Answer:
The provided statement is False.
Step-by-step explanation:
The assumptions to perform a test of independence are:
The sample selected is randomA large sample is selectedThe observations are independent of each otherThe observations follow the same distribution.It is not necessary that the parent population or the population from which the sample is collected is normally distributed.
Thus, the provided statement is False.
janice published a novel. Last month the book sold 1364 copies, earning Janice a total of $1579.16. This month the book sold 1347 copies. How much should Janice expect to receive in royalties this month?
[tex]\$1562.52[/tex]
Unitary MethodThe unitary method is a methodology for solving problems that involves first determining the value of a single unit and then multiplying that value by the required value. The unitary method is used to calculate the value of a single unit from a given multiple.
Number of books sold last month [tex]=1364[/tex]
Total amount earned [tex]=\$1579.16[/tex]
So,
Price of each book [tex]=\frac{1579.16}{1364}[/tex]
[tex]=\$1.16[/tex]
Number of books sold this month [tex]=1347[/tex]
Total amount earned [tex]=1.16\times 1347[/tex]
[tex]=\boldsymbol{\$1562.52}[/tex]
Find out more information about unitary method here:
https://brainly.com/question/12116123?referrer=searchResults
A bag contains two six-sided dice: one red, one green. The red die has faces numbered 1, 2, 3, 4, 5, and 6. The green die has faces numbered 1, 2, 3, 4, 4, and 4. A die is selected at random and rolled four times. You are told that two rolls were 1's and two were 4's. Find the probability the die chosen was green.
Answer:
The probability the die chosen was green is 0.9
Step-by-step explanation:
From the information given :
A bag contains two six-sided dice: one red, one green. The red die has faces numbered 1, 2, 3, 4, 5, and 6. The green die has faces numbered 1, 2, 3, 4, 4, and 4.
SO, the probability of obtaining 4 in a single throw of a fair die is:
P (4 | red dice) = [tex]\dfrac{1}{6}[/tex]
P (4 | green dice) = [tex]\dfrac{3}{6}= \dfrac{1}{2}[/tex]
A die is selected at random and rolled four times.
When the die is selected randomly; the probability of the first die must be equal to the probability of the second die = [tex]\dfrac{1}{2}[/tex]
The probability of two 1's and two 4's in the first dice can be calculated as:
[tex]= \begin {pmatrix} \left\begin{array}{c}4\\2 \end{array}\right \end {pmatrix} \times \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} ^4[/tex]
[tex]=\dfrac{4!}{2!(4-2)!}\times (\dfrac{1}{6})^4[/tex]
[tex]=\dfrac{4!}{2!(2)!}\times (\dfrac{1}{6})^4[/tex]
[tex]=\dfrac{4\times 3 \times 2!}{2!(2)!}\times (\dfrac{1}{6})^4[/tex]
[tex]=\dfrac{12}{2 \times 1}\times (\dfrac{1}{6})^4[/tex]
[tex]= 6 \times (\dfrac{1}{6})^4[/tex]
[tex]= (\dfrac{1}{6})^3[/tex]
[tex]= \dfrac{1}{216}[/tex]
The probability of two 1's and two 4's in the second dice can be calculated as:
[tex]= \begin {pmatrix} \left\begin{array}{c}4\\2 \end{array}\right \end {pmatrix} \times \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} ^2 \times \begin {pmatrix} \dfrac{3}{6} \end {pmatrix} ^2[/tex]
[tex]= \dfrac{4!}{2!(4-2)!} \times \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} ^2 \times \begin {pmatrix} \dfrac{3}{6} \end {pmatrix} ^2[/tex]
[tex]= \dfrac{4!}{2!(2)!} \times \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} ^2 \times \begin {pmatrix} \dfrac{3}{6} \end {pmatrix} ^2[/tex]
[tex]= 6 \times \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} ^2 \times \begin {pmatrix} \dfrac{3}{6} \end {pmatrix} ^2[/tex]
[tex]= \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} \times \begin {pmatrix} \dfrac{3}{6} \end {pmatrix} ^2[/tex]
