discuss 5 features of mobile phones and how it can help play in a holistic digital marketing strategy​

Answer:

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

Answer:

(a). 0.1 × 10^-3 = 0.1 msec.

(b). 0.11 × 10^-3 = 0.11 msec.

(c). 1 × 10^-3. = 1 msec.

Explanation:

So, in order to solve this problem or question there is the need to use the Markov queuing formula which is represented mathematically as below;

Mean time delay, t = /(mean frame length,L) × channel capacity, C - frame arrival rate, F. ---------------------------------(1).

(a). Using equation (1) above, the delay experience by 90 frames/sec.

=> 1/(10^-4× 10^8 - 90). = 0.1 × 10^-3= 0.1 msec.

(b). Using equation (1) above, the delay experience by 900 frames/sec.

=> 1/(10^-4× 10^8 - 900). = 0.11 × 10^-3= 0.11 msec.

(c). Using equation (1) above, the delay experience by 90 frames/sec.

=> 1/(10^-4× 10^8 - 9000). = 1 × 10^-3= 1 msec.

Hence, the operating queuing system is; 900/10^-4 × 10^8 = 0.9.

Answer:

See explaination

Explanation:

import os,string

def readfile(filename):

if os.path.isfile(filename) is not True:return None

line_number=1

word_dict={}

print('Text File to be analyzed: {}'.format(filename))

with open(filename,'r') as infile:

for line in infile.readlines():

words = line.strip().split()

for word in words:

word = word.strip(string.punctuation)

if word.strip()=='':continue

if word_dict.get(word)==None:

word_dict[word]=[line_number]

else:

line_number_list=word_dict.get(word)

line_number_list.append(line_number)

line_number+=1

return word_dict

def write_to_file(word_dict,filename):

with open(filename,'w') as outfile:

for word in sorted(word_dict.keys()):

outfile.write('{0}:\t\t{1}\n'.format(word,','.join([str(n) for n in word_dict.get(word)])))

def main():

filename='D:\\Word.txt'

output_filename='D:\\word_index.txt'

word_dict = readfile(filename)

if word_dict ==None:

print('Unable to read file {}'.format(filename))

else:

for word in sorted(word_dict.keys()):

print('{0}:\t\t{1}'.format(word,','.join([str(n) for n in word_dict.get(word)])))

write_to_file(word_dict,output_filename)

main()

Answer:

Step 1: Identify the Problem

Step 2: Review the Literature. ...

Step 3: Clarify the Problem Step 4: Clearly Define Terms and Concepts.

Answer:

Question (1) the statements (i) and( iv) are logically equivalent and statements (ii) and (iii) are logically equivalent. Question (2) the statements (i) and (iii) are logically equivalent.

Explanation:

Solution

Question (1)

Now,

Lets us p as puppy in the house, and q as i am happy

So,

p : puppy in the house,  and q : i am happy

Thus,

The Statements

(i) so if there is a puppy in the house, I feel happy :  p -> q

(ii) If I am happy, then there is a puppy in the house : q -> p

(iii) If there is no puppy in the house, then I am not happy.   : ~ p -> ~q

(iv) If I am not happy, then there is no puppy in the house : ~q -> ~p

Hence, the statements (i) and( iv) are logically equivalent and statements (ii) and (iii) are logically equivalent.

Question (2)

Let us denote p as i am in school today, and q as i am in CSC231 class, and r as i am in civics class,

So,

p: i am in school today, q: i am in CSC231 class, r: i am in civics class,

Now,

(i) if I am in school today, then I am in CSC231 class  :p -> q

(ii) If I am not in school today, then I am not civics class  :~p -> ~r

(iii) If I am not in CSC231 class, then I am not in school today  :~q -> ~p

(iv) If I am in CSC231 class, then I am in school today  : q -> p

Therefore, the statements i) and iii) are logically equivalent.

Answer:

Innovation.

Explanation:

Innovation can be considered the ideal term, because an innovative idea arises from the set of a new technique, method or invention that aims to improve an existing method, standard, or product.

However, added to an innovative idea is the risk, since innovation breaks an already established standard, so it is through science and technology that an invention will gain greater foundation and recognition, which increases its credibility and acceptance.

Answer: Its the is the centralized management of the flow of goods and services and includes all processes that transform raw materials into final products. By managing the supply chain, companies are able to cut excess costs and deliver products to the consumer faster.

It is a management of the flow of goods, data, and finances related to a product or service, from the procurement of raw materials to the delivery of the product at its final destination.

