Determine whether or not the mixing of each of the two solutions indicated below will result in a buffer.
A. 75.0 mL of 0.10 MHF; 55.0 mL of 0.15 MNaF
B. 150.0 mL of 0.10 MHF; 135.0 mL of 0.175 MHCl
C. 165.0 mL of 0.10 MHF; 135.0 mL of 0.050 MKOH
D. 125.0 mL of 0.15 M CH3NH2; 120.0 mL of 0.25 MCH3NH3Cl
E. 105.0 mL of 0.15 M CH3NH2; 95.0 mL of 0.10 M HCl

Answer:

Choice d. No effect will be observed as long as other factors (temperature, in particular) are unchanged.

Explanation:

The equilibrium constant of a reaction does not depend on the pressure. For this particular reaction, the equilibrium quotient is:

[tex]Q = \displaystyle \frac{[\mathrm{SO_2\, (g)}]}{[\mathrm{O_2\, (g)}]}[/tex].

Note that the two sides of this balanced equation contain an equal number of gaseous particles. Indeed, both [tex][\mathrm{SO_2\, (g)}][/tex] and [tex][\mathrm{O_2\, (g)}][/tex] will increase if the pressure is increased through compression. However, because [tex]\rm SO_2\, (g)[/tex] and [tex]\rm O_2\, (g)[/tex] have the same coefficients in the equation, their concentrations are raised to the same power in the equilibrium quotient [tex]Q[/tex].

As a result, the increase in pressure will have no impact on the value of [tex]Q\![/tex]. If the system was already at equilibrium, it will continue to be at an equilibrium even after the change to its pressure. Therefore, no overall effect on the equilibrium position should be visible.

Answer:

0.00000045 m  is the wavelength of blue light in decimal

0.00000045 m  is the wavelength of blue light in decimal without using scientific notation.

Scientific notation is defined as a way of expressing numbers which are too large or too small so that they can be easily written in decimal form. It can be referred to the scientific form or the scientific index form or even the standard form.

Base ten notation is used by scientists, engineers as it helps in simplification of arithmetic operations. It contains the significant figures which include all non-zero numbers , the zeroes between significant digits and zeroes which are needed to be significant.

In scientific notation, the base should always be ten. The exponent should be a non-zero integer and it can be either positive or negative.

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Explanation:

Efficiency of a Carnot heat engine depends on :

(D) The temperature difference between hot and cold reservoirs

A 50.3 g piece of aluminum (specific heat = 0.930 J/g･°C) will change its temperature from 23.0°C to 67.0°C while absorbing 2.06 × 10³ J of heat.

When a material absorbs heat, its temperature increases. We can calculate the amount of heat (Q) absorbed using the following expression.

[tex]Q = c \times m \times \Delta T[/tex]

where,

[tex]Q = c \times m \times \Delta T\\Q = \frac{0.930J}{g. \° C } \times 50.3 g \times (67.0 \° C - 23.0 \° C) = 2.06 \times 10^{3} J[/tex]

A 50.3 g piece of aluminum (specific heat = 0.930 J/g･°C) will change its temperature from 23.0°C to 67.0°C while absorbing 2.06 × 10³ J of heat.

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Answer:

Option (C) Bromine (Br) has more electrons, which makes its energy sublevels more negative, which pulls them closer to the positively charged nucleus.

Atomic radius is the size of the atom that measures from the center to the outermost electron.  Bromine has a smaller atomic radius because of more number of electrons. Thus, option C is correct.

The elements are placed in the periods and groups in the periodic table based on the atomic number. Bromine belongs to group 17, period 4 in the periodic table, and scandium (Sc) to group 3, period 4.

In the periodic trend, the atomic radii of the element in the period decrease when moving from left-right. Here bromine and scandium both belong to the same period but differ in the group.

The number of electrons in bromine is more than the scandium element that in turn increases the force of attraction towards the nucleus making them have smaller radii.

Therefore, bromine has smaller radii.

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Answer:

Yes, the reaction is supported by spectrochemical series.

Explanation:

When copper oxidizes with concentrated nitric acid, it produces copper ions; and the nitric acid is then reduced to nitrogen dioxide, a very poisonous gas which is brown in color and with an irritating odor.

[tex]$ Cu + 4HNO_{3} \rightarrow Cu(NO_{3})_{2} + 2NO_2+2H_2O$[/tex]

The copper ions ([tex]$Cu^{2+} $[/tex]) product which is initially coordinated to form nitrate ions from nitric acid and thus first gives the solution a green color.

Now when the solution is further diluted with water, the water molecules then displaces the nitrate ions  around the copper ions and causes the solution to change its color to blue. The reaction is -

[tex]$ 3Cu + 8HNO_3 \rightarrow 3Cu(NO_3)_2+ 2NO + 4H_2O $[/tex]

Yes, the results are supported by spectrochemical series.