[tex]= \dfrac{9}{216}[/tex]
∴ The probability of two 1's and two 4's in both dies
= P( two 1s and two 4s | first dice ) P( first dice ) + P( two 1s and two 4s | second dice ) P( second dice )
The probability of two 1's and two 4's = [tex](\dfrac{1}{216} \times \dfrac{1}{2} )+ ( \dfrac{9}{216} \times \dfrac{1}{2})[/tex]
The probability of two 1's and two 4's = [tex]\dfrac{1}{432}+ \dfrac{1}{48}[/tex]
The probability of two 1's and two 4's = [tex]\dfrac{5}{216}[/tex]
Using Bayes Theorem; the probability that the die was green can be computed as follows:
P(second die (green) | two 1's and two 4's ) = The probability of two 1's and two 4's | second dice)P (second die) ÷ P(two 1's and two 4's)
P(second die (green) | two 1's and two 4's ) = [tex]\dfrac{\dfrac{1}{2} \times \dfrac{9}{216} }{\dfrac{5}{216}}[/tex]
P(second die (green) | two 1's and two 4's ) = [tex]\dfrac{\dfrac{1}{48} }{\dfrac{5}{216}}[/tex]
P(second die (green) | two 1's and two 4's ) =[tex]\dfrac{1}{48} \times \dfrac{216}{5 }[/tex]
P(second die (green) | two 1's and two 4's ) = [tex]\dfrac{9}{10}[/tex]
P(second die (green) | two 1's and two 4's ) = 0.9
∴
The probability the die chosen was green is 0.9
A teacher covered the exterior of a rectangular prism-shaped box that measured 8 inches by 9 inches by 10 inches using one sheet of. ... by 9 inches by 10 inches using one sheet of rectangular-shaped wrapping paper that measured 2 feet by 3 feet. ... How many square inches of wrapping paper were left over?
Answer:
380 square inches
Step-by-step explanation:
Step 1
We find the Surface Area of the Rectangular Prism
The Rectangular Prism has the dimensions of Length × Width × Height = 8 inches by 9 inches by 10 inches
Surface Area of a Rectangular Prism = 2(WL+ HL + HW)
Where W = Width = 9 inches
L = Length = 8 inches
H = Height = 10 inches
Surface Area of the Rectangular Prism = 2(9 × 8 + 10 × 8 + 9 × 10)
= 2(72 + 80 + 90)
= 2(242)
= 484 square inches.
Step 2
Find the area of the Rectangular shaped wrapping paper
The wrapping paper has dimensions :
2 feet by 3 feet
We have to convert to inches first
1 foot = 12 inches
2 feet = 2 × 12 inches = 24 inches
3 feet = 3 × 12 inches = 36 inches
Area of the Rectangular shaped wrapping paper = Length × Width
= 24 inches × 36 inches
= 864 square inches
Step 3
We calculate the amount of square inches of wrapping paper left.
The Amount left over = Area of Rectangular wrapping paper - Area of Rectangular prism
= 864 square inches - 484 square inches
= 380 square inches.
Therefore, the square inches of wrapping paper left over is 380 square inches.
A bag contains 4 red marbles, 6 blue marbles, and 7 green marbles. What is the probability of choosing a blue marble when one marble is drawn?
Answer:
Probabilty of selecting a blue marble if one marble is drawn
= 0.3529
Step-by-step explanation:
A bag contains 4 red marbles, 6 blue marbles, and 7 green marble.
Total number of marbles
=4 red+ 6 blue+7 green
= 17 marbles in total
Probabilty of selecting a blue marble if one marble is drawn
= Number of blue marble/total number of marble
Probabilty of selecting a blue marble if one marble is drawn
= 6/17
Probabilty of selecting a blue marble if one marble is drawn
= 0.3529
cos2A is equivalent to: A. sin2A−cos2A B. sin2A+cos2A C. cos2A−sin2A D. cosA−sinA
Answer:
C. [tex]cos^2A -sin^2A[/tex]
Step-by-step explanation:
Given:
[tex]cos2A[/tex]
To find:
The given expression is equivalent to:
A. [tex]sin^2A-cos^2A[/tex]
B. [tex]sin^2A+cos^2A[/tex]
C. [tex]cos^2A -sin^2A[/tex]
D. [tex]cosA-sinA[/tex]
Solution/Proof:
First of all, let us have a look at the compound angle formula for [tex]cos(X+Y)[/tex].