Explanation: ik its long but hope it helps

Answer:

1. =CONCATENATE(" John"," ","Smith")

2. =(" John"&" "&"Smith")

Explanation:

Given

Two separate strings; "John" and "Smith"

Required

2 separate formulas to concatenate both strings to form " John Smith"

There are several ways to concatenate strings in Microsoft Office Excel; one of the methods is using the concatenate function while the another method is using the traditional & operator.

Using the concatenate function, the formula is as follows

=CONCATENATE(" John"," ","Smith")

This function will combine the " John", " " and "Smith" to give a new string " John Smith" (without the quotes).

Using the traditional & operator may be a little bit difficult (and not frequently used) but the formula is as follows;

=(" John"&" "&"Smith")

The result will be the same as (1) above

Answer:

Not very big - maybe 64 GB or 128 GB

Explanation:

PPT doesn't take up much space

Answer:

see explaination

Explanation:

Final value :-

Memory => value = reference in code

5000 => 12 = x

5004 => 6000 = *y

5008 => 5000 = *z

5012 => 5000 = *a

6000 => 12 = y[0]

6004 => 15 = y[1]

6008 => 10 = y[2]

6012 => 12 = y[3]

6016 => 12 = y[4]

6020 =>

Answer: information can be viewed my strangers

Explanation:

Apex

Answer:

Aqueous carbon dioxide, CO2 (aq), reacts with water forming carbonic acid, H2CO3 (aq). Carbonic acid may loose protons to form bicarbonate, HCO3- , and carbonate, CO32-. In this case the proton is liberated to the water, decreasing pH. The complex chemical equilibria are described using two acid equilibrium equations.

PLS MARK AS BRAINLIEST

Answer: The UK government offers a global scholarship programme called “Chevening”. It is open to all international students who meet the Chevening eligibility criteria, which states you must have applied for at least three degree courses in the UK, usually one-year Master's courses

Explanation: So yes that should be fine

Answer:

What is your question?

//Write the class definition for the class Car

public class Car {

   //Declare the instance variables(fields)

   int yearModel;

   String make;

   int speed;

   //Declare the constructor: Make sure the constructor has  

   //the same name as the name of the class - Car.

   //The constructor receives two parameters - yearModel and make.

   //The parameters are then assigned to their respective fields.

   //The speed field is given a value of zero.

   public Car(int yearModel, String make){

       this.yearModel = yearModel;

       this.make = make;

       this.speed = 0;

   }

   //Accessor method - get - for the yearModel

   //returns the yearModel of the car

   public int getYearModel() {

       return yearModel;

   }

   //Accessor method - get - for the make

   //returns the make of the car

   public String getMake() {

       return make;

   }

   //Accessor method - get- for the speed

   //returns the speed of the car

   public int getSpeed() {

       return speed;

   }

   //Method accelerate() to increase the speed of the car by 5

   //each time it is called

   public void accelerate(){

       this.speed += 5;

   }

   //Method brake() to decrease the speed of the car by 5

   //each time it is called

   public void brake(){

       this.speed -= 5;

   }

}    //End of class declaration

The code above has been written in Java. It contains comments explaining the code. Please go through the comments. The actual lines of code that are executable are written in bold-face to distinguish them from the comments.

Answer:

Following are the code to this question:

#include <iostream>//defining header file  

using namespace std;    

bool rightTriangle(int s1,int s2,int s3) //defining method rightTriangle  

{

int t1,t2,t3; //defining integer variables

t1 = s1*s1; // multiplying side value and store it into declaring integer  variables

t2 = s2*s2; // multiplying side value and store it into declaring integer variables

t3 = s3*s3;  // multiplying side value and store it into declaring integer variables

if(t3 == t1+t2)//use if block to check Pythagoras theorem

{

return true; //return true

}

else //else block

{

return false; //return false

}

}

bool equalNums(int n1,int n2,int n3,int n4) //defining method equalNums  

{

if(n1==n3 && n2==n4) //defining if block that checks  

{

return true;//return value true  

}

else //else block  

{

return false; //return value false

}

}

int main()//defining main method

{  

int t1=3,t2=4,t3=5,t11=3,t12=4,t13=5; //declaring integer varibles and assign value  

int check=0;   //defining integer varible check that checks values

if(rightTriangle(t1,t2,t3)&&rightTriangle(t11,t12,t13)) //defining codition to check value using and gate