Answer: 3Ag⁺ (aq) + PO₄³⁻ (aq) → Ag₃PO₄ (s)

Explanation:

The question requires us to write down the net ionic equation for the precipitation of silver phosphate from aqueous solution:________

Note that we we told to:

(Use the solubility rules provided in the OWL Preparation Page to determine the solubility of compounds.)

Answer:

From the solubility rule,

Phosphate (PO₄³⁻) and Carbonates are insoluble except for NH₄⁺ and Group1A compounds.

According to the solubility rule, the precipitation of silver phosphates and that of the net ionic equations is given thus;

3AgNO³ (aq) + K₃PO₄ (aq) → Ag₃PO₄ (s) + 3KNO₃ (aq)

while the Net ionic equation is given;

3Ag⁺ (aq) + PO₄³⁻ (aq) → Ag₃PO₄ (s)

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Answer:

Rate = k [OCl] [I]

Explanation:

OCI+r → or +CI

Experiment [OCI] M I(-M) Rate (M/s)2

1 3.48 x 10-3 5.05 x 10-3 1.34 x 10-3

2 3.48 x 10-3 1.01 x 10-2 2.68 x 10-3

3 6.97 x 10-3 5.05 x 10-3 2.68 x 10-3

4 6.97 x 10-3 1.01 x 10-2 5.36 x 10-3

The table above able shows how the rate of the reaction is affected by changes in concentrations of the reactants.

In experiments 1 and 3, the conc of iodine is constant, however the rate is doubled and so is the conc of OCl. This means that the reaction is in first order with OCl.

In experiments 3 and 4, the conc of OCl is constant, however the rate is doubled and so is the conc of lodine. This means that the reaction is in first order with I.

The rate law is given as;

Rate = k [OCl] [I]

Answer:

Mitosis results in the formation of two haploid gametes which can then combine to form a diploid daughter cell

Explanation:

Meiosis creates different cells

Answer:

During the process of meiosis, haploid cells are formed. After fertilization, the diploid number of chromosomes is restored.

Explanation:

Answer:

Option D. 400 mmHg

Explanation:

The following data were obtained from the question:

Mole of He (nHe) = 0.04 mole

Mole of Ne (nNe) = 0.06 mole

Total pressure = 10³ mmHg

Partial pressure of He =.?

Next, we shall determine the total number of mole in the reaction vessel.

This can be obtained as follow:

Mole of He (nHe) = 0.04 mole

Mole of Ne (nNe) = 0.06 mole

Total mole =?

Total mole = nHe + nNe

Total mole = 0.04 + 0.06

Total mole = 0.1

Next, we shall determine the mole fraction of He.

This can be obtained as follow:

Mole fraction = mole of gas /total mole

Mole of He (nHe) = 0.04 mole

Total mole = 0.1

Mole fraction of He =.?

Mole fraction of He = nHe/total mole

Mole fraction of He = 0.04/0.1

Mole fraction of He = 0.4

Finally, we shall determine the partial pressure of He as follow:

Partial pressure = mole fraction x total pressure

Mole fraction of He = 0.4

Total pressure = 10³ mmHg

Partial pressure of He =.?

Partial pressure of He = 0.4 x 10³

Partial pressure of He = 400 mmHg.

Therefore, the partial pressure of He is 400 mmHg.

Answer:

The correct answer is option E) "none of the above".

Explanation:

This question is missing the following information "both the atmospheric pressure and temperature decreased"; as well as the last option, which is the correct one "none of the above". In this hypothetical scenario, a ballon has reach a height were the atmospheric pressure and the the temperature decreased. However, the change in the atmospheric pressure and the temperature would have no effect on the balloon's volume. The internal balloon's temperature and pressure tends to stabilize with the external conditions, therefore, the volume its not affected by the changes described in the question.

Answer:

9.5

Explanation:

Electrophoresis is a separation technique which involves the passage and the use of electric current in separating amino acid mixtures. The positively charged protein moves to the negative electrode while the negatively charged protein moves to the positive electrode which is in accordance to the law of attraction.