Compound angle means in which there is sum of two angles given.
In the above we are having X+Y i.e. sum of two angles X and Y. So it is compound angle.
The compound angle formula for cosine is given as:
[tex]\bold{cos(X+Y)=cosXcosY-sinXsinY}[/tex]
Here, let us put X = Y = A
[tex]cos(A+A)=cosAcosA-sinAsinA\\\Rightarrow \bold{cos(2A)=cos^2A-sin^2A}[/tex]
So, cos2A is equivalent to [tex]cos^2A -sin^2A[/tex].
Correct answer is:
Option C. [tex]cos^2A -sin^2A[/tex]
Let E1 be the event that tails come up when the coin is tossed the first time and E2 be the event that heads come up when the coin is tossed the second time. Drag the probability values from the right column and drop them in the corresponding events in the left column.
Answer:
Step-by-step explanation:
In the tossing of a fair coin, there are equal probabilities of getting a HEAD and getting a TAIL.
Total probability is always 1 and a coin has 2 faces - Head & Tail.
The probability of getting a Head is 1/2 = 0.5
The probability of getting a Tail is 1/2 = 0.5
E1 is the event that TAIL comes up when the coin is tossed the first time
E2 is the event that HEAD comes up when the coin is tossed the second time
The probability value for EVENT 1 is 0.5
The probability value for EVENT 2 is 0.5
pt 3 1-7 pleaseeee helpp
Answer:
-2s is ur answer
hope it helps u
Answer:
Step-by-step explanation:
2s+(−4s)
Combine 2s and −4s to get −2s.
−2s
Help plzdont get this
Answer:
$3.
Step-by-step explanation:
All you have to do is 9/3 = 3.
A set of numbers is transformed by taking the log base 10 of each number. The mean of the transformed data is 1.65. What is the geometric mean of the untransformed data?
Answer:
Step-by-step explanation:
Given that:
A set of numbers is transformed by taking the log base 10 of each number. The mean of the transformed data is 1.65. What is the geometric mean of the untransformed data.
To obtain the geometric mean of the untransformed data,
X = set of numbers
N = number of observations
Arithmetic mean if transformed data = 1.65
Log(Xi).... = transformed data
Arithmetic mean = transformed data/ N
Log(Xi) / N = 1.65
(Πx)^(1/N), we obtain the antilog of the aritmétic mean simply by raising 10 to the power of the Arithmetic mean of the transformed data.
10^1.65 = 44.668359
Find the surface area of the pyramid shown to the nearest whole number.
6 ft
5 ft
5 ft
Not drawn to scale
a. 85 A
b. 145 ft
c. 60 i
d. 25 ft
Answer:
The answer is option AStep-by-step explanation:
Surface area of a pyramid =
area of base + area of triangular faces
Since it's a square based pyramid
It's surface area is
area of base + 4( area of one triangular face)
Since the square has equal sides
For square base
Area of a square = l²
where l is the length
From the question l = 5
So we have
Area of square base = 5² = 25ft²
For one of the triangular face
Area of a triangle = ½ × base × height
base = 5
height = 6
Area = ½ × 5 × 6 = 15ft²
So the surface area of the pyramid is
25 + 4(15)
= 25 + 60
We have the final answer as
Surface area = 85 ft²Hope this helps you
A bakery makes 270 scones and 300 muffins each morning. What is the ratio of muffins to scones in simplest form?
Answer: 9 : 10 or 9/10.
Step-by-step explanation:
The ratio of muffins to scones is 300 : 270. Now to reduce it to the lowest term divide each by 30.
You will then get 9: 10
find the perimeter of the garden that has the side length of 4.3m, 8.7m and 10m
Simplify the algebraic expression 3+6(−9w+7)
Answer:
[tex] \boxed{ \bold{ \huge{\boxed{ \sf{ - 54w + 45}}}}}[/tex]
Step-by-step explanation:
[tex] \sf{3 + 6( - 9w + 7)}[/tex]
Distribute 6 through the parentheses
⇒[tex] \sf{3 - 54w + 42}[/tex]
Add the numbers : 42 and 3
⇒[tex] \sf{ - 54w + 45}[/tex]
Hope I helped!