{

if(equalNums(t1,t3,t11,t13) || equalNums(t2,t3,t12,t13)) // defining conditions to check value using or gate

check = 1; //if both conditions are true

}

if(check==1) //if block to check value is equal to 1

{

cout << "Right Congruent Triangles"; //print message

}

else//else block

{

   cout << "Not Right Congruent Triangles";//print message

}

}

Output:

Right Congruent Triangles

Explanation:

Answer:

a. Gross revenue

b. 95% P.I ( 91.774, 95.400)

Explanation:

Please check the file attached below to see the solution to given question using minitab

Answer:

nos despertamos a las ocho

Explanation:

Answer:

The method is easy . Divide the binary number by 2 and write the remainder . Again divide by 2 and write remainder and continue till remainder becomes 1 . Then write all the remainders (0 , 1) in the order . The decimal is converted into binary

If you wanna convert binary into decimal , number the digits of a binary number from right to left and from 0 to how much digits are there. Then the digit 1 or 0 is multiplied by the corresponding power of 2 , which comes after numbering . Add all them and you get them into decimal

Answer:

The answer is D) Look up the number on a binary-to-decimal conversion table.

Explanation:

Answer:

A program written in C++ was create for a customer bill for a company. the company sells five products, which are TV, DVD player, Remote Controller, CD Player, and Audio Visual Processor.

The code is implemented and shown below in the explanation section

Explanation:

Solution:

The C++ Code:

#include<iostream>

#include<string>

#include<iomanip>

using namespace std;

#define taxrate 8.75

int main(){

const double upTv = 500.00;

const double upDvdPlayer = 380.00;

const double upRemoteController = 35.00;

const double upCdPlayer = 74.00;

const double upAudioVideoProcessor = 1500.00;

cout << "How many TVs were sold? ";

double ntv;

cin >> ntv;

cout << "How many DVD players were sold? ";

double ndvd;

cin >> ndvd;

cout << "How many Remote Controllers were sold? ";

double nrc;

cin >> nrc;

cout << "How many CD Players were sold? ";

double ncd;

cin >> ncd;

cout << "How many AV Processors were sold? ";

double nav;

cin >> nav;

double ptv = ntv * upTv;

double pdvd = ndvd * upDvdPlayer;

double prc = nrc * upRemoteController;

double pcd = ncd * upCdPlayer;

double pav = nav * upAudioVideoProcessor;

double tp = ptv + pdvd + prc + pcd + pav;

cout << setw(5) << left << "QTY";

cout << setw(20) << left << "Description";

cout << setw(15) << left << "Unit Price";

cout << setw(15) << left << "Price" << endl;

cout << setw(5) << left << (int)ntv;

cout << setw(20) << left << "TV";

cout << setw(15) << left << fixed << setprecision(2) << upTv;

cout << setw(15) << left << fixed << setprecision(2) << ptv << endl;

cout << setw(5) << left << (int)ndvd;

cout << setw(20) << left << "DVD";

cout << setw(15) << left << fixed << setprecision(2) << upDvdPlayer;

cout << setw(15) << left << fixed << setprecision(2) << pdvd << endl;

cout << setw(5) << left << (int)nrc;

cout << setw(20) << left << "Remote Controller";

cout << setw(15) << left << fixed << setprecision(2) << upRemoteController;

cout << setw(15) << left << fixed << setprecision(2) << prc << endl;

cout << setw(5) << left << (int)ncd;

cout << setw(20) << left << "CD Player";

cout << setw(15) << left << fixed << setprecision(2) << upCdPlayer;

cout << setw(15) << left << fixed << setprecision(2) << pcd << endl;

cout << setw(5) << left << (int)nav;

cout << setw(20) << left << "AV Processor";

cout << setw(15) << left << fixed << setprecision(2) << upAudioVideoProcessor;

cout << setw(15) << left << fixed << setprecision(2) << pav << endl;

cout << setw(15) << left << "SUBTOTAL";

cout << setw(15) << left << fixed << setprecision(2) << tp << endl;

cout << setw(15) << left << "TAX";

cout << setw(15) << left << fixed << setprecision(2) << taxrate << endl;

double ttp = tp + 0.0875 * tp;

cout << setw(15) << left << "Total";

cout << setw(15) << left << fixed << setprecision(2) << ttp << endl;

return 0;

}

Answer:

Explanation:

Check the file attached below to see the diagram that is drawn for the question being answered

Answer:

4

Explanation:

For easier management of the host records of the company 4 zones should be used because

subdomain is part of a larger domain and the main domain which is the primary domain is the name which the company have decide to use which will represent the company website address and in a situation where the company

have different domain names in which they had registered, they will need to choose one among the domain which will inturn be their main domain.

