Determine whether the statement is always, sometimes, or never true.
If △JKL ≅ △MNP, then m∠L = m∠N.
Complete the explanation of your reasoning.
The statement is always/ sometimes/ never true.
∠L corresponds to ∠P.
By [CPCTC/ Triangle Sum Theorem/ SAS Triangle Congruence Theorem], ∠L ≅∠P.
If ∠P ≅∠N, then ∠L [≅/≇ ] ∠N by [CPCTC/ Triangle Sum Theorem/ SAS Triangle Congruence Theorem], ∠L ≅∠P.
and m∠L [≅/≇ ] m∠N.
Please help this is on HMH I will give Brainliest if it's right! :)
Answers
Answer:
I am pretty sure the correct answer is never true
Step-by-step explanation:
This is because when,
Δ JKL ≅ Δ MNP
Then, ∠J ≅ ∠M
∠K ≅ ∠N
∠L ≅ ∠P
so ∠L ≠ ∠N
i hope this is right haha
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At Chrissy's Clothes Warehouse, it takes fraction 2 over 5 of a day to complete fraction 1 over 10 of an order of t-shirts. At this rate, how long will it take to complete the entire order of t-shirts?
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Step-by-step explanation:
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Step-by-step explanation:
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A. 3 1/3Step-by-step explanation:
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t = 2, u = -2/3, v = - 1, w = - 1/3Find:
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Answers
Answer:
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Step-by-step explanation:
We can immediately rule out B and C; they are odd numbers while S is an even number.
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Answers
Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Step-by-step explanation:
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Answer:
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Answer:
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Answer:
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Answers
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Answers
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Answers
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Please mark brainliest
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Answers
Answer:
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NO LINKS PLEASE
Answers
2(1)-2y=-2
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Step-by-step explanation:
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Help now please now 50 points and brainliest
Answers
Answer:
F=(9C+160)/5
Step-by-step explanation:
C=5(F-32)/9
Simplify to 5F-160/9=c
multiply by 9 on both sides : 5F-160=9C
add 160 to both sides: 5F=9C+160
Divide by 5 on both sides: F=(9C+160)/5
Simplify: F=9/5c+32
Answer:
[tex]F=\frac{9C}{5}+32[/tex]
Step-by-step explanation:
The subject of the formula is the variable that's being worked out. Originally this was C. They want us to make F the subject of the formula.
[tex]c=\frac{5(F-32)}{9}[/tex]
To do this we first need to distribute 5.
[tex]C=\frac{5F-160}{9}[/tex]
Divide 5F-160 by 9.
[tex]C=\frac{5}{9}f-\frac{160}{9}[/tex]
We can then swap sides to make it easier.
[tex]\frac{5}{9}f-\frac{160}{9}=C[/tex]
We then add [tex]\frac{160}{9}[/tex] to each side.
[tex]\frac{5}{9}f=c+\frac{160}{9}[/tex]
We can then find F by multiplying by 9/5 or dividing by 5/9.
[tex]F=\frac{9}{5}(C+160/9)[/tex]
We then can simplify by multiplying.
[tex]F=\frac{9C}{5}+32[/tex]
:D