Best regards!!
The volume of a sphere is 36ft. What is the radius
Answer:
r≈2.05
Step-by-step explanation:
Answer:3
Step-by-step explanation:
Rewrite in simplest terms: -2(5d-9f)+7f-10(-9f-7d)−2(5d−9f)+7f−10(−9f−7d)
Answer:
= 5 ( 12d + 23f )
Step-by-step explanation:
-2(5d-9f)+7f-10(-9f-7d)
Open parenthesis
= -10d + 18f + 7f + 90f + 70d
Collect like terms
= -10d + 70d + 18f + 7f + 90f
= 60d + 115f
Factorise
= 5 ( 12d + 23f )
Therefore,
-2(5d-9f)+7f-10(-9f-7d) in its simplest form is 5 ( 12d + 23f )
Find the slope of the line that contains the points (4,2) and (7,-4)*
Answer:
-2
Step-by-step explanation:
To find the slope of the line you have to use the equation,
(y2-y1)/(x2-x1)
In this case it is, (-4-2)/7-4)
This simplifies to -2 and this is the slope of the line
Answer:
-8/5
hope this help!
Which of the following equations shows the correct way to apply the Commutative Property of Addition?
Answer:
Commutative Property of Addition: a + b = b + a
Step-by-step explanation:
The Commutative Property of Addition implies that even on changing the order of addition the final result (i.e. the sum) remains the same.
Consider the addition of two numbers, say a and b:a + b = b + a
Suppose a = 5 and b = 6, then:
a + b = 5 + 6 = 11
b + a = 6 + 5 = 11.
Thus, a + b = b + a.
Consider the addition of three numbers, say a, b and c:a + b + c= a + c + b = b + a + c = c + a + b
Suppose a = 4, b = 3 and c = 6, then:
a + b + c = 4 + 3 + 6 = 13
a + c + b = 4 + 6 + 3 = 13
b + a + c = 3 + 4 + 6 = 13
c + a + b = 6 + 4 + 3 = 13.
Thus, a + b + c= a + c + b = b + a + c = c + a + b.
solve by completing the square. 4x²-8x-32=0
Answer:
4, -2
Step-by-step explanation:
Hello, please consider the following.
[tex]\begin{aligned}4x^2-8x-32=0 &\text{ ***We divide by 4.***}\\\\x^2-2x-8=0 &\text{ ***We complete the square. ***}\\\\(x-1)^2-1-8=(x-1)^2-9=0 &\text{ ***We move the constant to the right.***}\\\\(x-1)^2=9=3^2 &\text{ ***We take the root.***}\\\\x-1=\pm3 &\text{ ***We add 1.***}\\\\x=1+3=\boxed{4} \ & or \ x=1-3=\boxed{-2}\end{aligned}[/tex]
Thanks
Combine the like terms to create an equivalent expression. \large{7n+4n}7n+4n
Answer:
11n
Step-by-step explanation:
The expression is 7n + 4n. Since 7n and 4n are like terms (they both are variables with n), we can combine them so the expression becomes 7n + 4n = 11n.
Using the cross multiplication method, which of the following is the solution to 21/(x+4) = 7/(x+2)?
Answer:
Step-by-step explanation:
Hello !
Using the cross multiplication method, which of the following is the solution to 21/(x+4) = 7/(x+2)?
21(x + 2) = 7(x + 4)
21x + 42 = 7x + 28
21x - 7x = 28 - 42
14x = -14
x = -14/14
x = -1
Answer:
3/(x+2)= x+1
Step-by-step explanation:
21/7=3
x/x= x
4/2=2
Represent the following sentence as an algebraic expression, where "a number" is the
letter x.
Twice a number.