Therefore for easier , efficient and effective management of the host records 4 zones will be the best zones to be used.

Example of sub domain is north.example.com

For easier management of the host records, 4 zones should be used

Host record or a DNS host, is simply known as record in one's domain's DNS zone file that is said to create the connection between one's domain and its matching IP address.

It is also called an A or Address record. It is said to links a domain to the physical IP address of a computer hosting that has the domain's services.

4 zones in the subdomain is good because a subdomain is part of a larger domain and the main domain and therefore having four will cater for all.

Its gives a creative approach to the management of DNS, DHCP, and IPAM data.

Conclusively, the use of host records helps to manage multiple DNS records, DHCP and IPAM data.

Learn more from

https://brainly.com/question/19281141

Answer:

A program was written in C++ that allows the user to play the game of Rock, Paper, Scissors against the computer.

Explanation:

Solution

C++ CODE:

#include<iostream>

#include <locale>

#include<string>

#include<cstdlib>

#include<time.h>

using namespace std;

int play(int user,int cpu){  

 return(user - cpu);   //here is just substracting and returning the value entered by user and cpu  

}  

void display(int choice){   //to display the choices entered by user or cpu  

 if(choice == 1){    //1 for Rock  

     cout<<"Rock"<<endl;  

 }else if(choice == 2){    //2 for Paper  

     cout<<"Paper"<<endl;  

 }else{       //3 for Scissors  

     cout<<"Scissors"<<endl;  

 }  

}  

void winner(int win){  

 if(win == 0){       //if user and cpu entered same value

     cout<<"A game is a draw."<<endl;  

 }else if(win == 1){   //if user entered Paper and cpu entered Rock or if user entered Scissors and cpu entered Paper  

     cout<<"Hurray You won."<<endl;

 }else if(win == -1){   //if user entered Rock and cpu entered Paper or if user entered Paper and cpu entered Scissors  

     cout<<"CPU won."<<endl;  

 }else if(win == 2){        //if user entered Scissors and cpu entered Rock  

     cout<<"CPU won."<<endl;  

 }else if(win == -2){       //if user entered Rock and cpu entered Scissors  

     cout<<"Hurray You won."<<endl;  

 }  

}  

int cpu_choice(){

 srand (time(NULL));    //this function is to generate random from time to time  

 int cpu = 1000;  

 while(cpu > 3){   //to generate random number between 1 to 3  

     cpu = (rand() % cpu) +1;  

 }  

 return cpu;  

}  

int main(){  

 int choice=0,cpu=0,win=0;  

 locale loc;  

 string ch;  

 cout<<"Enter your choice :"<<endl;  

 cout<<"1. Rock\n2. Paper\n3. Scissors"<<endl<<"\t";

 cin>>ch;ch[0] = toupper(ch[0],loc); //converting the first element to char if by misktake the user have entered lower case  

 if(ch.compare("Rock") == 0 || ch.compare("Paper") == 0 || ch.compare("Scissors") == 0){ //if choice is correct  

     cout<<"You: "<<ch<<endl; //display the choice entered by the user

     if(ch[0] == 'r' || ch[0] == 'R') choice = 1; //if the user enter rock or Rock  

     else if(ch[0] == 'p' || ch[0] == 'P') choice = 2; //if the user enter paper or Paper  

     else if(ch[0] == 's' || ch[0] == 'S') choice = 3; //if the user enter scissors or Scissors  

     cout<<"CPU: ";  

     cpu = cpu_choice(); //get cpu choice

     display(cpu); //display the choice entered by the cpu using the random number

     win = play(choice,cpu); //call the function to play the game and returns the winner

     winner(win); //display the winner

 }else{ //if entered choice is wrong

     cout<<"wrong choice!"<<endl;

 }  

 return 0;  

}

Answer:

Salesforce Marketing Cloud.

Explanation:

Exact Target was founded by Peter McCormick, Chris Baggott and Scott Dorsey on the 15th of December, 2000 in Indianapolis, Indiana, United States of America and was later acquired by Salesforce in the year 2013 for $2.5 billion. Salesforce in turn converted Exact Target to Salesforce Marketing Cloud in the year 2014.

The Salesforce Marketing Cloud is a company that provide services such as digital marketing automation and analytics software. Salesforce Marketing Cloud softwares are sold primarily on a multi-year subscription basis and based on number of users, features enabled, and level of customer service. It is a hosted, online subscription model that provides users with services such as, consulting, mobile, implementation, email, social and digital marketing.