Proteins however perform optimally at the right temperature and pH. Studies shows that the optimum pH to separate a mixture of lysine, arginine, and cysteine using the electrophoresis method of separation is around 9.5

Answer:  a)   [tex]_{88}^{234}\textrm{Ra}\rightarrow _{86}^{230}\textrm{Ra}+_{2}^{4}\textrm{He}[/tex]

b)  [tex]_{92}^{238}\textrm{Ra}\rightarrow _{93}^{238}\textrm{Np}+_{-1}^{0}{\beta}[/tex]

c)  [tex]_{92}^{238}\textrm{Ra}\rightarrow _{93}^{238}\textrm{Np}+_{-1}^{0}{\beta}[/tex]

 d) [tex]_{6}^{14}\textrm{C}\rightarrow _{7}^{14}\textrm{N}+_{-1}^{0}{\beta}[/tex]

e) [tex]_{12}^{24}\textrm{Mg}\rightarrow _{12}^{24}\textrm{Mg}+_{0}^{0}{\gamma}[/tex]

Explanation:

A balanced nuclear equation is one in which the atomic number and mass number remains same on both sides of the equation i.e the number of protons and neutrons remain same.

General representation of an element is given as:  

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

a) [tex]_{88}^{234}\textrm{Ra}\rightarrow _{86}^{230}\textrm{Ra}+_{2}^{4}\textrm{He}[/tex]

b)  [tex]_{92}^{238}\textrm{U}\rightarrow _{93}^{238}\textrm{Np}+_{-1}^{0}{\beta}[/tex]

c)  [tex]_{94}^{242}\textrm{Pu}\rightarrow _{92}^{238}\textrm{Ra}+_{2}^{4}\textrm{He}[/tex]

 d)   [tex]_{6}^{14}\textrm{C}\rightarrow _{7}^{14}\textrm{N}+_{-1}^{0}{\beta}[/tex]

e)   [tex]_{12}^{24}\textrm{Mg}\rightarrow _{12}^{24}\textrm{Mg}+_{0}^{0}{\gamma}[/tex]

Answer:

Sample Response: Both passive and active transport move substances into and out of the cell across the cell membrane. However, passive transport does not require the use of energy because molecules move from an area of high concentration to an area of low concentration. Active transport does require the use of energy because molecules move from an area of low concentration to an area of high concentration.

Explanation:

Active and passive transport are the two main biological processes which play an important role in providing the nutrients, oxygen, water and other essential molecules to the cells along with removing waste materials.

The active transport involves the movement of molecules across a membrane against a concentration gradient which requires energy. The passive transport is the movement of molecules or ions across the cell membrane without using energy.

The differences between active and passive transport are: Active transport is a rapid process, passive transport is a slow process. Active transport transpires in one direction whereas passive one transpires bidirectionally. Active transport requires carrier proteins and energy whereas passive one does not require both.

The similarities among them are: both transport system require concentration gradient, both helps in homeostatic regulation and allow entry and exit of ions.

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Answer:

pH = 7.0

Explanation:

The HCl reaction with KOH as follows:

HCl + KOH → H₂O + KCl

To find pH first we need to know how many moles of each reactant reacts as follows:

HCl = 0.1000L * (0.18 mol / L) = 0.018 moles HCl

KOH = 0.06667L * (0.27mol / L) = 0.018 moles KOH

That means all HCl reacts with all KOH and you will have in solution just water. The equilibrium of water is:

H₂O(l) ⇆ H⁺(aq) + OH⁻(aq)

K = 1x10⁻¹⁴ = [H⁺] [OH⁻]

As the amount of H⁺ = OH⁻:

1x10⁻¹⁴ = [H⁺]²

[H⁺] = 1x10⁻⁷M

as pH = -log [H⁺]

Answer:

This question is incomplete

Explanation:

This question is incomplete as the actual values are not provided however you can solve the question yourself if you have the actual value using the formulas below.

The formula for Molarity is

Molarity = number of moles (n) ÷ volume (in dm³ or Litre)

If number of moles is not given, to calculate for number of moles

number of moles (n) = given mass of NaOH ÷ molar mass of NaOH

Please NOTE that the volume MUST be converted to dm³ (or litre) if not provided in dm³.

The unit for Molarity is mol/dm³ or mol/L or M (molar concentration).

Average molarity = (Trial 1 + Trial 2 + Trial 3)/ 3

Answer:

D. The lone pair forces bonding atoms away from itself.

Explanation:

The lone pairs are found in the outermost shell thereby making sharing of electrons easier. Lone pairs which are found in a covalent bond creates a bond angle which makes it a determinant of the bond angle.

The lone pairs which are negatively charged repulses the bond pairs thereby creating a distortion in the shape of the molecule.

The lone pairs creates the distortion by forcing bonding atoms away from itself.