Answer:
[tex]x = 2a[/tex]
Step-by-step explanation:
Required
Represent twice a number is x as an algebra
Given that the number is a;
Then
[tex]Twice\ a\ number = 2 * a[/tex]
[tex]Twice\ a\ number = 2a[/tex]
Also,
[tex]Twice\ a\ number = x[/tex]
So, we have that
[tex]x = 2a[/tex]
Hence, the algebraic representation of the given parameters is
[tex]x = 2a[/tex]
i need help with this can someone help me
Answer:
a. 7(3) - 20 = 1°
b. 9 cm
c. Aly is correct
Step-by-step explanation:
Answer:
a. ZWY
b. 9cm
c. Aly's solution is correct
Step-by-step explanation:
a. YW bisects the whole angle, thus angle XWY and angle ZWY are same
NOTE: REMEMBER TO WRITE THE LETTER ACCORDINGLY
b. the two triangles are congruent by AAS (angle-angle-side) thus the two legs of the the triangles are also congruent. when one is 9cm, the other is also 9cm.
c. Since the triangles are congruent, their sides also congruent.
7x-20=2x-5
7x-2x=-5+20
5x=15
x=3
This is same as Aly's solution
On the first part of her trip Natalie rode her bike 16 miles and on the second part of the trip she rode her bike 42 miles. Her average speed during the second part of the trip was 6 mph faster than her average speed on the first part of the trip. Find her average speed for the second part of the trip if the total time for the trip was 5 hours.
Answer:
14 mph ( average speed during the second part of the trip )
Step-by-step explanation:
Let´s call "x" the average speed during the first part then
t = 5 hours
t = t₁ + t₂ t₁ and t₂ times during part 1 and 2 respectively
l = t*v ( distance is speed by time ) t = l/v
First part
t₁ = 16/x and t₂ = 42 / ( x + 6)
Then
t = 5 = 16/x + 42 /(x + 6)
5 = [ 16 * ( x + 6 ) + 42 * x ] / x* ( x + 6 )
5 *x * ( x + 6 ) = 16*x + 96 + 42 x
5*x² + 30*x - 58*x - 96 = 0
5*x² - 28*x - 96 = 0
We obtained a second degree equation, we will solve for x and dismiss any negative root since negative time has not sense
x₁,₂ = [28 ± √ (28)² + 1920 ] / 10
x₁,₂ = ( 28 ± √2704 )/ 10
x₁ = 28 - 52 /10 we dismiss that root
x₂ = 80/10
x₂ = 8 mph average speed during the first part, and the average speed in the second part was 6 more miles than in the firsst part. then the average spedd dring the scond part was 8 + 6 = 14 mph
2. (04.01) Which point could be removed in order to make the relation a function? (4 points) {(-9, -8), (-8, 4), (0, -2), (4, 8), (0, 8), (1, 2)} O (4,8) O (0,8) O (-9, -8) O (1,2)
Answer:
We are given order pairs (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}.
We need to remove in order to make the relation a function.
Step-by-step explanation:
Note: A relation is a function only if there is no any duplicate value of x coordinate for different values of y's of the given relation.
In the given order pairs, we can see that (0, –2) and (0, 8) order pairs has same x-coordinate 0.
So, we need to remove any one (0, –2) or (0, 8) to make the relation a function. hope this helps you :) god loves you :)
A survey of over 25,000 Americans aged between 18 and 24 years revealed the following: 88.1% of the 12,678 females and 84.9% of the 12,460 males had high school diplomas.
a) Do the data suggest that females are more likely to graduate from high school than males? Test at a significance level of 5%.
b) Set-up a 95% confidence interval for the difference in the graduation rates between females and males.
c) State the assumptions and conditions necessary for the above inferences to hold.
Answer:
(a) Yes, the data suggest that females are more likely to graduate from high school than males.
(b) A 95% confidence interval for the difference in the graduation rates between females and males is [0.024, 0.404] .
Step-by-step explanation:
We are given that a survey of over 25,000 Americans aged between 18 and 24 years revealed the following: 88.1% of the 12,678 females and 84.9% of the 12,460 males had high school diplomas.
Let [tex]p_1[/tex] = population proportion of females who had high school diplomas.
[tex]p_2[/tex] = population proportion of males who had high school diplomas.
(a) So, Null Hypothesis, [tex]H_0[/tex] : [tex]p_1\leq p_2[/tex] {means that females are less or equally likely to graduate from high school than males}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]p_1 > p_2[/tex] {means that females are more likely to graduate from high school than males}
The test statistics that will be used here is Two-sample z-test statistics for proportions;
T.S. = ~ N(0,1)
where, [tex]\hat p_1[/tex] = sample proportion of females having high school diplomas = 88.1%
[tex]\hat p_2[/tex] = sample proportion of males having high school diplomas = 84.9%
[tex]n_1[/tex] = sample of females = 12,678
= sample of males = 12,460
So, the test statistics =
= 7.428
The value of the standardized z-test statistic is 7.428.