Answer:

5, 10 and 16

Explanation:

The sum of their ages is √961 = 31

If Joe is x years old, the equation that follows is:

x + (x+5) + (x+5+6) = 31

This simplifies to

3x = 31 - 11 - 5 = 15

so x=5

From that you can find

Joe = x = 5

Kate = x+5 = 10

Jody = x+5+6 = 16

Answer:

FALSE

Explanation:

Answer:

A code was created to single list that contains the following collection of data in the order provided

Explanation:

Solution

#list that stores employee numbers

employeee_numbers=[1121,1122,1127,1132,1137,1138,1152,1157]

#list that stores employee names

employee_name=["Jackie Grainger","Jignesh Thrakkar","Dion Green","Jacob Gerber","Sarah Sanderson","Brandon Heck","David Toma","Charles King"]

#list that stores wages per hour employee

hourly_rate=[22.22,25.25,28.75,24.32,23.45,25.84,22.65,23.75]

#list that stores salary employee

company_raises=[]

max_value=0

#list used to store total_hourly_rate

total_hourly_rate=[]

underpaid_salaries=[]

#loop used to musltiply values in hourly_wages with 1.3

#and store in new list called total_hourly_rate

#len() is used to get length of list

for i in range(0,len(hourly_rate)):

#append value to the list total_hourly_rate

total_hourly_rate.append(hourly_rate[i]*1.3)

for i in range(0,len(total_hourly_rate)):

#finds the maximum value

if(total_hourly_rate[i]>max_value):

max_value=total_hourly_rate[i] #stores the maximum value

if(max_value>37.30):

print("\nSomeone's salary may be a budget concern.\n")

for i in range(0,len(total_hourly_rate)):

#check anyone's total_hourly_rate is between 28.15 and 30.65

if(total_hourly_rate[i]>=28.15 and total_hourly_rate[i]<=28.15):

underpaid_salaries.append(total_hourly_rate[i])

for i in range(0,len(hourly_rate)):

#check anyone's hourly_rate is between 22 and 24

if(hourly_rate[i]>22 and hourly_rate[i]<24):

#adding 5%

hourly_rate[i]+=((hourly_rate[i]/100)*5)

elif(hourly_rate[i]>24 and hourly_rate[i]<26):

#adding 4%

hourly_rate[i]+=((hourly_rate[i]/100)*4)

elif(hourly_rate[i]>26 and hourly_rate[i]<28):

#adding 3%

hourly_rate[i]+=((hourly_rate[i]/100)*3)

else:

#adding 2% for all other salaries

hourly_rate[i]+=((hourly_rate[i]/100)*2)

#adding all raised value to company_raises

company_raises.extend(hourly_rate)

#The comparison in single line

for i in range(0,len(hourly_rate)):

 For this exercise i used ternary

operator hourly_rate[i]= (hourly_rate[i]+((hourly_rate[i]/100)*5)) if (hourly_rate[i]>22 and hourly_rate[i]<24) else (hourly_rate[i]+((hourly_rate[i]/100)*4)) if (hourly_rate[i]>24 and hourly_rate[i]<26) else hourly_rate[i]+((hourly_rate[i]/100)*2)

Answer:

The queries for each question are explained.

1. Find the sids and snames of students who took "Database" course (i.e., cname = ‘Database’) in Fall 2019.

 The columns sid and sname are taken from students table.

The course name belong to the courses table.

The semester and year belong to the grades table.

To get the final query, all these tables need to be joined in the FROM clause using JOIN ON keywords.

select s.sid, sname

from students s join grades g on g.sid = s.sid

join courses c on g.cid = c.cid

where cname like 'database%'

and semester like 'Fall'

and year=2019

2. Find the average grade of all the students who took "CS327" (i.e., cid=‘CS327’) in Fall 2019. You can assume grade is a numerical attribute.

The grade column is taken from grades table.

The course id belongs to the grades table.

The semester and year also belong to the grades table.

The final query is formed using the grades table only.

 select avg(grade)

from grades

where cid like 'CS327'

and semester like 'Fall'

and year=2019

 3. Find the number of distinct courses offered by each department in Fall 2019.

 The department id belongs to the courses table.

The course id belongs to the grades table.

The semester and year also belong to the grades table.

To get the final query, the courses and the grades tables are joined in the FROM clause using JOIN ON keywords.

select dept_id, count(distinct g.cid)

from courses c join grades g on c.cid = g.cid

where semester like 'Fall'

and year=2019

group by dept_id