Answer:

OLA  IQESOXPJMXXXXOX{OADUOOAOOOOOSCDCSXWAXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX

Explanation:

Answer:

The correct answer is c. second order

Explanation:

In a rate law, second order means that the chemical rate is related with the reactant concentration raised to 2. For example, if the chemical equation is:

A ⇒ B

A is the reactant and it is a second order reaction, so the rate law will be:

r = [A]²

Answer:

50.0mL 0.10M NaOH

Explanation:

The chemical equation of H₂SO₄ with NaOH to reach the first equivalence point is:

H₂SO₄ + NaOH → HSO₄⁻ + Na⁺ + H₂O

Where 1 mole of the H₂SO₄ reacts per mole of NaOH

The initial moles of H₂SO₄ are:

50.0mL = 0.0500L × (0.10 mol / L) = 0.0050 moles of H₂SO₄

As 1 mole of the acid reacts per mole of NaOH, to reach the first equivalence point we need to add 0.0050 moles of NaOH. As molarity of NaOH is 0.10M, the volume that we need to add to reach 1st equivalence point is:

0.0050 moles NaOH ₓ (1L / 0.10 moles NaOH) = 0.050L NaOH 0.10M =

Answer:

Square planar.

Explanation:

Hello,

In this case, it can be demonstrated that the central atom Xenon in XeF₄ has a sp³d² hybridization which means that its geometry is likely to be octahedral.  Nevertheless Applying by applying the valence shell electron pair repulsion (VSEPR) model to in order to minimize the repulsion among lone pairs, bond pairs and lone pair-bond pairs, we we realize repulsion is actually minimized when lone pairs are anti to one another and the fluorine atoms are in equatorial position, for that reason, the corrected and properly exhibited geometry or molecular arrangement of the compound turns out square planar. You can verify it on the attached picture.

Regards.

Answer:

9.8 h

Explanation:

From the question,

Os²⁻ - 2e⁻ = Os

From the equation above,

2 F of electron is needed to liberate 1 mole of osmium.

45 g of osmium contains 45/190 mole of osmium = 0.237 mole.

2 F ⇒ 1 mole.

2(0.237) F ⇒ 0.237 mole

0.474 F. will produce 45 g of osmium.

If         1 F = 96500 C ,

Then,  0.474 F = 45741 C,

But,

Q = it

t = Q/i....................... Equation 1

Given: Q = 45741 C, i = 1.30 A

Substitute into equation 1

t = 45741/1.3

t = 9.8 h.

Answer:

Benzophenone

Explanation:

Given that:

an unknown compound’s semicarbazone melts at 162° -165°

The compound does not give a silver mirror in the Tollens’ test.

On reaction with KI/I2, NaOH/H2O no straw yellow precipitate forms.

The objective is to identify the unknown compound.

Since the unknown compound result to a semicarbazone, we can deduce that the unknown compound is a carbonyl compound. A carbonyl compound is either an aldehyde or ketone in nature. Also, the absence of  silver mirror in the Tollens’ test carried out in the reaction confirms that the compound is a ketone because  ketones will  never give a silver mirror in Tollens’ test.

Similarly, on reaction with KI/I2, NaOH/H2O no straw yellow precipitate forms,  that is an iodoform test. That implies that a keto-methyl group is absent in the unknown compound.

Finally, since the unknown compound melting point is between 162° -165° and Benzophenone semicarbazone  melting point is 164°.

We can conclude that the unknown  compound is Benzophenone semicarbazone  

Answer:

The correct answer is A.

Explanation:

Helium's Atomic Model has 2 Protons and 2 Neutrons, and on the outside it has 2 electrons circling around it.

Answer:

is A

Explanation:

Answer:

X

Anode

Loses mass

Electrons in the wire flow away from it

Anions from the salt bridge flow toward it

Y

Cathode

Gains mass

Electrons in the wire flow toward it

Cations from the salt bridge flow toward it

Explanation:

A galvanic cell consists of an anode, a cathode and a salt bridge. The cathode is the negative electrode. The cathode increases in mass due to mass deposition. The cathode becomes increasingly negative as the cell reaction progresses, hence cations from the salt bridge flow towards it.

The anode is the positive electrode. It becomes more positive as the cell reaction progresses hence anions from the salt bridge flow towards it. The anode is the electrode where oxidation reaction occurs hence electrons are lost here and flow towards the cathode. The anode looses mass as the cell reaction progresses due to oxidation.

Answer:

[tex]\Delta _rH=-136.27kJ/mol[/tex]

Explanation:

Hello,

In this case, for the given reaction, the enthalpy of reaction is computed in terms of the enthalpies of formation as:

[tex]\Delta _rH=\Delta _fH_{C_2H_6}-\Delta _fH_{C_2H_4}-\Delta _fH_{H_2}[/tex]

Whereas hydrogen, ethene and ethane enthalpies of formation are 0 kJ/mol, 52.47 kJ/mol and -83.8kJ/mol respectively. Therefore, we compute:

[tex]\Delta _rH=-83.8kJ/mol-52.47kJ/mol-0kJ/mol\\\\\Delta _rH=-136.27kJ/mol[/tex]

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hypothesis

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