Now, at a 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.
Since the value of our test statistics is more than the critical value of z as 7.428 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.
Therefore, we conclude that females are more likely to graduate from high school than males.
(b) Firstly, the pivotal quantity for finding the confidence interval for the difference in population proportion is given by;
P.Q. = [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] ~ N(0,1)
where, [tex]\hat p_1[/tex] = sample proportion of females having high school diplomas = 88.1%
[tex]\hat p_2[/tex] = sample proportion of males having high school diplomas = 84.9%
[tex]n_1[/tex] = sample of females = 12,678
[tex]n_2[/tex] = sample of males = 12,460
Here for constructing a 95% confidence interval we have used a Two-sample z-test statistics for proportions.
So, 95% confidence interval for the difference in population proportions, ([tex]p_1-p_2[/tex]) is;
P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level
of significance are -1.96 & 1.96}
P(-1.96 < [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] < 1.96) = 0.95
P( [tex]-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] < [tex]{(\hat p_1-\hat p_2)-(p_1-p_2)}[/tex] < [tex]1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] ) = 0.95
P( [tex](\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] < ([tex]p_1-p_2[/tex]) < [tex](\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] ) = 0.95
95% confidence interval for ([tex]p_1-p_2[/tex]) = [[tex](\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] , [tex](\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}} }[/tex] ]
= [ [tex](0.881-0.849)-1.96 \times {\sqrt{\frac{0.881(1-0.881)}{12,678}+\frac{0.849(1-0.849)}{12,460}} }[/tex] , [tex](0.881-0.849)+1.96 \times {\sqrt{\frac{0.881(1-0.881)}{12,678}+\frac{0.849(1-0.849)}{12,460}} }[/tex] ]
= [0.024, 0.404]
Therefore, a 95% confidence interval for the difference in the graduation rates between females and males is [0.024, 0.404] .
(c) The assumptions and conditions necessary for the above inferences to hold are;
The data must follow the normal distribution.The sample must be taken from the population data only or the sample represents the population data.exponents and power - simplify and express the result with positive index
I hope u will get help frm it.....
Find f. (Use C for the constant of the first antiderivative, D for the constant of the second antiderivative and E for the constant of the third antiderivative.)
f '''(t) = (t)^1/2 − 9 cos(t)
f(t) = _______.
You just need to integrate 3 times:
[tex]f'''(t)=t^{1/2}-9\cos t[/tex]
[tex]f''(t)=\displaystyle\int f'''(t)\,\mathrm dt=\frac23 t^{3/2}-9\sin t+C[/tex]
[tex]f'(t)=\displaystyle\int f''(t)\,\mathrm dt=\frac4{15} t^{5/2}+9\cos t+Ct+D[/tex]
[tex]f(t)=\displaystyle\int f'(t)\,\mathrm dt=\frac8{105} t^{7/2}+9\sin t+\frac C2 t^2+Dt+E[/tex]
who was the second president in Republican of the congo?
please I need you answer
Answer: Joseph Kabila
Step-by-step explanation:
Answer:
Joseph Kabila
Step-by-step explanation:
WHAT IS THE EQUATION FOR INVERSE PROPORTION?
Answer: Hi!
The equation for inverse proportion is x y = k or x = k/ y.
When finding the value of the constant k, you can use the known values and then use this formula to calculate all of the unknown values.
Hope this helps!
can someone pls help me.. thanks <3 Factor 15x^2y^2-3x^3y+75x^4 Show your work.
Answer:
3(x^y(5x^2y-x³)+25x⁴))
Step-by-step explanation:
15x^2y²-3x^3y+75x⁴
From 15x^2y²-3x^3y only, 3x^y is the common factor
=> 3x^y(5x^2y-x³)+75x⁴
Taking the common factor of the latter expression, 3 shows to be the common factor of all the expression.
=> 3(x^y(5x^2y-x³)+25x⁴)