form the reactants, the concentrations of the reactants and the products remain constant.

3. No free energy change

At equilibrium, the free energy change is zero. Neither the forward nor the reverse reaction is spontaneous and neither is favored. Consider the ice-water change. Above 0°C, ice melts spontaneously to form liquid water; G for this change is negative. Below 0°C, the change from ice to water is not spontaneous; G is positive. At 0°C, the two states are in equilibrium. The rate of melting is equal to the rate of freezing: the amount of ice and water and the amount of liquid water present remain constant, and the free energy change is zero as long as no energy is added to or subtracted from the mixture.

C. The Equilibrium Constant

In Chapter 12, we introduced the mathematical relationship between the concentrations of the components of an equilibrium, known as the equilibrium constant, Keq. We said that, for the general equation of a reversible reaction

Explanation:

sorry(: hope to help

How many moles of NaOH are present in 12.0 mL of 0.110 NaOH?

Moles: ___________

Answers

Answer:

0.00132moles

Explanation:

1000ml of NaOH contain 0.110 moles

12ml of NaOH contain (12*0.110)/1000 moles

= 0.00132 moles

Which of the following has the greatest mass?

A) One mole of mercury

B) One mole of barium

C) One mole of gold

D) They all have the same mass

Answers

Answer:one mole of gold

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